Answer:
y
Explanation:
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What is the resistance of resistor R1?
(1 point)
3.00 Ω
200 Ω
7.50 Ω
5.00 Ω
Answer: The answer is 3.00 Ω
Explanation:you join R1 up with R2.
Explain how the diffraction of light shows that light behaves like a wave.
Use key terms: Point source, circular wave pattern, and overlapping waves.
The way that light refracts is the same as how a wave would refract. The way that light diffracts is the same as how a wave would. Similar to how interference occurs in waves, it also occurs in light.
What evidence does light's diffraction provide that it behaves like a wave?Light will shift directions as it travels from one medium, like the air, to another, like the ocean. Light behaves in a similar manner to other waves, like sound waves.
How does the phenomenon of diffraction affect how light behaves as a wave?The bending and spreading of waves around a barrier is known as diffraction. Because you can bend and block out specific light waves, it has to do with how light behaves as a wave.
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A car on a freeway ramp starts at a velocity of 12.0 m/s. If its average acceleration over 8 s is 3.20 m/s2, what is the velocity at the end of that interval?
A. 13.6 m/s
B. 99.2 m/s
C.25.6 m/s
D. 37.6 m/s
Answer: D. 37.6 m/s
Explanation: its D
A roller couster turns in a circular path that has a radius of 25 meters, what's the fastest Velocity the roller coaster can travel without exceeding a centripetal acceleration of 16m/s^2
The fastest velocity that the roller coaster can travel without exceeding a centripetal acceleration of 16 m/s^2 is 20 m/s.
What is velocity ?
Velocity can be defined as the displacement of the object in unit time.
The centripetal acceleration (ac) of an object moving in a circular path with radius (r) and velocity (v) is given by the formula:
ac = v^2 / r
We want to find the maximum velocity (v) that the roller coaster can travel without exceeding a centripetal acceleration of 16 m/s^2, given that the radius of the circular path is 25 meters. We can rearrange the formula to solve for v:
v^2 = ac * r
v = sqrt(ac * r)
Substituting the given values, we get:
v = sqrt(16 m/s^2 * 25 m) = sqrt(400 m^2/s^2) = 20 m/s
Therefore, the fastest velocity that the roller coaster can travel without exceeding a centripetal acceleration of 16 m/s^2 is 20 m/s.
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