Answer: 0.18
Step-by-step explanation:
P(1 unit is defective)= C2 1* P^1*Q^1
C2 1= 2!/(1!*(2-1)!)=2
P=0.1 - probability that items from a production line are defective
Q=1-0.1=0.9 - probability that items from a production line are functional.
P(1 unit is defective)= 2*0.1*0.9=0.18
A rectangle is to be inscribed in a right triangle having sides of length 6 in, 8 in, and 10 in. Find the dimensions of the rectangle with greatest area assuming the rectangle is positioned as in Figure 1. Figure1
Answer: width = 2.4 in, length = 5
Step-by-step explanation:
The max area of a right triangle is half the area of the original triangle.
Area of the triangle = (6 x 8)/2 = 24
--> area of rectangle = 24 ÷ 2 = 12
Next, let's find the dimensions.
The length is adjacent to the hypotenuse. Since we know the area is half, we should also know that the length will be half of the hypotenuse.
length = 10 ÷ 2 = 5
Use the area formula to find the width:
A = length x width
12 = 5 w
12/5 = w
2.4 = w
The dimensions of the rectangle with greatest area is length is 3 inch and the width is 4 inch.
Let the length and width of the rectangle be x and y.
Then Area of the rectangle = xy
Now, from the triangle we can conclude that
[tex]\frac{6-x}{y} =\frac{6}{8} \\y=8(\frac{6-x}{6} ).[/tex]
Put the value of y in Area we get
[tex]A(x)=x\frac{8}{6} (6-x)\\A(x)=\frac{8}{6}(6x-x^{2} )\\[/tex]
Differentiating it w.r.t x we get
[tex]A'(x)=\frac{8}{6}(6-2x )\\A''(x)=\frac{8}{6}(0-2 )\\A''(x)=\frac{-8}{3}[/tex]
Put A'(x)=0 for maximum /minimum value
[tex]A'(x)=0\\\frac{8}{6}(6-2x)=0\\x=3[/tex]
Now, [tex]A''(3)=-\frac{8}{3} <0[/tex]
Therefore the area of the rectangle is maximum for x=3 inch
Now,
[tex]y=\frac{8}{6} (6-3)\\y=4[/tex]
Thus the dimensions of the rectangle with greatest area is 3 inch by 4 inch.
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Find the exact value of each expression, if it defined. ( if answer is undefined, enter undefined) tan (-1)
Answer:
[tex]tan(-1) \approx -0.02[/tex]
Step-by-step explanation:
The given expression is
[tex]tan(-1)[/tex]
The tangent of -1 is defined, it's around -0.02.
The tangent is a trigonometric function with a period of [tex]\pi[/tex], where each period is separated by a vertical asymptote which indicates that the function is not determined through all its domain, that's what the question refers to when it says "if is undefined, enter undefined".
However, at [tex]x=-1[/tex], the tangent is determined, that means, there's no asymptote on that coordinate, that's why it has a "determined value", which is -0.02 approximately.
[tex]tan(-1) \approx -0.02[/tex]
A local bottler, Fossil Cove, wants to ensure that an average of 16 ounces of beer is used to fill each bottle. Ben takes a random sample of 48 bottles and finds the average weight to be 15.8 ounces. Historically, the standard deviation has been 0.8 ounces.
Required:
a. Complete a hypothesis test (using the p-‐‐value approach). Interpret your results.
b. How would your answer change if instead of being given that the sample standard deviation was 0.8 ounces you were given the sample variance is 0.64?
Answer:
(a) The mean weight of beer used to fill each bottle is 16 ounces.
(b) The answer of part (a) would not change.
Step-by-step explanation:
A local bottler, Fossil Cove, wants to ensure that an average of 16 ounces of beer is used to fill each bottle.
Ben takes a random sample of n = 48 bottles and finds the average weight to be [tex]\bar x=[/tex] 15.8 ounces. Also it is known that the standard deviation is, σ = 0.8 ounces.
(a)
The hypothesis can be defined as follows:
H₀: The mean weight of beer used to fill each bottle is 16 ounces, i.e. μ = 16.
Hₐ: The mean weight of beer used to fill each bottle is not 16 ounces, i.e. μ ≠ 16.
Assume that the significance level of the test is, α = 0.05.
As the population standard deviation is provided, we will use a z-test for single mean.
Compute the test statistic value as follows:
[tex]z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}[/tex]
[tex]=\frac{15.8-16}{0.80/\sqrt{48}}\\\\=-1.732[/tex]
The test statistic value is -1.732.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected.
Compute the p-value for the two-tailed test as follows:
[tex]p-value=2\cdot P(Z>-1.732)[/tex]
[tex]=2\times [1-P(Z<1.732)]\\\\=2\times [1-0.04182]\\\\=0.08364\\\\\approx 0.084[/tex]
*Use a z-table for the probability.
The p-value of the test is 0.084.
p-value = 0.084 > α = 0.05
The null hypothesis will not be rejected.
Thus, it can be concluded that the mean weight of beer used to fill each bottle is 16 ounces.
(b)
The standard deviation of a random variable is the square root of the variance.
[tex]SD=\sqrt{Variance}[/tex]
So, if the variance was 0.64, then the standard deviation will be:
[tex]SD=\sqrt{Variance}=\sqrt{0.64}=0.80[/tex]
Thus, the answer of part (a) would not change.
please help Find: ∠a ∠b ∠c
Answer:
A-40
B-140
C-140
Step-by-step explanation:
b and c are supplementary angles to angle 40.
Therefore 180-40= 140.
and opposite angles in a quadrilateral are congruent to each other.
Use the minimum and maximum data entries and the number of classes to find the class width, the lower class limits, and the upper class limits. min = 14, max = 121, 8 classes
Answer:
The class width is [tex]C_w \approx 13[/tex]
Step-by-step explanation:
From the question we are told that
The upper class limits is [tex]max = 121[/tex]
The lower class limits is [tex]min = 14[/tex]
The number of classes is [tex]n = 8 \ classes[/tex]
The class width is mathematically represented as
[tex]C_w = \frac{max - min}{n }[/tex]
substituting values
[tex]C_w = \frac{121 - 14}{8 }[/tex]
[tex]C_w = 13.38[/tex]
[tex]C_w \approx 13[/tex]
Since
A ball is thrown straight down from the top of a 435-foot building with an initial velocity of -27 feet per second. Use the position function below for free-falling objects. s(t) = -16t^2 + v_0t + s_0 What is its velocity after 2 seconds? v(2) = -91 ft/s What is its velocity after falling 364 feet? v = 1.61 ft/s Find an equation of the parabola y = ax^2 + bx + c that passes through (0, 1) and is tangent to the line y = 5x - 5 at (1, 0). Y = 5x + 10
Answer:
a) The velocity of the ball after 2 seconds is -91 feet per second, b) The velocity of the ball after falling 364 feet is 155 feet per second, c) The equation of the parabola that passes through (0,1) and is tangent to the line y = 5x - 5 is [tex]y = 6\cdot x^{2}-7\cdot x +1[/tex].
Step-by-step explanation:
a) The velocity function is obtained after deriving the position function in time:
[tex]v (t) = -32\cdot t -27[/tex]
The velocity of the ball after 2 seconds is:
[tex]v(2\,s) = -32\cdot (2\,s) -27[/tex]
[tex]v(2\,s) = -91\,\frac{ft}{s}[/tex]
The velocity of the ball after 2 seconds is -91 feet per second.
b) The time of the ball after falling 364 feet is found after solving the position function as follows:
[tex]435\,ft - 364\,ft = -16\cdot t^{2}-27\cdot t + 435\,ft[/tex]
[tex]-16\cdot t^{2} - 27\cdot t + 364 = 0[/tex]
The solution of this second-grade polynomial is represented by two roots:
[tex]t_{1} = 4\,s[/tex] and [tex]t_{2} = -5.688\,s[/tex].
Only the first root is physically reasonable since time is a positive variable. Now, the velocity of the ball after falling 364 feet is:
[tex]v(4\,s) = -32\cdot (4\,s) - 27[/tex]
[tex]v(4\,s) = -155\,\frac{ft}{s}[/tex]
The velocity of the ball after falling 364 feet is 155 feet per second.
c) Let consider the equation for a second order polynomial that passes through (0, 1) and its first derivative that passes through (1, 0) and represents the give equation of the tangent line. That is to say:
Second-order polynomial evaluated at (0, 1)
[tex]c = 1[/tex]
Slope of the tangent line evaluated at (1, 0)
[tex]5 = 2\cdot a \cdot (1) + b[/tex]
[tex]2\cdot a + b = 5[/tex]
[tex]b = 5 - 2\cdot a[/tex]
Now, let evaluate the second order polynomial at (1, 0):
[tex]0 = a\cdot (1)^{2}+b\cdot (1) + c[/tex]
[tex]a + b + c = 0[/tex]
If [tex]c = 1[/tex] and [tex]b = 5 - 2\cdot a[/tex], then:
[tex]a + (5-2\cdot a) +1 = 0[/tex]
[tex]-a +6 = 0[/tex]
[tex]a = 6[/tex]
And the value of b is: ([tex]a = 6[/tex])
[tex]b = 5 - 2\cdot (6)[/tex]
[tex]b = -7[/tex]
The equation of the parabola that passes through (0,1) and is tangent to the line y = 5x - 5 is [tex]y = 6\cdot x^{2}-7\cdot x +1[/tex].
Which expression is equivalent to ? (2^1/2 times 2^3/4)^2
Answer: B or square root 2^5
Step-by-step explanation: I checked on my calculator
how do you slove 21 - 4d for d= 5
Look at the figure. Which step should be taken next to construct a line through point P perpendicular to BA?
ANSWER:
C. Place the compass on point A. Open the compass to a point between point P and point B.
EXPLANATION:
A perpendicular is a line that would be at a right angle to line BA.
The next step is to chose a radius that is greater than PB or PA so as to construct the bisector. And this can be done by placing the compass on point A, and open the compass to a point between point P and point B.
Use this radius to draw an arc above and below the line, and repeat the same using B as the center with the same radius. This would form two intersecting arcs above and below line BA. Join the point of intersection of the arcs by a straight line through P. This is the bisector of line BA through point P.
Given: AD = BC and AD || BC
Prove: ABCD is a parallelogram.
Angles Segments Triangles Statements Reasons
ZBCA
DAC
A
Statements
Reasons
00
D
с
Assemble the proof by dragging tiles to
the Statements and Reasons columns.
Answer:
See below
Step-by-step explanation:
Proof:
Statements | Reasons
AD ≅ BC | Given
AD ║ BC | Given
AC ≅ AC | Reflexive Property
∠DAC ≅ ∠ACB | If 2 || lines are cut by a trans., the | alternate interior ∠s are congruent.
ΔADC ≅ ΔBCA | S.A.S Postulate
BA ≅ DC | Corresponding sides of congruent Δs
So, quad. ABCD is a ║gm | If a quad. has its opposite sides
| congruent, the quad. is a parallelogram.
It is prove that given quadrilateral is a parallelogram.
Given that,AD ≅ BC and AD ║ BC
By reflexive property,AC ≅ AC
If two parallel lines are cut by a transversal. Then, alternate interior angles are congruent.So that, ∠DAC ≅ ∠ACB
By Side - angle - Side congruency rule,ΔADC ≅ ΔBCA
Since, the Corresponding sides of congruent triangles are congruent.So that, BA ≅ DC
Hence, opposite sides of given quadrilateral are equal. Therefore, given quadrilateral are parallelogram.
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PLESE HELPPP!!!!!!!!!!!!!!!!
Answer:
B. [tex]\frac{6}{2x^{2} - 5x}[/tex]
Step-by-step explanation:
The product of the ratioal expressions given above can be found as follows:
[tex] = \frac{2}{x} * \frac{3}{2x - 5} [/tex]
Multiply the denominators together, and the numerators together, separately to get a single expression
[tex] \frac{2(3)}{x(2x - 5)} [/tex]
[tex] = \frac{6}{x(2x) - x(5)} [/tex]
[tex]= \frac{6}{2x^{2} - 5x}[/tex]
The product of the expression [tex]\ = \frac{2}{x}*\frac{3}{2x - 5}[/tex] = [tex]\frac{6}{2x^{2} - 5x}[/tex]
The answer is B.
What is the slope of the line
described by -4X + 2Y = 16?
A. -2
B. -4
C. 4
D. 2
E. 16
Answer: THe slope is 2
SO answer d
Step-by-step explanation:
-4X + 2Y = 16 add 4x to the other side so equation is
2y=16+4x divided by 2
y=8+2x
Which type of graphs allows the reader to view the raw data values?
Answer:
bar graphs
Step-by-step explanation:
as in a bar graph, we don't do any calculations to graph on a paper,
so the data values, are taken RAW while graphing.
Question 15 of 25
What is the solution to this equation?
X + 8 = -3
Answer:
x=-11
Step-by-step explanation:
x+8=-3
x=-3-8 :- collect like term
since we are adding two negative numbers, we will let the number be negative but add them.
x=-11
Hope it helps :)
Answer:
x=-11
Step-by-step explanation:
x+8=-3
collect like terms;
x=-3-8
x=-11
Here is a list of ages (years) of children in a room: 4, 3, 2, 10, 10, 6, 7 State the median.
Answer: 6
Step-by-step explanation:
Lets re- write the numbers in growing order.
2,3,4,6,7,10,10
The number that stays exactly in the middle of the the sequence is the median.
Number 6 stays in the middle. So 6 is the median
Answer
6Step by step explanation
Given data : 4 , 3 , 2 , 10 , 10 , 6 , 7
Arranging the data in ascending order, we have,
2 , 3 , 4 , 6 , 7 , 10 , 10
Here, n ( total number of items) = 7
Now, position of median:
[tex] {( \frac{n + 1}{2}) }^{th} [/tex] item
plug the value
[tex] = {( \frac{7 + 1}{2} )}^{th} [/tex] item
Add the numbers
[tex] =( { \frac{8}{2} )}^{th} [/tex] item
Divide
[tex] = {4}^{th} [/tex] item
i.e 4th item is the median
Median = 6
------------------------------------------------------------------------
Further more explanation:
Let's take another example:
please see the attached picture.
In the above series, the numbers are arranged in ascending order. Here, the fourth item 17 has three items before it and three items after it. So, 17 is the middle item in the series. 17 is called the median of the series.
Thus, Median is the value of the middle - most observation, when the data are arranged in ascending or descending order of magnitude.
Hope I helped..
Best regards!!
use the substitution method to solve the system of equations. Choose the correct ordered pair y=3x 2x+3y=55
Answer:
(x,y) = (5,15)
Step-by-step explanation:
y = 3x
2x + 3y = 55
2x + 3(3x) = 55
2x + 9x = 55
11x = 55
x = 5
y = 3(5)
y = 15
please please please help. will do anything, anything!!
Hi there! :)
Answer:
2nd choice. f(x) = 4 sin x + 2
Step-by-step explanation:
Recall that the transformations form of a sine function is:
y = ±a sin(b(x-h)) + k
Where:
'a' changes the amplitude
'b' changes the period
'h' is a horizontal shift
'k' is a vertical shift, or a change in the midline.
In this instance, the function has a midline of y = 2, which means an equation representing this must have a 'k' value of 2.
The only equation that contains this value is:
f(x) = 4 sin x + 2.
Answer:
I'm pretty positive the answer is B. f(x) = 4sinx + 2
Step-by-step explanation:
Since d = 2 and the amplitude is 4 and there is nothing else effecting the function you are going up the graph 2 vertically and the amplitude will just go up and down 4 with you midline being at y = 2.
Maya is choosing between several pay plans for her new job. If she usually has monthly sales of about $5,000, which plan would allow Maya to earn the most money in a month? Plan Monthly base salary Commission rate A $500 8% B $600 7% C $700 6% D $800 5% plan A plan B plan C plan D
Answer:
Well Plan D
Step-by-step explanation:
Answer:
plan D.
Step-by-step explanation:
2021 edge
Write the expression as the logarithm of a single number or expression
4 In 2 +3 In 5
4 In 2 + 3 In 5-
(Simplify your answer.)
Answer:
ln(2000) = 7.601
Step-by-step explanation:
For this we need to know the rules of logarithms, specifically the product rule and the power rule. The product rule is simply ln(a*b) = ln(a) + ln(b). The power rule is simply ln(a^b) = b ln(a).
With these rules, let's begin to simplify the expression:
4 ln(2) + 3 ln(5)
= ln(2^4) + ln(5^3)
= ln(16) + ln(125)
= ln(16 * 125)
= ln(2000)
= 7.601
Hope this helps. Cheers.
A logarithm is a power to which a number must be raised in order to get some other number.
The value of the expression 4 log 2 + 3 log 5 as a single number is 3.30102.
What is a log?A logarithm is a power to which a number must be raised in order to get some other number.
Example:
log 10 = 1
log 100 = log 10² = 2 log 10 = 2 x 1 = 2
log 1000 = log 10³ = 3 log 10 = 3 x 1 = 3
log 0 = undefined
log 1 = 0
We have,
Some formulas for log:
log[tex]x^{n}[/tex] = n log x
log mn = log m + log n
Given,
4 log 2 + 3 log 5
= log [tex]2^{4}[/tex] + log [tex]5^{3}[/tex]
= log 16 + log 125
= log (16 x 125)
= log 2000
= 3.30102
Thus the value of the expression 4 log 2 + 3 log 5 as a single number is
3.30102.
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A firm just paid an annual dividend of $1.40 and increases that dividend by 2 percent each year. How do you find the price if the firm's stock at year 4 if the discount rate is 13 percent?
Answer:
14.05
Step-by-step explanation:
We have the following:
Current Dividend = D0 = $ 1.40
g = growth rate = 2%
r = discount rate = 13%
Dividend in Year 5
= D5 = D0 * (1 + g) ^ 5
= $ 1.40 * (1 + 2%) ^ 5
= $ 1.40 * (1.02) ^ 5
Firm Stock Price at the end of year 4 = Dividend in Year 5 / (r - g)
= $ 1.40 * (1.02) ^ 5 / (13% -2%)
= $ 1.40 * (1.02) ^ 5 / (0.13 - 0.02)
Therefore, firm stock at the end of year 4 is
P4 = $ 1.40 * (1.02) ^ 5 / (0.13 - 0.02) = 14.05
WILL GIVE YOU BRAINLIEST
Answer:
AB = 20 tan55°
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan55° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{AB}{20}[/tex] ( multiply both sides by 20 )
20 tan55° = AB
Solve for x. Then, find m∠FDG and m∠GOF. A. x = 24; m∠FDG = 56°; m∠GOF = 106° B. x = 29; m∠FDG = 66°; m∠GOF = 126° C. x = 28; m∠FDG = 64°; m∠GOF = 116° D. x = 27; m∠FDG = 62°; m∠GOF = 118°
Answer:
Option D
x = 27; m∠FDG = 62°; m∠GOF = 118°
Step-by-step explanation:
To solve this, we will need the help of the following laws of geometry:
1. We can see that the shape formed is quadrilateral. The sum of the interior angles of a quadrilateral = 360 degrees.
2. The angle between a radius and a tangent = 90 degrees. as a result of this, <OGD = <OFD = 90 degrees.
Once we have values for all the angles of the quadrilateral, we can set up an equation using the first rule mentioned above.
2x+8 + 4x+10 +90 +90 = 360 (Sum of interior angles of a quadrilateral = 360)
6x = 162
x=27 degrees
Now we have the value of x, we can find FDG and GOF as follows:
FDG = 2x + 8 = 2(27)+8 =62
FOG = 4x + 10 = 4(27)+ 10 =118
two boxes have the same volume. One box has a base that is 5 cm5\text{ cm}5 cm5, start text, space, c, m, end text by 5 cm5\text{ cm}5 cm5, start text, space, c, m, end text. The other box has a base that is 10 cm10\text{ cm}10 cm10, start text, space, c, m, end text by 10 cm10\text{ cm}10 cm10, start text, space, c, m, end text. How many times as tall is the box with the smaller base?
Answer:
The height of the box with the smaller base is 4 times that of the box with the larger base
Step-by-step explanation:
The volume of a box is the product of the base area and the height of the box, it is given as:
Volume = base area × height
For the smaller base box, it has a base of 5 cm by 5 cm, therefore the base area of the smaller base box = 5 cm × 5 cm = 25 cm². Let the height of the smaller base box be [tex]h_1[/tex]The volume of the small box = [tex]25*h_1[/tex]
For the larger base box, it has a base of 10 cm by 10 cm, therefore the base area of the larger base box = 10 cm × 10 cm = 100 cm². Let the height of the large base box be [tex]h_2[/tex]The volume of the larger base box = [tex]100*h_2[/tex]
Since both boxes have the same volume, therefore:
[tex]100*h_2[/tex] = [tex]25*h_1[/tex]
[tex]\frac{h_1}{h_2} =\frac{100}{25} \\\\\frac{h_1}{h_2}=4\\\\h_1=4h_2[/tex]
The height of the box with the smaller base is 4 times that of the box with the larger base
We can use the formula V=lwh to compare the volume in the two boxes.
First let's compare the volume of both boxes to see if they have the same height. To make it simple, let's use a height of 1 centimeter.
First the box with the smaller base.
V=lwh
V=5⋅5⋅1
V=25
Now the box with the larger base
V=lwh
V=10x10x1
V=100
We can set up an equation to find out how many times as tall the smaller box needs to be to have the same volume as the box with the larger base.
25·h=100
h=4
The boz with the smaller base is 4 times tall
hope it helped :)
6th grade math help me, please. :)
Step-by-step explanation:
Hello there!!
no need to be panic we will help you, alright.
look solution in picture ok...
sorry for cutting in middle.
Hope it helps...
you are given the following functions: g(x) = x^2 + 4x + 5 and h(x) = 3x - 4 What is (g+h)(x)
Answer:
g(x) = x² + 4x + 5
h(x) = 3x - 5
To find (g+h)(x) add h(x) to g(x)
That's
(g+h)(x) = x² + 4x + 5 + 3x - 4
Group like terms
(g+h)(x) = x² + 4x + 3x + 5 - 4
Simplify
We have the final answer as
(g+h)(x) = x² + 7x + 1Hope this helps you
The value of a car dropped from $7400 to $6800 over the last year. What percent decrease is this?
Answer:
8.1% decrease
Step by step
To find precentage decrease we use formula:
Percent decrease= original amount-new amount/original amount(100%)
percent decrease= 7,400-6,800/7,400(100%)=300/37=8.1%
What are the x and y intercepts?
[tex]f(x) = \frac{(x - 3)(x + 4)(x - 1)}{(x + 2)(x - 12)} [/tex]
Answer:
(a)The x-intercepts are 3, -4 and 1.
(b)f(x)=-0.5
Step-by-step explanation:
Given the function:
[tex]f(x) = \dfrac{(x - 3)(x + 4)(x - 1)}{(x + 2)(x - 12)}[/tex]
The x-intercepts occurs when y=0The y-intercepts occurs when x=0x-Intercepts
When y=f(x)=0
[tex]f(x) = \dfrac{(x - 3)(x + 4)(x - 1)}{(x + 2)(x - 12)}=0\\(x - 3)(x + 4)(x - 1)=0\\x - 3=0$ or $ x + 4=0 $ or $ x - 1=0\\x=3$ or $ -4$ or $ 1[/tex]
The x-intercepts are 3, -4 and 1.
y-intercepts
When x=0
[tex]f(x) = \dfrac{(x - 3)(x + 4)(x - 1)}{(x + 2)(x - 12)}\\f(x) = \dfrac{(0 - 3)(0 + 4)(0 - 1)}{(0 + 2)(0 - 12)}\\= \dfrac{(- 3)( 4)( - 1)}{( 2)( - 12)}\\= \dfrac{12}{-24}\\\\=-0.5[/tex]
The y-intercept is -0.5
Change -2Y - X=-2 to the slope-intercept form of the equation of a line.
Answer:
y = -(1/2)x+1
Step-by-step explanation:
-2Y - X = -2
Add x to both sides:
-2Y = X - 2
Divide both sides by -2:
Y = -(1/2)x+1
You could also use the shortcuts:
For Ay+Bx=C, the slope is -B/A and the y-intercept is C/A.
Slope = -B/A = -(-1)/(-2) = 1/-2 = -(1/2)
Y-intercept = C/A = (-2)/(-2) = 1
y = mx + b ---> y = -(1/2)x + 1
Answer:
y = -1/2x +1
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
-2y -x = -2
Solve for y
Add x to each side
-2y = x-2
Divide by -2
-2y/2- = x/-2 -2/-2
y = -1/2x +1
Divide (28x5 + 29x4 + 5x3 + 86x2 + 56x + 53) by (–4x – 7) using synthetic division.
Answer:
-7x⁴+5x³-10x²-4x-7 - 4/4x+7
Step-by-step explanation:
Given the division problem, (28x⁵ + 29x⁴ + 5x³ + 86x² + 56x + 53) by (–4x – 7), find the solution in the attachment below.
The polynomial of a function is expressed as P(x) = Q(x) + R(x)/D(x)
Q(x) is the quotient
R(x) is the remainder
D(x) is the divisor
Accordin gto the divsion, Q(x) = -7x⁴+5x³-10x²-4x-7
R(x) = 4
D(x) = -4x-7
Substituting this functions in the polynomial P(x);
P(x) = -7x⁴+5x³-10x²-4x-7 - 4/4x+7
The admission fee at an amusement park is $1.50 for children and S4 for adults. On a certain day, 289 people entered the park, and the admission fees collected totaled 746.00 dollars. How many children and
how many adults were admitted?
number of children equals
number of adults equals?
Set up two equations:
Let a = adults and c = child:
a + c = 289 ( rewrite as a = 289 - c)
1.50c + 4a = 746
Replace a with the rewritten formula:
1.50c + 4(289-c) = 746
SImplify:
1.50c + 1156 - 4c = 746
Combine like terms:
-2.50c + 1156 = 746
Subtract 1156 from both sides:
-2.50c = -410
Divide both sides by -2.50
c = -410 / -2.50 = 164
Number of children = 164
Number of adults = 289 - 164 = 125
Answer:
[tex] x+y = 289[/tex] (1) total people entered
[tex] 1.50 x +4 y = 746[/tex] (2) total amount collected
From the first equation we can solve for x and we got:
[tex] x = 289-y[/tex] (3)
Replacing (3) into (2) we got:
[tex] 1.5(289-y) +4y = 746[/tex]
And solving for y we got:
[tex] 433.5 -1.5 y +4y = 746[/tex]
[tex] 2.5 y= 312.5[/tex]
[tex]y=\frac{312.5}{2.5}= 125[/tex]
And then using (3) we can solve for x and we got:
[tex] x= 289-125= 164[/tex]
So then we have:
number of children = 164
number of adults = 125
Step-by-step explanation:
Let x the number of children and y the number of adults. From the info given we can set up the following equations:
[tex] x+y = 289[/tex] (1) total people entered
[tex] 1.50 x +4 y = 746[/tex] (2) total amount collected
From the first equation we can solve for x and we got:
[tex] x = 289-y[/tex] (3)
Replacing (3) into (2) we got:
[tex] 1.5(289-y) +4y = 746[/tex]
And solving for y we got:
[tex] 433.5 -1.5 y +4y = 746[/tex]
[tex] 2.5 y= 312.5[/tex]
[tex]y=\frac{312.5}{2.5}= 125[/tex]
And then using (3) we can solve for x and we got:
[tex] x= 289-125= 164[/tex]
So then we have:
number of children = 164
number of adults = 125