Answer:
The pressure at a depth h in a fluid with density ρ is given by:
P = ρgh
where g is the acceleration due to gravity.
The force exerted on the eardrum is equal to the pressure difference between the inside and outside of the eardrum multiplied by the area of the eardrum:
F = A(Pinside - Poutside)
where A is the area of the eardrum, Pinside is the pressure inside the ear, and Poutside is the pressure outside the ear.
To find the depth at which the force on the eardrum is 1.5 N above atmospheric pressure, we need to first find the pressure difference and then the corresponding depth.
The atmospheric pressure at sea level is approximately 101,325 Pa. Adding 1.5 N of force per the eardrum means adding 1.5 N of force per the area of the eardrum, which is:
A = π(0.0079 m/2)^2 = 4.909×10^-5 m^2
So the pressure difference is:
ΔP = F/A = 1.5 N/4.909×10^-5 m^2 = 3.057×10^4 Pa
Now we can solve for the depth using the pressure equation:
ΔP = ρgh
h = ΔP/(ρg) = (3.057×10^4 Pa)/(1.03×10^3 kg/m^3 × 9.81 m/s^2) ≈ 3.02 m
Therefore, the eardrum can be damaged when scuba diving at a depth of approximately 3.02 meters in seawater.
WORTH 50 POINTS!!!
A fellow student would like to know how magnets behave when considering their magnetic
poles. Construct a drawing to show how magnetic attraction is different from repulsion. Be sure
to properly label the magnetic poles. Include magnetic field lines to indicate where the magnetic
field is the strongest and weakest
The diagram to show behavior of magnetic poles is given.
Magnetic poles can be either north or south. Opposite magnetic poles (i.e., north and south) attract each other, while like magnetic poles (i.e., north and north, or south and south) repel each other. This behavior is due to the alignment of the magnetic fields around the poles.
The strongest part of a magnet's magnetic field is at the poles, while the weakest part is at the sides. Magnetic field lines flow out of the north pole and into the south pole, forming a loop around the magnet. The closer the field lines are to each other, the stronger the magnetic field is in that region.
Overall, this behavior of magnetic poles is a result of the interaction of magnetic fields, and is essential to many technological applications of magnets, such as in electric motors and generators.
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14. Ball A, weighing 30 N, experiences a gravitational force of 8.7 x 10-10 N from Ball B that is
at rest 3.0 m away. What is the mass of Ball B?
The mass of the Ball B is 1.35 x 10⁻⁶ kg.
Understanding Gravitational ForceGravitational Force is described by Newton's law of universal gravitation, which states that the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The law of universal gravitation is important in many fields, including astronomy, physics, and engineering.
The gravitational force F between two objects of masses m1 and m2 separated by a distance r is given by:
F = G(m₁m₂)/r²
where G is the gravitational constant.
We can rearrange the equation to solve for the mass of Ball B:
m₂ = Fr²/Gm₁
Substituting the given values, we get:
m₂ = (8.7 x 10⁻¹⁰ N)(3.0 m)²/(6.6743 x 10¹¹ N(m^2/kg²))(30 N)
m₂ = 1.35 x 10⁻⁶ kg
Therefore, the mass of Ball B is approximately 1.35 x 10⁻⁶kg.
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A liquid x at 25 degree Celsius is poured to a height of 40cm in a capillary tube of length 70cm and the diameter is 1cm .Assume that volume does not change with temperature. A find the initial volume of the liquid in cm^3. B. The temperature is reduced by 10°C causing the liquid to reduce in height to 37cm.Find the volume coefficient of the thermal expansion of the liquid. C. At the initial height of 40cm and temperature of 25°C , what change in temperature is needed for liquid to rise to a height of 49cm.
The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.
The initial volume of the liquid can be found using the formula for the volume of a cylinder:
V = πr²h
where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:
V = π(0.5 cm)²(40 cm)
V = 31.4 cm³
The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:
β = ΔV/(VΔT)
where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:
ΔV = βVΔT
We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:
ΔV = π(0.5 cm)²(40 cm - 37 cm)
ΔV = 0.59 cm³
Plugging in all the values, we get:
0.59 cm³ = β(31.4 cm³)(-10°C)
β = 0.002
To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:
ΔT = ΔV/(βV)
We know that ΔV is the difference between the initial volume and the volume at the new height, which is:
ΔV = π(0.5 cm)²(49 cm - 40 cm)
ΔV = 6.86 cm³
Plugging in all the values, we get:
ΔT = 6.86 cm³/(0.002)(31.4 cm³)
ΔT = 109.5°C
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which of the following is a plant structure that increases the probability of successful reproduction
The plant structure that increases the probability of successful reproduction is flower. So, option B.
The reproductive organs of flowering plants are flowers. The possibility of successful pollination and fertilization is increased by the presence of both male and female reproductive structures in them.
In the flowers, the pollen is considered as the male sex cells. The female part, i.e., the pistil, consists of the ovary, which produces female sex cells or eggs.
There are specialized plant structures in flowers, such as brightly colored petals to attract potential pollinators and extended stamens that require animals to brush against the plants in order to receive the nectar.
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What are fitness assessments designed to do?
diagnose medical conditions
screen for risk of heart disease
treat injuries
identify specific injuries
Answer: Fitness assessments are designed to screen for risk of heart disease.
Explanation:
Fitness assessments are medical examinations that are designed to measure a person's physical fitness and identify any health risks they may have. These assessments may include tests of strength, endurance, flexibility, and cardiovascular fitness. One of the primary objectives of a fitness assessment is to screen for the risk of heart disease, which is a major health concern that can be prevented or treated through exercise and other lifestyle changes. While fitness assessments may identify specific injuries or medical conditions, their primary focus is on evaluating a person's overall health and fitness.
How much would a spring scale with a spring constant of 120 N/m stretch if it had 3.75 J of work done on it?
A spring scale with a spring constant of 120 N/m would stretch by 0.14 meters if it had 3.75 J of work done on it.
The work done on a spring can be calculated using formula:
[tex]W = (1/2) * k * x^2[/tex]
where W is the work done in joules (J), k is spring constant in Newtons per meter (N/m), and x is displacement of the spring from its equilibrium position in meters (m).
Rearranging the formula, we get:
x = sqrt(2W/k)
Plugging in given values, we get:
x = sqrt(2 * 3.75 J / 120 N/m) = 0.14 m
Therefore, a spring scale with a spring constant of 120 N/m would stretch by 0.14 meters if it had 3.75 J of work done on it.
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An electron remains suspended between the
surface of the Earth (assumed neutral) and a
fixed positive point charge, at a distance of
6.08 m from the point charge.
Determine the charge required for this to
happen. The acceleration due to gravity
is 9.8 m/s
2
and the Coulomb constant is
8.98755 × 109 N · m2
/C
2
.
Answer in units of C.
The charge required for the fixed point charge is approximately [tex]4.8032 * 10^{-10} C[/tex].
The electrostatic force between the fixed point charge and the electron is equal in magnitude to the gravitational force between the electron and the Earth, so we can set these two forces equal to each other and solve for the charge of the fixed point charge.
Electrostatic force between two point charges is given by Coulomb's law:
[tex]F = k * q1 * q2 / r^2[/tex]
The gravitational force between two masses is given by Newton's law of gravitation:
[tex]F = G * m1 * m2 / r^2[/tex]
Setting these two forces equal to each other and solving for q2, we get:
[tex]k * q1 * q2 / r^2 = G * m_e * m\_earth / r^2[/tex]
Solving for q2, we get:
[tex]q2 = G * m_e * m\_earth / k[/tex]
Substituting the given values, we get:
[tex]q2 = (6.67430 * 10^{-11} N * m^2 / kg^2) *\\ (9.10938356 *10^{-31} kg) *\\ (5.9722 *10^{24} kg) / (8.98755 * 10^9 N * m^2 / C^2)[/tex]
[tex]q2 = 4.8032 * 10^{-10} C[/tex]
Therefore, the charge required for the fixed point charge is approximately [tex]4.8032 * 10^{-10}[/tex]C.
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Help me please!!!!!!!!!!
The velocity of the ball just before it hits the ground is 14.0 m/s
Let's solve the problem using the given equation:
[tex]v^2 = u^2 + 2as[/tex]
We know that u (initial velocity) is zero, s (distance traveled) is 10 meters, and a (acceleration due to gravity) is 9.81 m/s^2. We want to find the final velocity (v) just before the ball hits the ground.
Plugging in the given values, we get:
v^2 = 0 + 2(9.81)(10)
v^2 = 196.2
Taking the square root of both sides, we get:
v = sqrt(196.2)
v = 14.0 m/s
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--The complete Question is, A ball is dropped from a height of 10 meters. What is its velocity just before it hits the ground, assuming no air resistance? (Assume that the acceleration due to gravity is 9.81 m/s^2)
Hint: You can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration due to gravity, and s is the distance traveled.--
Need help Electric Forces
The net electric force on charge q2 is 28.7 N.
What is the net electric force on q2?The net electric force on charge q2 is calculated by applying Coulomb's law of electrostatic force.
F(net) = F(12) + F(23)
The force on q2 due to charge 1 is calculated as;
F(12) = -(9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.1²)
F(12) = 25.2 N
The force on q2 due to charge 3 is calculated as;
F(23) = (9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.15²)
F(23) = 3.5 N
The net force on q2 is calculated as;
F(net) = 25.2 N + 3.5 N = 28.7 N
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Consider a ring, sphere and solid cyclinder all with the same mass. They are all held at the top of an inclined plane which is at 20° to the horizontal. The top of the inclined plane is 1 m high. The shapes are released simultaneously and allowed to roll down the inclined plane. Assume the objects roll without slipping and that they are all made from the same material. Assume the coefficient of static friction between the objects and plane to be 0.3.
a) workout what order
they would get to the bottom of the Slope.
b) How long will it take each shape to reach the bottom of the Slope ?
c) which shapes have the greater moment of inertia ?
d) determine the linear acceleration(a)
e) calculate the tangential (linear) Velocity
of each shapes-
a) The order in which the objects reach the bottom of the slope depends on their moments of inertia, b) All three shapes will reach the bottom of the slope in approximately the same amount of time, which is around 0.42 seconds, c) The solid cylinder has the greatest moment of inertia, d) All three objects have the same linear acceleration of approximately 1.52 m/s^2, and e) All three objects have the same tangential (linear) velocity of approximately 1.52 m/s.
A slope is a slanted surface that connects two different levels or elevations.
a) The order in which the objects reach the bottom of the slope depends on their moments of inertia. The object with the smallest moment of inertia will reach the bottom first, followed by the object with the next smallest moment of inertia, and so on.
b) The time it takes each shape to reach the bottom of the slope can be calculated using the formula:
t = sqrt(2h/(g*sin(theta)))
where h is the height of the slope (1 m), g is the acceleration due to gravity (9.81 m/s^2), and theta is the angle of the slope (20°).
For the given values, we have:
t_ring = sqrt(21/(9.81sin(20°))) ≈ 0.42 s
t_sphere = sqrt(21/(9.81sin(20°))) ≈ 0.42 s
t_cylinder = sqrt(21/(9.81sin(20°))) ≈ 0.42 s
Therefore, all three shapes will reach the bottom of the slope in approximately the same amount of time.
c) The moment of inertia of a ring, sphere, and solid cylinder can be calculated using the formulas:
I_ring = m*r^2
I_sphere = (2/5)mr^2
I_cylinder = (1/2)mr^2
where m is the mass of the object and r is its radius.
Since all three objects have the same mass and are made from the same material, their radii must be different in order for their moments of inertia to be different. Therefore, the object with the greatest radius will have the greatest moment of inertia. In this case, the solid cylinder has the greatest radius, so it has the greatest moment of inertia.
d) The linear acceleration of each object can be calculated using the formula:
a = gsin(theta)(1 - mu*cos(theta))
where mu is the coefficient of static friction between the object and the slope.
For the given values, we have:
a_ring = 9.81sin(20°)(1 - 0.3cos(20°)) ≈ 1.52 m/s^2
a_sphere = 9.81sin(20°)(1 - 0.3cos(20°)) ≈ 1.52 m/s^2
a_cylinder = 9.81sin(20°)(1 - 0.3*cos(20°)) ≈ 1.52 m/s^2
Therefore, all three objects have the same linear acceleration.
e) The tangential (linear) velocity of each object can be calculated using the formula:
v = r*omega
where omega is the angular velocity of the object, which can be calculated using the formula:
omega = a/r
where a is the linear acceleration of the object and r is its radius.
For the given values, we have:
v_ring = r*omega = r(a/r) = a ≈ 1.52 m/s
v_sphere = r*omega = r(a/r) = a ≈ 1.52 m/s
v_cylinder = r*omega = r(a/r) = a ≈ 1.52 m/s
So, all three objects have the same tangential (linear) velocity.
Therefore, a) The order in which the objects reach the bottom of the slope depends on their moments of inertia, b) All three shapes will reach the bottom of the slope in approximately the same amount of time, which is around 0.42 seconds, c) The solid cylinder has the greatest moment of inertia, d) All three objects have the same linear acceleration of approximately 1.52 m/s^2, and e) All three objects have the same tangential (linear) velocity of approximately 1.52 m/s.
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The general gas law can be written as
5
Type the correct answer in the box. Spell all words correctly.
Complete the sentence.
is the sacrifice involved in making one decision over another.
Reset
Next
2
The sacrifice involved in making one decision over another is known as opportunity cost.
What is opportunity cost?The opportunity cost of a choice is described as the value of the best alternative forgone where, given limited resources, a choice needs to be made between several mutually exclusive alternatives.
When talking about an opportunity cost, it is referred to as those benefits that exist when making a decision which could either be in business or a personal decision.
The law of increasing opportunity cost sates that as you increase the production of one good, the opportunity cost to produce the additional good will increase . It is always recommended to make a cost-benefit analysis to contemplate all the benefits.
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#complete question:
What is the sacrifice involved in making one decision over another ?
A student creates a dichotomous key to identify common household pets. What is wrong with this key?
Pet dichotomous key
A. Hamsters have hairy bodies.
B. Goldfish don't live in cages.
C. A pet can have a hairy body and live in a cage, or can be hairless and not live in a cage.
D. All of the above.
A student creates a dichotomous key to identify common household pets. The wrong key is option C. A pet can have a hairy body and live in a cage, or can be hairless and not live in a cage.
What is the dichotomous key?A dichotomous key is an instrument utilized for the classification and identification of living organisms by examining their visible traits. It is comprised of a sequence of decisions or actions which guide the user towards accurately identifying the organism.
Every decision or move involves selecting between two alternative options or features that are contradictory to each other. Furthermore, the correct answer identified as option C acknowledges that pets can possess different traits and may not necessarily conform to a specific classification.
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Which statements accurately compare the tectonic activity of the planets? Check all that apply. The terrestrial planets experience quakes; the gas giants do not. The gas giants have multiple plates; the terrestrial planets do not. The gas giants have no true surfaces, so they experience tectonic activity. Terrestrial planets experience (or experienced) tectonic activity; gas giants do (or did) not. Mountains and volcanoes are found on the gas giants, not on terrestrial planets. Activity in the molten interior of the terrestrial planets results (or resulted) in tectonic activity.
1. The terrestrial planets experience quakes; the gas giants do not. 4.Terrestrial planets experience tectonic activity; gas giants do not.
6. Activity in molten interior of the terrestrial planets results in tectonic activity. Correct options are: 1, 4, 6.
Terrestrial planets, such as Earth, Mars, and Venus, have a solid surface that is broken into several pieces called tectonic plates. Gas giants like Jupiter and Saturn, on other hand, do not have a solid surface and, therefore, do not experience quakes. For example, is responsible for the formation of mountains, ocean basins, and other geological features. Heat generated by decay of radioactive elements within Earth's core causes convection currents, which move the tectonic plates around. Hence Correct answer: 1,4,6.
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--The complete Question is, Which statements accurately compare the tectonic activity of the planets?
Check all that apply.
1. The terrestrial planets experience quakes; the gas giants do not.
2. The gas giants have multiple plates; the terrestrial planets do not.
3. The gas giants have no true surfaces, so they experience tectonic activity.
4. Terrestrial planets experience (or experienced) tectonic activity; gas giants do (or did) not. 5. Mountains and volcanoes are found on the gas giants, not on terrestrial planets.
6. Activity in the molten interior of the terrestrial planets results (or resulted) in tectonic --
**NEED ANSWER ASAP**
Why is it difficult to determine the structure of the MW and how does modern astronomy get around the problem?
**FAKE ANSWERS WILL BE REPORTED
4. A 40.0 kg child swings in a swing supported by two chains, each 3.00 m long. If the tension in each at the lowest point is 350N, find (i) The child’s speed at the lowest point ,
The child's speed at the lowest point is 5.42 m/s.
At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.
Using the conservation of mechanical energy, we can write:
Potential energy at highest point = Kinetic energy at lowest point
mgh = (1/2)mv²
where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.
First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:
h = (1/2)3.00 m = 1.50 m
Next, we can solve for the child's speed at the lowest point:
mgh = (1/2)mv²
40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²
588 J = 20.0 kg * v²
v² = 29.4 m²/s²
v = 5.42 m/s
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Need help for this Asap please
The coefficient of static friction between the block of wood and the table is 0.449.
How to calculate the frictionThe weight of the block of wood is Mg = 4.0 kg × 9.81 m/s^2 = 39.24 N.
The coefficient of static friction μs is given by the equation μ_s = fs/N, where N is the normal force from the table.
Since the block is not accelerating vertically, we know that N = Mg, so we have:
μs = fs/N = 17.64 N / 39.24 N = 0.449
Therefore, the coefficient of static friction between the block of wood and the table is 0.449.
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A car moving with a speed of 40km/h can be stopped by applying the brakes after atleast 2m. If the same car is moving with the speed 80k/h what is the minimum stopping distance?
The minimum stopping distance is determined as 8 m.
What is the minimum stopping distance?The minimum stopping distance of the car is calculated as follows;
d = (u²)/(2a)
where;
d is the minimum stopping distanceu is the initial velocitya is the acceleration of the carwhen the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s
2 = (11.11²)/(2a)
a = (11.11²)/(2 x 2)
a = 30.86 m/s²
when the speed becomes 80 km/h, the minimum stopping distance is calculated as;
u = 80 km/h = 22.22 m/s
d = (22.22² )/ (2 x 30.86)
d = 8 m
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A record has an angular speed of
38.9 rev/min.
What is its angular speed?
Answer in units of rad/s.
pt 2
Through what angle does it rotate in 1.9 s?
Answer in units of rad
The record will rotate through an angle of 1.24°.
Angular speed of the record, ω = 38.9 rev/min = 0.65 rev/s
Time taken for the rotation, t = 1.9 s
Motion in a circular path or around the circumference of a circle is referred to as circular motion. It may rotate at a particular speed and angular rate or it may rotate at a variable rate, making it either uniform or non-uniform circular motion.
The angular speed is the rate of change of angular displacement.
Therefore, angular displacement of the record,
θ = ωt
θ = 0.65 x 1.9
θ = 1.24°
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What fraction of the total kinetic energy is rotational for the following objects rolling without slipping on a horizontal sur- face? (a) a uniform solid cylinder; (b) a uniform sphere; (c) a thin- walled, hollow sphere; (d) a hollow cylinder with outer radius R and inner radius R>2.
The ratio of their rotational kinetic energies is 4/5 or 0.8.
Let's denote the mass and radius of the cylinder and sphere as "m" and "r", respectively. At the top of the incline, both objects have only potential energy, which is then converted to kinetic energy. At the bottom of the incline, both objects have both translational and rotational kinetic energy.
For a uniform solid cylinder, the rotational inertia is[tex]1/2 * m * r^2[/tex]. For a uniform sphere, the rotational inertia is[tex]2/5 * m * r^2[/tex]. Therefore, the ratio of their rotational kinetic energies is:
(rotational kinetic energy of sphere) / (rotational kinetic energy of cylinder)
[tex]= (2/5 * m * r^2 * (v/r)^2) / (1/2 * m * r^2 * (v/r)^2)[/tex]
= (4/5)
Therefore, rotational kinetic energy of sphere is 80% of rotational kinetic energy of the cylinder at bottom of the incline.
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--The complete Question is, A uniform solid cylinder and a uniform sphere with the same mass and radius are released from rest at the top of an incline. They both roll without slipping down the incline and reach the bottom with the same translational speed. What is the ratio of their rotational kinetic energies at the bottom of the incline?--
A 3250 kg car slows down from 20.0 m/s to a stop in 5.33 s. How much force would be required to stop the car?
The force required to stop the car of mass 3250 kg is -12195.12 N.
What is force?Force is the product of mass and acceleration.
To calculate the force required to stop the car, we use the formula below
Formula:
F = m(v-u)/t.....................Equation 1Where:
F = Force required to stop the carm = Mass of the carv = Final speedu = Initial speedt = TimeFrom the question,
Given:
m = 3250 kgv = 0 m/su = 20 m/st = 5.33 sSubstitute these values into equation 1
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A ball is thrown upwards at 19.50m/s from a window 58.52m above the ground. When does it strike the ground?
The ball will strike the ground after 8.04 seconds.
Kinematic motion problemUsing the kinematic equation for displacement:
y = y0 + v0t - 1/2g*t^2
where:
y = final displacement (ground level), y = 0 my0 = initial displacement (window), y0 = 58.52 mv0 = initial velocity, v0 = 19.50 m/s (upwards)g = acceleration due to gravity, g = 9.81 m/s^2 (downwards)We want to findt, let's substitute the values:
0 = 58.52 + 19.50t - 1/2(9.81)*t^2
4.905t^2 - 19.50t - 58.52 = 0
Using the quadratic formula:
t = (-b ± sqrt(b^2 - 4ac)) / 2a
where:
a = 4.905b = -19.50c = -58.52t = (-(-19.50) ± sqrt((-19.50)^2 - 4(4.905)(-58.52))) / 2(4.905)
t = (19.50 ± 31.37) / 9.81
The two possible solutions are:
t1 = 5.61 s (ball on the way up)
t2 = 8.04 s (ball on the way down)
Since the question is asking for when the ball strikes the ground, we take the larger solution, which is:
t = 8.04 s
In other words, the ball will strike the ground after 8.04 seconds.
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An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)
An astronaut measure the period of a mass spring system on Earth.
The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.
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which of the following is not a environmental factor that would affect the hamsters growth
Answer: B
Explanation:
Please help with the question below. I also attached a picture of the apparatus along with the question as well. Thank you in advance!
3) Suppose that the apparatus shown in the figure to the right is to be used to measure the speed of sound. The apparatus contains a tube that is open on both ends which has been placed into a beaker containing tap water. The distance between the top of the tube and the water level varies by raising or lowering the tube. Suppose that each lab group is provided with this apparatus as well as a ruler and tuning forks of various frequencies. By striking any particular tuning fork near the top of the tube, a standing wave may be created by adjusting the distance between the water level in the tube and the top of the tube.
(a) Design an experiment using the materials described above with the objective of measuring the speed of sound in air. Include steps to reduce uncertainty and include steps for describing your observations narratively and graphically.
(b) Consider the dependent variable(s) and independent variable(s) in your experiment. Make a sketch of the graph showing the general relationship between these variables and describe a method of graphical analysis that can be used to determine the speed of sound from the data.
(c) Suppose that two lab groups in different locations came up with different results. Other than measurement error, briefly describe two potential reasons for the differences.
The experiment to measure the speed of sound will involve recording the time for the loudest sound to be heard.
What are the dependent and the independent variables in the experiment?The dependent variable in the experiment is the time and the independent variable is the frequencies of the tuning fork.
Some potential reasons for the two lab groups in different locations coming up with different results include:
the difference in temperature - the speed of sound is affected by temperature. The speed of sound generally increases with an increase in temperature.humidity - the difference in humidity in the two locations will affect the result the group obtains.Learn more about the speed of sound at: https://brainly.com/question/2142871
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a student measured the length of awire four times using ameter rule and obtained the following reading 18.6,18.5,18.6,18.5 determine the length
The student measured the length of a wire four times and the total length from the reading is 18.55 m.
From the given,
The length of the wire measured by the student using a meter rule is :
l₁ = 18.6 m
l₂ = 18.5m
l₃ = 18.6m
l₄ = 18.5 m
The total length of the wire is obtained from the average values of length.
Total length (L) = (l₁ + l₂ + l₃ + l₄)/4
L = (18.6 + 18.5 + 18.6 + 18.5) / 4
= 74.2 /4
= 18.55
Hence, the actual length of the wire = 18.6 m.
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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
a student measured the length of awire four times using ameter rule and obtained the following reading 18.6,18.5,18.6,18.5 determine the length
A student measured the length of a wire four times using a meter rule, then average length will be 18.55 cm
A student measured the length of a wire four times using a meter rule and obtained the following reading 18.6,18.5,18.6,18.5.
To determine the length of the wire, we need to calculate the average of the four measurements.
Wadding up all the readings and dividing by the number of readings.
Average length = (18.6 + 18.5 + 18.6 + 18.5) / 4
Average length = 74.2 / 4
Average length = 18.55 cm
Therefore, the length of the wire is approximately 18.55 cm.
The question is incomplete and the complete question is
'' A student measured the length of a wire four times using a meter rule and obtained the following readings: 18.6 cm; 18.5 cm and 18.6 cm. Determine the length the length the student should record''.
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A vacuum gage indicates that the pressure of carbon dioxide in a closed tank is −10 kPa. A mercury barometer gives the local atmospheric pressure as 750 mmHg. Determine the absolute pressure of the carbon dioxide, in kPa. The density of mercury is 13.59 g/cm3 and g is 9.81 m/s2.
A mercury barometer gives the local atmospheric pressure as 750 mmHg, then the absolute pressure of carbon dioxide is 89.87 kPa.
A vacuum gage indicates that the pressure of carbon dioxide in a closed tank is −10 kPa. A mercury barometer gives the local atmospheric pressure as 750 mmHg.
To determine the absolute pressure of carbon dioxide, we need to add the atmospheric pressure to the pressure indicated by the vacuum gauge.
Converting the atmospheric pressure from mmHg to kPa
750 mmHg x (101.3 kPa / 760 mmHg) = 99.87 kPa
Absolute pressure of carbon dioxide
-10 kPa + 99.87 kPa = 89.87 kPa
Therefore, the absolute pressure of carbon dioxide is 89.87 kPa.
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What is the total resistance in the circuit?
The total resistance in the circuit is 30 ohms. Option d is correct.
In an electric circuit, resistors can be connected in different ways, such as in series or parallel. When resistors are connected in series, the total resistance is equal to the sum of the individual resistances. This is because the same current flows through each resistor, and the total voltage across the resistors is divided among them.
The resistances in series is the sum of all resistances. The three resistances are, 10 ohms, 15 ohms and 5 ohms. Therefore,
Total Resistance = 10 ohms + 15 ohms + 5 ohms = 30 ohms.
Hence, option d is correct.
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