Both Nori and her brother Sean made the same amount in interest, $100, assuming that their investments lasted 1 year.
What is interest?The interest refers to the income or payment received or made for giving or taking credit from a lender.
The interest is usually depicted using a rate, which is expressed over 100.
Nori's Investment = $5,000
Interest rate = 2%
Interest amount = $100 ($5,000 x 2%)
Sean's investment = $10,000
Interest rate = 1%
Interest amount = $100 ($10,000 x 1%)
Thus, Nori and Sean equally made $100 in interest from their investments.
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The circle at each end of the court that surrounds the free throw line is the same size as the jump ball circle. (In other words, they have the same radius. ) What is the area of the rectangle (called the lane) whose length is 19 feet and whose width is the free throw line?
So the area of the rectangle (or lane) whose length is 19 feet and whose width is the free throw line, together with the two circles at each end of the court that surround the free throw line, is approximately 450.39 square feet.
What is the length of the rectangle and how many free throw line square feet?Since the circle at each end of the court that surrounds the free throw line is the same size as the jump ball circle, they both have the same radius. Let's call this radius "r".
The diameter of the circle is equal to the width of the lane, which is the same as the width of the free throw line. Therefore, the diameter of the circle is also 12 feet (the width of the free throw line is always 12 feet).
We know that the area of a circle is given by the formula A = πr^2, so the area of each circle is πr^2.
The rectangle (or lane) has a length of 19 feet and a width of 12 feet. Therefore, its area is simply the product of its length and width, which is:
A = 19 feet * 12 feet
A = 228 square feet
Since there are two circles, the total area of the circles is 2πr^2.
We know that the diameter of the circle is equal to the width of the lane, which is 12 feet. Therefore, the radius is half of the diameter, or:
r = 12 feet / 2
r = 6 feet
Now we can calculate the area of the circles:
A = 2πr^2
A = 2π(6 feet)^2
A = 72π square feet
Therefore, the total area of the rectangle and circles (or lane and circles) is:
A_total = A_rectangle + A_circles
A_total = 228 square feet + 72π square feet
A_total ≈ 450.39 square feet
So the area of the rectangle (or lane) whose length is 19 feet and whose width is the free throw line, together with the two circles at each end of the court that surround the free throw line, is approximately 450.39 square feet.
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Two factories blow their whistles at exactly the same time. If a man hears the two blasts exactly
4. 2 seconds and 5. 9 seconds after they are blown and the angle between his lines of sight to the two
factories is 40. 8°, how far apart are the factories? Give your result to the nearest meter. (Use the fact
that sound travels at 344 m/sec. )
A) 2903 meters
B) 3263 meters C) 1329 meters D) 1997 meters
The distance between the factories is approximately 1704 meters.
To solve this problem, we can use the Law of Cosines. Let's denote the distance between the man and Factory 1 as x, the distance between the man and Factory 2 as y, and the distance between the factories as z.
Given that the time difference for the man to hear the blasts from Factory 1 and Factory 2 is 4.2 seconds and 5.9 seconds respectively, we can calculate x and y using the speed of sound (344 m/s):
x = 4.2 seconds * 344 m/s = 1444.8 meters
y = 5.9 seconds * 344 m/s = 2030.4 meters
Now, we apply the Law of Cosines using the given angle of 40.8°:
z² = x² + y² - 2xy * cos(40.8°)
z² = 1444.8² + 2030.4² - 2(1444.8)(2030.4) * cos(40.8°)
z² ≈ 2904106.33
Take the square root to find the distance between the factories:
z ≈ √2904106.33 ≈ 1704.14 meters
Rounded to the nearest meter, the distance between the factories is approximately 1704 meters. However, this answer is not included in the given options. There might be an error in the question or the provided options.
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Arturo has completed 27 math problems, which is 75% of the assignment. How many problems total did he have to complete?
I need help!
The total number of problems he solved is 36 if after completion of 27 problems he has completed 75% of the assignments.
Percentage of completion = 75 % of the work
The percentage can be converted to decimal by dividing the percentage by 100.
Thus, the part that has been completed = 75% = 0.75 of the work
The number of questions done = 27
Let the total number of questions be x
Thus, 75% of x is given as 27
75% of x = 27
0.75 * x = 27
0.75x = 27
x = 27/0.75
x = 36
Thus, the total number of questions is 36.
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The rent for an apartment was $6,600 per year in 2012. If the rent increased at a rate of 4% each year thereafter, use an exponential equation to find the rent of the apartment in 2017. (Write your answer in dollars, such as $XX. XX)
The rent for the apartment using exponential equation in 2017 was $8,029.91.
To find the rent of the apartment in 2017, we will use an exponential equation. An exponential equation is a mathematical expression where a variable is raised to a power, often used to model growth or decay. In this case, we will model the growth of the rent over time.
1. Identify the initial rent, the growth rate, and the number of years that have passed since 2012.
Initial rent (A0): $6,600
Growth rate (r): 4% = 0.04
Number of years (t): 2017 - 2012 = 5
2. Write the exponential equation for the rent increase:
At = A0 * (1 + r)^t
3. Plug in the given values and calculate the rent in 2017:
At = $6,600 * (1 + 0.04)^5
4. Calculate the rent:
At = $6,600 * (1.04)^5
At = $6,600 * 1.2166529
At = $8,029.91
The rent for the apartment in 2017 was $8,029.91. This was calculated using an exponential equation, which allowed us to account for the 4% annual increase in rent over the 5 years since 2012.
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an army has 200 tanks. tanks need maintenance 10 times per year, and maintenance takes an average of 2 days. the army would like to have an average of at least 180 tanks working. how many repairmen are needed? assume exponential interarrival and service times. (hint: use a oneway data table.)
Here is the expected number of broken machines or tanks and K is the total number of tanks. So (K-L) gives the number of tanks in working condition.
The number of repairmen (R) needed to have an average of at least 180 tanks working is to be determined. Thus as observed from the results obtained for one-way data table, the value of R such that (K-L) is at least 180 is R = 11 repairmen
The Expected number of broken or bad machines (L) is
[tex]L=\sum j\pi_i[/tex]
The Expected number of machines waiting for service (1) is
[tex]L=\sum (j-R)\pi_i[/tex]
An expected number of words is often used as a guideline to ensure that the content is neither too long nor too short. In this case, the expected number is 150 words. A 150-word piece of writing can be considered a short composition. It is long enough to convey a basic idea or message, but not so long that it becomes tedious to read. This length is often used in blog posts, news articles, and social media updates.
When writing a 150-word piece, it is important to make every word count. The writing should be clear and concise, with each sentence contributing to the overall message. It may also be helpful to outline the main points before starting to write to ensure that the piece stays focused.
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PLEASE HELP!!
Solve for measure of angle a.
a = [?]°
Answer:
∠ a = 125°
Step-by-step explanation:
the measure of chord- chord angle a is half the sum of the measures of the arcs intercepted by the angle and its vertical angle, that is
∠ a = [tex]\frac{117+133}{2}[/tex] = [tex]\frac{250}{2}[/tex] = 125°
Tina is standing at the bottom of a hill. Matt is standing on the hill so that when Tina's line of sight is
perpendicular to her body, she is looking at Matt's shoes.
a. If Tina's eyes are 5 feet from the ground and 14. 5 feet from Matt's shoes, what is the angle of elevation of
the hill to the nearest degree? Explain.
The angle of elevation of the hill to the nearest degree is 44°.
The angle of elevation is the angle formed between the horizontal and an observer's line of sight to an object that is located above the observer. In this case, Tina is standing at the bottom of the hill and looking up at Matt who is standing on the hill. When Tina's line of sight is perpendicular to her body, she is looking at Matt's shoes.
This means that the line of sight forms a right angle with the ground.
To find the angle of elevation, we can use trigonometry. We know that the opposite side is the height of the hill (from Matt's shoes to the top of the hill), which is not given in the problem. However, we can use the Pythagorean theorem to find it.
Let h be the height of the hill. Then,
h^2 = (14.5)^2 - (5)^2
h^2 = 198.25
h ≈ 14.1 feet
Now, we can use the tangent function to find the angle of elevation.
tan θ = opposite/adjacent = h/14.5
tan θ = 14.1/14.5
θ ≈ 44.2°
Therefore, the angle of elevation of the hill to the nearest degree is 44°. This means that the hill slopes upward at an angle of 44° from the ground, as viewed from Tina's position at the bottom.
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Which describes the intersection of the plane and the solid? a: triangleb: rectanglec: parallelogram d: trapezoid
The solid being referred to is a cuboid and the plane that intersects it creates a triangular shape, then the intersection of the plane and the solid would be described as Triangle. Option A is the correct answer.
If a cuboid is being sliced by a plane that creates a triangular shape within the solid, then the intersection of the plane and the solid would take the form of a triangle.
However, it's important to note that this answer only applies to the specific scenario in which a cuboid is being sliced and the resulting intersection appears triangular.
In general, the intersection of a plane and a solid could take on a variety of shapes, including rectangles, parallelograms, or trapezoids, depending on the specific solid and plane in question.
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Given the following demand function, q = D(x) = 1536 - 2x², find the following: a. The elasticity function, E(x). b. The elasticity at x = 20. c. At x = 20, demand (circle one) is elastic has unit elasticity is inelastic d. Find the value(s) of x for which total revenue is a maximum (assume x is in dollars).
a. The elasticity function: E(x) = -8x²/(1536-2x²)
b. The elasticity at x = 20 is -2.78.
c. At x = 20, demand is elastic.
d. The value of x for which total revenue is a maximum is $12.
a. The elasticity function, E(x), can be calculated using the formula:
E(x) = (dQ/Q) / (dx/x)
where Q is the quantity demanded and x is the price. In this case, we have:
Q = D(x) = 1536 - 2x²
Taking the derivative with respect to x, we get:
dQ/dx = -4x
Using this, we can calculate the elasticity function:
E(x) = (dQ/Q) / (dx/x) = (-4x/(1536-2x²)) * (x/Q) = -8x²/(1536-2x²)
b. To find the elasticity at x = 20, we substitute x = 20 into the elasticity function:
E(20) = -8(20)²/(1536-2(20)²) = -3200/1152 = -2.78
So the elasticity at x = 20 is -2.78.
c. To determine whether demand is elastic, unit elastic, or inelastic at x = 20, we can use the following guidelines:
If E(x) > 1, demand is elastic.
If E(x) = 1, demand is unit elastic.
If E(x) < 1, demand is inelastic.
Since E(20) = -2.78, demand is elastic at x = 20.
d. To find the value(s) of x for which total revenue is a maximum, we use the formula for total revenue:
R(x) = xQ(x) = x(1536 - 2x²)
Taking the derivative of R(x) with respect to x, we get:
dR/dx = 1536 - 4x²
Setting this equal to zero to find the critical points, we get:
1536 - 4x² = 0
Solving for x, we get:
x = ±12
To determine whether these are maximum or minimum points, we take the second derivative of R(x):
d²R/dx² = -8x
At x = 12, we have d²R/dx² < 0, so R(x) is maximized at x = 12. Therefore, the value of x for which total revenue is a maximum is $12.
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Identify all the lines on the graph with unit rates that are less than 2 and greater than the unit rate of the relationship in the table. X y
7 8
14 16
21 24
The only line on the graph with a unit rate less than 2 is the horizontal line passing through y=8.
To identify the unit rates on the graph, we need to find the slope of the line connecting each pair of points. We can use the formula:
slope = (change in y) / (change in x)
For example, the slope between the first two points (7,8) and (14,16) is:
slope = (16-8) / (14-7) = 8/7
Similarly, we can find the slopes for the other pairs of points:
- between (7,8) and (21,24): slope = (24-8) / (21-7) = 16/14 = 8/7
- between (14,16) and (21,24): slope = (24-16) / (21-14) = 8/7
Notice that all three slopes are equal, which means the graph represents a line with a constant unit rate of 8/7.
To find lines with unit rates less than 2, we need to look for steeper lines on the graph. Any line with a slope greater than 2/8 (or 1/4) will have a unit rate greater than 2.
One way to see this is to note that a slope of 2/8 means that for every 2 units of increase in y, there is 8 units of increase in x. This is equivalent to saying that the unit rate is 2/8 = 1/4. If the slope is greater than 2/8, then the unit rate is greater than 1/4, and therefore greater than 2.
Looking at the graph, we can see that the steepest line has a slope of 2/3, which means it has a unit rate of 2/3. Therefore, any line with a slope greater than 2/3 will have a unit rate greater than 2, and any line with a slope less than 2/3 will have a unit rate less than 2.
To summarize:
- The graph represents a line with a constant unit rate of 8/7.
- Any line with a slope greater than 2/3 has a unit rate greater than 2.
- Any line with a slope less than 2/3 has a unit rate less than 2.
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Find the equation of the parabola described. Find the two points that define the latus rectum, and graph the equation.
Vertex at (0,0); axis of symmetry the y-axis; containing the point (6,4).
What is the equation of the parabola? Find the two points that define the latus rectum.
The equation of the parabola is:
x = ay²The two points that define the latus rectum are (±9/64, 4).
How to find the equation of the parabola?The equation of the parabola with vertex at (0,0) and axis of symmetry the y-axis can be written in the form x = ay^2, where a is a constant. Since the parabola contains the point (6,4), we can substitute these values to solve for a:
6 = a(4²)
6 = 16a
a = 6/16 = 3/8
So the equation of the parabola is x = (3/8)y².
To find the two points that define the latus rectum, we need to determine the focal length, which is the distance from the vertex to the focus.
Since the axis of symmetry is the y-axis, the focus is located at (0, f), where f is the focal length. We can use the formula f = a/4 to find f:
f = a/4 = (3/8)/4 = 3/32
So the focus is located at (0, 3/32). The two points that define the latus rectum are the intersections of the directrix, which is a horizontal line located at a distance of f below the vertex, with the parabola. The directrix is located at y = -3/32.
To find the intersections, we can substitute y = ±(16/3)x^(1/2) into the equation of the directrix:
y = -3/32
±(16/3)[tex]x^(^1^/^2^)[/tex]= -3/32
x = 9/64
So the two points that define the latus rectum are (±9/64, 4).
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they're surprised to see that final stores the value 0.7999999999999999 instead of 0.8. what is the best explanation for that result?
The limited precision of floating-point arithmetic in computers can cause rounding errors, leading to unexpected results such as the value 0.7999999999999999 instead of 0.8. This occurs because certain decimal values cannot be accurately represented in binary form.
This is due to the way floating-point numbers are represented in the computer's memory.
Binary floating-point arithmetic cannot represent every decimal value exactly, so sometimes small rounding errors can occur.
In this case, the value 0.8 cannot be represented exactly in binary floating-point format, so the closest approximation is used, resulting in a slightly different value.
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If a and b, then c. given: the if-then statement's reverse isalso correct. if a is true, b is true, what is c?
If a and b, then c means that if both a and b are true, then c must also be true. This is an example of a conditional statement, where the truth of one proposition (c) is dependent on the truth of the other two propositions (a and b).
Now, given that the reverse of the if-then statement is also correct, we can conclude that if b is true, then a is also true. This means that both a and b are true. Therefore, according to the original statement, c must also be true.
In other words, if a and b are both true, then c must also be true. This is because the conditional statement "if a and b, then c" holds true in this scenario. Therefore, we can conclude that the value of c is true.
Overall, understanding the logic behind conditional statements and their reverses can help us make logical conclusions about the truth of propositions based on the truth of other propositions.
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PLEASEEEEEEEEEEEEEEE HEEEEEEEEEEEELP
If a force of 1500 N is applied on a cart with a mass of 500 Kg, calculate the
acceleration of the cart
Answer:
3 m/s²
Step-by-step explanation:
We can use Newton's Second Law of Motion. The Second Law of Motion states that acceleration is calculated by dividing the force by the mass.
[tex]A=\frac{F}{m}[/tex] with f being the force and m being the mass
We know that the force is 1,500 N and the mass is 500 kg.
So, let's substitute:
[tex]A=\frac{1500}{500}\\A=3[/tex]
So the acceleration of the cart is 3 m/s²
Hope this helps :)
A cylinder and a cone have the same volume. The cylinder has radius x
and height y
. The cone has radius 2x
. Find the height of the cone in terms of y
.
The height of the cone in terms of y is h = y / 4.
How to find the volume of a cone and a cylinder?The cylinder and the cone have the same volume. The cylinder has radius x and height y. The cone has radius 2x.
Therefore,
volume of a cylinder = πr²h
where
r = radiush = heightVolume of a cone = 1 / 3 πr²h
where
r = radiush = heightTherefore,
πr²h = 1 / 3 πr²h
πx²y = 1 / 3 π (2x)²h
πx²y = 1 / 3 π 4x² h
multiply both sides by 3
πx²y = π 4x² h
divide both sides by π 4x²
Hence,
h = πx²y / π 4x²
h = y / 4
Therefore, the height of the cone is h = y / 4.
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The mass of the Rock of Gibraltar is 1. 78 ⋅ 1012 kilograms. The mass of the Antarctic iceberg is 4. 55 ⋅ 1013 kilograms. Approximately how many more kilograms is the mass of the Antarctic iceberg than the mass of the Rock of Gibraltar? Show your work and write your answer in scientific notation
The mass of the Antarctic iceberg is approximately 2.56 × 10¹more kilograms than the mass of the Rock of Gibraltar.
To find out, we can subtract the mass of the Rock of Gibraltar from the mass of the Antarctic iceberg:
4.55 × 10¹³ kg - 1.78 × 10¹² kg = 4.37 × 10¹³ kg
Therefore, the mass of the Antarctic iceberg is about 2.56 × 10¹ (or 25.6) times greater than the mass of the Rock of Gibraltar.
This is because the mass of the Antarctic iceberg is much larger than the mass of the Rock of Gibraltar, as it is a massive block of ice floating in the ocean while the Rock of Gibraltar is a solid rock formation on land.
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True or false?in an equation with two x’s, the solution is the number that makes the two sides equalwhen put in for both x’s.
The given statement "In an equation with two x’s, the solution is the number that makes the two sides equalwhen put in for both x’s is false because in an equation with two x's, the solution is the number that makes the two sides equal when put in for one or both of the x's.
For example, consider the equation 2x + 3 = 5x - 1. To find the solution, we need to find the value of x that makes both sides of the equation equal. We can do this by simplifying the equation:
2x + 3 = 5x - 1
2x - 5x = -1 - 3
-3x = -4
x = 4/3
So the solution to this equation is x = 4/3. Notice that we only substituted the value of x once in the equation, but we still found the solution.
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Moe wants to get to the restaurant at 8:30 a.m. It takes him 20 minutes to drive there. What time should Moe leave for the restaurant? Move numbers to the clock to show the time.
8:10
subtract 20min from 30 min
30-20=10
Answer: He should move at 8:10
Explanation: 10 + 20 = 30 / 30 - 20 = 10
Therefore he should leave at 8:10
Square $ABCD$ has side length 7. What is the length of the diagonal $AC?$ (its a square also)
The length of the diagonal AC in square ABCD is approximately 9.899 units.
To find the length of the diagonal AC, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In our case, since ABCD is a square, angle ABC is a right angle. Therefore, triangle ABC is a right-angled triangle with sides AB and BC both equal to 7 units. We can apply the Pythagorean theorem to find the length of diagonal AC (the hypotenuse):
AC² = AB² + BC²
Plugging in the side lengths:
AC² = 7² + 7² = 49 + 49 = 98
Now, we take the square root of both sides to find the length of AC:
AC = √98 ≈ 9.899
So, the length of the diagonal AC in square ABCD is approximately 9.899 units.
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Find the range and mean of each data set. Use your results to compare the two data sets.
Set A:
1 10 7 17 20
Set B:
10 17 16 18 12
Answer:
Set A: 1, 7, 10, 17, 20
Range: 19
Mean: 11
Set B: 10, 12, 16, 17, 18
Range: 8
Mean: 14.6
How to find...
Mean: Divide the sum of all values in a data set by the number of values.
Range: Find the largest observed value of a variable (the maximum) and subtract the smallest observed value (the minimum).
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a researcher is interested in the disappearance of spotted owls from northwestern forests. she studies 10 breeding pairs of spotted owls in cascade national park for one year. the 10 breeding pairs are the: group of answer choices selected sample snowball sample stratified sample target population
The 10 breeding pairs of spotted owls in Cascade National Park studied by the researcher represent a selected sample. So, the correct answer is A)
The 10 breeding pairs of spotted owls represent a selected sample.
A sample is a subset of a larger population that is chosen for research or study purposes. In this case, the researcher is interested in studying the disappearance of spotted owls from northwestern forests, but it would be impractical to study the entire population of spotted owls in the region.
Therefore, the researcher selected a smaller group of 10 breeding pairs in Cascade National Park as a representative sample to study over the course of one year. The selected sample may help the researcher to draw conclusions about the population of spotted owls in the region. So, the correct option is A).
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--The given question is incomplete, the complete question is given
" a researcher is interested in the disappearance of spotted owls from northwestern forests. she studies 10 breeding pairs of spotted owls in cascade national park for one year. the 10 breeding pairs are the: group of answer choices
selected sample
snowball sample
stratified sample
target population"--
A line includes the points (0,-7) and (n, -8) has a slope of -1/6. What is the value of n?
Answer:
n = 6.
Step-by-step explanation:
The slope of the line = (y2 - y1) / (x2 - x1) where the 2 points are (x1, y1) and (x2, y2).
So, (-8 - (-7)) / (n - 0) = -1/6
-1/n = -1/6
n = 6.
Ms. Griffin has 0. 8 liters of hot tea and 4 teacups. She will divide the tea evenly among the cups. Which model represents 0. 8 divide by 4
The model that represents Ms. Griffin's situation is 0.8 divided by 4, which equals 0.2 liters of hot tea in each teacup.
To find the amount of tea in each teacup, you need to divide the total amount of tea (0.8 liters) by the number of teacups (4). The model for this is 0.8 ÷ 4. Follow these steps:
1. Divide 0.8 by 4:
0.8 ÷ 4 = 0.2
2. Interpret the result:
Each teacup will have 0.2 liters of hot tea.
So, the model that represents Ms. Griffin's situation is 0.8 divided by 4, which equals 0.2 liters of hot tea in each teacup.
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Enter the y coordinate of the solution to this system of equations. 3x+y=-2 x-2y=4
The y coordinate of the solution to this system of equations is -2
Calculating the y coordinate of the solution to this system of equations.From the question, we have the following parameters that can be used in our computation:
3x+y=-2 x-2y=4
Express properly
So, we have
3x + y = -2
x - 2y = 4
Multiply the second equation by -3
so, we have the following representation
3x + y = -2
-3x + 6y = -12
Add the equations to eliminate x
7y = -14
Divide both sides by 7
y = -2
Hence, the value of y is -2
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C C
A student believes that a certain number cube is unfair and is more likely to land with a six facing up. The student rolls
the number cube 45 times and the cube lands with a six facing up 12 times. Assuming the conditions for inference
have been met, what is the 99% confidence interval for the true proportion of times the number cube would land with a
six facing up?
0. 27 2. 58
0. 221-0. 27)
45
0. 7342. 33
0. 731-0. 73)
45
0. 27 2. 33
0. 271 -0. 20)
45
0. 73 +2. 58
0. 73(10. 73)
45
Mix
Save and Exit
The answer is option B: (0.221-0.27).
Using the formula for a confidence interval for a proportion:
p± z*√(p(1-p)/n)
where p is the sample proportion (12/45 = 0.267), z* is the z-score for the desired confidence level (99% corresponds to a z-score of 2.576), and n is the sample size (45).
Substituting the values, we get:
0.267 ± 2.576*√(0.267(1-0.267)/45)
which simplifies to:
0.267 ± 0.195
Therefore, the 99% confidence interval for the true proportion of times the number cube would land with a six facing up is (0.072, 0.462).
So the answer is option B: (0.221-0.27).
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[4 marks) Find the unit tangent vector T and the principal unit normal vector N at t=0 for = r(t) = ti+at+j+ + 3 tk. NI
The unit tangent vector T is (1/√10)i + (3/√10)k
The principal unit normal vector N is j.
vector function r(t) = ti + at²j + 3tk.
Step 1: Find the derivative of r(t) with respect to t, which gives us the tangent vector.
r'(t) = (1)i + (2at)j + (3)k
Step 2: Evaluate r'(t) at t=0.
r'(0) = (1)i + (2a*0)j + (3)k = i + 3k
Step 3: Find the magnitude of r'(0).
|r'(0)| = √(1^2 + 3^2) = √10
Step 4: Normalize r'(0) to find the unit tangent vector T.
T = r'(0) / |r'(0)| = (1/√10)i + (3/√10)k
Step 5: Find the second derivative of r(t) with respect to t.
r''(t) = (0)i + (2a)j + (0)k
Step 6: Evaluate r''(t) at t=0.
r''(0) = (0)i + (2a)j + (0)k = 2aj
Step 7: Find the magnitude of r''(0).
|r''(0)| = √(2a)^2 = 2a
Step 8: Normalize r''(0) to find the principal unit normal vector N.
N = r''(0) / |r''(0)| = (2a/2a)j = j
So, at t=0, the unit tangent vector T is (1/√10)i + (3/√10)k, and the principal unit normal vector N is j.
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Find the inverse for each relation: 4 points each
1. {(1,‐2), (2, 3),(3, ‐3),(4, 2)}
2. {(4,2),(5,1),(6,0),(7,‐1)}
Find an equation for the inverse for each of the following relations.
3. Y=-8x+3
4. Y=2/3x-5
5. Y=1/2x+10
6. Y=(x-3)^2
Verify that f and g are inverse functions.
7. F(x)=5x+2;g(x)=(x-2)/5
8. F(x)=1/2x-7;g(x)=2x+14
The inverse relation is {(‐2,1), (3, 2),(‐3, 3),(2, 4)}, {(2, 4),(1, 5),(0, 6),(‐1, 7)}, the inverse equation is: y = (-x + 3)/8, y = (3/2)x - (15/2), y = (1/2)x + 10,
x = sqrt(y) + 3 or x = -sqrt(y) + 3 and f(g(x)) = g(f(x)) = x, f and g are inverse functions.
1.To find the inverse of the relation, we need to switch the x and y values of each point and solve for y:
{(‐2,1), (3, 2),(‐3, 3),(2, 4)}
2. Following the same process as above:
{(2, 4),(1, 5),(0, 6),(‐1, 7)}
So the inverse relation is {(2, 4),(1, 5),(0, 6),(‐1, 7)}.
3.To find the equation of the inverse, we can solve for x:
y = -8x + 3
x = (-y + 3)/8
So the inverse equation is: y = (-x + 3)/8.
4. Following the same process as above:
y = (2/3)x - 5
x = (3/2)y + 5
So the inverse equation is: y = (3/2)x - (15/2).
5. Following the same process as above:
y = (1/2)x + 10
x = 2(y - 10)
So the inverse equation is: y = (1/2)x + 10.
6.To find the inverse equation, we need to solve for x:
y = (x-3)^2
x = sqrt(y) + 3 or x = -sqrt(y) + 3
So the inverse equation is: x = sqrt(y) + 3 or x = -sqrt(y) + 3.
7,To verify that f and g are inverse functions, we need to show that f(g(x)) = x and g(f(x)) = x.
f(x) = 5x + 2
g(x) = (x-2)/5
f(g(x)) = 5((x-2)/5) + 2 = x - 2 + 2 = x
g(f(x)) = ((5x + 2)-2)/5 = x/5
Since f(g(x)) = g(f(x)) = x, f and g are inverse functions.
8.Following the same process as above:
f(x) = (1/2)x - 7
g(x) = 2x + 14
f(g(x)) = (1/2)(2x+14) - 7 = x
g(f(x)) = 2((1/2)x - 7) + 14 = x
Since f(g(x)) = g(f(x)) = x, f and g are inverse functions.
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A particle is moving along the x-axis on the interval 0 ≤ t ≤ 10, and its position is given by x of t equals one third times x cubed minus five halves times x squared plus 6 times x minus 10. at what time(s), t, is the particle at rest?
answers:
t = 0
t = 2 and 3
t = 1 and 5
t = 6
The particle is at rest at t = 3. Therefore, the particle is at rest at t = 2 and t = 3.
To find when the particle is at rest, we need to find the values of t where the velocity of the particle is zero.
The velocity function is obtained by taking the derivative of the position function: v(t) = x'(t) = x²(t) - 5x(t) + 6
Setting v(t) = 0, we get a quadratic equation in x(t): x²(t) - 5x(t) + 6 = 0. Factoring the quadratic, we get: (x(t) - 2)(x(t) - 3) = 0
Therefore, x(t) = 2 or x(t) = 3. We now need to check which values of t correspond to these values of x(t).
At x(t) = 2, we get: v(t) = x²(t) - 5x(t) + 6 = 4 - 10 + 6 = 0. Thus, the particle is at rest at t = 2. At x(t) = 3, we get: v(t) = x²(t) - 5x(t) + 6 = 9 - 15 + 6 = 0
Thus, the particle is at rest at t = 3. Therefore, the particle is at rest at t = 2 and t = 3.
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Morgan takes a train from London to Bewford and then another train to Agon.
The tree diagram shows the probabilities of Morgan's trains being late or not late.
to Bewford
to Agon
Late
0.24
Late
0.35
0.76
Not late
Late
0.24
0.65
Not late
0.76
Not
late
Morgan will not catch the train to Agon if the train to Bewford is late and the train to Agon is not late.
Work out the probability that Morgan will catch the train to Agon.
Give your answer as a decimal.
The probability that Morgan will catch the train to Agon is 0.578.
To catch the train to Agon, one of the following conditions must be met:
The train to Bewford is not late and the train to Agon is not late.
The train to Bewford is not late and the train to Agon is late.
The probability of the first condition is:
(0.76) x (0.65) = 0.494
The probability of the second condition is:
(0.24) x (0.35) = 0.084
Therefore, the probability that Morgan will catch the train to Agon is:
0.494 + 0.084 = 0.578 (to three decimal places)
So the probability that Morgan will catch the train to Agon is 0.578.
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Is it possible for a rectangle to have a perimeter of 100 feet and an area of 100 square
feet? Justify your response.
No, it is not possible for a rectangle to have a perimeter of 100 feet and an area of 100 square feet.
How to find the possibility ?The reason it is not possible for a rectangle to have a perimeter of 100 feet and an area of 100 square feet is thanks to the quantity. At some point, the perimeter of a rectangle is larger than the area.
However, as the dimensions increase, it becomes impossible for the perimeter to keep up such that the area keeps increasing. For a rectangle with 100 feet as perimeter, it would not be possible to have an area that is 100 square feet.
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