How do I do number 3?

How Do I Do Number 3?

Answers

Answer 1

3.) The volume of the triangular prism = 6,480 mi³

The surface area of the triangular prism = 1,872mi²

How to calculate the surface area of the triangular prism?

To determine the surface area of the given triangular prism, the formula that should be used is given as follows:

Surface area = bH + (b1+b2+b3)×l

where ;

b= 8 mi

b1 = 18 mi

b2 = 24 mi

b3 = 30 mi

Height = 18 mi

length = 24 mi

Surface area = 8×18 + ( 18+24+30)× 24

= 144 + 1728

= 1,872mi²

To calculate the volume of a triangular prism, the formula the should be used is given as follows;

Volume = 1/2 × b× h × L

where;

b = 24 ni

h = 18 mi

l = 30 mi

volume = 1/2 ×24×18×30

= 6,480 mi³

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Related Questions

The base and all three faces of a triangle pyramid are equilateral triangles with side lengths of 3ft. the height of each triangle is 2.6ft. what are the lateral area and the total surface area of the triangular pyramid?

Answers

The lateral area of the triangular pyramid is 11.7 sq ft and the total surface area is 15.6 sq ft.

To find the lateral area and total surface area of the triangular pyramid with base and faces as equilateral triangles, we can follow these steps:

1: Find the area of one equilateral triangle.

To find the area of an equilateral triangle with side length 3 ft and height 2.6 ft, we can use the formula:

Area = (1/2) × base × height

Area = (1/2) × 3 × 2.6 = 3.9 sq ft

2: Calculate the lateral area.

Since the pyramid has three equilateral triangles as faces, we can multiply the area of one triangle by 3 to find the lateral area:

Lateral Area = 3 × 3.9 = 11.7 sq ft

3: Calculate the total surface area.

The total surface area includes both the lateral area and the base area. Since the base is also an equilateral triangle with the same dimensions, we can simply add the area of the base to the lateral area to find the total surface area:

Total Surface Area = Lateral Area + Base Area = 11.7 + 3.9 = 15.6 sq ft

In conclusion, the lateral area is 11.7 sq ft and the total surface area is 15.6 sq ft.

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Which statement is true considering a significance level of 5%?

A. The result is statistically significant, which implies that wearing a watch does not help people manage their time better.

B. The result is not statistically significant, which implies that this result could be due to random chance.

C. The result is statistically significant, which implies that wearing a watch helps people manage their time better.

D. The result is not statistically significant, which implies that wearing a watch does not help people manage their time better.

Answers

Given the scenerio in the picture about corn, the statement that is true looking at a significance level of 5% is The result is not statistically significant which implies that spraying the corn plants with the new type of fertilizer does increase the growth rate.

What is the does the 5% significance level mean in the context provided?

Looking at the statement "The result is not statistically significant,"this means that the p-value (probability value) of the test was greater than 0.05. It could have 0.15 oe 0.2.

When a test is greater than 0.05 or 5 % significance level, it shows that the what is happening to the corn (increase in growth rate) could have been as a result of chance alone.

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Prove that the value of the expression: (36^5−6^9)(38^9−38^8) is divisible by 30 and 37.


_x30x37

Don't answer if you don't know

Answers

To prove that the expression (36^5−6^9)(38^9−38^8) is divisible by 30, we need to show that it is divisible by both 2 and 3.

First, we can factor out a 6^9 from the first term:

(36^5−6^9)(38^9−38^8) = 6^9(6^10-36^5)(38^9-38^8)

Notice that 6^10 can be written as (2*3)^10, which is clearly divisible by both 2 and 3. Also, 36 is divisible by 3, so 36^5 is divisible by 3^5. Thus, we can write:

6^9(6^10-36^5) = 6^9(2^10*3^10 - 3^5*2^10) = 6^9*2^10*(3^10 - 3^5)

Since 2^10 is divisible by 2, and 3^10 - 3^5 is clearly divisible by 3, the whole expression is divisible by both 2 and 3, and therefore divisible by 30.

To prove that the expression is divisible by 37, we can use Fermat's Little Theorem. Fermat's Little Theorem states that if p is a prime number and a is any positive integer not divisible by p, then a^(p-1) is congruent to 1 modulo p, which can be written as a^(p-1) ≡ 1 (mod p).

In this case, p = 37, and 36 is not divisible by 37. Therefore, by Fermat's Little Theorem:

36^(37-1) ≡ 1 (mod 37)

Simplifying the exponent gives:

36^36 ≡ 1 (mod 37)

Similarly, 38 is not divisible by 37, so:

38^(37-1) ≡ 1 (mod 37)

Simplifying the exponent gives:

38^36 ≡ 1 (mod 37)

Now we can use these congruences to simplify our expression:

(36^5−6^9)(38^9−38^8) ≡ (-6^9)(-1) ≡ 6^9 (mod 37)

We know that 6^9 is divisible by 3, so we can write:

6^9 = 2^9*3^9

Since 2 and 37 are relatively prime, we can use Euler's Totient Theorem to simplify 2^9 (mod 37):

2^φ(37) ≡ 2^36 ≡ 1 (mod 37)

Therefore:

2^9 ≡ 2^9*1 ≡ 2^9*2^36 ≡ 2^(9+36) ≡ 2^45 (mod 37)

Now we can simplify our expression further:

6^9 ≡ 2^45*3^9 ≡ (2^5)^9*3^9 ≡ 32^9*3^9 (mod 37)

Notice that 32 is congruent to -5 modulo 37, since 32+5 = 37. Therefore:

32^9 ≡ (-5)^9 ≡ -5^9 ≡ -1953125 ≡ 2 (mod 37)

So:

6^9 ≡ 2*3^9 ≡ 2*19683 ≡ 39366 ≡ 0 (mod 37)

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Andrew went deep sea diving with some friends. If he descends at a rate of 4 feet per minute, what integer represents Andrews depth in ¼ of an hour?

Answers

The integer that represents Andrews depth in ¼ of an hour is 60 feet.

How to determine what integer represents Andrews depth in 1/4 of an hour?

Word problems are sentences describing a 'real-life' situation where a problem needs to be solved by way of a mathematical calculation e.g. calculation of length and depth.

If Andrew descends at a rate of 4 feet per minute and we want to find his depth in ¼ of an hour.

1/4 of an hour = (1/4 * 60) minutes = 15 minutes

Thus, the integer that represents Andrews depth in ¼ of an hour will be:

(4 feet per minute) * (15 minutes) = 60 feet

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A license plate is made of three letters and three numbers, how many different license plates are possible?

Answers

There are 17,576,000 different license plates possible, considering 26 letters (A-Z) and 10 numbers (0-9).

There are 26 options for each of the three letters and 10 options for each of the three numbers. Therefore, using the multiplication principle, the total number of possible license plates is 26 x 26 x 26 x 10 x 10 x 10 = 17,576,000.

Alternatively, we can use the permutation formula to calculate the number of arrangements: P(26,3) x P(10,3) = 15,600 x 720 = 11,251,200.

However, since order does not matter in a license plate, we need to divide by the number of permutations of three letters and three numbers, which is 3! x 3! = 36, resulting in 11,251,200 / 36 = 17,576,000 possible license plates.

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If Franco's Pizza Parlor knows that the marginal cost of the 500th pizza is $3.50 and that the average total cost of making 499 pizzas is $3.30, then
a. average total costs are falling at Q = 500.
b. average variable costs must be falling.
c. average total costs are rising at Q = 500.
d. total costs are falling at Q = 500.

Answers

If Franco's Pizza Parlor knows that the marginal cost of the 500th pizza is $3.50 and that the average total cost of making 499 pizzas is $3.30, then Average total costs are rising at Q = 500. The correct answer is (c)

The marginal cost is the additional cost of producing one more unit. In this case, the marginal cost of the 500th pizza is $3.50.

The average total cost is the total cost of producing all units up to a certain level, divided by the number of units produced. In this case, the average total cost of making 499 pizzas is $3.30.

If the marginal cost of producing the 500th pizza is greater than the average total cost of making the first 499 pizzas, then the average total cost will increase when the 500th pizza is produced.

Therefore, the correct answer is (c) average total costs are rising at Q = 500.

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For how many different integers $k$ are there rational solutions to the quadratic equation
[tex]\[x^2 + kx + 4k = 0?\][/tex]

Answers

For k = 0 and k = 16, there are rational solutions to the quadratic equation [tex]x^{2} + kx + 4k = 0[/tex]

We are given a quadratic equation [tex]x^{2} + kx + 4k = 0[/tex]

An algebraic equation in x with a degree of 2 is known as a quadratic equation. It is written in the format [tex]a[/tex][tex]x^{2}[/tex] [tex]+ bx + c[/tex] = 0. To find out whether there exists two solutions, one solution, or no solution for a quadratic equation, we use the discriminant of the quadratic equation.

We will find the solutions to this quadratic equation with the help of discriminant formula

As we know from the equation that b = k, a = 1, and c = 4k.

[tex]b^2 - 4ac = 0[/tex]

[tex]k^2 - 4(4k) = 0[/tex]

[tex]k^2 - 16k = 0[/tex]

k (k-16) = 0

k = 0    or    k - 16 = 0

k = 0    or    k = 16

So, for k = 0 or k = 16 the equation [tex]x^{2} + kx + 4k = 0[/tex] has only one solution.

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6 Which graph best represents a quadratic function with a range of all
real numbers greater than or equal to 3?
F
G
H
H
P
J

Answers

The fourth graph best represents a quadratic function with a range of all real numbers greater than or equal to 3

The graph that best represents a quadratic function with a range of all real numbers greater than or equal to 3 is a graph that opens upward and has a vertex at the point (h, k), where k is the minimum value of the function.

Since the range is all real numbers greater than or equal to 3, the minimum value occurs at or above 3.

Therefore, the vertex of the quadratic function lies on or above the horizontal line y = 3.

Hence, the fourth graph best represents a quadratic function with a range of all real numbers greater than or equal to 3

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pls help <3 Triangle QRS has side lengths q = 11, r = 17, and s = 23. What is the measure of angle R

a.44.5°
b.59.3°
c.27.0°
d.108.6

Answers

Using the cosine law, the measure of angle R is calculated as approximately: a. 44.5°.

How to Use the Cosine Law to Solve a Triangle?

The cosine law is expressed as follows:

cos R = [s² + q² – r²]/2sq

Given the following side lengths of triangle QRS:

Side q = 11,

Side r = 17,

Side s = 23.

Plug in the values into the cosine law formula:

cos R = [23² + 11² – 17²]/2 * 23 * 11

cos R = 361/506

Cos R = 0.7134

R = cos^(-1)(0.7134)

R ≈ 44.5°

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A company manufactures to types of cabinets, type 1 and type 2. It produces 110 total cabinet’s each week.

Last week, the number of type 2 cabinets produced exceeded twice the number of type 1 cabinets produced by 20. If x is the number of type 1 cabinets produced and y is the number of type 2 cabinets produced, the system of equations that represent this situation is x + y = 110 and y = 2x+20

The number of type 2 cabinets produced last week is ____. This number exceeds the number of type 1 cabinets produced durin the week by ______.

Answers

The number of type 2 cabinets produced last week is 80. The number of type 2 cabinets produced last week exceeded the number of type 1 cabinets produced during the week by 50.

Using the system of equations given, we can solve for the number of type 1 and type 2 cabinets produced.

x + y = 110 represents the total number of cabinets produced, where x is the number of type 1 cabinets and y is the number of type 2 cabinets produced.

y = 2x + 20 represents the relationship between the number of type 1 and type 2 cabinets produced. This equation tells us that the number of type 2 cabinets produced exceeds twice the number of type 1 cabinets produced by 20.

To solve for y, we substitute the value of y from the second equation into the first equation:

x + (2x + 20) = 110

Simplifying this equation:

3x + 20 = 110

3x = 90

x = 30

Therefore, the number of type 1 cabinets produced last week is 30.

To find the number of type 2 cabinets produced, we substitute x = 30 into the second equation:

y = 2x + 20 = 2(30) + 20 = 80

The number of type 2 cabinets produced last week exceeds the number of type 1 cabinets produced during the week by:

80 - 30 = 50.

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A peregrine falcon can dive at the speed of 320km/h. Create a problem that you can solve by finding an equivalent rate for this speed. Then solve the problem.

Answers

What is a peregrine falcon's maximum speed while diving to catch prey , in feet per second ? (Round your answer to the nearest whole number. 1 mile = 5280 feet )

A particle moves along the x-axis with velocity given by v(t) = 3t2 + 6t for time t ≥ 0. If the particle is at position x = 2 at time t = 0, what is the position of the particle at t = 1?

Answers

The position of the particle at time t = 1 is x = 4 units.

What is the position of a particle that moves along the x-axis with velocity v(t) = [tex]3t^2[/tex] + 6t at time t = 1 if it is at position x = 2 at time t = 0?

To find the position of the particle at time t = 1, we need to integrate the given velocity function v(t) with respect to time from 0 to 1:

x(t) = ∫v(t)dt (from t = 0 to t = 1)

= ∫([tex]3t^2[/tex]+ 6t)dt (from t = 0 to t = 1)

= ([tex]t^3 + 3t^2[/tex]) (from t = 0 to t = 1)

[tex]= (1^3 + 3(1^2)) - (0^3 + 3(0^2))[/tex]

= 4

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Use matrices A, B, C and D. A = Find CD a. 2 3 0 -5 b. 27 -29 -7 31.0 -384-1 2 6 -6 -6 4 -2 -27 18 -9 -12 8 -4 2 Mark this and return C = 9 and D= [-3 2 -1] C. Please select the best answer from the choices provided | ** - 16 24 -8 0 -40 32 Save and Evil​

Answers

The product of matrices C and D is:

[tex]CD = \left[\begin{array}{ccc}-6&18&-4\\\end{array}\right][/tex]

The best answer is option b.

How to find the product of two matrices?

A matrix (plural matrices) is a set of numbers arranged in rows and columns so as to form a rectangular array.

The number of rows of a matrix can be determined by counting from top to bottom and the number of columns can be determined by counting from left to right.

The product (multiplication) of matrices C and D is:

CD = C * D

[tex]CD = \left[\begin{array}{ccc}2\\9\\4\end{array}\right] * \left[\begin{array}{ccc}-3&2&-1\\\end{array}\right][/tex]

To get the product, multiply each row by the column. That is:

2 * (-3) = -6

9 * 2 = 18

4 * (-1) = -4

[tex]CD = \left[\begin{array}{ccc}-6&18&-4\\\end{array}\right][/tex]

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What is the mean absolute deviation of 10 10 9 8 10 5 6 4 8 4

Answers

The mean absolute deviation of the given data set is approximately 2.16.

To find the mean absolute deviation (MAD), we first need to calculate the mean of the data set:

Mean = (10 + 10 + 9 + 8 + 10 + 5 + 6 + 4 + 8 + 4) / 10 = 7.4

Next, we calculate the absolute deviation of each data point from the mean:

|10 - 7.4| = 2.6

|10 - 7.4| = 2.6

|9 - 7.4| = 1.6

|8 - 7.4| = 0.6

|10 - 7.4| = 2.6

|5 - 7.4| = 2.4

|6 - 7.4| = 1.4

|4 - 7.4| = 3.4

|8 - 7.4| = 0.6

|4 - 7.4| = 3.4

Then, we find the average of these absolute deviations:

MAD = (2.6 + 2.6 + 1.6 + 0.6 + 2.6 + 2.4 + 1.4 + 3.4 + 0.6 + 3.4) / 10 ≈ 2.16

Therefore, the mean absolute deviation of the given data set is approximately 2.16.

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Every line segment used to make this hospital logo is 3 meters long. What is the total area of the logo in square meters?

Answers

Without an image I can’t really tell the exact area of the logo but if I had to use this I formation only I would say maybe 13.5 square meters.

ruby can assemble 2 22 gift baskets by herself in 7 77 minutes. emma can assemble 4 44 gift baskets by herself in 15 1515 minutes. ruby begins assembling gift baskets at 1 : 00 p.m. 1:00p.m.1, colon, 00, start text, p, point, m, point, end text, and emma begins assembling gift baskets at 1 : 15 p.m. 1:15p.m.1, colon, 15, start text, p, point, m, point, end text if they continue to work at the above rates, at what time will they finish the 5 4 th 54 th 54, start superscript, start text, t, h, end text, end superscript basket?

Answers

Ruby and Emma can assemble one gift basket in 0.1818 minutes, together. They will finish the 54th basket at  7:27 PM.

To solve the problem, we first need to find how many gift baskets Ruby and Emma can assemble in one minute.

Ruby can assemble 2/22 = 1/11 gift basket in one minute.

Emma can assemble 4/44 = 1/11 gift basket in one minute.

Together, they can assemble 1/11 + 1/11 = 2/11 = 0.1818 (rounded to four decimal places) gift baskets in one minute.

To assemble the 54th gift basket, they need to assemble 53 gift baskets before that.

53 gift baskets / 0.1818 gift baskets per minute = 291.8181 minutes

Since they start at 1:00 p.m. and Emma starts 15 minutes later, they will finish 291.8181 minutes after 1:15 p.m., which is approximately 7:27 p.m.

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Help right now Asapppppp

Answers

The angles that belongs to the right angles category are:

∠KER∠ARE

What makes a right angle in a circle?

KER must be a right angle because it is an angle formed between a tangent (KE) and a radius (AK) at the point of tangency (K). By the Tangent-Secant Theorem, it follows that the measure of the intercepted arc KR is equal to the measure of the angle ∠KER plus 90 degrees. Since KR is a diameter (and therefore a semicircle), its measure is 180 degrees. Therefore, ∠KER + 90 = 180, which implies that ∠KER = 90 degrees.

∠ARE must be a right angle because it is an inscribed angle that intercepts the diameter KR. By the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of its intercepted arc. Since KR is a diameter, the intercepted arc is the entire circle, which has a measure of 360 degrees. Therefore, ∠ARE = 360/2 = 180 degrees. Moreover, a diameter and a chord that contains the diameter must form a right angle at the point where they meet (in this case, point A). Hence, ∠ARE is a right angle.

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Image transcribed:

The figure below shows a circle with center A, diameter KR, and secants RE and RI. Which of the angles must be right angles? Select all that apply.

Q

E

R

K

D

∠KIR

∠ARD

∠KER

∠ARE

∠ERI

Describe the end behavior of
f(x)= -x² -1

show steps

Answers

As the x-values go to either positive or negative infinity, the function decreases towards negative infinity.

Step 1: Identify the degree and leading coefficient.
In f(x) = -x² - 1, the degree is 2 (the highest power of x), and the leading coefficient is -1.
Step 2: Determine the end behavior based on the degree and leading coefficient.
Since the degree is even (2) and the leading coefficient is negative (-1), we know that both ends of the graph will point in the same direction.

Step 3: Identify the specific end behavior.
Because the leading coefficient is negative, the graph of the function will open downward. As x approaches positive infinity, f(x) will decrease towards negative infinity. Similarly, as x approaches negative infinity, f(x) will also decrease towards negative infinity.

Step 4: Write the end behavior in a concise format.
The end behavior of f(x) = -x² - 1 can be written as:
As x → ±∞, f(x) → -∞.
In summary, the function f(x) = -x² - 1 has a downward-opening parabola due to its even degree and negative leading coefficient.

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Help me please first correct answer get branliest and please no essay

Answers

Answer:

6cm

Step-by-step explanation:

all the sides of a square are identical so we can assume the missing side as x

since all four sides are the same and the perimeter is the sum of all sides, we can write

x+x+x+x=24cm

4x=24cm

x=24/4

x=6cm

Flo ate
3
2
of a sandwich and Arnie ate- of a sandwich. If Arnie ate more, what
3
must be true?
A Flo's sandwich is bigger.
B Arnie's sandwich is bigger.
C) The sandwiches are the same size.
D) It doesn't matter which sandwich is bigger.

Answers

Flo ate more of the sandwich than Arnie.

Option A is the correct answer.

We have,

We need to compare the values 3/4 and 2/3 to determine which fraction represents a larger amount of sandwiches eaten.

To make the fractions comparable, we need to find a common denominator.

The least common multiple of 4 and 3 is 12.

So we can rewrite 3/4 and 2/3 with 12 as the denominator:

3/4 = 9/12

2/3 = 8/12

Comparing these fractions, we see that 9/12 (or 3/4) is greater than 8/12

(or 2/3).

Therefore,

Flo ate more of the sandwich than Arnie.

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Find f'(4) for f(x) = ln (2x^3"). Answer as an exact fraction or round to at least 2 decimal places.

Answers

To find f'(4) for the function f(x) = ln(2x^3), we first need to find the derivative f'(x) using the chain rule.

The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.

For f(x) = ln(2x^3), the outer function is ln(u) and the inner function is u = 2x^3.

The derivative of the outer function, ln(u), is 1/u.
The derivative of the inner function, 2x^3, is 6x^2 (using the power rule).

Now, apply the chain rule: f'(x) = (1/u) * 6x^2 = (1/(2x^3)) * 6x^2.

Simplify f'(x): f'(x) = 6x^2 / (2x^3) = 3/x.

Now, find f'(4): f'(4) = 3/4.

So, f'(4) for f(x) = ln(2x^3) is 3/4 or 0.75 when rounded to 2 decimal places.

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In ΔVWX, w = 4.7 inches, v = 2.4 inches and ∠V=8°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answers

The value of W to the nearest tenth of degree is 15.8°

What is sine rule?

The sine rule states that if a, b and c are the lengths of the sides of a triangle, and A, B and C are the angles in the triangle; with A opposite a, etc., then a/sinA=b/sinB=c/sinC.

Sine rule can be used to find unknown side or angle In a triangle.

w/sinW = v/sinV

4.7/sinW = 2.4 / sin8

2.4sinW = 4.7 sin8

2.4sinW = 0.654

sinW = 0.654/2.4

sinW = 0.273

W = sin^-1( 0.273)

W = 15.8° ( nearest tenth)

therefore the value of W is 15.8°

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a gambler is going to play a gambling game. in each game, the chance of winning $3 is 2/10, the chance of losing $2 is 3/10, and the chance of losing $1 is 5/10. suppose the gambler is going to play the game 5 times. (a) write down the box model for keeping track of the net gain. (you already did this in a previous lab.) (b) now write down the box model for keeping track of the number of winning plays. (c) calculate the expected value and standard error for the number of winning plays. (d) would it be appropriate to use the normal approximation for the number of winning plays? why or why not?

Answers

The  expected value and standard error for the number of winning plays is $3.1 and $ 2.21.

The population mean's likelihood to differ from a sample mean is indicated by the standard error of a mean, and simply standard error.

It reveals how much what the sample mean will change if a study were to be repeated with fresh samples drawn from a single population.

Chance of winning $3 = 2/10

chance of losing $2 = 3/10

chance of losing $1 = 5/10

Average of tickets. = - $2.50

SD of tickets = $1.80.

The box model for net gain has 2 tickets labeled $3, 3 tickets labeled $2, 5 tickets labeled

a) Expected value for the net gain.

The Expected value for net = ∑ x.p(x)

Here

can take value $1, $2 and $3

Here p(x) us the probability of winning respectively.

So, Now, Expected gain is,

(2 x 3 x 2/10) + (3 x -2 x 7/10) + (5 x -1 x 5/10)

= 12/10 - 18/10 - 25/10

= -31/10 = -$3.1.

b) Standard error of the net gain,

S.D = [tex]\sqrt{E(x^2) - [E(x)]^2}[/tex]

Now E(x²) = (2 x 3² x 2/10) + (3 x -2² x 7/10) + (5 x -1² x 5/10)

= 36/10 + 84/10 + 25/10 = 145/10

= $ 14.5

SD = [tex]\sqrt{14.5 - 3.1}\\[/tex]

SD = $ 2.21

c) Chance that the net gain is $15

P(X=15) = (z = 15-(-2.50)/1.80

= P(z=9.72) = 0.99.

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Solve for x WILL MAKE BRAINLIEST QUESTION IN PHOTI ALSO

Answers

The measure of x in the intersected chord is 16.

How to find the angle in an intersected chord?

If two chords intersect in a circle, then the measure of the angle formed is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle.

Using the chord intersection angle theorem,

5x - 7  = 1 / 2 (119 + 27)

5x - 7 = 1 / 2 (146)

5x - 7 = 73

add 7 to both sides of the equation

5x - 7 = 73

5x - 7 + 7 = 73 + 7

5x = 80

divide both sides of the equation by  5

x = 80 / 5

x = 16

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Find an angle in each quadrant with a common reference angle with 306°, from 0°≤θ<360°

Answers

The angle in each quadrant with a common reference angle with 306° are

Quadrant 1 is 126°Quadrant 2 is 54°Quadrant 3 is  306°Quadrant 4 is 234°

To find angles in each quadrant with a common reference angle with 306°, we first need to determine the reference angle for 306°.

Reference angle is the acute angle between the terminal side of an angle and the x-axis. We can find the reference angle for any angle θ by subtracting the nearest multiple of 180° from θ and taking the absolute value of the result. In this case:

|306° - 180°| = 126°

So, the reference angle for 306° is 126°.

Now, we can find an angle in each quadrant with a common reference angle of 126°:

1st quadrant: The angle with a reference angle of 126° in the 1st quadrant is simply 126°.

2nd quadrant: To find the angle with a reference angle of 126° in the 2nd quadrant, we need to subtract the reference angle from 180° (since all angles in the 2nd quadrant are between 90° and 180°).

180° - 126° = 54°

So, an angle with a reference angle of 126° in the 2nd quadrant is 54°.

3rd quadrant: To find the angle with a reference angle of 126° in the 3rd quadrant, we need to subtract the reference angle from 180° and then add 180° (since all angles in the 3rd quadrant are between 180° and 270°).

180° + 126° = 306°

So, an angle with a reference angle of 126° in the 3rd quadrant is 306°.

4th quadrant: To find the angle with a reference angle of 126° in the 4th quadrant, we need to subtract the reference angle from 360° (since all angles in the 4th quadrant are between 270° and 360°).

360° - 126° = 234°

So, an angle with a reference angle of 126° in the 4th quadrant is 234°.

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Find the t value that forms the boundary of the critical region in the right-hand tail for a one-tailded test with o=. 01 for each of the folling sample size n=10

Answers

The t critical value at 29 degrees of freedom and 0.01 level of significance is 2. 46

How to calculate the value

Using Critical value calculator we calculate the values.

a) at n = 10

Therefore degrees of freedom is = n - 1= 9, So therefore at 9 degrees of freedom and 0.01 level of significance, t critical value is 2.82

b) at n= 20

Degrees of freedom is 19.

The t critical value at 19 degrees of freedom and 0.01 level of significance is 2.54

c) at n = 30

Degrees of freedom is 29.

So therefore t critical value at 29 degrees of freedom and 0.01 level of significance is 2. 46

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Solve each system by substitution
Y=-2x+4
y=-3x+3

Answers

Answer: x = -1, y = 6

Step-by-step explanation:

lets substitute the value of y from the first equation into the y in the second equation.

-2x + 4 = -3x + 3

4 - 3 = -3x + 2x

1 = -1x

x = -1

we know from before that y = -2x + 4

so y = -2(-1) + 4

y = 6

What’s the answer? I need help please

Answers

Since $\triangle KLM$ is a right triangle, we can use the Pythagorean Theorem to find the length of $KM$:
\[KM = \sqrt{KL^2 + LM^2} = \sqrt{8^2 + 6^2} = \sqrt{64+36} = \sqrt{100} = 10.\]
Now we can use the definition of sine:
\[\sin \angle M = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{LM}{KM} = \frac{6}{10} = \boxed{\textbf{(A)}\ \frac{10}{12}}.\]

Answer:  10/12

Step-by-step explanation:

since they give you adjacent to angle m and hypotenuse use

cos x = opp/hyp

cos M = 10/12

Find an angle \thetaθ coterminal to -497^{\circ}−497 ∘

, where 0^{\circ}\le\theta<360^{\circ}0 ∘

≤θ<360 ∘

Answers

The correct answer for an angle coterminal to -497° within the interval 0°≤θ≤360° is 223°.

What are Coterminal angles?

Coterminal angles are angles that share the same initial and terminal sides when drawn in the standard position (starting from the positive x-axis) on the coordinate plane. In other words, coterminal angles are angles that differ by an integer multiple of 360° or 2π radians.

To find an angle coterminal to within the interval use the fact that to add or subtract a multiple of to an angle does not change its position on the unit circle.

To make the angle positive, add  360°  repeatedly until an angle within the desired interval is obtained:

= -497° +360°

= -137°

adjust this angle to be within the interval 0°≤θ≤360°, and add another 360°:

= -137° + 360°

= 223°

The required angle is 223°.

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An angle θ coterminal to -497 degrees, where 0 ≤ θ < 360 degrees, is 223 degrees.

Given that; the angle is, -497 degrees.

Now, for an angle coterminal to -497 degrees within the range 0≤θ<360 degrees, add or subtract multiples of 360 degrees until we get an angle within the desired range.

Now, add multiples of 360 degrees until we get a positive angle:

-497 + 360 = -137

Now we have an angle of - 137 degrees, but it is still not within the desired range of 0 ≤ θ < 360 degrees.

To adjust the angle, add 360 degrees to it:

-137 + 360 = 223

Now an angle of 223 degrees, which is within the desired range.

Therefore, an angle θ coterminal to -497 degrees, where 0 ≤ θ < 360 degrees, is 223 degrees.

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Laura is driving to Los Angeles. Suppose that the remaining distance to drive (in miles) is a linear function of her driving time (in minutes). When graphed, the function gives a line with a slope of -0.85. See the figure below. Laura has 52 miles remaining after 41 minutes of driving. How many miles were remaining after 33 minutes of driving?

Answers

The remaining distance after 33 minutes of driving = 58.8 miles.

Here, the slope of a linear function the remaining distance to drive (in miles) is -0.85

For this situation, we can write a linear equation as,

remaining distance = (slope)(drive time) + (intercept)

remaining distance = -0.85(drive time) + (intercept)      

y =  -0.85x + c        ..........(1)

where y represents the remaining distance

x is the drive time

and c is the y-intercept

Here, Laura has 52 miles remaining after 41 minutes of driving.

i.e., x = 41 and y = 52

Substitute these values in equation (1)

52 =  -0.85(41) + c    

c = 52 + 34.85

c = 86.85

So, equation (1) becomes,

y =  -0.85x + 86.85

Now, we need to find the remaining distance after 33 minutes of driving.

i.e., the value of y for x = 33

y =  -0.85(33) + 86.85

y =  -28.05 + 86.85        

y = 58.8

This is the remaining distance 58.8 miles.

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