If 32^2^c= 8^cC+7, what is the value of c?

Step-by-step explanation:

x intercept is 1

y intercept is 2

Hope it helps

Answer:

The congruency of triangle is the statement that describes the relationship between two figures Step-by-step explanation:

Answer:

147/20,7+2/5,7.407,7.41.

Step-by-step explanation:

147/20=7.35.

7+2/5=7.4.

7.407>7.4.

7.41>7.407.

Side note:

I changed everything into decimal form.

Answer:

Hello I'm sorry but I have a question and I have to give ans and I can ask my question

Answer:

Step-by-step explanation:

y = 3x - 2

Slope of line is 3.

Slope of any perpendicular to the line is -⅓.

Answer:

its either 2 or 4

Step-by-step explanation:

Answer:

$56×2=$112 and $45×4=$180 so $112+$180= $291

Answer:

12000

Step-by-step explanation:

Check the hundreds digit if greater Han 5 increase the thousands digit by 1 and change the other digits to 0

Answer:

that is what I got as my answer

Answer:

Yes the function is continuous f(5) = 13

Step-by-step explanation:

Replace the variable x with 5 in the expression

Simlify the results

f(5) = 3(5)-3

f(5) = 15=3

f(5) = 13

Plotting on a graph gives a coninous line with a positive gradient

y intercept (0,-2)

Please view the attached graph

Answer:

40

Step-by-step explanation:

i need point so i am writing this sentence you have to do 4 times 10 (4×10) it is 40

Answer:

1. 0

2.0

3.2

4.1

Step-by-step explanation:

1.3x+18

2.-2x+2

3.x-x+4-2

5-2x-2+5-2x

Answer:

Answer:

3,6

Step-by-step explanation:

Step-by-step explanation:

A 45° angle is complementary to angle

45°+x°=90°

I hope it helped U

stay safe stay happy

Hi there!

The numbers you have written there are correct.

[tex]-5<x<0[/tex] is true for any value of x that is greater than -5 or less than 0.

When a number is less than 0, we know that it has to be negative.

However, it cannot be more negative than -5. It cannot be -5 either.

So, x could be -1, -2, -3, -4, -1/2, -2.3, -4.9, the list goes on.

I hope this helps!

9514 1404 393

Answer:

  h = 3V/(πr²)

Step-by-step explanation:

The formula can be solved for h by multiplying both sides by the inverse of the coefficient of h.

  [tex]V=\dfrac{1}{3}\pi r^2h=\dfrac{\pi r^2}{3}h\\\\(\dfrac{3}{\pi r^2})V=(\dfrac{3}{\pi r^2})(\dfrac{\pi r^2}{3})h\\\\\boxed{\dfrac{3V}{\pi r^2}=h}[/tex]

_____

Additional comment

Whenever a variable has a coefficient you don't want, you can make that be 1 by multiplying the equation by the inverse of the coefficient. This is the same as dividing by the coefficient. This makes use of the fact that for any non-zero 'a', the ratio a/a has a value of 1. Anything multiplied by 1 is unchanged.

  V = ah   ⇒   V/a = (ah)/a = h(a/a) = h·1 = h

Note that we multiply the whole equation (both sides of the equal sign) by 1/a. The basic rule of equality is that you can do whatever you like to an equation, as long as you do it to both sides.

Answer:

41

Step-by-step explanation:

This composite function can be easily solved

First solve f(-2)

f(-2)=(-2)³+3

f(-2)=-8+3=-5

Now plug -5 for x in function g(x)

=2(-5)²+2(-5)+1

=50-10+1

=41

9514 1404 393

Answer:

  41

Step-by-step explanation:

g(f(-2)) = g((-2)³ +3) = g(-8+3) = g(-5)

= 2(-5)² +2(-5) +1 = 50 -10 +1

g(f(-2)) = 41

Answer:

Range is (0, -5)

Step-by-step explanation:

[tex]{ \sf{f(x) = - {x}^{2} - 5}}[/tex]

when x is 0:

[tex]{ \sf{f(0) = - 5}}[/tex]

Answer:

true, I hope this will help.

[tex]\boxed{\underline{\bf \: True}}[/tex]

[tex] \sf \: 6(10 + 5) = 6•10 + 6•5 [/tex]

Check with LHS = RHS rule method.

LHS

[tex]\sf6(10 + 5) \\ \sf = 6(15) \\ \sf = 6 \times 15 \\ \bf = 90[/tex]

RHS

[tex]\sf6•10 + 6•5 \\ \sf = 60 + 30 \\ \bf= 90[/tex]

We can see that both LHS & RHS give [tex]\boxed{\underline{\bf \: 90}}[/tex]as the solution. LHS = RHS. Hence proved.

Answer -> [tex]\boxed{\underline{\bf \: True}}[/tex]

_______________

Hope it helps.

RainbowSalt2222

Answer:

how to convert

Step-by-step explanation:

To convert a mixed number to an improper fraction, follow these steps: Multiply the denominator of the fractional part by the whole number, and add the result to the numerator. Use this result as your numerator, and place it over the denominator you already have. This method works for all mixed numbers

Answer:

Change the whole numbers

Step-by-step explanation:

For example

5 3/6

A whole number written as a fraction for this problem is 6/6.

If the problem was 7 4/9, it would 9/9

I'd the problem was 2 3/4, it would be 4/4.

So basically a whole number written as a fraction is when both the top and bottom number are the same. when divide by each other they equal one. 6 divided by 6 is 1, 9 divided by 9 is 1, 4 divide by 4 is 1.

First

Turn 5 3/6 into 5/1 + 3/6

Now add them to together

To add fractions together they have to have the same denominator or bottom number.

What is a number 1 and 6 have in common ?

6 because 1 can be multiplied with any number but 6 can never be multiplied to create 1.

5 is simple 5 whole numbers

so 5/1 × 6/6= 30/6

30/6 + 3/6 = 33/6

now it's an improper faction. There is no whole number, it been converted into a fraction where the top is bigger than the bottom hence why it is improper

Answer:

[tex]\frac{1}{30}[/tex]

Step-by-step explanation:

Take it in steps. First, find 7/9+6. Then we'll find 8+6/3, and, finally, we'll divide the two answers.

1:

7/9+6 = 7/15

2:

8+6/3 = 14/3

3:

[tex]\frac{\frac{7}{15}}{\frac{14}{3}}[/tex] or [tex]\frac{7/15}{14/3}[/tex]

Then take that in chunks: 7/14 and 15/3.

7/14 = 1/2

15/3 = 5/1

Use those to rewrite it as [tex]\frac{1/5}{2/3}[/tex].

1/5 = .2

2/3 ≈ .6667 so we'll keep writing it as 2/3

[tex]\frac{\frac{.2}{2}}{3}[/tex]

.2/2 = .1, so:

[tex]\frac{.1}{3}[/tex] = [tex]\frac{1}{30}[/tex]

9514 1404 393

Answer:

  (b)  6^10/7^6

Step-by-step explanation:

The applicable rules of exponents are ...

  (a/b)^c = (a^c)/(b^c)

  (a^b)^c = a^(bc)

__

This means you have ...

  [tex]\left(\dfrac{6^5}{7^3}\right)^2=\dfrac{(6^5)^2}{(7^3)^2}=\dfrac{6^{5\cdot2}}{7^{3\cdot2}}=\boxed{\dfrac{6^{10}}{7^6}}[/tex]

__

Additional comment

I find it helpful to remember that an exponent signifies repeated multiplication. Then ...

  [tex]\left(\dfrac{6^5}{7^3}\right)^2=\left(\dfrac{6^5}{7^3}\right)\cdot\left(\dfrac{6^5}{7^3}\right)=\dfrac{6^5\cdot6^5}{7^3\cdot7^3}=\dfrac{6^{5+5}}{7^{3+3}}=\dfrac{6^{10}}{7^6}[/tex]  

Answer:

VW = 6

Step-by-step explanation:

To find x, set up the following equation:

(5x - 4) + (2x) = 5x

Solve out left side

7x - 4 = 5x

Subtract 5x from both sides

2x - 4 = 0

Add 4 to both sides

2x = 4

Divide both sides by 2

x = 2

Plug into 5x - 4

5(2) - 4

10 - 4

6

Answer:

6

Step-by-step explanation:

5x - 4 + 2x = 5x

7x - 4 = 5x

-4 = -2x

2 = x

5(2) - 4

10 - 4

6

Answer:

Step-by-step explanation:

[tex]\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\[/tex]

[tex]\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\[/tex]

Answer:

1/4

Step-by-step explanation:

24/6

4

4+4+4+4+4+4

Step-by-step explanation:

As it holds Associative property..

So, it's correct

Answer:

TRUE

Step-by-step explanation:

Associative property of multiplication

Answer:

In order for the function to be discontinuous at an asymptote, the curve needs to exist on both sides of the asymptote. If the curve only exists on one side of the asymptote, then there's no discontinuity at that point.

Step-by-step explanation:

Answer:

98 [tex]cm^{2}[/tex]

Step-by-step explanation:

The formula for the area of a square when given the diagonal is:

A = [tex]\frac{1}{2}[/tex] [tex]d^{2}[/tex] Where d is the value of the diagonal so it becomes:

0.5 × 14 × 14

This is equal to 98 [tex]cm^{2}[/tex].

HOPE THIS HELPED

Answer:

(0, 0)

Step-by-step explanation:

Each reference line is called a coordinate axis or just axis (plural axes) of the system, and the point where they meet is its origin, at ordered pair (0, 0).