Find the distance, c, between (–4, –3) and (2, 1) on the coordinate plane. Round to the nearest tenth if necessary.

Answers

Answer 1

Answer:

d=√((x_2-x_1)²+(y_2-y_1)²)

d=√((2-(-4))²+(1-(-3))²)

d=√(6²+4²)

d=√36+16

d=√52

d=7.21110255...

d=7.2

Step-by-step explanation:

d=7.2

Answer 2

The distance between the points on the coordinate plane is 7.2 units.

What is coordinate geometry?

Coordinate geometry is the study of geometry using the coordinate points.  It provides a link between geometry and algebra through line graphs and curves.

For the given situation,

The points are (x1, y1) be (–4, –3) and (x2, y2) be (2, 1)

The formula for the distance between points,

[tex]d=\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }[/tex]

On substituting the above points,

⇒ [tex]d=\sqrt{(2-(-4))^{2}+(1-(-3))^{2} }[/tex]

⇒ [tex]d=\sqrt{6^{2}+4^{2} }[/tex]

⇒ [tex]d=\sqrt{52}[/tex]

⇒ [tex]d=7.211[/tex] ≈ [tex]7.2[/tex]

Hence we can conclude that the distance between the points on the coordinate plane is 7.2 units.

Learn more about coordinate geometry here

https://brainly.com/question/16410393

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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