Following a collision between a large spacecraft and an asteroid, a copper disk of radius 28.0 m and thickness 1.20 m, at a temperature of 850°C, is floating in space, rotating about its axis with an angular speed of 20.0 rad/s. As the disk radiates infrared light, its temperature falls to 20.0°C. No external torque acts on the disk.
A) Find the change in kinetic energy of the disk.
B) Find the change in internal energy of the disk.
C) Find the amount of energy it radiates.

Answer:

Fish C would float to the top & Fish A would sink to the bottom

Explanation:

A would sink to the bottom.Since B just remains where it is shown, its mass must balance the buoyant force and its weight must be equal to the weight of the water displaced. Since A is heavier, its weight will be greater than its buoyant force, it will sink. Since C is lighter, its buoyant force will be greater thanits weight and it will float to the top.

A, B, E , C, D

A nebula is an enormous cloud of dust and gas occupying the space between stars and acting as a nursery for new stars.

Nebulae are made up of dust, basic elements such as hydrogen and other ionized gases.

Nebula Formation:

In essence, a nebula is formed when portions of the interstellar medium undergo gravitational collapse.

Mutual gravitational attraction causes matter to clump together, forming regions of greater and greater density.

The formation events that occur within a cloud from earliest to latest are:

A. The cloud is large, cool, and slowly rotating

B. The cloud collapses into a disk.

E. The cloud starts to contract under the influence of gravity

C. Competing rotational and gravitational forces begin to flatten the cloud.

D. The cloud becomes denser, heats up, and rotates faster

Therefore , The rank from earliest to latest is A, B, E , C, D

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Answer:

A) 1.5 v

B) Top plate is at higher voltage than the bottom plate

Explanation:

Battery value set between 0.0 V and 1.5 V

a) The potential difference between the plates

Δ V = V1( potential at top plate) - V2( potential at lower plate )

potential at top plate = 1.5 V

potential at lower plate = 0.0 V

hence potential difference = 1.5 V

b ) The top plate is always connected to the positive terminal of the DC source ( which is at a higher potential )while the bottom plate is connected to the negative terminal of the DC source ( which is at a lower potential )

hence the Top plate is at higher voltage than the bottom plate

Answer:

the right answer is true

Answer:

True

Explanation:

Answer:

x = A sin w t           displacement in SHM

v = A w cos w t      velocity in SHM

PE = 1/2 k x^2 = 1/2 k A^2 sin^2 w t

KE = 1/2 m v^2 = 1/2 m w^2 A^2 cos^2 w t

If KE = PE then

k sin^2 w t = m w^2 cos^2 w t

sin^2 wt / cos^2 w t = tan^2 w t = m w^2 / k

but k / m = w^2

So tan^2 w t = 1  and tan w t = 1   or w t = pi / 4 or theta = 45 deg

Then  x = r sin w t  = r sin 45 = .707 r

Answer:

4.41 m/s^2

Explanation:

(v_f)^2 - (v_i)^2 = 2a * change in distance

(21)^2 - (0)^2 = 2a * 50

a = (21^2)/(2*50)

a = 4.41 m/s^2

Answer:

344.68 m

Explanation:

The computation of the far does the car travel before stopping is

Data provided in the question

Force = F = 8,868 N

mass = m = 2,500 kg

So,

accleration = a is

[tex]= \frac{-F}{m}\\\\\= \frac{8868}{2500}[/tex]

a = -3.54 m/s^2

The initial speed = u = 49.4 m / s

final speed = v = 0

Based on the above information

Now applying the following formula

v^ 2- u^ 2= 2aS

Therefore

[tex]S = \frac{v^ 2- u^ 2}{2a}\\\\\ = \frac{0- 49.4^ 2}{2\times -3.54}[/tex]

= 344.68 m

Answer:

The electric field strength between the plates can be increased by decreasing the length of each side of the plates.

Explanation:

The electric field strength is given by;

[tex]E = \frac{V}{d}[/tex]

where;

V is the electric potential of the two opposite charges

d is the distance between the two parallel plates

[tex]E =\frac{V}{d} = \frac{\sigma}{\epsilon _o} \\\\(\sigma = \frac{Q}{A} )\\\\E = \frac{Q}{A\epsilon_o} \\\\E = \frac{Q}{L^2\epsilon_o}[/tex]

Where;

ε₀ is permittivity of free space

L is the length of each side of the plates

From the equation above, the electric field strength can be increased by decreasing the length of each side of the plates.

Therefore, decreasing the length of each side of the plates, could be made to increase the strength of the electric field between the plates

Answer:

It is the carrier of genetic information.

Answer:

B=uonI/2

Explanation:

See attached file

Answer:

Explanation:

When water droplet condenses on the outer wall of glass of ice , it releases heat equal to mass x latent heat of condensation of water . This heat reaches the ice melting inside  glass . Due to this heat , the melting process is accelerated .

Hence the process of melting gets accelerated when water droplet condenses on the outer wall of glass containing mixture of ice and water .

Answer:

the direction of angular momentum = EAST

Explanation:

given

Direction of position = r = north

Direction of velocity = v = up

angular momentum = L = m(r x v)

where m is the mass, r is the radius, v is the velocity

utilizing the right hand rule, the right finger heading towards the course of position vector and curl them toward direction of velocity, at that point stretch thumb will show the bearing of the angular momentum.

then L = north x up = East

Answer:

Helium atoms compared to nitrogen atoms are moving faster and have a greater kinetic energy.

Explanation:

The molecular velocity of a gas at room temperature is inverse proportional to the square root of its molecular mass.

The greater the molecular mass of the gas the lesser the average speed of its molecules. Comparing the molecular masses of nitrogen and helium, helium is found to have a lower molecular mass and a corresponding greater velocity.

Hence helium moves faster than nitrogen and has a higher kinetic energy than nitrogen

Answer:

B. [tex]8sin(6.2x-12t)[/tex]

Explanation:

The general equation of a wave is expressed as [tex]y = Asin(kx-\omega t)[/tex]

A is the amplitude of the wave

k is the wave number and it is expressed as [tex]k =\frac{2\pi}{\lambda}[/tex]

[tex]\omega[/tex] is the angular frequency expressed as [tex]\omega = 2\pi f[/tex]

[tex]\lambda[/tex] is the wavelength and f is the angular frequency

Given k = 6.2rad/m and [tex]\omega = 12rad/s[/tex]

On substituting this value into the general wave equation;

[tex]y = Asin(kx-\omega t)\\y = Asin(6.2x-12t)[/tex]

From the expression gotten, the only equation that could be the equation of the wave is [tex]y = 8sin(6.2x-12t)[/tex]

Answer:

absorbent    p = S / c

reflective         p = 2S/c

Explanation:

The moment of radiation on a surface is

          p = U / c

where U is the energy and c is the speed of light.

In the case of a fully absorbent object, the energy is completely absorbed. The energy carried by the light is given by the Poynting vector.

           p = S / c

in the case of a completely reflective surface the energy must be absorbed and remitted, therefore there is a 2-fold change in the process

           p = 2S/c

Answer: W.D = 1/2mv^2

Explanation:

If an external force or a single force is acting on a body. Just like the first law of thermodynamics, the force acting on the body will cause work done on the system.

Work done = force × distance

And the work done on the body will cause the molecules of the body to experience motion and thereby producing kinetic energy.

The work done will be converted to kinetic energy.

W.D = 1/2mv^2

Answer:

The magnetic field's direction is towards the north

Explanation:

The force on a positive charge in a uniform magnetic field is represented by the right hand rule. To determine the direction of the force, place your right hand with your palm up, and your thumb at 90° to the other fingers. If the fingers represent the magnetic field, and the thumb the direction of the positive charge, then the palm will push up in the direction of the force. But a negative charge like an electron pushes in exactly the opposite direction. So if you follow this rule, you will find that the magnetic field points towards the north.

The direction of the magnetic field is towards the North. This can be

determined using the right hand rule by Fleming.

The right hand rule states that to determine the direction of the magnetic

force, the right thumb should be pointed in in the direction of the velocity,

index finger in the direction of the magnetic field and middle finger in the

direction of magnetic force.

When this is applied, we will discover that the index finger will point towards

the north region.

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Answer:

-0.105 m/s

Explanation:

Given that

Mass of the astronaut, m(a) = 68.5 kg

Mass of the tool, m(t) = 2.25 kg

Speed of the tool after it is thrown, v(t) = 3.20 m/s

We know that momentum of a particle,

p = mv

See the attachment for calculations

Therefore, the speed is 0.105 m/s and it moves in the opposite direction.

Answer:

a. The current is induced when there is ____3. EITHER DECREASING OR INCREASING___ magnetic flux through a closed loop of wire.

b. If the magnetic flux was constant then there _______WILL BE NO___ induced current regardless of the magnetic flux value.

c. If the magnetic flux was not constant then there __WILL BE______ induced current regardless of the magnetic flux value.

Explanation:

THIS IS BECAUSE IF FARADAY'S LAW OF ELECTROMAGNETIC INDUCTION WHICH STATES THAT WHENEVER THERE IS A CHANGE IN MAGNETIC LINES OF FORCE LINKED WITH A CLOSED CIRCUIT AN EMF IS INDUCED

Answer:

   s_400 = 16.5 m , s_700 = 29.4 m

Explanation:

The limit of the human eye's solution is determined by the diffraction limit that is given by the expression

                   θ = 1.22 λ / D

where you lick the wavelength and D the mediator of the circular aperture.

In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.

by introducing these values ​​into the formula

λ = 400 nm      θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad

λ = 700 nm     θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad

Now we can use the definition radians

          θ= s / R

where s is the supported arc and R is the radius. Let's find the sarcos for each case

λ = 400 nm       s_400 = θ R

                         S_400 = 6 10⁻⁵ 275 10³

                         s_400 = 16.5 m

λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³

                          s_700 = 29.4 m

Answer:

Energy, [tex]E=4.67\times 10^{-19}\ J[/tex]

Explanation:

It is given that,

Frequency of blue shade is, [tex]f=7.06\times 10^{14}\ Hz[/tex]

We need to find the energy of exactly one photon of this light. The formula that is used to find the energy of photon is given by :

[tex]E=nhf[/tex]

Here, n is number of photon, n = 1

h is Planck's constant

So,

[tex]E=1\times 6.626\times 10^{-34}\times 7.06\times 10^{14}\\\\E=4.67\times 10^{-19}\ J[/tex]

So, the energy of this light is [tex]4.67\times 10^{-19}\ J[/tex].

Answer:

16.96 W

Explanation:

Power: This can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).

From the question,

P = (F×d)/t....................... Equation 1

Where P = power, F = force, d = distance, t = time.

Given: F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s

Substitute these values into equation 1

P = (75×42)/186

P = 16.94 W

Hence the average power delivered by the child  = 16.96 W

The average power delivered by the child is 16.96 W.

Power can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).

Work done is the product of force and displacement caused.

Then the formula of power will be

P = (F×d)/t

Substitute F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s, we get the power as

P = (75×42)/186

P = 16.94 W

Hence, the average power delivered by the child is 16.96 W.

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Answer:

9.6×10⁹ A

Explanation:

From the question above,

P = VI.................... Equation 1

Where P = Electric power, V = Voltage, I = current.

make I the subject of the equation

I = P/V............. Equation 2

Given: P = 200 kW = 200×10³ W, V = 48000 V.

Substitute these vales into equation 2

I = 200×10³×48000

I = 9.6×10⁹ A.

Hence the current in the line is 9.6×10⁹ A.

Answer:

35.3°

18.4°

Explanation:

a.

The first polariser polarises the unpolarised light reducing its intensity from I0 to I0/2. We have to reduce the intensity from I0/2 to I0/3.

Using to Law of Malus, I=I0cos²θ

cos²θ=I/I0=(I0/3)/I0/2 ,

cosθ=√2/3−−√=0.6667−−−−−√=0.8165

θ=cos−1(0.8165)=35.3∘

B.

Cos²θ=I/Io =Io/10/Io9

Cosθ= √9/10= 0.9487

= cos−10.9487

=18.4°

(a) The angle of polaroid such that intensity reduces by 1/3 is 35.26°

(b) The angle of polaroid such that intensity reduces by 1/10 is 63.43°

According to the Malus Law: The intensity of light when passing through a polarizer is given by:

I = I₀cos²θ

where θ is the angle of the polarizer axis with the direction of polarization of the light

I₀ is the initial intensity

When an unpolarised light passes through a polarizer, θ varies from 0 to 2π, so the intensity after passing the first polarizer is :

I = I₀<cos²θ>   { average of cos²θ, for 0<θ<2π}

I = I₀/2

Now, this emerging light passes through a second polarizer such that:

(a) the intensity is I' = I₀/3

From Malus Law:

I' = Icos²θ

I₀/3 =  (I₀/2)cos²θ

cos²θ = 2/3

θ = 35.26°

(b) the intensity is I' = I₀/10

From Malus Law:

I' = Icos²θ

I₀/10 =  (I₀/2)cos²θ

cos²θ = 1/5

θ = 63.43°

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Answer:

There are 10 cubes in the box

Explanation:

Let the total number of cubes be x and the total number of pyramids be y

Since there are 17 total objects;

Then;

x + y = 17 •••••••••(i)

Also, the total number of sides of cubes is 6 * x = 6x ( a single cube has 6 sides)

For the pyramid we have 5 * y = 5y

adding both gives the total number of sides

6x + 5y = 95 •••••• (ii)

From i, we cabs say y = 17-x

plug this in ii

6x + 5(17-x) = 95

6x + 85 -5x = 95

6x-5x = 95-85

x = 10

Will occur if you were able to place a rotating magnet near a coil of wire is continually rotating magnetic field would continuously induce current.

When the magnet moves close to the coil or rapidly increasing until the magnet is within the flux of the coil. As it passes through the coil, the magnetic flux through the coil starts to decrease. Consequently, an induced EMF is inverted.

Whenever there is a relative movement between the loop and the magnet, regardless of who moves, an electric current, called induced current, appears in the loop.

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Answer:

Explanation:

Range of projectile R = 20 m

formula of range

R = u² sin2θ / g

u is initial velocity , θ is angle of projectile

putting the values

20 = u² sin2x 40 / 9.8

u² = 199

u = 14.10 m /s

At the initial point

vertical component of u

= u sin40 = 14.1 x sin 40

= 9.06 m/s

Horizontal component

= u cos 30

At the final point where the ball strikes the ground after falling , its speed remains the same as that in the beginning .

Horizontal component of velocity

u cos 30

Vertical component

= - u sin 30

= - 9.06 m /s

So its horizontal component remains unchanged .

change in vertical component = 9.06 - ( - 9.06 )

= 18.12 m /s

change in momentum

mass x change in velocity

= .050 x 18.12

= .906 N.s

Impulse = change in momentum

= .906 N.s .

Answer:

The speed at which the magnet falls through the copper block will be reduced dramatically.

Explanation:

Eddy's current are loops of electrical current induced within conductors by a changing magnetic field in the conductor. Eddy's current is proportional to the the magnetic field strength, the rate of change of flux, the area of the loop, and is inversely proportional to the resistivity of the material. Eddy currents flows perpendicularly to the magnetic field, and in closed loops within conductors.

Reducing the resistivity of the copper will increase the Eddy current on the copper, which will in turn increase the opposition to the action producing the flux change (the falling magnet through the copper block). The result is that the speed at which the magnet falls through the copper block will be reduced dramatically.

Answer:

Hello the options to your question is missing below are the options

2 x 10^8 ft-lb

15527950 ft-lb

2.8 x 10^7 ft-lb

13.55 x 10^7 ft-lb

Answer : 13.55 * 10^7 ft-Ib

Explanation:

Given data :

weight of Aircraft (p) = 20000 Ibs

height ( h ) = 5000 ft

Velocity = 200 KTS  = 370 km/h ( 10277 m/s) where 1 KTS = 1185 km/h

calculate the total energy

Total energy = potential energy + kinetic energy

potential energy = mgh = p * h =20000 * 5000 = 100 * 10^6 ft-Ibs

kinetic energy = 1/2 mv^2 = 1/2 * 625 * (33709)^2 = 3551 *10^6 ft-Ibs

where ; m = p/g = 20000 / 32 = 625 Ibs

             v = 10277 m/s ≈ 33709 ft/s

hence total energy = 100 * 10^6 + 3551 * 10^6 = 1355*10^7 ft-Ibs

Answer:

[tex]I=1.19\times 10^{-2}\ W/m^2[/tex]

Explanation:

It is given that,

Maximum value of magnetic field strength, [tex]B=10^{-8}\ T[/tex]

We need to find the intensity of the light at that place.

The formula of the intensity of magnetic field is given by :

[tex]I=\dfrac{c}{2\mu _o}B^2[/tex]

c is speed of light

So,

[tex]I=\dfrac{3\times 10^8}{2\times 4\pi \times 10^{-7}}\times (10^{-8})^2\\\\I=1.19\times 10^{-2}\ W/m^2[/tex]

So, the intensity of the light is [tex]1.19\times 10^{-2}\ W/m^2[/tex].