Function f is shown on the graph below where two points are marked. If function f is horizontally compressed by a factor of 2, plot the two corresponding points that would lie on the transformed function.

Answers

Answer 1

Answer:

If you have    

[tex]f(x) = x^2[/tex]

The point  (2,4)   would be transformed to (1,1)

Step-by-step explanation:

If your compression is horizontal then the transformation you are making is the following

[tex]g(x) = f(x/2)[/tex]

Therefore, if you have    

[tex]f(x) = x^2[/tex]

The point  (2,4)   would be transformed to (1,1)


Related Questions

When dividing 336 by the natural number n> 10, the remainder is 2. Then the remainder obtained by dividing 2007 by n is

Answers

Answer:

3

Step-by-step explanation:

336 / n = k + 2/n, where k is an integer

336 = kn + 2

334 = kn

2007 / n

(2004 + 3) / n

(334×6 + 3) / n

334×6/n + 3/n

6k + 3/n

The remainder is 3.

Find the volume of the region enclosed by the cylinder x squared plus y squared equals 36 and the planes z equals 0 and y plus z equals 36.

Answers

Answer:

[tex]\mathbf{V = 1296 \pi }[/tex]

Step-by-step explanation:

Given that :

Find the volume of the region enclosed by the cylinder [tex]x^2 + y^2 =36[/tex] and the plane z = 0 and y + z = 36

From y + z = 36

z = 36 - y

The volume of the region can be represented by the equation:

[tex]V = \int\limits \int\limits_D(36-y)dA[/tex]

In this case;

D is the region given by [tex]x^2 + y^2 = 36[/tex]

Relating this to polar coordinates

x = rcosθ    y = rsinθ

x² + y² = r²

x² + y² = 36

r² = 36

r = [tex]\sqrt{36}[/tex]

r = 6

dA = rdrdθ

r → 0 to 6

θ to 0  to 2π

Therefore:

[tex]V = \int\limits^{2 \pi} _0 \int\limits ^6_0 (36-r sin \theta ) (rdrd \theta)[/tex]

[tex]V = \int\limits^{2 \pi} _0 \int\limits ^6_0 (36-r^2 sin \theta ) drd \theta[/tex]

[tex]V = \int\limits^{2 \pi} _0 [\dfrac{36r^2}{2}- \dfrac{r^3}{3}sin \theta]^6_0 \ d\theta[/tex]

[tex]V = \int\limits^{2 \pi} _0 [648- \dfrac{216}{3}sin \theta]d\theta[/tex]

[tex]V = \int\limits^{2 \pi} _0 [648+\dfrac{216}{3}cos \theta]d\theta[/tex]

[tex]V = [648+\dfrac{216}{3}cos \theta]^{2 \pi}_0[/tex]

[tex]V = [648(2 \pi -0)+\dfrac{216}{3}(1-1)][/tex]

[tex]V = [648(2 \pi )+\dfrac{216}{3}(0)][/tex]

[tex]V = 648(2 \pi )[/tex]

[tex]\mathbf{V = 1296 \pi }[/tex]

Find factors of x³-7x-6 A. (x-4)(x-2)(x+1) B. (x-6)(x-1)(x+1) C. (x-3)(x+2)(x+1) D. (x+3)(x+2)(x-1)

Answers

Answer:

C. (x-3)(x+2)(x+1)

Step-by-step explanation:

We can use the rational roots test to help factor out the original equation.

The leading term is 1 and the constant is 6

p/q= 6/1

Now we find factors (all these are plus and minus)

1,2,3,6

1

We find the common ones (+1 and -1) and use -1 because it ends up being the root of the function

Factor, (x+1)

Now we have (x+1)(x^2-x-6)

Factor this with whatever method you perfer, I use AC method

Find two that are a product of -6 and add to -1 (-3 and 2)

We get (x+1)(x-3)(x+2)

C

Answer:

[tex]\boxed{C}[/tex]

Step-by-step explanation:

Let's solve all of the option and see which equals x³-7x-6

Option A)

[tex](x-4)(x-2)(x+1)[/tex]

=> [tex](x^2-6x+8)(x+1)[/tex]

=> [tex]x^3+x^2-6x^2-6x+8x+1\\x^3-5x^2+2x+1[/tex]

So, A is not correct

Option B)

[tex](x-6)(x-1)(x+1)\\(x+6)(x^2-1)\\x^3-x+6x^2-6\\x^2+6x^2-x-6[/tex]

This is also not correct

Option C)    ← Correct

[tex](x-3)(x+2)(x+1)\\(x^2-x-6)(x+1)\\x^3+x^2-x^2-x-6x-6\\x^3-7x-6[/tex]

This equals to x³-7x-6, So, this is the correct option. No need to do Option D since we have the right option now!

Solve for the unknown quantity, x. Type only the value of x in the answer area.
4
4/x = 50/500

Answers

Answer:

x = 40

Step-by-step explanation:

4/x = 50/500

Simplify the right side

4/x = 1/10

Using cross products

4*10 = 1*x

40 = x

Step-by-step explanation:

4/x = 50/500

4/x = 0.1

x = 4/0.1

x = 40

PLEASE HELP The probability distribution for a
random variable x is given in the table.

Answers

1

Step-by-step explanation:

p(x≤20)=p(x=-10) +p(x=-5)+p(X=0) +p(x=5) +p(x=10)+ p(X=15)+p(X=20)

This, p(X≤20)=0.20+0.15+0.05+0.1+0.25+0.1+0.15

=1

Hong buys a bag of 11 tangerines for $2.86.
Find the unit price in dollars per tangerine.
If necessary, round your answer to the nearest cent.

Answers

Answer:

$0.26

Step-by-step explanation:

To find the unit price, divide the cost by the amount you have.

$2.86/11 = $0.26

The unit price is $0.26.

(SAT Prep) Find the value of x.

Answers

Answer:

x = 65°

Step-by-step explanation:

Naming the sides of the parallelogram formed ABCD as shown in the attached image to this solution.

Angle A = 2x (vertically opposite angles are equal)

Angle A = Angle C (opposite angles of a parallelogram are equal)

Angle A = Angle C = 2x

(Angle C) + 50° = 180° (Sum of angles on a straight line is 180°)

2x + 50° = 180°

2x = 180° - 50° = 130°

x = (130°/2) = 65°

Hope this Helps!!!

Answer:

65 degrees

Step-by-step explanation:

A train goes past you in 10 seconds and goes past a 100 meter long bridge in 30 seconds. What is the length (in meters) and the speed (inm/s) of the train?

Answers

Answer:

Bridge = 300 m

Speed = 10 m/s

Step-by-step explanation:

If a goes past you in 10 seconds, it means the train has speed of

100 m/ 10 seconds as it is 100 m long

The speed in m/s is:

100 m/ 10 s = 10 m/s

Then it take 3 times of 10 seconds to cross the bridge, so

The length of the bridge is:

3*100 m= 300 m

Answer:

Length  : 50m

Speed   : 5 m  /  s

Prove that tan (pi/4 + A) tan (3pi/4 +A) = -1

Answers

Answer:

Step-by-step explanation:

tan(pi\4+A)tan(3pi\4+A) =-1

using the tangent sum of angle formula

Which could be the area of one lateral face of the triangular prism?
6.5 ft
6 ft
8 ft
2.5 ft
[Not drawn to scale]
7.5 ft2
15 ft?
20 ft
39 ft

Answers

Answer:

[tex](A)7.5 ft^2\\(C)20 ft^2[/tex]

Step-by-step explanation:

The diagram is attached below.

Area of the Rectangular Faces

[tex]8 X 6.5 =52$ ft^2\\8 X 2.5 =20$ ft^2\\8 X 6= 48$ ft^2[/tex]

Area of the Triangular face

[tex]=\dfrac12 X 2.5 X 6 =7.5$ ft^2[/tex]

Therefore, Options A and C could be the area of one lateral face of the triangular prism.

Answer:

C

Step-by-step explanation:

If 2/3 of a certain number is subtracted from twice the number, the result is 20. Find the number.​

Answers

Let x be the number.

Set up an equation:

2x - 2/3x = 20

Simplify:

1 1/3x = 20

Divide both sides by 1 1/3

X = 15

The number is 15

Answer: 60
Step by Step Explanation:
Let the number be x
So, x-2/3x=20
=> x/1 - 2/3x = 20
=> (3x - 2x)/3 = 20
=> x/3 = 20
=> x= 20*3
=> x=60
Checking if the solution is correct:
So substitute the value of x in x-2/3x=20
As we know x=60
So, => 60 - 2/3*60 = 20
=> 60 - 40 = 20
As 20 = 20
So this answer is correct

A bag contains six balls labeled 1 through 6. One ball will be randomly picked.
What is the probability of picking an odd number?
Write your answer as a fraction in simplest form.

Answers

S = sample space = set of all possible outcomes

S = set of whole numbers 1 through 6

S = {1,2,3,4,5,6}

E = event space = set of outcomes we want to happen

E = set of odd numbers between 1 through 6

E = {1,3,5}

We have 3 items in set E and 6 items in set S. So there are 3 ways to get what we want to happen out of 6 ways total. The probability is therefore 3/6 = 1/2

Answer: 1/2

At noon, ship A is 70 km west of ship B. Ship A is sailing south at 35 km/h and ship B is sailing north at 25 km/h. How fast is the distance between the ships changing at 4:00 PM

Answers

Answer:

57.6 km/h

Step-by-step explanation:

We are told that At noon, ship A is 70 km west of ship B.

Thus, coordinates of initial position of A and B is;

A(0,0) and B(70,0)

Now, we are told that Ship A is sailing south at 35 km/h and ship B is sailing north at 25 km/h. Thus, the final position of ship A and B after t hours are;

A(0,-35t) and B(70,25t)

Thus, distance between the two ships at time t hours is;

d(t) = √[(70 - 0)² + (25t - (-35t))²]

d(t) = √(4900 + 3600t²)

Now, to find how fast the distance between the ships changing, let's differentiate using the chain rule;

d'(t) = [1/(2√(4900 + 3600t²))] × 7200t

d'(t) = 3600t/√(4900 + 3600t²)

d'(t) = 3600t/10√(49 + 36t²)

d'(t) = 360t/√(49 + 36t²)

Now, at 4pm,it would have been 4 hours from noon. Thus, t = 4.

So;

d'(t) = (360×4)/√(49 + 36(4²))

d'(t) = 1440/√(49 + 576)

d'(t) = 1440/√625

d'(t) = 1440/25

d'(t) = 57.6 km/h

Simplify the expression:
3+ – 5(4+ – 3v)

Answers

Answer:

The answer is

15v - 17

Step-by-step explanation:

3+ – 5(4+ – 3v) can be written as

3 - 5( 4 - 3v)

Expand and simplify

That's

3 - 20 + 15v

15v - 17

Hope this helps you

Suppose a city official conducts a hypothesis test to test the claim that the majority of voters oppose a proposed school tax. Assume that all of the conditions fro proceeding with a one-sample test on proportions have been met. The calculated test statistic is approximately 1.23 with an associated p-value of approximately 0.1093. Choose the conclusion that provides the best interpretation for the p-value at a significance level of alpha = 0.05.
A. If the null hypothesis is true, then the probability of getting a test statistic that is as or more extreme than the calculated test statistic of 1.23 is 0.1093. This result is surprising (or considered unusual) and could not easily happen by chance.
B. If the null hypothesis is true, then the probability of getting a test statistic that is as or more extreme than the calculated test statistic of 1.23 is 0.1093. This result is not surprising (or considered unusual) and could easily happen by chance
C. The p-value should be considered extreme: therefore, the hypothesis test proves that the null hypothesis is true
D. none of the above

Answers

Answer:

The correct option is (B).

Step-by-step explanation:

The p-value is well-defined as per the probability, [under the null-hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.

In this case, we need to test the claim that the majority of voters oppose a proposed school tax.

The hypothesis can be defined as follows:

H₀: The proportion of voters opposing a proposed school tax is not a majority, i.e. p ≤ 0.50.

Hₐ: The proportion of voters opposing a proposed school tax is a majority, i.e. p > 0.50.

It is provided that the test statistic value and p-value are:

z = 1.23

p-value = 0.1093

The probability, [under the null-hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic is 0.1093.

The significance level of the test is:

α = 0.05

The p-value of the test is larger than the significance level of the test.

p-value = 0.1093 > α = 0.05

The null hypothesis will not be rejected.

Concluding that there is not enough evidence to support the claim.

Thus, the correct option is:

"If the null hypothesis is true, then the probability of getting a test statistic that is as or more extreme than the calculated test statistic of 1.23 is 0.1093. This result is not surprising (or considered unusual) and could easily happen by chance"

Find the measure of y. Polygon Angle-Sum theorems

Answers

Answer:

z = 70°

y = 103°

Step-by-step explanation:

From the picture attached,

110° + z° = 180° [Supplementary angles]

z = 180 - 110

z = 70°

Since sum of interior angles of a polygon = (n - 2)×180°

where n = number of sides of the polygon

For a quadrilateral (n = 4),

Sum of interior angles = (4 - 2) × 180°

                                     = 360°

z° + y° + 100° + 87° = 360°

70° + y° + 187° = 360°

y = 103°

Therefore, measure of the angles x = 70° and y = 103°.

A central angle is best described as which of the following?

A.
It has a measure greater than 180 degrees.

B.
It is an angle that has its vertex on the circle.

C.
It is an angle that has its vertex at the center of a circle.

D.
It is part of the circumference of a circle.

Answers

Answer:

C. It is an angle that has its vertex at the center of a circle.

Step-by-step explanation:

That's the definition.

A. is wrong. An angle with a measure greater than 180° is an obtuse angle,

B. is wrong. An angle that has its vertex on the circle is an inscribed angle.

D. is wrong. Part of the circumference of a circle is an arc.

Find the mean and standard deviation for each binomial random variable:

Answers

Answer: a) Mean = [tex]=37.80[/tex]

Standard deviation=[tex]=1.9442[/tex]

b) Mean = [tex]56.00[/tex]

Standard deviation=[tex]4.0988[/tex]

c) Mean = [tex]=24[/tex]

Standard deviation=[tex]2.4495[/tex]

Step-by-step explanation:

To compute Mean and standard deviation , we use following formula:

Mean = [tex]n\pi[/tex]

Standard deviation=[tex]\sqrt{n\pi(1-\pi)}[/tex]

a. [tex]n=42,\ \pi=0.90[/tex]

Mean = [tex]42\times0.90=37.80[/tex]

Standard deviation=[tex]\sqrt{42(0.90)(0.10)}=\sqrt{3.78}\approx1.9442[/tex]

b. [tex]n=80,\ \pi=0.70[/tex]

Mean = [tex]80\times0.70=56.00[/tex]

Standard deviation=[tex]\sqrt{80(0.70)(0.30)}=\sqrt{16.8}\approx4.0988[/tex]

c. [tex]n=32,\ \pi=0.75[/tex]

Mean = [tex]32\times0.75=24[/tex]

Standard deviation=[tex]\sqrt{32(0.75)(0.25)}=\sqrt{6}\approx2.4495[/tex]

How will the metric system be used in your furture career

Answers

Answer:

i feel as if in the United States, both the metric system and the English system of measurement are used, although the English system predominates. This discussion question has three parts:

Look around you to find something in the U.S. that is measured in metrics. Describe it to the class.

Give an example of how you think the metric system will be used in your future career.

Do you think the U.S. should switch to metric system exclusively? Why or why not?

This week we learned about the metric and U.S. customary measurement systems. Please upload and submit your responses to the following questions in at least 150 words:

In reflecting on both measurement systems, what did you find most important?

Explain how both measurement systems could relate to your life, community, or current/future career.

Expert Answer

Step-by-step explanation:

the numbers of students in the 10 schools in a district are given below. ( Note that these are already ordered from Least to Greatest) 198, 216, 220, 236, 246, 252, 253, 260, 290, 319. Suppose that the number 319 from this list changes to 369. Answer the following what happens to the median? what happens to the mean?​

Answers

Answer:median:249    

Step-by-step explanation:

median:198] 216} 220] 236] 246 252 [253[ 260 {290[ 369

246 +252=498

498/2=249

as for the mean  i will give you that later

Use the distributive property to write an equivalent expression to 2(n + 5)​

Answers

Answer:

2n + 10.

Step-by-step explanation:

2(n + 5)

= 2 * n + 2 * 5

= 2n + 10.

Hope this helps!

Answer: 2n + 10

Explanation: In this problem, the 2 "distributes" through the parenthses which means that it multiplies by each of the terms inside.

So we have 2(n) + 2(5) which simplifies to 2n + 10.

6x²-7x=20 solve the following quadratic equation

Answers

Answer:

x = -4/3 and x = 5/2.

Step-by-step explanation:

6x² - 7x = 20

6x² - 7x - 20 = 0

To solve this, we can use the quadratic formula to solve this.

[please ignore the A-hat; that is a bug]

[tex]\frac{-b±\sqrt{b^2 - 4ac} }{2a}[/tex]

In this case, a = 6, b = -7, and c = -20.

[tex]\frac{-(-7)±\sqrt{(-7)^2 - 4 * 6 * (-20)} }{2(6)}[/tex]

= [tex]\frac{7±\sqrt{49 + 80 * 6} }{12}[/tex]

= [tex]\frac{7±\sqrt{49 + 480} }{12}[/tex]

= [tex]\frac{7±\sqrt{529} }{12}[/tex]

= [tex]\frac{7±23 }{12}[/tex]

[tex]\frac{7 - 23 }{12}[/tex] = [tex]\frac{-16 }{12}[/tex] = -8 / 6 = -4 / 3

[tex]\frac{7 + 23 }{12}[/tex] = [tex]\frac{30}{12}[/tex] = 15 / 6 = 5 / 2

So, x = -4/3 and x = 5/2.

Hope this helps!  

Answer:

[tex]x1 = - \frac{4}{3} [/tex][tex]x2 = \frac{5}{2} [/tex]

Step-by-step explanation:

[tex]6 {x}^{2} - 7x = 20[/tex]

Move constant to the left and change its sign

[tex] {6x}^{2} - 7x - 20 = 0[/tex]

Write -7x as a difference

[tex]6 {x}^{2} + 8x - 15x - 20 = 0[/tex]

Factor out 2x from the expression

[tex]2x(3x + 4) - 15x - 20 = 0[/tex]

Factor out -5 from the expression

[tex]2x(3x + 4) - 5(3x + 4) = 0[/tex]

Factor out 3x + 4 from the expression

[tex](3x + 4)(2x - 5) = 0[/tex]

When the product of factors equals 0 , at least one factor is 0

[tex]3x + 4 = 0[/tex]

[tex]2x - 5 = 0[/tex]

Solve the equation for X1

[tex]3x + 4 = 0[/tex]

Move constant to right side and change its sign

[tex] 3x = 0 - 4[/tex]

Calculate the difference

[tex]3x = - 4[/tex]

Divide both sides of the equation by 3

[tex] \frac{3x}{3} = \frac{ - 4}{3} [/tex]

Calculate

[tex]x = - \frac{4}{3} [/tex]

Again,

Solve for x2

[tex]2x - 5 = 0[/tex]

Move constant to right side and change its sign

[tex]2x = 0 + 5[/tex]

Calculate the sum

[tex]2x = 5[/tex]

Divide both sides of the equation by 2

[tex] \frac{2x}{2} = \frac{5}{2} [/tex]

Calculate

[tex]x = \frac{5}{2} [/tex]

[tex]x1 = - \frac{4}{3} [/tex]

[tex]x2 = \frac{5}{2} [/tex]

Hope this helps...

Best regards!!

A firm has the​ marginal-demand function Upper D prime (x )equalsStartFraction negative 1200 x Over StartRoot 25 minus x squared EndRoot EndFraction . Find the demand function given that Dequals16 comma 000 when x equals $ 4 per unit.

Answers

Answer:

The demand function is  [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

Step-by-step explanation:

A firm has the​ marginal-demand function [tex]D' x = \dfrac{-1200}{\sqrt{25-x^2 } }[/tex].

Find the demand function given that D = 16,000 when x = $4 per unit.

What we are required to do  is to find the demand function D(x);

If we integrate D'(x) with respect to x ; we have :

[tex]\int\limits \ D'(x) \, dx = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

Let represent   t  with [tex]\sqrt{25-x^2}}[/tex]

The differential of t with respect to x is :

[tex]\dfrac{dt}{dx}= \dfrac{1}{2 \sqrt{25-x^2}}}(-2x)[/tex]

[tex]\dfrac{dt}{dx}= \dfrac{-x}{ \sqrt{25-x^2}}}[/tex]

[tex]{dt}= \dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex]

replacing the value of  [tex]\dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex]  for dt in   [tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

So; we can say :

[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = 1200\int\limits{\dfrac{- x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = 1200\int\limits \ dt[/tex]

[tex]D(x) = 1200t+ C[/tex]

Let's Recall that :

t  = [tex]\sqrt{25-x^2}}[/tex]

Now;

[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex]

GIven that:

D = 16,000 when x = $4 per unit.

i.e

D(4) = 16000

SO;

[tex]D(x) = 1200(\sqrt{25-x^2}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{25-4^2}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{25-16}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{9}})+ C[/tex]

[tex]D(4) = 1200(3}})+ C[/tex]

16000 = 1200 (3) + C

16000 = 3600 + C

16000 - 3600 = C

C = 12400

replacing the value of C = 12400 into [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex], we have:

[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

∴ The demand function is  [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

The profit y (in dollars) for a company for selling x games is represented by y=32x. Graph the equation. ANSWER BEFORE 11 FOr BOnUs PoINTS!!!

Answers

Answer:

I guess that we have the linear equation:

y = 32*x

Where y is the profit, and x is the number of games sold.

Then the first step may be doing a table.

Give x different values, then find the value of y.

if x = 0

y = 32*0 = 0

if x = 1, y = 32*1 = 32

if x = 2, y = 2*32 = 64

Then the points:

(0,0) (1,32) and (2, 64) belong to this line, now we need to conect them with a straigth line and its ready.

The graph will be:

When evaluating a multiple regression model, for example when we regress dependent variable Y on two independent variables X1 and X2, a commonly used goodness of fit measure is:

Answers

Answer:

Adjusted-R2

Step-by-step explanation:

When evaluating a multiple regression model, a commonly used goodness of fit is the adjusted-R2. It allows for a comparison of regression models with multiple predictors or independent variables. The addition of independent variables usually causes the model to be more reliable. The adjusted-R2 considers the effect of additional independent variables. It usually adjusts for the number of terms in the model.

Amber created a scatter plot and drew a line of best fit, as shown. What is the equation of the line of best fit that Amber drew?

Answers

Answer:

The correct answer for the best line of fit is C: y = 1/3x+12

Step-by-step explanation:

So our goal here is to find the best equation that matches the line of fit.

So right away we can already eliminate two of the options because in the scatter point it shows that the starting y-intercept is 12 and two of the options have a y-intercept of 15. So we are able to tell that Option B and Option D isn't the equation for the lien of fit.

Now we are left with Option A and Option C, which both have a y-intercept of 12. To find the right equation that best matches the line of fit we look at the slope. Option A has a slope of 3x while Option C has a slope of 1/3x, to tell what slope the line of has we applied both option's slope and see which one matches it.

When we match Option A's slope which is 3x it doesn't match because a slope of 3x is going first going up the y-axis 3 times then moving through the x-axis 1 time. Which would had made the line of fit more steep.

Next we match Option C's slope which is 1/3x this slope matches the line of fit because in the scatter plot it clearly shows  it going up 1 time on the y=axis and 3 times through the x-axis. Which made the line of fit not that steep.

So the correct answer to this question is C:  y = 1/3x+12.

Here a picture of the line of fit if it has a slope of 3x.

Answer:

correct answer  C: y = 1/3x+12

Step-by-step explanation:

i just did the problem

Identify any outlier(s) in the data. {52, 61, 42, 46, 50, 51, 49, 44, 40, 66, 53, 67, 45, 64, 60, 69}

Answers

There are none
For there to be a outlier there would need to be a number that is either around 74 or 34

An outlier in statistics is a data point that deviates considerably from other observations. The given data set has no outlier.

What is an outlier?

An outlier in statistics is a data point that deviates considerably from other observations. An outlier can be caused by measurement variability or by experimental mistake; the latter is sometimes eliminated from the data set.

To find the outlier for the given data set follow the given steps.

Step one: The first step is to find the quartiles for the data set.

For this data set, the quartiles are:

Q1 = 45.5

Q3 = 62.5

Step Two: Find the Interquartile Range

The interquartile range is the difference between the first and third quartiles.

IQR = Q3 - Q1

IQR = 45.5 - 62.5

IQR = 17

Step Three:

The next step is to set up a fence beyond the first and third quartiles using the interquartile range.

Lower Fence = Q1 - (1.5 × IQR)

Lower Fence = 45.5 - (1.5 × 17)

Lower Fence = 20

Upper Fence = Q3 + (1.5 × IQR)

Upper Fence = 62.5 + (1.5 × 17)

Upper Fence = 88

Step Four: Find the Outliers

Any numbers in the data that are above or below the fences are outliers.

Since there are no numbers outside the two fences. Hence, it can be concluded that the given data set does not have, any outlier.

Learn more about Outlier:

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Below are the jersey numbers of 11 players randomly selected from a football team. Find the​ range, variance, and standard deviation for the given sample data.
33 29 97 56 26 78 83 74 65 47 58
What do the results tell​ us?
A. Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.
B. Jersey numbers on a football team vary much more than expected.
C. The sample standard deviation is too large in comparison to the range.
D. Jersey numbers on a football team do not vary as much as expected.

Answers

Answer:

Option(A) is correct

Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

Step-by-step explanation:

The given data set in the question are ;33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58

the range can be determined by finding the highest value and subtract it to the lowest value. In this case the values are:

Highest = 97

Lowest = 71

Range = highest value - Minimum value

Range = 97 - 26 = 71

[tex] Range= 71[/tex]

mean of the data is the summation of all the numbers in the data set divided by the number of given samples.

Mean = (33 + 29 + 97 + 56+ 26 + 78 + 83 74+ 65 + 47 + 58)/11

= 647/11

[tex]Mean value =58.7[/tex]

Now to find the variance of the data set by using below formular

σ²=[ (xᵢ -mean)²]/n-1

[(33-58.7)² +(29-58.7)²+( 97-58.7)²+( 56-58.7)²+( 26 -58.7)²+(78-58.7)²+( 83 -58.7)²+(74-58.7)²+( 65-58.7)²+( 47 -58.7)²+(58 -58.7)²]/10

[tex]Variance=546[/tex]

Now, we will calculate standard deviation by taking square root over variance

σ =√(variance)

σ =√(546)

[tex]Standard deviation= 23.4[/tex]

Hence, the range is 71 ,variance is 546 and standard deviation is 23.4 therefore,

Option A is the answer that is Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

bh. Find the area of the shape with the given
The area of a triangle can be found by the formula A
base (b) and height (h).
h
b
b = 5 cm and h = 3 cm​

Answers

Answer:

[tex]7.5cm^2[/tex]

Step-by-step explanation:

Well using the following formula,

[tex]\frac{b*h}{2}[/tex]

5*3 = 15

15 / 2

7.5cm^2

Answer:[tex]7.5cm^{2}[/tex]

Step-by-step explanation:

h=3

b=5

area=1/2 x b x h

1/2 x 5 x 3

area=7.5

A catering service offers 11 appetizers, 8 main courses, and 4 desserts. A customer is to select 9 appetizers, 3 main courses, and 2 desserts for a banquet. In how many ways can this be done?

Answers

Answer:

Total number of required ways = 18480

Step-by-step explanation:

Given that

Total appetizers = 11

Total main courses = 8

Total desserts = 4

To be selected 9 appetizers

3 main courses and

2 desserts.

To find:

Number of ways of selecting them.

Solution:

Number of ways to select 'r' number of items out of 'n' number of items is given as:

[tex]_nC_r = \dfrac{n!}{(n-r)!r!}[/tex]

One important property:

[tex]_nC_r = _nC_{n-r}[/tex]

Here we have 3 items, we will find each items' number of ways of selecting and then will multiply all of them.

Number of ways to select 9 appetizers out of 11 appetizers:

[tex]_{11}C_9\ or\ _{11}C_2 = \dfrac{11 \times 10}{2} = 55[/tex]

Number of ways to select 3 out of 8 main courses:

[tex]_{8}C_3= \dfrac{8 \times 7 \times 6}{6} = 56[/tex]

Number of ways to select 2 desserts out of 4:

[tex]_{4}C_2= \dfrac{4 \times 3}{2} = 6[/tex]

Total number of ways = [tex]55 \times 56 \times 6[/tex] = 18480

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