Answer:
A = 9x² + 48x + 65
Step-by-step explanation:
Area of a Square Formula: A = lw
Since a square's length is equal to its width, we simply plug it into the formula:
A = (3x + 8)(3x + 8)
Then we simply use FOIL to expand the distribution)
First - 3x(3x) = 9x²
Outside - 8(3x) = 24x
Inside - 8(3x) = 24x
Last - 8(8) = 64
Lastly, we combine like terms
9x² + 24x + 24x + 64
9x² + 48x + 64
Which option is equal to 7 1/5
Answer:
D. is the answerStep-by-step explanation:
Question:
7^1/5
The number given has an exponent of a fraction: fraction exponent = 1/5
So, when you have a fraction - you always have a square root - Important!!Since the top is one, the number 7 stays the same. = 7^1 = 7
The bottom is a 5. This means it is to the fifth root.
Answer = D
Hope this helped,
Kavitha
Answer: If 36/7 is one of the options, choose that one.
If the question involves an exponent, you should use the "caret" which is ^ found above the 6 on a keyboard. [Shift + 6]. That helps avoid confusion.
Step-by-step explanation: 7 is equal to 35/5 because 7×5=35
Add 1/5 and you end up with 36/5. A Common rational number.
7^(1/5) = the 5th root of 7. A very small irrational number!
Examine the system of equations. –2x + 3y = 6 –4x + 6y = 12 Answer the questions to determine the number of solutions to the system of equations. What is the slope of the first line? What is the slope of the second line? What is the y-intercept of the first line? What is the y-intercept of the second line? How many solutions does the system have?
Answer:
Examine the system of equations.
–2x + 3y = 6
–4x + 6y = 12
Answer the questions to determine the number of solutions to the system of equations.
What is the slope of the first line?
✔ 2/3
What is the slope of the second line?
✔ 2/3
What is the y-intercept of the first line?
✔ 2
What is the y-intercept of the second line?
✔ 2
How many solutions does the system have?
✔ infinitely many
The equations are a multiple of the other, therefore, by the multiplicative
property of equality, the equations are equivalent.
Response:
The slope and y-intercept of the first equation are [tex]\underline{\dfrac{2}{3} \ and \ 2}[/tex] respectivelyThe slope and y-intercept of the second equation are [tex]\underline{\dfrac{2}{3} \, and \, 2}[/tex]The system of equations have infinitely many solutions.Methods used to obtain the above response.The given system of equations are;
-2·x + 3·y = 6
-4·x + 6·y = 12
Required:
The slope of the first line.
Solution:
The slope of the first line is given by the coefficient of x when the equation is expressed in the form; y = m·x + c.
Therefore, from -2·x + 3·y = 6, we have;
3·y = 2·x + 6
[tex]y = \dfrac{2}{3} \cdot x + \dfrac{6}{3} = \dfrac{2}{3} \cdot x + 2[/tex]
[tex]y =\dfrac{2}{3} \cdot x + 2[/tex]
[tex]\underline{The \ slope \ of \ the \ first \ equation \ is \ \dfrac{2}{3}}[/tex]
Required:
The slope of the second line;
Solution:
The equation of the second line, -4·x + 6·y = 12, can be expressed in the form;
[tex]y =\dfrac{4}{6} \cdot x + \dfrac{12}{6} = \dfrac{2}{3} \cdot x + 2[/tex]
[tex]y = \mathbf{\dfrac{2}{3} \cdot x + 2}[/tex]
[tex]\underline{The \ slope \ of \ the \ second \ equation \ is \ therefore \ \dfrac{2}{3}}[/tex]
The y-intercept of the first line = 2The y-intercept of the second line = 2Given that the equation have the same slope and the same y-intercept, the equations are equations of the same line, therefore;
The equations have an infinite number of solutionsLearn more about the solutions of a system of equations here:
https://brainly.com/question/15356519
Pls solve ASAP!! Review the attachment and solve. Pls hurry!
Answer:
A. 3
Step-by-step explanation:
ΔDEC is bigger than ΔABC by 5. For the hypotenuse, 25 is 5 times bigger than 5.
So, side DE on ΔDEC has to be 5 times bigger than side AB on ΔABC.
If side AB equals 3, side DE equals 18 - 3, which is 15.
15 is five times bigger than 3, so the answer is A. 3.
Hope that helps.
The sand used for sanding icy roads in the winter is stored in a conical-shaped structure with a radius of 10 m
and a height of 16 m. Calculate the maximum amount of sand which can be stored in this structure.
Answer:
[tex]V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3[/tex]
The maximum amount of sand that can be stored in this structure is 1675.52 m³.
Step-by-step explanation:
The volume of a conical-shaped structure is given by
[tex]V = \frac{1}{3} (\pi \cdot r^2 \cdot h)[/tex]
Where r is the radius and h is the height of the structure.
We are given that
radius = 10m
height = 16m
Substituting the above values into the formula, we get
[tex]V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3[/tex]
Therefore, the maximum amount of sand th can be stored in this structure is 1675.52 m³.
[tex]Let $u$ and $v$ be the solutions to $3x^2 + 5x + 7 = 0.$ Find\[\frac{u}{v} + \frac{v}{u}.\][/tex]
By the factor theorem,
[tex]3x^2+5x+7=3(x-u)(x-v)\implies\begin{cases}uv=\frac73\\u+v=-\frac53\end{cases}[/tex]
Now,
[tex](u+v)^2=u^2+2uv+v^2=\left(-\dfrac53\right)^2=\dfrac{25}9[/tex]
[tex]\implies u^2+v^2=\dfrac{25}9-\dfrac{14}3=-\dfrac{17}9[/tex]
So we have
[tex]\dfrac uv+\dfrac vu=\dfrac{u^2+v^2}{uv}=\dfrac{-\frac{17}9}{\frac73}=\boxed{-\dfrac{17}{21}}[/tex]
The value of [tex]\frac{u}{v} +\frac{v}{u}[/tex] is [tex]\frac{-17}{21}[/tex].
What is quadratic equation?A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is[tex]ax^{2} +bx+c=0[/tex], where a and b are the coefficients, x is the variable, and c is the constant term.
What is the sum and product of the roots of the quadratic equation?If [tex]ax^{2} +bx+c = 0[/tex] be the quadratic equation then
Sum of the roots = [tex]\frac{-b}{a}[/tex]
And,
Product of the roots = [tex]\frac{c}{a}[/tex]
According to the given question.
We have a quadratic equation [tex]3x^{2} +5x+7=0..(i)[/tex]
On comparing the above quadratic equation with standard equation or general equation [tex]ax^{2} +bx+c = 0[/tex].
We get
[tex]a = 3\\b = 5\\and\\c = 7[/tex]
Also, u and v are the solutions of the quadratic equation.
⇒ u and v are the roots of the given quadratic equation.
Since, we know that the sum of the roots of the quadratic equation is [tex]-\frac{b}{a}[/tex].
And product of the roots of the quadratic equation is [tex]\frac{c}{a}[/tex].
Therefore,
[tex]u +v = \frac{-5}{3}[/tex] ...(ii) (sum of the roots)
[tex]uv=\frac{7}{3}[/tex] ....(iii) (product of the roots)
Now,
[tex]\frac{u}{v} +\frac{v}{u} = \frac{u^{2} +v^{2} }{uv} = \frac{(u+v)^{2}-2uv }{uv}[/tex] ([tex](a+b)^{2} =a^{2} +b^{2} +2ab[/tex])
Therefore,
[tex]\frac{u}{v} +\frac{v}{u} =\frac{(\frac{-5}{3} )^{2}-2(\frac{7}{3} ) }{\frac{7}{3} }[/tex] (from (i) and (ii))
⇒ [tex]\frac{u}{v} +\frac{v}{u} =\frac{\frac{25}{9}-\frac{14}{3} }{\frac{7}{3} }[/tex]
⇒ [tex]\frac{u}{v} +\frac{v}{u} = \frac{\frac{25-42}{9} }{\frac{7}{3} }[/tex]
⇒ [tex]\frac{u}{v} +\frac{v}{u} = \frac{\frac{-17}{9} }{\frac{7}{3} }[/tex]
⇒ [tex]\frac{u}{v} +\frac{v}{u} =\frac{-17}{21}[/tex]
Therefore, the value of [tex]\frac{u}{v} +\frac{v}{u}[/tex] is [tex]\frac{-17}{21}[/tex].
Find out more information about sum and product of the roots of the quadratic equation here:
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what's the value? A.-20 B.-4 C.4 D.20
Answer:
-4Option B is the correct option.
Step-by-step explanation:
[tex] {(4 - 2)}^{3} - 3 \times 4[/tex]
Subtract the numbers
[tex] = {(2)}^{3 } - 3 \times 4[/tex]
Multiply the numbers
[tex] = {(2)}^{3} - 12[/tex]
Evaluate the power
[tex] = 8 - 12[/tex]
Calculate the difference
[tex] = - 4[/tex]
Hope this helps..
Best regards!!
Answer:
[tex]\boxed{-4}[/tex]
Step-by-step explanation:
[tex](4-2)^3-3 \times 4[/tex]
Brackets or parenthesis are to be evaluated first. Subtract the numbers in the brackets.
[tex](2)^3-3 \times 4[/tex]
Evaluate the power or exponent.
[tex]8-3 \times 4[/tex]
Multiply the numbers.
[tex]8-12[/tex]
Finally, subtract the numbers.
[tex]=-4[/tex]
Which is the best estimate of 90/7 divided by 1 3/4? 2 6 12 24
Answer:
6 is the best estimate.
Step-by-step explanation:
(90/7) / (1 & 3/4) == (90/7) / (7/4) == (90/7) * (4/7) == 360/49 > 7.
Choose 6 as your best approximation.
1/6.43 +2/3.56 +1/8.51 use reciprocal table.Correct answer only
Answer:
0.8348Step-by-step explanation:
Given the expression 1/6.43 +2/3.56 +1/8.51, If 'a' is a number, the reciprocal of such number is 1/a. According to the question, the reciprocal of 6.43, 3.56 and 8.51 are 1/6.43 and 1/3.56 and 1/8.51 respectively.
1/6.43 = 0.1555
2/3.56 = 2 * 1/3.56
= 2 * 0.2809
= 0.5618
1/8.51 = 0.1175
Taking the sum of the reciprocals;
1/6.43 +2/3.56 +1/8.51 = 0.1555 + 0.5618 + 0.1175
1/6.43 +2/3.56 +1/8.51 = 0.8348
Hence, the sum of 1/6.43, 2/3.56 and 1/8.51 is 0.8348
Which of the following formulas would find the lateral area of a right cylinder
with height equal to hand ras the radius?
O A. LA = 2πr2
O B. LA = 2πr
O C. LA = 2πrh
O D. LA = 2πr2
Answer:
C - LA = 2πrh
Step-by-step explanation:
Lateral surface area of right cylinder = 2 * π * radius * height
Explain how to solve the equation |2x-3| = x^2 graphically. Using a graphing calculator to find all real number solutions to the equation.
Answer:
x = -3 , x = 1
Step-by-step explanation:
Hello,
you need to draw the graph of the two functions and then find the intersection points.
please see below
So the solution is the two points A and B
(-3,9) and (1,1)
Hope this helps
What is the simplest form for the expression (-12.7y-3.1x) Plus 5.9y-(4.2y Plus x)
Answer:
[tex]\boxed{-4.1x-11y}[/tex]
Step-by-step explanation:
[tex](-12.7y-3.1x) + 5.9y-(4.2y + x)[/tex]
Expand brackets.
[tex]-12.7y-3.1x+ 5.9y-4.2y - x[/tex]
Combining like terms.
[tex]- x-3.1x-12.7y+ 5.9y-4.2y[/tex]
[tex]-4.1x-11y[/tex]
Answer:
[tex] \boxed{\red{ - 11y - 4.1x}}[/tex]
Step-by-step explanation:
[tex] (- 12.7y - 3.1x) + 5.9y - (4.2y + x) \\ - 12.7y - 3.1x + 5.9y - 4.2y - x \\ - 12.7y + 5.9y - 4.2y- 3.1x - x \\ = - 11y - 4.1x[/tex]
Solve the equation. \dfrac5{13}=t-\dfrac{6}{13} 13 5 =t− 13 6 start fraction, 5, divided by, 13, end fraction, equals, t, minus, start fraction, 6, divided by, 13, end fraction t=t=t, equals
Answer:
11 /13 = t
Step-by-step explanation:
5/13 = t -6/13
Add 6/13 to each side
5/13 + 6/13 = t -6/13+ 6/13
11 /13 = t
Answer:
[tex]t=\frac{11}{13}[/tex]
Step-by-step explanation:
[tex]\frac{5}{13} = t -\frac{6}{13}[/tex]
Add [tex]\frac{6}{13}[/tex] to both sides.
[tex]\frac{5}{13} + \frac{6}{13} = t -\frac{6}{13} + \frac{6}{13}[/tex]
[tex]\frac{11}{13} =t[/tex]
Dora bought a bottle of nail polish that was marked down by 20 percent from its original price of $4.50. Including a 9 percent sales tax, what is the final cost of the bottle of nail polish?
Answer:
Hey there!
Marked down by 20 percent is equal to 80 percent of the original value.
4.5(0.8)=3.6
9 percent sales tax
3.6(1.09)=3.92
Hope this helps :)
Answer:
$3.92
Step-by-step explanation:
I took the test
HELPPPP The equation 2x = 3y – 5 when written in slope-intercept form is: y = 2x – 5. y = -2x + 5. y = 2x + 5. None of these choices are correct.
Answer:
Y= 2/3x +(5/3)
Step-by-step explanation:
First, have to get Y alone on one side 3y=2x+5
Second, have to get read of the 3 with the Y so divide each side by three.
.
What is y + 3 = 7(2 – 2) written in standard form?
Answer:
y = -3
Step-by-step explanation:
y + 3 = 7(2 - 2)
y + 3 = 0
Subtract 3 from both sides
y + 3 - 3 = 0 - 3
y = -3
Answer:
7x - y = 17
Step-by-step explanation:
Maybe you want the standard form of the point-slope equation ...
y +3 = 7(x -2)
__
y + 3 = 7x -14 . . . . . eliminate parentheses
17 = 7x -y . . . . . . . . add 14-y
7x - y = 17
Please answer it now in two minutes
Answer:
3√6
Step-by-step explanation:
tan60=opp/adj
opp(d)=tan60*3√2=√3*3√2=3√6
graph the circle x2 + y2 - 12x + 6y +36 =0
x^2+y^2-12x+6y+36=0
Top Point: (6,0)
Left Point: (3,-3)
Right Point: (9,-3)
Bottom Point: (6,-6)
Answer:
[tex] x^2 +y^2 -12x +6y +36 =0[/tex]
And we can complete the squares like this:
[tex] (x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2[/tex]
And we got:
[tex] (x-6)^2 + (y+3)^2 = 9[/tex]
And we have a circle with radius r =3 and the vertex would be;
[tex] V= (6,-3) [/tex]
The graph is on the figure attached.
Step-by-step explanation:
For this case we have the following expression:
[tex] x^2 +y^2 -12x +6y +36 =0[/tex]
And we can complete the squares like this:
[tex] (x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2[/tex]
And we got:
[tex] (x-6)^2 + (y+3)^2 = 9[/tex]
And we have a circle with radius r =3 and the vertex would be;
[tex] V= (6,-3) [/tex]
The graph is on the figure attached.
He Perimeter of a
regular decagon is 328cm
stake the length of one of its
sides
Answer:
32.8 cm
Step-by-step explanation:
decagons have 10 sides, so 328/10=32.8
Answer:
32.8 cm
Step-by-step explanation:
A regular decagon has 10 equal sides.
The perimeter of the decagon is 328 centimeters. The perimeter is the measure of all 10 sides added together. Since this is a regular decagon, all 10 sides are equal. Therefore, we can divide 328 by 10.
328 / 10
32.8
Add units, in this case, centimeters or cm.
32.8 cm
Each side of the decagon is 32.8 centimeters.
solve for x, if a solution is extraneous identify in the final answer. thx :)
Answer:
x = 6 and x = 11.
Step-by-step explanation:
sqrt(x - 2) + 8 = x
sqrt(x - 2) = x - 8
(sqrt(x - 2))^2 = (x - 8)^2
x - 2 = x^2 - 16x + 64
x^2 - 16x + 64 = x - 2
x^2 - 17x + 66 = 0
We can use the discriminant to find whether there are solutions to the equation.
b^2 - 4ac; where a = 1, b = -17, and c = 66.
(-17)^2 - 4 * 1 * 66
= 289 - 264
= 25
Since the discriminant is positive, we know there are two valid solutions to the equation.
x^2 - 17x + 66 = 0
(x - 6)(x - 11) = 0
The solutions are when x - 6 = 0 and x - 11 = 0.
x - 6 = 0
x = 6
x - 11 = 0
x = 11
Hope this helps!
Answer:
x=11 solution
x=6 extraneous
Step-by-step explanation:
sqrt( x-2) + 8 = x
Subtract x from each side
sqrt(x-2) = x-8
Square each side
(sqrt(x-2))^2 = (x-8) ^2
x-2 = x^2 -8x-8x+64
x-2 = x^2 -16x+64
Subtract ( x-2) from each side
0 = x^2 -17x +66
Factor
0 = (x-6) ( x-11)
Using the zero product property
x=6 x=11
Checking the solutions
x=6
sqrt( 6-2) + 8 = 6
sqrt(4) +8 = 6
2 +8 = 6
False not a solution
x=11
sqrt( 11-2) + 8 = 11
sqrt(9) +8 =11
3 +8 = 11
solution
Plz write this on paper help me and send it❤️
Answer:
1. [tex]27^{\frac{2}{3} } =9[/tex]
2. [tex]\sqrt{36^{3} } =216[/tex]
3. [tex](-243)^{\frac{3}{5} } =-27[/tex]
4. [tex]40^{\frac{2}{3}}=4\sqrt[3]{25} =4325[/tex]
5. Step 4: [tex](\frac{343}{27}) ^{-1} =\frac{27}{343}[/tex]
6. [tex]D. -72cd^{7}[/tex]
Step-by-step explanation:
Use the following properties:
[tex]a^{\frac{x}{y} } =\sqrt[x]{a^{y} }[/tex]
[tex]\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}[/tex]
[tex]a^{-n} =\frac{1}{a^{n} }[/tex]
[tex](xy)^{z} =x^{z} y^{z} \\\\[/tex]
[tex](x^{y}) ^{z} =x^{yz}[/tex]
[tex]x^{y} x^{z} =x^{y+z}[/tex]
So:
1. [tex]27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9[/tex]
2. [tex]\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216[/tex]
3. [tex](-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27[/tex]
4. [tex]40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325[/tex]
5. [tex](\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}[/tex]
6.
[tex](-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}[/tex]
Greg goes fishing every day for a week. On the first day he catches seven fish and each
day he catches three more than the previous day. How many fish did he catch in total?
so first day and so on
7, 10, 13,....
as you can see it's an arithmetic progression
so sum for nth term= n/2 { 2a + (n-1) d}
it's the sum of the 7th term
so
7/2 { 7 ×2 + ( 7-1) 3}
7/2 × 32
7× 16
112 fishes
Answer:
I think the answer is 25
Step-by-step explanation:
7+3+3+3+3+3+3 becuase a week is seven days and the numbers there is seven ,and you plus the 7 with the remaining six days which are 3 each day,my answer was now 25 .please if you know this answer is wrong please tell everyone the correct oneURGENT
What else would need to be congruent to show that AABC= ADEF by the
AAS theorem?
Answer:
AC = EF
Step-by-step explanation:
ABC = DEF
You would need to know that AC = EF
In the first place, using deduction we know that we dont need another angle. We also know that BC does not equal DF by looking at the angles on the triangles.
The solution is : ∠C ≅ ∠F is congruent to show that ΔABC ≅ ΔDEF, else would need to be congruent to show that AABC= ADEF by the AAS theorem.
What is AAS theorem?The angle-angle-side theorem, or AAS, tells us that if two angles and a non-included side of one triangle are congruent to two angles and a non-included side of another triangle, then the triangles are congruent.
here, we have,
to find congruency in a triangle:
ΔABC ≅ ΔDEF
Therefore,
AAS congruence rule or theorem states that if two angles of a triangle with a non-included side are equal to the corresponding angles and non-included side of the other triangle, they are considered to be congruent.
Therefore,
∠C ≅ ∠F
Hence, The solution is : ∠C ≅ ∠F is congruent to show that ΔABC ≅ ΔDEF, else would need to be congruent to show that AABC= ADEF by the AAS theorem.
learn more on AAS here:
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Solve for x: (-1/2) x = 6
Answer: x = -12
Step-by-step explanation:
-1/2x=6
Divide by -1/2
x = -12
Hope it helps <3
Bill needs to edge his yard with the dimensions in the shape below. What distance will he have walked after completing his edging? Round your answer to one decimal place. Do not include units in your answer.
Answer:
37.8 m
Step-by-step explanation:
The computation of the distance is shown below:
In triangle ADE
[tex]AD^2 = AE^2 + DE^2 \\\\ AD^2 = 5^2 + 3^2 \\\\ AD^2 = 34[/tex]
AD = 5.8
Now the distance walked after completing his edging is
Distance = AD + AB + BC + CD
= 5.8 + 12 + 5 + 15
= 37.8 m
We simply added these four sides so that the correct distance could arrive
Hence, the distance walked after completing his edging is 37.7
Find the probability of choosing an item from the intersection of following sets Set A : {1, 5, 10, 14, 22} Set B : {5, 14, 20, 22, 27}
Answer:
1/3
Step-by-step explanation:
There are three elements that are intersecting: 5, 14, 22
Probability of choosing an item is 1/3
The summer has ended and it's time to drain the swimming pool. 20 minutes after pulling the plug, there is still 45 000L of water in the pool. The pool is empty after 70 minutes. Calculate the rate that the water is draining out of the pool. b) Calculate how much water was in the pool initially. c) Write an equation for this relationship. d) Use your equation to calculate how much water is in the pool at 62 minutes.
Answer:
a) -900 L/min
b) 63000 L
c) -900t +63000
d) 7200 L
Step-by-step explanation:
a) You are given two points on the curve of volume vs. time:
(t, V) = (20, 45000) and (70, 0)
The rate of change of volume
= ΔV/Δt = (0 -45000)/(70 -20) = -45000/50 = -900 liters per minute
b) In the first 20 minutes, the change in volume was
(20 min)(-900 L/min) = -18000 L
So, the initial volume was
initial volume - 18000 = 45000
initial volume = 63,000 liters
c) Since we have the slope and the intercept, we can write the equation in slope-intercept form as
V= -900t +63000.
d) now putting the number in the equation and do the arithmetic.
When t=62, the amount remaining is
= -900(62) +63000 = -55800 +63000 = 7200
Thus, 7200 L remain after 62 minutes.
Please answer it now in two minutes
Answer: 3.2 yd
Step-by-step explanation:
Notice that TWV is a right triangle.
Segment TU is not needed to answer this question.
∠V = 32°, opposite side (TW) is unknown, hypotenuse (TV) = 6
[tex]\sin \theta=\dfrac{opposite}{hypotenuse}\\\\\\\sin 32=\dfrac{\overline{TW}}{6}\\\\\\6\sin 32=\overline{TW}\\\\\\\large\boxed{3.2=\overline{TW}}[/tex]
MATH HELP ME ASAP!!!!
Answer: Zak - Resp after 24 months = $4,344.00
Zak - Technology Fund after 24 months = $1,102.98
Zak's Technology Fund has enough money to buy a laptop.
Zak's Savings (Resp) will last less than 6 months
Step-by-step explanation for Zak:
January - June 2019
$15/hr x 20 hr x 4 wks x 6 months = $7200 Gross Income
Resp (15%): $7200(0.15) = $1080CPP(5%): $7200(0.05) = $360EI(2%): $7200(0.02) = $144Taxable Income is $7200 - $1080 = $6120 (Annual Income $12,240)
Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,120-$4,500)(0.08) = $129.60→ $7,200 - ($1080 + $360 + $144 + $0 + $129.60) = $5,486.40 Net Income
Tech Fund (5%): $5486.40(0.05) = $274.32
Food Expense (30%): $5486.40(0.3) = $1,645.92
Clothing Expense (30%): $5486.40(0.3) = $1,645.92
Entertainment Expense (25%): $5486.40(0.25) = $1,371.60
Miscellaneous Expense (10%): $5486.40(0.1) = $548.64
Other Expenses: $5,212.08
July - December 2019 (excluding August)
$16/hr x 20 hr x 4 wks x 5 months = $6400 Gross Income
Resp (15%): $6400(0.15) = $960CPP(5%): $6400(0.05) = $320EI(2%): $6400(0.02) = $128Taxable Income is $6400 - $960 = $5440 (Annual Income $11,560)
Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($5,440-$4,500)(0.08) = $75.20→ $6,400 - ($960 + $320 + $128 + $0 + $75.20) = $4,916.80 Net Income
Tech Fund (5%): $4916.80(0.05) = $245.84
Food Expense (30%): $4916.80(0.3) = $1,475.04
Clothing Expense (30%): $4916.80(0.3) = $1,475.04
Entertainment Expense (25%): $4916.80(0.25) = $1,229.20
Miscellaneous Expense (10%): $4916.80(0.1) = $491.68
Other Expenses: $4,670.96
January - June 2020
$17/hr x 20 hr x 4 wks x 6 months = $8160 Gross Income
Resp (15%): $8160(0.15) = $1224CPP(5%): $8160(0.05) = $408EI(2%): $8160(0.02) = $163.20Taxable Income is $8160 - $1224 = $6936 (Annual Income $13,872)
Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,936-$4,500)(0.08) = $194.88→ $8,160 - ($1224 + $408 + $163.20 + $0 + $194.88) = $6,169.92 Net Income
Tech Fund (5%): $6169.92(0.05) = $308.50
Food Expense (30%): $6169.92(0.3) = $1,850.98
Clothing Expense (30%): $6169.92(0.3) = $1,850.98
Entertainment Expense (25%): $6169.92(0.25) = $1,542.48
Miscellaneous Expense (10%): $6169.92(0.1) = $616.98
Other Expenses: $5,861.42
July - December 2020 (excluding August)
$18/hr x 20 hr x 4 wks x 5 months = $7200 Gross Income
Resp (15%): $7200(0.15) = $1080CPP(5%): $7200(0.05) = $360EI(2%): $7200(0.02) = $144Taxable Income is $7200 - $1080 = $6120 (Annual Income $13,056)
Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,120-$4,500)(0.08) = $129.60→ $7,200 - ($1080 + $360 + $144 + $0 + $129.60) = $5,486.40 Net Income
Tech Fund (5%): $4916.80(0.05) = $274.32
Food Expense (30%): $5486.40(0.3) = $1,645.92
Clothing Expense (30%): $5486.40(0.3) = $1,645.92
Entertainment Expense (25%): $5486.40(0.25) = $1,371.60
Miscellaneous Expense (10%): $5486.40(0.1) = $548.64
Other Expenses: $5,212.08
[tex]\boxed{\begin{array}{l|r|r|r|r||r}\underline{ZAK}&\underline{Jan-Jun'19}&\underline{Jul-Dec'19}&\underline{Jan-Jun'20}&\underline{Jul-Dec'20}&\underline{Totals\quad }\\Gross&\$7200.00&\$6400.00&\$8160.00&\$7200.00&\$28960.00\\Resp&\$1080.00&\$960.00&\$1224.00&\$1080.00&\$4344.00\\Net&\$5486.40&\$4916.80&\$6169.92&\$5486.40&\$22059.52\\Other&\$5212.08&\$4670.96&\$5861.42&\$5212.08&\$20956.54\\Tech&\$274.32&\$245.84&\$308.50&\$274.32&\$1102.98\end{array}}[/tex]
can someone please help me
Answer:
3x^2 + 3/2 x -9
Step-by-step explanation:
f(x) = x/2 -3
g(x) =3x^2 +x -6
(f+g) (x) = x/2 -3 + 3x^2 +x -6
Combine like terms
= 3x^2 + x/2 +x -3-6
= 3x^2 + 3/2 x -9
HELP!! this is due today
Answer:
1
Step-by-step explanation:
If y=x, than the only way
y=rx can be possible is if r=1
Hope this helps!
Have a good day! :)
Answer:
1
Step-by-step explanation:
y = rx
Use any set of x and y-coordinates in the equation and solve for r.
For example, use (5.8, 5.8).
5.8 = r(5.8)
Divide both sides by 5.8:
r = 1
Answer: r = 1