Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 6x3 − 9x2 − 216x + 3, [−4, 5]

Answers

Answer 1

Answer:

absolute minimum = -749 and

absolute maximum = 467

Step-by-step explanation:

To get the absolute maximum and minimum of the function, the following steps must be followed.

First, we need to find the values of the function at the given interval [-4, 5].

Given the function f(x) = 6x³ − 9x² − 216x + 3

at x = -4;

f(-4) = 6(-4)³ − 9(-4)² − 216(-4) + 3

f(-4) = 6(-64) - 9(16)+864+3

f(-4) = -256- 144+864+3

f(-4) = 467

at x = 5;

f(5) = 6(5)³ − 9(5)² − 216(5) + 3

f(5) = 6(125) - 9(25)-1080+3

f(5) = 750- 225-1080+3

f(5) = -552

Then we will get the values of the function at the crirical points.

The critical points are the value of x when df/dx = 0

df/dx = 18x²-18x-216 = 0

18x²-18x-216 = 0

Dividing through by 18 will give;

x²-x-12 = 0

On factorizing the resulting quadratic equation;

(x²-4x)+(3x-12) = 0

x(x-4)+3(x-4) = 0

(x+3)(x-4) = 0

x+3 = 0 and x-4 = 0

x = -3 and x = 4 (critical points)

at x  = -3;

f(-3) = 6(-3)³ − 9(-3)² − 216(-3) + 3

f(-3) = 6(-27) - 9(9)+648+3

f(-3) = -162-81+648+3

f(-3) = 408

at x = 4

f(4) = 6(4)³ − 9(4)² − 216(4) + 3

f(4) = 6(64) - 9(16)-864+3

f(4) = 256- 144-864+3

f(4) = -749

Based on the values gotten, it can be seen that the absolute minimum and maximum are -749 and 467 respectively


Related Questions

Your birthday was in June and your rich Aunt Edna, who had been acting a little weird lately, gave you a check for $25,000 to help you celebrate. You opened a checking account with this money by making a DEPOSIT on June 16th and proceeded to have the time of your life!
​The first thing you did was move out of your parent’s house and into a high-rise apartment near downtown. On June 25th, you wrote CHECK #101 to the Trumble Tower for $1800 which included a $600 deposit. You wanted your “new” flat to be really cool, so you decided to decorate it with style and taste. You bought a home theater system and television at Best Buy using your Mastercard. At Rooms-To-Go, you purchased a living room set and bedroom set using your VISA card. You used your DEBIT card on July 4th for a $129.45 purchase at Macy’s. You invited all your friends over the following Saturday night for pizza and drinks and paid for it with your Mastercard.
On July 8th you realized that you needed some food and supplies for a day at the beach. First you went to Starbucks for breakfast using your DEBIT card to pay the $12.83 bill. You stopped at Walmart and bought $132.56 in food and supplies using your DEBIT card. At Kroger’s you used your DEBIT card to purchase $52.23 of groceries and your VISA card to buy gas. You also stopped by the ATM machine at your bank to withdraw $100 for the day at the beach.
On July 15th, you filled out a DEPOSIT slip for your paycheck of $250 since you forgot to sign up for direct deposit. After driving to and from the beach, you realized you needed a new car! You decided to go car shopping on July 16th since you did not have to work that day. At Best Friend Ford, you found the perfect car for $12,498.99! You wrote CHECK #102 for the car. Since you got a new car, you decided that you needed to look good while driving it so you went shopping on July 19th. You purchased clothing at H&M and Abercrombie & Fitch using your Mastercard.
Since you had been driving around in a new car wearing new clothes, your friends decided that they wanted to be paid the money that you owed them. Paul Smith accepted the $20 CHECK #103 you wrote him on July 21st. Linda Boltman and Max Badger wanted cash immediately so you went to the nearest gas station with an ATM and withdrew $80 in cash to pay them on July 23rd. Your bank charged you an ATM service FEE of $2.50 for the withdrawl.
At the end of the month, the bills started to arrive. You forgot to set up online banking with your checking account so you had to write checks. You paid the utility company Greenhouse Energy with CHECK #104 for $155.87 on July 25th, paid AllConnect with CHECK #105 for $150 for TV, internet, and phone on July 27th, paid Mastercard with CHECK #106 for $1518.23 on August 3rd, and paid VISA with CHECK #107 for $1994.02 on August 5th. You wrote a DEPOSIT slip on August 1st for your $250 paycheck and got $30 cash back with the deposit.

THE END​


Check Register Codes
ATM – ATM Withdrawal​​​​DEB – Debit Card​​​DEP – Deposit
FEE – Checking Account Fee​​​### (check number) – Check

2

Answers

Answer:

Dang shes rich, but what is the question?

Step-by-step explanation:

letry. 14 Chapter 9: Chapter 9 rest Chapter Test
A roof has a cross section that is a right triangle. The diagram shows the approximate dimensions of this cross section. Find the height of the roof.
Round your answer to the nearest tenth.
15 ft
h
8 ft
17 ft

Answers

Answer:

h = 7.1 cm

Step-by-step explanation:

To find the height of the triangle, we can first find the area of the triangle using the Heron's formula:

[tex]S = \sqrt{p(p-a)(p-b)(p-c)}[/tex]

Where a, b and c are the sides of the triangle and p is the semi perimeter of the triangle:

[tex]p = \frac{a+b+c}{2} = \frac{15 + 8 + 17 }{2} = 20\ cm[/tex]

So the area of the triangle is:

[tex]S = \sqrt{20(20-15)(20-8)(20-17)}[/tex]

[tex]S = 60\ cm^2[/tex]

Now, to find the height, we can use the following equation for the area of the triangle:

[tex]S = base * height/2[/tex]

The height draw in the figure is relative to the side of 17 cm, so this side is the value of base used in the formula. So we have that:

[tex]60 = 17 * h/2[/tex]

[tex]h = 120/17[/tex]

[tex]h = 7.06\ cm[/tex]

Rounding to the nearest tenth, we have h = 7.1 cm

Answer:

7.1 cm

Step-by-step explanation:

:D

A group of 10 students participate in chess club, karate club, or neither.

Answers

Answer:

P(A︱B) =0.50

Step-by-step explanation:

That's the answer

A standard dice is tossed twice. What is the probability of obtaining exactly one 5? Express your answer as a common fraction.

Answers

Answer:

  5/18

Step-by-step explanation:

There are a couple of ways to look at this.

1) If you make a matrix of all possibilities, you find there are 36 possible outcomes from the roll of a die twice. (That is the same number as for rolling two dice once.) Of those 36 outcomes, 10 are outcomes in which a 5 shows exactly once: (5, 1), (5, 2), (5, 3), (5, 4), (5, 6), (1, 5), (2, 5), (3, 5), (4, 5), (6, 5).

The probability of obtaining exactly one 5 is 10/36 = 5/18.

__

2) As listed above, there are two ways to get exactly one 5 in two rolls:

  (5 on the first, non-5 on the second) or (non-5 on the first, 5 on the second)

When the rolls are independent, as we assume here, the probability of a certain sequence is the product of the probabilities of the events in that sequence.

  P(5, non-5) = (1/6)(5/6) = 5/36

  P(non-5, 5) = (5/6)(1/6) = 5/36

The probability of obtaining either event is the sum of their individual probabilities:

  P({5, 5'} or {5', 5}) = 5/36 +5/36 = 10/36 = 5/18

__

The probability of obtaining exactly one 5 in two rolls of a die is 5/18.

Answer:

S= (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

    (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

    (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

    (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

    (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

    (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

For this case the size of the sample space is 36 now we count the number of pairs with exactly one 5 and we have:

(1,5), (2,5), (3,5), (4,5), (6,5), (5,6), (5,4), (5,3), (5,2), (5,1)

And then the probability would be:

[tex] p=\frac{10}{36}= \frac{5}{18}[/tex]

Step-by-step explanation:

For this case w ehave the following sample space:

S= (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

    (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

    (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

    (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

    (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

    (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

For this case the size of the sample space is 36 now we count the number of pairs with exactly one 5 and we have:

(1,5), (2,5), (3,5), (4,5), (6,5), (5,6), (5,4), (5,3), (5,2), (5,1)

And then the probability would be:

[tex] p=\frac{10}{36}= \frac{5}{18}[/tex]

Which expression is equivalent to 0.83¯ ?

Answers

As a fraction, this would be 5/6.

Answer:

Hello There!!

Step-by-step explanation:

Your answer will be 83/99. Because, We have to expressed the 0.83¯ as a fraction in simplest form. Let x = 0.83¯ = 0.8383. Then, We have to multiply by 100 to both sides we have: 100x = 83.8383. After, Subtract (One) to (Two) we will have: 99x = 83. Then, We will divide both sides by 99 we have: x = 83/99. Therefore, the 0.83¯ as a fraction in simplest form is, 83/99. Hope This Helps!!~ Sorry, If the example confusing...

Find m2WXY
59
X
D
24°
A 250
B. 26
C. 81
D. 839

Answers

Answer: d. 83

Step-by-step explanation: 59+ 24 = 83

Answer:

D. 83 degrees

Step-by-step explanation:

Angle WXY is made up of two angles, angle WXD and angle YXD.

Therefore, angle WXY will be equal to the sum of angle WXD and YXD.

So, we can add angles WXD and YXD together to find out what the measure of angle WXY is.

<WXY= <WXD + <YXD

We know that angle WXD is 24 degrees and angle YXD is 59 degrees.

<WXD= 24

<YXD= 59

<WXY= 24+59

Add 24 and 59

<WXY=83

The measure of angle WXY is 83 degrees, so choice D is correct.

determine both the lower and upper limits of a 90% z-confidence interval for µ , the mean score for all students in the school district who are enrolled in gifted and talented programs.

Answers

Answer:

CI = ( μ  -  1,64 * σ /√n ;  μ  +  1,64 * σ /√n )

Step-by-step explanation:

We assume Normal Distribution

For Confidence Interval, CI = 90 %     and  α = 10 %

α = 0,1  and  α/2  =  0,05

So  we will look for z score reciprocate to these values, at the two tails of the bell

z(α/2) = 1,64 at th right tail  and -1,64 at the left

CI = ( μ  ±  1,64 * σ /√n  )

CI = ( μ  -  1,64 * σ /√n ;  μ  +  1,64 * σ /√n )

M angle D=? What is the degree of the angle?

Answers

Answer:

80°

Step-by-step explanation:

In ACB and ECD

AC =~ CE [ Given ]

BC =~ CD [ Given ]

<ACD =~ <ECD [ Vertical angles ]

Hence, ∆ ACB =~ ECD by SAS congruency of triangles.

Then, <B = <D

In ∆ABC , sum of all three angles must be 180°

<A + <B + <C = 180°

plug the values

[tex] 30 + < d \: + 70 = 180[/tex]

Add the numbers

[tex]100 + < d = 180[/tex]

Move constant to R.H.S and change it's sign

[tex] < d = 180 - 110[/tex]

Subtract the numbers

[tex] < d = 80[/tex] °

Hope this helps..

Best regards!!

a(b + c) = a × b + a × c where a, b, and c are real numbers

use the distributive property to simplify the expression

8(3 + 4) = 24 + ?

Answers

Answer:

32

Step-by-step explanation:

8(3 + 4) = 24 + ?

8(3)+8(4)= 24 + ?

24+32= 24 + ?

24-24+32=?

32=?

Answer:

? = 32

Step-by-step explanation:

Let's assume a = 8 , b = 3 , c = 4

[tex] \sf \: So :- \: \: a(b + c) = 8(3 + 4)[/tex]

[tex]8 \times 3 + 8 \times 4[/tex]

[tex]24 + 32[/tex]

Hence, The required value of ? = 32 .

Use the​ power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonometric functions greater than 1.
16 sin4x
16sin4x = _____

Answers

Answer:

[tex]6-8cos2x+2cos4x[/tex]

Step-by-step explanation:

We are given that

[tex]16sin^4 x[/tex]

We can write the given expression as

[tex]16(sin^2x \times sin^2 x)[/tex]

[tex]16(\frac{1-cos2x}{2})(\frac{1-cos2x}{2})[/tex]

By using the formula

[tex]sin^2\theta=\frac{1-cos2\theta}{2}[/tex]

[tex]4(1-cos2x)^2[/tex]

[tex]4(1-2cos2x+cos^2(2x)[/tex]

Using the identity

[tex](a-b)^2=a^2+b^2-2ab[/tex]

[tex]4(1-2cos2x+\frac{1+cos4x}{2})[/tex]

[tex]4-8cos2x+2+2cos4x[/tex]

[tex]6-8cos2x+2cos4x[/tex]

This is required expression.

Solve for x in the equation X^2-16^x=0

Answers

Answer:

-1/2

Step-by-step explanation:

x^2- 16^x = 0x^2 =  16^xx^2 = 4^2xx = 4^xlogx = xlog41/x×logx = log4log(x^1/x) = log4x^(1/x) = 4

At this point you can guess and try. And it seems that x = -1/2, lets check:

(-1/2)^(1 /-1/2)= (-1/2)^-2= 2^2= 4

So, this is correct: x= -1/2

Give me the correct format of report writing plzzz (subject English) help plz

Answers

Step-by-step explanation:

Hi, there!!..

The format of report writing are given in points;

Title (reflects of report as its main function and it should be clear, brief, specific and weighty.)After title you have to right place and date.

and start your body,

Background information about the report. (it should be clear and have reasons)Purpose (the report should have purpose)Actions or, sequences of happening should be clearly written. Characters mentioned should be written properly.

and write conclusion,

Observation (it should be clear, factual and objectives).

You may add comments on it.

Hope it helps....

Integrate the following: ∫84 [tex]dx[/tex]

A. 42x
B. 84x
C. 84x + C
D. 42x + C

Answers

Answer:

Choice C. [tex]84\, x + C[/tex].

Step-by-step explanation:

Consider the power rule for integration. Let [tex]n[/tex] be a real number that is not equal to [tex](-1)[/tex]. The power rule for integration states that:

[tex]\displaystyle \int x^{n}\, d x = \frac{1}{n + 1}\, x^{n+ 1} + C[/tex],

How could this rule apply to this question, since there's apparently no [tex]x[/tex] (or its powers) in the integrand? Keep in mind that [tex]x^{0} = 1[/tex] for all real (and particularly non-zero) values of [tex]x[/tex]. In other words, the integrand [tex]84[/tex] is equal to [tex]84\, x^0[/tex]. The integral becomes:

[tex]\displaystyle \int 84\, x^{0}\, dx[/tex].

The constant can be moved outside the integral sign. Therefore:

[tex]\displaystyle \int 84\, x^{0}\, dx= 84 \int x^{0}\, dx[/tex].

Now that resembles the power rule. In particular, [tex]n = 0[/tex], such that [tex]n + 1 = 1[/tex]. By the power rule:

[tex]\begin{aligned}84 \int x^{0}\, dx = 84\, \left(\frac{1}{1}\, x^{1} + C\right) = 84\, x + 84\, C\end{aligned}[/tex].

The non-zero constant in front of [tex]C[/tex] can be ignored (where [tex]C[/tex] represents the constant of integration.) Therefore:

[tex]\displaystyle \int 84\, dx = 84\, x + C[/tex].

If a is a constant then it's inetgration is

[tex]\boxed{\sf \displaystyel\int adx=ax+C}[/tex]

Here 84 is constant

[tex]\\ \rm\Rrightarrow \displaystyle\int 84dx[/tex]

[tex]\\ \rm\Rrightarrow 84x+C[/tex]

Option C

The owner of a music store gathered data from several schools about the number of students in their concert and marching bands. The scatter plot shows the data she gathered and the line of best fit. The equation of the line of best fit is y = 0.677x + 1.77. Based on the line of best fit, approximately how many students are predicted to be in the marching band at a school with 35 students in the concert band?

Answers

Answer:

25 students

Step-by-step explanation:

Given the equation of the best line of fit, [tex] y = 0.677x + 1.77 [/tex] , the number of students predicted to be in the matching band, if we have 35 students in the concert band, can be approximated by plugging in 35 as "x" in the equation of the best line of fit, and solve for "y". y would give us the predicted number of students to expect in the marching band.

[tex] y = 0.677(35) + 1.77 [/tex]

[tex] y = 23.695 + 1.77 [/tex]

[tex] y = 25.465 [/tex]

The approximated number of to be in the marching band, with 35 students in the concert band is roughly 25 students.

Answer:25 students

Step-by-step explanation:

10 points + brainliest = 15 points!

Answers

Answer:

(2x^2+1)(4x+3)

Step-by-step explanation:

8x^3 + 6x^2 + 4x+3

Split into two groups

8x^3 + 6x^2       + 4x+3

Factor out 2x^2 from the first group and 1 from the second group

2x^2( 4x+3)  +1( 4x+3)

Factor out (4x+3) from each group

(4x+3) (2x^2+1)

Rearranging the order

(2x^2+1)(4x+3)

Answer:

(2x²+1)(4x+3)

Step-by-step explanation:

8x³ + 6x² + 4x +3=        regroup as follows(8x³ + 4x) + (6x²+3) =4x(2x²+1) + 3(2x²+1)=(2x²+1)(4x+3)

Correct choice is the second one

Select the correct answer. Consider the function f(x) = 3x and the function g, which is shown below. How will the graph of g differ from the graph of f? The graph of g is the graph of f shifted to the right by 3 units. The graph of g is the graph of f shifted down by 3 units. The graph of g is the graph of f shifted to the left by 3 units. The graph of g is the graph of f shifted up by 3 units.

Answers

Answer:

The graph of g is the graph of f shifted up by 3 units.

Step-by-step explanation:

Consider the graph of a function r with real numbers k and h.

Transformation Effect

r(x) + k shifts the graph up k units

r(x) - k shifts the graph down k units

r(x + h) shifts the graph to the left h units

r(x - h) shifts the graph to the right h units

It is given that g(x) = f(x) + 3. Therefore, the graph of g is the graph of f shifted up by 3 units.

Write these numbers in standard form 906000000

Answers

Answer:

9.06×10 to the power of 8(8 is superscript above 10)

Answer:

9.06 x 10^8

Step-by-step explanation:

906000000 = 9.06 x 10^8

8 decimal places in

Two similar triangles have perimeters of 45 cm and 75 cm respectively. What scale factor would relate these two triangles?

Answers

Answer:

1 2/3

Step-by-step explanation:

Well we divide 75 by 45 which is 1.6 repeating and that as a fraction is 1 2/3.

Thus,

the scale factor that relates the 2 triangles is 1 2/3.

Hope this helps :)

Penny's parents gave her $50 to spend on new video games. Used games are $7 and new games are $12. 1. What is the system of inequalities that represent this situation? 2. What is the maximum amount of used games that she could buy? 3. What is the minimum amount of new games that she could buy? 4. What are two possible combinations of used and new games she can purchase?

Answers

The correct answers are Part 1: 7x + 12y  50, x,y 0; Part 2: 7; Part 3: 0: Part 4: 2 old and 3 new video games.

Step-by-step explanation:

Penny's parents gave her $50 to buy new video games.

Price of used games are $7 and new games are $12.

Let Penny buy x number of old video games and y number of new video games.

Part 1:

Total price she spent on buying the video games are 7x + 12y.

This amount should be less than or equal to the amount of money she possess. therefore 7x + 12y  50, x, y  0.

Part 2:

Maximum number of used game she can buy can be given when she spends all her money just on used games. Therefore y = 0. This implies x .

Thus the maximum number of used game she can buy is 7 where she does not buy any new game and has $1 left with her after the purchase.

Part 3:

Minimum number of new games that Penny can buy is zero. She can not buy any new games and spent all her money purchasing old games.

Part 4:

The possible combination in which she can purchase both the video games is 2 old games and 3 new games.

hope this helps

Write the expression as the logarithm of a single number or expression.
4 In 2+3 In 5​

Answers

Answer:

ln [2^4 * 5^3]

Step-by-step explanation:

Rewrite 4 ln 2 as ln 2^4 and 3 ln 5 as ln 5^3.

Then 4 In 2+3 In 5 = ln 2^4 + ln 5^3, which in turn becomes

ln [2^4 * 5^3]

Solve x is less than or equal to 0 and x is greater than or equal to -4

Answers

Answer:

x = {-3, -2, -1, 0}

Step-by-step explanation:

x ≤ 0

x > -4

then

x {-3, -2, -1, 0}

I have a couple more questions and I don’t have time to answer them all lol, my science class starts in 15 minutes.

Answers

Answer:

[tex]\boxed{x = 7}[/tex]

Step-by-step explanation:

75 = 11x-2 (Corresponding angles are equal)

11x -2 = 75

Adding 2 to both sides

11x = 75+2

11x = 77

Dividing both sides by 11

x = 7

Answer:

[tex]\left[\begin{array}{ccc}\\x = 7\\\end{array}\right][/tex]

Step-by-step explanation:

Well to find x we can set up the following equation,

11x - 2 = 75

So we have to single out x.

+2 to both sides

11x = 77

Divide 11 by both sides

x = 7

Thus,

x = 7.

Hope this helps :)

Simplify 3/4(1/2x-12)+4/5

Answers

Answer:

3x/8 - 41/5

Step-by-step explanation:

Simplify each term.

3x/8 − 9+4/5

To write −9 as a fraction with a common denominator, multiply by 5/5

3x/8−9 x 5/5 + 4/5

Combine −9 and 5/5

Combine the numerators over the common denominator.

3x/8 + −41/5

Move the negative in front of the fraction

3x/8 - 41/5

Hope this helps you

A survey of 181 registered voters in one state reveals that 112 of them favor approval of a bill before the legislature. Construct a 98% confidence interval for the true proportion of all voters in the state who favor approval of the bill. Give your answers as decimals, rounded to 3 places after the decimal point (if necessary). 98% confidence interval for p: ( , )

Answers

Answer:

Hence the approximate 98% confidence interval for the voters in favor of the approval of the bill is  ( 0.541 , 0.683)

Step-by-step explanation:

The sample proportion is = p = 112/181 = 0.61878= 0.612

q = 1-p = 1- 0.612= 0.388

The degree of confidence is 98 % so z₀.₀₂₅= 1.96  taking α = 5 at 95 %

The interval X~± 0.98  is a random variable because X does not have a particular value but takes different values in different samples.

In repeated samples of size 16 from a normal distribution with standard deviation 2 the interval X~± 0.98 will contain true unknown value of mean about 95 percent of the time .

p ± z ( base alpha by 2) √pq/n

Substituting the values

0.612 ± 1.96√0.612*0.388/181

Multiplying p and q

= 0.612 ± 1.96 √0.237456/181

Solving the square root

=0.612 ± 1.96( 0.03622)

Multiplying  value of z with the value of square root

=0.612 ±  0.07099

Adding or subtracting will give   0.683, 0.541

Hence the approximate 98% confidence interval for the voters in favor of the approval of the bill is  ( 0.541 , 0.683)

The mean number of words per minute (WPM) typed by a speed typist is 149149 with a standard deviation of 1414 WPM. What is the probability that the sample mean would be greater than 147.8147.8 WPM if 8888 speed typists are randomly selected

Answers

Answer:

The probability is  [tex]P(\= X > x ) = 0.78814[/tex]

Step-by-step explanation:

From the question we are given that

     The population  mean is  [tex]\mu = 149[/tex]

     The standard deviation is  [tex]\sigma = 14[/tex]

     The random number    [tex]x = 147.81[/tex]

      The sample  size is  [tex]n = 88[/tex]

The probability that  the sample mean would be greater than [tex]P(\= X > x ) = P( \frac{ \= x - \mu }{\sigma_{\= x} } > \frac{ x - \mu }{\sigma_{\= x} } )[/tex]

Generally the z- score of this normal distribution is mathematically represented as

       [tex]Z = \frac{ \= x - \mu }{\sigma_{\= x} }[/tex]

Now

        [tex]\sigma_{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

         [tex]\sigma_{\= x } = \frac{14 }{\sqrt{88} }[/tex]

         [tex]\sigma_{\= x } = 1.492[/tex]

Which implies that

         [tex]P(\= X > x ) = P( Z > \frac{ 147.81 - 149 }{ 1.492} )[/tex]

        [tex]P(\= X > x ) = P( Z > -0.80 )[/tex]

Now from the z-table  the  probability is  found to be

        [tex]P(\= X > x ) = 0.78814[/tex]

celine is drake’s granddaughter. Her age is 4 years greater than 1/3 of drake’s age . if celine is 28 years old , how old is drake ?

Which equation represents this situation?

1) 4d - 1/3 = 28
2)1/3d - 4= 28
3) 1/3 + 4= 28
4) 4d + 1/3 = 28

Answers

Answer:

It should be 1/3d+4=28, but i dont see that option

Step-by-step explanation:

All the other ones are wrong. Its plus 4 because it states that its 4 years greater not lesser. Greater in the context means that its addition of 4.

idk if theres a typo or something but yeah.

The cost of plastering the 4 walls of a room which is 4m high and breadth one third of its length is Rs. 640 at the rate of Rs. 5/m². What will be the cost of carpeting its floor at the rate of Rs. 250/m².​

Answers

Answer:

Rs. 32,000

Step-by-step explanation:

height = 4m

let length = x m

breadth = x/3 m

Area of the 4 walls = 2(length × height) + 2(breadth × height)

Area = 2(4×x) + 2(4 × x/3) = 8x + (8x)/3

Area = (32x)/3 m²

1 m² = Rs. 5

The cost for an area that is (32x)/3 m²=  (32x)/3  × 5 Rs.

The cost of plastering 4 walls at Rs.5 per m² = 640

(32x)/3  × 5  = 640

(160x)/3 = 640

x = length = 12

Area =  (32x)/3 m² = (32×12)/3 = 128m²

The cost of carpeting its floor at the rate of Rs. 250/m²:

= 128m² × Rs. 250/m² = 32,000

The cost of carpeting its floor at the rate of Rs. 250/m² = Rs. 32,000

Veda solves the following system of linear equations by elimination. What is the value of x in the solution of the system
of equations?
6+4x-2y=0
-3-7y=10x

Answers

Answer:

work shown and pictured

Answer:

x= -1  y = 1

Step-by-step explanation:

1. Suppose f(x) = x^4-2x^3+ax^2+x+3. If f(3) = 2, then what is a? 2. Let f, g, and h be polynomials such that h(x) = f(x) * g(x). If the constant term of f(x) is -4 and the constant term of h(x) is 3, what is g(0)? 3. Suppose the polynomials f and g are both monic polynomials. If the sum f(x) + g(x) is also monic, what can we deduce about the degrees of f and g? 4. If f(x) is a polynomial, is f(x^2) also a polynomial 5. Consider the polynomial function g(x) = x^4-3x^2+9 a. What must be true of a polynomial function f(x) if f(x) and f(-x) are the same polynomial b.What must be true of a polynomial function f(x) if f(x) and -f(-x) are the same polynomial

Answers

Answer:

1. a = -31/9

2. -3/4

3. Different degree polynomials

4. Yes, of a degree 2n

5. a. Even-degree variables

b. Odd- degree variables

Step-by-step explanation:

1. Suppose f(x) = x^4-2x^3+ax^2+x+3. If f(3) = 2, then what is a?

Plugging in 3 for x:

f(3)= 3^4 - 2*3^3 + a*3^2 + 3 + 3= 81 - 54 + 6 + 9a = 33 + 9a and f(3)= 2

9a+33= 29a= -31a = -31/9

------------

2. Let f, g, and h be polynomials such that h(x) = f(x) * g(x). If the constant term of f(x) is -4 and the constant term of h(x) is 3, what is g(0)?

f(0)= -4, h(0)= 3, g(0) = ?h(x)= f(x)*g(x)g(x)= h(x)/f(x)g(0) = h(0)/f(0) = 3/-4= -3/4g(0)= -3/4

------------

3. Suppose the polynomials f and g are both monic polynomials. If the sum f(x) + g(x) is also monic, what can we deduce about the degrees of f and g?

A monic polynomial is a single-variable polynomial in which the leading coefficient is equal to 1.

If the sum of monic polynomials f(x) + g(x) is also monic, then f(x) and g(x) are of different degree and their sum only change the one with the lower degree, leaving the higher degree variable unchanged.

------------

4. If f(x) is a polynomial, is f(x^2) also a polynomial?

If f(x) is a polynomial of degree n, then f(x^2) is a polynomial of degree 2n

------------

5. Consider the polynomial function g(x) = x^4-3x^2+9

a. What must be true of a polynomial function f(x) if f(x) and f(-x) are the same polynomial?

If f(x) and f(-x) are same polynomials, then they have even-degree variables.

b.What must be true of a polynomial function f(x) if f(x) and -f(-x) are the same polynomial?

If f(x) and -f(-x) are the same polynomials, then they have odd-degree variables.

Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1

Answers

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

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