I need help with this please

By similarity of triangle the height of a children will be 4ft.

Similar triangles are that kind of triangles that have the same shape, but different  sizes. examples of similar objects are All equilateral triangles, squares of any side lengths. In another words, if two triangles having their corresponding angles are congruent and corresponding sides are in equal proportion then two triangles are said to be similar. It is denoted  by ‘~’ symbol.

We can use the property of similar triangles to estimate the height of the child:

The ratio of the height of the adult to the length of their shadow is the same as the ratio of the height of the child to the length of their shadow:

height of adult / length of adult shadow = height of child / length of child shadow

Plugging in the values we know:

6 / 15 = height of child / 10

Solving for the height of the child:

height of child = (6 / 15) * 10 = 4 feet

Therefore, the estimated height of the child is 4 feet.

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Drag the following statement, equation or reason to each box to complete this proof accordingly:

2. Multiplication Property of Equality

3. x-2 = 8  

4. Addition Property of Equality

5. x = 10               Simplifying

An equation is a mathematical statement that expresses the equality between two expressions. It contains an equal sign "=" that separates the two expressions.

The proof of the equation with reason can be completed as follow:

(x-2)/4 = 2                                 Given

4(x-2)/4 = 4 * 2                         Multiplication Property of Equality

x-2 = 8                                      Simplifying

x - 2+ 2 = 8 + 2                         Addition Property of Equality

x = 10                                        Simplifying

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The composite figure compromising of a sector, a triangle and a trapezoid have a total area calculated to be 15.9 square units.

We can observe from the figure that it is a combination of a sector, a triangle and a trapezoid, so we shall calculate the area of each shape and add their result to get the area of the composite figure as follows:

area of the sector = 135°/360° × 22/7 × 2 × 2

area of the sector = 33/7

area of the sector = 4.7 square units

area of triangle = 2.6 × 1

area of the triangle = 2.6 square units

area of the trapezoid = 1/2 × (2.6 + 6) × 2

area of the trapezoid = 8.6 square units

area of the composite figure = 4.7 + 2.6 + 8.6

area of the composite figure = 15.9 square units

In conclusion, the composite figure compromising of a sector, a triangle and a trapezoid have a total area calculated to be 15.9 square units.

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The conditional probability that a randomly selected participant wore leather pants and played an acoustic guitar is 6/25. Therefore, the answer is option D. 6/25.

Conditional probability is the probability that an event will occur given that another event has already occurred.

It is denoted by P(A|B), where A and B are events, and the vertical line | indicates "given that" or "conditional on".

The conditional probability of an event A given event B is defined as the probability of both A and B happening divided by the probability of B happening:

P(A|B) = P(A and B) / P(B)

In this case, the event A is playing an acoustic guitar and the event B is wearing leather pants.

We can start by finding the probability of wearing leather pants:

P(B) = (6 + 9) + (3 + 7) = 25

This is because there are a total of 6 contestants wearing leather pants and 19 contestants in total.

Next, we need to find the probability of both wearing leather pants and playing an acoustic guitar:

P(A and B) = 6

This is because there are 6 contestants wearing leather pants and playing an acoustic guitar.

Now we can use the formula to find the conditional probability:

P(A|B) = P(A and B) / P(B) = 6 / 25

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1. The triangles are not similar because they do not have proportional set of sides.

2. Both triangles are not similar as well.

The SSS similarity theorem states that if three corresponding sides of two triangles are proportional, then the triangles are similar. "SSS" stands for "side-side-side," which refers to the three corresponding sides that are proportional.

More formally, the SSS similarity theorem can be stated as follows:

If ΔABC ~ ΔDEF, then: AB/DE = BC/EF = AC/DF (the sides are proportional)

1. QP/ML = 90/40 = 2.25

RQ/LK = 81/36 = 2.25

PR/MK = 64/28 = 2.29

Thus, this means that QP/ML = RQ/LK ≠ PR/MK. This implies the three sides are of both triangles are not proportional. Therefore, they are not similar by SSS nor any other theorem.

2. Both triangles do not have any set of corresponding angles that are congruent, therefore, they are not similar.

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Step-by-step explanation:

5. Name the Circle.

Ans. Circle C.

6. Name to radii.

Ans. BH, AD

7. Name two chords.

Ans. AD ,BH

8. Name a diameter

Ans. AD

9. Name a secant .

Ans. KG

10.Name a tangent

Ans. GE

Point of tangency = F

More to Know :

• Radii: The distance from the centre of the circle to the circumference.

• Chord: Chord is a line segment that have two end points on the circle

• Secant: It refers to the line that intersect the circle at two points.

• Diameter: The lines that passes from the centre of the circle and meet at both the ends of the circle.

• Point of tagency: It is referred to the point where the tangent meets the circle.

[tex]\\[/tex]

Answer:

Answer 3

Step-by-step explanation:

Answer: 3

Step-by-step explanation:

Answer:

12.5

Step-by-step explanation:

9.6² + 2.8² = 10²

10² + 7.5² = 12.5²

Answer:

The sonar station will not detect the submarine.

Step-by-step explanation:

The area that the sonar station can detect can be modelled as a circle with center (0, 0) and radius 5 km.

The equation of a circle formula is (x - h)² + (y - k)² = r², where (h, k) is the center and r is the radius.

Therefore, the equation of the circle modelling the perimeter of the sonar station detection area is:

[tex]\implies (x-0)^2+(y-0)^2=5^2[/tex]

[tex]\implies x^2+y^2=25[/tex]

To determine whether the sonar station will detect a swiss submarine traveling along a trajectory defined by y = -2/3x + 26/3, substitute the equation of the trajectory into the found equation of the circle.

[tex]\implies x^2+\left(-\dfrac{2}{3}x+\dfrac{26}{3}\right)^2=25[/tex]

Simplify:

[tex]\implies x^2+\dfrac{4}{9}x^2-\dfrac{104}{9}x+\dfrac{676}{9}=25[/tex]

[tex]\implies 9x^2+4x^2-104x+676=225[/tex]

[tex]\implies 13x^2-104x+451=0[/tex]

Solve the equation for x using the quadratic formula:

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

[tex]\implies x=\dfrac{-(-104) \pm \sqrt{(-104)^2-4(13)(451)}}{2(13)}[/tex]

[tex]\implies x=\dfrac{104 \pm \sqrt{-12636}}{26}[/tex]

[tex]\implies x=\dfrac{104 \pm 18\sqrt{39}\:i}{26}[/tex]

[tex]\implies x=4 \pm \dfrac{9\sqrt{39}}{13}\:i[/tex]

As the solutions are complex numbers, this means that the linear trajectory of the submarine will not intersect the detection area of the sonar station. Therefore, the sonar station will not detect the submarine.

Thus, following the transformation T-5,00 D2, the image point of (-9,-5) is (-8,-10). Hence, choice C is the right response.

The term "transformations" refers to the movements or adjustments that can be made to a geometric shape or object, such as turning, reflecting, translating, processes in an organization, or resizing. With these procedures, the original form or object can retain its geometry, angles, and other geometric attributes while changing its position, size, and orientation. Geometry, photography, and other disciplines frequently employ transformations to manipulate and examine patterns and shapes.

given

Applying the translation T-5,00 to the point (-9,-5) first yields (-9-(-5),-5+0) =, which we can use to determine the image point of (-9,-5) following the transformation T-5,00 D2 (-4,-5).

Then, we dilate the point (-4, -5) using the formula (2(-4,2(-5)) = (-8,-10).

Thus, following the transformation T-5,00 D2, the image point of (-9,-5) is (-8,-10). Hence, choice C is the right response.

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Answer:There seems to be a typo in the equation for f(x). I will assume that the correct equation is:f(x) = 4x - 25To find the first x value where g(x) > f(x), we can set the two equations equal to each other and solve for x:g(x) = f(x)

2(5)x = 4x - 25

10x = 4x - 25

6x = -25

x = -25/6

Step-by-step explanation:However, we need to check if this value satisfies the condition g(x) > f(x):g(-25/6) = 2(5)(-25/6) = -25

f(-25/6) = 4(-25/6) - 25 = -75/3 - 25/1 = -100/3Therefore, g(x) > f(x) is not true for x = -25/6. We need to keep looking for a larger value of x where g(x) > f(x).To do this, we can graph the two functions and look for the point where the graph of g(x) is above the graph of f(x). Alternatively, we can simply plug in some larger values of x and compare the values of g(x) and f(x) until we find the first x value where g(x) > f(x).Let's try plugging in x = 0:g(0) = 2(5)(0) = 0

f(0) = 4(0) - 25 = -25Since g(0) = 0 and f(0) = -25, we have g(x) > f(x) for x > 0. Therefore, the first x value where g(x) > f(x) is x = 0.

Answer:

undetermined  or most likely Tasmania

Step-by-step explanation:

Based on the choices of experts in the first round of the Australian netball competition, we can conclude that Victoria played against WA. This is because, out of the common tips, WA was tipped by an expert who also tipped Victoria and didn't tip Queensland. Therefore, WA is the likely team that Victoria played against.

To identify which team Victoria played in the Australian netball competition we can reason through our experts' tips. The experts' tips overlap at Queensland and WA as indicated by Expert A and Expert B. However, Expert C tipped Victoria, and they did not tip Queensland which tells us that Victoria did not play against Queensland, leaving us with WA. Hence Victoria must've played against WA.

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Answer:

Delia's hair grew less since her last haircut

Step-by-step explanation:

2.45 centimeters is a higher number then 2.03, making Delia's hair shorter than Carolyn's.

Answer:

Delia's hair grew less.

Step-by-step explanation:

2.45 - 2.03 = 0.42

Deila's hair is 0.42 less than Carolyn's hair.

Answer:

[tex]y=40\sqrt{\frac{6}{x} }[/tex]

[tex]y=-40\sqrt{\frac{6}{x} } ,x > 0[/tex]

Step-by-step explanation:

pls tell me if wrong have a good night/day

The image of the triangle is attached with coordinates

(0, 0)

(0. 3)

(3, 3)

In mathematics, a scale factor is a constant that multiplies every length of an object, changing its size while preserving its shape. In the context of dilation, which is a type of transformation that changes the size of a shape, the scale factor determines the amount by which the shape is enlarged or reduced.

When a shape is dilated with a scale factor greater than 1, the resulting shape is larger than the original. Conversely, when a shape is dilated with a scale factor between 0 and 1, the resulting shape is smaller than the original. If the scale factor is exactly 1, then the shape remains the same size.

In the problem the image is dilated with a scale factor less than one hence the resulting image is lesser

The new coordinates are gotten as follows

(0, 0) * 1/3 =  (0, 0)

(0. 9) * 1/3 =  (0. 3)

(9, 9) * 1/3 =  (3. 3)

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Answer:

If two lines and a transversal form alternate interior angles that are congruent, then the two lines are parallel. Converse of the Same-Side Interior Angles Postulate: If two lines and a transversal form same-side interior angles that are supplementary, then the two lines are parallel.

Answer: 2(x-6) < -3(x-1) is x < 3.

Step-by-step explanation:
2(x-6) < -3(x-1)

Expanding the brackets, we get:

2x - 12 < -3x + 3

Adding 3x to both sides, we get:

5x - 12 < 3

Adding 12 to both sides, we get:

5x < 15

Dividing both sides by 5, we get:

x < 3

Answer:

x>12

Step-by-step explanation:

1/3(x-6)>2

distribute 1/3

1/3x-2>2

add 2 to both sides

1/3x>4

multiply both sides by 3

x>12

Answer:

The number of minutes it will take for a liquid and a solid to reach the same temperature is 3 minutes.

Step-by-step explanation:

You know that the temperature of liquid at 16.9°C is decreasing at a rate of 2.3°C per minute. Then, the temperature of the liquid after t minutes, as its value decreases, will be the difference between the initial temperature of 16.9 ° C and the temperature after t minutes. So:

temperature of the liquid= 16.9°C - 2.3 °C/minute * t

On  the other  side, you know that the temperature of a solid at 30.7°C is decreasing at a rate of 6.9°C per minute. Then, the temperature of the solid after t minutes, as its value decreases, will be the difference between the initial temperature of 30.7°C and the temperature after t minutes. So:

temperature of the solid= 30.7°C - 6.9 °C/minute * t

You want to calculate the number of minutes it will take for a liquid and a solid to reach the same temperature. This is:

temperature of the liquid= temperature of the solid

16.9°C - 2.3 °C/minute * t= 30.7°C - 6.9 °C/minute * t

Solving:

- 2.3 °C/minute * t= 30.7°C - 6.9 °C/minute * t - 16.9°C

- 2.3 °C/minute * t + 6.9 °C/minute *t= 30.7°C - 16.9°C

4.6 °C/minute * t = 13.8 °C

t=3 minutes

So the number of minutes it will take for a liquid and a solid to reach the same temperature is 3 minutes.

Answer:

x = 2,5

Step-by-step explanation:

[tex]3(3 - 2x) = 2x - 11[/tex]

[tex]9 - 6x = 2x - 11[/tex]

Put numbers with x's to the left, and the plain numbers to the right:

[tex] - 6x - 2x = - 11 - 9[/tex]

[tex] - 8x = - 20[/tex]

[tex]x = 2.5[/tex]

Answer:y=-x+6

Step-by-step explanation:

2/3 of 35 is 23. Kofi is 23.

The reason why the green triangle is not possible given an angle of 30° and a side length of 8.73 is due to the fact that the green triangle violates the triangle inequality theorem.

According to the triangle inequality theory, any triangle's lengths of any two sides must add up to more than the length of the third side.

The triangle inequality theorem is broken in the instance of the green triangle if the second side is extended to a very long length, making the triangle's lengths of the two shorter sides (7 and 8.73) less than the length of the longer side (24).

The orange triangle, which has side lengths of 7, 15, and roughly 16.16 (determined using the Pythagorean equation), is the only one that can exist because the green triangle is impossible.

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The rectangle's area is growing at a pace of 138 [tex]\frac{cm^{2} }{s}[/tex] when its length is 10 cm and its width is 6 cm, this is the case.

One quantity's rate of change with regard to another quantity is known as the rate of change function. In order to calculate the rate of change, one simply divides the amount of change in one item by the equivalent amount of change in another.

Let L and W represent the length and breadth of the rectangle, respectively, and A represents the area of the rectangle. Next, we have:

A = L * W

When L = 10 cm and W = 6 cm, we are interested in determining the rate of increase of the rectangle's area with regard to time, or dA/dt.

We can begin by finding the derivative of A = L * W with regard to time t for both sides of the equation:

Derivate the equation by both sides with respective t.

[tex]\frac{d}{dt} (L * W) = \frac{dA}{dt}[/tex]

Using the principle of product rule of derivative, we arrive at:

[tex]L * W + L * \frac{dw}{dt} = \frac{dA}{dt}[/tex]

To determine dA/dt when L = 10 cm and W = 6 cm, we are provided that [tex]\frac{dL}{dt}[/tex] = 8 cm/s and [tex]\frac{dw}{dt}[/tex]= 9 cm/s. Therefore, we replace these numbers in the previous equation to obtain:

[tex]\frac{dA}{dt}[/tex] = (8 [tex]\frac{cm}{s}[/tex]) * (6 cm) + (10 cm * 9 [tex]\frac{cm}{s}[/tex]).

[tex]\frac{dA}{dt} = 48 \frac{cm^{2}}{s} + 90 \frac{cm^{2}}{s} \\[/tex]

[tex]138 \frac{cm^{2} }{s} = \frac{dA}{dt}[/tex]

Since the rectangle's area is growing at a pace of 138 [tex]\frac{cm^{2} }{s}[/tex]when its length is 10 cm and its width is 6 cm, this is the case.

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The "loading" of the die makes P(1)=112, P(6)=312, and the following four outcomes equally likely. A roll with an even number larger than two has a 50% probability of occurring.

The probability of rolling an even number is 1/2 since there are three even numbers (2, 4, 6) and six possible outcomes in total.

The probability of rolling a number greater than two is 5/6 since there are five outcomes (3, 4, 5, 6) greater than two and six possible outcomes in total.

To find the probability that the number rolled is both even and greater than two, we need to find the probability of rolling a 4 or a 6 since these are even numbers that are greater than two.

The probability of rolling a 4 is P(4) = 1/12 + 1/6 = 1/4 since the die is loaded to favour a 6 over the other numbers, but all other outcomes are equally likely.

The probability of rolling a 6 is P(6) = 3/12 = 1/4 since the probability of rolling a 6 is given as 3/12.

Therefore, the probability of rolling an even number that is greater than two is:

P(even and greater than two) = P(4 or 6) = P(4) + P(6) = 1/4 + 1/4 = 1/2.

So the probability of rolling an even number that is greater than two is 1/2.

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Answer: To find out how many rides take place in 28 minutes, we need to divide the total ride length by the length of one side, and then round down to the nearest whole number.

The length of one ride can be calculated by dividing the total ride length by the number of rides. Since we don't know the number of rides, let's call it "n":

length of one ride = total ride length / n

314 minutes / n

Now we can set up an equation to solve for "n":

28 minutes = length of one ride * number of rides

28 minutes = (314 minutes / n) * number of rides

We can simplify this equation by multiplying both sides by "n":

28 minutes * n = 314 minutes * number of rides

Dividing both sides by 314 minutes, we get:

n = (28 minutes * number of rides) / 314 minutes

Multiplying both sides by 314 minutes and dividing by 28 minutes, we get:

number of rides = (n * 314 minutes) / 28 minutes

number of rides = 11.21

Rounding down to the nearest whole number, we get:

number of rides = 11

Therefore, in 28 minutes, 11 rides take place.

Step-by-step explanation:

Answer:

a) Distance is 40m b)0 c)2.5m/min

Step-by-step explanation:

a)8*5=40 b)He went from A to A c)16 min s=d/t 40/16

Answer: The total amount of the hummingbirds' weight is 15 grams.

Step-by-step explanation:

As it is shown in the dot graph, the four hummingbirds' weigh is recorded to the nearest gram.

Hummingbird 1 - 2 1/2

Hummingbird 2 - 3

Hummingbird 3 -  4 1/2

Hummingbird 4 - 5

2 1/2 + 4 1/2 = 7

3 + 5 = 8

Seven plus eight equals to fifteen. Therefore, the total weight of all four hummingbirds is 15.

The volume integral for f(x,y,z) = 1 over the region E : x² + y² + z² ≤ 4,

1) In spherical coordinates system is

[tex]V = {\int_{0}^{2π} \int_{0}^{π} \int}_{0}^{2} \rho^{2} \sin( \phi) \: d\rho d\phi d\theta[/tex]

2) In cylinderical coordinates system is

[tex]V = \int_{0}^{2π} \int_{0}^{2} (\int_{-\sqrt {4 - x² - y²}}^{\sqrt{ 4 - x² - y²}} dz) rdr d \theta \\ [/tex]

3) In rectangular coordinates syatm is

[tex]V = \int_{0}^{2}\int_{-\sqrt {4 - x²}}^{\sqrt{4 - x²}} \int_{ - \sqrt{ 4 - x² - y²}}^{ \sqrt{4 - {x}^{2} - {y}^{2} } } \: dz dy dx \\ [/tex]

We pick a region E : x² + y² + z² ≤ 4 and determine volume over the region E for function, f(x,y,z ) = 1 .

[tex]V = {\int \int \int}_{E} f(x,y,z) dV[/tex]

In spherical coordinates system we plug,

[tex]x = \rho sin \phi cos \theta[/tex]

[tex]y = \rho sin \phi sin \theta[/tex]

[tex]z = \rho cos \phi [/tex]

[tex]dV = dx dy dz = |J| d\rho d\phi d\theta [/tex]

where, [tex]|J| = \rho² sin \phi[/tex]

=> [tex]dx dy dz = \rho² sin \rho d\rho d\phi d\theta[/tex]

So, [tex]V = {\int \int \int}_{x² + y² + z² ≤ 4} 1 \: dxdy dz[/tex]

Now, [tex]V = {\int_{0}^{2π} \int_{0}^{π} \int}_{0}^{2} \rho^{2} \sin( \phi) \: d\rho d\phi d\theta[/tex]

Region , E : x² + y² + z² ≤ 4

=> z² ≤ 4 - x² - y²

=> z ≤ ± √4 - x² - y²

[tex]V = {\int \int_{ x² + y² ≤ 4} \int}_{ - \sqrt{ 4 - x² - y²}}^{ \sqrt{4 - {x}^{2} - {y}^{2} } } 1 \: dz dx dy \\ [/tex]

here, r∈[0, 2], θ∈[0,2π]

[tex]V = \int_{0}^{2π} \int_{0}^{2} (\int_{-\sqrt {4 - x² - y²}}^{\sqrt{ 4 - x² - y²}} dz) rdr d \theta \\ [/tex]

[tex]V = {\int \int \int}_{E} f(x,y,z) dV[/tex]

[tex]V = {\int \int_{ x² + y² ≤ 4} \int}_{ - \sqrt{ 4 - x² - y²}}^{ \sqrt{4 - {x}^{2} - {y}^{2} } } 1 \: dz dx dy \\ [/tex]

Here, y² ≤ 4 - x²

=> y = ± √4 - x² and x∈ [0,2], So,

[tex]V = \int_{0}^{2}\int_{ -\sqrt {4 - x²}}^{\sqrt{4 - x²}} \int_{ - \sqrt{ 4 - x² - y²}}^{ \sqrt{4 - {x}^{2} - {y}^{2} } } \: dz dy dx \\ [/tex]

Hence, in above we determined the volume integral for region, E in all three coordinates systems.

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