If a 3.5 gram ping pong ball were traveling to the right horizontally at 12 m/s, and a larger 12 g super ball were thrown directly behind it (also to the right) at 15 m/s so that the super ball bumped into and elastically collided with the ping pong ball, what would be the velocities of the two balls after the collision

Answers

Answer 1

Answer:

v = 14.32 m/s

Explanation:

According to the principle of conservation of linear momentum, both the momentum and kinetic energy of the system are conserved. Since the two balls are in the same direction of motion before collision, then;

[tex]m_{1} u_{1}[/tex] + [tex]m_{2} u_{2}[/tex] = ([tex]m_{1}[/tex] + [tex]m_{2}[/tex]) v

0.035 × 12 + 0.120 × 15 = (0.035 + 0.120) v

0.420 + 1.800 = (0.155) v

2.22 = 0.155 v

⇒ v = [tex]\frac{2.22}{0.155}[/tex]

      = 14.323

The velocity of the balls after collision is 14.32 m/s.


Related Questions

A piano has a mass of 99 kg. What is the weight of the piano?
A. 1030 N
B. 842 N
C. 1129 N
D. 970 N
Help!!

Answers

Answer:

[tex]D.\ 970\ N[/tex]

Explanation:

Given:

Mass of Piano: 99kg

Required:

Calculate its weight

The weight of an object is calculate as thus;

[tex]Weight = Mass\ (m) * Acceleration\ due\ to\ gravity\ (g)[/tex]

[tex]m = 99kg[/tex] and [tex]g = 9.8m/s^2[/tex]

The formula becomes

[tex]Weight = 99kg * 9.8m/s^2[/tex]

[tex]Weight = 970.2\ kgm/s^2[/tex]

[tex]Weight = 970.2\ N[/tex]

[tex]Weight = 970\ N[/tex] Approximated

Hence, the weight of the piano is 970N

Fill in the blanks in the following statements:
1. A parsec is defined as the distance from the Sun which would result in a parallax of_____ arcsecond as seen from Earth when observed 6 months apart.
2. One parsecs is about_____light years.
3. The more distant a star, the_____its parallax.
4. The statement "we can measure stellar parallax for most stars in our galaxy" is_____.
5. The closest stars have parallaxes smaller than______arcsecond.
6. The first successful measurements of stellar parallax were made by______in year______for the star named.
7. Star Fred has parallax four times greater than star Bob. Star Fred is______times______then star Bob.

Answers

Answer:

Explanation:

1. A parsec is defined as the distance from the Sun which would result in a parallax of_TWO____ arcsecond as seen from Earth when observed 6 months apart.

2. One parsecs is about_3.3____light years

3. The more distant a star, the_LESS ____its parallax.

4. The statement "we can measure stellar parallax for most stars in our galaxy" is__TRUE .___.

5. The closest stars have parallaxes smaller than_.002 _____arcsecond.

6. The first successful measurements of stellar parallax were made by_Friedrich Bessel_____in year_1838_____for the star named.

7. Star Fred has parallax four times greater than star Bob. Star Fred is__4____times_nearer_____than star Bob.

Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel and Jerry are using the same force F. Jerry stops after 10 min, while Joel is able to push for 5.0 min longer. Compare the work they do.

Answers

Answer:

The work done by Joel is greater than the work done by Jerry.

Explanation:

Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

[tex]W = F\cdot \Delta s[/tex]

Where:

[tex]W[/tex] - Work, measured in joules.

[tex]F[/tex] - Force exerted on the object, measured in newtons.

[tex]\Delta s[/tex] - Travelled distance by the object, measured in meters.

During the first 10 minutes, the net work exerted on the object is zero. That is:

[tex]W_{net} = W_{Joel} - W_{Jerry}[/tex]

[tex]W_{net} = F\cdot \Delta s - F\cdot \Delta s[/tex]

[tex]W_{net} = (F-F)\cdot \Delta s[/tex]

[tex]W_{net} = 0\cdot \Delta s[/tex]

[tex]W_{net} = 0\,J[/tex]

In exchange, the net work in the next 5 minutes is the work done by Joel on the object:

[tex]W_{net} = W_{Joel}[/tex]

[tex]W_{net} = F\cdot \Delta s[/tex]

Hence, the work done by Joel is greater than the work done by Jerry.

How will you connect 3 cells each of value 2V to give a total of 3V * Two in parallel with one in series Two in series with one in parallel All in parallel All in series

Answers

Answer:

two of them in series with one in parallel

Explanation:

When two or more batteries are connected in

(a) series: the total voltage produced is equal to the sum of the voltages on each of the batteries. For example, if two batteries A and B of 3V and 2V respectively are connected in series, then the total voltage produced is

3V + 2V = 5V

(b) parallel: the total voltage produced is equal to the voltage on any one of the batteries. As a mention, only batteries of the same voltage should be connected together in parallel. For example, if two batteries A and B each of 4V are connected together in parallel, then the total voltage produced is 4V.

If these batteries are not of the same voltage, then the one of larger voltage will charge the one of the lower voltage until they both have the same voltage. That means that their eventual voltage will be the average of their voltages. For example, if two batteries A and B of 3V and 2V respectively, are connected in parallel, their total voltage will be,

(3V + 2V) / 2 =2.5V

Now, from the question.

Since there are three cells each of value 2V.

=>If we connect two of them in series, the total voltage from those two cells will be 2V + 2V = 4V

=>If we then connect this series connection in parallel with the third cell, then we have a parallel combination of 4V and 2V. Since they have different voltages, then the total voltage will be the average of the two voltages. i.e

(4V + 2V) / 2 = 6 / 2 = 3V

Therefore, to have a total of 3V from three cells each of 2V, we need to connect two of them in series with one in parallel

can someone plz go help me answer my question? I have to ask twice bc no one answered it the first time. a figure skater can increase her spin rotation rate from an initial rate of 1.0 rev every 1.5s to a final rate of 2.5rev/s. If her initial moment of inertia was 4.6kgxm^2, what is her final moment of inertia?

Answers

Answer:

1.2 kg m²

Explanation:

Angular momentum is conserved:

L = L

Iω = Iω

(4.6 kg m²) (1.0 rev / 1.5 s) = I (2.5 rev/s)

I = 1.2 kg m²

help me helpppp the last words are experience a total ​

Answers

Answer:

False

Explanation:

Total internal reflection is a condition that occurs when light travels from dense medium to less dense medium.

From the table given in the question above,

Refractive Index of Whale oil = 1.460

Refractive Index of vacuum = 1

From the above, we can see that the whale oil has a higher Refractive Index than vacuum. This implies that the whale oil is denser than the vacuum.

Therefore, total internal reflection will occur when light travels from whale oil to vacuum because the whale oil is denser than the vacuum.

can someone proofread my Big freeze theory of the universe? does it make sense?

Answers

Answer:

Yes great job it was well written!:)

A mass of 1.15 kg of air at 111 kPa and 27 C is contained in a gas-tight, frictionless piston cylinder device. The air is now compressed to a final pressure of 0.84 MPa. During this process, heat is transferred from the air such that the temperature inside the cylinder remains constant. Calculate the work input (in kJ) during this process.

Answers

Answer:

Work input W = -200.39 KJ

Explanation:

From the question, we are given;

m = 1.15 kg

Constant temperature T1 = T2 = 27 + 273 = 300k

Since the temperature is constant, we can say that the process is isothermal

P1 = 111 KPa

P2 = 0.84 MPa = 0.84 * 1000 KPa = 840 KPa

Now what we want to calculate is W1-2

Mathematically, for isothermal process;

W1-2 = mRTlnP1/P2

where R can be obtained from table and it is equal to 0.287 KJ/kg.k

Hence;

W1-2 = (1.15)(0.287)(300)(ln 111/840)

W1-2 = 99.015 * -2.023871690525 = -200.39 KJ

Kindly note that the value of the work is negative because work is done on the system and not by the system

2. When backing straight or to the right: a. Position your right hand on the back of the passenger seat. b. Grip the steering wheel at the 12 o’clock position with your left hand. c. Move the wheel left or right in the direction in which you want the rear of the vehicle to go. d. All of the above

Answers

Answer:

Option d = all of the above.

Explanation:

This question is more of a driving lesson or tutorial Question and not that scientific, it is logical and the "rule" attached to reversing and driving that is operating of vehicles especially cars, trucks and so on.

All the options given in the Question from option 'a' to option 'c' are all correct when driving backwards that is reversing or backing . Driving backward(backing or reversing) is not as easy as during forward (drive mode).

=> " Position your right hand on the back of the passenger seat. Grip the steering wheel at the 12 o’clock position with your left hand"

REASON: FOR BALANCING.

=> " Move the wheel left or right in the direction in which you want the rear of the vehicle to go."

The above, given in the Question are all correct.

When backing straight or to the right, all of the mentioned options are correct and recommended practices are to Position your right hand on the back of the passenger seat. The correct option is option d.

a) Position your right hand on the back of the passenger seat: This is a technique used by some drivers to help them have a better sense of the vehicle's position and reference point while backing up.

b) Grip the steering wheel at the 12 o'clock position with your left hand: This hand position allows for better control and maneuverability of the steering wheel while backing up.

c) Move the wheel left or right in the direction in which you want the rear of the vehicle to go: This is the fundamental principle of steering while backing up. By turning the wheel in the desired direction, you can guide the rear of the vehicle in that direction.

Therefore, These practices can assist in improving control, visibility, and maneuverability while backing up, ensuring a safer and more effective backing maneuver. The correct option is option d.

To know more about the principle of steering:

https://brainly.com/question/29458022

#SPJ6

a 6 letter word a way of explaining an object or event using a set of facts

Answers

Explanation:

A theory is a way of explaining an object or event using a set of facts.

1. The electric field strength between two parallel plates separated by 6.00 cm is 7.50 × 104 V/m . (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?

Answers

Answer:

a)4500V

b)750V

Explanation:

Given:

Distance between the plate=

6.00 cm

We need to convert to m

Then the Distance between the plate=

0.06m

electric field strength between two parallel plates =

7.50 × 104 V/m .

Then E= 7.50 × 104 V/m .

(a) What is the potential difference between the plates?

potential difference between the plates can be calculated using the formula below

Δ Vab=ED

Where E is the given electric field strength

D= The Distance between the plate

ΔVab=7.50 × 10⁴V/m ×

0.06m

= 4500V

(b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?

the potential 1cm from the zero volt plate

Then the 1cm must be converted to m

= 0.01m

Let us say plate A as the plate at 0 volts:

The potential increases linearly going from plate A (0 V) to plate B (4500V).

Therefore,if the potential difference between A and B, separated by 6 cm, is 4500 V, then the potential difference between A and a point located at 1 cm from A is can be calculated also

If the plate with Lowest potential is taken to be zero then

=ΔVab=Vab-Vb=Va-0=Va=ED

Va=7.50 × 10⁴V/m × 0.01=750V

How much work is done when 0.0042 C is moved through a potential difference of 12.0 V? Use W = qV A. 0.050 J B. 0.00035 J C. 2900 J D. 12 J

Answers

Answer:

Work done by charge (W) = 0.050 (Approx)

Explanation:

Given:

Charge (q) = 0.0042 C

Potential difference(V) = 12.0 V

Find:

Work done by charge

Computation:

Work done(W) = qV

Work done by charge (W) = (0.0042)(12)

Work done by charge (W) = 0.0504

Work done by charge (W) = 0.050 (Approx)

Answer:

Work done by charge (W) = 0.050 (Approx)

Explanation:

Charge (q) = 0.0042 C

Potential difference(V) = 12.0 V

Find:

Work done by charge

Computation:

Work done(W) = qV

Work done by charge (W) = (0.0042)(12)

Work done by charge (W) = 0.0504

Work done by charge (W) = 0.050 (Approx)

In a given chemical reaction the time energy of the products is less than the energy of the reactants which statements is true for this chemical reaction

Answers

Answer:

Energy is released in this reaction possibly in the form of heat thus it is an exergonic and or exothermic reaction.

Explanation:

The energy is sometimes transferred as heat, inflicting the reaction mixture and its surroundings to become hotter. The temperature increase may be detected employing a measuring device. Some samples of exothermic reactions are: Combustion .An chemical reaction may be a chemical process that releases energy by lightweight or heat

Hope this helps...

Have a nice day!!!!

a) A conductor carrying a current I = 12.5 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A magnetic force per unit length of 0.110 N/m acts on the conductor in the negative y direction. Determine the magnitude of the magnetic field in the region through which the current passes.

Answers

Answer:

8.8 mT

Explanation:

Current through the conductor = 12.5 A

Magnetic force per unit length on the wire = 0.110 N/m

Recall that the magnetic force per unit length on a current carrying conductor is in a uniform magnetic field is

[tex]\frac{F}{l}= IBsin\alpha[/tex]

where B is the magnetic field magnitude

[tex]I[/tex] is the current in the conductor

α is the angle the conductor makes with the  magnetic field ( since it is perpendicular in this case, α is 90°)

imputing values into the equation, we'll have

0.11 = 12.5 x B x sin 90°

but sin 90° = 1, therefore, we have

0.11 = 12.5B

B = 0.11/12 = 8.8 x 10^-3 T

or rather = 8.8 mT

A leopard chasing a deer reaches a constant speed of 75m / s. In How long does 1200m travel?

Answers

Answer:

16 seconds

Explanation:

To do this you would set up the equation 75x=1200. Then you would divide 75 from both sides so you get x=16 or it takes 12 seconds for it to travel 1200 meters

Answer:

Time = 16 s

Explanation:

Distance =Speed x Time

1200 = 75 x time

Time = 1200/75 = 16 sec

find the molecular formula of the following​

Answers

Answer: hello i am a hacker

Explanation:

magnesium sulphate=(24*1)+(32*1)+(16*4)=120                                                             water=H2O=(1*2)+(1*16)=18                                                                                                        carbon dioxide=CO2=(12*1)+(16*2)=44                                                                                     ammonia=NH3=(14*1)+(1*3)=17                                                                                                   alminiumsulphate=AL2(SO4)3=(26*2)+(32*3)+(12*16)=340                                                          hydrogen peroxide=H2O2=(1*2)+(16*2)=34                                                              zinc sulphate=ZNSO4=(65*1)+(32*1)+(16*4)=161

         

1. Chanice drives her scooter 7 kilometres north. She stops for lunch and then drives 5 kilometres east. What distance did she cover? What was her displacement?

Answers

Answer:

i. Distance covered is 12 kilometres.

ii. Her displacement is 8.6 kilometres.

Explanation:

Distance is a span of length between two points, while displacement is the distance moved in a specified direction. Distance is a scalar quantity, while displacement is a vector.

She drives 7 kilometres north, then 5 kilometres east later.

i. Distance covered = 5 + 7

                                 = 12

Her distance covered is 12 kilometres.

ii. To determine her displacement, apply the Pythagoras rule to the sketch of her journey.

[tex]x^{2}[/tex] = [tex]5^{2}[/tex] + [tex]7^{2}[/tex]

   = 25 + 49

   = 74

x = [tex]\sqrt{74}[/tex]

  = 8.6023

Thus, her displacement is 8.6 kilometres.

You work for an advertising company and have been hired to place a blimp above a football stadium. The angle of elevation from a point directly under the goal post is 72° and the blimp will be directly above the 50 yard line. a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line? b. How high above the ground is the blimp? c. In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement? If not, what possible angle of elevation could we use? d. What is the exact angle if the blimp is at 150 feet?

Answers

Answer:

a) tangent ; b) 153.88 yds ; c) No , less than or equal to 45° ; D) 45°

Explanation:

Given the following ;

From the triangle sketch :

Base length = 50 yards

Angle of elevation = 72°

a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line?

Using trigonometry :

The height of the blimp will be calculated using :

Tangent :

Tan θ = opposite / Adjacent

B.) How high above the ground is the blimp?

Using :

Tan θ = opposite / Adjacent

Θ = 72° ; adjacent = 52, opposite = height(h)

Tan 72° = h / 50

h = 3.0776835 * 50

h = 153.88 yds

C.) In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement?

1 yard = 3 Feets

153.88 yards = 3 * 153.88

= 461.65 feets

No, because the height of the blimp is 461.65 Feets which is greater than 150 Feets.

To make viewing possible, the angle of elevation should be:

50 yards is equivalent to (3 * 50) = 150 feets

Max imum Height of blimp = 150 Feets

From pythagoras ;

Tanθ = 150 Feets / 150 Feets

Tanθ = 1

θ = tan^-1(1)

θ = 45°

To make viewing advertisement possible, angle of elevation should not exceed 45°

d.)If height of blimp is 150 Feets, then the exact angle of elevation will be 45°

Signal propagation in the nervous system can be modeled as

a) A resistor network.

b) A wave of electricity that travels down conducting tissue.

c) A series of RC circuits.

Answers

Answer:

c) A series of RC circuits.

What is the wavelength of the following waves?

Answers

Answer:

i. the wavelength is 7.2 m

ii. the wavelength is 2.4 m

Explanation:

the wavelength of a wave is from crest to crest or from trough to trough.

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near its center. You have enough wire for 3800 circular turns, and the solenoid must be 1.60 m long and 20.0 cm in diameter. What current will you need to produce the necessary field?

Answers

Answer:

Explanation:

Magnetic field = permeability x turn density x current

Magnetic field = 0.22T

turn density = 4150 /1.6 = 2593.75 t/m

permeability : µ = k µ°

µ°= 4 π 10^-7

k = 1

I = 0.22 / 4 π 10^-7 * 2593.75 = 0.22 10^7 /32594 = 67.497 A

Which refers to the rate of change in velocity?
O speed
O acceleration
O direction
O magnitude

Answers

Answer:

acceleration is the answer

Answer:

Acceleration

Explanation:

A river flows with a speed of 3km/h in still water. A man who can swim with a speed of 5km/h wishes to reach a point on the other bank just opposite to the starting point. In which direction should he put his strokes and how long will he take to cross the river of width 1.2km? Please try to provide a diagram and step by step explanation.

Answers

Answer:

Explanation:

Let the angle required be θ with direction opposite to current .

cos θ = 3 / 5

θ = 53° .

Resultant velocity towards the opposite side

= √ ( 5 ² - 3²)

= 4 km /h

distance covered = 1.2 km

time taken = 1.2 / 4 = .3 h

= 18 min .

Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0 X 1012 electrons are added to sphere A, then the two spheres are separated. Afterward, what is the charge of sphere A

Answers

Answer:

Charge that will be left on sphere A is -8 x 10^-8 C

Explanation:

Number of electrons = 1.0 x 10^12 electrons

charge on an electron is = -1.6 × 10^-19 coulombs

for the number of electron, total charge = (1.0 x 10^12) x (-1.6 × 10^-19)

==> -1.6 x 10^-7 C

Since the two spheres were in contact when the charge was added to one of the spheres A, the sphere will then be distributed between the two spheres A and B equally. This means that after separation, sphere A will be left with

==> (-1.6 x 10^-7 C) ÷ 2 = -8 x 10^-8 C

Ted throws an object straight up into the air with an initial velocity of 54 ft/s from a platform that is 40 ft above the ground. Use the formula h(t)=−16t2+v0t+h0, where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

Answers

Answer:

The time it will take for the object to hit the ground will be 4.

Explanation:

You have:

h(t)=−16t²+v0*t+h0

Being v0 the initial velocity (54 ft/s) and  h0 the initial height (40 ft) and replacing you get:

h(t)=−16t²+54*t+40

To know how long it will take for the object to touch the ground, the height h(t) must be zero. So:

0=−16t²+54*t+40

Being a quadratic function or parabola: f (x) = a*x² + b*x + c, the roots or zeros of the quadratic function are those values ​​of x for which the expression is 0. Graphically, the roots correspond to the points where the parabola intersects the x axis. To calculate the roots the expression is used:

[tex]\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}[/tex]

In this case you have that:

a=-16b= 54c= 40

Replacing in the expression of the calculation of roots you get:

[tex]\frac{-54+\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}[/tex]  Expresion (A)

and

[tex]\frac{-54-\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}[/tex] Expresion (B)

Solving the Expresion (A):

[tex]\frac{-54+\sqrt{5476 } }{2*(-16)}= \frac{-54+74}{2*(-16)}=\frac{20}{2*(-16)}=\frac{20}{-32}= -\frac{5}{8}[/tex]

Solving the Expresion (B):

[tex]\frac{-54-\sqrt{5476 } }{2*(-16)}= \frac{-54-74}{2*(-16)}=\frac{-128}{2*(-16)}=\frac{-128}{-32}= 4[/tex]

These results indicate the time it will take for the object to hit the ground can be -5/8 and 4. Since the time cannot be negative, then the time it will take for the object to hit the ground will be 4.

Answer:

4 seconds

Explanation:

i checked on the test and the other person was right give them brainliest

A classroom measures 3 m X 4m x 6 m.
Calculate the volume of air in the room. Give your answer in
a
cubic metres (mº).

Answers

3m * 4m * 6m= 72m^3
I hope you get it

calculate the energy dissipated by an electric iron which draws a current of 5A from a240v power supply for 25minutes​

Answers

Explanation:

Given,

I = 5 A

V = 240 V

T = 25 mins = 1500 sec

Now,

Energy dissipated = IVT= 5×240×1500 = 1800000 J

Which statement describes dynamic equilibrium? A. The forces on an object in motion are balanced. B. An object is accelerating due to forces acting on it. C. The forces on an object are unbalanced. D. The forces on a stationary object are balanced.

Answers

Answer: A. The forces on an object in motion are balanced.

Explanation:

The dynamic equilibrium is defined as the phase when an object moves at a constant velocity such that all forces on the object are balanced.

Simple case of dynamic equilibrium: A horizontal force is applied to an object making it run with a constant velocity across a surface.

Hence, the statement describes dynamic equilibrium is " The forces on an object in motion are balanced. "

So, the correct option is "A".

Answer:

Hope this helps!

if rain drops of equal size fall with terminal velocity of 0.50m/s. what will be the terminal velocity if the drops collaspe to form a big drop?

Answers

Answer:

0.25m/s

Explanation:

m1v1 =m2 v2. law of conservation the of momentum. since they smash together to form a big drop M2 =2m1

m1*0.50m/s=2m1*v2

V2= m1*0.50m/s÷2m1

V2= 0.25m/s

what is the formula of gravitational force​

Answers

Answer:

[tex]\displaystyle F_g = \frac{GM_1 m_2}{r^2}[/tex]

[tex]F_g[/tex] is the force.

[tex]G[/tex] is the gravitational constant.

[tex]M_1[/tex] is the mass of one object.

[tex]m_2[/tex] is the mass of the other object.

[tex]r[/tex] is the distance between the two objects.

Other Questions
How did the Marquis de Lafayette and Baron von Steuben play similar roles in the American Revolution? In a shot-put competition, a shot moving at 15m/s has 450J of mechanical kinetic energy. What is the mass of the shot? Please help, and include the formula for the answer and a step by step explanation Containers, Inc., sends its standard order form to Distribution Corporation to evidence a sale of packing materials. Distribution responds with its own standard purchase order form. Additional terms in the purchase order automatically become part of the contract unless:________. Mitochondrion; crista Mitochondrion; crista Mitochondrion is a constituent part of crista. Crista is a constituent part of mitochondrion. Mitochondrion and crista are separate structures with no particular relationship to each other.1. Mitochondrion; crista: a. Mitochondrion is a constituent part of crista. b. Crista is s constituent part of mitochondrion. c. Mitochondrion and crista are separate structures with no particular relationship to each other. 2. Gobi complex; nucleus a. Goo complex is a constituent part of nucleus. b. Nucleus is e constituent part of Gobi complex. c. Goo complex and nucleus are separate structures with no particular relationship to each other. Can an absolute value function also be a polynomial function? Why or why not? If an object is propelled upward from a height of 72 feet at an initial velocity of 90 feet per second, then its height h after t seconds is given by the equation h = 16 t 2 + 90 t + 72 . After how many seconds does the object hit the ground? Springfield Company offers a bonus plan to its employees and the amount of the employee bonuses for the current year is estimated to be $32,500 to be paid during January of the following year. The journal entry on December 31 to record the bonuses is:________. A) Debit Estimated Bonus Payable $32,500; credit Cash $32,500. B) Debit Employee Bonus Expense $32,500; credit Bonus Payable $32,500. C) No entry since the bonuses are not paid until January. D) Debit Employee Bonus Expense $32,500; credit Prepaid Employee Bonus $32,500. E) Debit Unearned Bonuses $32,500; credit Bonus Payable $32,500. A raspberry has a red color because it _____ red light. A. emits B. reflects C. absorbs D. transmits What similarities the US Constitution have to the CONSTITUTION OF THE CHOCTAW NATION OF OKLAHOMA? the scale on the map is 1 cm represents 40 km . the actual straight line distance between 2 cities is about 320 km what is the map distance between these 2 cities Please help me with geometry questions :(( Jennifer invested $302 in a simple interest account. The account earns 3.3%/year how much will Jennifer have in her account in 10 months?? Find the circumference of a circular field with a diameter of 16 yards.(Let it = 3.14) Colossus Added to six flags st. Louis in 1986, the Colossus is a giant Ferris wheel. Its diameter is 165 feet, it rotates at a rate of about 1.6 revolutions per minute, and the bottom of the wheel is 15 feet above the ground. Determine an equation that relates a rider's height the ride at the bottom of the wheel. 2x - y = 64x-y13anch The pressure and temperature at the beginning of compression of an air-standard Diesel cycle are 95 kPa and 300 K, respectively. At the end of the heat addition, the pressure is 7.2 MPa and the temperature is 2150 K. Determine a) the compression ratio. b) the cutoff ratio. c) the thermal efficiency of the cycle. d) the mean effective pressure, in kPa. Which Carbon is the triple bound attached to in 6-ethyl-2-octyne?-first-fourth-third-second Escoge la respuesta apropriada a esta pregunta. Qu haras con mucho dinero? Mi madre ira al trabajo. Compraras un carro. Venderan su casa. Viajara a muchos lugares. surface area of a equilateral by hand Why is the couple aghast? What consequences might they face if they can't find the missing necklace?Help please I need to graduate the book is necklace