In 2012, entering freshmen at the UA have an average ACT score of 25.4 with a standard deviation of 2.1. 1. What is the probability a student has an ACT score more than 24.1

Answer:

V = pi 36 units^3

V =113.04 units^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

V = pi ( 2) ^2 *9

V = pi 36

Letting pi = 3.14

V =113.04

Answer:

x=2 y=4

Step-by-step explanation:

Step-by-step explanation:

to find the sum of nth term

equation is

n/2 ( 2a + (n-1)d) where a is the 1st term and d is the common difference

5/2 ( 120 +( 4 × 31))

5/2 ( 120 + 124)

5/2 × 244

5 × 122 dividing 244 by 2

610

Answer: 610

Step-by-step explanation:

This sequence starts at 60 and increases by increments of 31.  Thus, to get the last two numbers, do 122+31=153, and 153+31=184.  Then add 60+91+122+153+184 to get 610.

Hope it helps <3

Answer:

1km

Step-by-step explanation:

1000m=1km

Ez Money

Answer:

1000m= 1km

if you convert 1m to km is 0.001km times it by 1000, you get 1km.

Answer:

The sample size is 30.

Step-by-step explanation:

The sample size of a histogram can be calculated by summing up all the frequencies of all the occurrences in the data set

From the question the frequency is given as

Frequency = 2 4 6 8 10

The sample size n =

2 + 4 + 6 + 8 + 10

= 30

Therefore the sample size n of the data set = 30

Answer:

The answer is option C

Step-by-step explanation:

Total surface area of a cylinder is

2πr( r + h)

The curved surface area of a cylinder is

2πrh

where r and h are the radius and height respectively

h = 10cm

r = 7cm

Total surface area is

2π×7( 7 + 10)

14π ( 7 + 10)

98π + 140π

238π

Which is

748 cm²

The curved surface area is

2π (7)(10)

140π

Which is

440cm²

The difference between the total surface area and the curved surface area of the cylinder is

748 cm² - 440cm²

Hope this helps you

Answer:

Error in the sphere's surface: 29 [tex]cm^2[/tex]  and relative error in surface measure: 0.011

Error in the sphere's volume: 205 [tex]cm^3[/tex] and relative error in the volume measure: 0.017

Step-by-step explanation:

(a)

The measured length (l) of the circumference is 90 cm with an error of 0.5 cm, that is:

[tex]l=2\,\pi\,R=90\,cm\\R=\frac{90}{2\,\pi} \,cm=\frac{45}{\pi} \,cm=14.3239\,\,cm[/tex]

and with regards to the error:

[tex]dl=0.5 \, cm\\dl=2\,\pi\,dR\\dR=\frac{dl}{2\,\pi} =\frac{1}{4\,\pi} cm = 0.0796\,cm[/tex]

then when we use the formula for the sphere's surface, we get:

[tex]S=4\,\pi\,R^2\\dS=4\,\pi\,2\,R\,(dR)\\dS=8\,\,\pi\.(\frac{45}{\pi} \,\,cm)\,(\frac{1}{4\pi}\,cm) =\frac{90}{\pi} \,\,cm^2\approx \,29\,cm^2[/tex]

Then the relative error in the surface is:

[tex]\frac{dS}{S} =\frac{90/\pi}{4\,\pi\,R^2} =\frac{1}{90} =0.011[/tex]

(b)

Use the formula for the volume of the sphere:

[tex]V=\frac{4\,\pi}{3} R^3\\dV=\frac{4\,\pi}{3}\,3\,R^2\,(dR)=4\,\pi\,R^2\,(\frac{1}{4\pi}) \,cm=(\frac{45}{\pi})^2 \,\,cm^3\approx 205\,\,cm^3[/tex]

Then the relative error in the volume is:

[tex]\frac{dV}{V} =\frac{205}{12310.5} \approx 0.017[/tex]

Answer: 308 gallons of water.

Step-by-step explanation:

First find the volume of the water been.

The volume of a rectangular prism uses the formula

V= L * W *H

V = 8 * 5 * 1

V = 40 ft^3

Now we will convert 40ft into gallons using what they gave us that 1 gallon is 0.13 ft^3  

[tex]\frac{1}{x} = \frac{0.13}{40}[/tex]    which means if 1 gallon is 0.13 cubic feet how much will 40 cubic feet be when converted to gallons.

Solve by cross product.

0.13x = 40  divide both sides by 0.13  

x= 308

Answer:

Step-by-step explanation:

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Answer:

7

Step-by-step explanation:

f(x) = 2^(x + 3)

Shifted 10 units to the right:

f(x) = 2^(x + 3 − 10)

f(x) = 2^(x − 7)

Therefore, k = 7.

Answer:

Step-by-step explanation:

Since the gravel being dumped is in the shape of a cone, we will use the formula for calculating the volume of a cone.

Volume of a cone V = πr²h/3

If the diameter and the height are equal, then r = h

V = πh²h/3

V = πh³/3

If the gravel is being dumped from a conveyor belt at a rate of 20 ft³/min, then dV/dt = 20ft³/min

Using chain rule to get the expression for dV/dt;

dV/dt = dV/dh * dh/dt

From the formula above, dV/dh = 3πh²/3

dV/dh =  πh²

dV/dt = πh²dh/dt

20 = πh²dh/dt

To calculate how fast the height of the pile is increasing when the pile is 11 ft high, we will substitute h = 11 into the resulting expression and solve for dh/dt.

20 = π(11)²dh/dt

20 = 121πdh/dt

dh/dt = 20/121π

dh/dt = 20/380.133

dh/dt = 0.0526ft/min

This means that the height of the pile is increasing at  0.0526ft/min

Answer:

178.5 actually

Step-by-step explanation:

Answer:

12a + 3b.

Step-by-step explanation:

3(4a + b)

= 3 * 4a + 3 * b

= 12a + 3b.

Hope this helps!

Answer:

[tex]12a+3b[/tex]

Step-by-step explanation:

[tex]\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=3,\:b=4a,\:c=b\\=3\times \:4a+3b\\\mathrm{Multiply\:the\:numbers:}\:3\times \:4=12\\=12a+3b[/tex]

Answer:

$253

Step-by-step explanation:

Margin of error is the critical value times the standard error.

MoE = z × σ/√n

At 99% confidence, z = 2.576.

MoE = 2.576 × 844/√74

MoE = 253

Answer:

[tex]\boxed{Side \ Length \ of \ hot \ tub = 4.8\ ft.}[/tex]

Step-by-step explanation:

Scale Factor = 5

Also,

B'C' = 24 feet

Since both are squares so both have all sides equal.

Sqaure A'B'C'D' is dilated by a scale factor of 5

So,

AB = BC = CD = DA = 24/5 = 4.8 ft.

The length of one side of the hot tub is 4.8 feet and this can be determined by using the concept of dilation.

Given :

The following steps can be used in order to determine the length of one side of the hot tub:

Step 1 - According to the given data, the dilation factor is 5.

Step 2 - So, after the dilation by a factor of 'a' the length of the side be 'b' becomes 'ab'.

Step 3 - So, according to the given data, the length of B prime C prime is 24 feet. Therefore, after the dilation by a factor of 5, the length of the segment BC becomes:

[tex]\rm =\dfrac{24}{5}=4.8\;feet[/tex]

So, the length of one side of the hot tub is 4.8 feet. Therefore, the correct option is b).

For more information, refer to the link given below:

https://brainly.com/question/2856466

Answer:

A

Step-by-step explanation:

To factor x² - 5x + 4, we need to find 2 numbers that have a sum of -5 and product of 4; these 2 numbers are -1 and -4 so the factored version is (x - 1)(x - 4). Since x - 4 is not an answer choice but x - 1 is, the answer is A.

Answer: the intersection point is (2.4, -4.8)

Step-by-step explanation:

A) we have the function:

y = 0.5*x - 6.

First we want to know if this function intersects the line y´ = -1.5*x

Now, first we can recall that two lines are parallel only if the slope is the same for both lines, here we can see that the slopes are different, so the lines are not parallel, which means that the lines must intersect at some point.

Now, to find the intersection point we asumme y = y´ and want to find the value of x.

0.5*x - 6 = -1.5*x

(0.5 + 1.5)*x - 6 = 0

2.5*x = 6

x = 6/2.5 = 2.4

Now, we evaluate one of the functions in this value of x.

y = 0.5*2.4 - 6 = -4.8

So the intersection point is (2.4, -4.8)

Answer:

[tex]\boxed{\mathrm{Option \ C}}[/tex]

Step-by-step explanation:

=> [tex]x^2+22x = 31[/tex]

=> [tex](x)^2+2(x)(11) = 31[/tex]

Since b = 11 , So [tex](11)^2[/tex] needs to be added to both sides

Adding [tex](11)^2[/tex]  to both sides

=> [tex](x)^2+2(x)(11)+(11)^2 = 31+(11)^2[/tex]

Completing the square

=> [tex](x+11)^2 = 31+121[/tex]

=> [tex](x+11)^2 = 152[/tex]

Answer:

Hey there!

The slope of a vertical line is undefined! The run is zero, and as we know, dividing by zero is undefined!

Hope this helps :)

Answer:

Undefined

Step-by-step explanation:

A vertical line has an undefined slope or there is no slope of the line.

Answer:

The minimum svore required to get an A is 85.3.

Step-by-step explanation:

Complete Question

Exam grades: Scores on a statistics final in a large class were normally distributed with a mean of 75 and a standard deviation of 8.

The instructor wants to give an A to the students whose scores were in the top 10% of the class. What is the minimum score needed to get an A?

Solution

Scores in the top 10% of the class will have a minimum greater than the remaining bottom 90% of the class.

If the minimum score for the top 10% of the class is x'

P(X ≤ x') = 90% = 0.90

If the z-score of this minimum score of the top 10%, x', is z'.

P(X ≤ x') = P(z ≤ z') = 0.90

using the z-distribution tables

z' = 1.282

But the z-score of any value is given as the value minus the mean divided by the standard deviation.

z = (x - μ)/σ

So,

z' = (x' - μ)/σ

Mean = 75

Standard deviation = 8

z' = 1.282

1.282 = (x' - 75)/8

x' = (1.282 × 8) + 75 = 85.256

= 85.3 to 3 s.f.

Hope this Helps!!!

Answer:

D. The linear parent function

Step-by-step explanation:

Linear functions are always characterized by a straight line graph with or without an intercept on the vertical or horizontal axis. A linear function usually has an independent variable and a dependent variable. The independent variable is commonly depicted as x while the dependent variable is y.

Thus a linear equation is an equation of the type y=ax where a is a constant term. The equation of a straight line graph his y=mx +c, where;

m= gradient of the straight line graph

x= the independent variable

y= the dependent variable

c= the vertical intercept

Answer:

The linear parent function :)

Step-by-step explanation:

Answer:

a. (24 ln 2 − 7) / 9

b. x tan x + ln|cos x| + C

Step-by-step explanation:

a. ∫₁² x² ln x dx

Integrate by parts.

If u = ln x, then du = 1/x dx.

If dv = x² dx, then v = ⅓ x³.

∫ u dv = uv − ∫ v du

= (ln x) (⅓ x³) − ∫ (⅓ x³) (1/x dx)

= ⅓ x³ ln x − ∫ ⅓ x² dx

= ⅓ x³ ln x − ¹/₉ x³ + C

= ¹/₉ x³ (3 ln x − 1) + C

Evaluate between x=1 and x=2.

[¹/₉ 2³ (3 ln 2 − 1) + C] − [¹/₉ 1³ (3 ln 1 − 1) + C]

⁸/₉ (3 ln 2 − 1) + C + ¹/₉ − C

⁸/₉ (3 ln 2 − 1) + ¹/₉

⁸/₃ ln 2 − ⁸/₉ + ¹/₉

⁸/₃ ln 2 − ⁷/₉

(24 ln 2 − 7) / 9

b. ∫ x sec² x dx

Integrate by parts.

If u = x, then du = dx.

If dv = sec² x dx, then v = tan x.

∫ u dv = uv − ∫ v du

= x tan x − ∫ tan x dx

= x tan x + ∫ -sin x / cos x dx

= x tan x + ln|cos x| + C

Answer:

width = length = 3 inches

height = 7 inches

Step-by-step explanation:

If x is the width and length of the base, and y is the height, then:

y = x + 4

The volume of the box is:

63 = x²y

The surface area of the box is:

93 = x² + 4xy

Substitute the first equation into the third.

93 = x² + 4x (x + 4)

93 = x² + 4x² + 16x

0 = 5x² + 16x − 93

0 = (x − 3) (5x + 31)

x = 3

y = 7

Use the second equation to check your answer.

63 = (3)²(7)

63 = 63

Answer:

Length=Width=3

Height=7.

Step-by-step explanation:

First, let's write some equations. So, we have an open box (with no lid) that has a square base. It has a height 4 units more of its width/length.

First, let's write the equation for the volume. The volume of a rectangular prism is:

[tex]V=lwh[/tex]

Recall that we have a square base. In other words, the length and width are exactly the same. Therefore, we can do the following substitution:

[tex]V=(w)wh=w^2(h)[/tex]

Now, recall that the height is four units more than the width/length. Therefore, we can make the following substitution:

[tex]V=w^2(w+4)\\63=w^2(w+4)[/tex]

We can't really do anything with this. Let's next find the equation for the surface area.

So, we have 5 sides (not 6 because we have no lid). The bottom side is a square, so it's area is w^2. Since we have a square base, the remaining four sides will have an area w(w+4). In other words:

[tex]93=w^2+4(w(w+4))[/tex]

The left term represents the area of the square base. The right term represents the area of one of the rectangular sides, times sides meaning four sides. Simplify:

[tex]93=w^2+4w^2+16w\\5w^2+16w-93=0[/tex]

This seems solvable. Let's try it. Trying factoring by guessing and checking.

We can see that it is indeed factor-able. -15 and 31 are the numbers:

[tex]5w^2-15w+31w-93=0\\5w(w-3)+31(w-3)=0\\(5w+3)(w-3)=0\\w=3\\h=w+4=7[/tex]

We ignore the other one because width cannot be negative.

So, the width/length is 3 and the height is 7. We can check this by plugging this into the volume formula:

[tex]63\stackrel{?}{=}(3)^2(7)\\63\stackrel{\checkmark}{=}63[/tex]

Answer:

z= 2.38

P = 0.008656

Step-by-step explanation:

Here n= 500 and p~= 464/500= 0.928 and q`= 1- 0.928 = 0.072

We formulate our null and alternate hypothesis as

H0 =  0.9 ;       H0 > 0.9

The degree of confidence = 90%

z₀.₀₅ = 1.645 for  α= 0.05

We use the test statistic

z=  x- np/√npq

z= 466-500 *0.9/ √500 * 0.9(1-0.9)

z= 466- 450/ √45

z= 16/6.7082

z= 2.38

As the calculated value of z= 2.38  is greater than α =1.645 so we reject H0.

If H0 is true the P value is calculated as

P = 1- Ф( 2.38)

P = 1-0.991344=0.008656

Answer:

[tex]x^\frac{8}{3} y^\frac{16}{3}[/tex]

Step-by-step explanation:

Given the expression [tex](x^4y^8)^\frac{2}{3}[/tex], to simplify the expression using the rational exponents;

Applying one of the law of indices to simplify the expression;

[tex](a^m)^n = a^{mn}[/tex]

[tex](x^4y^8)^\frac{2}{3}\\\\= (x^4)^\frac{2}{3} * (y^8)^\frac{2}{3}\\\\= x^{4*\frac{2}{3} } * y^{8*\frac{2}{3} }\\\\= x^\frac{8}{3} * y^\frac{16}{3}\\ \\The \ final \ expression \ will \ be \ x^\frac{8}{3} y^\frac{16}{3}[/tex]

Answer:

[tex]g(x) = |x| + 1[/tex]

Step-by-step explanation:

Given

[tex]y = |x|[/tex]

Required

Translate 1 unit up

Start by replacing y with f(x)

[tex]f(x) = |x|[/tex]

To translate an the graph of an absolute function upward, you make use of the formula;

[tex]g(x) = f(x) + k[/tex]

Where k is the number of units

In this case; [tex]k = 1[/tex]

Hence;

[tex]g(x) = f(x) + k[/tex]

Substitute [tex]k = 1[/tex]

[tex]g(x) = f(x) + 1[/tex]

Substitute  [tex]f(x) = |x|[/tex]

[tex]g(x) = |x| + 1[/tex]

Hence, the resulting equation is [tex]g(x) = |x| + 1[/tex]

Answer:

11/36

Step-by-step explanation:

Find the probability that neither dice shows a 5 (also means the dice can show any number except 5- where there are 5 possible choices out of 6):

= 5/6 x 5/6

=25/36

If we subtract the probability that neither dice shows a 5, we can obtain the probability that at least 1 dice shows a 5- (either one of them is 5, or both of them is 5)

1- 25/36

=11/36

Answer:

Solution,

∆ ACB = ∆ EFD

finding the value of X,

[tex] \frac{x}{3.8} = \frac{15}{5} [/tex]

Apply cross product property

[tex]x \times 5 = 15 \times 3.8[/tex]

Calculate the product

[tex]5x = 57[/tex]

Divide both sides by 5

[tex] \frac{5x}{5} = \frac{57}{5} [/tex]

Calculate

[tex]x = 11.4[/tex]

Hope this helps...

Good luck on your assignment...

Answer:

The required probability for the high temperature which 90% of the August days exceed. is 0.0333

Step-by-step explanation:

High temperatures in a certain city for the month of August follow a uniform distribution over the interval 61° F  to 91° F   . Find the high temperature which 90°  F of the August days exceed.

Let assume that X is the random variable

The probability mass function is:

[tex]f(x) = \dfrac{1}{b-a}[/tex]

[tex]f(x) = \dfrac{1}{91-61}[/tex]

[tex]f(x) = \dfrac{1}{30}[/tex]

Thus; The probability density function of X can be illustrated as :

[tex]f(x) = \left \{ {{ \ \ \dfrac{1}{30}} \atop { \limits }}_ \right. _0[/tex]       61 <  x < 91  or otherwise

The required probability for the high temperature at 90°  F can be calculated as follows:

[tex]P(X> 90) = \int\limits^{91}_{90} {f(x)} \, dx[/tex]

[tex]P(X> 90) = \int\limits^{91}_{90} \ {\dfrac{1}{30} \, dx[/tex]

[tex]P(X> 90) = {\dfrac{1}{30} \int\limits^{91}_{90} \ \, dx[/tex]

[tex]P(X> 90) = {\dfrac{1}{30} [x]^{91}_{90}[/tex]

[tex]P(X> 90) = {\dfrac{1}{30} (91-90)[/tex]

[tex]P(X> 90) = {\dfrac{1}{30} \times 1[/tex]

[tex]P(X> 90) = 0.0333[/tex]

The required probability for the high temperature which 90% of the August days exceed. is 0.0333

Answer:

$42.88

Step-by-step explanation:

We can set up a cross product fraction ratio to find how much 21 pounds of turkey costs.

[tex]\frac{10}{20.42} = \frac{21}{x}[/tex]

Let's apply the cross multiplication property.

[tex]20.42\cdot21=428.82[/tex]

Now we divide this by 10.

[tex]428.82\div10=42.882[/tex]

This simplifies down to [tex]42.88[/tex].

Hope this helped!