The area of the swimming pool cover obtained by considering the area as the sum of the areas of a rectangle and two semicircles is about 218.54 ft²
What is the area of semicircle based on the diameter?The area of a semicircle is; A = π·D²/(2 × 4) = π·D²/8
The area of the swimming pool cover can be found from the area of the composite figure comprising of one rectangle and the two semicircles as follows;
The length of the parallel sides which represent the length of the rectangle = 14 ft
The distance the parallel sides are apart = The width of the rectangle = 10 ft
The width of the rectangle = The diameter of the semicircle part of the swimming pool = 10 ft
Area of the rectangle = 14 ft × 10 ft = 140 ft²
Area of the two semicircle = 2 × π × (10 ft)²/8 = 25·π ft²
The area of the swimming pool cover = 140 ft² + 25·π ft² ≈ 218.54 ft²
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Calculate the accumulated amount in each investment after 40 years. Using a TVM solver
a. $150 invested on the first day of each month at 6% compounded monthly.
b. $900 invested on January 1st and on July 1st at 4% compounded semi-annually.
c. $450 invested on January 1st, April 1st, July 1st, and October 1st at 5% compounded quarterly.
Answer: a. Using a TVM solver with the following inputs:
Present value (PV) = 150
Interest rate (I/Y) = 6/12 = 0.5 (monthly interest rate)
Number of periods (N) = 40 years x 12 months/year = 480
Payment (PMT) = -150 (negative because it's an outgoing cash flow at the beginning of each month)
Compounding frequency (C/Y) = 12 (monthly compounding frequency)
We get an accumulated amount (FV) of $222,812.64.
b. Using a TVM solver with the following inputs:
Present value (PV) = 900
Interest rate (I/Y) = 4/2 = 2 (semi-annual interest rate)
Number of periods (N) = 40 years x 2 semi-annual periods/year = 80
Payment (PMT) = 0 (because there are no regular payments)
Compounding frequency (C/Y) = 2 (semi-annual compounding frequency)
We get an accumulated amount (FV) of $3,054.58.
c. Using a TVM solver with the following inputs:
Present value (PV) = 450
Interest rate (I/Y) = 5/4 = 1.25 (quarterly interest rate)
Number of periods (N) = 40 years x 4 quarterly periods/year = 160
Payment (PMT) = 0 (because there are no regular payments)
Compounding frequency (C/Y) = 4 (quarterly compounding frequency)
We get an accumulated amount (FV) of $2,109.64.
Step-by-step explanation: can i get brainliest :D
To calculate the accumulated amount in each investment after 40 years, we can use the TVM solver. For each investment, use the appropriate formula to calculate the accumulated amount by plugging in the given values of principal amount, interest rate, number of times interest is compounded per year, and number of years. Finally, calculate the accumulated amount to find the answer.
Explanation:a. To calculate the accumulated amount in the first investment, $150 invested on the first day of each month at 6% compounded monthly for 40 years, you can use the formula:
Let P be the principal amount: $150Let r be the annual interest rate: 6% or 0.06Let n be the number of times interest is compounded per year: 12 (monthly)Let t be the number of years: 40Use the formula A = P(1 + r/n)^nt to calculate the accumulated amount:A = 150(1 + 0.06/12)^(12*40)
A=1643.61
b. To calculate the accumulated amount in the second investment, $900 invested on January 1st and July 1st at 4% compounded semi-annually for 40 years, you can use the formula:
Let P be the principal amount: $900Let r be the annual interest rate: 4% or 0.04Let n be the number of times interest is compounded per year: 2 (semi-annually)Let t be the number of years: 40Use the formula A = P(1 + r/n)^(2*t) to calculate the accumulated amount:A = 900(1 + 0.04/2)^(2*40)
A=4387.89
c. To calculate the accumulated amount in the third investment, $450 invested on January 1st, April 1st, July 1st, and October 1st at 5% compounded quarterly for 40 years, you can use the formula:
Let P be the principal amount: $450Let r be the annual interest rate: 5% or 0.05Let n be the number of times interest is compounded per year: 4 (quarterly)Let t be the number of years: 40Use the formula A = P(1 + r/n)^(n*t) to calculate the accumulated amount:A = 450(1 + 0.05/4)^(4*40)
A=3284.11
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The value of lim a^x-x^a/x^x-a^a is
lim (1 - a^(1-a)) / (ln(a)) as x -> a This is the value of the given limit.
To find the value of the given limit, which can be represented as lim (a^x - x^a) / (x^x - a^a) as x approaches 'a', you can apply L'Hôpital's Rule, which states that if the limit of the ratio of the derivatives of two functions exists, then the limit of the original functions is equal to that limit.
First, differentiate the numerator and denominator with respect to x:
Numerator: d(a^x - x^a) / dx = a^x * ln(a) - a * x^(a-1)
Denominator: d(x^x - a^a) / dx = x^x * ln(x)
Now, we can find the limit of the ratio of the derivatives as x approaches 'a':
lim (a^x * ln(a) - a * x^(a-1)) / (x^x * ln(x)) as x -> a
After substituting 'a' for 'x' in the limit:
lim (a^a * ln(a) - a * a^(a-1)) / (a^a * ln(a)) as x -> a
Now, cancel out the common term a^a * ln(a):
lim (1 - a^(1-a)) / (ln(a)) as x -> a
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What is the volume of a hemisphere with a radius of 8. 8 cm, rounded to the nearest
tenth of a cubic centimeter?
Please help
The volume of a hemisphere with a radius of 8. 8 cm, rounded to the nearest tenth of a cubic centimeter, is approximately 1436.8 cubic centimeters.
To find the volume of a hemisphere with a radius of 8.8 cm, you can use the formula:
Volume = (2/3)πr³
where r is the radius of the hemisphere. Plugging in the given radius:
Volume = (2/3)π(8.8)³ ≈ 1436.8 cubic centimeters
So, the volume of the hemisphere is approximately 1436.8 cubic centimeters, rounded to the nearest tenth of a cubic centimeter.
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In the figure, is tangent to the circle at point U. Use the figure to answer the question.
Hint: See Lesson 3. 09: Tangents to Circles 2 > Learn > A Closer Look: Describe Secant and Tangent Segment Relationships > Slide 4 of 8. 4 points.
Suppose RS=8 in. And ST=4 in. Find the length of to the nearest tenth. Show your work.
1 point for the formula, 1 point for showing your steps, 1 point for the correct answer, and 1 point for correct units.
If you do not have an answer please dont comment
The length of UX (the length of a tangent segment to a circle) is approximately 4.9 inches.
To find the length of UX, we can use the formula for the length of a tangent segment to a circle:
Length of tangent segment = √(radius² - distance from center²)
In this case, we don't know the radius or the distance from the center, but we can use the fact that RU is perpendicular to UT to find them:
RU = RS + ST = 8 + 4 = 12 in.
UT = radius = RU/2 = 12/2 = 6 in.
Now we can plug these values into the formula:
Length of tangent segment = √(6² - 4²) ≈ 4.9 in.
Therefore, the length of UX is approximately 4.9 inches.
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Quadrilateral ABCD is a square with diagonals AC and BD. If A(4, 9) and C(3, 2), find the slope of BD.
Using the given information from #13, find the length of BD. Give your answer in simplest radical form.
B
the location of point 0 on directed line segment PS such that PO: OS is divided into a ratio of 3:2
The length of BD is √(65)) and the slope of BD is 1/7.
What does Quadrilateral means ?
In geometry, a quadrilateral is a four-sided polygon with four sides (sides) and four angles (vertices). The word is derived from the Latin words quadri, the form of four, and latus, meaning "side". Different types of quadrilaterals include trapezoid, parallelogram, rectangle, rhombus, square, kite
To find the slope of the diagonal BD of square ABCD, you must first find the coordinates of points B and D. Since ABCD is a square, all sides are the same length and the diagonals bisect each other at 90 degrees.
The midpoint M of AC is the intersection of the diagonals, so we can find the coordinates of M by taking the average of the x-coordinates and the average of the y-coordinates:
M = ((4 +3)/2, (9+ 2)/2) = (3.5, 5.5)
Since BD bisects AC, the coordinates of the midpoint M are also the coordinates of both B and D. Hence we have:
B = D = (3.5, 5.5)
The slope of the line passing through points A and C is:
m_AC = (2-9)/(3-4) = -7
Since the diagonals of the square are perpendicular, the slope of BD is the negative inverse of m_AC:
m_BD = -1/m_AC = 1/7
We can use the Pythagorean theorem to find the length of BD. Let x be the length of BD. Then we have:
AC² + BD² = 2x²
Since AC is the diagonal of the square, its length is:
AC = square((3-4)²+ (2-9)²) = square(65)
Substituting this into the above equation and solving for x, we get:
√(65) x² = 2x²
x² = square(65)
x = square (square(65))
Therefore, the length of BD is √(65) and the slope of BD is 1/7.
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4. Lana has a bag of marbles. The probability of picking a striped marble is 8%. If Lana picks a marble and then replaces it 320 times, predict about how many times she would pick a marble that is not striped.
Lana would pick a non-striped marble about 294 times.
The probability of picking a marble that is not striped is 100% - 8% = 92% = 0.92. This means that for each pick, the probability of getting a non-striped marble is 0.92.
If Lana picks a marble and replaces it 320 times, the number of times she would pick a non-striped marble can be predicted by multiplying the probability of getting a non-striped marble by the number of picks.
So, the number of times she would pick a non-striped marble is:
0.92 x 320 = 294.4
Rounding to the nearest whole number = 294.
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A) Eight percent (8%) of all college graduates hired by companies stay with the same company for more than five years. (i) What is the probability, rounded to four decimal places, that in a random sample of 15 such college graduates hired recently by companies, exactly 2 would stay with the same company for more than five years?(4 marks)
(ii) What is the probability, rounded to four decimal places, that in a random sample of 15 such college graduates hired recently by companies, more than 3 would stay with the same company for more than five years? (5 marks)
(iii) If 24 college graduates were hired by companies, how many are expected to stay with the same company for more than five years. (2 marks)
(iv) Describe the shape of this distribution. Justify your answer using the relevant statistics
The probability that exactly 2 out of 15 college graduates stay with the same company 0.0246, the probability that more than 3 out of 15 college graduates stay with the same company is 0.0567, 2 college graduates would stay in the company and the shape of the binomial distribution is approximately normal
(i) To find the probability that exactly 2 out of 15 college graduates stay with the same company for more than five years, we use the binomial probability formula:
P(X = 2) = (15 choose 2) * (0.08)^2 * (0.92)^13
= 105 * 0.0064 * 0.3369
≈ 0.0246
So the probability, rounded to four decimal places, is 0.0246.
(ii) To find the probability that more than 3 out of 15 college graduates stay with the same company for more than five years, we can use the complement rule and find the probability of 3 or fewer staying with the same company, and then subtract that from 1:
P(X > 3) = 1 - P(X ≤ 3)
= 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)]
= 1 - [(15 choose 0) * (0.08)^0 * (0.92)^15 + (15 choose 1) * (0.08)^1 * (0.92)^14 + (15 choose 2) * (0.08)^2 * (0.92)^13 + (15 choose 3) * (0.08)^3 * (0.92)^12]
≈ 0.0567
So the probability, rounded to four decimal places, is 0.0567.
(iii) If 8% of all college graduates hired by companies stay with the same company for more than five years, then we would expect 0.08 * 24 = 1.92 college graduates to stay with the same company for more than five years. Since we cannot have a fractional number of college graduates, we would expect 2 college graduates to stay with the same company for more than five years.
(iv) The distribution of the number of college graduates staying with the same company for more than five years follows a binomial distribution. This is because each college graduate either stays with the same company for more than five years or they do not, and the probability of success (staying with the same company for more than five years) is constant for all college graduates.
The shape of the binomial distribution is approximately normal, provided that both np and n(1-p) are greater than or equal to 10, where n is the sample size and p is the probability of success. In this case, np = 15 * 0.08 = 1.2 and n(1-p) = 15 * 0.92 = 13.8, which are both greater than or equal to 10, so we can assume that the distribution is approximately normal.
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Using Newton's Method, estimate the positive solution to the following equation by calculating x2 and using X0 = 1. x⁴ – x = 3 Round to four decimal places.
Answer:
To estimate the positive solution to the equation x⁴ – x = 3 using Newton's Method, we can start by taking the derivative of the equation, which is 4x³ - 1. Then we can use the formula X1 = X0 - f(X0) / f'(X0), where X0 = 1, f(X0) = 1⁴ - 1 - 3 = -3, and f'(X0) = 4(1)³ - 1 = 3. Plugging these values into the formula, we get:
X1 = 1 - (-3) / 3
X1 = 2
Now we can repeat the process using X1 as our new X0:
X2 = X1 - f(X1) / f'(X1)
X2 = 2 - (2⁴ - 2 - 3) / (4(2)³ - 1)
X2 ≈ 1.7708
Therefore, the positive solution to the equation x⁴ – x = 3, rounded to four decimal places, is approximately 1.7708.
Step-by-step explanation:
The positive solution to the equation x⁴ – x = 3, estimated using Newton's Method with x₀ = 1 and x₂ as the final estimate, is approximately 1.5329, rounded to four decimal places.
To use Newton's Method to estimate the positive solution to the equation x⁴ – x = 3, we need to find the derivative of the function f(x) = x⁴ – x. This is given by:
f'(x) = 4x³ - 1
We can then use the formula for Newton's Method:
x(n+1) = x(n) - f(x(n)) / f'(x(n))
where x(n) is the nth estimate of the solution.
Starting with x₀ = 1, we can plug this into the formula to get:
x₁ = 1 - (1^4 - 1 - 3) / (4(1^3) - 1) ≈ 1.75
We can then repeat this process using x₁ as the new estimate, to get:
x₂ = 1.75 - (1.75^4 - 1.75 - 3) / (4(1.75^3) - 1) ≈ 1.5329
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HELP ME PLEASE I BEG YOU!!
Surface area of the box is 304 square inches
Step-by-step explanation:Two different methods:
Method 1: Sum of the parts
Method 2: General formula for the Surface Area of a box
Method 1: Sum of the parts
For a box, there are 6 sides, all of which are rectangles:
the front and backthe left and right sidesthe top and bottomEach of the above pairs has the same area.
The general formula for the area of a rectangle is [tex]A_{rectangle}=length*width[/tex]
As we look at different rectangles, the length of one rectangle may be considered the "width" of another rectangle, and that's okay as we calculate things separately. (We'll examine how to calculate everything at once in Method 2).
The area for the front/back side is 8in * 10in = 80 in^2
[tex]A_{front}=A_{back}=80~in^2[/tex]
The area for the left/right side is 4in * 8in = 32 in^2
[tex]A_{left}=A_{right}=32~in^2[/tex]
The area for the top/bottom side is 4in * 10in = 40 in^2
[tex]A_{top}=A_{bottom}=40~in^2[/tex]
So, the total surface area is
[tex]A_{Surface~Area} = A_{front} + A_{back} + A_{left} + A_{right} + A_{top} + A_{bottom}[/tex]
[tex]A_{Surface~Area} = (80in^2) + (80in^2) + (32in^2) + (32in^2) + (40in^2) + (40in^2)[/tex]
[tex]A_{Surface~Area} = 304~in^2[/tex]
Method 2: General formula for the Surface Area of a box
There is a formula for the surface area of a box:[tex]A_{Surface~Area~of~a~box} = 2(length*width + width*height + height*length)[/tex]
This formula calculates the area of one of each of the matching sides from the side pairs discussed in Method 1, adds those areas together (giving 3 of the sides), and doubles the result (bringing in the area for the matching missing 3 sides).
For clarity, let's decide that the "10 in" is the width, the "8 in" is the height, and the left over "4 in" is the length.
[tex]A_{Surface~Area~of~the~box} = 2((4in)(10in) + (10in)(8in) + (8in)(4in))[/tex]
[tex]A_{Surface~Area~of~the~box} = 2(40in^2 + 80in^2 + 32in^2)[/tex]
[tex]A_{Surface~Area~of~the~box} = 2(152in^2)[/tex]
[tex]A_{Surface~Area~of~the~box} = 304in^2[/tex]
How to find number 3?
Answer:
V=3456, SA= 1008
Step-by-step explanation:
V=b*h*L (Formula)
8*18*24=3456 (sub, alg)
SA=30*8+24*18+24*8+8*18=54*8+32*18=1008 (Formula; sub, alg)
How many containers will it take fill the aquarium with water
A.13 containers
B. 14 containers
C. 15 containers
D. 16 containers
Answer:
for that first u should know that how much litres of water that aquarium can contain.
for that first u should know that how much litres of water that aquarium can contain.so that probably depends upon the size length and width of a container
for that first u should know that how much litres of water that aquarium can contain.so that probably depends upon the size length and width of a containera normal container can be filled with approximately 15 containers
Malachi ask students in his class, “ how long does it take you to get to school?“ The histogram shows the data
Answer: C Distribution is symmetric
Step-by-step explanation:
If you flip a coin 4 times what is the best prediction possible for the number of times it will land on tails?
Answer:it would still be a 50/50 chance of it be tails
Step-by-step explanation:
a coin has 2 sides. The probability would be 1/2. That means if you flip it a even amount, there would be a 50/tip chance. Let me know if I’m correct.
please solve these 4 and show the work for it
The length, slope and midpoints of the segment in the drawing, obtained using the distance and midpoint formula are;
The length of [tex]\overline{AB}[/tex] = √(29)
The midpoint of [tex]\overline{AB}[/tex] is (3, -0.5)
The slope of segment [tex]\overline{CD}[/tex] = 2/5
The midpoint of segment [tex]\overline{CD}[/tex] = (-1.5, 2)
What is the slope of a segment?The slope of a segment on the coordinate plane is the ratio of the rise to the run of the segment.
The coordinates of the required points in the figure are; A(2, 2), B(4, -3), C(1, 3), and D(-4, 1)
The distance formula that can be used in finding the distance between points on the coordinate plane can be presented as follows;
d = √((x₂ - x₁)² + (y₂ - y₁)²)
The distance formula indicates that the length of [tex]\overline{AB}[/tex] can be found as follows;
[tex]\overline{AB}[/tex] = √((4 - 2)² + (-3 - 2)²) = √(29)
The midpoint formula indicates tha midpoint of the segment [tex]\overline {AB}[/tex] can be found as follows
The midpoint of [tex]\overline{AB}[/tex] = ((2 + 4)/2, (2 + -3)/2) = (3, -0.5)
The slope of [tex]\overline{CD}[/tex] = ((3 - 1)/(1 - (-4)) = 2/5
The midpoint of [tex]\overline{CD}[/tex] = ((1 + (-4))/2, (3 + 1)/2 = (-1.5, 2)
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If 10 monkeys vary inversely when there are 18 clowns. How many monkeys will there be with 4 clowns? Your final answer should be rounded to a whole number with no words included
The number of monkeys when number of monkeys varies inversely to the number of clowns is 45.
What is inverse proportion:
Inverse proportion is a mathematical relationship between two variables, in which an increase in one variable causes a proportional decrease in the other variable, and a decrease in one variable causes a proportional increase in the other variable.
In other words, the two variables vary in such a way that their product remains constant.
Here we have
10 monkeys vary inversely when there are 18 clowns.
We can set up the inverse variation equation as:
=> monkey ∝ 1/clown
If k is the constant of proportionality.
=> Monkey (clown) = k
It is given that when there are 10 monkeys, there are 18 clowns, so we can write:
=> (10)(18) = k
Solving for k, we get:
k = (10 x 18) = 180
Now we can use this value of k to find the number of monkeys when there are 4 clowns:
=> monkey = k/clown = 180/4 = 45
Therefore,
The number of monkeys when number of monkeys varies inversely to the number of clowns is 45.
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Can someone please help me ASAP? It’s due tomorrow.
Answer:
There are 16 total outcomes for tossing 4 quarters
This is because each coin flip has 2 possibilities, so if you flip the coin 4 times it will equal
2x2x2x2.
What is the solution for 11\31×38\33
Answer:
38/93
Step-by-step explanation:
11/31 x 38/33
11 x 38 = 418
31 x 33 = 1023
= 418/1023
Simplifying
The simplified form of 418/1023 is 38/93.
38/93 is your final answer.
solve this problem:
Suppose that you are headed toward a plateau 50 m high. If the angle of elevation to the top of the plateau is 20 , how far are you from the base of the plateau?
Answer:
Step-by-step explanation:
We can use trigonometry to solve this problem. Let's call the distance from the base of the plateau to our position "x". We can then use the tangent function to find x:
tan(20°) = opposite / adjacent
In this case, the opposite side is the height of the plateau (50 m) and the adjacent side is x. So we can write:
tan(20°) = 50 / x
To solve for x, we can rearrange this equation:
x = 50 / tan(20°)
Using a calculator, we get:
x = 143.45 meters (rounded to two decimal places)
Therefore, if the angle of elevation to the top of the plateau is 20 degrees, and the plateau is 50 meters high, we are approximately 143.45 meters away from the base of the plateau.
Answer:
The distance is 137.3739 feet.
Step-by-step explanation:
I hope this answer is right.
Will give brainliest!
given that the slope of the consecutive sides is -2/3 and 3/2
can you prove that it is a parallelogram or a rectangle.
explain your answer.
A figure with slope of consecutive sides -2/3 and 3/2 is a rectangle and it is not a parallelogram.
To prove that it is a parallelogram or a rectangle, we need to show that the opposite sides are parallel and the adjacent sides are perpendicular.
Let's first check if the opposite sides are parallel. The slope of one side is -2/3, and the slope of the adjacent side is 3/2. For opposite sides to be parallel, the slopes must be equal. However, -2/3 and 3/2 are not equal, so we can conclude that the given figure is not a parallelogram.
Now, let's check if the adjacent sides are perpendicular. The product of the slopes of the adjacent sides is
(-2/3) x (3/2) = -1, which is the slope of a line perpendicular to both sides. Since the product of the slopes is -1, we can conclude that the adjacent sides are perpendicular.
Therefore, figure is not a parallelogram, but it is a rectangle.
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I absolutely hate IQR so can someone help pls
Answer:5
Step-by-step explanation: The median of the lower quartile is 23 and the median of the upper quartile is 28. 28-23=5. The IQR is 5.
Suppose you carry out a significance test of h0: μ = 8 versus ha: μ > 8 based on sample size n = 25 and obtain t = 2.15. find the p-value for this test. what conclusion can you draw at the 5% significance level? explain.
a the p-value is 0.02. we reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05.
b the p-value is 0.02. we fail to reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05.
c the p-value is 0.48. we reject h0 at the 5% significance level because the p-value 0.48 is greater than 0.05.
d the p-value is 0.48. we fail to reject h0 at the 5% significance level because the p-value 0.48 is greater than 0.05.
e the p-value is 0.52. we fail to reject h0 at the 5% significance level because the p-value 0.52 is greater than 0.05.
We can draw at the 5% significance level, the p-value is 0.02. we reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05. The correct answer is a.
To find the p-value, we need to find the area to the right of t = 2.15 under the t-distribution curve with 24 degrees of freedom (df = n - 1 = 25 - 1 = 24). Using a t-table or a calculator, we find that the area to the right of t = 2.15 is approximately 0.02.
Since the p-value (0.02) is less than the significance level (0.05), we reject the null hypothesis H0: μ = 8 and conclude that there is sufficient evidence to support the alternative hypothesis Ha: μ > 8 at the 5% significance level. This means that we can say with 95% confidence that the true population mean is greater than 8.
Therefore the correct answer is a.
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The height of each cone and the cylinder is 5 (cm) centimeters. The radius of the base of each cone and the cylinder is 4 (cm). What is the volume of the composite figure?
Therefore, the volume of the composite figure is approximately 419.05 cubic cm.
What is volume?Volume is the amount of space occupied by a three-dimensional object or shape. It is measured in cubic units such as cubic centimeters, cubic inches, or cubic meters. The volume of an object can be calculated by multiplying the area of its base by its height, or by using specific formulas depending on the shape of the object. The volume of an object is an important parameter in many areas of science and engineering, such as physics, chemistry, fluid mechanics, and material science, as it allows us to determine how much space an object will occupy or how much material is needed to fill a container or build a structure.
Here,
The composite figure consists of a cylinder and two cones, so we need to find the volume of each of these shapes and add them together.
Volume of cylinder = πr²h
= π(4²)(5)
= 80π cubic cm
Volume of one cone = (1/3)πr²h
= (1/3)π(4²)(5)
= (1/3)(80π)
= 26.67π cubic cm
Volume of both cones = 2(26.67π)
= 53.34π cubic cm
Total volume of composite figure = Volume of cylinder + Volume of both cones
= 80π + 53.34π
= 133.34π
= 419.05 cubic cm (rounded to two decimal places)
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A random sample of 13 $1 Trifecta tickets at a local racetrack paid a mean amount of $52. 23 with a sample standard deviation of $3. 35. Is there sufficient evidence to conclude that the average Trifecta winnings exceed $50? Use a 10% significance level and assume the distribution is approximately normal.
What is the critical value?
The critical value for the given problem is 1.282.
To determine if there's sufficient evidence that the average Trifecta winnings exceed $50, follow these steps:
1. State the hypotheses:
H0: µ ≤ $50 (null hypothesis)
H1: µ > $50 (alternative hypothesis)
2. Choose the significance level:
α = 0.10
3. Calculate the test statistic (t-score):
t = (sample mean - population mean) / (sample standard deviation / √sample size)
t = ($52.23 - $50) / ($3.35 / √13)
t ≈ 2.15
4. Determine the critical value:
Using a t-distribution table or calculator, find the critical value for a one-tailed test with 12 degrees of freedom (13-1) and α = 0.10. The critical value is 1.282.
5. Compare the test statistic to the critical value:
Since the test statistic (2.15) is greater than the critical value (1.282), we reject the null hypothesis.
In conclusion, there is sufficient evidence to conclude that the average Trifecta winnings exceed $50 at a 10% significance level.
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Complete question:
A random sample of 13 $1 Trifecta tickets at a local racetrack paid a mean amount of $52. 23 with a sample standard deviation of $3. 35. Is there sufficient evidence to conclude that the average Trifecta winnings exceed $50? Use a 10% significance level and assume the distribution is approximately normal.What is the critical value?
Below is attached t-table image:
The captain of the baseball team hit a homerun 1 out of every 6 at-bats. What is the probability that the captain will hit a homerun on his next 2 at-bats?
Determine which simulation models the situation. Select Yes if the simulation can be used to model the situation or No if the simulation cannot be used to model the situation.
Yes No
OO
Using a six-sided number cube to model the situation, assign the number 1 to represent the captain hitting a homerun and the number 2 to represent not hitting a homerun.
Using a stre-sided number cube to model the situation, assign the number 1 to represent the captain hitting a homerun and the numbers 2 to 6 to represent not hitting a homerun
Using a coin flip to model the situation, assign heads to represent the captain hitting a homerun and tails for not hitting a homerun
O
Using a random number generator between 1 and 60 to model the situation, assign the numbers 1 to 10 to represent the captain hitting a homerun and the numbers 11 to 60 to represent not hitting a homerun.
The probability of the captain hitting a home run in his next two at-bats is 1/36, and the best simulations to model the situation are using a six-sided number cube or a random number generator between 1 and 60.
Determine the probability that the captain will hit a home run in his next two at-bats and find the best simulation to model the situation.
The probability of the captain hitting a home run in one at-bat is 1/6. To find the probability of hitting a home run in two consecutive at-bats, you can multiply the individual probabilities:
Probability = (1/6) * (1/6) = 1/36
Now let's evaluate the provided simulations:
1. Using a six-sided number cube: Yes, this can be used to model the situation because the probability of hitting a home run (1/6) and not hitting a home run (5/6) can be represented accurately by the numbers 1 and 2-6, respectively.
2. Using a three-sided number cube: No, this cannot be used to model the situation because the probability distribution is not accurately represented with only three sides.
3. Using a coin flip: No, this cannot be used to model the situation because the probability distribution is not accurately represented with only two outcomes (heads and tails).
4. Using a random number generator between 1 and 60: Yes, this can be used to model the situation because the probability of hitting a home run (1/6) and not hitting a home run (5/6) can be represented accurately by the numbers 1-10 and 11-60, respectively.
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Furnace repair bills are normally distributed with a mean of 264 dollars and a standard deviation of 30 dollars. if 144 of these repair bills are randomly selected, find the probability that they have a mean cost between 264 dollars and 266 dollars.
Answer is the probability that 144 furnace repair bills have a mean cost between 264 dollars and 266 dollars is approximately 0.2881 or 28.81%
The distribution of the sample mean of furnace repair bills will also be normally distributed with a mean of 264 dollars and a standard deviation of 30/sqrt(144) = 2.5 dollars (by the Central Limit Theorem).
We need to find the probability that the sample mean falls between 264 and 266 dollars:
z1 = (264 - 264) / 2.5 = 0
z2 = (266 - 264) / 2.5 = 0.8
Using a standard normal distribution table or calculator, we can find the area under the curve between z1 and z2:
P(0 ≤ Z ≤ 0.8) = 0.2881
Therefore, the probability that 144 furnace repair bills have a mean cost between 264 dollars and 266 dollars is approximately 0.2881 or 28.81%.
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A particle moves on a coordinate line with acceleration a = d^2s/dt^2 = 15 sqrt(t) - (3/sqrt(t)), subject to the conditions that ds/dt = 4 and s = 0 when t = 1. Find a. the velocity y = ds/dt in terms of t. b. the position s in terms of t.
a.The velocity function is: v = ds/dt = (2/5)t^(5/2) - 6t^(1/2) + 16.
b. The position function is: s = (4/35)t^(7/2) - 8t^(3/2) + 16t - 12.
a. To find the velocity, we need to integrate the acceleration function. We get:
v = ds/dt = ∫a dt = ∫(15√t - 3/t^(1/2)) dt
Integrating the first term, we get (2/5)t^(5/2), and integrating the second term, we get -6t^(1/2) + C. Thus, the velocity function is:
v = ds/dt = (2/5)t^(5/2) - 6t^(1/2) + C
We can find the constant C using the initial condition that ds/dt = 4 when t = 1. Substituting these values into the equation, we get:
4 = (2/5)(1)^(5/2) - 6(1)^(1/2) + C
C = 4 + 12 = 16
Therefore, the velocity function is:
v = ds/dt = (2/5)t^(5/2) - 6t^(1/2) + 16
b. To find the position function, we need to integrate the velocity function. We get:
s = ∫v dt = ∫((2/5)t^(5/2) - 6t^(1/2) + 16) dt
Integrating the first term, we get (4/35)t^(7/2), integrating the second term, we get -8t^(3/2), and integrating the third term, we get 16t. Thus, the position function is:
s = ∫v dt = (4/35)t^(7/2) - 8t^(3/2) + 16t + C2
We can find the constant C2 using the initial condition that s = 0 when t = 1. Substituting these values into the equation, we get:
0 = (4/35)(1)^(7/2) - 8(1)^(3/2) + 16(1) + C2
C2 = -12
Therefore, the position function is:
s = (4/35)t^(7/2) - 8t^(3/2) + 16t - 12
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You are asked by your teacher to arrange the letters in the word probability regardless of each word 's meaning. in how many ways can you arrange the letter in the word?
[tex]\color{blue}{analysis}[/tex] : the problem involve permutation or combination) of objects
[tex]\color{red}{required}[/tex] : the value that is to be solved in the problem is the____
[tex]\color{pink}{given}[/tex]: the given value is____ which is the_____ of the word probability
[tex]\color{cyan}{formula}[/tex]: we will use the formula______ to soive for the unknown.
solution
The number of ways to arrange the letters in the word "probability" is 11 factorial (11!).
How many ways to arrange?In this problem, we need to arrange the letters in the word "probability." Since the order of the letters matters, we are dealing with permutations of objects.
The value we are trying to solve is the number of ways to arrange the letters. The given value is the word "probability," which has a total of 11 letters. To solve for the unknown, we will use the formula for permutations.
The formula for permutations of objects is n! / (n - r)!, where n is the total number of objects and r is the number of objects being arranged. In this case, we have 11 letters to arrange, so the formula becomes 11! / (11 - 11)!.
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Q2) For the following exercises, write the first five terms of the indicated
sequence:
The first five terms of the sequence are: 3/5, 3/4, 9/7, 3/2, 15/9.
To find the first five terms of the sequence aₙ = 3n/(n+4)
we need to substitute the values of n from 1 to 5 and solve for .
a₁ = 3×1/(1+4) = 3/5
a₂ = 3×2/(2+4) = 3/4
a₃ = 3×3/(3+4) = 9/7
a₄ = 3×4/(4+4) = 12/8 = 3/2
a₅ = 3×5/(5+4) = 15/9
Hence, the first five terms of the sequence are: 3/5, 3/4, 9/7, 3/2, 15/9.
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Hello im new to brainly and i needed some help becuase i dont understand the question.
The number of customers surveyed were 15 customers.
The greatest number of items purchased by a customer was 11 items.
The customers purchased 9 items is 2 customers.
The customers purchased at least 5 items was 7 customers.
The median number of items purchased was 3.
How to interpret the line plots?How many customers were surveyed?
1 (0 items) + 1 (1 item) + 2 (2 items) + 4 (3 items) + 0 (4 items) + 2 (5 items) + 0 (6 items) + 2 (7 items) + 0 (8 items) + 2 (9 items) + 0 (10 items) + 1 (11 items) = 15 customers
The greatest number of items purchased by a customer is 11 items. 2 customers purchased 9 items.
How many customers purchased at least 5 items?
2 (5 items) + 0 (6 items) + 2 (7 items) + 0 (8 items) + 2 (9 items) + 0 (10 items) + 1 (11 items) = 7 customers
To find the median, we need to find the middle value of the data. Since there are 15 customers, the median will be the 8th value when the data is ordered.
0, 1, 2, 2, 3, 3, 3, 3, 5, 5, 7, 7, 9, 9, 11
The median number of items purchased is 3.
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Room and board charges for on-campus students at the local college have increased 3.1% each year since 2000. In 2000, students paid $4,291for room and board.
Write a function to model the cost C after t years since 2000.
If the trend continues, how much would a student expect to pay for room and board in 2017? Express your answer as a decimal rounded to the nearest hundredth.
A student would expect to pay approximately $7,096.47 for room and board in 2017. Rounded to the nearest hundredth, this is $7,096.47 rounded to $7,096.50.
What is Function ?
In mathematics, a function is a rule that assigns each element in a set (the domain) to a unique element in another set (the range). The domain and range can be any sets, but they are typically sets of real numbers.
The cost of room and board after t years since 2000 can be modeled by the equation:
C(t) = 4291[tex](1 + 0.031)^{t}[/tex]
where C(t) is the cost after t years.
To find out how much a student would expect to pay in 2017, we need to plug in t = 17 (since 2017 is 17 years after 2000) into the equation:
C(17) = 4291[tex](1 + 0.031)^{17}[/tex]
≈ 7,096.47
Therefore, a student would expect to pay approximately $7,096.47 for room and board in 2017. Rounded to the nearest hundredth, this is $7,096.47 rounded to $7,096.50.
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