Answers
Answer:
Number is yellow box=3
Step-by-step explanation:
We know this because the way we get that number is subtracting the two numbers above it, which is 8 and 5, which give us 3.
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Related Questions
Add the following polynomials, then place the answer in the proper location on the grid.
2x3 - 4x2 + 6x - 3
29 +6x2 - 8x + 12
- 3x3 + 2x2 - 4x - 7
Help ????????
Answers
Answer:
[tex] x^3 - 6x + 2 [/tex]
Step-by-step explanation:
The given polynomials can be added together by adding like terms together as shown below:
=> Add together, the coefficient of all terms that have the power of 3.
[tex] (2x^3) + (x^3) + (-3x^3) [/tex]
[tex] 2x^3 + x^3 - 3x^3 [/tex]
[tex] 3x^3 - 3x^3 [/tex]
[tex] x^3 [/tex]
=> [tex] (-4x^2) + (6x^2) + (2x^2) [/tex]
[tex] -4x^2 + 8x^2 [/tex]
[tex] 4x^2 [/tex]
=> [tex] (6x) + (-8x) + (-4x) [/tex]
[tex] 6x - 8x - 4x [/tex]
[tex] -6x [/tex]
=> [tex] (-3) + (12) +(-7) [/tex]
[tex] -3 + 12 - 7 [/tex]
[tex] 2 [/tex]
The answer = [tex] x^3 - 6x + 2 [/tex]
Answer:
4x^2-6x+2
Step-by-step explanation:
*4.8.21
Question Help
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After the release of radioactive material into the atmosphere from a nuclear power plant in a country in 2000, the hay in that country was contaminated by a radioactive
isotope (half-life 7 days). If it is safe to feed the hay to cows when 14% of the radioactive isotope remains, how long did the farmers need to wait to use this hay?
The farmers needed to wait approximately days for it to be safe to feed the hay to the cows.
(Round to one decimal place as needed.)
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Answers
Answer:
19.9 days
Step-by-step explanation:
The amount remaining after d days is ...
a = (1/2)^(d/7)
We want to find d when a = 0.14
log(a) = (d/7)log(1/2)
d = 7·log(0.14)/log(1/2) ≈ 19.855 ≈ 19.9
The farmers need to wait about 19.9 days for it to be safe.
A backpacking company requires each camper to bring a lantern to go on a trip. The company supplies 4 extra in case any lanterns get lost or broken. If 13 campers go on the trip, how many lanterns will they bring?
Answers
Answer:
17 lanterns.
Step-by-step explanation:
There are 13 campers with one lantern each, so that will be 13 * 1 = 13 lanterns.
The company supplies 4 extra lanterns for the whole group.
So, they will bring 13 + 4 = 17 lanterns.
Hope this helps!
The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out to see whether this is the case. What conclusion is appropriate in each of the following situations?
(a) n 15 t 1.66 a 0.05
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(b) n 15 t 1.66 a 0.05
Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(c) n 26, t 2.55 a 0.01
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(d) n 26, t 3.95
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Answers
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
C
b
C
c
C
d
A
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 0.5 \ in[/tex]
Generally the Null hypothesis is [tex]H_o : \mu = 0. 5 \ in[/tex]
The Alternative hypothesis is [tex]H_a : \mu \ne 0.5 \ in[/tex]
Considering the parameter given for part a
The sample size is n = 15
The test statistics is t = 1.66
The level of significance [tex]\alpha = 0.05[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 15- 1[/tex]
[tex]df = 14[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145[/tex]
We are making use of this [tex]t_{\frac{\alpha }{2} }[/tex] because it is a one-tail test
Looking at the value of t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that [tex]t < t_{\frac{\alpha }{2} }[/tex] so the null hypothesis would not be rejected
Considering the parameter given for part b
The sample size is n = 15
The test statistics is t = -1.66
The level of significance [tex]\alpha = 0.05[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 15- 1[/tex]
[tex]df = 14[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha}{2} ,df }[/tex] the we see that t does not lie in the area covered by [tex]t_{\frac{\alpha}{2} , df }[/tex] (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis
Considering the parameter given for part c
The sample size is n = 26
The test statistics is t = -2.55
The level of significance [tex]\alpha = 0.01[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 26- 1[/tex]
[tex]df = 25[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that t does not lie in the area covered by [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis
Considering the parameter given for part d
The sample size is n = 26
The test statistics is t = -3.95
The level of significance [tex]\alpha = 0.01[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 26- 1[/tex]
[tex]df = 25[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha}{2} }[/tex] the we see that t lies in the area covered by [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we reject the null hypothesis
Type the slope-intercept equation
of the line that passes through
the points (-1,3) and (2,-3).
y = [? ]x + [ ]
Answers
Answer:
y= -2x +1
Step-by-step explanation:
slope- intercept form:
y= mx +c, where m us the gradient and c is the y-intercept.
Let's find the value of m first using the gradient formula.
Gradient= [tex] \frac{y1 - y2}{x1 - x2} [/tex]
[tex]m = \frac{ - 3 - 3}{2 - ( - 1)} \\ m = \frac{ - 6}{2 + 1} \\ m = \frac{ - 6}{3} \\ m = - 2[/tex]
y= -2x +c
To find the value of c, substitute a pair of coordinates.
When x= -1, y=3,
3= -2(-1) +c
3= 2 +c
c= 3 -2
c= 1
Thus the equation of the line is y= -2x +1.
Transformations of exponential functions
Answers
Answer:
It's the last one. We know it's to the right because the -8 is in the exponent and also, it's -8 not +8.
Tessa solves the equation below by first squaring both sides of the equation HELP PLEASE
Answers
Answer:
-7Step-by-step explanation:
[tex] \sqrt{ {x}^{2} - 3x - 6} = x - 1[/tex]
Squaring on both sides:
[tex] {x}^{2} - 3x - 6 = {(x - 1)}^{2} [/tex]
Use the formula:[tex] {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} [/tex]
[tex] {x}^{2} - 3x - 6 = {x}^{2} - 2x + 1[/tex]
Combine like terms.
[tex] {x}^{2} - {x}^{2} - 3x + 2x = 1 + 6[/tex]
[tex] - 3x + 2x = 7[/tex]
Calculate
[tex] - x = 7[/tex]
[tex]x = - 7[/tex]
Hope this helps...
Good luck on your assignment..
Answer:
-7
Step-by-step explanation:
Khan academy
PLEASE HELP QUICK! Determine x value of: sqrt x + 8 - sqrt x - 4 = 2
Answers
Answer:
x=8
Step-by-step explanation:
[tex]\sqrt{x+8}-\sqrt{x-4}=2\\\sqrt{x+8}=2+\sqrt{x-4}\\\left(\sqrt{x+8}\right)^2=\left(2+\sqrt{x-4}\right)^2\\x+8=x+4\sqrt{x-4}\\8=4\sqrt{x-4}\\8^2=\left(4\sqrt{x-4}\right)^2\\64=16x-64\\x=8[/tex]
Which is the graph of g(x) = (0.5)x + 3 – 4? On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = negative 4. It crosses the y-axis at (0, negative 4). On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = 3. It crosses the y-axis at (0, 3). On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = negative 4. It crosses the y-axis at (0, 4). On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = 4. It crosses the y-axis at (0, 12).
Answers
Answer:
The graph will be an exponential function that crosses the y-axis at about (0, -4).
Step-by-step explanation:
[tex]g(x) = (0.5)^{x + 3} - 4[/tex]
That means that when x = 0...
[tex]g(0) = (0.5)^{0 + 3} - 4[/tex]
[tex]g(0) = (0.5)^{3} - 4[/tex]
[tex]g(0) = 0.125 - 4[/tex]
[tex]g(0) = -3.875[/tex]
So, the graph will be an exponential function that crosses the y-axis at about (0, -4).
Hope this helps!
Answer:
its a
Step-by-step explanation:
i put the equation in desmos and the graph looked exactly like a lol
Leechtown Co. has 4.3% coupon bonds on the market with 18 years left to maturity. The bonds make annual payments. If the bond currently sells for $870, what is its YTM? (Do not round intermediate calculations. Round the final answer to 2 decimal places.) Yield to maturity %
Answers
Answer:
YTM = 5.45%
Step-by-step explanation:
Here, we are interested in calculating the yield to maturity.
Mathematically;
Annual coupon=1000*4.3%=43
YTM=[Annual coupon+(Face value-Present value)/time to maturity]/(Face value+Present value)/2
=[43+(1000-870)/18]/(1000+870)2
=5.45%
Solving exponential functions
Answers
Answer:
Option B
an increasing exponential graph
Write the following numbers in increasing order: −1.4; 2; −3 1 2 ; −1; − 1 2 ; 0.25; −10; 5.2
Answers
Answer:
-12,-10,-3,-1.4,-1,0.25,2,5.2,12
Step-by-step explanation:
The following number −1.4; 2; −3 1 2 ; −1; − 1 2 ; 0.25; −10; 5.2 in increasing order
-12,-10,-3,-1.4,-1,0.25,2,5.2,12
It's arranged this way starting from the negative sign because positive it's greater than negative and if the negative gets to approach zero it's get smaller
Answer:
-10 ; -3 1/2 ; -1.4 ; -1 ; -1/2 ; 0.25 ; 2 ; 5.2
A customer enrolled in a 1-year product purchase plan that costs $60 per month. After 6 months, the customer received a monthly discount of 20%. What is the total amount the customer will pay for the 1-year plan?
Answers
Answer:
$432
Step-by-step explanation:
60*6=360
They paid $360 for the first 6 months.
20%*60=.2*60
0.2*60=12
12*6=72
They paid $72 for the last 6 months.
360+72=432
They paid $432
$648 is the total amount the customer will pay for the 1-year plan
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
Given that a customer enrolled in a 1-year product purchase plan that costs $60 per month.
After 6 months, the customer received a monthly discount of 20%.
We need to find the total amount the customer will pay for the 1-year plan.
Product Plan = $60 per month
Money he pay for 1 month = $ 60
Money He pay for first 6 month = 6 × 60 = $ 360
after 6 month he receives 20% discount monthly,
So, Now he pay for 1 month = 60 - 20% × 60
=60-20/100×60
=60-12=48
Money he pay for last 6 month = 6 × 48 = 288
Total Money he pay in a year = 360 + 288 = $ 648
Hence, $648 is the total amount the customer will pay for the 1-year plan
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47% of the students in a class of 34 students has glasses or contacts. How many students in the class have either glasses or contacts?
Answers
Answer:
16
Step-by-step explanation:
47% is 0.47
34 x 0.47 = 15.98
So a trick question, its either 15 students or 16 students.... I would say 16 students, although the percentage would be 47.05%
16 students either have glasses or contacts.
Quick!!! Urgent!!!!!!!!!
Answers
Answer:
my best answer for this is B. False.
I calculated as fast as i can.
Is the test below left-, right-, or two-tailed? H0:p=0.39, Ha:p≠0.39 Select the correct answer below: The hypothesis test is two-tailed. The hypothesis test is left-tailed. The hypothesis test is right-tailed.
Answers
Answer:
The hypothesis test is a two-tail test
Step-by-step explanation:
The test hypothesis:
Null hypothesis H₀ p = 0,39 or p = p₀
Where p₀ is a nominal proportion (established proportion) and
Alternate hypothesis Hₐ p ≠ 0,39 or p ≠ p₀
Is a two-tail test, (≠) means different, we have to understand that different implies bigger and smaller than something.
For a test to be one tail-test, it is necessary an evaluation only in one sense in relation to the pattern ( in this case the proportion )
Variables A and B have a covariance of 45, and variables C and D have a covariance of 627. How does the A and B relationship compare to the C and D relationship?
Answers
Answer:
variable A and Variable B are more negatively related than variable C and variable D.
Step-by-step explanation:
Variables A and B have a covariance = 45
Variables C and D have a covariance = 627
Comparing the relationship between variable A AND B with the relationship between variable C and D
variable A and Variable B are more negatively related than variable C and variable D. this is because the covariance between variable A and Variable B are less positive
Hi any help is appreciated. Just wanna graduate:))
Answers
Answer: C
Step-by-step explanation:
h · k(x) = 2(3x - 5)(-2x + 1)
= (6x - 10)(-2x + 1)
= -12x² + 6x + 20x - 10
= -12x² + 26x - 10
Answer:
C
Step-by-step explanation:
h(x) × k(x)
= 2(3x - 5)(- 2x + 1) ← expand factors using FOIL
= 2(- 6x² + 3x + 10x - 5)
= 2(- 6x² + 13x - 5) ← distribute parenthesis by 2
= - 12x² + 26x - 10 → C
Which expression is equivalent to g5?
О 9х5
О 5x5x5x5x5x5x5x5x5
О 9х9х9х9х9
О 9х9х9х9х9х5x5x5x5x5x5x5x5x5
Answers
Answer:
9 x 9 x 9 x 9 x 9
Step-by-step explanation:
9^5 = 9 x 9 x 9 x 9 x 9
Answer:
it is C
Step-by-step explanation:
A publisher requires 2∕3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest whole page, how many pages of the magazine are advertisements?
Answers
Answer:
[tex]\boxed{13}[/tex] pages
Step-by-step explanation:
Divide the total number of pages by 5 to get how many sets of every 5 pages will contain 2/3 of a page of advertisements.
[tex]\frac{98}{5} = 19.6[/tex]
Multiply this value by [tex]\frac{2}{3}[/tex] to get the total number of pages.
[tex]19.6 * \frac{2}{3} \approxeq 13[/tex] pages
Maths Problem I can't quite understand. Please could you help? All shown on the picture :) I hope you could help
Answers
Answer:
50 1 20
4 10 25
5 100 2
Step-by-step explanation:
Hello,
we can use Dudeney method
[tex]1000 = 2^35^3[/tex]
so we have a =2 and b = 5
the solution is
[tex]ab^2 \ \ 1 \ \ \ \ a^2b\\a^2 \ \ \ ab \ \ \ b^2\\b \ \ \ \ a^2b^2 \ \ a[/tex]
just need to replace a by 2 and b by 5
hope this helps
several years ago ravi invested in some gold gold is currently valued at $2737 per ounce which is 70% more than rafa originally paid for it what was the purchase price of the gold
Answers
Answer:
Original price is $1610
Step-by-step explanation:
2737=1.7*Original price
divide each side by 1.7
Original price=1610
Hope this helps!
In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $31 and standard deviation of $6. Construct a confidence interval at a 80% confidence level.
Answers
Answer:
29.4≤μ≤32.6
Step-by-step explanation:
The datas given from the questions are as shown:
Number of people n = 24
Mean xbar= $31
Standard deviation σ = $6
Confidence Interval formula is expressed as:
CI = xbar ± Z(σ/√n)
Z value for 80% confidence interval is 1.282
Substituting the values into the Confidence Interval formula will give;
CI = 31 ± 1.282{6/√24}
CI = 31 ± 1.282(1.225)
CI = 31 ± 1.57045
CI = 31+1.57045 and 31-1.57045
CI = (29.42955, 32.57045)
CI = (29.4, 32.6) to 1dp
The confidence interval will be within the range 29.4≤μ≤32.6
Use arrow notation to describe the translation of point PC-9, 5) to point P4-6, 7).
A (x,y) → (x - 3,7 - 2)
B (x,y) → (x + 3y - 2)
C (x,y) → (x + 3y + 2)
D (x,y) → (x - 3y + 2)
Answers
Write down the first 6 elements of the following sequence (where n ∈ Z +), then give a recursive definition for an. Do not forget the base case. (You do not need to prove it is correct). (a) an = 3n − 10 (b) an = (1 + (−1)n ) n
Answers
Step-by-step explanation:
The first six terms for each of the following sequenses are:
(a) a_n = 3n - 10
1. a_1 = -7
2. a_2 = -4
3. a_3 = -1
4. a_4 = 2
5. a_5 = 5
6. a_6 = 8
(b) a_n = (1 + (-1)^n) ^n
1. a_1 = 0
2. a_2 = 4
3. a_3 =0
4. a_4 = 16
5. a_5 = 0
6. a_6 = 32
A patrolmen spend 25% of every day completing paperwork. The patrol and shift each day is 8 hourZ how much of his time does he spend doing paperwork each day
Answers
Answer:
25 percent of 8 is 2 so 2 hours
Step-by-step explanation:
Find the value of EB
Answers
Answer:
31Step-by-step explanation:
Given,
AD = 38
EB = 7x - 4
FC = 6x - 6
Now, we have to find the value of X
[tex]eb \: = \frac{1}{2} (ad \: + fc \: )[/tex] ( Mid segment Theorem )
Plug the values
[tex]7x - 4 = \frac{1}{2} (38 + 6x - 6)[/tex]
Calculate the difference
[tex]7x - 4 = \frac{1}{2} (32 + 6x)[/tex]
Remove the parentheses
[tex]7x - 4 = \frac{32}{2} + \frac{6x}{2} [/tex]
[tex]7x - 4 = 16 + 3x[/tex]
Move variable to L.H.S and change its sign
Similarly, Move constant to R.H.S and change its sign
[tex]7x - 3x = 16 + 4[/tex]
Collect like terms
[tex]4x = 16 + 4[/tex]
Calculate the sum
[tex]4x = 20[/tex]
Divide both sides of the equation by 4
[tex] \frac{4x}{4} = \frac{20}{4} [/tex]
Calculate
[tex]x = 5[/tex]
The value of X is 5
Now, let's find the value of EB
EB = 7x - 4
Plug the value of X
[tex] = 7 \times 5 - 4[/tex]
Calculate the product
[tex] = 35 - 4[/tex]
Calculate the difference
[tex] = 31[/tex]
The value of EB is 31
Hope this helps..
Best regards!!
Which inequality has a dashed boundary line when graphed? A y>=3/5x+1 B y>= -1/3x+1 C y>3x+1
Answers
Answer: C y>3x+1
Step-by-step explanation:
When we graph an inequality with strictly greater of less than sign ('<' or '>'), then the graph has a dashed boundary line .Further it indicates that it does not include the points on the line.From all the given options , only C contains inequality with '>' sign .
Hence, y>3x+1 is the inequality has a dashed boundary line when graphed.
hence, the correct option is C.
Please answer this correctly without making mistakes
Answers
Answer: 4.8mi
Step-by-step explanation:
From Newton, getting to Bloomington takes 10mi, and getting to Arlington takes 5.2mi. Thus, simply do 10-5.2 to get 4.8mi.
Hope it helps <3
Please answer the followings: W^mW^n=
Answers
Step-by-step explanation:
[tex]W^m=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m}\\\\W^n=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{n}\\\\W^mW^n=\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{m}\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{n}\\\\=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m+n}=W^{m+n}[/tex]
From the following given equation, the answer to W^mW^n = [tex]\mathbf{W^{m+n}}[/tex]
The laws of indices provide us with the rules and principles for simplifying mathematical computations or algebraic expressions that include powers of the same base.
The example of the question given can be solved by using the multiplication rule. The multiplication rule states that we sum up the power of the integers if they have the same base.
From the given information
W^mW^n = [tex]\mathbf{W^{m+n}}[/tex]
Learn more about indices here:
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