how much force does she hit the ball with ?

Answer:

(1)     you kick the stone

(2)    air molecules are set in motion

(3)    the first molecules set other molecules in motion

(4)     these moving molecules set other molecules in motion

Answer:

A

Explanation:

The bacteria exists as organic matter

Answer:

a) is probably the answer

Answer:

People are familiar with F = M a in rectilinear motion

Γ = I α is the corresponding relation in rotational motion.

Also, Γ = R X F gives the direction of the torque

When the wheel is turned over the direction of R is reversed since if it was pointing to the right the lever arm on which the force was acting is now pointing to the left. The gravitational force is still pointing downward  so the direction of Γ has been reversed and the gravitational force is still in the downwards direction  and there is a reversal in the torque acting on the wheel.

One can also think of the wheel having bendable spokes. A force that would turn the wheel and bend the spokes in one direction would have the opposite effect when the wheel was turned over. (A force forcing the spokes backwards would still force the spokes backwards when the wheel is turned over but now the wheel is rotating in the opposite direction)

Solar energy is an increasingly popular form of energy that is quickly becoming more efficient and cost effective than other sources of energy.

Energy is the capacity of a physical system to do work. It is a property of objects which can be transferred to other objects or converted into different forms, but cannot be created or destroyed. Energy can take the form of kinetic, potential, thermal, electrical, chemical, nuclear, or other various forms.

Solar energy is an abundant, renewable source of energy that can be used to power homes, businesses, and other applications without harming the environment. Solar energy is produced when energy from the sun is captured and converted into electricity. This electricity can be used to power everyday appliances and other activities.

Solar energy has many advantages over other forms of energy. For starters, it is a clean form of energy that does not create any air or water pollution. Additionally, solar energy does not require any finite resources, such as coal or oil, to produce. This means that solar energy is an inexhaustible source of energy and is able to provide an unlimited amount of power. Solar energy is also very cost effective compared to other sources of energy. Solar installations require a significant upfront cost, but the savings in energy costs can be significant.

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a) The multimeter in figure 2(a) is set up to measure DC voltage. The setting is indicated by the V with a straight line above it, which stands for "DC voltage".

b) The multimeter in figure 2(a) reads 25.6 V (volts).

c) The multimeter in figure 2(b) is set up to measure DC current. The setting is indicated by the A with a straight line above it, which stands for "DC current".

d) The multimeter in figure 2(b) reads 0.40 A (amperes).

What is multimeter?

A multimeter is an electronic instrument that is used to measure electrical parameters such as voltage, current, and resistance. Multimeters can measure AC and DC voltage, AC and DC current, resistance, continuity, capacitance, and frequency.

What is DC volage?

DC voltage refers to the level or strength of a direct current (DC) electrical signal. Direct current is a type of electrical current that flows in one direction only and does not alternate in polarity. DC voltage can be measured using a multimeter or other voltage measurement instrument, and is typically expressed in volts (V). DC voltage is commonly used in many electronic devices and systems, such as batteries, power supplies, and DC motors.

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Answer:

i hope this is what you are looking for

As an electron moves towards the positive plate in a uniform electric field between two parallel plates, the distance between the electron and the positive plate decreases, force causing the electric field between them to increase. Hence, the correct option is (2).

In the given diagram, there is a uniform electric field between two parallel plates, with the positive plate on the left and the negative plate on the right. When an electron is placed between the plates and moves towards the positive plate, it experiences a force due to the electric field. The direction of this force is opposite to the direction of the electric field and is given by F = qE, where F is the force, q is the charge of the electron, and E is the electric field. As the electron moves towards the positive plate, the distance between the electron and the positive plate decreases, which means that the electric field between them increases. Therefore, the force acting on the electron also increases according to F = qE. Hence, the correct option is (2) increases.

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The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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The object will land a distance of ωR√(2h/g) east of the point vertically below where it was dropped.

The rotation of the Earth causes the object to have an eastward velocity component, which causes it to land to the east of the point vertically below where it was dropped.

To determine how far to the east the object will land, we need to consider the following:

Let's assume that the building is located exactly on the equator, so its distance from the Earth's axis is equal to the radius of the Earth, R. The angular speed of the Earth's rotation is given by the symbol omega, which is approximately equal to 7.27 x 10⁻⁵ radians per second.

First, let's find the eastward velocity component of the object due to the Earth's rotation. This can be calculated using the formula:

v = ω * R * cos(latitude)

where;

Since cos(0) = 1, the formula simplifies to:

v = ωR

Next, let's find the time it takes for the object to fall from the top of the building to the ground. This can be calculated using the formula:

t = √(2h/g)

where;

Finally, let's find the distance the object moves eastward during that time due to its eastward velocity component.

This can be calculated using the formula:

d = vt

Substituting the formulas for v and t, we get:

d = ωR√(2h/g)

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The skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².

The pace at which a speed changes over time is called acceleration. In other words, it is a measurement of how quickly an object's velocity alters. It is a vector quantity with a direction and magnitude.

Finding the net force affecting the skydiver can be our first step. The vector sum of all forces acting on the skydiver is known as the net force. Weight and drag force are the two forces at play here as they affect the skydiver.

The skydiver's weight is determined by:

Weight= mass x acceleration due to gravity

Weight: 82.0 kg x 9.81 m/s² (acceleration due to gravity)

Weight= 804.42 N

The skydiver is under the following net force:

net force = weight - drag force

850 N - 804.42 N = Net force

45.58 N of net force (upwards)

The skydiver will accelerate upwards since the net force is upward. The magnitude of the acceleration can be determined by applying Newton's second law of motion:

Net force is calculated as follows:

Net force = mass x acceleration

45.58 N = 82.0 kg x acceleration

Acceleration = 0.556 m/s².

As a result, the skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².

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The equivalent resistance of the circuit is 5.65 k

Equivalent resistance of an electric circuit is the equivalent sum of all the resistances in the circuit whether in series or in parallel.

Now, in the circuilt above, we can see that we have two resistances 1.1 k and 4.55 k. We also note that the resistances are in series.

For resistors in series, to find their equivalent resistance, we add them together.

So, the equivalent reistance R = R' + R" where R' = 1.1k and R" = 4.55 k

So, substituting the values of the variables into the equation, we have that

R = R' + R"

= 1.1 k + 4.55 k

= 5.65 k

So, the equivalent resistance is 5.65 k

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The disk must have traveled a distance of 4.52 meters before coming to a stop.

We can use the equation for the distance traveled by an object under constant acceleration:

d = (v_f^2 - v_i^2) / (2 * a)

The acceleration of the disk is determined by the force of friction, which is given by:

F_friction = friction_coefficient * F_normal

We can find the weight of the disk by using the formula:

F_gravity = m * g

Let's assume the mass of the disk is 0.5 kg. Then:

F_gravity = 0.5 kg * 9.8 m/s^2 = 4.9 N

So the normal force on the disk is also 4.9 N.

Now we can find the force of friction:

F_friction = 0.34 * 4.9 N = 1.67 N

The acceleration of the disk is given by:

a = F_friction / m = 1.67 N / 0.5 kg = 3.34 m/s^2

Plugging this into the equation for distance, we get:

d = (0 - (5.6 m/s)^2) / (2 * (-3.34 m/s^2)) = 4.52 m

Therefore, the disk travels 4.52 meters before coming to a stop, which is less than the length of the court (14.3 m).

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A.The linear acceleration of block A is [tex]a = -3.42 m/s^2[/tex]

B.The linear acceleration of block B is [tex]a = 3.42 m/s^2[/tex]

C.The angular acceleration of the wheel c  is [tex]a= -31.09 rad/s^2[/tex]

D. The tension in the left side is T = -210.83 N

E.The tension in the right side is T = -58.75 N

A. The linear acceleration of block A can be calculated using the equation for the acceleration of an Atwood's machine:

[tex]a =\frac{ (m2 - m1)g}{ (m1 + m2)}[/tex]

Substituting the given values, the linear acceleration of block A is:

[tex]a =\frac{ (2.00 kg - 5.50 kg) 9.81 m/s^2 }{ (5.50 kg + 2.00 kg)}\\a = -3.42 m/s^2[/tex]

B. The linear acceleration of block B can be calculated using the same equation:

[tex]a =\frac{ (m2 - m1)g}{ (m1 + m2)}[/tex]

Substituting the given values, the linear acceleration of block B is:

[tex]a = \frac{(2.00 kg - 5.50 kg) 9.81 m/s^2 }{ (5.50 kg + 2.00 kg)}\\a = 3.42 m/s^2[/tex]

C. The angular acceleration of the wheel can be calculated using the equation:

[tex]a = \frac{a}{r}[/tex]

where α is the angular acceleration, a is the linear acceleration and r is the radius of the wheel.

Substituting the given values and the value for the linear acceleration of block A, the angular acceleration of the wheel is:

[tex]a = \frac{-3.42 m/s2 }{ 0.110 m}[/tex]

[tex]a= -31.09 rad/s^2[/tex]

D. The tension in the left side of the cord can be calculated using the equation:

T = m1a + m1rα

Substituting the given values, the tension in the left side of the cord is:

T = 5.50 kg (-3.42 m/s2) + 5.50 kg (0.110 m) (-31.09 rad/s2)

T = -210.83 N

E. The tension in the right side of the cord can be calculated using the equation:

T = m2a + m2rα

Substituting the given values, the tension in the right side of the cord is:

T = 2.00 kg (3.42 m/s2) + 2.00 kg (0.110 m) (-31.09 rad/s2)

T = -58.75 N

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a) The number of excess electrons on the sphere is 1.97 x 10^10 electrons.

b) There are 0.0000857 excess electrons per lead atom.

a) The elementary charge of a single electron is -1.6 x 10^-19 C. To find the number of excess electrons on the sphere, we can divide the total charge by the charge of a single electron:

-3.15 x 10^-9 C / (-1.6 x 10^-19 C/electron) = 1.97 x 10^10 electrons

b) To find the number of excess electrons per lead atom, we need to first find the number of lead atoms in the sphere. We can use the molar mass of lead and the mass of the sphere to find the number of moles of lead:

7.90 g / 207 g/mol = 0.0382 mol

Next, we can use Avogadro's number to find the number of lead atoms:

0.0382 mol x (6.02 x 10^23 atoms/mol) = 2.30 x 10^22 atoms

Finally, we can divide the number of excess electrons by the number of lead atoms:

1.97 x 10^10 electrons / 2.30 x 10^22 atoms ≈ 0.0000857 excess electrons per lead atom.

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The space station would complete one revolution in about 2.2 minutes.

It's exciting to consider the use of artificial gravity inside a spacecraft. Many believe it would be a smart way to maintain humans' health on lengthy missions, preventing bone and muscle loss over the roughly 18 months it would take to fly to and from Mars in weightlessness.

The period of rotation T can be calculated using the formula T = 2π/ω, where ω is the angular velocity. Since the artificial gravity is equal to 1g, we can use the formula g = ω²r, where r is the radius of the cylinder. When we solve for, we obtain = sqrt(g/r).

Substituting the given values, we get ω = sqrt(9.81 m/s² / (2135/2 m)) = 0.0477 rad/s.

Using the formula for T, we get T = 2π/ω = 131.9 seconds, or approximately 2.2 minutes.

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The two experimental procedures for determining rate laws are the method of initial rates and the graphical method.

The two experimental procedures for determining rate laws are the method of initial rates and the graphical method.

Method of Initial Rates: This method involves measuring the initial rates of reaction under different initial concentrations of reactants while keeping all other conditions constant. The rate law can be determined by comparing the initial rates with the initial concentrations of the reactants.

Graphical Method: In this method, the concentration of the reactants is plotted against time. The rate law can be determined by analyzing the slope of the resulting curves.

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The height of the real tree is 1.92 × 10^-3 cm.

We can use the magnification formula to solve this problem. The magnification formula relates the size of the object to the size of its image and is given by: magnification = size of image/size of the object

In this case, the magnification is given as 1.2 × 10^3, the size of the image is 2.3 cm, and we want to find the size of the object, which is the height of the tree. So we can rearrange the formula to solve for the size of the object: the size of the object = size of the image/magnification

Substituting the given values, we get:

size of object = 2.3 cm / 1.2 × 10^3 = 1.92 × 10^-3 cm

So the height of the real tree is 1.92 × 10^-3 cm.

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To determine the stone's kinetic energy when it touches the ground, we can use the law of conservation of energy. The stone is initially at rest 80 metres above the ground, and its potential energy is provided by: PEi = mg

(ii) For free fall, the body's overall energy supply remains constant at any given moment. It is the same as adding P.E. and K.E.

The energy held by the 10 kg item at 6 inches in height. m above ground is 588 J.

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Answer:

The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is 62271.86 N

Explanation:

To find the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck, we need to consider the static equilibrium condition of the truck.

The weight of the truck and its contents acts downwards through its center of gravity (cg) and the normal force exerted by the ground acts upwards. The normal force is distributed between the front and rear axles of the truck according to the position of the cg.

Let F_R be the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck.

Then, from the static equilibrium condition:

Sum of vertical forces = 0

F_R + (8010 kg)(9.81 m/s^2) - F_F = 0

where F_F is the magnitude of the total vertical force exerted by the ground on the front wheels of the truck.

The distance between the cg and the rear axle is given as 0.63(2.3 m) = 1.449 m.

The distance between the cg and the front axle is therefore (2.3 m - 1.449 m) = 0.851 m.

We can assume that the weight is evenly distributed between the four wheels of the truck. Therefore, the weight supported by each wheel is:

(8010 kg)(9.81 m/s^2)/4 = 19653.45 N

Using moments about the rear axle, we get:

F_F(0.851 m) - F_R(1.449 m) = 0

Solving these two equations simultaneously, we get:

F_R = 62271.86 N

Therefore, the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is 62271.86 N.

The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is approximately 62,203 N.

Static equilibrium refers to the state of an object at rest when the net force acting on it is zero. In other words, when an object is in static equilibrium, it is not accelerating in any direction and all forces acting on it are balanced.

The principle of static equilibrium states that the sum of all forces acting on an object in static equilibrium is zero, and the sum of all torques (rotational forces) acting on the object is also zero. This principle can be applied to solve problems involving the forces and torques acting on objects at rest.

Static equilibrium is important in many areas of physics and engineering, including structural analysis, civil engineering, and mechanical engineering. Understanding static equilibrium is essential for designing structures and machines that can support loads without collapsing or breaking, and for analyzing the stability of systems in various applications.

Here in the Question,

To find the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck, we need to analyze the forces acting on the truck and apply the principle of static equilibrium, which states that the sum of all forces acting on an object in static equilibrium is zero.

The forces acting on the truck are the weight of the truck and its contents and the reaction forces from the ground acting on each of the four wheels. The weight of the truck and its contents can be represented as a single force acting vertically downwards at the center of gravity (cg) of the truck.

Since the truck is at rest on a horizontal road, the reaction forces from the ground acting on the wheels must balance the weight of the truck and its contents in both the horizontal and vertical directions. The horizontal components of the reaction forces cancel each other out, since the truck is at rest and not moving in the horizontal direction.

To find the vertical forces, we can first find the weight of the truck and its contents:

w = m*g

where w is weight, m is mass, and g is the acceleration due to gravity (9.81 m/s^2).

Substituting the given values, we get:

w = 8010 kg * 9.81 m/s^2 = 78,419.1 N

Next, we can find the position of the center of gravity (cg) relative to the front and rear axles of the truck:

d = L * (m1 - m2) / m

where d is the distance from the cg to the rear axle, L is the distance between the front and rear axles (2.3 m), m1 is the mass of the truck and contents behind the cg, m2 is the mass of the truck and contents in front of the cg, and m is the total mass of the truck and contents.

Substituting the given values, we get:

d = 2.3 m * (8010 kg * 0.63 - 8010 kg * 0.37) / 8010 kg = 0.743 m

Now, we can find the magnitudes of the vertical forces acting on the rear and front wheels of the truck using the principle of static equilibrium. Since the truck is not moving vertically, the sum of the vertical forces acting on it must be zero. Therefore:

Frear + Ffront = w

where Frear is the vertical force exerted by the ground on the rear wheels, Ffront is the vertical force exerted by the ground on the front wheels, and w is the weight of the truck and its contents.

The rear wheels support the weight of the truck and its contents, as well as a portion of the weight shifted forward of the rear axle due to the position of the cg. The front wheels support only a portion of the weight shifted backward of the front axle. To find the magnitudes of the vertical forces, we can use the following equations:

Frear = (m1/m)*w

Ffront = (m2/m)*w

where m1 is the mass of the truck and contents behind the cg, m2 is the mass of the truck and contents in front of the cg, and m is the total mass of the truck and contents.

Substituting the given values and using the value of d found earlier, we get:

Frear = (8010 kg * 0.63 / 8010 kg)*78,419.1 N = 62,202.7 N

Ffront = (8010 kg * 0.37 / 8010 kg)*78,419.1 N = 36,216.4 N

The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is:

Frear = 62,202.7 N ≈ 62,203 N

Therefore, the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is approximately 62,203 N.

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Answer:

Explanation:

The force of gravity acting on the block can be resolved into two components, one parallel to the incline and one perpendicular to the incline. The perpendicular component is balanced by the normal force of the incline, and the parallel component is opposed by the force of friction. The force of friction is given by:

F_friction = coefficient_of_friction * F_norm

where F_norm is the normal force of the incline. The normal force is equal in magnitude and opposite in direction to the perpendicular component of the force of gravity, which is:

F_perpendicular = m * g * cos(theta)

where m is the mass of the block, g is the acceleration due to gravity, and theta is the angle of inclination.

The parallel component of the force of gravity is:

F_parallel = m * g * sin(theta)

The net force acting on the block is:

F_net = F_parallel - F_friction

Using Newton's second law, F = m * a, we can solve for the acceleration of the block:

a = F_net / m

Substituting the expressions for F_parallel and F_friction, we get:

a = [m * g * sin(theta) - coefficient_of_friction * m * g * cos(theta)] / m

Simplifying, we get:

a = g * [sin(theta) - coefficient_of_friction * cos(theta)]

Substituting the given values, we get:

a = 9.8 m/s^2 * [sin(36°) - 0.55 * cos(36°)] = 6.43 m/s^2

Therefore, the acceleration of the block is 6.43 m/s^2.

Answer:

The first mechanical means for transmitting real-time stock market data from exchange floors to brokers and investors across the country.

Explanation:

Answer:

Explanation:

To determine the force needed to accelerate a 70 kg table at a rate of 4 m/s², we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a).

So, we can calculate the force (F) required using the following formula:

where F is the force in Newtons (N), m is the mass in kilograms (kg), and a is the acceleration in meters per second squared (m/s²).

Plugging in the given values, we get:

The change in momentum of the ball is -1.215 kg m/s. This is known as the law of conservation of momentum, which states that the total momentum of an isolated system remains constant if no external forces act upon it.

What is Momentum?

Momentum is a physics concept that describes the quantity of motion an object has. It is defined as the product of an object's mass and velocity. The formula for momentum is p = mv, where p is momentum, m is mass, and v is velocity. Momentum is a vector quantity, meaning it has both magnitude and direction. In the absence of external forces, the total momentum of a system is conserved.

a. The initial momentum of the ball can be calculated using the formula:

p = mv

where p is the momentum, m is the mass, and v is the velocity.

p = (0.045 kg) (27 m/s) = 1.215 kg m/s

Therefore, the initial momentum of the ball is 1.215 kg m/s.

b. The final momentum of the ball can also be calculated using the formula:

p = mv

Assuming the ball comes to a stop after being hit, the final velocity will be 0 m/s. So we get:

p = (0.045 kg) (0 m/s) = 0

Therefore, the final momentum of the ball is 0 kg m/s.

c. The change in momentum of the ball can be calculated using the formula:

Δp = pf - pi

where Δp is the change in momentum, pf is the final momentum, and pi is the initial momentum.

Δp = 0 - 1.215 kg m/s = -1.215 kg m/s

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Answer: The length of track required is 500 m.

Explanation: Determine the object's original velocity by dividing the time it took for the object to travel a given distance by the total distance. In the equation V = d/t, V is the velocity, d is the distance, and t is the time.

Brainliest? <33

Answer:

This is an isolated system

Explanation:

By the definition

"Isolated system is a type of system on which no external force acts on"

In the above diagram, the surroundings are not applying any force on the enclosed system

Hence it is an Isolated system (Option 1)

Hope you understand

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Answer:

E = h ν     energy of wave of frequency ν

ν = c / λ      frequency of wave in terms of wavelength

E = h c / λ

Since λ = 6.4E-11 is the shortest wavelength this corresponds to the highest potential needed

E = 6.63E-34 * 3.00E8 / 6.4E-11 = 3.11E-15 joules

V = E / q = 3.11E-15 / 1.6E-19 = 19,400 volts

Note (E above is energy required and not the electric field)

The heaviest box that you can push up the ramp at constant speed is 114kg where the coefficient of kinetic friction is 0.30.

Given the mass of heaviest box (m) = 68kg

The coefficient of kinetic friction of floor is (k1) = 0.30

The angle of inclination of ramp (θ) = 60°

The coefficient of kinetic friction between the box and ramp is(k2) =  0.30

The speed to push box on floor is constant = F

In the first case, the maximum horizontal force that can be applied to the box is equal to the coefficient of kinetic friction multiplied by the weight of the box.

F1 = k1 * m = 68 * 0.30 = 20.4 N.

In the second case, the maximum force that can be applied to the box is equal to the coefficient of kinetic friction multiplied by the normal force that the ramp exerts on the box.

The maximum force on ramp is (F2) = 0.30 x 68 x cos 60.0 = 34.2 N.

Thus it means that you can push a heavier box up the ramp at constant speed than you can across the level floor.

The maximum weight of the box that can be pushed up the ramp at constant speed is (M) = F2/k2 = 34.2 N / 0.30 = 114 kg.

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As 500 kg of supplies are added to the truck, the gravitational force between the two vehicles rises from 1.27 106 N to 1.33 106 N.

As a result, when the space between the objects is cut in half, the gravitational force multiplies by four.

The Newton's Law of Universal Gravitation can be used to compute the gravitational force between the two vehicles: F = G * (m1 * m2) / d²

Plugging in the values given in the problem, we get:

F = 6.6743 × 10⁻¹¹ * ((3,650 kg) * (9,850 kg)) / (25.0 m)²

F = 1.27 × 10⁻⁶ N

As a result, there is 1.27 106 N of gravitational force between the two vehicles.

The separation between the two vehicles stays constant. Hence, after entering the updated values, we obtain:

F = 6.6743 × 10⁻¹¹ * ((3,650 kg) * (10,350 kg)) / (25.0 m)²

F = 1.33 × 10⁻⁶ N

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