DNA polymerase and RNA polymerase are enzymes responsible for polymerizing nucleotides during DNA replication and transcription, respectively. Both enzymes use a template strand of DNA to synthesize a complementary strand of RNA or DNA, respectively.
What does the sequence of template provide ?The sequence of the template strand of DNA provides the information needed for DNA or RNA polymerase to know what nucleotides to polymerize.
DNA polymerase reads the sequence of the template strand of DNA and selects the corresponding nucleotide to add to the growing complementary strand. Similarly, RNA polymerase reads the sequence of the template strand of DNA and selects the corresponding ribonucleotide to add to the growing RNA strand.
The nucleotides are selected based on the base-pairing rules, which dictate that adenine (A) pairs with thymine (T) in DNA, and with uracil (U) in RNA, and that cytosine (C) pairs with guanine (G).
Therefore, By following these rules, the enzymes ensure that the new DNA or RNA strand is complementary to the template strand and that the genetic information is faithfully transmitted from one generation to the next.
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What is NAD (NAD+) and NADH? Describe them as if you were a
chemist – consider their structures – what do they transfer? Why is
NAD+ needed by all cells no matter what type of metabolism they
use?
NAD, or nicotinamide adenine dinucleotide, is a coenzyme found in all living cells. It is involved in metabolism, or the process of breaking down molecules for energy. NAD+ is the oxidized form of NAD, while NADH is the reduced form.
In terms of structure, NAD+ and NADH are both composed of two nucleotides joined by their phosphate groups. The first nucleotide contains an adenine base, while the second contains a nicotinamide base. The difference between the two forms lies in the presence of an extra hydrogen atom and an extra electron in NADH.
NAD+ is needed by all cells because it plays a crucial role in the electron transport chain, which is the final step in the process of cellular respiration. This is where the majority of ATP, the molecule that provides energy for cellular processes, is produced. Without NAD+, the electron transport chain would not be able to function, and cells would not be able to produce enough energy to survive.
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Describe one biological example where intermolecularforces/interactions (Van der Waals) are important (2 marks).Explain why glycogen must be easy to hydrolyze. (2marks)
One biological example where intermolecular forces/interactions (Van der Waals) are important is in the folding and stabilization of proteins.
Van der Waals forces are important in the formation of the tertiary and quaternary structures of proteins, which are essential for their proper function. These forces allow for the proper folding of the protein and for the interaction between different subunits of the protein, allowing for the formation of functional protein complexes.
Glycogen must be easy to hydrolyze because it is a primary source of energy for the body. Glycogen is stored in the liver and muscles and is broken down into glucose through the process of hydrolysis when the body needs energy.
If glycogen were not easy to hydrolyze, the body would not be able to quickly access the energy it needs, leading to a lack of energy and potentially causing harm to the body.
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Define and describe the following classes of cytotoxicity assays
and give an example of each:
Viability-
Survival-
Metabolic-
genotoxicity and transformation-
Irritancy-
Cytotoxicity assays are used to measure the ability of a substance to damage or kill cells.
There are several different classes of cytotoxicity assays, each of which measures a different aspect of cell health or damage. Viability assays measure the ability of cells to maintain basic functions necessary for life, such as membrane integrity and metabolic activity. An example of a viability assay is the trypan blue exclusion assay, which measures the ability of cells to exclude the dye trypan blue, indicating intact cell membranes.Survival assays measure the ability of cells to survive and proliferate in the presence of a toxic substance. An example of a survival assay is the colony forming assay, which measures the ability of cells to form colonies in the presence of a toxic substance.Metabolic assays measure the ability of cells to maintain metabolic activity in the presence of a toxic substance. An example of a metabolic assay is the MTT assay, which measures the ability of cells to reduce the dye MTT, indicating metabolic activity.Irritancy assays measure the ability of a substance to cause irritation or inflammation in cells or tissues. An example of an irritancy assay is the HET-CAM assay, which measures the ability of a substance to cause irritation in the chorioallantoic membrane of a chicken embryo.Learn more about essays here:https://brainly.com/question/11606608
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Some strains of staphylococcus aureus are resistant to modified penicillins e.g. methicillin, flucloxacillin because they are able to:
1) Pump the drug from the cell before it can act
2) Prevent the drug reaching its site of action
3) Infect human cells unaffected by the drug
4) Produce an enzyme unaffected by the drug
The main cell type in our blood that phagocytoses and digests foreign material is the:
1) Erythrocyte
2) Platelet
3) megakarycoyte
4) Neutrophil
5) Lymphocyte
Helicobacter pylori
1) Is not associated with stomach cancer
2) Is a common cause of diarrhoea
3) Is commonly cultured from pus obtained from an infected appendix
4) Is the main cause of duodenal ulcers
5) Shoulder never be treated because it is resistant to all antibiotics
The subset of T lymphocytes that control immune and inflammatory responses is:
1) TCR cells
2) CD4 cells
3) NK cells
4) CD3 cells
5) CD8 cells
T cells that can kill virus infected and cancer cells are identified by which maker?
1) CD8
2) CD4
3) CD3
4) CD1
5) CD20
Multiple choice questions. please answer all questions with the right answer from the options
1) Some strains of staphylococcus aureus are resistant to modified penicillins e.g. methicillin, flucloxacillin because they are able to: 4) Produce an enzyme unaffected by the drug
2) The main cell type in our blood that phagocytoses and digests foreign material is the: 4) Neutrophil
3) Helicobacter pylori: 4) Is the main cause of duodenal ulcers
4) The subset of T lymphocytes that control immune and inflammatory responses is: 2) CD4 cells
5) T cells that can kill virus infected and cancer cells are identified by which marker is: 1) CD8
What's cellThe definition of a cell is the smallest unit of an organism or living thing. The cell is the basic structural and functional unit of organisms, just like the atoms in a chemical structure. Cells can determine the durability of living things.
Substances that make up cells consist of organic and inorganic compounds. The inorganic elements of cells consist of carbon, hydrogen, nitrogen, and oxygen. While organic elements are in the form of complex structures ranging from the nucleus, ribosomes, and others.
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What does the chromosome do in a plant cell?
Answer:
carry genetic material
Explanation:
Chromosomes are used to transport the genetic material of organisms. In animals chromosomes determine the gender of offspring. The Mendelian factors that are influenced by DNA are carried in the chromosomes, and these include things like flower color, leaf size, seed shape, etc.
30 POINTS + BRAINLIEST!!!
According to the phylogenetic tree, from which domain did Eukarya evolve?
The first branch of the phylogenetic tree holds the species of the bacteria division. It contains thermotoga bacteria, green non sulfur bacteria, cyanobacteria, gram positive bacteria, and purple bacteria. The second branch of the phylogenetic tree holds species of the Eukarya. It contains diplomonads, microsporidia, trichomonads, flagellates, entamoeba, slime molds, ciliates, plants, animals, and fungi. The last branch of the phylogenetic tree starts at the beginning of Eukarya line and holds the species of the Archaea division. It contains Thermococcus, Pyrodictium, Thermoproteus, Methanobacterium, and extreme halophiles.
A. Animals
B. Bacteria
C. Thermotoga
D. Archaea
Eukarya includes all organisms that have cells with nuclei and other complex cellular structures. According to current scientific understanding, the Eukarya domain evolved from the Archaea domain.
What is a phylogenetic tree?A phylogenetic tree is a diagrammatic representation of the evolutionary relationships among different groups of organisms. It depicts the evolutionary history and ancestry of organisms based on their physical or genetic characteristics, such as DNA sequences or morphological features.
The phylogenetic tree suggests that the Archaea domain and the Eukarya domain share a common ancestor, and that the two domains diverged from a common ancestor approximately 2 billion years ago. This hypothesis is supported by genetic and biochemical evidence, which indicates that the two domains share many common features, such as certain metabolic pathways.
It's worth noting that the third domain of life, Bacteria, evolved independently from both Archaea and Eukarya, and represents a distinct evolutionary lineage.
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Answer:
D. Archaea
Explanation:
i got it right on my quiz
A 24-year-old astrologer with a history of intravenous drug abuse sees his doctor because he has felt tired and unwell for the past few weeks. He has noticed that his urine is very dark, he feels nauseated, and does not feel like eating, and he has developed right-sided abdominal discomfort. A friend thinks that he looks ‘yellow’. On examination he is tattooed, has yellow sclerae, and is tender in the right upper quadrant of his abdomen. His liver is enlarged, firm and smooth.
The results of investigations including the liver function tests are: AST, 1200 IU/l; ALT, 1000 IU/l; ALP, 100 IU/l; bilirubin, 60 μmol/l.
1. What is the most likely diagnosis and what is the differential diagnosis of a viral hepatitis in this setting?
2. What investigations would you perform?
3. How would you manage this man?
4. What other factors are important regarding the control of infection?
The most likely diagnosis for this 24-year-old astrologer with a history of intravenous drug abuse is acute viral hepatitis. The differential diagnosis includes other forms of hepatitis, such as autoimmune hepatitis, alcoholic hepatitis, and drug-induced hepatitis.
Diagnosis investigationTo further investigate this diagnosis, the following investigations should be performed:
- Hepatitis serology to determine the type of viral hepatitis (A, B, C, etc.)
- Complete blood count (CBC) to assess for anemia or other abnormalities
- Coagulation studies to assess for any bleeding disorders
- Ultrasound or CT scan of the abdomen to assess for any liver abnormalities or evidence of cirrhosis
In terms of management, the main goal is to provide supportive care while the patient's immune system fights off the infection.
This may include:
- Rest and avoiding strenuous activity
- Avoiding alcohol and any medications that may be harmful to the liver
- Providing adequate hydration and nutrition
- Monitoring for any complications, such as liver failure or encephalopathy
Other important factors regarding the control of infection include:
- Ensuring that the patient does not share needles or other drug paraphernalia with others
- Practicing safe sex to prevent the spread of infection to sexual partners
- Avoiding close contact with others who may be at risk for contracting the infection
- Getting vaccinated against other forms of viral hepatitis, if appropriate.
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Please provide a detailed but easily understood
explanation of how the chemistry of PowerQuant System (DNA).
The chemistry of PowerQuant System is based on the principle of DNA amplification and quantification. This system utilizes a process called polymerase chain reaction (PCR) to amplify specific regions of DNA in a sample.
The amplified DNA is then quantified using fluorescent probes that bind to the DNA and emit a signal that can be detected and measured. The PowerQuant System specifically targets two regions of human DNA, one on the X chromosome and one on the Y chromosome, to determine the quantity of male and female DNA in a sample. This information is important in forensic analysis, as it can help to determine the presence of a male or female suspect in a crime scene sample. Overall, the chemistry of PowerQuant System is a powerful tool for DNA analysis and quantification, and is widely used in forensic and other scientific applications.
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Please identify and describe the major sequence of events involved in Muscle Contraction and Relaxation. Please be sure to begin with the Action Potential events at the Neuromuscular junction, and end with Muscle Relaxation. Please be sure to include all neurotransmitters involved, any associated ions and structures, and any and all proteins involved in this process. Be sure to include the specific roles of ATP in the processes.
The major sequence of events involved in Muscle Contraction and Relaxation, the process begins with the action potential events at the neuromuscular junction and ends with muscle relaxation. In this process, several neurotransmitters, ions, structures, and proteins are involved. ATP also plays a significant role in these processes.
When an action potential is sent down an axon and reaches the neuromuscular junction, it causes the release of the neurotransmitter acetylcholine (ACh). ACh binds to receptors on the muscle cell and triggers an influx of sodium ions, resulting in a depolarization of the cell. This depolarization causes calcium ions to be released from the sarcoplasmic reticulum, a membrane-bound organelle in muscle cells.
The released calcium ions bind to a protein called troponin, which allows the protein myosin to interact with the thin actin filaments of the sarcomere. This interaction forms a cross bridge between the two proteins, which pulls the actin filaments closer together and results in muscle contraction. To sustain the contraction, ATP is needed to break the cross bridge and form a new one, creating the contraction-relaxation cycle.
The relaxation of a muscle cell occurs when the calcium ions are re-absorbed into the sarcoplasmic reticulum. This causes troponin to no longer bind with the myosin, and the myosin-actin cross bridge is broken. This releases the tension on the actin filaments, causing the muscle to relax.
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You're given the following data for the ankle. Based on numerical differentiation with the central difference method, is the ankle moving in dorsiflexion or plantar flexion at 0.3 seconds? Show your work below and explain vour answer (1 mark)
Time(seconds) Relative Ankle Angle(degrees)
0.1
108
0.2 120
0.3 104
0.4 93
Based on numerical differentiation with the central difference method, the ankle is moving in dorsiflexion at 0.3 seconds. To calculate the numerical differentiation, subtract the value of the function at the lower point (t-1) from the value of the function at the higher point (t+1) and divide it by the change in the independent variable (2h).
Therefore, the numerical differentiation of the data at 0.3 seconds is calculated as:
(1040 - 1200) / (0.4 - 0.2) = -160/0.2 = -800.
Dorsiflexion is defined as the movement of the ankle joint in which the foot is moved toward the front of the leg. During dorsiflexion, the foot is lifted toward the shin, with the toes pointing toward the shin and the heel pointing downward. The muscles and tendons involved in dorsiflexion are the tibialis anterior, the extensor hallucis longus, and the extensor digitorum longus. These muscles help lift the ankle and flex the toes.
Dorsiflexion is important for activities such as running, walking, and jumping. It allows us to move our feet in the desired direction, while also providing stability and balance. It also plays an important role in posture and standing balance. By flexing the ankle joint, the muscles and tendons involved can help to maintain an upright posture.
Dorsiflexion also helps protect the knee and hip joints from damage. By dorsiflexing the ankle, the knee and hip joints are better able to absorb shock. This helps reduce the risk of injury to these joints.
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Alyssa C. is your first patient. She was born in Italy, and moved to the United States with her family when she was 10. She is a 60-year-old homemaker, who appears slightly overweight, and admits to high blood pressure and high cholesterol, both controlled by medication. She has been a patient in the practice of your dentist's sister, Dr. Lynne, who has an office across town, for the last 30 years. She recently decided to change dental practices as our office is near her residence.
Alyssa has been faithful with her recall visits, and has followed all the treatments that Dr. Lynne and the various hygienists have suggested during her years as a patient in that practice, including routine radiographs.
You begin probing, and Alyssa questions what you are doing. She states that "no one has ever done that to her teeth and gums," and quite frankly finds it very uncomfortable. Alyssa says that she thought her oral health could be evaluated by the "full set of x-rays" that she received every few years.
Clinically, it reveals that Alyssa presents with generalized tooth mobility and early furcation involvement, especially on the maxillary molars. Her probe readings are generalized 4 to 6 mm in the posterior sextants. She assumed that her mouth was in good health, and is shocked to find out otherwise.
1. What ethical principles are in conflict in this dilemma?
2. What is the best way for you to handle this ethical dilemma?
3. What is the best way to address/discuss Philomena's treatment plan?
Autonomy: Alyssa has the right to make decisions about her health and her body. She believed that routine radiographs were enough to evaluate her oral health, and may feel that her autonomy was violated by the probing and examination.
Beneficence: As a healthcare provider, your duty is to do what is in the patient's best interest, which may include identifying and addressing oral health issues, such as periodontal disease. However, in doing so, you may be causing discomfort or anxiety to the patient, which may create tension with the principle of autonomy.
Non-maleficence: Healthcare providers should not cause harm to their patients. In this case, probing may be uncomfortable for Alyssa, and she may feel that the examination caused her harm.
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True or False:
1. Triose phosphate isomerase decreases ΔG for the step in glycolysis catalyzed by aldolase through rapid removal of dihydroxyacetone phosphate.
2. Aldolase catalyzes an irreversible "splitting" of hexose, fructose 1,6-bisphosphate, to form two triose sugars.
3. 6-Phosphogluconate is a more reduced form of glucose 6-phosphate.
4. The pyruvate kinase catalyzed step is a reversible reaction in glycolysis, allowing gluconeogenesis to proceed via the same enzyme.
5. Triose phosphate isomerase converts dihydroxyacetone phosphate to glyceraldehyde 3-phosphate through an intermediate with a carbon-carbon double bond.
6. In the reaction catalyzed by aldolase, the carbon atoms of the product dihydroxyacetone phosphate are derived from carbon atoms 1-3 of fructose bisphosphate.
1. True
2. True
3. False
4. False
5.True
Determine True or False1. True. Triose phosphate isomerase does decrease ΔG for the step in glycolysis catalyzed by aldolase through rapid removal of dihydroxyacetone phosphate.
2. True. Aldolase does catalyze an irreversible "splitting" of hexose, fructose 1,6-bisphosphate, to form two triose sugars.
3. False. 6-Phosphogluconate is not a more reduced form of glucose 6-phosphate, it is actually an oxidized form of glucose 6-phosphate.
4. False. The pyruvate kinase catalyzed step is not a reversible reaction in glycolysis, it is an irreversible reaction.
5. True. Triose phosphate isomerase does convert dihydroxyacetone phosphate to glyceraldehyde 3-phosphate through an intermediate with a carbon-carbon double bond.
6. True. In the reaction catalyzed by aldolase, the carbon atoms of the product dihydroxyacetone phosphate are derived from carbon atoms 1-3 of fructose bisphosphate.
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1) Explain in your own words three examples of
how membranes are asymmetrical, and state how each example is
related to membrane function.
Biological membranes are asymmetrical structures, which means that the two leaflets of the membrane have different compositions. This asymmetry is critical for the function of the membrane, as it allows for the segregation of different molecules and the establishment of distinct biochemical environments on either side of the membrane.
1) Lipid Bilayer: The lipid bilayer of the cell membrane is asymmetrical because the two layers of phospholipids face each other with the non-polar tails pointing inward and the polar heads facing outward. This asymmetry is important for membrane function as it helps form a barrier that keeps unwanted substances out while allowing certain substances in.
2) Proteins: Proteins embedded within the cell membrane are also asymmetrical. Depending on their function, they can either be embedded within the lipid bilayer or span across the two layers. This asymmetry helps regulate cell-signalling, transport of substances across the membrane, and cell-recognition.
3) Cholesterol: Cholesterol molecules are asymmetrically distributed within the cell membrane. The cholesterol molecules increase the rigidity of the membrane, which helps regulate the membrane's fluidity and is important for cell-signalling.
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Help i need to answer this question!! A chef needs to increase the temperature of a food dish. She thinks she can do this by stacking another dish on top of it. She has three dishes to choose from for the top dish: A, B, and C.
Which one of these dishes would make the food dish the warmest when placed on top of it? As part of your answer, explain how the energy and temperature of both the top dish and the food dish will change when the food dish warms up, and why.
Stacking another dish on top of a food dish is not an effective way to increase its temperature, as the dish on top may get slightly warm and the food won't be cooked in less time while the dish at the base will get more temperature.
What is the temperature in cooking?The dish on top may get slightly warm, but it will not be enough to significantly heat up the food dish underneath, and the reason for this is that the transfer of heat from one object to another depends on the temperature difference between them, the surface area of contact, and the thermal conductivity of the materials involved.
Hence, stacking another dish on top of a food dish is not an effective way to increase its temperature, as the dish on top may get slightly warm and the food won't be cooked in less time.
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What level of the marine food chain does the dugong occupy
The "sea bull" or dugong is an insectivorous marine mammal that mostly eats aquatic habitats.
As a result, it functions as a primary consumer at a very low level of the seafood chain, consuming producers (seagrasses) and supplying food for higher-level consumers like sharks and crocodiles.
Due to their ability to keep the balance between nutrient cycling and seagrass growth, dugongs are crucial to the health of the marine ecosystem. Their feeding habits assist in limiting the growth of seagrass, which can cause habitat degradation and oxygen deprivation.
Due to their existence as a marker of a thriving seagrass bed, dugongs are also used as a gauge of ecosystem health. Threats to dugongs include habitat degradation, poaching, and unintentional entrapment in fishing gear.
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Long hair (L) and erect ears (E) are dominant over short hair (I) and drooping ears (e) in dogs. In a cross between with long hair and erect ears, what is the percentage of the offspring that will...
have the same genotype as their parents?
be heterozygous long hair and homozygous drooping ears?
be double recessives for both characters?
be pure breeding for the ear type characteristic?
have only 1 homozygous recessive character in its genotype?
Dogs with long hair (L) are more dominating than those with short hair (I) and drooping ears (e). The answer to the percentage of the offspring questions are:
100% of the offspring will have the same genotype as their parents0% of the offspring will be heterozygous long hair and homozygous drooping ears0% of the offspring will be double recessives for both characters0% of the offspring will be pure breeding for the ear type characteristic0% of the offspring will have only 1 homozygous recessive character in its genotypeTo answer these questions, we need to use the Punnett square method. For the first cross, the parents have the genotype LLEe, which means they have long hair and erect ears. The Punnett square for this cross is:
| | L | l |
|---|---|---|
| E | LE | lE |
| e | Le | le |
From this Punnett square, we can see that:
100% of the offspring will have the same genotype as their parents (LLEe).0% of the offspring will be heterozygous long hair and homozygous drooping ears (Llee).0% of the offspring will be double recessives for both characters (llee).0% of the offspring will be pure breeding for the ear type characteristic (EE or ee).0% of the offspring will have only 1 homozygous recessive character in its genotype (ll or ee).Learn more about dominant and recessive character https://brainly.com/question/20639307
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2. Review information about redox reactions. Describe this term
and specifically what oxidation means and what reduction means.
Redox reactions, also known as oxidation-reduction reactions, involve the transfer of electrons between two species. Oxidation is the process in which electrons are removed from an atom, causing it to lose its negative charge. Reduction is the process in which electrons are added to an atom, causing it to gain a negative charge.
Redox reactions, also known as oxidation-reduction reactions, are a type of chemical reaction in which the oxidation states of atoms are changed. Oxidation and reduction are two processes that occur during redox reactions, see:
Oxidation is the process of losing electrons, which results in an increase in the oxidation state of an atom. This can occur through the addition of oxygen to a compound, the removal of hydrogen from a compound, or the loss of electrons to another atom or molecule.Reduction, on the other hand, is the process of gaining electrons, which results in a decrease in the oxidation state of an atom. This can occur through the removal of oxygen from a compound, the addition of hydrogen to a compound, or the gain of electrons from another atom or molecule.See more about redox reactions at https://brainly.com/question/21851295.
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1) Matching.
Using the figure below, identify the missing words corresponding with the organization of life.
a.
atom
b.
molecule
d.
The missing words in the figure would be cell and tissue.
Organization of lifeThe missing words corresponding with the organization of life would be:
atommoleculecelltissueAtoms are the basic units of matter. Molecules are formed when two or more atoms bond together. Cells are the fundamental units of life that are made up of molecules. Tissues are groups of cells that work together to perform a specific function in the body.
These four concepts describe the hierarchical organization of living things.
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A. The liver is more likely than many other organs to develop
cancer. Why?
B. Describe how bone is both flexible and rigid.
A. The liver is more likely than many other organs to develop cancer because the liver is the main organ that filters and removes toxins from the body. The liver is also involved in metabolizing various substances such as drugs, hormones, and nutrients. Exposure to these toxins and metabolites can cause damage to the liver cells, leading to the development of cancer.
B. Bone is both flexible and rigid because it is made up of two types of tissue: cortical bone and cancellous bone. Cortical bone is the dense, hard outer layer of bone that provides strength and support. Cancellous bone, also known as spongy bone, is the more flexible inner layer that helps absorb shock and stress.
The combination of these two types of tissue allows bone to be both rigid and flexible, making it able to withstand stress and pressure while also allowing for movement and flexibility. Additionally, bone is constantly being remodeled by cells called osteoblasts and osteoclasts, which helps maintain its strength and flexibility over time.
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Archaea are composed of ________ cells.
Archaea are composed of ________ cells.
eukaryotic
prokaryotic
bacterial
animal
Archaea are composed of Prokaryotic cells. The correct option is B.
Thus, Any single-celled prokaryotic organism that belongs to the domain Archaea has unique molecular characteristics that set it apart from bacteria, the other, more well-known group of prokaryotes.
It is from eukaryotes, which include organisms like plants and animals and whose cells contain a defined nucleus.
The word archaea comes from the Greek word archaios, which means "ancient" or "primitive," and some archaea do in fact exhibit traits deserving of that description.
Thus, Archaea are composed of Prokaryotic cells. The correct option is B.
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Draw and describe a flow volume loop depicting an obstructive
disease patient, restrictive disease patient, and normal
patient.
A flow volume loop depicting an obstructive disease patient has a scooped out shape, restrictive disease patient has a tall and narrow shape, and normal patient has a rounded shap.
A flow volume loop is a graph that shows the relationship between airflow and lung volume during a respiratory cycle. The x-axis represents lung volume and the y-axis represents airflow. There are different shapes of flow volume loops for normal patients, obstructive disease patients, and restrictive disease patients. In normal patient, the flow volume loop of a normal patient has a rounded shape. The peak flow occurs at mid-inspiration and the expiratory flow is greater than the inspiratory flow.
The obstructive disease patient, the flow volume loop of an obstructive disease patient has a scooped out shape. The peak flow occurs early in inspiration and the expiratory flow is less than the inspiratory flow, this is because the airways are narrowed and there is an obstruction to airflow. In restrictive disease patient, the flow volume loop of a restrictive disease patient has a tall and narrow shape. The peak flow occurs early in inspiration and the expiratory flow is greater than the inspiratory flow, this is because the lungs are stiff and there is a restriction to lung expansion. In conclusion, the flow volume loop is a useful tool for diagnosing respiratory diseases. The shape of the loop can indicate if the patient has an obstructive disease, restrictive disease, or normal lung function.
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State True or False: Amino acids are the building blocks of protein.
The statement about amino acids are the building blocks of protein is true.
What are amino acids?Аmino аcids аre orgаnic molecules thаt serve аs the building blocks of proteins, which аre the most importаnt biomolecules in living cells. They're аlso essentiаl to а vаriety of physiologicаl processes, including enzyme operаtion, cell signаlling, аnd neurotrаnsmitter synthesis.
Eаch аmino аcid is mаde up of а centrаl cаrbon аtom (C), аn аmino group ([tex]NH_{2}[/tex]), а cаrboxyl group (COOH), аnd а side chаin (R group). Аmino аcids аre linked together viа peptide bonds to form polypeptide chаins, which cаn be folded into а specific three-dimensionаl shаpe to produce а functionаl protein.
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More than 80 years ago, a biologist studied harvest records to understand how the population dynamics of a secondary consumer may be determined by the population dynamics of a primary consumer that makes up a large part of its diet. What were the species involved, and which was the primary vs. secondary consumer (2pts)? Describe how their population sizes were linked (2pts), and explain how such a relationship might be disrupted by other factors in the ecosystem (2pts).
The species involved in this study were lynx (secondary consumer) and snowshoe hare (primary consumer).
The biologist observed that when the population of snowshoe hares increased, the population of lynx would also increase due to the availability of food.
However, when the population of hares decreased, the population of lynx would also decrease due to the lack of food. This relationship between the two species is known as a predator-prey relationship.
Other factors in the ecosystem can disrupt this relationship, such as the introduction of a new predator or competition for resources.
For example, if a new predator was introduced into the ecosystem that also preyed on snowshoe hares, the lynx would have to compete for food, which could lead to a decrease in the lynx population.
Additionally, if there was a decrease in the availability of resources for the snowshoe hares, such as food or shelter, their population could decrease, which would in turn affect the lynx population.
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Write a lab report in the scientific method for the organic molecules experiment. Your purpose is to test samples for the presence of organic molecules. GUARANTEED THUMBS UP PLEASE ANSWER IT PLEASE
The scientific method is a series of steps that scientists use to answer questions and solve problems. In the organic molecules experiment, we are testing samples for the presence of organic molecules.
Lab Report exampleHere is a lab report written in the scientific method for this experiment:
1. Purpose: The purpose of this experiment is to test samples for the presence of organic molecules.
2. Hypothesis: If the samples contain organic molecules, then they will test positive for the presence of organic molecules.
3. Materials: The materials used in this experiment are the samples to be tested, a testing kit, and a lab notebook.
4. Procedure: The procedure for this experiment is as follows: a. Label each sample with a number or letter. b. Use the testing kit to test each sample for the presence of organic molecules. c. Record the results of each test in the lab notebook.
5. Results: The results of this experiment are the observations and data collected during the testing process.
6. Conclusion: The conclusion of this experiment is the answer to the question of whether or not the samples contain organic molecules. This is based on the results of the testing process.
7. Discussion: The discussion of this experiment includes any observations or conclusions that were made during the testing process, as well as any potential sources of error or limitations of the experiment.
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Near the end of both March and September,
a. spring begins in both hemispheres.
b. the sun's rays strike Earth with the same intensity everywhere.
c. Earth's axis is no longer pointing at the North Star.
d. neither end of Earth's axis is tilted toward the sun.
Answer:
A. Spring begins in both hemispheres.
Explanation:
There are 2 equinoxes in a year. One on 21st March and one on 22nd September. This is when both side of the hemispheres have roughly the same amount of daytime and nighttime.
In addition to vitamin D production, exposure to sunlight also increases production of endorphins, calcitonin, and melanocyte stimulating hormone. These factors all ___________ the ability to attribute the effects of sun exposure to Vitamin D.
Group of answer choices
a. assists in
b. completely prevent
c. confound
The statement is completed as: ''These factors all confound the ability to attribute the effects of sun exposure to Vitamin D.'' Therefore, alternative c. is correct.
The meaning of the term 'confound' is to cause something to become confused. The exposure to sunlight increases the production of endorphins, calcitonin, and melanocyte stimulating hormone besides vitamin D production.
These factors can become confusing as they all mask the ability to attribute the effects of sun exposure to Vitamin D.
So, the right option among the given choices is c. confound.
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Q. Absorbance outside the standard curve cannot be used to determine the unknown concentrations using the standard curve. Explain why not.
Q. An enzyme catalyzes a reaction at a velocity of 20 μmol/min when the concentration of substrate (S) is 0.01 M. The Km for this substrate is 1 × 10-5 M. Assuming that Michaelis-Menten kinetics are followed,
A) What will the reaction velocity be when the concentration of S is (a) 1 × 10-5 M and (b) 1 × 10-6 M?
B) What would be the effect on the initial reaction velocities if an enzyme was reduced to 10 % of the original amount used?
A. Absorbance outside the standard curve cannot be used to determine the unknown concentrations using the standard curve because the standard curve is only accurate within a certain range of absorbance values.
If the absorbance is outside of this range, the standard curve cannot accurately predict the concentration of the unknown substance.
A. (a) When the concentration of S is 1 × 10-5 M, the reaction velocity will be the same as the maximum reaction velocity (Vmax) because the concentration of S is equal to the Km. Therefore, the reaction velocity will be 20 μmol/min.
(b) When the concentration of S is 1 × 10-6 M, the reaction velocity will be lower than the maximum reaction velocity because the concentration of S is lower than the Km. The reaction velocity can be calculated using the Michaelis-Menten equation:
V = (Vmax[S])/(Km + [S])
V = (20 μmol/min)(1 × 10-6 M)/(1 × 10-5 M + 1 × 10-6 M)
V = 1.67 μmol/min
B. If the enzyme was reduced to 10% of the original amount used, the initial reaction velocities would be reduced to 10% of their original values. This is because the amount of enzyme is directly proportional to the reaction velocity. If there is less enzyme available to catalyze the reaction, the reaction will proceed at a slower rate.
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The American shad is a species of herring (type of fish) that spends most of the time in the ocean but spawns in many of the larger rivers of Oregon and California. What is the name for this type of migratory life history strategy?
The type of migratory history strategy exhibited by the American shad is called anadromy.
What is Anadromy?Anadromy is a type of fish migration where fish move between freshwater and saltwater environments, often travelling long distances in order to spawn in their original habitats.
Anadromous fish, like the American shad, are born in freshwater, migrate to the ocean to grow and mature, and then return to freshwater to spawn.
This is different from catadromy, in which fish are born in the ocean, migrate to freshwater to grow and mature, and then return to the ocean to spawn. Anadromy is a common strategy among species of herring, salmon, and sturgeon.
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When we mixed species A and a low ph solution, this one survived.
When we mixed species E and a low ph solution, this one did not survived.
When we have Species E and species A and we mixed them in a low ph solution, both survived. What chemical process happened here? how does the Species A change the environment so that species E can survive?
The chemical process that happened here is called buffering.
In this case, species A acted as a buffer, preventing the pH from dropping too low and allowing species E to survive.
Buffering is the process in which a solution resists changes in pH when small amounts of an acid or base are added to it.
Species A likely contains a weak acid or weak base that reacts with the strong acid or base in the low pH solution to maintain a stable pH. This change in the environment allowed species E to survive, even though it could not survive in the low pH solution on its own.
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which of the following steps happens last during transcription
A: RNA polymerase pulls apart the double helix
B: RNA polymerase reaches the end of a gene
C: RNA polymerase reaches the beginning of the gene
D: RNA polymerase produces mRNA from DNA
The last stage in transcription of DNA is RNA polymerase reaches the end of a gene. The correct option to this question is B.
ProcessWhen RNA polymerase crosses a stop (termination) sequence in the gene, transcription is terminated, which marks the end of the process. Once the mRNA strand is finished, it separates from the DNA.Termination is the process that completes translation. When a stop codon (UAA, UAG, or UGA) in the mRNA enters the A site, the process is terminated. Although they are not tRNAs, release factors are proteins that fit perfectly into the P site and identify stop codons.Initiation, elongation, and termination are the three phases of transcription.RNA, which can be found as mRNA, tRNA, or rRNA, is the end product of transcription, whereas a polypeptide amino acid chain, which is what gives rise to proteins, is the end product of translation.For more information on DNA transcription kindly visit to
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