Help!! Truth table.

Thank you.

Answer:

48 49 51 53 58

Step-by-step explanation:

48×2= 96 so 49 51 53 and 58 are greater hope this helps:)

Treating the data as a Venn set, it is found that:

---------------------------------

I am going to say that:

---------------------------------

9 are good in all of the three courses.

This means that: [tex]A \cap B \cap C = 9[/tex]

---------------------------------

13 are good in both mathematics and psychology

This means that:

[tex](A \cap C) + (A \cap B \cap C) = 13[/tex]

[tex](A \cap C) + 9 = 13[/tex]

[tex](A \cap C) = 4[/tex]

---------------------------------

15 are good in both mathematics and in English

This means that:

[tex](A \cap B) + (A \cap B \cap C) = 15[/tex]

[tex](A \cap B) + 9 = 15[/tex]

[tex](A \cap B) = 6[/tex]

---------------------------------

16 are good in both English and psychology

This means that:

[tex](B \cap C) + (A \cap B \cap C) = 16[/tex]

[tex](B \cap C) + 9 = 16[/tex]

[tex](B \cap C) = 7[/tex]

---------------------------------

20 are good in psychology

This means that:

[tex]c + (A \cap C) + (B \cap C) +  (A \cap B \cap C) = 20[/tex]

[tex]c + 4 + 7 + 9 = 20[/tex]

[tex]c = 0[/tex]

---------------------------------

45 are good in mathematics

This means that:

[tex]a + (A \cap B) + (A \cap C) +  (A \cap B \cap C) = 45[/tex]

[tex]a + 6 + 4 + 9 = 45[/tex]

[tex]a = 26[/tex]

---------------------------------

Question a:

[tex]a = 26[/tex], which means that 26 students are good in mathematics only.

---------------------------------

Question b:

At least one is:

[tex]a + (A \cap B) + (A \cap C) + (B \cap C) +  (A \cap B \cap C) = 26 + 6 + 4 + 7 + 9 = 52[/tex]

Thus, 80 - 52 = 28

28 students are not good in any of the three courses.

A similar problem is given at: https://brainly.com/question/22003843

Answer:

No

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 1 ← is in slope- intercept form

with slope m = 3

Calculate the slope using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (2,4) and (x₂, y₂ ) = (4, 12) ← 2 ordered pairs from the table

m = [tex]\frac{12-4}{4-2}[/tex] = [tex]\frac{8}{2}[/tex] = 4

Parallel lines have equal slopes

The slope of these 2 lines are not equal , thus not parallel

9514 1404 393

Answer:

  p = -3/4b -3/4

Step-by-step explanation:

Vectors are perpendicular when their dot product is zero.

  A·B = p(4) +b(3) -3(-1) = 4p +3b +3

We want this to be zero, so ...

  4p +3b +3 = 0

  4p = -3b -3

  p = -3/4b -3/4 . . . . the value of p that makes A⊥B

Let lebgth be x

[tex]\\ \rm\Rrightarrow Perimeter=2(L+B)[/tex]

[tex]\\ \rm\Rrightarrow 2(x+\dfrac{3x}{4})=140[/tex]

[tex]\\ \rm\Rrightarrow 2\left(\dfrac{4x+3x}{4}\right)=140[/tex]

[tex]\\ \rm\Rrightarrow 2\left(\dfrac{7x}{4}\right)=140[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{14x}{4}=140[/tex]

[tex]\\ \rm\Rrightarrow 14x=140(4)[/tex]

[tex]\\ \rm\Rrightarrow 14x=560[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{560}{14}[/tex]

[tex]\\ \rm\Rrightarrow x=40[/tex]

Answer:

(5,2)

(6,-6)

Step-by-step explanation:

Answer:

100 km

Step-by-step explanation:

Speed = distance/time

=> Speed × time = distance

=> Distance = speed × time

=> Distance = (40 km/h) × 2.5 hours

=> Distance = 100 km.h/h

=> Distance = 100 km

Answer:

1. Y

2. YX , YZ

3. X

4. XZ

Answer: 30 degrees

This is the minimum amount of rotation.

Why this value? Well because 360/12 = 30

Consider a triangle with 3 sides. Specifically I mean an equilateral triangle. We can rotate it 120 degrees to have it line up with itself. Now notice that 360/3 = 120.

For a square, we can rotate it 90 degrees and we can say 360/4 = 90

So the general rule is that the minimum angle of rotation is 360/n, where n is the number of sides. This rule only works for regular polygons. Regular polygons have the same side length and the same angle measure (the side and angle measure won't necessarily be equal).

So going back to this 12 sided dodecagon, we have n = 12 and 360/n = 360/12 = 30 as the minimum angle of rotation. Each 30 degree rotation will have the polygon match up perfectly with its old image. The preimage and image will be identical.

Answer:

Step-by-step explanation:

Coordinates of Q and S are:

We need to find the coordinates of R such that:

Let R has coordinates (x, y):

The point is R(2, -2)

Answer:

2,-2

Step-by-step explanation:

Answer:

[tex]-\sqrt{3} /2[/tex]

Step-by-step explanation:

300 degrees is in the fourth quadrant (it's between 270 and 360); sine is negative in the fourth quadrant.

Given we're in the fourth quadrant, the reference angle is 360 - 300 = 60 degrees

sin(60°) = [tex]\sqrt{3} /2[/tex]

And since sine is negative, this value turns negative:

sin(300°) = [tex]-\sqrt{3} /2[/tex]

Answer:

hope it helps you........

(6x - 5y + 4) dy + (y - 2x - 1) dx = 0

(6x - 5y + 4) dy = (2x - y + 1) dx

dy/dx = (2x - y + 1) / (6x - 5y + 4)

Let X = x - a and Y = y - b. We want to find constants a and b such that

dY/dX = (a rational function)

where the numerator and denominator on the right side are free of constant terms. Substituting x and y in the equation, we have

dY/dX = (2 (X + a) - (Y + b) + 1) / (6 (X + a) - 5 (Y + b) + 4)

dY/dX = (2X - Y + 2a - b + 1) / (6X - 5Y + 6a - 5b + 4)

Then we solve for a and b in the system,

2a - b + 1 = 0

6a - 5b + 4 = 0

==>   a = -1/4 and b = 1/2

With these constants, the equation reduces to

dY/dX = (2X - Y) / (6X - 5Y)

Now substitute Y = VX and dY/dX = X dV/dX + V :

X dV/dX + V = (2X - VX) / (6X - 5VX)

The equation becomes separable after some simplification:

X dV/dX + V = (2 - V) / (6 - 5V)

X dV/dX = (2 - V) / (6 - 5V) - V

X dV/dX = (2 - V - (6 - 5V)) / (6 - 5V)

X dV/dX = (4V - 4) / (6 - 5V)

- (5V - 6) / (4V - 4) dV = 1/X dX

Integrate both sides:

-5/4 V + 1/4 ln|4V - 4| = ln|X| + C

Extract a constant from the logarithm on the left:

-5/4 V + 1/4 (ln(4) + ln|V - 1|) = ln|X| + C

-5/4 V + 1/4 ln|V - 1| = ln|X| + C

-5V + ln|V - 1| = 4 ln|X| + C

Get this back in terms of Y :

-5Y/X + ln|Y/X - 1| = 4 ln|X| + C

Now get the solution in terms of y and x :

-5 (y - 1/2)/(x + 1/4) + ln|(y - 1/2)/(x + 1/4) - 1| = 4 ln|x + 1/4| + C

With some manipulation of constants and logarithms, and a bit of algebra, we can rewrite this solution as

-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|x + 1/4| + 4 ln(4) + C

-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|4x + 1| + C

-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| - ln|4x + 1| = 4 ln|4x + 1| + C

-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| = 5 ln|4x + 1| + C

Step-by-step explanation:

1. 6(5)^2-1/(5)^2 = 149/25

2. 6(-5)^2-1/25 = -150/25

3. 6x^2-2/x^2

Answer:

[tex]1) \huge\boxed{ \sf f(5) = 5 \frac{24}{25} }[/tex]

[tex]2) \huge\boxed{ \sf f(-5) = 5\frac{24}{25} }[/tex]

[tex]3) \huge\boxed{\sf f(-x) = \frac{6x^2-1}{x^2} }[/tex]

Step-by-step explanation:

[tex]\displaystyle f(x) = \frac{6x^2-1}{x^2}[/tex]

For f(5):

Put x = 5

[tex]\displaystyle f(5) = \frac{6(5)^2-1}{(5)^2} \\\\f(5) = \frac{6(25)-1}{25} \\\\f(5) = \frac{150-1}{25} \\\\f(5) = \frac{149}{25} \\\\f(5) = 5 \frac{24}{25}[/tex]

For f(-5):

Put x = -5

[tex]\displaystyle f(-5) = \frac{6(-5)^2-1}{(-5)^2} \\\\f(-5) = \frac{6(25)-1}{25} \\\\f(-5) = \frac{150-1}{25} \\\\f(-5) = \frac{149}{25} \\\\f(-5) = 5\frac{24}{25}[/tex]

For f(-x):

Put x = -x

[tex]\displaystyle f(-x) =\frac{6(-x)^2-1}{(-x)^2} \\\\f(-x) = \frac{6x^2-1}{x^2} \\\\\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

x = -5 ​

Step-by-step explanation:

3+X=-2 ​

Subtract 3 from each side

3-3+X=-2-3

x = -5 ​

Answer:

-5

Step-by-step explanation:

1 Subtract 3 from both sides.

x=-2-3

2 Simplify -2 -3 to -5

x=-5

9514 1404 393

Answer:

Step-by-step explanation:

Rewrite as a quadratic in sin(θ) and solve that in the usual way.

  3cos(2θ) +sin(θ) = 1

  3(1 -2sin²(θ)) +sin(θ) = 1 . . . . use an identity for cos(2θ)

  6sin²(θ) -sin(θ) -2 = 0 . . . . . rearrange to standard form

  (3sin(θ) -2)(2sin(θ) +1) = 0 . . . . factor

The values of sin(θ) that make this true are ...

  sin(θ) = 2/3, sin(θ) = -1/2

In the range 0 < θ < 180°, we're only interested in ...

  sin(θ) = 2/3

  θ = arcsin(2/3) or 180° -arcsin(2/3)

  θ ≈ {41.81°, 138.19°}

Answer:

29, 35, 41

Step-by-step explanation:

sequence is in the difference of 6

Answer:

height =10

[tex] \frac{4}{5} h + 2 = h \\ h - \frac{4}{5} h = 2 \\ \frac{1}{5} h = 2 \\ h = 2 \times 5 = 10[/tex]

Answer:

You need to bring the function to the standard form.

The term with highest degree exponent is the leading term and its coefficient is the leading coefficient.

Let it be axⁿ.

Depending on the n and a, the end behavior of the function will change.

This is an odd function and:

This is an odd function and:

This is an even function and:

This is an even function and:

Answer:

Yeah your right

Step-by-step explanation:

Answer:

x = 7

Step-by-step explanation:

2x - 8 = 6              (Given)

2x - 8 + 8 = 6 + 8  (Add 8 on both sides)

2x = 14                  (Simplify)

2x/2 = 14/2           (Divide 2 on both sides)

x = 7                      (Simplify)

Answer: trescientos ochenta mil doscientos diez es,pero te ayude

Answer:

Step-by-step explanation:

(16.2t+3.4u+2.9)cm

Step-by-step explanation:

A triangle is a plane shape that has three sides. The perimeter of a triangle is gotten by taking the sum of all the lengths of the three sides. Let the length of the three sides by s1, s2 and s3, the perimeter of the triangle will be expressed as;

P = s1+s2+s3

Given the side lengths

s1 = (8.1t-6.1)cm

s2 = (8.1t+7.1)cm

s3 = (3.4u+1.9)cm

Perimeter of the triangle = 8.1t-6.1+8.1t+7.1+3.4u+1.9

collect the like terms

P = 8.1t+8.1t+3.4u-6.1+7.1+1.9

P = 16.2t+3.4u+2.9

Hence the expression that represents the perimeter, in centimeters, of the triangle is  (16.2t+3.4u+2.9)cm

Answer:

D. [tex] 5.1[/tex]

Step-by-step explanation:

[tex] \frac{ - 44.288 - 31.6}{ - 3.1(6 - 1.2)} [/tex]

➡️ [tex] \frac{ - 75.888}{ - 3.1 \times 4.8} [/tex]

➡️ [tex] \frac{24.48}{4.8} [/tex]

➡️ [tex] = 5.1[/tex]

Step-by-step explanation:

[tex]b(1) = 4[/tex]

Since this is an arithmetic sequence, notice that if you subtract b(1) (i.e., 4) from b(2)(i.e., 22), you get 18. Likewise, if you subtract b(2) from b(3) you also get 18. Therefore,

[tex]b(n) = b(n-1) + 18[/tex]

Answer:

Y=3

Step-by-step explanation:

in the first to second step: -2(7-y)+4=-4 to -14-2y+4=-4, the part -2(7-y) should equal -14+2y instead of 14-2y because two negative signs add to be positive

so y should be 3

Answer: What that other guy said

Step-by-step explanation:

There is 7 blocks that measure is 12.0-12.2

11 blocks that measure 12.2 to 12.4

18 blocks that measure 12.4 to 12.6

10 blocks that measure 12.6-12.8

4 blocks that measure 12.8 to 13.0

We can't find a mean by with Intervals so let find the midpoint of each interval,

12.1, 12.3, 12.5, 12.7, 12.9.

Add up the products and divide them by 50

[tex]\frac{623.6}{50} = 12.472[/tex]

Standard Deviation is

0.23( it is alot of steps so I use a calculator to save time).

The interqualtie range is 0.4

Answer:

-16200

Step-by-step explanation:

162×(-92)+(162)×(-810)×3

Step-by-step explanation:

[tex](162 \times ( - 92) + 162 \times ( - 5 \times - 162) \times 3 = (-14904 + 162 )\times( 810 \times 3) = (-14904+ 162) \times (2430) = - 14742\times 2430 = 378,756

Answer:

B

Step-by-step explanation:

tan(30)=n/(5*sqrt(3))

=> n=5

Answer:

A, B, C, and E

Step-by-step explanation:

A) -4 X-3 = 12

B) 6 x 2 = 12

C) -6 X-2 = 12

D) 3 X-4 = -12

E) 12 x 1 = 12

the expressions that have a value of 12 are :

A, B, C, and E

Answer:

Lets find

[tex]\\ \rm\longmapsto -4(-3)=12\checkmark[/tex]

[tex]\\ \rm\longmapsto 6(2)=12\checkmark[/tex]

[tex]\\ \rm\longmapsto -6(-2)=12\checkmark[/tex]

[tex]\\ \rm\longmapsto 3(-4)=-12\checkmark[/tex]

[tex]\\ \rm\longmapsto 12(1)=12\checkmark[/tex]