How do you make an XY graph in Excel?

Answer:

5.369 x 105

Step-by-step explanation:

Answer:

5.369 x 105

Cause in scientific notation, the decimal point is always after the first number from the left.

It is proven that ΔABD ≅ ΔDCA by RHS congruency criteria.

Triangles must have equal corresponding sides and equal corresponding angles in order to be congruent.

According to the RHS congruence theorem, two right-angled triangles are congruent if their respective hypotenuses and sides are the same as those of another right-angled triangle.

Here we have

AOC and BOD are diameters of a circle and have a center O.

It is given that AOC and BOD are diameters of a circle.

From the triangles Δ AOC and ΔBOD

⇒ BD = CA  [ Diameters of the circle i.e Hypotenuse of triangles ]    

⇒ ∠BAD = ∠CDA [ Right angles in a semicircle is 90°]

⇒ AD = AD [ Common in both triangles i.e sides of triangles ]

Thus, Using RHS congruence criteria

⇒ ΔABD ≅ ΔDCA

Hence,

It is proven that ΔABD ≅ ΔDCA by RHS congruency criteria.

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Answer:  The resulting expression is 8+9y+4, which simplifies to 12+9y.

Step-by-step explanation: To combine like terms, we add the coefficients of the terms that are the same. In this expression, the like terms are 2y and 7y. Their coefficients are 2 and 7, respectively, so when we add them we get 2+7=9. The resulting expression is 8+9y+4, which simplifies to 12+9y.

Answer:

14

Step-by-step explanation:

You can determine the common ratio by dividing each number in the sequence from the number preceding it.

There are 90 ways to arrange 6 beads of distinct colors in a 2*3 grid if reflections and rotations are considered the same.

In order to reach this result, we may use Burnside's Lemma, which states that the average number of arrangements of a symmetric object's symmetric parts, is taken throughout the set of all possible symmetry operations of the object.

You may fix one element and position the rest around it because of the rotation. You now have a total of 90 configurations available.

Thus, If reflections and rotations are treated equally, there are 90 ways to arrange 6 beads of different colors on a 2*3 grid.

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By using the conversion factor: 1 km/h = 0.277778 m/s, we get 12 meter per second is equal to 43.2 km/h.

Velocity is a vector quantity that represents the rate of change of an object's position. It is defined as the displacement of an object divided by the time it takes for that displacement to occur. In other words, velocity tells you how fast an object is moving in a certain direction.

The standard unit for velocity is meters per second (m/s) or kilometers per hour (km/h) in the International System of Units (SI). In imperial system of units, it is expressed in feet per second (ft/s) or miles per hour (mph).

The formula for velocity is:

velocity = displacement / time

To convert 12 m/s to km/h, you can multiply 12 by the conversion factor:

12 m/s * (1 km/h / 0.277778 m/s) = 43.2 km/h

So 12 meters per second is equal to 43.2 kilometers per hour.

Another way to do the conversion is by applying the formula :

Speed (km/h) = Speed (m/s) x 3.6

12 x 3.6 = 43.2

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Answer: h = 15 yards

Volume = 475.17 cubic yards

Diameter = 5.5*2 = 11.0 = 11 yards

HOPE THIS HELPS

The volume of a sphere with radius [tex]r[/tex] is [tex]\frac{4}{3}\pi r^3[/tex]. If the radius is multiplied by a constant [tex]k[/tex], then the new volume is [tex]\frac{4}{3} \pi (kr)^3[/tex], which is equal to [tex]k^3 \cdot \frac{4}{3} \pi r^3[/tex]. This means that the volume of the sphere is multiplied by [tex]k^3[/tex].

a. If the radius is doubled, the volume is multiplied by 8

b. If the radius is tripled, the volume is multiplied by 27

c. if the radius is quadrupled, the volume is multiplied by 64

According to the information we can infer that the triangle and its internal angles are: 76.7°, 125.2°, and 21.9°.

To draw the triangle with the given measures we must take into account the internal angles so that the triangle is correct. Additionally we must take into account that it is a scalene triangle.

In this case, the internal angles are the most important part because it gives the shape of the triangle. These angles are:

So, according to the above, this triangles is scalene and its sides are:

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If  sin (A + B) = 1

and tan (A - B) = 1/√3

value of:

We know that,

So,

A + B + A - B = 90 + 30

(A + A) + (B - B) = 120

2A = 120

A = 120/2

By putting value of A in 2

A - B = 30

60 - B = 30

-B = 30 - 60

-B = -30

tan 60 + tan 30

We know that

√3 + 1/√3

√3 × √3 + 1/√3

3 + 1/√3

[tex]4/√3[/tex]

sec A- cosec B

sec 60 - cosec 30

We know that

2 - 2 = [tex]0[/tex]

tan A+ tan B=4/√3

sec A- cosec B=0

Answer:

4

[tex]4 \sqrt{2(2) + 8} = 4 \sqrt{4 + 8 } = 4 \sqrt{12} = 4(6) = 24[/tex]

Answer:

2. k = -24

3. y = 50

4. m = -13

5. b = 8/7

6. x = -1/2

7. a = -4

8. k = 7.8

Step-by-step explanation:

2. -20 ÷ 5/6

3. 18 ÷ 0.36

4. -1/2 * 26

5. 6/7 + 2/7

6. 1/8 - 5/8

7. -2.3 - 1.7

8. 3.4 + 4.7

Those should be good. Good luck

Answer:

41235

Step-by-step explanation:

There are 120 five-digit numbers that can be made from the digits 1, 2, 3, 4, 5 if each digit is used once in the number,

The total number of times where each number will occur or be at first place is calculated as:

4! = 4 × 3 × 2 × 1

= 24

Hence,

24th number = The last number where 1 is at first place

We can write this out as:

12345

12354

12435

12453

12534

12543

13245

13254

13425

13452

13524

13542 e.t.c.

48th number = The last number where 2 is at first place

72nd place = The last number where 3 is at first place.

This means, the 73rd number is the first number where 4 is at first place.

Therefore, the 73rd number based on pattern is 41235

The approximate value of ㏒(b) to the nearest hundredth is 1.23.

The other method to write exponents in mathematics is using logarithms. A number's base-based logarithm is equal to some other number. A logarithm performs exponentiation's exact opposite function. 

In Logarithms, ㏒ₐ(b) = ㏒(b)/ ㏒(a)

Given that

The two expressions below have the same value when rounded to the nearest hundredth

=> ㏒₅ (b) = ㏒₉ (48)  

As we know  ㏒ₐ(b) = ㏒(b)/ ㏒(a)

=> ㏒₅ (b) = ㏒(b)/㏒(5)

=> ㏒(b)/㏒(5) = ㏒₉ (48)  

=> ㏒(b) = ㏒₉ (48) ㏒(5)

=> ㏒(b) =  (1.7618)(0.6989)  

=> ㏒(b) = 1.23132202  

=> ㏒(b) = 1.23  

Therefore,

The approximate value of ㏒(b) to the nearest hundredth is 1.23.

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Which of these is the algebraic expression for "5 times the sum of 2 and y?" (1 point)

A. 5 ⋅ 2 + y

B. 2 + 5 ⋅ y

C. 2(5 + y)

D. 5(2 + y) ✔

______________

Answer:

D 5(2+y)

Step-by-step explanation:

"5 times (so moltepli by 5) the sum (the answer of a addition equation) of 2 and y?".

hope this helps, pleas give Brainliest. :)

The required true statements for the given lines are 1 and 4.

An element or portion of a line with two endpoints is called a line segment. A line segment, in contrast to a line, has a known length. A line segment's length can be calculated using either metric measurements like millimeters or centimeters, or conventional measurements like feet or inches.

Statement A: E and C are co-linear.

It is true, E and C are lie in same line

statement 2: Lines I and m intersect at point D.

It is false, I and m intersect at point E.

statement 3: AE and DC are line segments on line I

It is false,because AE and DC are line segments placed in different line.

statement 4: EA and EC are rays on the line m.​

It is true, as EA and EC are in same line m.

Thus, required true statements are 1 and 4.

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Answer:

1 and 4

Step-by-step explanation:

Given:

The quadratic function is:

[tex]f(x)=(x+2)^2+1[/tex]

To find:

The graph of the given quadratic function.

Solution:

The vertex form of a quadratic function is:

[tex]f(x)=a(x-h)^2+k[/tex]              ...(i)

Where, a is a constant and (h,k) is the vertex of the graph of the quadratic function.

We have,

[tex]f(x)=(x+2)^2+1[/tex]           ...(ii)

On comparing (i) and (ii), we get

[tex]a=1[/tex]

[tex]h=-2[/tex]

[tex]k=1[/tex]

Now,

[tex](h,k)=(-2,1)[/tex]

It means the vertex of the graph of the given function is at point (-2,1).

Only in graph C, the vertex of the parabola is at (-2,1).

Therefore, the correct option is C.

Answer:

its 28

Step-by-step explanation:

Answer:

The top second one :))

Step-by-step explanation:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 0

Answer:

I think it's 0.18 in decimal

Answer: It's 42

Since 48 + 90 = 138

And because every triangle equals 180 all you gotta do is add 42

The required simplified solution of the given expression is 8√3.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

here,
Given expression,
=  2 √ 3 + 2 √ 27

Since √27 = 3√3
= 2√3 + 2× 3√3
= √3 [2 + 6]
= √3[8]
= 8√3

Thus, the required simplified solution of the given expression is 8√3.

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By using the area of circle formula, the solution of the given problem of circle comes out to be 6 + π cm

Every location in the plane of a circle is equally separated from the center and is a closed, as double object. Each line tracing the circle contributes to the formation of a line of reflection symmetry. Additionally, each angle has axis of symmetry around the center.

Here,

A 9 Pi square centimeter circle's sector has a 60 degree center angle. The sector's exterior border is

Circle area is equal to. πR² = 9π

Circumference =2πR

=> 2π*3 = 6π cm

Arc length equals (60/360)*6 to cm

Arc's perimeter is calculated as follows: Radius + Length of Arc + Radius = π +3 + 3 = 6 +  π cm

Therefore , the solution of the given problem of circle comes out to be

6 + π cm.

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By using the area of circle formula and circumference of a circle formula, the solution of the given problem of circle comes out to be 12π cm

Every location in the plane of a circle is equally separated from the center and is a closed, as double object. Each line tracing the circle contributes to the formation of a line of reflection symmetry. Additionally, each angle has axis of symmetry around the center.

Here,

sector area of circle = 9π

arc measure = 90°

Area of sector  = (arc/360°)*πr²

⇒ 9π = (90°/360°)πr²

⇒ 9π = (1/4)πr²

⇒ 4*9π = πr²

⇒ 36 = r²

⇒ 6² = r²

r = 6

and Circumference of circle = 2πr

=> 2π*6 = 12π cm

Therefore , the solution of the given problem of circle comes out to be

12π cm.

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Answer:

The first one

Step-by-step explanation:

The figure shown is a rectangular pyramid

The volume of a rectangular pyramid can be calculated using the formula

[tex]V=\frac{1}{3} lwh[/tex]

where l = length of base, w = width of base and h = height

We have a given length of 6 in, a given width of 4 in and a given height of 8 in

That being said, we plug in the given values into the formula

[tex]V=\frac{1}{3} (6)(4)(8)[/tex]

This equation matches A therefore A is the answer

The average value of both f(x) and g(x) on 0≤x≤2 is 1/4. The average value of (f.g) on 0≤x≤2 is 0 and the statement avg(f) . avg(g) = avg(f . g) is false.

avg value of a function = 1/(b - a) ∫f(x) with limts a and b. Here a and b are the constraints under which the average has to be calculated.

a)

Hence average value of f(x) on 0≤x≤2

= 1/2 ∫f(x)  with 0 and 2 as intervals

Since integration is basically the area under the curve we get

avg of f(x) = 1/2[area under curve from 0 to 1 + Area under the curve from 1 to 2]

Since from 0 to 1, the figure is a triangle and beyond that a straight line we get

1/2[1/2 X 1 X 1 + 0]

= 1/4 sq units

b)

Similarly, the average value of g(x) on 0 ≤ x ≤ 2

1/2[area from 0 to 1 + area from 1 to 2]

= 1/2[0 + 1/2]

= 1/4 sq units

c) here we need to find the average of f(x) . g(x)

Here we see that f(x) is 0 from x = 1 to x = 1 while g(x) id 0 from x = 0 from x = 1

Hence we see that on multiplying the functions, the resultant has to be a 0 function.

Hence its average value will be 0.

d)

Average(f) . Average(g) = 1/4 X 1/4

= 1/16

Average of (f.g) = 0

Hence the statement is false

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Complete Question

The figure attached to the left is a graph of f(x), and below to the right is g(x).

The figure below to the left is a graph of f(x), a

(a) What is the average value of f(x) on 0≤x≤2? avg value = __________

(b) What is the average value of g(x) on 0≤x≤2? avg value = __________

(c) What is the average value of f(x) . g(x) on 0≤x≤2? avg value = _________

(d) Is the following statement true?

Average(f) . Average(g)=Average(f.g)

A. Yes

B. No

Given:

Number of pink bows = 6

Number of blue bows = 1

Number of purple bows = 3

Nataly will randomly choose 1 bow from the box.

To find:

The probability that the Nataly will choose a pink bow.

Solution:

The total number of bows is:

[tex]6+1+3=10[/tex]

The  total number of bows is the total outcomes.

Total outcomes = 10

The number of pink bows is the favorable outcomes.

Favorable outcomes = 6

We know that, the probability that the Nataly will choose a pink bow is

[tex]\text{Probability}=\dfrac{\text{Number of pink bows}}{\text{Total number of bows}}[/tex]

[tex]\text{Probability}=\dfrac{6}{10}[/tex]

[tex]\text{Probability}=0.6[/tex]

Therefore, the probability that Nataly will choose a pink bow is 0.6.

Answer:

If you want the improper fraction 43/8

If you want it in a decimal 5.375

Step-by-step explanation:

Answer:

5 3/8 or 5.375

Step-by-step explanation:

Assuming that your "and" means addition, 5 and 3/8 is

5 3/8 or 5.375

I would choose both I and II for accomplishing the task of "When you want to Add or Remove Filters, you select Data in the ribbon, and then Filter. You would prefer to do this with one click, so you decide to add Filters to the Quick Access Toolbar."

Click the Commands Not in the Ribbon option in the Customize Quick Access Toolbar dialog box. Click Filter in the list of commands. Select the Add option. Press the OK button. You may use the FILTER function to filter a set of data depending on criteria you provide. The Filter option makes it simple to narrow down your search field.

Here,

I would choose both I and II to complete the task of "When you wish to Add or Remove Filters, go to the Data ribbon, then Filter. You'd prefer to do this with a single click, so you add Filters to the Quick Access Toolbar."

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