Answer:
Explanation:
According to the Law of Conservation of Mass, matter cannot be created or destroyed in a chemical reaction. Therefore, the mass of the reactants must be equal to the mass of the products.
If 15 grams of reactant went into the reaction, then the mass of the products formed must also be 15 grams. This assumes that the reaction is complete and no reactants are left unreacted.
It is important to note that this applies to closed systems where there is no loss or gain of mass. In real-world situations, some mass may be lost due to factors such as evaporation or incomplete reactions, which can affect the accuracy of the calculations.
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Benzoic acid (C6H5COOH) and aniline (C6H5NH2) are both derivatives of benzene. Benzoic acid is an acid with Ka=6.3×10^(−5) and aniline is a base with Kb=4.3×10^(−10) .What is the value of the equilibrium constant for the following equilibrium? C6H5COOH(aq)+C6H5NH2(aq)⇌C6H5COO−(aq)+C6H5NH3+(aq)
i want an accurate answer
The reaction C₆H₅COOH(aq) + C₆H₅NH₂(aq) ⇌ C₆H₅COO⁻(aq) + C₆H₅NH₃⁺(aq) has an equilibrium constant of 0.3698.
How to determine equilibrium constant?The equilibrium constant (Kb) for the reaction can be calculated using the Ka and Kb values of the reactants and the equation:
Kw = Ka x Kb
where Kw = ion product constant of water (1.0 x 10⁻¹⁴ at 25°C).
Calculate the Kb value for aniline:
Kb = Kw/Ka = (1.0 x 10⁻¹⁴)/(4.3 x 10⁻¹⁰) = 2.33 x 10⁻⁵
Use the Kb value for aniline and the Ka value for benzoic acid to calculate the equilibrium constant (K) for the reaction:
K = Kb/Ka = (2.33 x 10⁻⁵)/(6.3 x 10⁻⁵) = 0.3698
Therefore, the equilibrium constant for the reaction C₆H₅COOH(aq) + C₆H₅NH₂(aq) ⇌ C₆H₅COO⁻(aq) + C₆H₅NH₃⁺(aq) is 0.3698.
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2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)
If 538 mol
of octane combusts, what volume of carbon dioxide is produced at 31.0 ∘C
and 0.995 atm?
The volume of the carbon dioxide is produced at the 31.0 °C and the 0.995 atm is 119,786 L.
The number of moles of octane = 538 mol
The moles of carbon dioxide = 4888 mol
The temperature of the gas = 31.0 °C
The pressure of the gas = 0.995 atm
The volume of the gas = ?
The ideal gas equation is :
P V = n R T
Where,
The p is the pressure = 0.995 atm
The V is the volume = ?
The n is moles of gas = 4888 mol
The R is gas constant = 0.823 atm L / mol K
The T is temperature = 31 + 273 = 304 K
V = n R T / P
V = ( 4888 mol × 0.0823 × 304 ) / 0.995
V = 119,786 L
The volume is 119,786 L.
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Suppose 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter. The final temperature of the water and copper calorimeter is 18.0C.
1) What was the initial common temperature of the water and copper? (Express your answer to three significant figures.)
The intital common temperature of copper and water is 9.5°C, under the condition that 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter.
Now to evaluate the initial common temperature of the water and copper calorimeter, we have to apply the formula
m1c1(Tk - Ti) + m2c2(Tk - Ti)
= mcopperccopper(Tk - Ti)
Here,
m1 = mass of water,
c1 =specific heat capacity of water,
m2 = mass of copper calorimeter,
c2 = specific heat capacity of copper calorimeter, mcopper = mass of copper block
ccopper =specific heat capacity of copper.
Here, this equation to evaluate Ti
Ti = (m1c1Tk + m2c2Tk - mcopperccopperTk - m1c1Ti - m2c2Ti) / (m1c1 + m2c2 - mcopperccopper)
Staging the given values into this equation
Ti = (-300.0 g)(4.18 J/g°C)(18.0°C) + (200.0 g)(0.385 J/g°C)(18.0°C) + (10.0 g)(0.385 J/g°C)(18.0°C) / [(300.0 g)(4.18 J/g°C) + (200.0 g)(0.385 J/g°C) - (10.0 g)(0.385 J/g°C)]
Ti = 9.5°C
Hence, the initial common temperature of the water and copper calorimeter was 9.5°C.
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If 12.5 mol
of an ideal gas occupies 50.5 L
at 69.00 ∘C,
what is the pressure of the gas?
The pressure of a gas that occupies 50.5L at 69.0°C is 6.95 atm.
How to calculate pressure?The pressure of an ideal gas can be calculated using Avogadro's equation as follows;
PV = nRT
Where;
P = pressureV = volume n = no of molesT = temperatureR = gas law constantAccording to this question, 12.5 mol of an ideal gas occupies 50.5 L at 69.00°C. The pressure can be calculated as follows:
P × 50.5 = 12.5 × 0.0821 × 342
50.5P = 350.9775
P = 6.95 atm
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A 250.0-mL flask contains 0.2500 g of a volatile oxide of nitrogen. The pressure in the flask is 760.0 mmHg at 17.00°C. How many moles of gas are in the flask?
Answer:
0.0104 moles of gas in the flask.
Explanation:
To calculate the number of moles of gas in the flask, you can use the ideal gas law equation: PV = nRT. Where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant and T is temperature.
First, you need to convert the pressure from mmHg to atm and the temperature from Celsius to Kelvin. The pressure in atm is 760.0 mmHg / 760 mmHg/atm = 1 atm. The temperature in Kelvin is 17.00°C + 273.15 = 290.15 K.
Next, you need to convert the volume from mL to L. The volume in L is 250.0 mL / 1000 mL/L = 0.2500 L.
Now you can plug all the values into the ideal gas law equation and solve for n: (1 atm)(0.2500 L) = n(0.08206 L·atm/mol·K)(290.15 K). Solving for n gives n = 0.0104 mol.
So there are approximately 0.0104 moles of gas in the flask.
How are models used in chemistry? How does evidence change these models?
Answer: As they develop theories, chemists use models to attempt to explain their findings. Chemists assess the model they are using as new evidence becomes available and, if required, continue to refine it by making modifications.
Explanation:
What is the S-P difference (sec)?
What is the amplitude (mm)?
What isthe distance (km)?
What is the magnitude (M)?
The S-P difference (sec) is the time gap between the arrival of the S-wave and the arrival of the P-wave at a seismic station. The S-P discrepancy is depicted in the figure as 20 seconds.
The amplitude (mm) of a seismic wave is the largest displacement from its resting point. The amplitude of the waves is not depicted in the image and cannot be calculated based on the information provided.
Distance (km): Using the S-P time difference and the known velocity of seismic waves, the distance from the seismic station to the earthquake epicenter may be determined. Seismic wave velocity is determined by the type of wave and the features of the Earth's interior. The velocity of P-waves in the Earth's crust, for example, is around 6 km/s. We may compute the distance to the epicenter using this value and the S-P difference of 20 seconds as follows:
Distance = Speed x Time = 6 km/h x 20 seconds = 120 kilometres
As a result, the distance between the seismic station and the earthquake epicenter is about 120 km.
The magnitude of an earthquake (M) is a measurement of the energy generated by the earthquake based on the amplitude of the seismic waves and the distance to the epicenter. Magnitude is commonly measured on a logarithmic scale, with each whole number reflecting a factor of ten increase in energy release.
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7 Suppose you weighed a different sample, of 2.500-g, which consisted of a mixture of CuO and potassium chloride and dissolved it in 25.00 mL of 0.437 M H₂SO4 solution. Some acid remains after treatment of the sample. Determine: a) If 35.4-mL of 0.108 M NaOH were required to titrate the excess sulfuric acid, how (6) many moles of CuO were present in the original sample?
The initial sample had 0.010925 mol of Copper(II) oxide, or one mole.
What exactly is kinetic-molecular theory?The kinetic-molecular theory, which describes the states of matter, is based on the presumption that matter is composed of minuscule particles that are constantly in motion. This theory explains the observable properties and behaviours of solids, liquids, and gases. The container's walls and the quickly moving particles' collisions with one another are constant.
Copper(II) oxide + Sulfuric acid → Cupric sulfate + Water
One mole of Copper(II) oxide interacts with one mole of Sulfuric acid, as shown by the equation. The amount of Sulfuric acid that reacted with the Copper(II) oxide in the sample is therefore equal to the amount of Copper(II) oxide in the sample.
We must first determine how many moles of Sulfuric acid interacted with the sample:
moles Sulfuric acid = concentration × volume
moles Sulfuric acid = 0.437 mol/L × 0.025 L
moles Sulfuric acid = 0.010925 mol
Since the acid is in excess, the moles of Sulfuric acid remaining after treatment of the sample is:
moles Sulfuric acid remaining = moles Sulfuric acid added – moles Sulfuric acid reacted
moles Sulfuric acid remaining = 0.437 mol/L × 0.0354 L – 0.010925 mol
moles Sulfuric acid remaining = 0.007571 mol
To determine the number of moles of Copper(II) oxide in the original sample, we can use the following equation:
moles Copper(II) oxide = moles Sulfuric acid reacted = 0.010925 mol
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Question 7 of 10
Which variable is unknown until the experiment is performed?
O A. A responding variable
OB. A mathematical variable
OC. A controlled variable
OD. A manipulated variable
SUBI
The mathematical variable is not a standard term in experimental design and is not typically used to describe variables in scientific experiments.
The variable that is unknown until the experiment is performed is typically the responding variable.
The responding variable is the variable that is observed and measured during the experiment, and its value changes in response to the manipulated variable. In contrast, the manipulated variable is the variable that is intentionally changed by the researcher to observe its effect on the responding variable.
The controlled variable is the variable that is kept constant throughout the experiment to ensure that any changes in the responding variable are due to the manipulated variable and not due to other factors. The mathematical variable is not a standard term in experimental design and is not typically used to describe variables in scientific experiments.
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For the Li2 molecule, rank order the following orbitals from lowest to highest energy: 1s, 2s, σ2s, σ*2s
The order of the energy levels for the Li2 molecule is:
1s < σ2s < 2s < σ*2s
The 1s orbital is the lowest in energy because it is closest to the nucleus and has the highest electron density. The σ2s orbital is next in energy because it is a bonding orbital that is formed by the overlap of two atomic 2s orbitals. The 2s orbital is higher in energy than the σ2s orbital because it is an atomic orbital that has not participated in bonding. The σ*2s orbital is the highest in energy because it is an antibonding orbital that weakens the bond between the two Li atoms.
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If 50 joules of energy is added to sample of water, the temperature will?
Explanation:
The temperature change of a substance when it absorbs or loses energy can be calculated using the specific heat capacity of the substance. The specific heat capacity of water is approximately 4.18 J/(g°C), which means that it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
To calculate the temperature change of the water sample when 50 joules of energy is added, we need to use the following equation:
q = m * c * ΔT
where q is the amount of energy absorbed by the water, m is the mass of the water sample, c is the specific heat capacity of water, and ΔT is the resulting temperature change.
Rearranging the equation to solve for ΔT, we get:
ΔT = q / (m * c)
Plugging in the values, we get:
ΔT = 50 J / (m * 4.18 J/(g°C))
We need to know the mass of the water sample to calculate the temperature change. Let's assume a mass of 10 grams:
ΔT = 50 J / (10 g * 4.18 J/(g°C))
ΔT = 1.2°C
Therefore, if 50 joules of energy is added to a 10-gram sample of water, the resulting temperature change will be approximately 1.2 degrees Celsius.
All changes save
3. Litharge, Pb0, is an ore that can be roasted (heated) in the presence of carbon monoxide, CO, to produce elemental lead. The
reaction that takes place during this roasting process is represented by the balanced equation below.
PbO(s) + CO(g) → Pb(s) + CO₂(g)
In which compound does carbon have the greater oxidation number
Answer:
Explanation:
In the given reaction, carbon has a greater oxidation number in carbon dioxide (CO₂) than in carbon monoxide (CO). In CO₂, the oxidation number of carbon is +4, while in CO it is +2.
If heat is going INTO the system, that means that energy must have come OUT FROM the ____________
If heat is going into a system, it means that energy must have come out from the surroundings.
How is energy/heat transferred?Heat is a form of energy transfer from a hotter object to a cooler one, and the direction of heat flow is always from the hotter object to the cooler one.
Therefore, if heat is entering a system, it must be gaining energy from its surroundings, which are at a lower temperature and therefore have less thermal energy.
Conversely, if heat is leaving a system, it means that energy is being transferred from the system to its surroundings, which are at a higher temperature and therefore have more thermal energy.
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If you mix 30 mL of cold water with 70 mL of hot water in a calorimeter, then calculate that the cold water gained 142 J of heat and the hot water lost 181 J of heat, and the temperature change of the cold water (and calorimeter) was an increase in 1.93°C, then what is the heat capacity of the calorimeter in J/°C (only enter the number, not units, and assume that no heat was lost to the environment around the calorimeter, assume the density of water to be 1.00g/mL and specific heat capacity of water to be 4.184 J/g-°C)?
First, we need to calculate the heat gained by the cold water and the heat lost by the hot water:
Qcold = mcΔT = (30 g)(4.184 J/g-°C)(1.93°C) = 242.06 J
Qhot = mcΔT = (70 g)(4.184 J/g-°C)(-1.93°C) = -546.53 J
Since energy is conserved, we can assume that the heat gained by the cold water and calorimeter is equal to the heat lost by the hot water:
Qcold + Qcalorimeter = Qhot
Qcalorimeter = Qhot - Qcold
Qcalorimeter = -546.53 J - 242.06 J = -788.59 J
Therefore, the heat capacity of the calorimeter can be calculated as:
Ccalorimeter = Qcalorimeter / ΔT
Ccalorimeter = (-788.59 J) / (1.93°C)
Ccalorimeter ≈ -408.4 J/°C
Note that the negative sign indicates that the calorimeter loses heat when the system gains heat, which is expected since the calorimeter is absorbing some of the heat from the hot water.
Please help me with this chemistry investigation I need answers as soon as possible please
B. To plot the data on a bar chart, draw a horizontal axis for metals and a vertical axis for time to complete the reaction. Then, draw bars for each metal that represent the amount of time required to complete the reaction. The height of the bars must match the time values in the table.
C. No, Emilia was not correct in her forecast. According to the data, aluminum reacted 100 seconds faster than magnesium, which reacted in 50 seconds. Thus aluminum reacts more rapidly with hydrochloric acid than magnesium.
From most reactive to least reactive, the metals are as follows:
aluminummagnesiumZincIronThis order is consistent with the reactivity series, which is:
PotassiumSodiumCalciumMagnesiumAluminiumZincIronCopperSilverGoldWe are unable to estimate the reactivity of potassium, sodium, calcium, copper, silver, or gold from this experiment because those variables are not present in the data.
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NaOH is the limiting reactant, producing
2.0 mol Na3PO4. What mass of
Na3PO4 forms during the reaction?
Na3PO4: 164 g/mol
[?] g Na3PO4
Report your answer to two significant figures.
g Na PO
4
Enter
The mass of Na₃PO₄ formed during the reaction is 328 g.
The balanced chemical equation for the reaction is:
[tex]3NaOH + Na_3PO_4 - > 3Na_2PO_4 + H_2O[/tex]
From the equation, we can see that 3 moles of NaOH produce 1 mole of Na₃PO₄.
Given that 2.0 moles of Na₃PO₄ is produced, we can set up a proportion to find the amount of NaOH required:
3 mol NaOH / 1 mol Na₃PO₄ = x mol NaOH / 2.0 mol Na3PO4
Solving for x, we get:
x = (3 mol NaOH / 1 mol Na₃PO₄) × (2.0 mol Na₃PO₄ / 1) = 6.0 mol NaOH
So, 6.0 moles of NaOH are required to produce 2.0 moles of Na₃PO₄.
To find the mass of Na₃PO₄ produced, we can use its molar mass:
mass = moles × molar mass = 2.0 mol × 164 g/mol = 328 g
Therefore, the mass of Na₃PO₄ formed during the reaction is 328 g.
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A platinum ring is composed of 2.35×1023 atoms. Calculate the mass of the ring in grams.
The mass of the platinum ring is 76.0 grams.
To calculate the mass of the platinum ringWe need to know the molar mass of platinum and the number of platinum atoms in the ring.
The molar mass of platinum (Pt) is 195.08 g/mol.
The number of platinum atoms in the ring is 2.35×10^23.
Now we can use the following formula to calculate the mass of the ring:
mass = (number of atoms) x (atomic mass) / Avogadro's number
where Avogadro's number is 6.022 x 10^23 mol^-1.
Substituting the values:
mass = (2.35×10^23 atoms) x (195.08 g/mol) / (6.022 x 10^23 mol^-1)
mass = 76.0 g
Therefore, the mass of the platinum ring is 76.0 grams.
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Will we ever send humans to another planet? Most believe that if we were to travel to another planet, Mars would be the best option. Which of these would be a potential problem associated with travel to another planet?
Question 1 options:
we already know everything about Mars
no astronauts would ever volunteer for this mission
Mars has such a high gravity that it would crush humans and our spacecraft
the extended time for humans to be in space
A potential problem associated with travel to another planet is : the extended time for humans to be in space.
What is the potential problem associated with travel to another planet?It is highly likely that humans will travel to another planet, and Mars is currently considered the most viable option for human exploration. However, there are many potential problems associated with this endeavor, and one of the major issues is the extended time that humans would need to spend in space.
Traveling to Mars would take several months, and once there, astronauts would need to spend significant amount of time on planet before returning to Earth. This means that they would be exposed to high levels of radiation and would need to find ways to survive in harsh and unforgiving environment.
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Calculate the energy difference (deltaE, in Joules) of an electron's transition from n = 6 to n = 1 in a hydrogen atom.
The energy difference of an electron's transition from n = 6 to n = 1 in a hydrogen atom is approximately -2.17 × 10⁻¹⁸ Joules.
To calculate the energy difference (deltaE) of an electron's transition from n = 6 to n = 1 in a hydrogen atom, we can use the following equation:
deltaE = -13.6 * (1/n_final^2 - 1/n_initial^2) eV
where n_initial is the initial energy level (6 in this case), n_final is the final energy level (1 in this case), and -13.6 eV is the ionization energy of hydrogen.
Converting eV to Joules, we get:
1 eV = 1.602 x 10^-19 J
Therefore, deltaE in Joules can be calculated as follows:
deltaE = -13.6 * (1/1^2 - 1/6^2) * 1.602 x 10^-19 J/eV
deltaE = -2.179 x 10^-18 J
Therefore, the energy difference (deltaE) of an electron's transition from n = 6 to n = 1 in a hydrogen atom is -2.179 x 10^-18 J.
To calculate the energy difference (ΔE) for an electron's transition from n = 6 to n = 1 in a hydrogen atom, you can use the following formula:
ΔE = -13.6 eV * (1/nf² - 1/ni²)
Where ΔE is the energy difference in electron volts (eV), nf is the final energy level (1 in this case), and ni is the initial energy level (6 in this case).
ΔE = -13.6 eV * (1/1² - 1/6²)
ΔE ≈ -13.56 eV
Now convert electron volts to Joules:
1 eV = 1.6 × 10⁻¹⁹ J
ΔE ≈ -13.56 eV * 1.6 × 10⁻¹⁹ J/eV
ΔE ≈ -2.17 × 10⁻¹⁸ J
So, approximately -2.17 × 10⁻¹⁸ Joules is the energy difference of an electron's transition from n = 6 to n = 1 in a hydrogen atom.
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Balloons for a New Years Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 c and then hung outside. what is the volume of the balloon once they have cooled to the outside temperature of -34.0 c?
The volume of the balloon once they have cooled to the outside temperature of -34.0 c is 1.53 L.
Charles' law predicts the relationship between the volumes and the temperatures of a sample of an ideal gas at different conditions. For this equation to hold true, the number of molecules and the pressure must remain constant despite changes in the environment.
Determine the volume of the balloon outside, V2. We do this by applying Charles' law, such that we relate the volume, V, and the temperature, T, of a sample of gas as
V₁ /T₁ = V₂/ T₂
at two conditions. We are given the following values for the variables:
• V₁ = 1.90 L
T₁ = 22.0+ 273.15 = 295.15 K
T₂= 34.0+273.15= 239.15 K
We proceed with the solution.
V₁/T₁ = V₂/T₂
V₁ /T₁ × T₂ = V₂
1.90 L/295.15 K x 239.15 K = V₂
1.53 L =V₂
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The complete question is
Balloons for a New Year's Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 degrees Celsius and then hung outside where the temperature is -34.0 degrees Celsius. What is the volume of the balloons after they have cooled to the outside temperature? Assume that atmospheric pressure inside and outside the house is the same.
A solution contains 0.0400 M Ca2+ and 0.0990 M Ag+. If solid Na3PO4 is added to this mixture, which of the phosphate species would precipitate out of solution first? Ca3(PO4)2
Ag3PO4
Na3PO4
When the second cation just starts to precipitate, what percentage of the first cation remains in solution?
When the second cation first starts to precipitate, 80.8% of Ca²⁺ will still be in solution.
What is cation?A cation is an ion with a positive charge. It is formed when an atom loses one or more of its electrons, resulting in a net positive charge. Cations are attracted to anions (ions with a negative charge) due to their opposite charges. Cations are found in many different substances, including acids, bases, and salts.
Ca₃(PO₄)₂ will be the first species that separates out of solution when solid Na₃PO₄ is introduced to the mixture. This is due to Ca3(PO4)2 having a substantially lower solubility than Ag₃PO₄ and Na₃PO₄.
The proportion of the first cation (Ca²⁺ ) still in solution when the second cation (Ag⁺) is just beginning to precipitate will depend on the starting concentrations of the two cations. In this instance, the starting concentrations of Ca²⁺ and Ag⁺ are 0.0400 M and 0.0990 M, respectively. Therefore, 80.8% of Ca²⁺ will still be in solution when its second cation first begins to precipitate.
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If the amount of solute present in a solution at a given temperature is less than the maximum amount that can be dissolved at that tempature the solution is said to be
Answer:
Unsaturated
Explanation:
A solution is unsaturated when it contains less than the maximum amount of solute that is capable of being dissolved.
Can someone please help me with chemistry?
Show steps! Thank you
a. The mass of Cr2O3 is 0.559 g Cr2O3 is the maximum amount of Cr2O3 produced.
b.The limiting reactant is Cr(NO3)3 because it produces less moles of Cr2O3 than Na2O.
c. The percent yield is 84%.
How do we calculate?The balanced equation is shown below:
2 Cr(NO3)3 + 3 Na2O → Cr2O3 + 6 NaNO3
moles of Cr(NO3)3 = 1.75 g / 238.01 g/mol = 0.00735 mol
moles of Na2O = 1.75 g / 61.98 g/mol = 0.0282 mol
moles of Cr2O3 = (0.00735 mol Cr(NO3)3) × (1 mol Cr2O3 / 2 mol Cr(NO3)3) = 0.00368 mol Cr2O3 (theoretical yield)
mass of Cr2O3 = (0.00368 mol Cr2O3) × (151.99 g/mol) = 0.559 g Cr2O3
The percent yield can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100%:
percent yield = (actual yield / theoretical yield) × 100%
percent yield = (0.455 g / 0.559 g) × 100% = 81.4%
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1. Which is an example of heat being transferred through conduction?
2. 6 C (s) + 3 H2 → C6H12 (l)
ΔH = -903
Therefore, this reaction (loses/gains) heat/energy.
Answer:
9. B
10. Loses
Explanation:
9. Conduction is The procedure by which thermal energy or electricity is directly transported through a substance without the material moving when there is a variance in temperature between adjacent parts. Only choice B shows this process.
10. In exothermic reactions, energy/heat is lost. Exothermic reactions are characterized by a negative delta H, such as the delta H for the reaction show.
What mass of sulfur must be used to produce 25.7 L of gaseous sulfur dioxide at STP
according to the following equation?
S8 (s) + 8 O2 (g) −→ 8 SO2 (g)
Answer in units of g.
A mass of 37.0 g of sulfur must be used to produce 25.7 L of gaseous sulfur dioxide at STP.
What is the reactant mass of the sulfur?The molar ratio of S₈ to SO₂ is 1:8.
At STP, one mole of gas occupies 22.4 L. Therefore, 25.7 L of SO₂ gas will contain;
25.7 L / 22.4 L/mol = 1.15 mol of SO₂.
The number of moles of S₈ needed is calculated as;
= 1.15 mol SO₂ / 8 mol S₈ per 1 mol SO₂
= 0.144 mol S₈.
The mass of S₈ needed is calculated as;
0.144 mol S₈ × 256.6 g/mol = 37.0 g of S₈.
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PLEASE HELP!
Distilled vinegar contains a solution of acetic acid (CH3CO2H) in H2O. Using the formula M1V1=M2V2, solve for the concentration of the solution that results from diluting 0.50 L of 0.839 M vinegar solution to 2.5 L?
Question 4 options:
0.15 M
0.24 M
0.17 M
1.49 M
Pleas help thanks!!!!!!!!!!!!!!!!!!!!
The number of molecules of BF₃ present in 2 grams of BF₃ is 1.776×10²² molecules (1st option)
How do i determine the number of molecules of BF₃?
We'll begin by calculating the number of mole of 2 grams of BF₃. Details below:
Mass of BF₃ = 2 grams Molar mass of BF₃ = 67.81 g/molMole of BF₃ =?Mole = mass / molar mass
Mole of BF₃ = 2 / 67.81
Mole of BF₃ = 0.02949 mole
Finally, we shall determine the number of molecules of BF₃. This is shown below:
Avogadro's hypothesis suggest that:
1 mole of BF₃ = 6.022×10²³ molecules
Therefore,
0.02949 mole of BF₃ = 0.02949 × 6.02×10²³
0.02949 mole of BF₃ = 1.776×10²² molecules
Thus, the number of molecules of BF₃ is 1.776×10²² molecules (1st option)
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You want to have a barbecue this weekend! But you're worried about global warming. You only want to release a maximum of 0.750 kg of carbon dioxide from your propane grill. Using the below equation to answer the following questions.
CH3(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
ΔHrxn = -2220.1 kJ
a. How many kilojoules will you be able to release?
b. If it requires 1900 kJ to cook one hamburger, how many hamburgers can you cook?
a. We will be able to release 37,827 kJ. b. You can cook a maximum of 19 hamburgers without exceeding the limit of 0.750 kg of carbon dioxide.
a. We need to use the balanced chemical equation and the enthalpy change of the reaction.
Therefore, moles [tex]CO_2[/tex] produced are[tex]0.750 kg / 44.01 g/mol = 17.03 mol.[/tex]
The enthalpy change of the reaction is -2220.1 kJ/mol. Thus, the maximum number of kilojoules that can be released is:
[tex]\Delta Hrxn * moles of[/tex] [tex]CO_2[/tex] = [tex]-2220.1 kJ/mol * 17.03 mol = -37,827 kJ[/tex]
We need to reverse the sign of the answer, giving us 37,827 kJ.
b. If it requires 1900 kJ to cook one hamburger, we can divide the maximum number of kilojoules that can be released by the energy required to cook one hamburger:
37,827 kJ / 1900 kJ/hamburger = 19.91 hamburgers
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How many grams of zinc chloride would be formed if 77.1 grams of zinc reacts?
Zn + HCl -->ZnCl2 + H2
The amount of zinc chloride that would be formed if 77.1 grams of zinc reacts is approximately 160.77 grams
To determine how many grams of zinc chloride ([tex]ZnCl_2[/tex]) would be formed if 77.1 grams of zinc (Zn) reacts, we'll use stoichiometry.
First, we need the molar masses of the substances involved:
Zn: 65.38 g/mol
[tex]ZnCl_2[/tex] : 136.29 g/mol
Now, we'll convert grams of Zn to moles:
77.1 g Zn × (1 mol Zn / 65.38 g Zn) = 1.179 moles Zn
According to the balanced chemical equation, 1 mole of Zn reacts to form 1 mole of [tex]ZnCl_2[/tex]:
1.179 moles Zn × (1 mol ZnCl₂ / 1 mol Zn) = 1.179 moles ZnCl₂
Finally, convert moles of ZnCl₂ to grams:
1.179 moles ZnCl₂ × (136.29 g ZnCl₂ / 1 mol ZnCl₂) ≈ 160.77 g ZnCl₂
So, approximately 160.77 grams of zinc chloride would be formed if 77.1 grams of zinc reacts.
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If the average speed of an oxygen molecule is 4.37 ✕ 104 cm/s at 25°C, what is the average speed of a CO2 molecule at the same temperature?
The average speed of a gas molecule is proportional to the square root of its temperature and inversely proportional to the square root of its molar mass. Therefore, we can use the following equation to find the average speed of a CO2 molecule at the same temperature:
v2/v1 = sqrt(M1/M2)
where v1 and v2 are the average speeds of the oxygen and CO2 molecules, respectively, M1 and M2 are the molar masses of oxygen and CO2, respectively.
The molar mass of oxygen (O2) is 32 g/mol, and the molar mass of CO2 is 44 g/mol.
We are given that the average speed of an oxygen molecule is 4.37 × 10^4 cm/s at 25°C. We can convert the temperature to Kelvin by adding 273.15 to get:
T = 25°C + 273.15 = 298.15 K
Now we can solve for v2:
v2 = v1 * sqrt(M1/M2)
v2 = 4.37 × 10^4 cm/s * sqrt(32 g/mol / 44 g/mol)
v2 = 3.67 × 10^4 cm/s
Therefore, the average speed of a CO2 molecule at the same temperature is 3.67 × 10^4 cm/s.