Answer:
h²= G²- R²
h² = 10²-6²
h²= 100 - 36
h²= 64
h = √64
.............
Heya!
Answer:
h = √91 cm
Step-by-step explanation:
Apply pythagorean theorem, a² + b² ° c².
Where,
a = ½(6) = 3 cm
b = h
c = 10 cm
Plug in the values
3² + h² = 10²
9 + h² = 100
9 + h² - 9 = 100 - 9
h² = 91
h = √91 cm
Hope this helps <33
3. You have 3 consecutive numbers, with the smallest number n.
a) What are the 7 numbers in the term of n?
b) Hence what is the sum of all the numbers?
( plz write down a step by step explanation ).
1. Give an example of a whole number that is not a natural number
2. Give an example of a rational number that is not a whole number.
3. Give an example of a real number that is irrational.
4. Are integers always/sometimes/never whole numbers?
5. Are natural numbers always/sometimes/never rational numbers?
6. Are irrational numbers always/sometimes/never rational numbers?
Glas
Answer:
2
Step-by-step explanation:
Simple interest on a certain sum is 16 by 25 of the sum. find the rate of interest and time is the both are numerically equal.
Answer:
hence rate of interest is 8% and time 8 years
Step-by-step explanation:
Write the following as an algebraic expression;
a) Half the sum of X and y
b) Half the cube of X subtracted from y
Answer:
1/2(x + y)
Step-by-step explanation:
The sum of x and y is x + y
1/2 the sum of x + y is 1/2(x + y)
1/2 x^3
This is subtracted from y
y - 1/2 x^3
Find the slope of the line going through the points (-10,0)
and (4,0)
Answer:
0
Step-by-step explanation:
To find the slope, we can use the slope formula
m = (y2-y1)/(x2-x1)
= (0-0)/(4- -10)
= (0-0)/(4+10)
= 0/14
=0
reflect point (-3,1) in the line y=5
Answer:
6 (4757)
Step-by-step explanation:
Which is the domain of the function f(x) = -5/6(3/5)^x
= ?
all real numbers
all real numbers less than 0
all real numbers greater than 0
all real numbers less than or equal to 0
Answer:
all the real numbers greater then 0
2a + 9 = 4 then a = _______
Answer:
[tex]a=\frac{-5}{2}[/tex]
Step-by-step explanation:
[tex]2a+9=4[/tex]
[tex]2a=4-9[/tex]
[tex]2a=-5[/tex]
[tex]a=\frac{-5}{2}[/tex]
16. Which situation can be represented by y = 60x – 20?
A. The time remaining in minutes, y, for x hours after 20 minutes have past.
B. The cost, y, of buying x pairs of jeans for $60 with a 20% off coupon.
C. The cost, y, after buying raffle tickets for $40 each.
D. The number of seconds, y, in an x minute commercial if you skip the first 20 minutes.
Answer:
A is the right answer. so right it
1. The quotient of a number and 6 is 12.
Answer:
2 is your answer
Step-by-step explanation:
6x2=12
Answer:
72
Step-by-step explanation:
[tex] \frac{x}{6} = 12 \\ x = 12 \times 6 \\ x = 72[/tex]
Which of the following is equivalent to 6.32x10^-3?
A. 0.632
B. 0.0632
C. 0.00632
D. 0.000632
Answer:
c. 0.00632
Step-by-step explanation:
Since 10 is raised to a negative 3, this means that the zeros come before the non-zero digits
The ratio of the radius or diameter or circumference of a circle to its diameter or radius or circumference is approximately 3.14.
Answer:
the question is?
Step-by-step explanation:
What is the value of 20 - (3 × 23 - 5)?
A
-191
B
1
C
11
D
131
Answer:
20 - (3 × 23 - 5) = 20 - (69 - 5) =20 - 64 =- 44Note.
The answer options are not matching the question. Something is wrong with the question.
[tex]\huge\boxed{\frak{Hey\ there!}}[/tex]
[tex]\huge\boxed{\frak{20 - (3\times23-5)}}\\\\\huge\boxed{\frak{3\times23 \rightarrow 69}}\\\\\huge\boxed{\frak{= 20 - (69 - 5)}}\\\\\huge\boxed{\frak{69 - 5 \rightarrow 64}}\\\\\huge\boxed{\frak{= 20 - 64}}\\\\\huge\boxed{\rightarrow\frak{-44}}\\\\\\\boxed{\frak{Answer: -44}}\huge\checkmark\\\boxed{\rm{\star \ None\ of\ the\ above\ }\star}[/tex]
[tex]\frak{Good \ luck \ on \ your \ assignment \ and \ enjoy\ your \ day!}\\\\\\\\\frak{Amphitrite1040}[/tex]
7. A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base 8 cm and sides 6 cm each is to be made of three different shades as shown in Fig. 8.17. How much paper of each shade has been used in it?
Answer:
Step-by-step explanation:
diagonal = 32 cm
Area of square = [tex]\dfrac{d^{2}}{2}[/tex]
[tex]=\dfrac{32*32}{2}\\\\=512 \ cm^{2}[/tex]
Diagonal separate the square into two equal triangles.
Area of upper triangle that is shaded black = area of lower triangle = 512/2
= 256 cm²
Isosceles triangle:
a = 6 cm ; b = 6 cm c = 8cm
[tex]s = \dfrac{a+b+c}{2}\\\\=\dfrac{6+6+8}{2}\\\\=\dfrac{20}{2}\\\\=10\\\\s-a = 10 - 6 = 4 \ cm\\\\s-b = 10-6 = 4 \ cm\\\\c - c = 10 - 8 = 2 \ cm\\\\Area = \sqrt{s*(s-a)(s-b)(s-c)}\\\\=\sqrt{10*4*4*2}\\\\=\sqrt{2 * 2 * 4 * 4 * 5}\\\\=4*2\sqrt{5}\\\\=8\sqrt{5}\\\\=8*2.24\\\\=17.92 \ cm^{2}[/tex]
Area of black shade paper = 256 + 17.92 = 273.92 cm²
Area of white shade paper = 256 cm²
Area of the isosceles triangle = s(s-a)(s-b)(s-c)
Write the value of each expression in standard form. Expression Standard Forr 2hundres×10 in standard form
Two rectangles are similar. The smaller has a length of 8 cm and an area of 40 cm.
If the width of the larger rectangle is 10 cm, find its area.
Answer:
160 cm²
Step-by-step explanation:
If the two rectangles are similar, that means they have equal scale factors. The smaller rectangle has length of 8 cm and area of 40 cm, which means the width is 5 cm.
The width of the larger rectangle is 10 cm, which is double the width of the smaller, similar rectangle. So, to find the length of the larger rectangle, multiply 8 x 2, which gives you 16 cm for the length, since the scale factor is 2.
Now, just find the area of the larger rectangle by doing length x width. 16cm x 10 cm = 160 cm²
Answer:
160 cm^2
Step-by-step explanation:
Our strategy is to find the length of the larger rectangle so we can find the area. To find the length, we will rely on the fact the two rectangles are "similar": their sides are in equal proportions, or have the same "ratio."
We know that the smaller rectangle has a width of 5 cm because, when we substitute area and length into
A = lw
we get
40 = 8w
w = 5
when we divide both sides by 8.
Because of equal proportions:
Width : length of the smaller rectangle = Width : length of the larger rectangle
We can write an equation
5 / 8 = 10 / x
Cross multiply
5x = 80
x = 16
So the larger rectangle has a length of 16 cm and a width of 10 cm (given)
meaning the area is
16 * 10 = 160 cm^2
Evaluate 6a-b^2/2 + (b/a)^2 if a = 2 and b = 4.
2
6
10.25
36
[tex] \frac{6a - {b}^{2} }{2} + \binom{b}{a} ^{2} [/tex]
a=2 b=4
[tex] \frac{6(2) - {4}^{2} }{2} + \binom{4}{2}^{2} [/tex]
[tex] \frac{12 - 16}{2} + \frac{16}{4} [/tex]
[tex] \frac{ - 4}{2} + 4 [/tex]
[tex] - 2 + 4 = 2[/tex]
answer is option a 2
please mark this answer as brainlist
5. Based on the graph of the trigonometric function,
what is the amplitudes
Answer:
[tex]\displaystyle 3[/tex]
Explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A|[/tex]
AND
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A|[/tex]
Accourding to the graph AND the above information, your amplitude is three units. This means each crest is extended three units beyond the midline of [tex]\displaystyle y = 0,[/tex] the centre of your graph, also known as the vertical shift. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
Now, just in case you wanted to know the equation(s) of this graph, look below:
[tex]\displaystyle y = 3sin\:(\frac{\pi}{2}x + \frac{\pi}{2}) \\ y = 3cos\:\frac{\pi}{2}x[/tex]
I am delighted to assist you at any time.
a) When I add 8 the answer is 30.
Answer:
if we add 8 then the answer will be 30"
because
if 22is added 8 then it became 30
22+8= 30
simple
urgent help needed fast
Answer:
Below
Step-by-step explanation:
You can use this formula to find the sum of an arithmetic series
Sn = n / 2 (a1 + an)
You need to find the number of terms in each series before using the formula
Tn = a + (n - 1) d
a) 53 = 5 + (n - 1) 3
n = 17
Sn = 17 / 2 (5 + 53)
= 493
b) 98 = 7 + (n - 1) 7
n = 14
Sn = 14 / 2 (7 + 98)
= 735
c) -102 = 8 + (n - 1) -5
n = 23
Sn = 23 / 2 (8 + (-102))
= - 1081
d) 41/3 = 2/3 + (n - 1) 1
n = 14
Sn = 14 / 2 (2/3 + 41/3)
= 301 / 3 or 100 1/3
Hope this helped! Best of luck <3
Please walk me through how to solve these problems. If you can only solve one that’s fine, I just don’t know where to start. (This is geometry)
Answer:
5,-0.5 is the answer to the fist one
Step-by-step explanation:
they want you to give the middle point of the line segment when you have graphed the two end points,... find the coordinates of the point the would be in the middle,... Best of luck,... Chow
if (a+3,b-2=b-1,2a-3 then find the value of A and B
Answer:
a=5 and b=9
Step-by-step explanation:
(x, y) = (s, t) => x=s and y=t
Hence, a+3=b-1 and b-2=2a-3, solving we get a=5 and b=9
-1/2x3/5 divided by (-51/40)
plz help me simplify this
-4/17
Step-by-step explanation:
-1/2×3/5÷-51/40
= -1/2×3/5×40/51
=-4/17
Solution of equation??
Answer:
[tex] \frac{3p}{5} - 15 = 3 \\ 3p - 15 = 15 \\ 3p = 15 + 15 \\ 3p = 30 \\ p = 10[/tex]
in a class 1/6 of a children are girls there are five girls in the class how many boys are there in the class
1) The endpoints of FCare (-2,-4 and G(1,0). Find the length of FG-
Answer:
it is [tex]5[/tex]
I need this ASAP!!!! PLZ HELP!!! 20 points!!
hey please help where it says the > thing it says fives, eights, threes
Answer:
[tex]8 \\ = 40 + 24 \\ = 64[/tex]
I hope I helped you^_^
Answer:
[tex]8 \times 8 = 5eights + 3eight \\ 8 \times 8 = 40 + 24 \\ 8 \times 8 = 64 \\ thank \: you[/tex]
l.c.m of 84 ,27,35,45
please help
Answer:
3780
Step-by-step explanation:
84 = 2^2 * 3 * 7
27 = 3^3
35 = 5 * 7
45 = 3^2 * 5
lcm = 2^2 * 3^3 * 5 * 7 = 3780
The first and second term of a linear sequence (A.p) are 3 and 8 respectively. Determine the least number of terms of the A.P that must be added so that the sum is greater than 250.
We are to find the number of terms in the AP that has a sum greater than 250
The number of teams in the AP which has a sum greater than 250 is at least 11 terms
First term, a = 3
second term, a + d = 8
so
common difference, d = 8-3
= 5
let
n = number of terms in the AP
The sum of n terms is 250
Sum = n/2{2a + (n - 1)d}
250 = n/2{2*3 + (n-1)5 }
250 = n/2{6 + 5n - 5}
250 = n/2(1 + 5n)
500 = n + 5n²
5n² + n - 500 = 0
Solve quadratically using formula
n = -b ± √b² - 4ac / 2a
= -1 ± √1² - 4(5)(-500) / 2(5)
= -1 ± √1 - (-10000) / 10
= -1 ± √1 + 10000 / 10
= -1 ± √10001 / 10
= -1 + √10001 / 10 or -1 - √10001 / 10
= -1/10 + √10001/10
or
-1/10 - √10001 / 20
= 9.9005 or -10.1005
The value of n must be positive and a whole value
Therefore,
n = 9.9005
Approximately, n = 10
The number of teams in the AP which has a sum greater than 250 is at least 11 terms
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