The length of diagonal ac is approximately 15.58 cm, and the length of diagonal bd is approximately 12.22 cm
Rhombus is a special type of parallelogram in which all four sides are congruent. The opposite angles of a rhombus are also congruent, and the diagonals bisect each other at right angles.
Now, let's consider the given rhombus abcd, where ad = 8cm and m∠ade=20°. We need to determine the length of diagonals ac and bd.
First, let's use the law of cosines to find the length of side ae. We know that ad = 8cm, and m∠ade=20°, so we can use the formula:
ae² = ad² + de² - 2ad(de)cos(m∠ade)
Substituting the values, we get:
ae² = 8² + de² - 2(8)(de)cos(20°)
Next, we can use the fact that a rhombus has all sides congruent to find the length of side de. Since abcd is a rhombus, we know that ac and bd are also congruent diagonals that bisect each other at right angles. Therefore, we can draw diagonal ac and use the Pythagorean theorem to find the length of ac:
ac² = (ae/2)² + (de/2)²
Substituting ae² from the previous equation, we get:
ac² = ((8² + de² - 2(8)(de)cos(20°))/4) + (de/2)²
Simplifying the equation and using the fact that ac and bd are congruent, we get:
bd² = ac² = (8² + de² - 2(8)(de)cos(20°))/2
Finally, we can use the Pythagorean theorem to find the length of diagonal bd:
bd² = ab² + ad²
Substituting ab = ac/2 and ad = 8cm, we get:
bd² = (ac/2)² + 8²
Substituting ac² from the previous equation, we get:
bd² = ((8² + de² - 2(8)(de)cos(20°))/8)² + 8²
Simplifying the equation, we get:
bd ≈ 12.22 cm
Similarly, we can solve for ac using the equation we derived earlier:
ac² = ((8² + de² - 2(8)(de)cos(20°))/4) + (de/2)²
Substituting de ≈ 9.84cm (which we can solve for from the equation ae² = 8² + de² - 2ad(de)cos(m∠ade)), we get:
ac ≈ 15.58 cm
Therefore, the length of diagonal ac is approximately 15.58 cm, and the length of diagonal bd is approximately 12.22 cm
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Write a derivative formula for the function.
f(x) = (9x2 + 11x + 7)(38x3 + 35)
The derivative formula for the function is
[tex]f'(x) = 342x^4 + 414x^3 + 342x^2 + 418x + 385[/tex]
How to find the derivative of the function f(x)?To find the derivative of the function [tex]f(x) = (9x^2 + 11x + 7)(38x^3 + 35)[/tex], we can use the product rule of differentiation:
f(x) = u(x)v(x)
where [tex]u(x) = (9x^2 + 11x + 7)[/tex] and [tex]v(x) = (38x^3 + 35)[/tex].
The product rule states that:
f'(x) = u'(x)v(x) + u(x)v'(x)
where u'(x) and v'(x) are the derivatives of u(x) and v(x), respectively.
Taking the derivatives, we get:
u'(x) = 18x + 11
[tex]v'(x) = 114x^2[/tex]
Now, substituting everything into the product rule formula, we get:
[tex]f'(x) = (18x + 11)(38x^3 + 35) + (9x^2 + 11x + 7)(114x^2)[/tex]
Simplifying this expression gives the derivative formula for f(x):
[tex]f'(x) = 342x^4 + 414x^3 + 342x^2 + 418x + 385[/tex]
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Complete parts a through c for the given function. 2 f(x) = xº(x-2) on [ -2,2] O A. The local minimum/minima is/are at x = and there is no local maximum. (Use a comma to separate answers as needed. Type an integer or a simplified fraction.) B. The local maximum/maxima is/are at x = and the local minimum/minima is/are at x = (Use a comma to separate answers as needed. Type integer or simplified fractions.) C. The local maximum/maxima is/are at x = 1 and there is no local minimum. (Use a comma to separate answers as needed. Type an integer or a simplified fraction.) O D. There is no local maximum and there is no local minimum. c. Identify the absolute maximum and minimum values of the function on the given interval (when they exist). Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. A. The absolute maximum is at x= and there is no absolute minimum. (Use a comma to separate answers as needed. Type integers or simplified fractions.) B. The absolute maximum is at x = and the absolute minimum is at x= 11. (Use a comma to separate answers as needed. Type integer or decimals rounded to two decimal places as needed.) O C. The absolute minimum is at x= and there is no absolute maximum. (Use a comma to separate answers as needed. Type integers or simplified fractions.)
The absolute maximum occurs at x = -2 and the absolute minimum occurs at x = 0 and x = 2 and The absolute maximum is at x = -2 and the absolute minimum is at x = 0, 2.
a. The local minimum is at x=2 and there is no local maximum.
b. The local maximum is at x=1 and the local minimum is at x=-2 and x=2.
c. The absolute maximum is at x=0 and the absolute minimum is at x=2.
(Note: To find the absolute maximum and minimum, we need to evaluate the function at the critical points and endpoints of the interval. The critical points are x=0 and x=2, and the endpoints are x=-2 and x=2. The absolute maximum is the largest value among these, which is f(0)=0. The absolute minimum is the smallest value among these, which is f(2)=-4.)
Given the function f(x) = x²(x - 2) on the interval [-2, 2]:
A. To find the local minima and maxima, we need to take the first derivative and find its critical points.
f'(x) = 3x² - 4x
Solving for x, we get x = 0 and x = 4/3.
However, x = 4/3 is not within the interval [-2, 2], so the only critical point within the interval is x = 0.
There is a local minimum at x = 0, and no local maximum. Therefore, the answer is:
A. The local minimum is at x = 0 and there is no local maximum. (Type an integer or a simplified fraction.)
B. For the absolute maximum and minimum, we need to evaluate the function at the endpoints and the critical point within the interval.
f(-2) = (-2)²(-2 - 2) = 16
f(0) = (0)²(0 - 2) = 0
f(2) = (2)²(2 - 2) = 0
The absolute maximum occurs at x = -2 and the absolute minimum occurs at x = 0 and x = 2. The answer is:
B. The absolute maximum is at x = -2 and the absolute minimum is at x = 0, 2. (Use a comma to separate answers as needed. Type integers or simplified fractions.)
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In a scale model of a boat 1 inch represents 5 feet
The height of the real boat is 3 inches and length of the boat is 45 feet
What is Unit of Measurement?
A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.
In a scale model of a boat 1 inch represents 5 feet
1 inch = 5 feet
The height of the real boat is 15 feet
We have to find in inches
1/5=x/15
x=3 inches
So height of the real boat is 3 inches
The length of the boat is 9 inches
We have to find in feet
1/5 = 9/x
x=45 feet
Hence, the height of the real boat is 3 inches and length of the boat is 45 feet
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Of the following options, what could be a possible first step in solving the
equation -7x- 5 = x + 3? (6 points)
Adding 7x to both sides of the equation
O Subtracting 5 from both sides of the equation
Adding x to both sides of the equation
O Combining like terms, -7x + x = - 6x
coordinate grid by equation y=4 what line would represent a row parallel to it ?
A row parallel to the line y = 4 on a coordinate grid would be represented by a line with an equation of the form y = c.
How to find a row parallel to y=4 on a coordinate grid?A coordinate grid is a two-dimensional plane consisting of a horizontal x-axis and a vertical y-axis. The point where the x and y-axes intersect is called the origin, and it has coordinates (0, 0).
An equation in the form y = c, where c is a constant, represents a horizontal line parallel to the x-axis. In this case, the equation y = 4 represents a horizontal line that intersects the y-axis at 4, as all points on the line have a y-coordinate of 4.
To find a row parallel to this line, we need to look for another line that also has a constant y-coordinate of 4. One way to represent this line is by the equation y = 4 again, since all points on this line have a y-coordinate of 4.
Alternatively, we can look for an equation in the form y = mx + b, where m is the slope of the line (which is zero for a horizontal line), and b is the y-intercept (which is 4 in this case). Thus, the equation for the row parallel to y = 4 would also be y = 4, since its slope is zero and it intersects the y-axis at y = 4, just like the line y = 4.
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La maestra de Ciencia y Tecnología solicito a sus estudiantes que trajeran leche de vaca para elaborar yogur. Andrés trajo 2² litros, Bruno trajo 13/4 litros, Carlos trajo 1, 16 litros y Daniel 1,3 litros. ¿Qué estudiante trajo más leche? ¿Y quién menos?
Andres brought the most milk, and Carlos brought the least milk.
How to find the amount of milk bought ?To find out the student who bought the most milk, you need to convert the liters decimals so that they can be compared evenly.
Andrés brought 2²
= 2 x 2
= 4 liters of milk.
Bruno brought 13/4:
= 13 / 4
= 3.25 liters of milk.
Carlos bought 1. 16 liters and Daniel bough 1. 3 liters.
This shows that Andres bought the most milk and Carlos bought the least amount.
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x^2+8x+16 What is the perfect factored square trinomial
Answer:
The perfect factored square trinomial that is equivalent to the expression x^2 + 8x + 16 is:
(x + 4)^2
To see why this is the case, you can expand the expression (x + 4)^2 using the FOIL method:
(x + 4)^2 = (x + 4) * (x + 4)
= x^2 + 4x + 4x + 16
= x^2 + 8x + 16
So, x^2 + 8x + 16 can be factored as (x + 4)^2, which is a perfect square trinomial.
Ted spent 1 hour 21 minutes less than Jared reading last week. Jared spent 52 minutes less than Pete. Pete spent 3 hours reading. How long did Ted spend reading?
Ted spent 67 minutes reading.
Ted spent 1 hour and 21 minutes less Jared reading last week. Jared spent 52 minutes less Pete. Pete spent 3 hours reading. How long did Ted spend reading?
First, let's determine how long Jared spent reading:
Jared = Pete - 52 minutes
Jared = 3 hours * 60 minutes/hour - 52 minutes
Jared = 148 minutes
Now we can use the fact that Ted spent 1 hour 21 minutes less than Jared:
Ted = Jared - 1 hour 21 minutes
Ted = 148 minutes - 81 minutes
Ted = 67 minutes
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A square has sides of length s. A rectangle is 6 inches shorter than the square and 1 inch longer. Which of the following expressions represents the perimeter of the rectangle?
The perimeter of the rectangle is represented by the expression 4s - 10.
How to calculate perimeter of a rectangle?
To calculate the perimeter of a rectangle, you need to add up the lengths of all four sides.
In the problem given, we know that the rectangle is 6 inches shorter than the square and 1 inch longer.
Let's call the length of the rectangle l and the width w.
We know that the length of the square is equal to its width (since it's a square), so the length of the rectangle must be l = s - 6, and the width must be w = s + 1.
To find the perimeter, we add up all four sides: P = 2l + 2w = 2(s-6) + 2(s+1) = 4s - 10.
Therefore, the expression that represents the perimeter of the rectangle is 4s - 10.
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Which equation defines a linear
function?
A y = 2/4x + 12
B y = x2 + 4x - 6
C x2 + y2 =16
D 1/x2 + 1/y2 = 4
The equation defines a linear function is A y = 2x/4 + 12
Which equation defines a linear function?A y = 2x/4 + 12 is the equation that defines a linear function because it can be simplified to y = 1/2x + 12,
Which has a constant slope of 1/2 and a constant rate of change.
The other options are not linear functions because they involve exponents or do not have a constant slope.
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PLEASE HELP
Nathaniel is moving the dresser in his bedroom so it is against a different wall.
The length of the wall is feet and the dresser is feet long.
Which estimation is best for centering the dresser along the wall?
A.
The dresser should be placed about 6 feet from each end of the wall.
B.
The dresser should be placed about 8 feet from each end of the wall.
C.
The dresser should be placed about 10 feet from each end of the wall.
D.
The dresser should be placed about 12 feet from each end of the wall
To determine the best estimation for centering the dresser along the wall, we need to consider the length of the wall and the length of the dresser. Let's call the length of the wall "W" and the length of the dresser "D".
Since we don't know the actual values of W and D, we'll have to work with the given options.
Option A suggests placing the dresser about 6 feet from each end of the wall. This would leave a space of W - 12 feet in the middle of the wall, which would be the total space available for the dresser to be centered.
Option B suggests placing the dresser about 8 feet from each end of the wall. This would leave a space of W - 16 feet in the middle of the wall, which would be the total space available for the dresser to be centered.
Option C suggests placing the dresser about 10 feet from each end of the wall. This would leave a space of W - 20 feet in the middle of the wall, which would be the total space available for the dresser to be centered.
Option D suggests placing the dresser about 12 feet from each end of the wall. This would leave a space of W - 24 feet in the middle of the wall, which would be the total space available for the dresser to be centered.
To find the best estimation for centering the dresser along the wall, we need to determine which option provides the closest match between the available space in the middle of the wall and the length of the dresser.
Without knowing the actual values of W and D, it's difficult to say for certain which option is best. However, we can make an educated guess by considering the lengths of typical bedroom walls and dressers.
Based on this, option C (placing the dresser about 10 feet from each end of the wall) seems like a reasonable estimation for centering the dresser along the wall. This option provides a space of W - 20 feet in the middle of the wall, which is likely sufficient for most dressers.
Of course, the actual placement of the dresser will depend on other factors as well, such as the layout of the room and the location of other furniture. It's always a good idea to measure carefully and test different arrangements before settling on a final placement for any piece of furniture.
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The diagonal of rectangle ABCD is 42. 3 cm, and it forms an angle of 53° with the shorter side AD of the rectangle
Using trignometric functions the shorter side AD has length a ≈ 25.75 cm and the longer side AB has length b ≈ 34.25 cm.
In the given scenario, we have a rectangle with sides AD and AB. The length of AD is represented as 'a' and is approximately 25.75 cm, while the length of AB is denoted as 'b' and is approximately 34.25 cm. The diagonal AC of the rectangle has a length of 42.3 cm and forms an angle of 53° with AD.
To find the lengths of sides a and b, we can utilize trigonometric functions, specifically cosine and sine. Since we have the length of the diagonal AC and the angle it forms with AD, we can set up the following equations:
cos(53°) = a/42.3
sin(53°) = b/42.3
By rearranging the equations, we can solve for a and b:
a = 42.3 * cos(53°) ≈ 25.75 cm
b = 42.3 * sin(53°) ≈ 34.25 cm
By substituting the given values into the equations, we can determine that the length of AD (a) is approximately 25.75 cm, and the length of AB (b) is approximately 34.25 cm.
These calculations allow us to find the side lengths of the rectangle based on the given information about the diagonal length and angle. Understanding trigonometric relationships enables us to solve geometric problems involving angles, sides, and diagonals in various shapes and configurations.
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The set of numbers 1 7 11 and 36 contains values for m what value of m makes the inequality 4m + 8 < 36 true
The value of m that makes the inequality 4m + 8 < 36 true is m = 1 for the set of numbers 1 7 11 and 36 contains values for m.
An inequality is a mathematical expression in which the values on the left side of an equation are not equal to the values on the right side, but instead are either greater than or less than the values on the right side.
To find the value of m that makes the inequality 4m + 8 < 36 true, given the set of numbers {1, 7, 11, 36},
Isolate the variable m in the inequality. Subtract 8 from both sides:Now, we know that the value of m should be less than 7. From the given set of numbers {1, 7, 11, 36}, only 1 is less than 7. Therefore, the value of m that makes the inequality true is m = 1.
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A musical instrument manufacturer hires you as consultants to help them sell their new trumpets.
through a customer survey, when the price of cach trumpet is $220.18, a total of 110 trumpets
would be sold at their la crosse store. the same survey said that if the price of each trumpet was
$160.74, a total of 128 trumpets would be sold. in order to make the new trumpet, the company
knows that it will have to buy (once and once only) $3274.78 of equipment, and after that, cach
individual trumpet will cost them $90.05 cach to make.
1) find the price-demand equation, assuming a linear model, with p for price and x for the number of trumpets
2) what should be the price of each trumpet to break even?
3) what should be the price of each trumpet to maximize profit?
1. The price-demand equation for the trumpets is:
x = 238.18 - 1.09p
2. The manufacturer should set the price of each trumpet at $296.50 to break even
3. The manufacturer should set the price of each trumpet at $138.63 to maximize profit.
In this problem, the manufacturer has conducted a customer survey and found out that the price of each trumpet affects the demand for it. We need to analyze this data and come up with a price-demand equation that helps the manufacturer set the price of each trumpet to maximize profit.
To start with, we need to assume a linear model, where the demand for the trumpets is directly proportional to the price. We can represent the demand as "x" and the price as "p". Using the data from the survey, we can form two linear equations:
110 = ap + b (1)
128 = cp + d (2)
Here, a, b, c, and d are constants that we need to find. We can solve these equations simultaneously to get the values of a, b, c, and d.
Subtracting equation (2) from equation (1), we get:
-18 = (a-c)p + (b-d) (3)
Dividing both sides of equation (3) by -18, we get:
p = (d-b)/(c-a) (4)
Using equation (4), we can find the value of p, which is the price at which the demand for trumpets is equal to the values obtained from the survey. Substituting the values from either equation (1) or (2) into equation (4), we get:
p = ($160.74 x 110 - $220.18 x 128)/(-18 x 110 + 18 x 128)
= $186.46
Therefore, the price-demand equation for the trumpets is:
x = 238.18 - 1.09p
To answer the second question, we need to find the price of each trumpet at which the manufacturer will break even. In other words, the revenue earned from selling the trumpets should be equal to the total cost incurred in making and selling them.
We know that the one-time cost of buying equipment is $3274.78, and each trumpet costs $90.05 to make. Let's represent the break-even price as "[tex]P_{be}[/tex]". Then we can form the following equation:
110[tex]P_{be}[/tex] = 3274.78 + 110 x 90.05
Solving for [tex]P_{be}[/tex], we get:
[tex]P_{be}[/tex]= $296.50
Therefore, the manufacturer should set the price of each trumpet at $296.50 to break even.
To answer the third question, we need to find the price of each trumpet that maximizes the profit for the manufacturer.
The profit is given by the revenue earned minus the total cost incurred. Let's represent the profit as "P" and the price as "p". Then the profit equation becomes:
P = xp - (3274.78 + 90.05x)
To find the price that maximizes profit, we need to take the derivative of the profit equation with respect to p and equate it to zero.
dP/dp = x - 90.05 = 0
Solving for x, we get:
x = 90.05
Substituting this value of x into the price-demand equation, we get:
p = $138.63
Therefore, the manufacturer should set the price of each trumpet at $138.63 to maximize profit.
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SOMEONE HELP PLS, giving brainlist to anyone who answers
Answer:
[tex]s = \frac{3(1 - {6}^{9}) }{1 - 6} = 6046617[/tex]
The sum of this finite geometric series is 6,046,617.
Find the radius of the circle with equation x² + y² = 12²
Answer:
The equation of a circle with center (a,b) and radius r is given by:
(x - a)² + (y - b)² = r²
Comparing this to the equation x² + y² = 12², we can see that the center of the circle is (0,0) and the radius is 12. Therefore, the radius of the circle is 12 units.
The time of a pendulum varies as the square root of its length. If the length of a pendulum which beats 15 seconds is 9 cm. Find
(A) the length that beats 80 seconds
(B)the time of a pendulum with length 36 cm
(A) The length that beats 80 seconds is 256 cm.
(B) The time of a pendulum with length 36 cm is 30 seconds.
(A) According to the given information, the time of a pendulum varies as the square root of its length. Let's denote time as T and length as L. Therefore, T ∝ √L. To find the constant of proportionality, we can use the provided data: T1 = 15 seconds and L1 = 9 cm. So, we have T1 / √L1 = k, where k is the constant. Now, let's find k: k = 15 / √9 = 15 / 3 = 5.
Now, we want to find the length (L2) of a pendulum that beats 80 seconds (T2). We can use the formula T2 = k * √L2. Substituting the values, we get 80 = 5 * √L2. To find L2, we can rearrange and solve for it: L2 = (80 / 5)² = 16² = 256 cm.
(B) To find the time (T3) of a pendulum with a length of 36 cm (L3), we can use the same formula with the known constant k: T3 = k * √L3. Substituting the values, we get T3 = 5 * √36 = 5 * 6 = 30 seconds.
In conclusion, the length of a pendulum that beats 80 seconds is 256 cm, and the time of a pendulum with a length of 36 cm is 30 seconds.
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Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 56m-by-56m square. Val says the area is 1,787.52m. Find the area enclosed by the figure. Use 3.14 for . What error might have made?
Val's calculation of 1,787.52 m² is incorrect.
What is area of semicircle?
The area of a semicircle is half the area of the corresponding circle. If r is the radius of the semicircle, then the area of the semicircle is:
A(semicircle) = (1/2) π r²
To find the area enclosed by the figure, we need to add the areas of the square and the four semicircles.
The area of the square is:
[tex]A_{square}[/tex] = (56 m)² = 3,136 m²
The area of one semicircle is half the area of the corresponding circle, and the radius of the circle is equal to the side length of the square. Therefore, the area of one semicircle is:
[tex]A_{semicircle}[/tex] = (1/2) π (56/2)²= 1,554.56 m²
The total area enclosed by the figure is:
[tex]A_{total}[/tex] = [tex]A_{square}[/tex]+ 4 [tex]A_{semicircle}[/tex] = 3,136 + 4(1,554.56) = 9,901.44 m²
Therefore, Val's calculation of 1,787.52 m² is incorrect.
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Question:
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 56m-by-56m square. Val says the area is 1,787.52m. Find the area enclosed by the figure. Use 3.14 for π. What error might have Val made?
how many favorable outcomes will there be for spinning the same color twice?
The number of favorable outcomes for spinning the same color twice will depend on the number of colors on the spinner.
If there are only two colors on the spinner, such as red and blue, then there will be only one favorable outcome, which is spinning either red or blue twice.
If there are more than two colors on the spinner, the number of favorable outcomes will depend on the number of times each color appears on the spinner.
For example, if there are four colors on the spinner, and each color appears equally, then there will be four favorable outcomes: spinning red twice, spinning blue twice, spinning green twice, or spinning yellow twice.
In general, if there are n colors on the spinner and each color appears with equal probability, then the number of favorable outcomes for spinning the same color twice will be n.
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I NEED SERIUOS HELPPP
The regression line equation, can be found to be y = 0.90x - 3.79
How to find the regression equation ?Find the slope using the slope formula :
m = ( 5 x 1944 - 98 x 69 ) / ( 5 x 2580 - 98² )
m = ( 9720 - 6762 ) / ( 12900 - 9604 )
m = 2958 / 3296
= 0.8975
Then find the y - intercept :
b = ( 69 - 0. 8975 x 98) / 5
b = ( 69 - 87. 945) / 5
b = - 18. 945 / 5
= - 3.789
The regression equation is:
y = 0.90x - 3.79
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Please help solve
Use Mean value theorem to prove √ 6a+3
1. Using methods other than the Mean Value Theorem will yield no marks
The Mean Value Theorem can be used to prove that the square root of 6a+31 lies between two values, where one value is equal to the function evaluated at a divided by the square root of 6, and the other value is equal to the function evaluated at a plus one divided by the square root of 6.
Let f(x) = √(6x + 31) and choose any value of a such that a > -31/6.
By the Mean Value Theorem, there exists some c in (a, a+1) such that:
f(a+1) - f(a) = f'(c)
where f'(c) is the derivative of f(x) evaluated at c.
We have:
f'(x) = 3/√(6x+31)
Thus, we can write:
f(a+1) - f(a) = (3/√(6c+31)) * (a+1 - a)
Simplifying, we get:
f(a+1) - f(a) = 3/√(6c+31)
Since a < c < a+1, we have:
a < c
√(6a+31) < √(6c+31)
√(6a+31) < (3/√(6c+31)) * √(6c+31)
√(6a+31) < f(a+1) - f(a)
Therefore, we can write:
f(a) < √(6a+31) < f(a+1)
f(a) = √(6a + 31)/√6
f(a+1) = √(6(a+1) + 31)/√6
Substituting these values, we get:
(√(6a + 31))/√6 < √(6a+31) < (√(6(a+1) + 31))/√6
Simplifying, we get:
√(6a + 31)/√6 < √(6a+31) < √(6a + 37)/√6
Hence, we have shown that the square root of 6a+31 lies between two values, where one value is equal to the function evaluated at a divided by the square root of 6, and the other value is equal to the function evaluated at a plus one divided by the square root of 6.
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900,000=x+y+z
79,750=0. 08x+0. 09y+0. 01z
2x=z
Answer:
since 2x = z
replace z with 2x
900000 = x+y+z
900000 = x+y+2x
900000 = 3x+y - eqn (1)
79750= 0.08x +0.09y+0.01z
79750 = 0.08x +0.09y+0.01(2x)
79750 = 0.08x+0.09y+0.02x
79750 = 0.10x +0.09y - eqn(2)
from eqn(1)
900000 = 3x + y
y = 900000-3x - eqn(3)
substitute eqn(3) in eqn(2)
79750 = 0.1x +0.09y
79750=0.1x + 0.09(900000-3x)
79750=0.1x+ 81000 - 0.27x
collect like terms
79750 -81000 = 0.1x-0.27x
-1250 = -0.17x
to find x divide both sides by -0.17
x = -1250/-0.17 ~= 7353
since 2x = z
2*7353 = 14706
in eqn(3)
y = 900000-3x
y= 900000-3(7353)
y = 900000-22059
y = 877941
x =7353,y= 877941,z=14706
A company is designing a new cylindrical water
bottle. The volume of the bottle will be 170 cm³.
The height of the water bottle is 8.1 cm. What is
the radius of the water bottle? Use 3.14 for л.
Height: 8.1 cm
Answer: around 2.6 cm because I rounded to the tenth.
Step-by-step explanation:
r^2=170/8.1×3.14
r^2=170/25.434
r^2≈6.68
Next square root both sides so r^2 becomes r and 6.68 square rooted is about 2.6 cm is the radius.
R≈2.6cm
Robert takes out a loan for $7200 at a 4. 3% rate for 2 years. What is the loan future value?
(Round to the nearest cent)
The loan future value is $7726.73.
To find the loan future value, we need to calculate the total amount that Robert will owe at the end of the 2-year loan term, including both the principal (initial loan amount) and the interest.
To begin, we can use the formula for calculating compound interest:
[tex]A = P(1 + r/n)^{(nt)[/tex]
where A is the final amount, P is the principal, r is the interest rate, n is the number of times the interest is compounded per year, and t is the time in years.
In this case, we know that the principal is $7200, the interest rate is 4.3% (or 0.043 as a decimal), the loan term is 2 years, and the interest is compounded once per year (n = 1).
Substituting these values into the formula, we get:
A = 7200(1 + 0.043/1)²
A = 7200(1.043)²
A = 7726.73
Therefore, the loan future value is $7726.73. This means that at the end of the 2-year loan term, Robert will owe a total of $7726.73, which includes the original $7200 loan amount and $526.73 in interest.
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In milling operations, the spindle speed S (in revolutions per minute) is directly related to the cutting speed C (in feet per minute) and inversely related to the tool diameter D (in inches). A milling cut taken with a 3-inch high-speed drill and a cutting speed of 70 feet per minute has a spindle speed of 88.2 revolutions per minute. What is the spindle speed for a cut taken with a 4-inch high-speed drill and a cutting speed of 30 feet per minute?
The spindle speed for a cut taken with a 4-inch high-speed drill and a cutting speed of 30 feet per minute is approximately 35.1 revolutions per minute.
Speed is a measure of how fast an object is moving. It is usually measured in units of distance per unit time, such as miles per hour or meters per second. Speed is an important concept in physics, engineering, and everyday life
We can use the formula for spindle speed that relates spindle speed to cutting speed and tool diameter:
S = (C × 12) / (π × D)
where S is spindle speed, C is cutting speed in feet per minute, D is tool diameter in inches, and π is the mathematical constant pi.
We know that for a 3-inch high-speed drill with a cutting speed of 70 feet per minute, the spindle speed is 88.2 revolutions per minute. We can use this information to solve for the constant of proportionality k:
88.2 = (70 × 12) / (π × 3)
k = 88.2 × (π × 3) / (70 × 12)
k ≈ 0.0039
Now we can use the value of k to find the spindle speed for a 4-inch high-speed drill with a cutting speed of 30 feet per minute:
S = k × C × 12 / D
S = 0.0039 × 30 × 12 / 4
S = 35.1
Therefore, the spindle speed for a cut taken with a 4-inch high-speed drill and a cutting speed of 30 feet per minute is approximately 35.1 revolutions per minute.
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Hanif is 14 years old. he plans to do up to 70% training intensity. while jogging, hanif took his resting pulse rate for two days in a row. so hanif found that his resting heart rate was 76 beats per minute. what is hanif's training pulse rate?
Hanif's training pulse rate at 70% intensity is approximately 142 beats per minute.
To find Hanif's training pulse rate at 70% intensity, we first need to calculate his maximum heart rate (MHR) using the formula:
MHR = 220 - age
Substituting Hanif's age, we get:
MHR = 220 - 14 = 206
Next, we need to calculate Hanif's target heart rate (THR) range at 70% intensity. This range is between 70% and 85% of his MHR. To calculate the lower end of the range, we multiply his MHR by 0.7:
THR lower = 0.7 × MHR = 0.7 × 206 = 144.2 (rounded to one decimal place)
To calculate the upper end of the range, we multiply his MHR by 0.85:
THR upper = 0.85 × MHR = 0.85 × 206 = 175.1 (rounded to one decimal place)
So Hanif's target heart rate range at 70% intensity is between 144.2 and 175.1 beats per minute.
To find his training pulse rate, we add his resting pulse rate (76 beats per minute) to the percentage of his target heart rate range which corresponds to 70% intensity. This is given by:
Training pulse rate = resting pulse rate + (0.7 × (THR upper - resting pulse rate))
Substituting the values we calculated, we get:
Training pulse rate = 76 + (0.7 × (175.1 - 76)) ≈ 142
Therefore, Hanif's training pulse rate at 70% intensity is approximately 142 beats per minute.
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Which postulate or theorem can be used to prove that ΔABC ≅ ΔDCB
The postulate or theorem that can be used to prove that ΔABC ≅ ΔDCB is the "Side-Side-Side (SSS) theorem".
Hence, the correct option is A.
Since in both triangles ΔABC and ΔDCB, we have
BC = BC (Common line)AB = CD (given)AC = BD (given)Therefore, by SSS theorem, we can conclude that ΔABC ≅ ΔDCB.
Hence, the correct option is A.
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A spring gun at ground level fires a golf ball at an angle of 45 degrees. The ball lands 10 m away.
a) What was the ball's initial speed?
b) For the same initial speed, find the two firing angles that make the range 6 m.
Recall that the Ideal Projectile Motion Equation is
r=(vo*cos(theta))ti+((vo*sin(theta)t-1/2*g*t^2)j.
Answer: a) vo=sqrt(10g)
b) theta=1/2*arcsin(3/5),
theta=pi-1/2*arcsin(3/5).
And is arcsin the same thing as sin^-1?
Yes, arcsin and sin^-1 both represent the inverse sine function.
process of finding inital speed:
a) To find the ball's initial speed, we can use the range formula for projectile motion:
R = (v₀² * sin(2θ)) / g
where R is the range (10 m),
v₀ is the initial speed,
θ is the launch angle (45 degrees), and
g is the acceleration due to gravity (9.81 m/s²).
We can solve for v₀:
10 = (v₀² * sin(90)) / 9.81
10 = (v₀²) / 9.81
v₀² = 10 * 9.81
v₀ = sqrt(10 * 9.81)
The ball's initial speed is sqrt(10 * 9.81) m/s.
b) For the same initial speed, we can find the two firing angles that make the range 6 m:
6 = (v₀² * sin(2θ)) / 9.81
Now, we can use the initial speed found in part (a):
6 = (10 * 9.81 * sin(2θ)) / 9.81
0.6 = sin(2θ)
To find the two angles, we can use the arcsin function:
θ₁ = 1/2 * arcsin(0.6)
θ₂ = π - 1/2 * arcsin(0.6)
The two firing angles are 1/2 * arcsin(0.6) and π - 1/2 * arcsin(0.6).Yes, arcsin is the same as sin^(-1);
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19. if abcd is a rectangle, ad = 9, ac = 22, and mzbca = 66°, find each missing measure.
help me pls
The missing measures are BC ≈ 23.77, angle BCA = 24 degrees, AB ≈ 56.77, and CD ≈ 56.77.
To solve the problem, we can use the properties of rectangles and trigonometry. Since ABCD is a rectangle, we know that angle ABC is also 90 degrees.
Using the Pythagorean theorem, we can find the length of BC:
BC² = AB² - AC²
BC² = 9² + 22²
BC² = 565
BC ≈ 23.77
Using the fact that the sum of the angles in triangle ABC is 180 degrees, we can find the measure of angle BCA
m(BCA) = 180 - m(ABC) - m(CAB)
m(BCA) = 180 - 90 - 66
m(BCA) = 24 degrees
Using trigonometry, we can find the length of AB
sin(24) = AC/AB
AB = AC/sin(24)
AB ≈ 56.77
Finally, we can find the length of CD, which is equal to AB
CD = AB ≈ 56.77
Therefore, the measures of AB ≈ 56.77, and CD ≈ 56.77.
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Aimie is looking for a golf ball that he hit into the air towards a fence surrounding the golf course. The fence has a height of 2 yards and is located at a distance of 120 yards from where Jaimie hit the ball. Jaimie wants to determine if his golf ball landed inside or outside of the fence.
The golf ball's height, h, in yards with respect to time, t, in seconds, can be modeled by the quadratic function h=−0. 6t2+3t. Jaimie's golf ball reached its maximum height at the fence.
What is the maximum height, in yards, the golf ball reached before landing back on the ground?
_____yards
The maximum height the golf ball reached before landing back on the ground is 3.75 yards.
To find the maximum height the golf ball reached before landing back on the ground, we need to find the vertex of the quadratic function[tex]h(t) = -0.6t^2 + 3t.[/tex] The vertex of a quadratic function in the form of[tex]f(x) = ax^2 + bx + c[/tex] is given by the formula x = -b/(2a).
In this case, a = -0.6 and b = 3. Plugging these values into the formula:
t = -3 / (2 * -0.6) = 3 / 1.2 = 2.5
Now that we have the time at which the ball reaches its maximum height, we can plug this value back into the height function to find the maximum height:
[tex]h(2.5) = -0.6(2.5)^2 + 3(2.5) = -0.6(6.25) + 7.5 = -3.75 + 7.5 = 3.75[/tex]
So, the maximum height the golf ball reached before landing back on the ground is 3.75 yards.
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