I need to write a program, using getline and copy (which we were given via the textbook) that takes in multiple lines of random letters, and outputs how many unique letters are in the line (upper and lowercase count the same).

This was my attempt at that but it doesnt provide any output. What am I doing wrong?

(This is in C programming)​

Answer:

Name

Explanation:

Answer:

name

Explanation:

brain

Answer:

prey

Explanation:

Answer:

food plis let me now if am wrong

Explanation:

Answer:

Trojan Horse

Explanation:

A trojan horse is something that looks different than what it really is; it's deceptive.

Answer: I’m sorry, but what is your question? Then, I may be able to help you. Also, add a link (image)!

Explanation: Thank You!

Answer:

Hi! There has to be two answers to your question. That is the only way you are able to give a brainliest. You can give a brainliest if you believe a person who wrote an answer to your question fully detailed and organized. It has to answer your question.

Hope this helps! :D

Answer:

b

Explanation:

because i think i go with my gut

Answer: ask someone to show or explain the doll to him

Explanation:

edmentum

Answer: ask someone to show or explain the doll to him

Explanation:

If Joe asks his teammates to show or explain the doll to him, he too can contribute ideas for the successful completion of the project.

The step that Jim should try first to resolve the issue is to check for and install patches or software updates. Thus, the correct option for this question is D.

A software update may be defined as a sequence of changes to the software in order to update, fix or improve it. Changes to the software will usually either fix bugs, fix security vulnerabilities, provide new features or improve performance and usability.

The process of software update usually fixes bugs in your current operating system and secures your phone from malicious attacks by fixing any security lapses. G-Pixel handsets receive security updates every month. However, that's not the case with all Android phones.

Therefore, checking for and installing patches or software updates is the step that should Jim try first in order to resolve the issue. Thus, the correct option for this question is D.

To learn more about Software updates, refer to the link:

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Answer:

qegfds

Explanation:

Answer:

Here is the get_pos function:

def get_post(string):  #function that takes string as parameter

   string=string.lower() #converts the string to lower case                    

   string=strip_punctuation(string)  #calls strip_punctuation to remove punctuation from string

   string=string.split() #split the string into a list      

   count_positive=0  #counts the occurrences of positive words

   for word in string:  #loops through the string

       if word in positive_words:  #if a word in a string is a positive words

           count_positive=count_positive+1  #adds 1 to the count of count_positive each time a positive word appears

   return count_positive #returns the positive integer - how many occurrences there are of positive words in the string

Explanation:

In order to explain the working of this function lets suppose the punctuation_chars list contains the following punctuation characters:

punctuation_chars = ["'", '"', ",", ".", "!", ":","?", ";", '#']

Lets suppose the positive_words.txt file contains the following two words i.e. yes  okay

Lets suppose the string is Hi! I am okay, see you later.

string = " Hi! I am okay, see you later. "

string=string.lower()  statement converts the string to lower case:

string = hi! i am okay, see you later.

string=strip_punctuation(string)   this statement calls strip_punctuation method to remove the punctuation from string.

string = hi i am okay see you later

string=string.split() this statement splits the sentence into list

['hi', 'i', 'am', 'okay', 'see', 'you', 'later']  

for word in string: this loop iterates through the string

At first iteration if condition checks if word "hi" is in positive_words. This is not true because positive_words only contain the words okay and yes.

At next iteration if condition checks if word "i" is in positive_words. This is not true because positive_words only contain the words okay and yes.

At next iteration if condition checks if word "am" is in positive_words. This is also not true.

At next iteration if condition checks if word "okay" is in positive_words. This is true because positive_words contains the words okay. So count_positive=count_positive+1 statement executes which adds 1 to the count of count_positive so

count_positive = 1

At next iteration if condition if word in positive_words checks if word "see" is in positive_words. This is not true.

At next iteration if condition checks if word "you" is in positive_words. This is also not true.

At next iteration if condition checks if word "later" is in positive_words. This is also not true.

Now the statement:  return count_positive  returns the occurrence of positive words in the string which is 1. So the output of this is 1.

Here is the strip_punctuation method:

def strip_punctuation(word):  #removes punctuation from words

   New_word=""   #initializes new word string to empty

   print("Word is: ",word)  #prints the word

   for w in word:  #iterates through words

       if w not in punctuation_chars:  #if word is not in punctuation_char list

           New_word=New_word+w  #adds that word to new word string

   return  New_word #returns word after removing punctuation

Answer:

"HL7 Translator" seems to be the appropriate answer.

Explanation:

Answer:

D is the answer

Explanation:

because arteriales don't requare valves because they only go to one direction

Answer:

Here is the JAVA program :

import javax.swing.JOptionPane;   //to use JOptionPane  

public class Main {   //class name

public static void main(String[] args) { //start of main method

   int ECount= 0;   //counts number of upper case E

   int eCount= 0;  //counts number of lower case e

   String sentence;   //stores input sentence string

sentence = JOptionPane.showInputDialog(null, "Type a sentence (type stop to exit)");  //uses showInputDialog method to display a dialog box which prompts user to enter a sentence

 int length = sentence.length();  //stores the length of the sentence

 while (!sentence.equalsIgnoreCase("stop"))  //the loop continues to execute until the user types stop

{ for (int i = 0; i < length; i++) { //loops through the sentence

             if (sentence.charAt(i) == 'E')  //if the character is an uppercase E

                  ECount += 1;  //adds 1 to the count of Ecount

             if (sentence.charAt(i) == 'e')  //if the character in a sentence is lowercase e

                  eCount += 1;}  //adds 1 to the count of lower case e

JOptionPane.showMessageDialog(null, "There are " + ECount + " number of E's and " + eCount + "  number of e's in " +sentence);   //displays the number of times uppercase and lowercase (E and e) occur in sentence

sentence = JOptionPane.showInputDialog(null, "Type a sentence (type stop to exit");  //prompts user to enter the next sentence

length = sentence.length();  //stores the length of sentence at each iteration of while loop until user enters stop

eCount=0;  //resets the counter of lowercase e

ECount=0;  } } } //resets the counter of uppercase e

Explanation:

The program uses showInputDialog() method that displays a dialog box on output screen. This dialog box prompts the user to enter a string (sentence) Suppose user enters "Evergreen" as input sentence so

sentence = "Evergreen"

Next the length of this string is computed using length() method and stored in length variable. So

length = sentence.length();

length = 9

The for loop iterates through this input sentence until the variable i is less than length i.e. 9

At first iteration

if (sentence.charAt(i) == 'E') becomes

if (sentence.charAt(0) == 'E')

Here charAt() method is used which returns the character at the specified index i. This if condition is true because the character at 0-th index (first character) of the sentence Evergreen is E. So ECount += 1; statement adds 1 to the count of upper case E so

ECount = 1

At second iteration:

if (sentence.charAt(1) == 'E')

this condition is false because the character at 1st index of sentence is 'v' which not an upper case E so the program moves to next if condition if (sentence.charAt(i) == 'e') which is also false because the character is not a lower case e either.

At third iteration:

if (sentence.charAt(2) == 'E')

this condition is false because the character at 2nd index of sentence is 'e' which not an upper case E so the program moves to next if condition if (sentence.charAt(i) == 'e') which is true because the character is a lower case e. So the statement eCount += 1; executes which adds 1 to the count of e.

eCount = 1

So at each iteration the sentence is checked for an upper case E and lower case e. After the loop breaks, the program moves to the statement:

JOptionPane.showMessageDialog(null, "There are " + ECount + " number of E's and " + eCount + "  number of e's in " +sentence);

which displays the number of uppercase E and lower case e in a message dialog box. So the output is:

There are 1 number of E's and 3 number of e's in Evergreen.

Then because of while loop user is prompted again to enter a sentence until the user enters "stop". Now the user can enter Stop, StOp, STOp etc. So equalsIgnoreCase method is used to cover all upper/lower case possibilities of the word "stop".

The screenshot of the program and its output is attached.

Answer:

B. grants

Explanation: This is the correct answer on Edge 2021, just did the assignment. Hope this helps ^-^.

the answers are:

- cleaning the fan

- backup

- cleaning out unneeded files

- widget

- removing unwanted applications

- checking the hard drive for errors

Answer:

The working principle of the computer system. Computers do the work primarily in the machine and we can not see, a control center that converts the information data input to output. This control center, called the central processing unit (CPU), How Computers Work is a very complex system.

Explanation:

Answer:

import java.util.Scanner;

public class InchConversion

{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

 System.out.print("Enter inches: ");

 double inches = input.nextDouble();

 inchesToFeet(inches);

 inchesToYards(inches);

}

public static void inchesToFeet(double inches){

    double feet = inches / 12;

    System.out.println(inches + " inches = " + feet + " feet");

}

public static void inchesToYards(double inches){

    double yards = inches / 36;

    System.out.println(inches + " inches = " + yards + " yards");

}

}

Explanation:

In the inchesToFeet() method that takes one parameter, inches:

Convert the inches to feet using the conversion rate, divide inches by 12

Print the feet

In the inchesToYards() method that takes one parameter, inches:

Convert the inches to yards using the conversion rate, divide inches by 36

Print the yards

In the main:

Ask the user to enter the inches

Call the inchesToFeet() and inchesToYards() methods passing the inches as parameter for each method

Answer:

I believe it is the Second Option as all the others are correct.

Answer:

B. When the content is highly sensitive or emotional

Explanation:

B. When the content is highly sensitive or emotional.

Answer:

after you are accepted in the college

Explanation:

You should apply for admission to the colleges you are interested in BEFORE filing your FAFSA. Once you are accepted to the colleges you have applied to, you can add those schools to receive financial aid award offers from when you file your FAFSA.

Answer:

Probably Wi-Fi or a network but if you need more specific i'm not sure

Explanation:

Answer:

nunya

Explanation:

Answer:

Explanation:

The shortest time needed means that we are not taking into account the amount of time it takes to switch pancakes, flip them, or take them out of the pan, etc. Only cooking them. Therefore, written in Java would be the following...

public static int minutesNeeded (int numCakes, int panCapacity) {

       int minutesNeededtoCook = 0;

       while (numCakes != 0) {

           if (numCakes > panCapacity) {

               numCakes -= panCapacity;

               minutesNeededtoCook += 10;

           } else {

               numCakes = 0;

               minutesNeededtoCook += 10;

           }

       }

       return minutesNeededtoCook;

   }

The code takes in the amount of pancakes and the pan capacity, then compares them and adds 10 minutes (5 on each side) per pancake batch that is being made until all the pancakes are made.

According to the Modern Language Association (MLA) guidelines, the correct line spacing for a document is double-spacing. This means that there should be a full blank line between each line of text in the document. Hence, option A is the correct answer.

Double spacing helps improve readability and makes it easier for readers to distinguish between different lines of text. It also allows for better legibility and makes it easier to add annotations or comments to the document.

It's important to note that the MLA guidelines may change over time, so it's always a good idea to consult the most recent edition of the MLA Handbook or check with your instructor or institution for any specific requirements regarding line spacing or formatting.

Hence, option A is the correct answer.

Learn more about MLA here:

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Answer:

\frac is the shortcut for inserting fraction in ms-word

e.g of a/b = \frac {a}{b}

Answer:

The answer is "Cooperation

"

Explanation:

Answer:

Microsoft Windows is one of the world most popular operating system

. answer is windows please mark me brain list

Answer:

The function written in Python is as follows:

def checksublist(lista,listb):

     if(all(elem in lista for elem in listb)):

           print("The first list is a sub list of the second list.")  

     else:

           print("The first list is not a sub list of the second list.")

Explanation:

This line defines the function

def checksublist(lista,listb):

The following if condition checks if list1 is a subset of list2

     if(all(elem in lista for elem in listb)):

           print("The first list is a sub list of the second list.")  

The following else statement is executed if the above if statement is not true

     else:

           print("The first list is not a sub list of the second list.")

The function that takes two integer lists (not necessarily sorted) and returns true precisely when the first list is a sub list of the second is as follows:

def check_sublist(x, y):

  if(set(x).issubset(set(y))):

     return "The first list is a sublist of the second"

  else:

     return "The first list is not a sublist of the second"

print(check_sublist([2, 3, 5], [1, 2, 3, 4, 5, 6, 7]))

The code is written is python.

learn more on python code here; https://brainly.com/question/25797503?referrer=searchResults

Answer:

Sometimes called the press junket or film junket, film promotion generally includes press releases, advertising campaigns, merchandising, franchising, media and interviews with the key people involved with the making of the film, like actors and directors.

Explanation: