AB is dilated by a scale factor of 3 to form A'B'. Point O, which lies on AB, is the center of dilation.
The slope of AB is 3. The slope of A'B' is 3. A'B' passes through point O.
What is dilation in mathematics?Dilation is a process of transformation used to resize an object.
The items are enlarged or shrunk through dilation. An image that retains the original shape is created by this alteration. The size of the form does differ, though.
By multiplying the x and y coordinates of the original figure by the scale factor, you may locate locations on the dilated image when a dilation in the coordinate plane has the origin as the center of dilation.
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The greenery landscaping company puts in an order for 2 pine trees and 5 hydrangea bushes for a neighborhood project. the order costs $150. they put in a second order for 3 pine trees and 4 hydrangea bushes that cost $144.50.
2(2.5) + 5(23) = 150
3(2.5) + 4(23) = 144.5
Both equations are satisfied, so our solution is correct.
The greenery landscaping company orders how many trees and bushes for the neighborhood?To solve the problem, let's first assign some variables. Let x be the cost of one pine tree and y be the cost of one hydrangea bush. We can then use these variables to set up a system of equations:
2x + 5y = 150 (equation 1)
3x + 4y = 144.5 (equation 2)
We can solve this system of equations using various methods. Here, we will use the substitution method.
From equation 1, we can solve for x in terms of y:
2x = 150 - 5y
x = (150 - 5y)/2
We can then substitute this expression for x into equation 2:
3((150 - 5y)/2) + 4y = 144.5
Multiplying both sides by 2 to eliminate the fraction:
3(150 - 5y) + 8y = 289
Expanding and simplifying:
450 - 15y + 8y = 289
-7y = -161
y = 23
We can now substitute this value for y into either equation 1 or 2 to solve for x:
2x + 5(23) = 150
2x = 5
x = 2.5
Therefore, one pine tree costs $2.50 and one hydrangea bush costs $23.
To check our work, we can substitute these values into both equations:
2(2.5) + 5(23) = 150
3(2.5) + 4(23) = 144.5
Both equations are satisfied, so our solution is correct.
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The measures of the angles of a triangle are shown in the figure below. Solve for x.
(2x+16) 48degrees
Answer:
x = 16
Step-by-step explanation:
(2x + 16) = 48
Subtract 16 with the positive 16 to cancel the numbers.
Subtract 16 with 48.
2x = 32
divide 32 by 2 to isolate the x.
32/2 = 16
x = 16
what percentage is equivalent to 96/160
Answer:
60%
Step-by-step explanation:
Take 96 and divide it by 160.
(easier if done on a calculator.)
For example: Find A/B as a percentage: take "A" and divide it by "B"
HELPPP SOMEBODY PLEASEEE WITH THIS MATHHHH
The correct statement is given as follows:
The function g(t) reveals the market value of the house increases by 3.6% each year.
How to define an exponential function?An exponential function has the definition presented as follows:
[tex]y = ab^x[/tex]
In which the parameters are given as follows:
a is the value of y when x = 0.b is the rate of change.The parameter b for this problem is given as follows:
b = 1.036.
As the parameter b has an absolute value greater than 1, the function is increasing, with a rate given as follows:
1.036 - 1 = 0.036 = 3.6% a year.
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The average depth of the Arctic Ocean is approximately 1050 meters, and the average depth of the Indian Ocean is approximately 3900 meters. To the nearest tenth, how many times as great is the average depth of the Indian Ocean compared to the average depth of the Arctic Ocean?A. 3. 7B. 3. 1C. 2. 8D. 2. 2
The average depth of the Indian Ocean is 3.7 time greater than that of Arctic Ocean. Therefore, the correct option is A.
To find how many times as great the average depth of the Indian Ocean is compared to the Arctic Ocean, we need to divide the average depth of the Indian Ocean by the average depth of the Arctic Ocean.
1: Divide the average depth of the Indian Ocean by the average depth of the Arctic Ocean:
3900 meters (Indian Ocean) / 1050 meters (Arctic Ocean) = 3.7142857
2: Round the result to the nearest tenth:
3.7
So, the average depth of the Indian Ocean is approximately 3.7 times greater than the average depth of the Arctic Ocean. The correct answer is A. 3.7.
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A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year.
This situation represents:
A. Exponential decay
B. Exponential growth
The rate of growth or decay, r, is equal to:
A. 1. 02
B. 0. 02
C. 0. 98
So the depth of the lake each year is ______ times the depth in the previous year.
A. 0. 98
B. 0. 02
C. 1. 02
It will take between _____ years for the depth of the lake to reach 26. 7 meters.
A. 3 and 4
B. 11 and 12
C. 9 and 10
D. 5 and 6
The situation represents exponential decay.
The rate of growth or decay, r, is equal to 0.02.
So the depth of the lake each year is 0.98 times the depth in the previous year.
It will take between 11 and 12 years for the depth of the lake to reach 26. 7 meters.
The situation represents exponential decay, as the depth of the lake decreases by a constant percentage each year. The rate of decay is 2% per year, so the rate of growth or decay, r, is equal to 0.98 (1 - 0.02). This means that the depth of the lake each year is 0.98 times the depth in the previous year.
To find the number of years it will take for the depth of the lake to reach 26.7 meters, we can use the formula for exponential decay:\
D = D₀ *[tex]e^{(-rt)[/tex]
where D is the current depth, D₀ is the initial depth, r is the rate of decay, and t is the number of years.
Substituting the given values, we get:
26.7 = 30 * [tex]e^{(-0.02t)[/tex]
Solving for t, we get:
t = ln(26.7/30) / (-0.02) ≈ 11.33
Therefore, it will take between 11 and 12 years for the depth of the lake to reach 26.7 meters.
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The graph below shows segment FG and point P what is the first coordinate of point M
Note that the first coordinate of M is -1. (Option D)
Why is this so?
Given :- coordinates of F = (-4,-2) = (x1,y1)
coordinates of G = (2,-2) = (x2,y2)
coordinates of P = (2,-8) = (x3,y3)
and distance between point M and P is half of the distance between FG
To find :- first coordinate of point M
solution :- let the coordinate of M be (x4,y4)
as we know that distance between of the opposite point of parallel line segments are equal
so, second coordinate of M = -8
now by distance formula
FG = √(x2-x1)² + (y2-y1²)
= √[2-(-4)]² + [-2-(-2)]²
= √(2+4)² + (2-2)²
= √(6)² + (0)²
=√36
F G = 6
so, distance between point M and P = 1/2 × F G
= 1/2 × 6
= 3units
again, by distance formula
MP = √(x3-x⁴)² + (y3-y4)²
3 = √(2-x⁴)² + [-8-(-8)]²
squaring on both side
(3)² = (√(2-x⁴)² + [-8-(-8)]²)²
9 = (2-x⁴)² + [-8-(-8)]²
9 = (2-x⁴)²+(0)²
9 = (2-x⁴)²
√9 = 2-x⁴
3 = 2-x⁴
x⁴ = 2-3
x⁴ = -1
Hence the first coordinate of M is -1
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Point M is located in the third quadrant.
The distance between point M and point P is half the distance between point F and point G.
• Segment MP is parallel to segment FG. What is the first coordinate of point M?
Ofra tried to solve an equation.
3x = 4.5
3x 4.5
3
3
=
Setting up
x = 1.5 Calculating
Where did Ofra make her first mistake?
Choose 1 answer:
Setting up
B Calculating
Ofra correctly solved the equation.
If Ofra tried to solve an equation 3x = 4.5, The statement "Ofra correctly solved the equation" is correct. So, correct option is C.
We can see this by substituting x = 1.5 into the original equation 3x = 4.5:
3(1.5) = 4.5
Simplifying the left-hand side, we get:
4.5 = 4.5
This is a true statement, which means that x = 1.5 is a valid solution to the equation 3x = 4.5.
Therefore, Ofra did not make any mistakes in solving the equation. She correctly set up the equation 3x = 4.5 by multiplying both sides by 3 to isolate x, and then calculated the value of x to be 1.5, which is the correct solution.
Option (c) is the correct answer.
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Complete question is:
Ofra tried to solve an equation.
3x = 4.5, Setting up x = 1.5 Calculating
Where did Ofra make her first mistake?
Choose 1 answer:
a) Setting up
b) Calculating
c) Ofra correctly solved the equation.
A triangle is shown with its exterior angles. The interior angles of the triangle are angles 2, 3, 5. The exterior angle at angle 2 is angle 1. The exterior angle at angle 3 is angle 4. The exterior angle at angle 5 is angle 6. Which statements are always true regarding the diagram? Select three options. m∠5 + m∠3 = m∠4 m∠3 + m∠4 + m∠5 = 180° m∠5 + m∠6 =180° m∠2 + m∠3 = m∠6 m∠2 + m∠3 + m∠5 = 180°
The true triangle statement regarding the diagram are:
1. m∠5 + m∠6 = 180° ________Linear Pair
2. ∠ 2+ ∠ 3 = ∠ 6________Exterior angle Property of Triangle
3. m∠2 + m∠3 + m∠5 = 180°________Triangle Sum Property
What is the angle measurement?From the question, Δ ABC with Exterior angles as ∠ 1 , ∠ 4 ,and ∠ 6
Note that the Exterior angle Property of Triangle state that An exterior angle of a triangle is equal to the sum of the opposite interior angles.
Hence: For Exterior ∠ 1 :
∠ 1 = ∠ 5 + ∠ 3 ________Exterior angle Property of Triangle
Also,
For Exterior ∠ 4:
∠ 4 = ∠ 5 + ∠ 2 ________Exterior angle Property of Triangle
Also,
In regards to Exterior ∠ 6:
∠ 6 = ∠ 2 + ∠ 3 ________ Exterior angle Property of Triangle
Using Triangle Sum Property, it state that In a triangle sum of the measures of angles is equal to 180° Hence: m∠2 + m∠3 + m∠5 = 180° ________Triangle Sum Property
The Linear Pair will be: The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.
Therefore, m∠5 + m∠6 = 180° ________Linear Pair
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See full question below
A triangle is shown with its exterior angles. The interior angles of the triangle are angles 2, 3, 5. The exterior angle at angle 2 is angle 1. The exterior angle at angle 3 is angle 4. The exterior angle at angle 5 is angle 6. Which statements are always true regarding the diagram? Select three options.
m∠5 + m∠3 = m∠4
m∠3 + m∠4 + m∠5 = 180°
m∠5 + m∠6 =180°
m∠2 + m∠3 =
m∠6 m∠2 + m∠3 + m∠5 = 180°
CAN SOMEONE SHOW ME STEP BY STEP ON HOW TO DO THIS
A city just opened a new playground for children in the community. An image of the land that the playground is on is shown.
A polygon with a horizontal top side labeled 45 yards. The left vertical side is 20 yards. There is a dashed vertical line segment drawn from the right vertex of the top to the bottom right vertex. There is a dashed horizontal line from the bottom left vertex to the dashed vertical, leaving the length from that intersection to the bottom right vertex as 10 yards. There is another dashed horizontal line that comes from the vertex on the right that intersects the vertical dashed line, and it is labeled 12 yards.
What is the area of the playground?
900 square yards
855 square yards
1,710 square yards
Kali has a choice of 20 flavors for her triple scoop cone. If she
chooses the flavors at random, what is the probability that the 3 flavors she
chooses will be vanilla, chocolate, and strawberry?
Ailani draws a map of her local town. she places the town hall at the origin of a coordinate plane and represents a lake with a circle drawn on the map. the center of the lake is 19 miles east and 3 miles south of the town hall, and the radius of the lake is 0. 5 miles. if the positive x-axis represents east and the positive y-axis represents north, which equation represents the lake? (x 19)2 (y – 3)2 = 0. 5 (x – 19)2 (y 3)2 = 0. 5 (x 19)2 (y – 3)2 = 0. 25 (x – 19)2 (y 3)2 = 0. 25.
The equation is (x^2 + y^2 - 38x + 6y = -369).
The center of the lake is 19 miles east and 3 miles south of the town hall, which means the coordinates of the center are (19,-3). The radius of the lake is 0.5 miles.
Using the standard equation of a circle, we have:
(x - h)^2 + (y - k)^2 = r^2
where (h,k) is the center of the circle and r is the radius.
Substituting the given values, we get: (x - 19)^2 + (y + 3)^2 = 0.5^2
Expanding the left side, we get: x^2 - 38x + 361 + y^2 + 6y + 9 = 0.25
Simplifying and rearranging terms, we get:
x^2 + y^2 - 38x + 6y + 369.25 = 0.25
Subtracting 369 from both sides, we get:
x^2 + y^2 - 38x + 6y = -369
Therefore, the equation that represents the lake on the map is:
(x - 19)^2 + (y + 3)^2 = 0.5^2, which can be simplified to (x^2 + y^2 - 38x + 6y = -369).
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measured in astronomical units, can be modeled using the expression ((1)/(52)x)^((2)/(3)) , where x is the number of Earth weeks it takes for the planet to orbit the sun. Which expression could also be used to represent the average distance of a planet from the sun using radicals?
So the expression that represents the average distance of a planet from the sun using radicals is: d = k/2√13 * √x
What is exponent?An exponent, also known as a power, is a mathematical notation that indicates the number of times a quantity is multiplied by itself. It is usually written as a small number (the exponent) placed to the right and above a larger number (the base). Exponents are used in many mathematical concepts, including logarithms, roots, and scientific notation.
Here,
The expression ((1)/∛(52)x)²) can be simplified using exponent rules:
((1)/∛(52)x)²) =((1)/∛(52)x)²) * ∛x²)
= 1/(∛52² * ∛x²)
The average distance of a planet from the sun measured in astronomical units can be represented using the formula:
d = k * √T
where d is the distance from the sun, T is the time it takes for the planet to orbit the sun, and k is a constant of proportionality.
We can rewrite this formula in terms of Earth weeks by noting that there are 52 weeks in a year, so T = (1/52)x years. Substituting this into the formula, we get:
d = k * √((1/52)x)
Simplifying this expression using exponent rules, we get:
d = k * √(1/52)* √x
So an equivalent expression using radicals to represent the average distance of a planet from the sun is:
d = k * √(1/(52)) * √x
which simplifies to:
d = k/√(52) * √x
or
d = k/2√13 * √x
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Mathematics help nedd
To solve the equation, we need to first simplify both sides:
(4x - 6)/5 + 1 = (x + 1)/5 - 2/5
Multiplying both sides by 5 to eliminate the denominator:
4x - 6 + 5 = x + 1 - 2
Simplifying further:
4x - 1 = x - 1
Subtracting x from both sides:
3x - 1 = -1
Adding 1 to both sides:
3x = 0
Dividing both sides by 3:
x = 0
Therefore, the solution to the equation is x = 0.
Answer: x=28
Step-by-step explanation:
Given: <A=68
Find: x
Reasoning:
<B = 2x+x
<B= 3x
<C=x they say the sides across from <C is same as other side so the
angles are the same
Solution:
All angles of a triangle =180
<A + <B + <C =180 >substitute
68 + 3x + x =180 > combine like terms
68 + 4x = 180 > subtract 68 from both sides
4x=112 >divide both sides by 4
x=28
Please hurry I need it ASAP
(3X-5)^1/4+3=4
Your anwser should be x=2!
SHOW WORK
(Explanation below)
x=2
x = 2 is the solution of the equation
What is Equation?Two or more expressions with an Equal sign is called as Equation.
The given equation is [tex](3X-5)^(^1^/^4^) + 3 = 4[/tex]
We have to find the value of x
Subtracting 3 from both sides:
[tex](3X-5)^(^1^/^4^) = 1[/tex]
Raising both sides to the fourth power:
3X - 5 = 1^4
3X - 5 = 1
Adding 5 to both sides:
3X = 6
Dividing by 3:
X = 2
Therefore, x = 2 is the solution of the equation
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You get a job as a nurse. Your salary for the first year is $74,000. You will
receive a 1.2% increase every year. If you could save your entire salary, how
much money would you have in 5 years? Round to the nearest cent (2 decimal
places). Hint: What is a₁? What is r? Then use the formula for a finite
geometric series.
Answer: The amount of money you would have in 5 years if you could save your entire salary with a 1.2% increase every year would be $87,357.41.
Explanation:
The initial term, a₁, is $74,000, and the common ratio, r, is 1 + 1.2% = 1.012. To find the sum of the first 5 terms, we use the formula for a finite geometric series:
S₅ = a₁(1 - r⁶)/(1 - r)
Plugging in the values, we get:
S₅ = $74,000(1 - 1.012⁵)/(1 - 1.012) = $87,357.41 (rounded to the nearest cent)
Therefore, if you save your entire salary, you would have approximately $87,357.41 in 5 years with a 1.2% increase every year.
Select the correct answer
a mine extracts 2 metric tons of coal in an hour. the
number of hours spent mìning, which expression re
oa. the expression is at. the amount of ore
ob. the expression
The expression that represents the amount of ore sold and how much ore can the mine sell after extracting ore for 12 hours is option B: The expression is 2t−14t. The amount of ore is 21 metric tons.
The reasoning for the selection of the expression and amount of ore can the mine sell after extracting ore for 12 hours is as follows.
1: Determine the amount of coal used for electricity generation in terms of t.
The mine uses 14 tons of coal every hour, so the total amount used for electricity generation is 14t.
2: Determine the total amount of coal extracted in terms of t.
The mine extracts 2 tons of coal every hour, so the total amount extracted is 2t.
3: Calculate the amount of coal sold in terms of t.
To find the amount of coal sold, subtract the amount used for electricity generation from the total amount extracted: 2t - 14t.
4: Determine the amount of coal sold after 12 hours.
Substitute t = 12 into the expression:
2(12) - 14(12) = 24 - 168 = -144.
However, since the mine uses 14 tons of the extracted coal every hour, it cannot sell more coal than it extracts. So, the correct expression should be 2t - 14 (without the t for the amount used for electricity generation).
5: Calculate the amount of coal sold after 12 hours using the corrected expression.
Substitute t = 12 into the expression: 2(12) - 14 = 24 - 14 = 10 metric tons.
The correct expression should be 2t - 14, and the amount of coal the mine can sell after extracting coal for 12 hours is 10 metric tons. Hence, the correct answer is option B.
Note: The question is incomplete. The complete question probably is: A mine extracts 2 metric tons of coal in an hour. The mine uses 14 ton of the extracted coal every hour to generate electricity for the mine and sells the rest. If t is the number of hours spent mining, which expression represents the amount of ore sold? How much ore can the mine sell after extracting ore for 12 hours? A) The expression is 2t−1/4t. The amount of ore is 23 3/4 metric tons. B) The expression is 2t−1/4t. The amount of ore is 21 metric tons. C) The expression is 2t+1/4t. The amount of ore is 24 metric tons. D) The expression is 2t+1/4t. The amount of ore is 24 1/4 metric tons.
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On a coordinate plane, a line segment has endpoints P(6,2) and Q(3. 8). 9. Point M lies on PQ and divides the segment so that the ratio of PM-MQ is 2-3. What are the coordinates of point M?
The coordinates of point M come out to be 4.8, 4.4
This case is solved by using the section formula which states that
The coordinate of point P that divides the line segment AB in the ratio of m:n where the coordinate of A is [tex]x_1,y_1[/tex] and the B is [tex]x_2,y_2[/tex] is described as
[tex]\frac{mx_2+nx_1}{m+n}[/tex],[tex]\frac{my_2+ny_1}{m+n}[/tex]
The line to be divided = PQ
Coordinates of P = (6,2)
Coordinates of Q = (3,8)
Ratio = 2:3
Thus, the coordinates of M = [tex]\frac{2*3+3*6}{2+3}[/tex],[tex]\frac{8*2+2*3}{2+3}[/tex]
= 24/5 , 22/5
= 4.8, 4.4
Point M with coordinates (4.8,4.4) lies on PQ and divides the segment so that the ratio of PM-MQ is 2-3
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i need help its due in 2 hours
Answer:
C. The product of two irrational numbers is irrational.
Example: √3•√3=3
Let R(x). C(x), and P(x) be, respectively, the revenue, cost, and profit, in dollars, tomi the production and sale of x items. I R(%) = 6x and C(X) = 0.001x^2 + 1 8x + 40.
find each of the following
a) P(x)
b) R(200). C(200), and P(200)
c) R'(. C't and P'(x)
d) R' (200). C'(200), and P' (200)
a) P(x) = R(x) - C(x) = 6x - (0.001x^2 + 18x + 40) = -0.001x^2 - 12x - 40
b) R(200) = 6(200) = 1200
C(200) = 0.001(200)^2 + 18(200) + 40 = 4000
P(200) = R(200) - C(200) = 1200 - 4000 = -2800
c) R'(x) = 6
C'(x) = 0.002x + 18
P'(x) = R'(x) - C'(x) = 6 - (0.002x + 18) = -0.002x - 12
d) R'(200) = 6
C'(200) = 0.002(200) + 18 = 18.4
P'(200) = -0.002(200) - 12 = -12.4
Here are the answers to each part:
a) P(x) is the profit function, which is calculated as the difference between the revenue function and the cost function: P(x) = R(x) - C(x). In this case, P(x) = 6x - (0.001x^2 + 18x + 40).
b) To find R(200), C(200), and P(200), plug x = 200 into each function:
R(200) = 6(200) = 1200
C(200) = 0.001(200^2) + 18(200) + 40 = 7600
P(200) = 1200 - 7600 = -6400
c) To find R'(x), C'(x), and P'(x), we need to find the derivative of each function with respect to x:
R'(x) = d(6x)/dx = 6
C'(x) = d(0.001x^2 + 18x + 40)/dx = 0.002x + 18
P'(x) = R'(x) - C'(x) = 6 - (0.002x + 18)
d) To find R'(200), C'(200), and P'(200), plug x = 200 into each derivative function:
R'(200) = 6
C'(200) = 0.002(200) + 18 = 18.4
P'(200) = 6 - 18.4 = -12.4
I hope this helps! Let me know if you have any further questions.
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Identify the random variable in each distribution, and classify it as
discrete or continuous. Explain your reasoning.
1) The number of hits for the players of a baseball team.
2) The distances traveled by the tee shots in a golf
The random variable in the first situation is the number of hits for the players of a baseball team and in the second situation is the distance traveled by the tee shots in a golf game.
1) The random variable in this distribution is the number of hits for the players of a baseball team. This is a discrete random variable because hits are counted as whole numbers and cannot take on non-integer values.
2) The random variable in this distribution is the distance traveled by the tee shots in a golf game. This is a continuous random variable because the distances traveled can take on any value within a certain range, including non-integer values. The exact distance traveled by a tee shot can be measured to any degree of precision, and there are infinitely many possible distances within the range of possible outcomes. Therefore, it is a continuous random variable.
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Find the inverse for each relation: 4 points each
1. {(1,‐2), (2, 3),(3, ‐3),(4, 2)}
2. {(4,2),(5,1),(6,0),(7,‐1)}
Find an equation for the inverse for each of the following relations.
3. Y=-8x+3
4. Y=2/3x-5
5. Y=1/2x+10
6. Y=(x-3)^2
Verify that f and g are inverse functions.
7. F(x)=5x+2;g(x)=(x-2)/5
8. F(x)=1/2x-7;g(x)=2x+14
The inverse for each relation:
1. {(1,‐2), (2, 3),(3, ‐3),(4, 2)} - {(-2, 1), (3, 2), (-3, 3), (2, 4)}
2. {(4,2),(5,1),(6,0),(7,‐1)} - {(2, 4), (1, 5), (0, 6), (-1, 7)}
3. Inverse equation: y=(-1/8)x+3/8
4. Inverse equation: y=3/2x+15/2
5. Inverse equation: y=2x-20
6. Inverse equation: y=[tex]x^{(1/2)}+3[/tex]
7. Since fog(x) = gof(x) = x, f and g are inverse functions.
8. Since fog(x) = gof(x) = x, f and g are inverse functions.
1. To find the inverse of the relation, we need to swap the positions of x and y for each point and then solve for y.
{(1, -2), (2, 3), (3, -3), (4, 2)}
Inverse: {(-2, 1), (3, 2), (-3, 3), (2, 4)}
2. Again, we swap x and y and solve for y.
{(4, 2), (5, 1), (6, 0), (7, -1)}
Inverse: {(2, 4), (1, 5), (0, 6), (-1, 7)}
3. To find the inverse equation for y=-8x+3, we swap x and y and solve for y.
x=-8y+3
x-3=-8y
y=(x-3)/-8
Inverse equation: y=(-1/8)x+3/8
4. To find the inverse equation for y=2/3x-5, we swap x and y and solve for y.
x=2/3y-5
x+5=2/3y
y=3/2(x+5)
Inverse equation: y=3/2x+15/2
5. To find the inverse equation for y=1/2x+10, we swap x and y and solve for y.
x=1/2y+10
x-10=1/2y
y=2(x-10)
Inverse equation: y=2x-20
6. To find the inverse equation for y=(x-3)², we swap x and y and solve for y.
x=(y-3)²
[tex]x^{(1/2)}=y-3[/tex]
[tex]y=x^{(1/2)}+3[/tex]
Inverse equation: [tex]y=x^{(1/2)}+3[/tex]
7. To verify that f(x)=5x+2 and g(x)=(x-2)/5 are inverse functions, we need to show that fog(x)=gof(x)=x for all x in the domain of f and g.
fog(x) = f(g(x)) = f((x-2)/5) = 5((x-2)/5) + 2 = x
gof(x) = g(f(x)) = g(5x+2) = ((5x+2)-2)/5 = x/5
Since fog(x) = gof(x) = x, f and g are inverse functions.
8. To verify that f(x)=1/2x-7 and g(x)=2x+14 are inverse functions, we need to show that fog(x)=gof(x)=x for all x in the domain of f and g.
fog(x) = f(g(x)) = f(2x+14) = 1/2(2x+14) - 7 = x
gof(x) = g(f(x)) = g(1/2x-7) = 2(1/2x-7) + 14 = x
Since fog(x) = gof(x) = x, f and g are inverse functions.
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The regular price of a red T-shirt is $6.93. Ernest has a coupon for $6.75 off. How much will Ernest pay for the T-shirt?
Answer:
18 cent
Step-by-step explanation:
Evaluate the integrals (Indefinite and Definite) and Simplify. 5 (a) 5 (5:-* - - 5 sin ) : dc xl1 (v) [(1822–1 18x)(6x3 – 9x2 – 3)6 dx ° ? (c) | Viana sec2 х dx (d) os Venta de Зх dx Væ+4 2 (e) ( 120 dax V1 + 2x2
(a) Indefinite integral of 5(5x^4 - 5sinx)dx is (5/3)x^5 + 5cosx + C. Definite integral over [0, π/2] is (125π/6) - 5.
We can evaluate the indefinite integral by applying the power rule and integration by substitution. The definite integral can be evaluated by substituting the limits of integration and simplifying.
(b) Indefinite integral of [(18x^2 - 1)(6x^3 - 9x^2 - 3)]^6dx is (18x^11 - 77x^9 + 126x^7 - 108x^5 + 49x^3 - 9x) / 11 + C.
To simplify the given expression, we can first expand the polynomial and then apply the power rule to integrate each term. The constant of integration can be added at the end.
(c) Definite integral of ∫tan^2(x)sec^2(x)dx over [0,π/4] is 1.
We can use the trigonometric identity sec^2(x) - 1 = tan^2(x) to simplify the integrand. Then we can apply the power rule and substitute the limits of integration to evaluate the definite integral.
(d) Indefinite integral of ∫(x+4)^2√(3x^2+4)dx is (1/15)(3x^2+4)^(3/2)(x+4) - (4/45)(3x^2+4)^(3/2) + C.
We can use substitution to simplify the integrand by setting u = 3x^2 + 4. After integrating, we can substitute back for u and simplify the constant of integration.
(e) Indefinite integral of ∫(120/(1+2x^2))dx is 60√2tan^(-1)(√2x) + C.
We can use substitution to simplify the integrand by setting u = 1 + 2x^2. After integrating, we can substitute back for u and simplify the constant of integration.
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The time it takes Alice to walk to the bus stop from her home is normally distributed with mean 13 minutes and variance 4 minutes squared. The waiting time for the bus to arrive is normally distributed with mean 5 minutes and standard deviation 2 minutes. Her bus journey to the bus loop is a normal variable with mean 24 and standard deviation 5 minutes. The time it take Alice to walk from the bus loop to the lecture theatre to attend stats class is normally distributed with mean 18 minutes and variance 4 minutes. The total time taken for Alice to travel from her home to her STAT 251 lecture is Normally distributed.
Part a) What is the mean travel time (in minutes)?
Part b) What is the standard deviation of Alice's travel time (in minutes, to 2 decimal places)?
Part c) The STAT 251 class starts at 8 am sharp. Alice leaves home at 7 am. What is the probability (to 2 decimal places) that Alice will not be late for her class?
The mean travel time is 60 minutes, the standard deviation is approximately 6.08 minutes, and the probability that Alice will not be late for her class is 0.50 or 50%.
How to find the mean time interval?To find the mean travel time, we need to add up the mean times for each stage of Alice's journey. Let's calculate it step by step:
Step 1: Alice's walking time from home to the bus stop:
Mean walking time = 13 minutes
Step 2: Waiting time for the bus to arrive:
Mean waiting time = 5 minutes
Step 3: Bus journey time from the bus loop:
Mean bus journey time = 24 minutes
Step 4: Walking time from the bus loop to the lecture theatre:
Mean walking time = 18 minutes
Now, let's calculate the total mean travel time:
Mean travel time = Mean walking time + Mean waiting time + Mean bus journey time + Mean walking time
= 13 + 5 + 24 + 18
= 60 minutes
So, the mean travel time is 60 minutes.
How to find the standard deviation?To find the standard deviation of Alice's travel time, we need to calculate the variance for each stage and then sum them up. Finally, we take the square root to get the standard deviation. Let's calculate it step by step:
Step 1: Alice's walking time from home to the bus stop:
The variance of walking time = 4 minutes squared
Step 2: Waiting time for the bus to arrive:
The standard deviation of waiting time = 2 minutes
Step 3: Bus journey time from the bus loop:
The standard deviation of bus journey time = 5 minutes
Step 4: Walking time from the bus loop to the lecture theatre:
The variance of walking time = 4 minutes squared
Now, let's calculate the total variance of travel time:
Variance of travel time = Variance of walking time + Variance of waiting time + Variance of bus journey time + Variance of walking time
= 4 + 4 + 25 + 4
= 37 minutes squared
Finally, the standard deviation of travel time is the square root of the variance:
The standard deviation of travel time = [tex]\sqrt(37)[/tex]
≈ 6.08 minutes (rounded to 2 decimal places)
So, the standard deviation of Alice's travel time is approximately 6.08 minutes.
How to find the probability?To find the probability that Alice will not be late for her class, we need to calculate the z-score for the desired arrival time and then find the corresponding probability from the standard normal distribution table. Let's calculate it step by step:
Step 1: Calculate the total travel time from home to the lecture theatre:
Total travel time = Mean travel time = 60 minutes
Step 2: Calculate the difference between the desired arrival time and the total travel time:
Time difference = 8 am - 7 am = 1 hour = 60 minutes
Step 3: Calculate the z-score using the formula:
z = (Time difference - Mean travel time) / Standard deviation of travel time
z = [tex]\frac{(60 - 60) }{ 6.08}[/tex]
z = 0
Step 4: Find the probability corresponding to the z-score from the standard normal distribution table.
Since the z-score is 0, the probability is 0.50 (or 50%).
Therefore, the probability (to 2 decimal places) that Alice will not be late for her class is 0.50 or 50%.
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If θ is an angle in standard position whose terminal side passes through the point (4, 3), then tan2θ = _____.
3/2
24/7
7/24
21/32
To find the value of tan(θ), we first need to calculate the values of sine and cosine for the given point (4, 3) terminal side. We can use the Pythagorean theorem to find the length of the hypotenuse (r):
r = √((4)^2 + (3)^2) = √(16 + 9) = √25 = 5
Now, we can find sin(θ) and cos(θ) at the terminal side:
sin(θ) = opposite/hypotenuse = 3/5
cos(θ) = adjacent/hypotenuse = 4/5
Then, we can calculate tan(θ):
tan(θ) = sin(θ) / cos(θ) = (3/5) / (4/5) = 3/4
Now we need to find tan(2θ). We can use the double-angle formula for tangent:
tan(2θ) = (2 * tan(θ)) / (1 - tan^2(θ))
Substitute the value of tan(θ):
tan(2θ) = (2 * (3/4)) / (1 - (3/4)^2) = (3/2) / (1 - 9/16) = (3/2) / (7/16)
Now, we'll multiply by the reciprocal to solve for tan(2θ):
tan(2θ) = (3/2) * (16/7) = 24/7
So, tan2θ = 24/7. Your answer is: 24/7
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What is the value of B? Bº 58° 61°
Answer:
61 degrees
Step-by-step explanation:
Triangle interior measures add up to 180 degrees.
61 + 58 + x = 180
119 + x = 180
x = 61
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compute (7 4/9 -8)*3.6-1.6*(1/3-3/4)+ 1 2/5 ÷(0.35)
The value of (7 4/9 -8)*3.6-1.6*(1/3-3/4)+ 1 2/5 ÷(0.35) is given as 241/54.
How to solve for the value(7 4/9 -8) = -5/9.
3.6-1.6 = 2.0
1/3-3/4 = 1/3 - 3/4
= 4/12 - 9/12
= -5/12
we will have -5/9 * 2 = -10/9.
-10/9 * -5/12
10/9 * -5/12 = (10 * 5) / (9 * 12) = 50/108
We can simplify this fraction by dividing both the numerator and denominator by their greatest common factor, which is 2:
50/108 = 25/54
we will have
25/54 + 1 2/5 ÷(0.35)
1 2/5 ÷ 0.35 = (7/5) ÷ (35/100) = (7/5) * (100/35) = 4
Now, we can substitute this value into the expression:
25/54 + 4 = (25/54) + (216/54) = 241/54
Therefore, the value of the expression 25/54 + 1 2/5 ÷(0.35) is 241/54.
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You can find the area of a trapezoid by decomposing it into a rectangle and one or more triangles you can find the area of a kite by decomposing it into triangles
The statement on finding the areas of a trapezoid and a kite are True.
How to find area by decomposing shapes ?To determine the area of a trapezoid, it can be broken down into separate geometrical shapes. One possible breakdown would include a rectangle with two adjacent right triangles or an isosceles triangle with one right triangle configuration. By calculating each smaller compartment's size and summing them together, one can obtain the total area for the trapezoid.
Similarly, in order to find the surface area of a kite shape, drawing a diagonal creates two adjoining triangles that are easily computed individually then summed.
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Options for this question :
True
False