Find the value of x. Give reasons to justify your solution. D ∈ AC

Find The Value Of X. Give Reasons To Justify Your Solution. D AC

Answers

Answer 1

Answer:

x = 25°

Step-by-step explanation:

From the picture attached,

Since AE║BC and AC is a transverse,

Therefore, ∠EAC ≅ ∠BCA [Alternate interior angles]

m∠EAC = m∠BCA = x°

∠BCD = ∠DCB + ∠DBC [Since ∠BCD is an exterior angle of ΔBDC]

m∠BCD = m∠DCB + m∠DBC

50° = x° + x°

2x = 50

x = 25°

Therefore, value of x is 25°.

Answer 2

Answer: 25 degrees

Step-by-step explanation:


Related Questions

22,403 Check:
- 8,675

how i do this​

Answers

Answer:

Hello!! :) The answer to your question is 13,728

Steps will be below.

Step-by-step explanation:

So we will subtract 22,403 and 8,675.

When we do that we will get 13,728

To check your answer we have to do the opposite of subtracting which will be adding.

This is how we check our work: the answer we got was 13,728...we have to take that answer and add it to 8,675 which will give us 22,403

(Both of the numbers are from the question)

At the bottom I attached a picture of how I did the subtracting and how I checked my work.

Sorry for my handwriting......if you can’t understand my handwriting, I attached another picture which is more clearer.

ANSWER TO YOUR QUESTION: 13,728

Brainliest would be appreciated! Thank you :3

Hope this helps! :)

Answer:

The answer is 13,728

Step-by-step explanation:

Check your work with addition.

Expedia would like to test the hypothesis that the average round-trip airfare between Philadelphia and Paris is higher for a flight originating in Philadelphia when compared to a flight originating in Paris. The following data summarizes the sample statistics for round-trip flights originating in both cities. Assume that the population variances are equal.
Originating City
Philadelphia Paris
Sample mean $1,240 $1,060
Sample size 15 19
Sample standard
deviation $270 $240
If Population 1 is defined as flights originating in Philadelphia and Population 2 is defined as flights originating in Paris, the degrees of freedom for this hypothesis test are _____
(a) 33
(b) 32
(c) 34
(d) 28

Answers

Answer:

(b) 32

Step-by-step explanation:

From the information given :

sample mean of Philadelphia μ₁ = $1240

Sample size of Philadelphia n₁ = 15

Sample Standard deviation σ₁ = $270

sample mean of Paris μ₂ = $1,060

Sample size of Paris  n₂ = 19

Sample Standard deviation of Paris  σ₂ = $240

If Population 1 is defined as flights originating in Philadelphia and Population 2 is defined as flights originating in Paris;

the degrees of freedom for this hypothesis test can be calculated as;

degree of freedom df = n - 1

degree of freedom for both hypothesis test = (n₁ - 1 + n₂ -1)

degree of freedom for both hypothesis test  = (n₁ + n₂ - 2)

degree of freedom for both hypothesis test  = ( 15 + 19 - 2)

degree of freedom for both hypothesis test are   32  

Square root of 5 + square root of 3 the whole divided by sqaure root of 5 - square root of 3

Answers

Answer:

The answer is 4 + 15 .

Step-by-step explanation:

You have to get rid of surds in the denorminator by multiplying it with the opposite sign :

[tex] \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } [/tex]

[tex] = \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } [/tex]

[tex] = \frac{ {( \sqrt{5} + \sqrt{3} ) }^{2} }{( \sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3}) } [/tex]

[tex] = \frac{ {( \sqrt{5} )}^{2} + 2( \sqrt{5} )( \sqrt{3}) + {( \sqrt{3}) }^{2} }{ {( \sqrt{5}) }^{2} - { (\sqrt{3} )}^{2} } [/tex]

[tex] = \frac{5 + 2 \sqrt{15} + 3 }{5 - 3} [/tex]

[tex] = \frac{8 + 2 \sqrt{15} }{2} [/tex]

[tex] = 4 + \sqrt{15} [/tex]

Lettets a, b, c, and d are angle measures Which should equal 105 to prove false g

Answers

Answer:

a equals 105°

Step-by-step explanation:

angles in a straight line add up to 180°

a+75=180

a=180-75

a=105°

Suppose a ball is thrown upward to a height of h 0 meters. After each​ bounce, the ball rebounds to a fraction r of its previous height. Let h Subscript n be the height after the nth bounce. Consider the following values of h 0 and r. Complete parts​ (a) and​ (b) below. h0=30​, r=0.25
a- find the first 4 terms of the sequence of heights(hn)
b- find a general expression for the nth term of the sequence (hn)

Answers

Answer:

A)1st term:45

2nd term:48.75

3rd term:49.6875

4th term:49.921875

B) Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

Step-by-step explanation:

We are given;

h₀ = Initial height of the ball = 30

r = Rebound fraction = 0.25

a) The arithmetic sequence of bouncing balls is given by the following;

Sₙ=h₀+2h₀(r¹+r²+r³+r⁴.........rⁿ)

The first term of the sequence is;

S₁ = h₀ + 2h₀r¹

S₁ = 30 + (2 × 30 × 0.25)

S₁ = 45

The second term of the sequence is;

S₂ = h₀ + 2h₀(r¹+r²)

S₂ = 30 + (2 × 30 × (0.25 + 0.25²)) = 48.75

The third term of the sequence is;

S₃ = h₀ + 2h₀(r¹ + r² + r³) = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³)) = 49.6875

S₄ = h₀ + 2h₀(r¹ + r² + r³ + r⁴)

S₄ = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³ + 0.25⁴)) = 49.921875

B) The general expression for the nth term of the sequence is;

Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

Determine the area under the standard normal curve that lies to the left of
(a) Z = 1.75, (b) Z=0.01, (c) Z= -0.01, and (d)Z = 1.29.
Click the icon to view a table of areas under the normal curve.
(a) The area to the left of Z= 1.75 is
(Round to four decimal places as needed.)

Answers

Answer:

a) 0.9599b) 0.5040c) 0.4960d) 0.9015

Step-by-step explanation:

You did not provide the table, so I used a spreadsheet. Most have functions for finding the area under a standard normal curve.

need help with these 3 questions (giving brainiest if you can answer with equations)

Answers

Problem 10

Answer: approximately 57.39159 km

Explanation: You'll use the equation cos(28) = d/65 to solve for d to get d = 65*cos(28) = 57.39159 approximately. We use the cosine ratio because it ties together the adjacent and hypotenuse.

=====================================

Problem 11

Answer: approximately 10.46162 meters

Explanation: This time we use the sine rule. We have the height as the opposite side (which is unknown, call it x) and the hypotenuse is the ladders length (11). So we have sin(72) = x/11 which solves to x = 11*sin(72) = 10.46162

=====================================

Problem 12

Answer: approximately 16.05724 cm

Explanation: Now we use the tangent rule to connect the opposite and adjacent sides.

tan(37) = 12.1/x

x*tan(37) = 12.1

x = 12.1/tan(37)

x = 16.05724 approximately

EXAMPLE 2 (a) Find y' if x3 + y3 = 18xy. (b) Find the tangent to the folium of Descartes x3 + y3 = 18xy at the point (9, 9). (c) At what point in the first quadrant is the tangent line horizontal?

Answers

(a) Via implicit differentiation, we get

[tex]x^3+y^3=18xy\implies 3x^2+3y^2y'=18y+18xy'[/tex]

Solve for [tex]y'[/tex]:

[tex]y'=\dfrac{18y-3x^2}{3y^2-18x}=\dfrac{6y-x^2}{y^2-6x}[/tex]

(b) Find the slope of the tangent line at (9, 9) by plugging in x = y = 9 into the equation above:

[tex]y'=\dfrac{6\cdot9-9^2}{9^2-6\cdot9}=-1[/tex]

Use the point-slope formula to find the equation of the line:

[tex]y-9=-1(x-9)\implies y=-x+18[/tex]

(c) The tangent line is horizontal when its slope is 0, so solve [tex]y'=0[/tex]:

[tex]\dfrac{6y-x^2}{y^2-6x}=0\implies6y-x^2=0\implies y=\dfrac{x^2}6[/tex]

Now substitute y in the equation for the folium to solve for x :

[tex]x^3+\left(\dfrac{x^2}6\right)^3=18x\cdot\dfrac{x^2}6[/tex]

[tex]x^3+\dfrac{x^6}{6^3}=3x^3[/tex]

[tex]\dfrac{x^6}{6^3}-2x^3=0[/tex]

[tex]x^3\left(\left(\dfrac x6\right)^3-2\right)=0[/tex]

[tex]\implies x=0\text{ or }x=6\sqrt[3]{2}[/tex]

x = 0 corresponds to y = 0 (plug x = 0 into the folium equation to see why), i.e. the origin. If you don't consider the origin to belong to the first quadrant, then we only keep

[tex]x=6\sqrt[3]{2}\implies y=6\sqrt[3]{4}[/tex]

Solve for qqq. 3\left(q+\dfrac43\right) = 23(q+ 3 4 ​ )=2
pls answer this

Answers

Answer:

19/3

Step-by-step explanation:

Given the expression [tex]3\left(q+\dfrac43\right) = 23[/tex], we are to find the value of q;

[tex]3\left(q+\dfrac43\right) = 23\\on\ expansion\\\\3q + 4/3(3) = 23\\\\3q+4 = 23\\\\subtract \ 4\ from \ both\ sides \ of \ the \ equation\\\\3q+4-4 = 23-4\\\\3q = 19\\\\Diviide \both\ sides \ by \ 3\\\\3q/3 = 19/3\\\\q = 19/3[/tex]

Hence the value of q is 19/3

Answer:

-2/3

Step-by-step explanation:

Don't worry about it, i got connections.

In a small private​ school, 55 students are randomly selected from 1313 available students. What is the probability that they are the fivefive youngest​ students?

Answers

Complete Question

In a small private​ school, 5 students are randomly selected from 13 available students. What is the probability that they are the five youngest​ students?

Answer:

The  probability is [tex]P(x) = 0.00078[/tex]

Step-by-step explanation:

From the question we are told that

    The number of student randomly selected is  r =  5

   The  number of available students is  n  =  13

Generally the number of ways that 5 students can be selected from 13 available students is mathematically represented as

      [tex]n(k)=\left n} \atop {}} \right.C_r = \frac{n ! }{(n-r ) ! r!}[/tex]

substituting values    

      [tex]\left n} \atop {}} \right.C_r = \frac{13 ! }{(13-5 ) ! 5!}[/tex]

    [tex]\left n} \atop {}} \right.C_r = \frac{13 * 12 * 11 * 10 * 9 *8! }{8 ! * 5 * 4 * 3 * 2 *1}[/tex]

     [tex]\left n} \atop {}} \right.C_r = 1287[/tex]

The  number of method by which  5 youngest  students are selected is n(x) =  1

   So  

          Then the probability of  selecting the five youngest students is mathematically represented as

        [tex]P(x) = \frac{n(x)}{n(k)}[/tex]

substituting values

        [tex]P(x) = \frac{1}{1287}[/tex]

        [tex]P(x) = 0.00078[/tex]

42.
You were given the four numbers below and were asked to find the sum
of the first two numbers, the difference between the last two numbers,
the quotient when the sum is divided by the difference and the product
when the quotient is multiplied by 8. What is the final answer?
6458 2994
7013
6945

Answers

Answer:

1112

Step-by-step explanation:

6458 + 2994  = 9452

7013  - 6945  = 68

9452/68 = 139

139 * 8 = 1112

A bag of marbles contains 4 green marbles, 3 blue marbles, 2 red marbles, and 5 yellow marbles. How many total possible outcomes are there when choosing a marble from the bag?

Answers

Answer:

its 14/C

Step-by-step explanation:

i got i right on edg U^U

Answer:

16

Step-by-step explanation:

i did edge test yea dont  be imma fake :***    

Which graph shows the solution to the system of linear inequalities? y ≥ 2x + 1 y ≤ 2x – 2

Answers

The lines of the inequalities are parallel, and the system of inequalities do not have any solution.

How to determine the solution of the inequalities

The system of inequalities are  given as:

y ≥ 2x + 1 y ≤ 2x – 2

The inequality y ≥ 2x + 1 has the following characteristics:

A slope of 2A y-intercept of 1A closed line, where the upper region is shaded

The inequality y ≤ 2x – 2 has the following characteristics:

A slope of 2A y-intercept of -2A closed line, where the lower region is shaded

See attachment for the graphs of the system of inequalities

Read more about system of inequalities at:

https://brainly.com/question/9774970

5/9 + (1/9 + 4/5)=×

Answers

Answer:

22/15I hope it helps :)

Step-by-step explanation:

[tex]\frac{5}{9}+\left(\frac{1}{9}+\frac{4}{5}\right)=x\\x=\frac{5}{9}+\left(\frac{1}{9}+\frac{4}{5}\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\x=\frac{5}{9}+\frac{1}{9}+\frac{4}{5}\\\mathrm{Compute\:a\:number\:comprised\:of\:factors\\\:that\:appear\:in\:at\:least\:one\:of\:the\:following:}\\9,\:9,\:5\\=3\times \:3\times\:5\\\mathrm{Multiply\:the\:numbers:}\:3\times \:3\times \:5=45\\\frac{5}{9}=\frac{5\times \:5}{9\times \:5}=\frac{25}{45}\\[/tex]

[tex]\frac{1}{9}=\frac{1\times \:5}{9\times \:5}=\frac{5}{45}\\\\\frac{4}{5}=\frac{4\times \:9}{5\times \:9}=\frac{36}{45}\\\\x=\frac{25}{45}+\frac{5}{45}+\frac{36}{45}\\\\\mathrm{Since\:the\:denominators\:are\:equal,\\combine\:the\:fractions}:\\\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\x=\frac{25+5+36}{45}\\\\x=\frac{66}{45}\\\\x=\frac{22}{15}[/tex]

The Ambell Company uses batteries from two different manufacturers. Historically, 60% of the batteries are from manufacturer 1, and 90% of these batteries last for over 40 hours. Only 75% of the batteries from manufacturer 2 last for over 40 hours. A battery in a critical tool fails at 32 hours. What is the probability it was from manufacturer 2?

Answers

Answer:

The probability that the battery in a critical tool fails at 32 hours was from manufacturer 2 is 0.625

Step-by-step explanation:

Given that:

60% of the batteries are from manufacturer 1

90% of these batteries last for over 40 hours

Let the number of the battery duration be n = 0.90

Therefore n' = 1 - 0.90 = 0.10

Let p = manufacturer 1  and q = manufacturer 2

q = 1 - p

q = 1 = 0.6

q = 0.4

Thus ; 40% of the batteries are from manufacturer 2

However;

Only 75% of the batteries from manufacturer 2 last for over 40 hours.

Let number of battery duration be m = 0.75

Therefore ; m' = 1 - 0.75 = 0.25

A battery in a critical tool fails at 32 hours.

Thus; the that the battery in a critical tool fails at 32 hours was from manufacturer 2 is:

[tex]= \dfrac{q \times m' }{ p \times n' + q \times m' }[/tex]

[tex]= \dfrac{0.4 \times0.25 }{ (0.6 \times 0.1) + (0.4 \times 0.25 ) }[/tex]

[tex]=\dfrac{0.1}{0.06+ 0.1}[/tex]

[tex]=\dfrac{0.1}{0.16}[/tex]

= 0.625

The probability that the battery in a critical tool fails at 32 hours was from manufacturer 2 is 0.625

The probability that the battery was from manufacturer 2 is 62.5%.

Since the Ambell Company uses batteries from two different manufacturers, and historically, 60% of the batteries are from manufacturer 1, and 90% of these batteries last for over 40 hours, while only 75% of the batteries from manufacturer 2 last for over 40 hours, if a battery in a critical tool fails at 32 hours, to determine what is the probability it was from manufacturer 2 the following calculation must be performed:

You must establish the percentage of failure of the total batteries, and determine what percentage of failures corresponds to each manufacturer. Manufacturer 1 = 60 x 0.1 = 6 Manufacturer 2 = 40 x 0.25 = 10 Total = 16 16 = 100 10 = X 100 x 10/16 = X 62.5 = X

Therefore, the probability that the battery was from manufacturer 2 is 62.5%.

Learn more in https://brainly.com/question/14461509

Consider the recursive function,
f(1) = 2
f(n) = 5•f(n − 1), for n > 2

Answers

Answer:

yes?

Step-by-step explanation:

??? can u say exactly what the question is please? thank you

Answer:

the question is:

Which statement is true?

A. The value of F(6) is 2 times the value of f(3).

B. The value of f(6) is 15 times the value of f(3).

C. The value of f(6) is 1/125 times the value of f(3).

D. The value of f(6) is 125 times the value of f(3).

Step-by-step explanation:

comment the answer below for everyone please.

Which statement describes this system of equations? 9x – 6y = 15, 3x – 2y = 5 The equations in the system are equivalent equations. There is no solution to the system of equations. The system of equations has one solution at (3, 2). The system of equations has one solution at (5, 5).

Answers

Answer:

There is no solution to the systems of equation.

Step-by-step explanation:

Graph the system by using y=mx+b

Both systems are y=2/5x+5/2.

Answer:

that guy is wrong. its the first option.

Step-by-step explanation:

i just took it

Each marble bag sold by Carmen's Marble Company contains 3 purple marbles for every 4 blue marbles. If a bag has 28 blue marbles, how many purple marbles does it contain?

Answers

Answer:

21 purple marbles

Step-by-step explanation:

my explanation is i looked at it like a ratio so ¾= x/28

then i took 28 ÷ 4 which equals 7, then i took 7 and multiplied it by 3 which gave me 21, so the answer is 21 purple marbles

Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary.
Age (yr) when award was won: 25-34, 35-44, 45-54, 55-64, 65-74, 75-84, 85-94
Frequency: 29, 34, 16, 3, 5, 1, 2

Answers

Step-by-step explanation:

kindly find attached detailed information of the remaining information as requested for your reference

   

1. The lower class limit is the left number in the age column

   i.e in the 25-34 the lower class limit is 25          

2. The upper class limit is the right number in the age column

   i.e in the 25-34 the lower class limit is 34

3. The class width is the difference  between the class boundaries of a single class

 class width = 34.5-24.5= 10

4. The number of individuals is= 29+34+16+3+5+1+2= 90    

Which describes the graph in words?
A. All numbers less than -10 and less than or equal to 8.
B. All numbers greater than -10 and less than 8
C. All numbers greater than or equal to -10 and less than or equal to 8
D. All numbers greater than -10 and less than or equal to 8.

Answers

D. All numbers greater than -10 and less than or equal to 8

Help ASAP!!!!

Identify the correct trigonometry formula to use to solve for x.

Answers

Sin (angle) = opposite leg / hypotenuse

Sin(62) = 18/x

The answer is the third choice.

What is the Greatest Common Factor GCF between two expressions?

Answers

Answer:

The GCF is the largest expression that is factor of all expressions

Answer:

The GCF of two expressions is the greatest expression that is a factor of both the expressions.

Step-by-step explanation:

For example 7x² and 14x.

7x² = 1, 7, x, x

14x = 2, 7, x

The greatest common factor of the two expressions is 7x.

what is the approximate radius of a sphere with a volume of 1436cm to power of 3

Answers

Answer:

The radius is 7 cm

Step-by-step explanation:

Volume of a sphere is given by

[tex]V = \frac{4}{3} \pi {r}^{3} [/tex]

where r is the radius

From the question V = 1436 cm³

[tex]1436 = \frac{4}{3} \pi {r}^{3} [/tex]

Multiply through by 3

We have

[tex]4308 = 4\pi {r}^{3} [/tex]

Divide both sides by 4π

[tex] {r}^{3} = \frac{4308}{4\pi} [/tex]

[tex] {r}^{ 3} = \frac{1077}{\pi} [/tex]

Find the cube root of both sides

[tex]r = \sqrt[3]{ \frac{1077}{\pi} } [/tex]

r = 6.99

We have the final answer as

r = 7cm

Hope this helps

What is the size of the matrix resulting from...

Answers

Answer:

1 x 3

Step-by-step explanation:

The order of the first matrix is 1 × 3

The order of the second matrix is 3 × 3

that is (1 × 3 ) × (3 × 3 )

The bold values at the ends of the orders give the order of the product, that is

1 × 3

McKenzie has a bag contains six red marbles four blue marbles and 14 yellow marbles if she chooses one marble from the bag what is the probability that the marble is not yellow

Answers

Answer:

5/12

Step-by-step explanation:

Total number of marbles in the bag

6red+ 4blue + 14 yellow = 24 marbles

Not yellow marbles = 10 marbles

P ( not yellow ) = number of not yellow marbles / total marbles

                          =10/24

                          = 5/12

Answer:

5/12

Step-by-step explanation:

6 red marbles

4 blue marbles

14 yellow marbles

total marbles = 6 + 4 + 14 = 24 marbles

24 - 14 = 10 marbles

10 marbles are not yellow.

P(not yellow) = 10/24 = 5/12

Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is found that 4% of the legitimate users originate calls from two or more metropolitan areas in a single day. However, 30% of fraudulent users originate calls from two or more metropolitan areas in a single day. The proportion of fraudulent users is 0.0130%. If the same user originates calls from two or more metropolitan areas in a single day, what is the probability that the user is fraudulent

Answers

Answer:

0.0009741

Step-by-step explanation:

The approach to solve this question is by the use of Baye’s theorem in conditional probability

Please check attachment for complete solution and explanation

Answer:

0.000974

Step-by-step explanation:

Let assume that;

P(Q) is the probability that the same user originated calls from two or more metropolitan areas in a single day

Also; Let consider M to be the event that denotes the legitimate users and N to be the event that denote the fraudulent users .

Then;

P(M) = 0.00013

P(N) = 1 - P(M)

P(N) = 1 - 0.00013

P(N) = 0.99987

P(Q|M) = 0.3

P(Q|N) = 0.4

The probability the same users originates calls from two or more metropolitan areas in a single day is calculated as follows:

P(Q) = (P(M) P(Q|M) ) + ( P(N) P(Q|N)  )

P(Q) = ( 0.00013 × 0.3 ) + (0.99987 × 0.04 )

P(Q) = 0.000039 + 0.0399948

P(Q) = 0.0400338

However; The probability that the users is fraudulent given that the same users originates calls from two or more metropolitan areas in a single day is,

[tex]P(M|Q) = \dfrac{P(M) P(Q|M)}{(P(M) \ P(Q|M) ) + ((P(N) \ P(Q|N)) } \\ \\ \\ P(M|Q) = \dfrac{0.0001 \times 0.3}{0.0400338} \\ \\ \\ P(M|Q) = \dfrac{0.000039}{0.0400338} \\ \\ \\ \mathbf{P(M|Q) = 0.000974}[/tex]

Select the correct answer.

Answers

Answer:

C. 5 × 3

Step-by-step explanation:

The order of a matrix is the number of rows and columns that a matrix has. Rows are listed first and columns are listed second. The matrix has 5 rows going across horizontally and 3 columns going down vertically.

So, the order of the matrix is 5 × 3.

Hope that helps.

Question 3
34° Celsius is equal to
o
Fahrenheit​

Answers

False, 34° celcius is NOT equal to 0° Fahrenheit. It is 93.2°F

Hi

Below the formulas to convert Celsius into Fahrenheit.

9/5 C +32 = degree in fahrenheit.

Where C is the degree in celsius. So have a try and find the answer.

Construct a polynomial function with the stated properties. Reduce all fractions to lowest terms. Second-degree, with zeros of −7 and 6, and goes to −∞ as x→−∞.

Answers

y = -(x - 6)(x + 7).

Answer:

f( x ) = - x² - x + 42

Step-by-step explanation:

The polynomial function will have to include the zeroes with opposing signs, considering that when you isolate the value x say, you will take that value to the opposite side, changing the signs,

f(x) = (x + 7)(x - 6)

Now as you can see, x extends to negative infinity, such that,

f(x) = - (x + 7)(x - 6) - that negative makes no difference whatsoever on the zeroes of the function. All we want to do now is to expand this, and we receive out simplified solution.

Goal : [tex]expand\:-\:\left(x\:+\:7\right)\left(x\:-\:6\right)[/tex],

[tex]- xx+x\left(-6\right)+7x+7\left(-6\right)[/tex] = [tex]- xx-6x+7x-7\cdot \:6[/tex] = [tex]-\left(x^2+x-42\right)[/tex],

Expanded Solution : [tex]-x^2-x+42[/tex],

Polynomial Function : f( x ) = [tex]-x^2-x+42[/tex]

Rita ha decidido emprender un negocio de ventas de productos de protección personal, para lo cual tiene que inventir 1/3 de su dinero en mascarillas, 4/15 en guantes, 1/10 en protección facial y el resto en alcohol. ¿Que fracciónde dinero se invierte en alcohol?

Answers

Answer:

3/10

Step-by-step explanation:

Subtract the sum of 1/3, 4/15 and 1/10 from 1:

                                 10/30 + 8/30 + 3/30 = 21/30, or 7/10

                                   Then:  1 - 7/10 = 3/10

Other Questions
WILL MARK BRAINLIESTPLEASE HELP Please help me answer 1 and 2 and explain how you did it so I can understand x Which type of organism developed first? The perceived demand for a monopolistic competitor If you were to calculate the pull of the Sun on the Earth and the pull of the Moon on the Earth, you would undoubtedly find that the Sun's pull is much stronger than that of the Moon, yet the Moon's pull is the primary cause of tides on the Earth. Tides exist because of the difference in the gravitational pull of a body (Sun or Moon) on opposite sides of the Earth. Even though the Sun's pull is stronger, the difference between the pull on the near and far sides is greater for the Moon. Required:a. "Let F(r) be the gravitational force exerted on one mass by a second mass a distance r away. Calculate dF(r)/dr to show how F changes as r is changed. b. Evaluate this expression for dF(r) jdr for the force of the Sun at the Earth's center and for the Moon at the Earth's center. c. Suppose the Earth-Moon distance remains the same, but the Earth is moved closer to the Sun. Is there any point where dF(r)/dr for the two forces has the same value? Instructions on how to control your cells are contained in what part of the DNA? Sager Industries is considering an investment in equipment that will replace direct labor. The equipment has a cost of $86,000 with a $7,000 residual value and a 10-year life. The equipment will replace three employees who has an average total wages of $15,810 per year. In addition, the equipment will have operating and energy costs of $4,190 per year. Determine the average rate of return on the equipment, giving effect to straight-line depreciation on the investment. Solve x is less than or equal to 0 and x is greater than or equal to -4 Police need _________________ before they can conduct a search, but educators can legally search students when there are reasonable grounds to believe the students have violated the law or broken school rules. What is a stanza and how many lines does it have. #Write a function called after_second that accepts two #arguments: a target string to search, and string to search #for. The function should return everything in the first #string *after* the *second* occurrence of the search term. #You can assume there will always be at least two #occurrences of the search term in the first string. # #For example: # after_second("11223344554321", "3") -> 44554321 # #The search term "3" appears at indices 4 and 5. So, this #returns everything from the index 6 to the end. # # after_second("heyyoheyhi!", "hey") -> hi! # #The search term "hey" appears at indices 0 and 5. The #search term itself is three characters. So, this returns #everything from the index 8 to the end. # #Hint: This may be more complicated than it looks! You'll #have to look at the length of the search string and #either modify the target string or take advantage of the #extra arguments you can pass to find(). #Write your function here! The following information concerns the intangible assets of Epstein Corporation: On June 30, 2021, Epstein completed the acquisition of the Johnstone Corporation for $2,420,000 in cash. The fair value of the net identifiable assets of Johnstone was $2,050,000. Included in the assets purchased from Johnstone was a patent that was valued at $91,200. The remaining legal life of the patent was 13 years, but Epstein believes that the patent will only be useful for another eight years. Epstein acquired a franchise on October 1, 2021, by paying an initial franchise fee of $250,800. The contractual life of the franchise is 11 years. Required: 1. Prepare year-end adjusting journal entries to record amortization expense on the intangibles at December 31, 2021. 2. Prepare the intangible asset section of the December 31, 2021, balance she Write a program that takes as command-line arguments an integer N and a double value p (between 0 and 1), plots N equally spaced dots of size .05 on the circumference of a circle, and then, with probability p for each pair of points, draws a gray line connecting them. a(b + c) = a b + a c where a, b, and c are real numbersuse the distributive property to simplify the expression 8(3 + 4) = 24 + ? M angle D=? What is the degree of the angle? I have a couple more questions and I dont have time to answer them all lol, my science class starts in 15 minutes. What is the slope of the line which passes through (2, 0) and (0, 4)? (5 points) 2 Undefined 2 0 if F, V, and we're chosen as fundamental unit of force, velocity and time respectively , the dimensions of mass would be represented as A cause-and-effect relationship occurs when one event causes another event to happen. What events in the story and prior led to Margots unhappiness? ( the story is All Summer In a Day btw :) ) Please answer this in two minutes In My Story, when Rosa Parks writes about her famous bus ride and arrest on December 1, 1955, she mostly uses a chronological text structure because she wants