Help Please!
Find the value of x for which ABCD must be a parallelogram.

Answer:

the answer for question 1 is -7

9514 1404 393

Answer:

  $9072

Step-by-step explanation:

Put the given numbers in the given formula and do the arithmetic.

  A = MN . . . . . . M = payment = $189. N = number of payments = 48.

  A = $189 × 48 = $9072

The total amount paid is $9072.

Step-by-step explanation:

a proportional or similar shadow uses the same factor for each line/dimension.

so, since the height of the proportional rectangle is 4 times longer than the height of the original rectangle, then also the width must be 4 times longer.

heightP = 12 cm = f × height = f × 3 cm

f = 12/3 = 4

widthP = f × width = 4 × 5 = 20 cm

Answer:

B

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

c ≤ 4

Interval Notation:

( − ∞ , 4]

Answer:

x = -0.5

y = 2

Step-by-step explanation:

(2(-0.5)+3(2), 4) = (5, 2(2))

(-1 + 6, 4) = (5, 4)

(5, 4) = (5, 4)

Answer:

A) y=-7

Step-by-step explanation:

we talking about the better pond right?

Answer:

[tex]\displaystyle \text{d. }y=\frac{-6}{x}[/tex]

Step-by-step explanation:

If two values [tex]x[/tex] and [tex]y[/tex] are inversely proportional, their product is always some maintained constant (the product of [tex]x[/tex] and [tex]y[/tex] is always maintained). This way, if one goes up, the other must go down by the same extent. By definition, this represents an inversely proportional relationship.

Therefore, we can simply find this constant by multiplying the given values of [tex]x[/tex] and [tex]y[/tex]:

[tex]xy=k,\\6\cdot (-1)=-6[/tex]

The constant [tex]-6[/tex] must be maintained as the product of [tex]x[/tex] and [tex]y[/tex] for all values of [tex]x[/tex] and [tex]y[/tex] for them to be inversely proportional. Thus, we have the equation:

[tex]xy=-6[/tex]

Divide both sides by [tex]x[/tex] to isolate [tex]y[/tex]:

[tex]\boxed{y=\frac{-6}{x}}[/tex]

Answer:

d. [tex]\displaystyle y = \frac{-6}{x}[/tex]

Step-by-step explanation:

The fastest way to do this is to simply plug in whatever the exercise gave to you into each answer choise to figure out which one fits the best.

I am joyous to assist you at any time.

Answer:

[tex]\sup(S) = 3[/tex].

[tex]\displaystyle \inf(S) = \frac{1}{3}[/tex].

Step-by-step explanation:

When factored, [tex]3\,x^{2} - 10\, x + 3[/tex] is equivalent to [tex](3\, x - 1)\, (x - 3)[/tex].

[tex]3\, x^{2} - 10\, x + 3 < 0[/tex] whenever [tex]\displaystyle x \in \left(\frac{1}{3},\, 3\right)[/tex].

Typically, the supremum and infimum of open intervals are the two endpoints. In this question, [tex]\sup(S) = 3[/tex] whereas [tex]\displaystyle \inf(S) = \frac{1}{3}[/tex].

Below is a proof of the claim that [tex]\sup(S) = 3[/tex]. The proof for [tex]\displaystyle \inf(S) = \frac{1}{3}[/tex] is similar.

In simple words, the supremum of a set is the smallest upper bound of that set. (An upper bound of a set is greater than any element of the set.)

It is easy to see that [tex]3[/tex] is an upper bound of [tex]S[/tex]:

To see that [tex]3[/tex] is the smallest upper bound of [tex]S[/tex], assume by contradiction that there exists some [tex]\epsilon > 0[/tex] for which [tex](3 - \epsilon)[/tex] (which is smaller than [tex]3\![/tex]) is also an upper bound of [tex]S\![/tex].

The next step is to show that [tex](3 - \epsilon)[/tex] could not be a lower bound of [tex]S[/tex].

There are two situations to consider:

Either way, it would be necessary to find (or construct) an element [tex]z[/tex] of [tex]S[/tex] such that [tex]z > 3 - \epsilon[/tex].

For the first situation, it would be necessary that [tex]\displaystyle 3 - \epsilon \le \frac{1}{3}[/tex], such that [tex]\displaystyle \epsilon \ge \frac{8}{3}[/tex]. Let [tex]z := 1[/tex] (or any other number between [tex](1/3)[/tex] and [tex]3[/tex].)

With the first situation [tex]\displaystyle \epsilon \ge \frac{8}{3}[/tex] accounted for, the second situation may assume that [tex]\displaystyle 0 < \epsilon < \frac{8}{3}[/tex].

Claim that  [tex]\displaystyle z:= \left(3 - \frac{\epsilon}{2}\right)[/tex] (which is strictly greater than [tex](3 - \epsilon)[/tex]) is also an element of [tex]S[/tex].

Either way, [tex](3 - \epsilon)[/tex] would not be an upper bound of [tex]S[/tex]. Contradiction.

Hence, [tex]3[/tex] is indeed the smallest upper bound of [tex]S[/tex]. By definition, [tex]\sup(S) = 3[/tex].

The proof for [tex]\displaystyle \inf(S) = \frac{1}{3}[/tex] is similar and is omitted because of the character limit.

Answer:

l.c.m of 100,150,200

Step-by-step explanation:

9514 1404 393

Answer:

  47°

Step-by-step explanation:

The law of sines helps you find angle T. From there, you can find angle S.

  sin(T)/t = sin(R)/r

  sin(T) = (t/r)sin(R) = (10/20)sin(104°)

  T = arcsin(sin(104°)/2) ≈ 29°

Then angle S is ...

  S = 180° -R -T = 180° -104° -29°

  ∠S = 47°

false

false

false........

false

Answer:

it extends forever in one direction. so false i guess

Step-by-step explanation:

Answer:

$79.50

Step-by-step explanation:

1. $350 + $210 + $100 + $294 = $954

2. $954 ÷ 12 = 79.50

Raul monthly expense is $79.50.

Here,

In filing his income​ tax, Raul reported annual contributions of ​$350 350 to a public radio​ station, ​$210 210 to a public tv​ station, ​$100 100 to a local food​ bank, and ​$294 294 to other charitable organizations.

We have to find Raul's monthly expense.

What is total amount?

A total is a whole or complete amount.

Now,

Raul's annual expense = $350 + $210 + $100 + $294

                                   = $954

Hence,

Raul's monthly expense =  954/12

                                     = 79.50

So, Raul monthly expense is $79.50.

Learn more about the total amount visit:

https://brainly.in/question/45320943

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Answer:   9 is a rational number.

Step-by-step explanation:

it is a Rational number

.

9

.

.

.

.

Step-by-step explanation:

steps are in the picture above.

Answer:

0. 8064

Step-by-step explanation:

Look at the Image

Answer:

∠AOB + ∠BOC = ∠AOC we will be using this equation

x = 21   this is the value of x

Step-by-step explanation:

Angle AOC = 84

Angle AOB = 3x

Angle BOC = x

it is given that Angle AOC = 84so we just need to add Angle AOB and Angle BOC

now lets make the equation we that we will be using

∠AOB + ∠BOC = ∠AOC

3x + x = 84

4x = 84

x = 84 ÷ 4

x = 21

Step-by-step explanation:

Here, we have,

AOC=84°

AOB=3x

BOC=x

Now, the required equation will be;AOC=AOB+BOC[whole part axiom]

or, 84°=3x+x

or, 84°=4x

or, 84°÷4=x

or, x=21°

Thus, the equation to find the answer is AOC=AOB+BOC and the value of x is 21°.

I'm guessing you mean

[tex]\displaystyle \int\frac{x^2+4}{x^2+4x+3}\,\mathrm dx[/tex]

First, compute the quotient:

[tex]\displaystyle \frac{x^2+4}{x^2+4x+3} = 1 + \frac{4x-1}{x^2+4x+3}[/tex]

Split up the remainder term into partial fractions. Notice that

x ² + 4x + 3 = (x + 3) (x + 1)

Then

[tex]\displaystyle \frac{4x-1}{x^2+4x+3} = \frac a{x+3} + \frac b{x+1} \\\\ \implies 4x - 1 = a(x+1) + b(x+3) = (a+b)x + a+3b \\\\ \implies a+b=4 \text{ and }a+3b = -1 \\\\ \implies a=\frac{13}2\text{ and }b=-\frac52[/tex]

So the integral becomes

[tex]\displaystyle \int \left(1 + \frac{13}{2(x+3)} - \frac{5}{2(x+1)}\right) \,\mathrm dx = \boxed{x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C}[/tex]

We can simplify the result somewhat:

[tex]\displaystyle x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C \\\\ = x + \frac12 \left(13\ln|x+3| - 5\ln|x+1|\right) + C \\\\ = x + \frac12 \left(\ln\left|(x+3)^{13}\right| - \ln\left|(x+1)^5\right|\right) + C \\\\ = x + \frac12 \ln\left|\frac{(x+3)^{13}}{(x+1)^5}\right| + C \\\\ = \boxed{x + \ln\sqrt{\left|\frac{(x+3)^{13}}{(x+1)^5}\right|} + C}[/tex]

Answer:

8*(-4)^(n-1)

Step-by-step explanation:

The common ratio is - 32/8 = - 4, the first term being 8. The formula will be 8*(-4)^(n-1).

Answer:

a^(m-n)

Step-by-step explanation:

We have

a^m / a^n

Exponent rules state that

a^m / a^n = a^(m-n)

Answer:a= 7

Step-by-step explanation:

Answer:

51

Step-by-step explanation:

1 book= N8.50

therefore 6 books= N8.50 × 6 = N51

Answer:

what to do which lesson of ath

[tex]\boxed{\sf \displaystyle{\lim_{x\to a}}(x^n)=a^n}[/tex]

[tex]\\ \sf\longmapsto \displaystyle{\lim_{x\to \infty}}(\sqrt{3x}-\sqrt{x-5})[/tex]

[tex]\\ \sf\longmapsto \displaystyle{\lim_{x\to \infty}}\sqrt{3x}-\displaystyle{\lim_{x\to \infty}}\sqrt{x-5}[/tex]

[tex]\\ \sf\longmapsto \infty^{\dfrac{1}{2}}-\sqrt{\infty-5}[/tex]

[tex]\\ \sf\longmapsto \infty-\sqrt{\infty}[/tex]

[tex]\\ \sf\longmapsto\infty-\infty[/tex]

[tex]\\ \sf\longmapsto\infty[/tex]

Answer:

Fareed

Step-by-step explanation:

All the other people have complications that won't let them be on every floor, but Fareed can.

in this case, we are looking at a length × width equation. this equation gives you the area of the gym. so the answer is B.

Answer:

B

Step-by-step explanation:

L× w = area of a rectangle

Answer:

A. 158

Step-by-step explanation:

Angle ABC and Angle ECF have the same tick mark(little line over the angle). The means they are congruent, the same. Since Angle ECF + Angle DCE = 180 degrees, 180 - 22 is the measure of angle DCE, or 158. You're welcome, and brainliest me.

Wanted to add that this is not at all college math. This like middle school lvl bro.

Answer:

2.4 put a bar over the 4 because it is repeating

Step-by-step explanation:

22/9 =

22 divided by 9

equals