The concentration of Cl- in the serum sample is 4.82 x 10-3 M.
What is concentration?Concentration is a mental state in which a person focuses on a single activity or thought. It involves the ability to focus one’s attention on a task, block out distractions, and maintain focus for an extended period of time. Concentration is an important skill for productivity, problem-solving, and creativity. It is also essential for academic success, as students must be able to focus on their studies for long periods of time. Concentration can also be useful in everyday life, as it helps us to make decisions, think clearly, and stay organized.
The principle of the titration is based on the following equation:
2Cl(aq) +Hg(NO3)2(aq) → 2NO3(aq) + HgCl₂(s)
Given the data, we can calculate the concentration of Cl- in the serum sample:
1. Calculate the moles of Hg(NO3)2 (aq) used in the titration:
Moles = (concentration of Hg(NO3)2) x (volume of Hg(NO3)2)
= (8.25 x 10-4 M) x (1.46 mL)
= 0.001205 mol
2. Calculate the moles of Cl- in the sample:
Moles = (concentration of Cl-) x (volume of Cl-)
= (C1) x (0.25 mL)
= 0.001205 mol
3. Calculate the concentration of Cl- in the serum sample:
Concentration of Cl- = (moles of Cl-) / (volume of serum sample)
= 0.001205 / 0.25 mL
= 4.82 x 10-3 M
Therefore, the concentration of Cl- in the serum sample is 4.82 x 10-3 M.
To know more about concentration-
https://brainly.com/question/18761928
#SPJ1
what is the chemical value of nitrogen monoxide?
Answer:
it is "no"
Explanation:
do u understand
CAN SOMEONE HELP WITH THIS QUESTION?
1234y5934y89524y5284952y542
WILL MARK BRAINLIEST
2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g) in word form
Potassium (K) reacts with water (H2O) to form potassium hydroxide (KOH) and hydrogen gas (H2).
What is Balanced Chemical Equation?
A balanced chemical equation is a representation of a chemical reaction that shows the relative numbers of reactant and product molecules that participate in the reaction. It obeys the law of conservation of mass, which states that matter cannot be created or destroyed, only transformed from one form to another.
The given chemical equation represents a chemical reaction between potassium (K) and water (H2O), which results in the formation of potassium hydroxide (KOH) and hydrogen gas (H2).
When potassium is added to water, it reacts vigorously, releasing hydrogen gas and forming an alkaline solution of potassium hydroxide. The balanced chemical equation shows that for every 2 moles of potassium (K) and 2 moles of water (H2O), 2 moles of potassium hydroxide (KOH) and 1 mole of hydrogen gas (H2) are produced.
Learn more about Balanced Chemical Equation from the given link
https://brainly.com/question/11904811
#SPJ1
Determine the empirical formula of a compound that is composed of 39.27g Iron and 33.77g sulfer (please give indepth explanation)
Answer:
To determine the empirical formula of a compound, we need to know the relative amounts of each element in the compound. Given the masses of iron and sulfur, we can calculate the number of moles of each element present:
moles of iron = 39.27 g / 55.85 g/mol = 0.703 mol
moles of sulfur = 33.77 g / 32.06 g/mol = 1.053 mol
We can then find the ratio of these moles by dividing both by the smallest number of moles (0.703):
0.703 mol Fe : 1.053 mol S
0.667 Fe : 1.000 S
This ratio indicates that there are approximately 0.667 atoms of iron for every 1 atom of sulfur in the compound.
To convert this ratio to a whole-number ratio of atoms, we need to multiply by a factor that will give us whole numbers. We can do this by dividing both sides of the ratio by the smallest number of atoms:
0.667 Fe : 1.000 S
0.667/0.667 Fe : 1.000/0.667 S
1.000 Fe : 1.498 S
This gives us a ratio of approximately 1 atom of iron for every 1.498 atoms of sulfur. To get a whole-number ratio, we can multiply both sides by 2:
2.000 Fe : 2.996 S
Rounding to the nearest whole number, we get a ratio of:
2 Fe : 3 S
Therefore, the empirical formula of the compound is Fe2S3.
An ideal gas (at STP) has a volume of 5 L, how many moles of the gas are present?
Answer:
At STP (standard temperature and pressure), the conditions are:
Temperature (T) = 273.15 K Pressure (P) = 1 atm = 101.3 kPa Volume (V) = 22.4 L (for one mole of gas)
So, for a gas at STP with a volume of 5 L, we can use the following formula to calculate the number of moles present:
n = V / Vm
where: n = number of moles V = volume of gas (in liters) Vm = molar volume of gas at STP (22.4 L/mol)
Plugging in the values, we get:
n = 5 L / 22.4 L/mol n = 0.2232 mol (rounded to four significant figures)
Therefore, there are approximately 0.2232 moles of the gas present.
(Please could you kindly mark my answer as brainliest you could also follow me so that you could easily reach out to me for any other questions)
oxidation take place at the anode during electrolysis because the anode is (a) is deficient in electrode (B)is deficient in proton (c) has excess electron (d)has attraction for positive ion
Answer : Option (c) is correct.
During electrolysis, a process in which an electric current is passed through a solution containing ions, two electrodes are immersed in the electrolyte solution. The cathode is the negatively charged electrode, while the anode is the positively charged electrode. The electrolyte solution contains both positively charged ions (cations) and negatively charged ions (anions).
At the anode, oxidation occurs as the positively charged ions (cations) in the electrolyte are attracted to the negatively charged anode. The cations lose electrons and become neutral atoms, and these electrons are transferred to the anode. This loss of electrons by the cations results in their oxidation.
The anode, being the electrode where oxidation occurs, has an excess of electrons, which are attracted by the positively charged cations in the electrolyte. The excess of electrons is due to the fact that the anode is connected to the positive terminal of the power source, which supplies electrons to the electrode.
25 points and i’ll give brainliest!!!
Fast please
Calculate the vapor pressure lowering, ΔP, when 10.0 mL of glycerol (C3H8O3) is added to 500 mL of water at 50oC. At this temperature, the vapor pressure of pure water is 92.5 torr and its density is 0.988 g/mL. The density of glycerol is 1.26 g/mL.
Answer:
To calculate vapor pressure lowering:
Use ΔP = X2 * P2° equation, where X2 is the mole fraction of the solute and P2° is the vapor pressure of the pure solvent at the same temperature.
Calculate mole fraction of glycerol by using moles of glycerol and water.
Calculate vapor pressure of pure water at 50°C using the Antoine equation.
Substitute the values and calculate the vapor pressure lowering, which is 0.459 torr for this problem.
The vapor pressure lowering is 0.213 torr when 10.0 mL of glycerol is added to 500 mL of water at 50°C.
What is vapor pressure?Pressure exerted by vapor in thermodynamic equilibrium with its condensed phases at a certain given temperature in closed system is called vapor pressure.
ΔP = X2 * P0 * (1 - (ρ1 / ρ2))
ΔP is vapor pressure lowering, X2 is mole fraction of the solute (glycerol), P0 is vapor pressure of solvent (water), and ρ1 and ρ2 are the densities of solvent and solution, respectively.
As, moles of glycerol = mass of glycerol / molar mass of glycerol
moles of glycerol = (10.0 mL)(1.26 g/mL) / (92.09 g/mol)
moles of glycerol = 0.136 mol
and moles of water = mass of water / molar mass of water
= (500 mL)(0.988 g/mL) / (18.02 g/mol)
moles of water = 27.5 mol
So, total moles = moles of glycerol + moles of water
total moles = 0.136 mol + 27.5 mol
total moles = 27.6 mol
X2 (mole fraction of glycerol) = moles of glycerol / total moles
= 0.136 mol / 27.6 mol
X2 = 0.00493
ΔP = X2 * P0 * (1 - (ρ1 / ρ2))
= (0.00493)(92.5 torr) * (1 - (0.988 g/mL / 1.250 g/mL))
ΔP = 0.213 torr
Therefore, the vapor pressure lowering is 0.213 torr when 10.0 mL of glycerol is added to 500 mL of water at 50°C.
To know more about vapor pressure, refer
https://brainly.com/question/4463307
#SPJ1
In the body-centered cubic unit cell, the centers of ____________ identical particles define the ____________ of the cube plus ____________ particle at the ____________ of ____________ . The particles do not touch along the cube's ____________ or faces but do touch along the cube's ____________ . There is/are ____________ particles per unit cell and the coordination number is ____________ .,
4. How many moles of NaOH are needed to make a 6 liters of a 3.0 M NaOH solution?
5. How many grams of NaOH are needed to make 4 liters of a 6.0 M NaOH solution?
4. To determine how many moles of NaOH are needed to make a 6 liters of a 3.0 M NaOH solution, we can use the formula:
moles = concentration (in M) x volume (in L)
Substituting the values given, we have:
moles = 3.0 M x 6 L = 18 moles of NaOH
Therefore, 18 moles of NaOH are needed to make a 6 liters of a 3.0 M NaOH solution.
5. To determine how many grams of NaOH are needed to make 4 liters of a 6.0 M NaOH solution, we can use the formula:
moles = concentration (in M) x volume (in L)
Then, we can use the molar mass of NaOH to convert moles to grams:
mass (in g) = moles x molar mass
The molar mass of NaOH is 40 g/mol.
Substituting the values given, we have:
moles = 6.0 M x 4 L = 24 moles of NaOH
mass = 24 moles x 40 g/mol = 960 grams of NaOH
Therefore, 960 grams of NaOH are needed to make 4 liters of a 6.0 M NaOH solution.
Calculate the N/Z ratio for elements with atomic numbers 104 through 109. Are they in the belt of stability? Are they stable? How do you know?
The ratio of neutrons to protons, or the N/Z ratio, plays a crucial role in determining a nucleus' stability. The range of N/Z ratios in which nuclei are stable is generally referred to as the belt of stability.
How can you tell whether a substance is stable or unstable?If the forces between the constituents of the nucleus are equal, an atom is stable. If these forces are out of balance or if the nucleus has an excessive amount of internal energy, an atom is unstable (radioactive).
Z = 104 for Rutherfordium, element 104. The isotopes 261Rf and 262Rf, having masses of 261 and 262, respectively, have the longest half-lives. Accordingly, N/Z ratios are:
261Rf: N/Z = (261-104)/157 = 1.08
262Rf: N/Z = (262-104)/158 = 1.09
These N/Z ratios are a little bit higher than the average belt of stability values, which are about 1.0 for heavy nuclei. These isotopes are thought to be reasonably stable because they are close enough.
Z = 109 for Meitnerium, element 109. The isotopes 278Mt and 282Mt, with masses of 278 and 282, respectively, have the longest half-lives. Accordingly, N/Z ratios are:
278Mt: N/Z
To know more about neutrons visit:-
https://brainly.com/question/29248303
#SPJ1
moles of Zn(NO 3 ) 2 in 173.50 g of this substances
Answer:
To calculate the moles of Zn(NO3)2 in 173.50 g of the substance, we first need to know the molar mass of Zn(NO3)2.
The molar mass of Zn(NO3)2 can be calculated by adding the atomic masses of its constituent elements:
Zn: 1 x 65.38 g/mol = 65.38 g/mol
N: 2 x 14.01 g/mol = 28.02 g/mol
O: 6 x 16.00 g/mol = 96.00 g/mol
Molar mass of Zn(NO3)2 = 65.38 + 28.02 + 96.00 = 189.40 g/mol
Now we can use this molar mass to calculate the moles of Zn(NO3)2 in 173.50 g of the substance:
moles = mass/molar mass
moles = 173.50 g/189.40 g/mol
moles = 0.9164 mol
Therefore, there are 0.9164 moles of Zn(NO3)2 in 173.50 g of the substance.
(Please could you kindly mark my answer as brainliest you could also follow me so that you could easily reach out to me for any other questions)
the presence of chloride ions in a sample can be detected by reacting it with silver nitrate, agno3. if agno3 is added to an aqueous solution of sodium chloride; silver chloride, which contains cl- ions, is essentially insoluble in water, will precipitate from solution as a white solid. create a balanced equation of this reaction.
The balanced equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) to form silver chloride (AgCl) and sodium nitrate (NaNO3) is:
AgNO3 + NaCl → AgCl + NaNO3
A balanced equation is a representation of a chemical reaction that shows the reactants and products involved, as well as the ratios in which they combine. The law of conservation of mass states that in a chemical reaction, the mass of the reactants must be equal to the mass of the products, which means that the number and type of atoms on both sides of the equation must be the same.
To balance an equation, coefficients are added to the reactants and products so that the number of atoms of each element on the left side of the equation is equal to the number on the right side. For example, the combustion of methane gas can be represented by the equation CH4 + 2O2 → CO2 + 2H2O. Balanced equations are essential for understanding chemical reactions and predicting the amount of reactants needed and products formed.
To learn more about Balanced equation visit here:
brainly.com/question/12192253
#SPJ4
Batrachotoxin, C31H42N2O6 , an active component of South American arrow poison, is so toxic that 0.05μg can kill a person.
In 0.05μg, there are [tex]6.9 * 10^{15} molecules[/tex] of batrachotoxin.
To calculate the number of molecules of batrachotoxin, we first need to calculate the molar mass of the molecule. This can be done by adding up the atomic masses of the elements in the compound. The elements in batrachotoxin are carbon (C), hydrogen (H), nitrogen (N), and oxygen (O). The atomic masses of these elements are 12 g/mol for C, 1 g/mol for H, 14 g/mol for N, and 16 g/mol for O. Therefore, the molar mass of batrachotoxin is:
Molar mass = 12 g/mol C + 1 g/mol H + 14 g/mol N + 16 g/mol O
Molar mass = 43 g/mol
We then need to calculate the mass of 0.05 μg of batrachotoxin. This can be done by converting 0.05 μg to grams. To do this, we divide 0.05 μg by 1,000,000. This gives us:
[tex]\frac{0.05\mu g }{ 1,000,000 }= 0.00000005 g[/tex]
Now we can calculate the number of molecules of batrachotoxin in 0.05 μg by dividing the mass in grams by the molar mass:
Number of molecules =[tex]\frac{ 0.00000005 g }{ 43 g/mol}[/tex]
Number of molecules = [tex]1.16 * 10^{-8} mol[/tex]
Finally, we can calculate the number of molecules by multiplying the number of moles by Avogadro's number:
Number of molecules =[tex]\frac{1.16 * 10^{-8 }mol * 6.022 * 10^{23 }molecules}{mol}[/tex]
Number of molecules = [tex]6.9 * 10^{15} molecules[/tex]
Therefore, there are [tex]6.9 * 10^{15} molecules[/tex] of batrachotoxin in 0.05 μg.
learn more about molecules Refer:brainly.com/question/19556990
#SPJ1
complete question:Batrachotoxin, C31H42N2O6 an active component of South American arrow poison, is so toxic that 0.05μg can kill a person.
How many molecules is this? Express your answer as an integer
Give the IUPAC name of the amine shown.
The figure shows a compound with the following structure: CH3CH2NCH2CH2CH3, with a CH2CH2CH3 group attached to the nitrogen atom.
The IUPAC name of the amine shown is N-ethylbutan-1-amine.
What is the IUPAC name of an organic compound?
The IUPAC name of an organic compound is a systematic way of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).
It is a standard method to ensure that every organic compound has a unique name, which reflects its structure and the functional groups present in the molecule.
The IUPAC name usually consists of several parts, including the parent chain, substituent groups, and functional groups, arranged in a specific order according to a set of rules.
Learn more about IUPAC name at: https://brainly.com/question/27199266
#SPJ1
Can someone understand this because I don’t
We need 8.8 moles of O2
We need 1.266 moles of K
We will produce 0.96 moles of water
What is a balanced reaction equation?We know that;
2H2O + O2 → 2H2O2
If 1 mole of O2 makes 2 moles of H2O2
x moles of O2 makes 17.6 moles of H2O2
x = 8.8 moles
Again;
2K + HgCl2 → 2KCl + Hg
If 2 moles of K reacts with 1 mole of HgCl2
x moles of K reacts with 0.633 moles of HgCl2
x = 1.266 moles
Again;
C3H8 + 5O2 → 3CO2 + 4H2O
5 moles of O2 produces 4 moles of H2O
1.2 moles of O2 would produce x moles of water
x = 0.96 moles
Again;
2NH3 ---->N2 + 3H2
If 1 moles of N2 is formed when 3 moles of H2 are formed
3 moles of N2 will lead to the formation of 3 * 3/1
= 9 moles of H2
Learn more about moles:https://brainly.com/question/26416088
#SPJ1
How many moles are in 0.1 g of Magnesium?
Answer:
there are approximately 0.004118 moles in 0.1 g of magnesium.
Explanation:
The molar mass of magnesium is approximately 24.31 g/mol. To calculate the number of moles in 0.1 g of magnesium, we can use the following formula:
Number of moles = Mass / Molar mass
Number of moles = 0.1 g / 24.31 g/mol
Number of moles = 0.004118 mol (rounded to 3 significant figures)
Therefore, there are approximately 0.004118 moles in 0.1 g of magnesium.
Answer:
Explanation:
To calculate the number of moles of magnesium in 0.1 g of magnesium, we first need to determine the molar mass of magnesium. The molar mass of magnesium is 24.31 g/mol.
Using this information, we can use the following formula to calculate the number of moles of magnesium:
moles of magnesium = mass of magnesium / molar mass of magnesium
moles of magnesium = 0.1 g / 24.31 g/mol
moles of magnesium ≈ 0.00412 mol
Therefore, there are approximately 0.00412 moles of magnesium in 0.1 g of magnesium.
These two samples of NaCl and CoCl2 have the same number of moles. Do they have the same mass? Do they have the same number of particles? Explain.
No, two samples of NaCl and CoCl2 do not have the same mass, but they have the same number of particles.
What is meant by moles?Mole is the amount of material containing 6.02214 × 10²³ particles.
Molar mass of NaCl (sodium chloride) is 58.44 g/mol, while molar mass of CoCl2 (cobalt chloride) is 129.84 g/mol. Since both samples have same number of moles, it means that they contain same number of particles of their respective compounds. However, mass of each sample will be different due to the difference in molar mass.
For example, if we assume that both samples contain 1 mole of their respective compounds, then mass of NaCl sample will be 58.44 g, while mass of CoCl2 sample will be 129.84 g. So, two samples have different masses but the same number of particles.
To know more about moles, refer
https://brainly.com/question/29367909
#SPJ1
What quantity in moles of NaI are there in 175.0 mL of 0.210 M NaI?
There are 0.03675 moles of NaI in 175.0 mL of 0.210 M NaI solution.
How to calculate the number of moles ?To calculate the number of moles of NaI in 175.0 mL of 0.210 M NaI solution, we can use the formula:
moles of solute = concentration (in M) x volume (in liters)
First, we need to convert the volume from milliliters to liters:
175.0 mL = 175.0/1000 L = 0.175 L
Now we can plug in the values:
moles of NaI = 0.210 M x 0.175 L = 0.03675 moles of NaI
Therefore, there are 0.03675 moles of NaI in 175.0 mL of 0.210 M NaI solution.
Learn more about moles of solute here : brainly.com/question/2306123
#SPJ1
Question 3 of 16
Determine the number of atoms of O in 46.6 moles of Al2(CO3)3.
There are approximately 2.526 × 10^26 atoms of O in 46.6 moles of Al2(CO3)3.
Steps
To find the number of atoms of O in 46.6 moles of Al2(CO3)3, we need to first calculate the total number of moles of O in the compound and then multiply it by Avogadro's number.
The molecular formula of Al2(CO3)3 shows that there are three O atoms per one CO3 group, and there are three CO3 groups per one Al2(CO3)3 molecule. Therefore, the total number of O atoms in one Al2(CO3)3 molecule is:
3 O atoms/CO3 group × 3 CO3 groups/Al2(CO3)3 molecule = 9 O atoms/Al2(CO3)3 molecule
Next, we need to calculate the total number of moles of O atoms in 46.6 moles of Al2(CO3)3:
46.6 moles Al2(CO3)3 × 9 O atoms/Al2(CO3)3 molecule = 419.4 moles O atoms
Finally, we can calculate the total number of O atoms by multiplying the number of moles of O by Avogadro's number:
419.4 moles O atoms × 6.022 × 10^23 atoms/mole = 2.526 × 10^26 O atoms
Therefore, there are approximately 2.526 × 10^26 atoms of O in 46.6 moles of Al2(CO3)3.
learn more about atoms here
https://brainly.com/question/17545314
#SPJ1
TiCl4 + 2 H2O → TiO2 + 4 HCl How many mols of TiO2 is produced with 100 g of TiCl4
0.29 mol
0.50 mol
0.98 mol
0.74 mol
0.50 mοI οf titanium diοxide is prοduced with 100 g οf titanium tetrachIοride. Thus the cοrrect answer is οptiοn (c).
Hοw dο yοu caIcuIate the number οf mοIes οf TiO2 prοduced?The baIanced chemicaI equatiοn fοr the reactiοn is:
TiCI₄ + 2 H₂O → TiO₂ + 4 HCI
Frοm the equatiοn, we can see that 1 mοIe οf TiCI₄ prοduces 1 mοIe οf TiO₂.
Tο caIcuIate the number οf mοIes οf TiO₂ prοduced frοm 100 g οf TiCI₄, we need tο first determine the number οf mοIes οf TiCI₄ present in 100 g.
The mοIar mass οf TiCI₄ is 189.68 g/mοI (47.867 + 4 x 35.453). Using this mοIar mass, we can caIcuIate the number οf mοIes οf TiCI₄ in 100 g as:
mοIes οf TiCI₄= mass οf TiCI₄/ mοIar mass οf TiCI₄
mοIes οf TiCI₄= 100 g / 189.68 g/mοI
mοIes οf TiCI₄= 0.5276 mοI
Since 1 mοIe οf TiCI₄ prοduces 1 mοIe οf TiO₂, the number οf mοIes οf TiO₂ prοduced is aIsο 0.5276 mοI.
Therefοre, the cοrrect answer is οptiοn (c) 0.50 mοI.
Learn more about titanium dioxide here:
brainly.com/question/12162067
#SPJ1
Aniline, a starting compound for urethane plastic foams, consists of C, H, and N.
Combustion of such compounds yields CO2 (carbon dioxide), H2O (water), and N2 as
products. If the combustion of 9.71 mg of Aniline yields 6.63 mg of H2O and 1.46 mg of
N2, what is its empirical formula? The molecular weight of Aniline is 93 amu. What is its
molecular formula?
The empirical formula of Aniline is C9H10N and its molecular formula is C9H9.9N.
Steps
To determine the empirical formula of Aniline, we need to calculate the number of moles of each element present in the given mass of the compound and then find the smallest whole-number ratio between them.
Given:
Mass of Aniline = 9.71 mg
Mass of water produced = 6.63 mg
Mass of N2 produced = 1.46 mg
The molecular weight of Aniline = 93 amu
First, let's calculate the number of moles of water and nitrogen produced:
moles of H2O = 6.63 mg / 18.015 g/mol = 0.3680 mmol
moles of N2 = 1.46 mg / 28.014 g/mol = 0.0521 mmol
Next, we need to calculate the number of moles of carbon and nitrogen present in Aniline:
moles of C = (9.71 mg - (0.3680 mmol x 12.011 g/mol)) / 12.011 g/mol = 0.4811 mmol
moles of N = 0.0521 mmol
Now, we need to find the smallest whole-number ratio between these elements. We can divide the number of moles of each element by the smallest value, which is 0.0521 mmol:
moles of C = 0.4811 mmol / 0.0521 mmol = 9.231 ≈ 9
moles of N = 1
moles of H = not calculated, but we can find it using the difference in mass between Aniline and the products formed.
Now, let's calculate the mass of carbon and nitrogen in Aniline:
mass of C = 9 x 12.011 g/mol = 108.099 g/mol
mass of N = 1 x 14.007 g/mol = 14.007 g/mol
Finally, we can calculate the mass of hydrogen by taking the difference between the mass of Aniline and the sum of the masses of carbon, nitrogen, water, and nitrogen:
mass of H = 9.71 mg - (108.099 g/mol + 14.007 g/mol + 6.63 mg + 1.46 mg) = 2.47 mg
Now, we can calculate the number of moles of hydrogen:
moles of H = 2.47 mg / 1.008 g/mol = 2.449 mmol
Finally, we can express the empirical formula of Aniline as: C9H10N
To find the molecular formula, we need to calculate the molecular weight of the empirical formula:
Empirical formula weight = (9 x 12.011 g/mol) + (10 x 1.008 g/mol) + (1 x 14.007 g/mol) = 93.126 g/mol
Now, we can find the molecular formula by dividing the molecular weight of Aniline by the empirical formula weight and multiplying each subscript in the empirical formula by the result:
The molecular weight of Aniline = 93 amu
The molecular weight of the empirical formula = 93.126 g/mol
Molecular formula = empirical formula x (Molecular weight of Aniline / Empirical formula weight)
= C9H10N x (93 amu / 93.126 g/mol)
= C9H9.9N
Therefore, the empirical formula of Aniline is C9H10N and its molecular formula is C9H9.9N.
learn more about Combustion here
https://brainly.com/question/13251946
#SPJ1
9. Which of the following best describes the valence electrons of a crystal that is an
excellent conductor?
Answer choices :
(A)They’re easy to dislodge a difficult to move through the crystal .
(B)They’re easy to dislodge an easy to move through the crystal .
(C)They are difficult to dislodge, but easy to move through the crystal .
(D) They are difficult to dislodge and difficult to move through the crystal .
Answer:
A
Explanation:
They're easy to dislodge a difficult to move through it the crystal
I’ll mark you as brainlist
Identify the precipitation
Precipitation reactions and non- precipitation reactions
When two aqueous solutions are combined, a precipitation process takes place in which an insoluble substance (precipitate) develops. Reactions 1, 2, 3, and 5 in the list are precipitation reactions.
What are some examples of precipitation reactions?When an impermeable material called a precipitate separates from the solution, a reaction known as a precipitation reaction takes place. As an example, a white precipitate of barium sulphate and sodium chloride solution is created when sodium sulphate solution and barium chloride solution are mixed.
Describe precipitates and provide an example.An insoluble material is called a precipitate. For instance, barium sulphate and sodium chloride solution is created when sodium sulphate solution and barium chloride solution are combined.
To know more about precipitation reactions visit:-
https://brainly.com/question/29762381
#SPJ1
how many significant figure are in 0.03412
The measurement of 0.03412 kg has 5 significant figures. Significant figures are used to provide an indication of the precision of a measurement and should be used when performing calculations.
What is measurements?Measurements are the numerical values used to quantify the size, amount, or extent of something. Measurements are used to describe physical attributes and characteristics, such as length, width, weight, height, area, volume, speed, temperature, pressure, force, energy, power, and time. Measurements are also used to determine the amount of a certain material that is needed for a given purpose, such as a recipe. Measurements are essential for scientific investigation, engineering, and other activities that require precision and accuracy.
The measurement of 0.03412 kg has 5 significant figures. Significant figures are the meaningful digits of a number that are important in providing information about the measurement. In this measurement, the 4 digits after the decimal point (3412) provide the precision of the measurement, and therefore are significant figures. The leading zero does not provide any additional precision and is not a significant figure. Therefore, the measurement of 0.03412 kg has 5 significant figures.
Significant figures are used to provide an indication of the precision of a measurement. For example, a measurement of 0.03412 kg has a precision of 0.00001 kg, which is greater than a measurement of 0.3412 kg, which has a precision of 0.0001 kg. The more significant figures a measurement has, the more precise it is.
Significant figures are also important in calculations. To ensure accuracy, all calculations should be done using the same number of significant figures as the measurements being used. For example, if two measurements, 0.03412 kg and 0.02384 kg, are used in a calculation, the result should be reported to 5 significant figures.
In conclusion, the measurement of 0.03412 kg has 5 significant figures. Significant figures are used to provide an indication of the precision of a measurement and should be used when performing calculations.
To know more about measurements click-
https://brainly.com/question/28835783
#SPJ1
The measurement of 0.03412 kg has 5 significant figures. Significant figures are used to provide an indication of the precision of a measurement and should be used when performing calculations.
What is measurements?Measurements are the numerical values used to quantify the size, amount, or extent of something. Measurements are used to describe physical attributes and characteristics, such as length, width, weight, height, area, volume, speed, temperature, pressure, force, energy, power, and time. Measurements are also used to determine the amount of a certain material that is needed for a given purpose, such as a recipe. Measurements are essential for scientific investigation, engineering, and other activities that require precision and accuracy.
The measurement of 0.03412 kg has 5 significant figures. Significant figures are the meaningful digits of a number that are important in providing information about the measurement. In this measurement, the 4 digits after the decimal point (3412) provide the precision of the measurement, and therefore are significant figures. The leading zero does not provide any additional precision and is not a significant figure. Therefore, the measurement of 0.03412 kg has 5 significant figures.
Significant figures are also important in calculations. To ensure accuracy, all calculations should be done using the same number of significant figures as the measurements being used. For example, if two measurements, 0.03412 kg and 0.02384 kg, are used in a calculation, the result should be reported to 5 significant figures.
In conclusion, the measurement of 0.03412 kg has 5 significant figures. Significant figures are used to provide an indication of the precision of a measurement and should be used when performing calculations.
To know more about measurements click-
https://brainly.com/question/28835783
#SPJ1
The complete question is as follows:
How many significant figure are in 0.03412 kg?
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:
2Al(s)+3Cl2(g)→2AlCl3(s)
You are given 12.0g of aluminum and 17.0g of chlorine gas. If you had excess aluminum, how many moles of aluminum chloride could be produced from 17.0g of chlorine gas, Cl2?
Express your answer to three significant figures and include the appropriate units.
Therefore, 0.160 moles of aluminum chloride could be produced from 17.0g of chlorine gas, Chlorine.
According to the equation below, aluminum produces aluminum chloride when it interacts with chlorine gas?Aluminum chloride is created when aluminum and chlorine gas combine, as shown by the equation below. 3Chlorine + 2aluminum = 2Aluminum chloride if the reaction between 20 aluminum ions and 45 chlorine gas molecules.
First, let's determine how many molecules of each reactant we have:
moles of aluminum = 12.0 g / 26.98 g/mol = 0.445 mol
moles of Chlorine = 17.0 g / 70.90 g/mol = 0.240 mol
To determine the limiting reagent, we need to compare the actual mole ratio of aluminum to Chlorine with the stoichiometric ratio. The actual ratio is:
0.445 mol aluminum / 0.240 mol Chlorine = 1.854
From the balanced equation, 3 moles of Chlorine react with 2 moles of Aluminum chloride to form 2 moles of Aluminum chloride. Therefore, the number of moles of Aluminum chloride that can be produced is:
0.240 mol Chlorine × (2 mol Aluminum chloride / 3 mol Chlorine) = 0.160 mol Aluminum chloride
To know more about aluminum chloride visit:-
https://brainly.com/question/29446640
#SPJ1
Can someone help me with this?
Arrhenius base - Releases OH ions when dissolved in water
Arrhenius acid - Releases H+ ions when dissolved in water
Bronsted-Lowry base - Accepts a proton
Bronsted-Lowry acid - donates a proton
How are Arrhenius bases recognized?An Arrhenius base is a molecule that decomposes into an OH- or hydroxide in solution when dissolved in water. Look for a molecule ending in OH that does not follow CHx, which denotes an alcohol, to identify the Arrhenius base. Examples of Arrhenius bases include sodium hydroxide, or NaOH.
Arrhenius acid: What is it?A substance that raises the concentration of H+ ions in an aqueous solution is known as an Arrhenius acid. Traditional Arrhenius acids are highly polarized covalent substances that dissociate in water to form an anion (A-) and the cation H+. Often, the H+ is referred to as a proton.
What distinguishes a Bronsted-Lowry base?Count the hydrogens on each component before and after the reaction to determine if it is an acid or a basic. If there are fewer hydrogens, then the substance is acid (donates hydrogen ions). The material is the base if the hydrogen count has increased (accepts hydrogen ions).
To know more about the Bronsted-Lowry base visit;
https://brainly.com/question/12377772
#SPJ1
You have a 10.40 g mixture of table sugar (C12H22O11) and table salt (NaCl). When this mixture is dissolved in 150 g of water, the freezing point is found to be –2.24°C. Given Kf of water is 1.86 °C·kg/mol, and assume complete dissociation of the salt, calculate the percentage by mass of sugar in the original mixture.
The mass proportion of sugar in the initial combination, assuming complete dissociation of the salt, is 55.0%.
How do you figure out how much sugar there was in the original combination, measured in mass?There are 58.44 g/mol of NaCl in the mixture, which equals the following:
Moles of NaCl are equal to the mass of NaCl divided by the molar mass of NaCl. For example, 10.40 g - x g = 58.44 g/mol
NaCl dissolves into two particles, hence there are actually two particles in the solution.
effective particles equal 2 moles of sodium chloride plus 1 mole of sugar.
2.24 °C = 1.86 °C mol/kg x (27.63 - 0.605 x) mol/kg
x = 5.72 g
(Mass of sugar / Total Mass of Mixture) x 100%, where % Sugar
% sugar = 55.0%
To learn more about mass by percentage visit:
brainly.com/question/16885872
#SPJ1
Find the mass in grams of 2.00 x 10^23 molecules of F2.
The weight, in grammes, of 2.00 x 1023 F2 molecules. As a result, 12. 62 g equals 21023 moles of F2.
How can I calculate mass in grammes?The precise formula for determining a substance's Gram Molecular Mass is: Formula in grammes Mass is equal to the product of the solute's mass and its formula. It is consistently expressed in terms of grammes per mole (g/mol).
How many kilos does a molecule weigh?Number-wise, the mass with one mole (or formula unit) of atomic mass units is equal to the mass with one mole (or formulas unit) in grammes. One mole of O2 molecules, for instance, weighs 32.00 g and a single O2 molecule, 32.00 u.
To know more about moles visit:
https://brainly.com/question/26416088
#SPJ1
Give me the cation and anion of
zinc sulphate
The cation of zinc sulfate is Zn²⁺, which is a positively charged ion of zinc.
The anion of zinc sulfate is SO₄²⁻, which is a negatively charged ion of sulfate.
What is Cation and anion?A cation is a positively charged ion that is formed when an atom loses one or more electrons. The loss of electrons causes the atom to have a net positive charge, and it is then referred to as a cation. Cations are formed from metals, which tend to lose electrons to form positively charged ions.
An anion, on the other hand, is a negatively charged ion that is formed when an atom gains one or more electrons. The gain of electrons causes the atom to have a net negative charge, and it is then referred to as an anion. Anions are formed from non-metals, which tend to gain electrons to form negatively charged ions.
Learn more about zinc sulfate:https://brainly.com/question/29355805
#SPJ1
Consider the balanced reversible reaction of acetic acid with ethanol, which takes place with no solvent water.
acetic acid
+
ethanol
⇌
ethyl acetate
+
water
When you react
8.29
M
acetic acid with
8.29
M
ethanol, the equilibrium concentration of acetic acid is
3.28
M
.
What is the equilibrium concentration (M) of ethyl acetate?
The equilibrium concentration of ethyl acetate is 4.02 M.
Steps
The balanced chemical equation for the reaction is:
acetic acid + ethanol ⇌ ethyl acetate + water
We are given that the initial concentration of acetic acid and ethanol is 8.29 M and that the equilibrium concentration of acetic acid is 3.28 M. Let's call the equilibrium concentration of ethyl acetate x.
Using the equilibrium constant expression for this reaction:
Kc = [ethyl acetate][water] / [acetic acid][ethanol]
We know that this reaction is balanced, meaning that the stoichiometric coefficients for the reactants and products are equal. Therefore, we can write:
Kc = [ethyl acetate][water] / [acetic acid][ethanol]
Kc = x(8.29 - 3.28) / (3.28)(8.29 - x)
Kc = 1.47
Now we can use the equilibrium constant expression to solve for x:
1.47 = x(8.29 - 3.28) / (3.28)(8.29 - x)
1.47(3.28)(8.29 - x) = x(8.29 - 3.28)
12.0437 - 1.47x = 8.29x - 27.1924
9.76x = 39.2361
x = 4.02 M
Therefore, the equilibrium concentration of ethyl acetate is 4.02 M.
learn more about reversible reaction here
https://brainly.com/question/21426719
#SPJ1