a sample of what size would be needed to estimate a population mean to within 4 units with 95 percent confidence if the population has a standard deviation of 12?

Answer:

29

Step-by-step explanation:

she spends $75 on the gift cards, which brings the total down to $175 which is how much money she has left. She then spends $123.5 on the 13 movie passes, she is then left with $51.5 to spend. Then you divide 51.5 by 1.75 to get 29.4 and rounds down to 29.

Answer:

  X

Step-by-step explanation:

You want to identify the graph that represents a function.

A graph represents a function if no vertical line intersects the graph in more than one place.

W – the line x=0 intersects the graph at y = -4 and at y = 4. This graph is not the graph of a function.

X – At points where the graph might overlap, one point is identified as not include, (1, -1) for example, while the other point is identified as included (1, 1) for example. This means there is only one function value at that point, so this is the graph of a function.

Y – The vertical line x=-2 intersects the graph in an infinite number of points. This graph is not the graph of a function.

Z – The vertical line x=0 intersects the graph at y = -2, y = 0, and y = 2. This graph is not the graph of a function.

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The best approx. for mean of 10,000 sample means is equal to the population mean which is 84. The Option C is correct.

According to central limit theorem, the distribution of sample means from a large sample size will be normal regardless of the shape of the population distribution.

This is because the mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

The standard deviation of distribution of sample means will be:

= Population standard deviation / √sample size

= 7.2 / √100

= 0.72

So, the best approximation for the mean of 10,000 sample means is equal to the population mean which is 84.

Full question "Suppose we have a large population with mean = 84 and standard deviation = 7.2. 10 points Let's say we randomly sample 100 values from this population and compute the mean, then repeat this sampling process 10,000 times and record all the means we get.  Which of the following is the best approximation for the mean of our 10,000 sample means? A. 8.4 b. 100 c. 84"

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The bottom end of the pendulum travels 18,115.2 meters/day, which is approximately 18.12 kilometers/day (since 1 kilometer = 1000 meters).

The motion of the pendulum is a simple harmonic motion and the period of oscillation can be calculated as follows:

T = 2π√(l/g)

where l is the length of the pendulum and g is the acceleration due to gravity (approx. 9.81 m/s²).

Substituting l = 1 m, we get

T = 2π√(1/9.81)

T ≈ 2.006 s.

In one day, there are

24 hours x 60 minutes/hour x 60 seconds/minute

= 86,400 seconds.

The pendulum makes half a period (i.e., one back-and-forth swing) in 2/2 = 1 second. Therefore, it makes

86,400/2

= 43,200 back-and-forth swings in one day.

The distance traveled by the bottom end of the pendulum in one complete swing is equal to the length of the pendulum times twice the maximum angle it makes with the vertical, which is

2 x 12 degrees

= 24 degrees

= 0.419 radians.

Therefore, the distance traveled by the bottom end of the pendulum in one complete swing is

1 meter x 0.419

= 0.419 meters.

Multiplying by the number of swings in one day, we get:

0.419 meters/swing x 43,200 swings/day

= 18,115.2 meters/day.

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The result of adding -3 (row 1) to row 2 is determined as (0  10) |-14.

The resultant of the row multiplication in the Matrice is calculated by applying the following method;

row 1 in the given matrices = [1  -4] | 8

To multiply row1 by -3, we will multiply each entity by 3 as shown below;

= -3(1  -4) | 8

= (-3  12) | -24

To add the result to 3;

(-3  12) | -24  +  (3   -2)|10

= (0  10) |-14

Thus, the result of the row multiplication is determined by multiplying each entry in row 1, by - 3.

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The equation 5ʷ ⁺ ³ = 17 when solved for w is approximately w = 0.41 and the solution to the inequality is b ≤ 1.87

From the question, we have the following parameters that can be used in our computation:

5ʷ ⁺ ³ = 17

Take the logarithm of both sides

So, we have

w + 3 = ln(17)/ln(3)

Evaluate the quotient

This gives

w + 3 = 2.59

So, we have

-3 + w + 3 = 2.59 - 3

Evaluate

w = 0.41

For the second expression, we have

2ᵇ ⁺ ¹ ≤ 7.31

Take the logarithm of both sides

So, we have

b ≤ ln(7.31)/ln(2) - 1

So, we have

b ≤ 1.87

Hence, the equation when solved for w is approximately w = 0.41

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Answer:

Starting with the equation:

-2x + 6 = -x^2

First, we can rearrange it to put it in standard quadratic form:

x^2 - 2x - 6 = 0

To complete the square, we need to add and subtract a constant term that will make the left-hand side of the equation a perfect square. The constant we need to add is (b/2)^2, where b is the coefficient of x. In this case, b = -2, so:

x^2 - 2x + 1 - 1 - 6 = 0

The first three terms can be written as a perfect square:

(x - 1)^2 - 7 = 0

Add 7 to both sides:

(x - 1)^2 = 7

Now we can take the square root of both sides:

x - 1 = ±√7

Add 1 to both sides:

x = 1 ± √7

So the solutions to the equation are:

x = 1 + √7 or x = 1 - √7

mark me brilliant

Exactly one-year later,

(a) Mean of the ages will be 13 years and 3 months.

(b) Range of the ages will be same 2 years and 7 months.

Part (a) : To find the mean of the ages of the same group of students exactly one year later, we add one year to each student's age and find the new mean.

New mean is : 12 years and 3 months + 1 year = 13 years and 3 months;

So the mean of the ages of the same group of students exactly one year later is 13 years and 3 months.

Part (b) : The range of their ages would still be 2 years and 7 months because we are adding the same amount to all of their ages, the difference between the youngest and oldest member of the group would remain the same.

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Observing the given histogram we know that there are 16 pumpkins that have a mass greater than 6 kilograms.

A histogram is a graph that displays the values of a numeric variable's distribution as a collection of bars.

The height of a bar represents the frequency of data points with values falling within the relevant bin; each bar typically spans a range of numerical values known as a bin or class.

Similar to a bar chart, a histogram is produced with bars of varying widths.

In a histogram, the frequency is revealed by the bar's area rather than its height.

We plot the frequency density rather than frequency on the y-axis. To figure this out, divide a group's frequency by its width.

So, the x-axis of the given histogram represents the mass of the pumpkins.

The y-axis of the histogram represents the number of pumpkins.

Then, the pumpkins with greater mass than 6 kilograms:

= 8 + 6 + 2

= 16

Therefore, observing the given histogram we know that there are 16 pumpkins that have a mass greater than 6 kilograms.

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Answer:

v=12

Step-by-step explanation:

9/v = 6/8

9 = 6v/8

72= 6v

v= 12

Answer:

v = 12

Step-by-step explanation:

Now we have to,

→ Find the required value of v.

Given proportion,

→ (9/v) = (6/8)

Then the value of v will be,

→ (9/v) = (6/8)

→ 9 × 8 = 6 × v

→ 72 = 6v

→ 6v = 72

→ v = 72/6

→ [ v = 12 ]

Hence, the value of v is 12.

Answer:

70.4%

Step-by-step explanation:

Assuming the test is the only graded assignment, and the remaining 80% of her grade is still at 73%, we can calculate Kayla's new overall grade as follows:

New overall grade = (0.80 x 73) + (0.20 x 60)

New overall grade = 58.4 + 12

New overall grade = 70.4

Therefore, Kayla's new overall grade is 70.4%

Answer:

70.4% or a C-.

Step-by-step explanation:

To calculate Kayla's new grade after taking the test, you need to first find out what percentage of her overall grade the test is worth. If the test is worth 20% of her grade, then the remaining 80% of her grade is based on other factors, such as homework, quizzes, and other tests.

To calculate Kayla's new grade, you can use the following formula:

New grade = (Current grade x Weight of current assignments) + (Grade on test x Weight of test)

Plugging in the numbers given in the problem, we get:

New grade = (0.73 x 0.80) + (0.60 x 0.20)

New grade = 0.584 + 0.12

New grade = 0.704

Therefore, Kayla's new grade after taking the test would be approximately 70.4%, or a C-.

The graphs are:

1) not one-to-one

2) one-to-one

3) not one-to-one

A graph represents an one-to-one function only if.

We can't draw a vertical line that touches the graph twice or more.

We can't draw an horizontal line that touches the graph twice or more.

For example, for the first graph, we can see that there are horizontal lines like y = -5 that touch the graph two times.

Similarly forthe third graph, the line y = 0 touches two points-

So these two are not one-to-one.,

For the remaining graph, the middle one, no line touches the graph more than once, so it is one-to-one.

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The constant of variation, k, is defined as the ratio between the two variables' values, multiplied by their respective powers:  [tex]k = y/x^a \times z/x^b,[/tex] where a and b are the powers of x in the expressions for y and z, respectively. when   [tex]x = -3[/tex]  and [tex]y = 4[/tex] , z is equal to -81/16.

In this case, we have x = 8, y = 54, and z = 144, so we need to determine the powers of x in the expressions for y and z:

[tex]y = 54 = (8^a) \times k = > a = 3[/tex]

[tex]z = 144 = (8^b) \times k = > b = 2[/tex]

Substituting these values into the formula for k, we get:

[tex]k = y/x^a \times z/x^b = 54/8^3 \times 144/8^2 = 27/64[/tex]

Therefore, the constant of variation is 27/64.

Using the same formula as above, we can solve for z when x = -3 and y = 4:

[tex]k = y/x^a \times z/x^b[/tex]

We need to determine the powers of x in the expressions for y and z:

[tex]y = 4 = (-3)^a * k = > a = -1[/tex]

[tex]z = ? = (-3)^b * k = >[/tex] we don't know b or z yet

Substituting these values into the formula for k, we get:

[tex]k = y/x^a * z/x^b = 4/(-3)^(-1) * z/(-3)^b = -12z/(-3)^2[/tex]

Simplifying this expression, we get:

[tex]k = -12z/9 = -4z/3[/tex]

Now we can solve for z:

[tex]-4z/3 = 27/64[/tex]

Multiplying both sides by 3/(-4), we get:

[tex]z = -81/16[/tex]

Therefore, when  [tex]x = -3[/tex] and   [tex]y = 4, z[/tex] is equal to   [tex]-81/16.[/tex]

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The surface area of the rectangular prism is 210 in²

An equation is an expression that shows the relationship between numbers and variables using mathematical operators.

The surface area of a rectangular prism is the sum of each area for the surface.

Hence:

Surface area = 2(8 in * 5 in) + 2(5 in * 5 in) + 2(8 in * 5 in) = 210 in²

The surface area of the prism is 210 in²

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The maximum voltage produced by the system is 12 volts.

The function given is:

[tex]v_{inst}(t) = 12 * sin(360 * 60 * 6.3 + 79)[/tex]

To find the maximum voltage produced by the system, we need to determine the maximum value of the sine function within the given range.

Let's focus on the argument of the sine function: 360 * 60 * 6.3 + 79.

First, calculate the value of the argument:

360 * 60 * 6.3 + 79 = 136080 + 79 = 136159

Now, substitute this value back into the sine function:

sin(136159)

The sine function has a periodicity of 360 degrees or [tex]2\pi[/tex] radians. Therefore, we can subtract multiples of 360 degrees from the argument without changing the value of the sine function. Let's find the nearest multiple of 360 degrees to 136159:

136159 ÷ 360 [tex]^\sim_\sim[/tex] 378.22

Since the quotient is not an integer, we can conclude that subtracting multiples of 360 degrees will not bring us closer to a maximum or minimum value of the sine function.

Therefore, to find the maximum voltage, we need to evaluate sin(136159) directly. However, calculating the sine function of such a large number is not practical or necessary. The sine function oscillates between -1 and 1, and the maximum value it can reach is 1.

So, regardless of the specific value of sin(136159), the maximum voltage produced by the system will be:

Maximum voltage = 12 * 1 = 12 volts.

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Answer:

Step-by-step explanation:

However many decimals you move to get 1 after the first number that is not 0 is what goes in the exponent.  Negative version because to get to a decimal you move in the negative direction.

.1  =  1.0 x [tex]10^{-1}[/tex]

.01 = 1.0 x [tex]10^{-2}[/tex]

.001 = 1.0 x [tex]10^{-3}[/tex]

.000001  =,1.0 x [tex]10^{-6}[/tex]

Answer:

X = 6

Y = 17

Step-by-step explanation:

The points GHIJ for a cyclic quadrilateral.

The sum of opposite angles of a cyclic quadrilateral is 180°

So

     ∠J + ∠H = 180°

⇒   6y + 78° = 180°

⇒   6y = 180° - 78°

⇒   6y = 102°

⇒   y = 102°/6

⇒   y = 17°

Similarly for angle x

     ∠I + ∠G = 180°

⇒   16x + 14x = 180°

⇒   30x = 180°

⇒   x = 180°/30

⇒   x = 6°

Answer:

x = 23°

Step-by-step explanation:

We Know

The 67° angle + the x must be equal to 90°

Find the x.

Let's solve

67° + x = 90°

x = 23°

The value of x in the function f(x) = (1/3)^x - 2 such that f(x) = 7 is -2

From the question, we have the following equation that can be used in our computation:

f(x) = (1/3)^x - 2

When the value of f(x) is 7, we have

(1/3)^x - 2 = 7

So, we have

(1/3)^x = 9

Take the log of both sides

x = log(9)/log(1/3)

Evaluate

x = -2

Hence, the value of x is -2

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The decimals as a power of 10 are given as follows:

A number in scientific notation is given by the notation presented as follows:

[tex]a \times 10^b[/tex]

With the base being [tex]a \in [1, 10)[/tex], meaning that it can assume values from 1 to 10, with an open interval at 10 meaning that for 10 the number is written as 10 = 1 x 10¹, meaning that the base is 1, justifying the open interval at 10.

Hence the numbers are represented as follows:

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The sum of 125 (base 7) and 256 (base 7) is 404 (base 7). To compute it, we convert each number to base 10, add them, and then convert the result back to base 7.

Write each number in expanded form using powers of 7.

125 (base 7) = 1 x 7² + 2 x 7¹ + 5 x 7⁰ = 49 + 14 + 5 = 68

256 (base 7) = 2 x 7² + 5 x 7¹ + 6 x 7⁰ = 98 + 35 + 6 = 139

Add the two numbers together to get the sum in decimal form.

68 + 139 = 207

Convert the decimal sum to base 7 using repeated division by 7.

Divide 207 by 7 to get a quotient of 29 and a remainder of 4. Write down the remainder as the rightmost digit in the base 7 representation. Divide 29 by 7 to get a quotient of 4 and a remainder of 1. Write down the remainder as the next digit to the left in the base 7 representation.

Divide 4 by 7 to get a quotient of 0 and a remainder of 4. Write down the remainder as the leftmost digit in the base 7 representation.

So the sum of 125 (base 7) and 256 (base 7) is 404 (base 7).

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Answer:

  (3, 9) and (3, -7)

Step-by-step explanation:

You want the end points of the latus rectum for the parabola defined by ...

 (y -1)² = 16(x +1)

Compare the given equation to the form ...

  (y -k)² = 4p(x -h)

we see that (h, k) = (-1, 1) and p = 16/4 = 4. The ordered pair (h, k) is the vertex of the parabola. The scale factor 'p' gives the distance from the vertex to the focus (and from the directrix to the focus). Larger 'p' values result in a "flatter" parabola.

Since the squared term is a y-term, and the value of 'p' is positive, we know the parabola opens to the right. The end points of the latus rectum are ...

  (h+p, k±2p) = (-1+4, 1±2·4) = (3, 9) and (3, -7)

__

Additional comment

If the roles of x and y are interchanged (the parabola opens up or down), then the end points of the latus rectum are (h±2p, k+p).

On a graph of the parabola, the end points of the latus rectum lie on lines through the vertex with slope ±2 (parabola opens in x-direction), or with slope ±1/2 (parabola opens in y-direction).

The probabilities are given as follows:

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation for this problem is given as follows:

[tex]\mu = 957, \sigma = 193[/tex]

The probability is the p-value of Z when X = 1000.1 subtracted by the p-value of Z when X = 964.6, hence:

Z = (1000.1 - 957)/193

Z = 0.22.

Z = 0.22 has a p-value of 0.5871.

Z = (964.6 - 957)/193

Z = 0.04.

Z = 0.04 has a p-value of 0.5160.

Hence:

0.5871 - 0.5160 = 0.0711.

For the sample of 58, the standard error is obtained as follows:

s = 193/sqrt(58) = 25.34.

Hence:

Z = (1000.1 - 957)/25.34

Z = 1.7.

Z = 1.7 has a p-value of 0.9554.

Z = (964.6 - 957)/25.34

Z = 0.3.

Z = 0.3 has a p-value of 0.6179.

Hence:

0.9554 - 0.6179 = 0.338.

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ans. 1400000

we know that

work done by gravity =  mgh

just putting values we get

= 1400x 100 x 10

= 1400000

hence,work done an elevator motor need to do to lift a 1400kg elevator a height of 100m is 1400000

The area of the circle with a diameter of 22 in in terms of pi is 121π in².

A circle is simply a closed 2-dimensional curved shape with no corners or edges.

The area of a circle is expressed mathematically as;

A = πr²

Where r is radius and π is constant pi.

Given that:

The diameter of the circle is 22 inches.

Radius is half of diameter

Hence:

Radius r = diameter/2 = 22/2 = 11 in

Plug the value into the above formula and solve for area.

A = πr²

A = π × ( 11 in )²

A = 121π in²

Therefore, the area is 121π in².

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B is a 2 by 2 matrix, and the determinant of B written as |B| is equal to -1.

We can find |B|, the determinant of the matrix B by subtracting the multiple of row column and row 2 column 1 from the multiple of row column 1 and row 2 column 2 as follows:

|B| = (-2 × -2) - (1 × 5)

|B| = 4 - 5

|B| = -1.

Therefore, the determinant of the 2 by 2 matrix B written as |B| is equal to -1.

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According to the information, the dilated rectangle would have the dimensions of 2.66cm on the side and 5cm on the base.

To calculate the dimensions of each side of the dilated figure we must identify the dilation factor. In this case it is 3, so we must divide the length of each side into the number of the expansion factor as shown below:

According to the above, the dilated rectangle would remain with the dimensions of 2.66cm on the side and 5cm on the base.

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