The answer is $21,989.34 and Yes, $10,000 invested at 6% interest will double its value in half the time as $10,000 invested at 3% interest.
Now, For the 6% investment:
$10,000 invested at 6% interest will double in 12 years:
$10,000 × (1.06)^12 = $21,989.34
For the 3% investment:
$10,000 invested at 3% interest will double in 24 years:
$10,000 × (1.03)^24 = $21,989.34
Therefore, it will take half the time (12 years) for the 6% investment to double its value compared to the 3% investment (24 years).
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HELP PLEASE I WILL GIVE POINTS PLEASE HELP PLS PLS
Answer:
Air
Step-by-step explanation:
it's asking you to look at the chart and find which substance is densest by comparing it to how fast sound can move through it (the speed of sound in the substance). In my opinion copper is not the densest material because sound moves through it the fastest; which means the particles in copper are not as densely held together. Air however, shows that sound can only travel 330 meters per second which is incredibly slow compared to the other listed materials, so by that logic it must be the densest.
what is the answer to this?
Answer:
B. y=7x
Step-by-step explanation:
A direct proportion is where the ratio is constant. The ratio will stay the same. Therefore, y = 7x, this ratio will stay constant making it a direct proportion.
Hope this helps : )
Find the equation of a line with the properties given. Write the equation in the form indicated. Through (3,5) and parallel to the line whose equation is ( y=-6x+4 ). Give answer in slope-int
The equation of the line through (3,5) and parallel to the line whose equation is ( y=-6x+4 ) is y = -6x + 23.
To find the equation of a line with the given properties, we need to use the concept of parallel lines and the point-slope form of a linear equation.
Parallel lines have the same slope, so the slope of the new line will be the same as the slope of the given line ( y=-6x+4 ), which is -6.
Next, we can use the point-slope form of a linear equation, which is (y - y1) = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Plugging in the given point (3, 5) and the slope -6, we get:
y - 5 = -6(x - 3)
Simplifying the equation, we get:
y - 5 = -6x + 18
y = -6x + 23
Finally, we can write the equation in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. The equation of the new line is y = -6x + 23.
Therefore, the equation of the line through (3,5) and parallel to the line whose equation is ( y=-6x+4 ) is y = -6x + 23.
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Find the gradients of lines A and B.
B
-2
6
O
-21
Fet
A
4
72%
X
The gradient of line A is 4/72% or 0.0555.The gradient of line B is -2/6 or -0.3333.
What is value?Value is the worth of something, or the amount of importance, good qualities, or benefits that something has. It is determined by the amount of effort, time, and resources that have been put into it. Value can also refer to a person's moral or ethical principles and standards. It is the measure of worth that someone places on something or someone. Ultimately, value is subjective, as it is based on individual opinion.
The gradients of lines A and B indicate the rate of change of the line in relation to the x-axis. The gradient of line A is positive, which indicates that the line is increasing as it moves along the x-axis. This means that the y-value of the line is increasing as the x-value increases. On the other hand, line B has a negative gradient, which means that the y-value of the line is decreasing as the x-value increases. This means that the line is decreasing as it moves along the x-axis. This is why the gradients of lines A and B are different.
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whats the answer to this?
Answer:
Answer is C
Step-by-step explanation:
using long divison:
Please help me on 6,7and8
\[ \begin{array}{l} n=4 \\ -1,4, \text { and } 3+2 i \text { are zeros; } \\ f(1)=-144 \end{array} \] \[ f(x)= \] (Type an expression using \( x \) as the variable. Simplify your answer.)
Plugging in \( x = 1 \) gives us \[ -144 = (1+1)(1-4)(1^2 - 6(1) + 13) = (2)(-3)(8) = -48a \] Solving for \( a \) gives us \[ a = \frac{-144}{-48} = 3 \] So, the expression for \( f(x) \) is \[ f(x) = 3(x+1)(x-4)(x^2 - 6x + 13) \]
To find the expression for \( f(x) \), we need to use the fact that the zeros of a polynomial are the values of \( x \) that make the polynomial equal to zero. This means that if \( -1, 4, \) and \( 3+2i \) are zeros of \( f(x) \), then the factors of \( f(x) \) are \[ (x+1)(x-4)(x-(3+2i))(x-(3-2i)) \] Now, we can simplify the last two factors by multiplying them together: \[ (x-3-2i)(x-3+2i) = (x-3)^2 - (2i)^2 = x^2 - 6x + 9 - 4i^2 = x^2 - 6x + 9 + 4 = x^2 - 6x + 13 \] So, the expression for \( f(x) \) is \[ f(x) = (x+1)(x-4)(x^2 - 6x + 13) \] Now, we can use the fact that \( f(1) = -144 \) to find the value of the leading coefficient of \( f(x) \). Plugging in \( x = 1 \) gives us \[ -144 = (1+1)(1-4)(1^2 - 6(1) + 13) = (2)(-3)(8) = -48a \] Solving for \( a \) gives us \[ a = \frac{-144}{-48} = 3 \] So, the expression for \( f(x) \) is \[ f(x) = 3(x+1)(x-4)(x^2 - 6x + 13) \] This is the final answer.
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rocket travels 180 ft in 15 sec. What is the ratio of feet to seconds to the lowest term
Answer:
12ft: 1sec
Step-by-step explanation:
180ft : 15sec
180÷15=12
15÷15=1
soooo it's
12ft : 1sec in the lowest term
18. To find the perimeter of a regular octagon, use the
expression 8s, where s represents side length. If the
side length of a regular octagon is 1. 5 feet, what is
its perimeter in feet?
The perimeter of a regular octagon, we use the expression 8s, where s represents side length. The perimeter of a regular octagon with side length 1.5 feet is equals to the 12 feet.
Regular octagon is a polygon with eight sides. The perimeter of a polygon is equals to the sum of all its sides. All eight sides of regular octagon are same measure. So, in other words the perimeter of Regular octagon is equal to eight times the length its side. Here,
Side length of a regular octagon
= 1.5 feet
=> Perimeter = 8 × 1.5 feet [An octagon has 8 sides]
=> Perimeter = 12 feet
Hence, required perimeter is 12 feet.
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Given △PQR ~ △STU, find the missing measures in △STU.
(geometry)
As a result, the missing angles' measurements are as follows: 3.75 parallel lines degree angle; 105 degrees at angle 4.; 75 degrees at angle 5.; 105 degrees at angle 6.
what is parallel lines?In geometry, parallel lines are coplanar infinite lines that never cross. Parallel planes are those in a three-dimensional space that never intersect. Parallel curves are those having a continuous minimum separation between them and no points of touch or junction. In geometry, parallel lines are two lines that are in the same plane, equally spaced apart, and never cross. Both vertical and horizontal can be used. With commonplace items like railroad tracks, stacks of notebooks, and pedestrian crossings, parallel lines may be seen.
Two parallel lines are crossed by a transversal in the example illustration. To locate the missing angles, we may make advantage of the characteristics of angles created by parallel lines and a transversal.
Angle 3: If angles 1 and 3 are equivalent angles and angle 1 is 75 degrees,
Angle 4: As angles 2 and 4 are equivalent angles and angle 2 is 105 degrees,
If angles 1 and 5 are alternative internal angles, and angle 1 is 75 degrees,
Angle 6: If angles 2 and 6 are alternative internal angles, and angle 2 is 105 degrees,
As a result, the missing angles' measurements are as follows:
3.75 degree angle
105 degrees at angle 4.
75 degrees at angle 5.
105 degrees at angle 6.
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Question 4 Use the Rational Zero Theorem to list all possible rational zeros for the given function. f(x)=-2x^(3)+x^(2)-4x+6
The possible rational zeros for the given function are ±1, ±2, ±3, ±6.
The Rational Zero Theorem states that if f(x) = anxn + an-1xn-1 + ... + a1x + a0 is a polynomial with integer coefficients, then any rational zero of f(x) must be of the form p/q, where p is a factor of the constant term a0 and q is a factor of the leading coefficient an.
For the given function f(x)=-2x^(3)+x^(2)-4x+6, the constant term is a0 = 6 and the leading coefficient is an = -2.
The factors of the constant term are ±1, ±2, ±3, and ±6, and the factors of the leading coefficient are ±1 and ±2.
Therefore, the possible rational zeros for the given function are ±1/±1, ±2/±1, ±3/±1, ±6/±1, ±1/±2, ±2/±2, ±3/±2, and ±6/±2, which simplifies to ±1, ±2, ±3, and ±6.
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Hamlet, Rosencrantz and Guildenstern are flipping coins. The odd man wins the coins of the others; if all coins appear alike, no coins change hands. Find the expected number of throws required to force one man out of the game provided Hamlet has 14 coins to start with and Rosencrantz and Guildenstern have 6 coins each.
Hint: Look for the expectation in the form Klmn, where l m and n are the numbers of coins they start with and K depends only on l + m + n the total number of coins.
The expected number of throws required is 243/8, or approximately 30.375.
The key to solving this problem is to find the probability that each player will be the odd man out on each flip of the coin, and then use this to calculate the expected number of throws required to eliminate one player.
Let E(l, m, n) be the expected number of throws required to eliminate one player when Hamlet starts with l coins, Rosencrantz starts with m coins, and Guildenstern starts with n coins. We can write the following recursive equations:
E(l, m, n) = 1 + (1/2)(E(l-1, m+1, n) + E(l+1, m-1, n))
E(l, m, n) = 1 + (1/2)(E(l, m-1, n+1) + E(l, m+1, n-1))
E(l, m, n) = 1 + (1/2)(E(l+1, m, n-1) + E(l-1, m, n+1))
The first equation gives the expected number of throws required when Hamlet is the odd man out, the second equation gives the expected number of throws required when Rosencrantz is the odd man out, and the third equation gives the expected number of throws required when Guildenstern is the odd man out.
Using these equations, we can solve for E(14, 6, 6) to get the expected number of throws required when Hamlet starts with 14 coins and Rosencrantz and Guildenstern each start with 6 coins:
E(14, 6, 6) = 243/8
Therefore, the expected number of throws required is 243/8, or approximately 30.375.
We use a recursive approach to find the expected number of throws required to eliminate one player, starting from the initial configuration of 14-6-6 coins. At each step, we consider the three possible cases where one of the players is the odd man out, and calculate the expected number of throws required to eliminate that player. We then take the average of these three values, weighted by the probability that each player will be the odd man out on the next flip of the coin. We repeat this process until only one player is left.
The final answer, 243/8, represents the expected number of throws required to eliminate one player, starting from the initial configuration of 14-6-6 coins. This means that, on average, it will take about 30.375 throws of the coin to eliminate one player and reduce the game to a two-player game.
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A crew of highway workers can pave 600 yards in 2/3of an hour.
If they continue to work at the same rate, how much highway will they pave in one hour?
Answer:900 yards
Step-by-step explanation:
Unit rate would be 600/2 meaning 300 yards would be done in a third of an hour. Multiply that be 3 (3 thirds is 1) and 300x3=900
pretty straightforward :)
According To The Texas Parks And Wildlife Department, There Are About 40 White-Tailed Deer Per Square Mile In Each Of 35 Texas Counties. A Rectangular Area On A Ranch In One Of These Counties Measures \( 2.25 \) Miles By \( 6.7 \) Miles. How Many White-Tailed Deer Are Expected To Live In This Rectangular Area?
603 white-tailed deer are expected to live in the rectangular area. To find the total number of white-tailed deer in the rectangular area, we need to find the area of the rectangle first. The area of a rectangle is given by the formula:
Area = length × width
In this case, the length is 2.25 miles and the width is 6.7 miles. So, the area of the rectangle is:
Area = 2.25 × 6.7
Area = 15.075 square miles
According to the given information, there are about 40 white-tailed deer per square mile in each of 35 Texas counties. We need to find how many white-tailed deer are expected to live in a rectangular area that measures 2.25 miles by 6.7 miles.
Now, we can find the total number of white-tailed deer in the rectangular area by multiplying the area by the number of deer per square mile:
Total number of deer = 15.075 × 40
Total number of deer = 603
Therefore, there are expected to be 603 white-tailed deer in the rectangular area.
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tor company, which sells tractors, is P=4.4n^(2)+5n-3, where n is the number of tractors sold and P is in hundreds of dolla
The company's profit for selling 10 tractors is $48700.
The total revenue (in hundreds of dollars) for the tractor company, when selling n tractors, is P = 4.4n^(2) + 5n - 3, where n is the number of tractors sold and P is in hundreds of dollars.
To find the company's profit for a given number of tractors sold, we can plug in the value of n into the equation and solve for P.
For example, if the company sells 10 tractors, we can plug in n=10 into the equation:
P=4.4(10)^(2)+5(10)-3
P=4.4(100)+50-3
P=440+50-3
P=487
Therefore, the company's profit for selling 10 tractors is $48700 (since P is in hundreds of dollars).
Similarly, we can plug in different values of n to find the company's profit for different numbers of tractors sold.
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You have $109 in the bank and your parents just gave you $281 for your birthday. Now you have exactly enough money to buy a laptop. How much does the laptop cost? Write an equation to represent the question. Use x as the variable.
Answer:
$109+$281=x when x=391
so that means a laptop equals $391 dollars
(Answer quick) Please show work.
Answer:
Step-by-step explanation:
The solution of inequality is n < - 9
answer this for 50 points (riddle) if u get it right you aslo get brainliest
How do you make six an odd number?
Answer:
Remove the S and you have IX which is the roman numeral for 9
Answer:
How do you make six an odd number?Take away the S and you have IX that would make the roman numeral 9.
Step-by-step explanation:
You're welcome.
21. A path 1 m wide is built along the border and inside a square garden of side 30 m. Find:
(i) the area of the path
(ii) the cost of planting grass in the remaining portion of the garden at the rate of Rs 40 per m2
(i) The area of the path is 120x - 4x² square meters.
(ii) The cost of planting grass in the remaining portion of the garden at the rate of Rs 40 per m² is (900 - 120x + 4x²) × 40
To find the area of the path and the remaining portion of the garden, we need to first find the dimensions of the inner square after the path has been constructed.
Let the width of the path be "x" meters. Then the dimensions of the inner square garden will be (30-2x) meters on each side.
(i) The area of the path can be found by subtracting the area of the inner square from the area of the outer square.
Area of outer square = 30 × 30 = 900 sq.m.
Area of inner square = (30-2x) × (30-2x) = 900 - 120x + 4x² sq.m.
Area of path = Area of outer square - Area of inner square
= 120x - 4x² sq.m.
(ii) The remaining portion of the garden is the area of the inner square.
Area of remaining portion = (30-2x) × (30-2x) sq.m.
= 900 - 120x + 4x² sq.m.
The cost of planting grass in the remaining portion of the garden at the rate of Rs 40 per m² can be found by multiplying the area of the remaining portion by the rate.
Cost of planting grass = Area of remaining portion × Rate
= (900 - 120x + 4x²) × 40
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When 508,000,000 is written in scientific notation, what will be the value of the exponent?
Step-by-step explanation:
When 508,000,000 is written in scientific notation, it will be represented as:
5.08 x 10^8
Therefore, the value of the exponent is 8.
Clay has a bag that contains 4 white marbles and 10 black marbles. Clay chooses a marble from the bag without looking, records the color, replaces it, then
chooses another marble. What is the theoretical probability that Clay chooses a white marble both times?
• 2.04%
O 8.16%
0 28.57%
O 51.02%
!!
Explanation:
There are 4 white marbles out of 4+10 = 14 total
4/14 = 2/7 is the probability of randomly picking a white marble.
(2/7)*(2/7) = 4/49 is the probability of picking two whites in a row, when the first marble is replaced.
Use a calculator to find that 4/49 = 0.0816 approximately.
That converts to 8.16% after moving the decimal point two spots to the right. This is equivalent to multiplying by 100.
Given that Sine theta = StartFraction 21 Over 29 EndFraction, what is the value of cosine theta, for 0 degrees less-than theta less-than 90 degrees?
Negative StartRoot StartFraction 20 Over 29 EndFraction EndRoot
Negative StartFraction 20 Over 29 EndFraction
StartFraction 20 Over 29 EndFraction
StartRoot StartFraction 20 Over 29 EndFraction EndRoot
The value [tex]Cos\theta[/tex] is 20/29 and it can be determined by using the Pythagoras theorem.
Given that,
The value [tex]Sin\theta[/tex] is [tex]\frac{21}{29}[/tex],
Where [tex]0^o < \theta < 90^o[/tex].We have to determine,
The value of [tex]Cos\theta[/tex]?
According to the question,
To determine the value of [tex]Cos\theta[/tex] following all the given below.
The formula of [tex]Sin\theta[/tex] is,
[tex]Sin\theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]
On comparing to the given value of [tex]Sin\theta[/tex] is,
[tex]Sin\theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]
[tex]sin\theta=\dfrac{21}{29}[/tex]
Here, Hypotenuse = 29, and Perpendicular = 21
Then,
The formula of [tex]Cos\theta[/tex] is,
[tex]Cos\theta=\dfrac{Base}{Hypotenuse}[/tex]
Let, the base be x,
The value of base finding by using Pythagoras theorem,
[tex](Hypotenuse)^2=(Perpendicular)^2+(Base)^2[/tex]
[tex](29)^2=(21)^2+(x)^2[/tex]
[tex]841=441+x^2[/tex]
[tex]x^2=841-441[/tex]
[tex]x^2=400[/tex]
[tex]x=20[/tex]
The value of the base is 20.
Therefore,
[tex]Cos\theta=\dfrac{Base}{Hypotenuse}[/tex]
[tex]cos\theta=\dfrac{20}{29}[/tex]
Hence, The value [tex]Cos\theta[/tex] is 20/29.
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what does the term "basic" mean as used in the car advertisement
No paint job, no trims, no extra things on the car.
The term "basic" in a car advertisement could have different meanings depending on the context. It could refer to a stripped-down version of a car model that has fewer features and is more affordable, or it could refer to a car that has all the necessary features without any unnecessary add-ons.
In general, when a car is described as "basic," it suggests that the car has a minimal set of features and functions that are essential for driving, but may not have all the bells and whistles that come with higher-end models. A basic car may have a standard transmission, basic stereo system, cloth seats, and manual windows, for example, without any additional features like a sunroof or heated seats.
However, it's important to note that the term "basic" can be subjective and vary depending on the brand, model, and price point. What one person considers basic, another may see as luxurious. So, it's always a good idea to review the specific features and specifications of a car before making a purchase decision, rather than relying solely on advertising language.
Each fall, thousands of mushroom hunters search the forest for truffles. A set of plots of equal size in an old-growth forest in Northern California was surveyed to count the number of truffles. The resulting distribution is presented in the following table. Are truffles randomly located around the forest? If not, are they clumped or dispersed? How can you tell? (the mean number of truffles per plot is 0.60)
Include the hypotheses you are testing, the chi-square value, the critical value, p-value, and conclusion Number of truffles per plot frequency
0 203
1 39
2 18
3 13
>3 15
As the variance/mean ratio is significantly greater than 1, the population is found to be a clumped distribution.
What is a Clumped Distribution?A clumped distribution, also known as an aggregated distribution, is a pattern of dispersion or arrangement of individuals within a population where they are found in groups or clusters. This means that individuals within a population are more likely to be found in certain areas, while other areas may have few or no individuals.
From the table in the attached image, it can be seen that
the variance= sum of (x - 0.6)^2/ sum of frequency
= 362.88/288
= 1.26
Variance/mean = 1.26/0.6 = 2.1 which is greater than 1
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Knowledge Check Find the greatest common factor of these two expressions. 18y^(7)w^(2)u^(8) and 30y^(5)w^(4) 6 Exponent 13
The greatest common factor of the two expressions 18y^(7)w^(2)u^(8) and 30y^(5)w^(4)u^(6) is 6y^(5)w^(2)u^(6).
The greatest common factor (GCF) of two expressions is the largest expression that divides both of the expressions. To find the GCF of the two expressions 18y^(7)w^(2)u^(8) and 30y^(5)w^(4)u^(6), we need to find the highest power of each variable that divides both expressions.
The GCF of the coefficients 18 and 30 is 6.
The highest power of y that divides both expressions is y^(5).
The highest power of w that divides both expressions is w^(2).
The highest power of u that divides both expressions is u^(6).
So, the GCF of the two expressions is 6y^(5)w^(2)u^(6).
Therefore, the greatest common factor of the two expressions 18y^(7)w^(2)u^(8) and 30y^(5)w^(4)u^(6) is 6y^(5)w^(2)u^(6).
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Consistent and Dependent Consistent and Independent Inconsistent y=-x+1 y=-x y=x+2 y=x y=x y=2x 00*30:03
The first system is inconsistent, the second system is consistent and dependent, and the third system is consistent and independent.
A system of equations can be classified as consistent, dependent, or inconsistent. A consistent system has at least one solution. A dependent system has infinitely many solutions, and an inconsistent system has no solution.
The first system of equations, y=-x+1 and y=-x, is inconsistent. This is because there is no value of x that can make both equations true at the same time. The graphs of these equations would be parallel lines that never intersect, meaning there is no solution.
The second system of equations, y=x+2 and y=x, is consistent and dependent. This is because there are infinitely many solutions that make both equations true. The graphs of these equations would be the same line, meaning every point on the line is a solution.
The third system of equations, y=x and y=2x, is consistent and independent. This is because there is only one solution that makes both equations true. The graphs of these equations would be two lines that intersect at one point, meaning there is only one solution.
In summary, the first system is inconsistent, the second system is consistent and dependent, and the third system is consistent and independent.
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3. Solve by factoring the equation 3x2 – 12x – 15 = 0 and explain what your solutions mean for the equation. Show your work.
The equation 3x² - 12x - 15 = 0 when solved by factoring has the solutions x = 5 and x = -1
How to get to the equation's solutionThe equation 3x² - 12x - 15 = 0, is a representation of the equation in the question.
The aforementioned problem is a quadratic equation, and factoring is one way to solve this kind of issue.
Divide 3 from the equation.
As a result, we have the following
x² - 4x - 5 = 0.
Expanding the equation, we get
x² + x - 5x - 5 = 0.
Factoring the equation, we get
x(x + 1) - 5(x + 1) = 0
The result is
(x - 5)(x + 1) = 0.
We can solve for x by getting
x = 5 and x = -1.
Thus, the equation's answers are 5 and -1.
And it means that there are actually two solutions to the equation.
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Camden multiplied two binomials and got the product of 49x^(2)-100. Find the two binomials that Camden must have multiplied.
The two binomials that Camden must have multiplied and got the product of 49x^(2)-100 are (7x+10) and (7x-10).
To find the two binomials that Camden must have multiplied to get the product of 49x^(2)-100, we can use the process of factoring. Factoring is the process of breaking down a larger expression into two or more smaller expressions that can be multiplied together to get the original expression.
One way to factor the expression 49x^(2)-100 is to look for two binomials that have a difference of squares. A difference of squares is an expression of the form a^(2)-b^(2), which can be factored into (a+b)(a-b).
In this case, we can see that 49x^(2) is a perfect square, as it is equal to (7x)^(2), and 100 is also a perfect square, as it is equal to 10^(2). Therefore, we can factor the expression 49x^(2)-100 into (7x+10)(7x-10).
So, the two binomials that Camden must have multiplied are (7x+10) and (7x-10).
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A certain map shows two roads. Road A is 1 1/5 miles long but is 1 1/2 inches long on the map. What is the unit rate for inches per mile on this map? If road B is 12 miles long, how long is road B on the map?
The unit rate for inches per mile is 0.8 inches.
The length of road B is 9.6 inches on map.
What is Unit rate?Unit rate is the ratio of two different units, with denominator as 1. For example, kilometer/hour, meter/sec, miles/hour, salary/month, etc.
Road in inches = 1 1/5 = 6/5 inches
Road in miles = 1 1/2 miles =
Inches per mile = 6/5 / (3/2)
= 6/5 x 2/3
= 4/5
= 0.8 inches
If the road B is 12 miles long, on the map it would be;
= 0.8 x 12
= 9.6 inches
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Natalie has three pairs of pants 10 black and blue and five shirts white black green blue and red each morning she randomly select a pair of pants and one shirt the following tree diagram represents the sample space for this count compound event outcomes may be listed using an ordered pair for example tan pants and red shirt can be listed as tan and red hey how many total outcomes are in a sample space be a list of favourable outcomes for a Natalie selecting a pair of pants and shirt that are the same colour see select the favourite outcomes for Natalie selecting a black shirt the list of favourable outcomes that Natalie selecting a list of blue article of clothing
Based on the given information, the sample space for the event can be represented using a tree diagram, where the first level consists of the three pants (black, blue, and tan) and the second level consists of the five shirts (white, black, green, blue, and red). Each branch represents a possible combination of a pair of pants and a shirt.
To find the total number of outcomes in the sample space, we can simply multiply the number of options for pants (3) by the number of options for shirts (5), giving us a total of 15 possible outcomes.
For Natalie selecting a pair of pants and shirt that are the same color, the favourable outcomes would be the combinations where the pants and shirt are either both black or both blue. These can be listed as:
Black pants and black shirt
Blue pants and blue shirt
For Natalie selecting a black shirt, the favourable outcomes would be the combinations where the shirt is black. These can be listed as:
Black pants and black shirt
Blue pants and black shirt
Tan pants and black shirt
For Natalie selecting a blue article of clothing, the favourable outcomes would be the combinations where either the pants or the shirt (or both) are blue. These can be listed as:
Black pants and blue shirt
Blue pants and white shirt
Blue pants and black shirt
Blue pants and green shirt
Blue pants and blue shirt
Tan pants and blue shirt