if the researcher chose a different design and this time had 30 players complete the game both with and without music playing? what type of design would this be? group of answer choices non -response bias convenience sampling volunteer sampling matched pairs

A testable prediction of what will happen under a specific set of conditions is known as a hypothesis.

A hypothesis is a tentative explanation or prediction about a phenomenon or relationship between variables, based on limited evidence or prior knowledge. It is often formulated as a statement that can be tested through research or experimentation.

A hypothesis typically includes an independent variable (the variable that is being manipulated or studied) and a dependent variable (the variable that is being measured or observed). The hypothesis also includes a prediction about how the independent variable will affect the dependent variable.

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a. It makes sense to test the same cats in both treatments (Still and Fountain) rather than using two independent samples because this approach eliminates any potential individual differences among cats. By using the same cats, the study can better isolate the effect of the water source on water consumption, making the comparison more accurate and meaningful.

b. To determine if there is convincing evidence at a = 0.05 that cats tend to drink more water from fountains than from a bowl, follow these 7 steps:

1. State the null hypothesis (H0): There is no difference in water consumption between still and fountain sources (µ_still = µ_fountain).
2. State the alternative hypothesis (Ha): Cats drink more water from fountains than from a bowl (µ_still < µ_fountain).
3. Choose the significance level (α): 0.05.
4. Identify the appropriate test: Paired t-test (since each cat is tested under both conditions).
5. Calculate the test statistic using the provided data (you may use statistical software like JMP or Excel for this calculation).
6. Determine the p-value by comparing the test statistic to the t-distribution with degrees of freedom equal to the number of cats minus 1 (n-1).
7. Make a decision: If the p-value is less than α, reject the null hypothesis in favor of the alternative hypothesis, concluding that there is convincing evidence that cats drink more water from fountains than from a bowl. If the p-value is greater than α, fail to reject the null hypothesis.

c. The characteristic feature of a pilot study present in this dataset is its small sample size, with only nine cats participating. Pilot studies are often conducted as a preliminary test to evaluate the feasibility of a research design and gather preliminary data before conducting a full-scale study. These results can be used to improve future research by identifying any potential issues in the experimental design, determining appropriate sample sizes for a larger study, or providing initial data to support funding applications for more extensive research.

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Answer:

Yes, we can still find the median. You just need to convert the rest to the given data / kilograms and you have to just do the steps of finding the median.

Answer:

B- 24.413

Step-by-step explanation:

3.3*3.15=10.395

10.395/2=5.1975

To find the right side of the bottom triangle- 6.3-3.15=3.15

3.15*3=9.45

9.45/2=4.725

4.6*3.15=14.49

Adding all the areas

14.49+4.725+5.1975=24.4125

24.4125 rounded is 24.413

Let's represent the speed of the plane in still air as "p" and the speed of the wind as "w".

When the plane is traveling with the wind, its speed is (p + w) and against the wind, its speed is (p - w).

Given that it travels d1 miles with the wind in t hours and d2 miles against the wind in the same time, we can form the following equations:

d1 = t(p + w)
d2 = t(p - w)

Now, we need to solve for "p" and "w". Divide the first equation by t, and the second equation by t as well:

d1/t = p + w
d2/t = p - w

Add the two equations together to eliminate "w":

(d1/t) + (d2/t) = 2p

Solve for "p":

p = (d1 + d2) / (2t)

Now, substitute the value of "p" in either equation to solve for "w":

w = (d1/t) - p

Once you have the specific values for d1, d2, and t, plug them into the equations to find the speed of the plane in still air (p) and the speed of the wind (w).

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The argument can be used to adjust the size of the two tick labels B and 0 on the x-axis is cex.axis of the boxplot. Option D is the correct choice.

To create a boxplot of rear width (RW) by species (sp) using the boxplot function in R, you can use the following R code:
```R
boxplot(RW ~ sp, data = your_data)
```

In this code, replace 'your_data' with the name of your data frame containing the variables RW and sp.

Regarding the options for adjusting the size of the tick labels (B and 0) on the x-axis, the correct argument is (D) cex.axis. You can use this argument to set the size of the tick labels as follows:
```R
boxplot(RW ~ sp, data = your_data, cex.axis = desired_size)
```

Replace 'desired_size' with a numerical value to set the size of the tick labels.

The answer is: (D) cex.axis

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The probability that the store was not busy given you did not work late is approximately 0.8083 or 80.83%.

To find the probability that the store was not busy given you did not work late, we can use Bayes' theorem.

1. Let A be the event "store is not busy" and B be the event "did not work late".
2. We are given P(A') = 0.56, where A' is the event "store is busy". So, P(A) = 1 - P(A') = 1 - 0.56 = 0.44.
3. We are also given P(B'|A') = 0.84, where B' is the event "worked late". So, P(B|A') = 1 - P(B'|A') = 1 - 0.84 = 0.16.
4. Additionally, we are given P(B'|A) = 0.14. So, P(B|A) = 1 - P(B'|A) = 1 - 0.14 = 0.86.

Now we can apply Bayes' theorem to find P(A|B):

P(A|B) = (P(B|A) * P(A)) / (P(B|A) * P(A) + P(B|A') * P(A'))

P(A|B) = (0.86 * 0.44) / (0.86 * 0.44 + 0.16 * 0.56)
P(A|B) = (0.3784) / (0.3784 + 0.0896)
P(A|B) = 0.3784 / 0.468

P(A|B) = 0.8083

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The derivative dy/dx for the given functions [tex]y = 6u^-5[/tex] and [tex]u = 2(14x)[/tex]is:

[tex]dy/dx = (-30(28x)^-6) * 28[/tex]

GIven the functions y = f(u) and u = g(x), and we need to find the derivative dy/dx using the chain rule. The given functions are [tex]y = 6u^-5[/tex]and [tex]u = 2(14x).[/tex] Let's begin.

First, let's find the derivative of y with respect to u, which is f'(u). We have:

[tex]y = 6u^-5\\f'(u) = -30u^-6[/tex]

Next, let's find the derivative of u with respect to x, which is g'(x). We have:

u = 2(14x)
g'(x) = 28

Now we can apply the chain rule to find dy/dx:

dy/dx = f'(g(x)) * g'(x)

Substitute the derivatives we found earlier and the function u = g(x):

dy/dx = (-30(2(14x))^-6) * 28

Simplify the expression:

dy/dx = (-30(28x)^-6) * 28

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Therefore, the third piece of fabric is 39 meters long.

The International System of Units' fundamental unit of length is the metre. The Earth's circumference is around 40000 km, according to the original definition of the metre in 1793, which was one ten-millionth of the distance between the equator and the North Pole on a great circle.

We know that the total cost of three pieces of fabric is S/ 811.37 and the price per meter is S/ 6.61. Let's calculate the total length of the first two pieces of fabric:

43.5 m + 40 m = 83.5 m

To find the length of the third piece, we can subtract the total length of the first two pieces from the total cost:

S/ 811.37 ÷ S/ 6.61 per meter = 122.5 meters

83.5 m + x = 122.5 m

x = 39 m

So, Therefore, the third piece of fabric is 39 meters long.

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Correct Question:

Teresa, dedicated to making dress pants, buys three pieces of fabric for S/ 811.37. One of the pieces is 43.5 m, another 40 m and we know that the price per meter is, in all cases, S/ 6. 61. How many meters is the third piece?

The maximum error of the estimated mean amount spent by customers for a 99% level of confidence is $2.803. This means that the company can estimate the mean amount spent by customers with a 99% level of confidence and an error of no more than $2.803.

The maximum error of the estimated mean amount spent by customers for a 99% level of confidence can be determined using the formula:

Maximum Error = Z-value * (Estimated Standard Deviation / √Sample Size)

Where the Z-value for a 99% level of confidence is 2.576 (found using a standard normal distribution table or calculator).

Given that the local retail company's budget limits the number of surveys to 250 and the estimated standard deviation is $17.00, the maximum error can be calculated as:

Maximum Error = 2.576 * (17 / √250) = 2.576 * (17 / 15.8114) = 2.803

Therefore, the maximum error of the estimated mean amount spent by customers for a 99% level of confidence is $2.803. This means that the company can estimate the mean amount spent by customers with a 99% level of confidence and an error of no more than $2.803.

It's important to note that the maximum error decreases as the sample size increases. However, since the budget limits the number of surveys to 250, the company must work within this constraint to obtain the most accurate estimate of the mean amount spent by customers.

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x 10.5 is the disparity that best describes the issue.

Sandra aims to cover a minimum of 10.5 miles while walking.

For her new puppy, Sandra set a walking goal that she divided evenly across the seven lengthy walks she intends to take this week.

To meet the target, each walk should be at least 1.5 kilometres long.

Let x be the total number of miles Sandra wants to walk.

Let's now construct an inequality based on the available data:

Sandra wants to walk x miles overall, which divides into 7 walks at a rate of 1.5 miles per walk.

Fix the inequality now:

x / 7 ≥ 1.5

To isolate x, multiply both sides by 7 as follows: x 1.5 * 7 x 10.5.

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The sum of the series Σ (6^(n-2) + 1 / (-8)^n) is 53 / 540.

To find the sum of the series, let's express it in sigma notation and then simplify it:

Σ (6^(n-2) + 1 / (-8)^n)

First, let's consider the first term of the series: 6^(n-2).

We can rewrite this term as 6^(-2) * 6^n.

Now, let's consider the second term of the series: 1 / (-8)^n.

Since (-8)^n can be written as (-1)^n * 8^n, we can rewrite the term as 1 / ((-1)^n * 8^n).

Combining the two terms, we have:

Σ (6^(-2) * 6^n + 1 / ((-1)^n * 8^n))

We can split this into two separate series:

Σ (6^(-2) * 6^n) + Σ (1 / ((-1)^n * 8^n))

Now, let's calculate each series separately.

For the first series, Σ (6^(-2) * 6^n), we have a geometric series with a common ratio of 6. The formula for the sum of a geometric series is:

Sum = a / (1 - r),

where a is the first term and r is the common ratio.

In this case, a = 6^(-2) and r = 6.

Sum of the first series = 6^(-2) / (1 - 6) = 6^(-2) / (-5) = -1 / (5 * 6^2) = -1 / 180.

For the second series, Σ (1 / ((-1)^n * 8^n)), we also have a geometric series, but with a common ratio of (-1/8).

Using the formula for the sum of a geometric series, we get:

Sum of the second series = 1 / (1 - (-1/8)) = 1 / (1 + 1/8) = 1 / (9/8) = 8/9.

Now, let's find the sum of the entire series by adding the sums of the two separate series:

Sum of the series = Sum of the first series + Sum of the second series

                 = -1/180 + 8/9

                 = (-1 + 160) / (180 * 9)

                 = 159 / 1620

                 = 53 / 540.

Therefore, the sum of the series Σ (6^(n-2) + 1 / (-8)^n) is 53 / 540.

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The inequality that represents the normal temperature range of a dog, where t represents body temperature is given as follows:

|t - 101.8| ≤ 0.7.

The absolute value of a number gives the distance of a number from the origin, hence it basically can be interpreted as the number without the signal, as for example, |-2| = |2| = 2.

The average temperature for a dog is 101.8° F, but it can vary by as much as 0.7° F, hence the absolute value of the difference between t and 101.8 is of at most 0.7, hence the inequality is:

|t - 101.8| ≤ 0.7.

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The fractions equivalent to 6/12 are 6/12, 2/4, and 1/2.

1. 4/6: To see if these fractions are equivalent, we can simplify 6/12. Divide both the numerator and the denominator by their greatest common divisor, which is 6. 6/12 ÷ (6/6) = 1/2. Now, simplify 4/6 by dividing both by their greatest common divisor, which is 2. 4/6 ÷ (2/2) = 2/3. These fractions are not equivalent, as 1/2 ≠ 2/3.

2. 3/8: This fraction cannot be equivalent to 6/12, as their denominators are different and don't have a common factor. So, no further calculation is needed.

3. 6/12: This fraction is the same as the original fraction and is therefore equivalent to itself.

4. 2/4: Simplify 2/4 by dividing both the numerator and the denominator by their greatest common divisor, which is 2. 2/4 ÷ (2/2) = 1/2. This fraction is equivalent to 6/12, as 1/2 = 1/2.

5. 1/2: As we found out earlier, 6/12 simplifies to 1/2, so this fraction is equivalent to 6/12.

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To evaluate the limit, we can use the Ratio Test:

|an+1/an| = |15(n+2)(n+1)4^(n+1) / (n+1)(2n+1)4^n15|
= |60(n+2)/(2n+1)|

As n approaches infinity, this ratio approaches 30. Since 30 is less than 1, the series is convergent. To determine whether the series is absolutely convergent, conditionally convergent, or divergent, we need to examine the absolute value of the series:

|15" ni (n + 1)42n41| = 15" ni (n + 1)(4/41)^n

This is a geometric series with the first term 15 and a common ratio of 4/41. Since the absolute value of the common ratio is less than 1, the series is absolutely convergent. To answer your question, let's first rewrite the given series and then apply the Ratio Test.

Series: ∑(15^(n) * (n) * (n+1)) / (42^(n))

We need to evaluate the limit:

lim (n→∞) (|a_(n+1)| / |a_n|)

First, let's find the expression for a_(n+1):

a_(n+1) = (15^(n+1) * (n+1) * (n+2)) / (42^(n+1))

Now, we can find the limit:

lim (n→∞) (|a_(n+1)| / |a_n|) = lim (n→∞) (|15^(n+1) * (n+1) * (n+2) / (42^(n+1))|) / (|15^n * n * (n+1) / 42^n|)

By simplifying, we get:

lim (n→∞) (15/42 * (n+2)/(n))

Since 15/42 is less than 1, the limit converges to a value less than 1:

L = 15/42

Using the Ratio Test, we can conclude that the series is "Convergent."Finally, to determine whether the series is absolutely convergent, conditionally convergent, or divergent, we can analyze the given series. Since the series is already convergent based on the Ratio Test, it is "Absolutely Convergent."

So, to summarize:

- The limit L = 15/42
- The series is "Convergent" using the Ratio Test
- The series is "Absolutely Convergent"

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The area of the figure is 528units²

The space enclosed by the boundary of a plane figure is called its area. The area is measured in square units.

The figure contains several rectangles by dividing it into different shapes.

The first part is a rectangle;

area = l×w

= 16×8 = 128 units²

for the second part ;

area = l× w

= 8× 24

= 192 units²

for the third part

The area of the whole rectangle

= l×w

= 8× 24

= 192 units²

area of the cut out section

= 12 × 4 = 48 units²

Therefore area of the figure = 128+192+192-48

= 528 units²

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The derivative is y' = cos(x). However, based on our calculations, we found that y' = sec^2(x). Therefore, the given function and derivative do not match, and we cannot verify that the function satisfies the differential equation.

Let's use the given function and its derivative:

Function: y = 2 tan(x) - x
Derivative: y' = cos(x)

Now, let's rewrite the function in terms of sin(x) and cos(x), since tan(x) = sin(x) / cos(x):

y = 2 (sin(x) / cos(x)) - x

To find the derivative y', we will need to apply the Quotient Rule, which states:

(d/dx)[u(x) / v(x)] = (v(x) * (du/dx) - u(x) * (dv/dx)) / [v(x)]^2

Here, u(x) = sin(x) and v(x) = cos(x). Thus, we have:

(du/dx) = cos(x) and (dv/dx) = -sin(x)

Applying the Quotient Rule:

y' = (cos(x) * cos(x) - sin(x) * -sin(x)) / cos^2(x)

y' = (cos^2(x) + sin^2(x)) / cos^2(x)

Using the Pythagorean identity, cos^2(x) + sin^2(x) = 1:

y' = 1 / cos^2(x)

Now, recall that 1 / cos^2(x) is equal to the secant squared function, sec^2(x). Therefore, we can rewrite y' as:

y' = sec^2(x)

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Answer:

6 3/5+ 3 2/5 =10

Step-by-step explanation:

EZ 6+3 3/5+2/5 10

The monthly payment for a $375,000 mortgage with a yearly interest rate of 3% and a 25-year term would be approximately $1,786.51.

Mortgage amount = P = $375,000,

Interest rate = i = 3%

Time =  n = 25 years

Thus, converting rate and time

Interest rate = i = 3% / 12 = 0.0025, and

Time =  n = 25 years x 12 months/year = 300 months.

A mortgage is a loan granted to a buyer by a bank or other type of mortgage lender so they may buy a home.

Calculating the monthly payment for a mortgage -

[tex]M = P [ i(1 + i)^n ] / [ (1 + i)^n – 1][/tex]

Substituting the values in the formula -

[tex]M = 375000 [ 0.0025(1 + 0.0025)^300 ] / [ (1 + 0.0025)^300 – 1][/tex]

= 1,786.51

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Answer: 1778.29

Step-by-step explanation:

We must apply the formula for P0 and solve for d, that is,

P0=d(1−(1+rk)−Nk(rk).

We have P0=$375,000,r=0.03,k=12,N=25, so substituting in the numbers into the formula gives

$375,000=d(1−(1+0.0312)−25⋅12)(0.0312),

that is,

$375,000=210.878645d⟹d=$1,778.29.

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The domain of the revenue function is the set of all possible values of p. In this case, the price-demand equation tells us that the highest possible price for the table saws is $400, so the domain of the revenue function is 0 ≤ p ≤ 400.

Revenue is equal to the number of units sold times the price per unit. To obtain the revenue function, multiply the output level by the price function.

To find the revenue function, we need to multiply the price-demand equation by the quantity produced (x).

Revenue function = p * x = p * (8,000 - 20p)

Simplifying the expression, we get:

Revenue function = 8,000p - 20p^2

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Answer:

6 pints

Step-by-step explanation:

2 2/5 x 2 = 24/5

2 2/5 x 2/4 = 6/5

6/5 + 24/5 = 6

Therefore, the patient will drink 6 pints over the week.

I hope this helped! :)

Therefore, the delivery truck service needs 437,400 cubic inches of volume to transport the 75 boxes.

The volume of one cube is calculated by using the formula V = s³, where s is the length of one side of the cube. In this case, we are given that each side of the cube is 18 inches long, so we can substitute this value into the formula to get V = 18³ = 5832 cubic inches.

To find the total space needed to transport 75 boxes, we need to multiply the volume of one box by the number of boxes. We are given that there are 75 boxes, so we can simply multiply the volume of one box by 75 to get the total volume needed. Thus, the total volume is 75 * 5832 = 437,400 cubic inches. This is the amount of space required to transport all 75 boxes.

The volume of one cube is given by:

V = s³

= 18³

= 5832 cubic inches

To find the total space needed to transport 75 boxes, we can multiply the volume of one box by the number of boxes:

Total volume = 75 * 5832

= 437,400 cubic inches

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The slope between any two points on this graph is constant. Therefore, options B and C are the correct answers.

The given equation is y=x+4.

Substitute x=0, 1, 2, 3, 4, 5,......

So, y = 4, 5, 6, 7, 8, 9,.....

Graph the line using the slope and y-intercept, or two points.

Slope: 1

y-intercept: (0, 4)

Therefore, options B and C are the correct answers.

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The given limit expression can be written as a definite integral on the interval [-2, 2]. Here's the conversion: lim (n→∞) Σ (SCi + 3) Δxi, i = 1 to n, on the interval [-2, 2] As a definite integral, it becomes: ∫[-2, 2] (SCx + 3) dx

The limit can be written as the definite integral on the interval [-2, 2] of the function (x+3) with respect to x, where ci is any point in the ith subinterval.

In other words, lim Σ (SCi + 3) Δxi [-2, 2] ||Δ|| →0 i = 1 can be rewritten as lim Σ f(ci) Δxi [-2, 2] ||Δ|| →0 i = 1 where f(x) = x+3, and Δx = (b-a)/n = (2-(-2))/n = 4/n.

Then, we can use the definition of the definite integral to find that ∫[-2, 2] f(x) dx = ∫[-2, 2] (x+3) dx = [x^2/2 + 3x]_(-2)^2 = (4+6) - (-2-6) = 12.

Thus, the limit can be written as lim Σ (SCi + 3) Δxi [-2, 2] ||Δ|| →0 i = 1 = lim Σ f(ci) Δxi [-2, 2] ||Δ|| →0 i = 1 = ∫[-2, 2] f(x) dx = 12.

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Yes, it is reasonable to believe that more than half of food delivery drivers eat some of the food they are delivering based on the confidence interval provided.

The interval (0.398, 0.706) represents the range of plausible values for the true proportion of food delivery drivers who eat some of the food they are delivering with 95% confidence. The fact that the majority of the interval is greater than 0.50 suggests that the true proportion is more likely to be greater than 0.50 than not. Additionally, the center of the interval is 0.552, which is greater than 0.50, further supporting the idea that the majority of food delivery drivers eat some of the food they are delivering. While it is true that 0.50 is within the interval, this does not necessarily mean that it is the most likely proportion or that the true proportion is exactly 0.50. Additionally, the fact that there are values less than 0.50 in the interval does not necessarily mean that less than half of food delivery drivers eat some of the food they are delivering. Overall, the confidence interval provides evidence that more than half of food delivery drivers eat some of the food they are delivering.

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The error represented in this scenario is an inappropriate task allocation or a mismatch between job responsibilities and the assigned task during the interview process.

The primary role of a customer service representative is to interact with customers, address their concerns, and log calls professionally and efficiently. In contrast, performing a detailed analysis of call-in data falls under the domain of data analysis or business intelligence roles.

By asking the candidate to perform a task unrelated to their potential job responsibilities, the company may not accurately assess the candidate's aptitude for customer service tasks. This error could lead to selecting a candidate who may excel in data analysis but may not possess the necessary communication and problem-solving skills required for a customer service representative position.

To avoid this error, the company should focus on evaluating candidates based on their skills, experience, and performance in tasks directly relevant to the customer service role.

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The value of x that makes the equation 3(x − 6) − 8x = − 2 + 5(2x+1) true is - 7 / 5.

An equation is an expression with an 'equal to' symbol between two expressions that have equal values.

Therefore, let's find the variable x in the equation to know what make the value of x that makes the equation true.

A variable is a number represented with letters in an equation.

3(x − 6) − 8x = − 2 + 5(2x+1)

3x - 18 - 8x  = -2 + 10x + 5

3x - 8x - 18 = 3 + 10x

-5x - 18 = 3 + 10x

-5x - 10x = 3 + 18

-15x = 21

x = 21 / -15

Therefore,

x = -  7 / 5

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Each set is Z is universal set is ({x EZ:x≤ -1} U {n EZ:n>4}) = {k EZ:-1<k<=4}

Now, let's consider the set ({x EZ:x≤ -1} U {n EZ:n>4}). The notation indicates the complement of a set, which means that it includes all the elements that are not in the original set. Therefore, we need to find all the elements in the universal set that are not in the set ({x EZ:x≤ -1} U {n EZ:n>4}).

Firstly, let's consider the set {x EZ:x≤ -1}. This set includes all the integers x that are less than or equal to -1. Next, we consider the set {n EZ:n>4}, which includes all the integers n that are greater than 4. The union of these two sets, {x EZ:x≤ -1} U {n EZ:n>4}, contains all integers less than or equal to -1 and all integers greater than 4.

Therefore, the complement of this union set, ({x EZ:x≤ -1} U {n EZ:n>4}) includes all the integers that are greater than -1 and less than or equal to 4. This is because these are the only integers that are not in the union set.

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The statistical strategy that would allow the professor to determine if the average score on the final exam has gone higher is a hypothesis test. The professor can formulate a null hypothesis (H0) that the average score is still 83 and an alternative hypothesis (Ha) that the average score is greater than 83. Then the professor can collect a sample of final exam scores and calculate the sample mean.

The professor can use the sample mean and standard deviation to calculate a test statistic, which can be compared to a critical value or p-value to determine if the null hypothesis should be rejected or not.

Hypothesis testing is a commonly used statistical method to make decisions about a population based on a sample. In this case, the professor wants to determine if the average score on the final exam has increased or not. By setting up a hypothesis test, the professor can use the sample data to make an inference about the population. The null hypothesis assumes that there is no difference between the population mean and the previous average score of 83.

The alternative hypothesis assumes that the population mean has increased. By calculating a test statistic and comparing it to a critical value or p-value, the professor can make a decision to either reject or fail to reject the null hypothesis. If the null hypothesis is rejected, the professor can conclude that there is evidence to support the claim that the average score on the final exam has increased.

In the past, students have scored an average of 83 points on the final exam in a statistics course. The professor thinks that this average has now gone higher. What statistical strategy would allow the professor to determine if he is correct? Confidence interval Regression analysis Empirical rule Hypothesis test

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The statistical strategy that would allow the professor to determine if the average score on the final exam has gone higher is a hypothesis test. The professor can formulate a null hypothesis (H0) that the average score is still 83 and an alternative hypothesis (Ha) that the average score is greater than 83. Then the professor can collect a sample of final exam scores and calculate the sample mean.

The professor can use the sample mean and standard deviation to calculate a test statistic, which can be compared to a critical value or p-value to determine if the null hypothesis should be rejected or not.

Hypothesis testing is a commonly used statistical method to make decisions about a population based on a sample. In this case, the professor wants to determine if the average score on the final exam has increased or not. By setting up a hypothesis test, the professor can use the sample data to make an inference about the population. The null hypothesis assumes that there is no difference between the population mean and the previous average score of 83.

The alternative hypothesis assumes that the population mean has increased. By calculating a test statistic and comparing it to a critical value or p-value, the professor can make a decision to either reject or fail to reject the null hypothesis. If the null hypothesis is rejected, the professor can conclude that there is evidence to support the claim that the average score on the final exam has increased.

In the past, students have scored an average of 83 points on the final exam in a statistics course. The professor thinks that this average has now gone higher. What statistical strategy would allow the professor to determine if he is correct? Confidence interval Regression analysis Empirical rule Hypothesis test

To learn more about null hypothesis : brainly.com/question/28920252

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To represent the scenario of tides in the bay, you can draw a sketch of the curve y = 7*cos(π/6x) + 29, where x represents the number of hours since high-tide and y represents the depth of the water in the bay. The equation for this scenario is y = 7*cos(π/6x) + 29.

a. To draw a sketch representing this scenario for two full periods, follow these steps:

1. Label the x-axis as "hours since high-tide" and the y-axis as "depth of water in the bay."

2. The maximum depth is 36 feet and the minimum depth is 22 feet, so the amplitude (A) is (36 - 22) / 2 = 7 feet. This means the cosine curve will oscillate 7 feet above and below the average depth.

3. The average depth is (36 + 22) / 2 = 29 feet. This is the vertical shift (C) in the equation.

4. High tide occurs every 12 hours, so the period is 12 hours. To find the value of B, use the formula period = 2π/B, which gives B = 2π/12 = π/6.

5. Now you can plot the cosine curve y = 7*cos(π/6x) + 29 for two full periods (0 to 24 hours).

b. The equation to represent this scenario is y = 7*cos(π/6x) + 29, where x represents the number of hours since high-tide and y represents the depth of the water in the bay.

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