Answer:
-25ºC
Explanation:
A ball accelerates uniformly at +4.0 m/s2
If the ball was initially moving a +0.20 m/s and the average velocity was +4.2 m/s, then how long will it take it to reach the final velocity?
It will take 1 second to reach the final velocity
Acceleration of a body is the change in velocity of the body with respect to time. This is mathematically represented as;
[tex]a=\frac{v-u}{t}[/tex]
Given the following parameters
a = +4.0 m/s²
u = +0.20m/s
v = +4.2m/s
Substitute the given parameters into the formula to get the time "t"
[tex]4=\frac{4.2-0.2}{t}\\4t=4.2-0.2\\4t=4.0\\t=\frac{4}{4}\\t=1sec[/tex]
This shows that it will take 1 second to reach the final velocity
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how can you reduce the percentage uncertainty in measurements that you make?
Answer:
you can decrease the uncertainty by making the same measurement multiple times and taking the average.
Explanation:
Help if u understand for a b c
Golf cart is moving 8 metre in 1 second
so, in 10 seconds it moves 8 × 10 = 80 m
a) velocity = 80/10 = 8 m/s
b) acceleration = v - u / t
= 8 - 0 / 10
= 0.8 m/s²
c) the displacement of the graph is increasing
I hope this answer is correct and helpful to you
A student drops a ball off the top of building and records that the ball takes 2.55s to reach the ground. Determine all unknowns and answer the following questions. Neglect drag.
The unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
The given parameter;
time of motion of the ball, t = 2.55 sThe equations that model the motion of the ball is given as follows;
[tex]h = v_0_y + \frac{1}{2} gt^2[/tex]
[tex]v_f = v_0_y + gt[/tex]
All the unknown variables in the equations include;
[tex]v_0_y[/tex] is the initial vertical velocity of the ball, = 0g is the acceleration due to gravity = 9.8 m/s²h is the vertical distance traveled by the ball = ?[tex]v_f[/tex] is the final velocity of the ball = ?The vertical distance traveled by the ball is calculated as follows;
[tex]h = \frac{1}{2} gt^2\\\\h = 0.5 \times 9.8 \times 2.55^2\\\\h = 31.86 \ m[/tex]
The final velocity of the ball is calculated as follows;
[tex]v_f = 0 + 9.8(2.55)\\\\v_f = 25 \ m/s[/tex]
Thus, the unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
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Use the velocity vs time graph to analyze the motion of the object.
Explanation:
the object has constant velocity for 2 seconds and it get a constant accelration (2ms-2)
List the three main regions of the cells in the human body. Describe the main functions of each region.
A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal
We have that for the Question "A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the book is
F=44N
From the question we are told
A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal
Generally the equation for the Force is mathematically given as
[tex]F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\[/tex]
F=44N
Therefore
the minimum force that must be applied on the book is
F=44N
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what are the intermolecular forces present in water?
123456789 cari aja sendiri
Answer:
The main intermolecular forces present in water is hydrogen bond.
It is followed by,
Dipole-dipole attractions
Dipole-induced dipole attractions
London dispersion forces
The hydrogen bonds are the strongest force, but the other types of intermolecular attraction are still present.
What did Dr Allan McInnes say was required in order to launch a satellite into space, at the necessary altitude and speed? What is required and why?
According to this graph, the acceleration
is approximately:
Velocity (m/s)
MN
0
1 2 3 4
Time t(s)
5
A. 4 m/s2
B. 2 m/s2
C. 1 m/s2
D. 3 m/s2
Answer:
1 m/s^2
Explanation:
a=(v-u)/t
where,
a=acceleration
v=final velocity
u=initial velocity
(4.5-0)/4.5
1 m/s^2
quỹ đạo chuyển động của vật là đường thẳng?
Explanation:
what is your language i don't no
Using parallax, what is the distance to the
farthest stars you can measure?
Two coins, made of different material, are placed next to each other so that they are touching. Both coins are 15mm in diameter. One coin has a mass of 6.5 g and the gravitational force between the coins is 4.03 × 10^-11 N
The mass of the second coin for the given gravitation force is 20.9 g.
The given parameters;
distance between the two coins, r = 15 mm = 0.015 mmass of one coin, m₁ = 6.5 g = 0.0065 kggravitational force between the coins = 4.03 × 10⁻¹¹ NThe mass of the second coin is determined by applying Newton's law of universal gravitation as shown below;
[tex]F = \frac{Gm_1 m_2 }{R^2} \\\\m_2 = \frac{FR^2}{Gm_1} \\\\m_2 = \frac{(4.03 \times 10^{-11}) \times (0.015)^2}{(6.67 \times 10^{-11}) \times (0.0065)} \\\\m_2 = 0.0209 \ kg\\\\m_2 = 20.9 \ g[/tex]
Thus, the mass of the second coin for the given gravitation force is 20.9 g.
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A murder has been committed and you are a juror at the trial. The prosecuting attorney has presented evidence that the victim put up a struggle and injured her assailant, drawing blood, prior to her demise. Blood typing was completed and the blood type matches the defendant's blood type. The prosecuting attorney states that this evidence is proof that the defendant is guilty of murder. As a juror, do you think the defendant is guilty of murder based on this evidence? Why or why not? If not, what other evidence do you think is needed?
The fact that the blood type matches that of the defendant is no proof that the defendant is guilty as charged.
There are about four blood types that people can have, these blood types are; A, B, AB and O. Everybody must posses one of these blood types. A person's blood type is determined through laboratory tests.
The prosecuting attorney was wrong in concluding that the defendant is guilty as charged only based on the blood type evidence. different people could have the same blood type. Only DNA analysis can conclusively prove that the defendant is actually guilty as charged.
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A book is to be produced with pages of thickness 0.125mm.If the book is to be exactly 1cm thick what is the maximum number of pages it can contain?
Answer:
1cm=10mm
10cm/0.125mm
80pages
A 130 N horizontal force keeps a 30 kg chair moving at a constant velocity. Find the coefficient of kinetic friction between the chair and the floor.
The coefficient of kinetic friction between the chair and the floor is 0.44.
Given the following data:
Horizontal force = 130 NMass of chair = 30 kgWe know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]
To find coefficient of kinetic friction between the chair and the floor:
Mathematically, the coefficient of kinetic friction between two objects is given by the formula;
[tex]u = \frac{F_k}{mg}\\\\u = \frac{130}{30[9.8]}\\\\u = \frac{130}{294}[/tex]
Coefficient of kinetic friction, u = 0.44.
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A 89 kg object is suspended from 2 cables, with an angle of 120 degrees between them. What is the
tension on each cable? (Assume each cable is at an equal angle above the horizontal) Answer in
Newtons.
→ The tension on the cable is 890 N.
The free body diagram is drawed below. Applying the second law of newton:
(you have to transpose the T forces to the 'y' axis). After that:
[tex]\Large \text {$2Tcos(60) = 89 \times 10$}[/tex]
89 x 10 is the Weight Gravitational force (Mass times gravity). Therefore:
[tex]\Large \text {$T = 890$ N}[/tex]
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What experiment determines the upper fixed point of a liquid in a glass thermometer
Explanation:
A flask is half filled with water and heated until the water starts boiling.A thermometer is clamped inside the flask without letting it be in contact with waterThe thermometer is left in the steam such that the bulb is heated by the steam at standard atmospheric pressure.As the bulb is heated, the mercury thread rises up and ehre it remains steady for sometime is marked with a light scratch as the upper fixed point(Add diagram )
Push the skateboard and the box with a force of 500N. Observe and describe the behavior of the velocity once the skateboard is released?
Answer:
Force and Motion - Word ACROBAT w otion" Applied Force O Newtons DD -500 500 Net Force Motion Friction Acceleration I
2. Select the checkboxes: Forces, Values, Masses and Speed Force Values Masses Speed 3. Push the skateboard and the box with a force of 500N. Observe and describ behavior of the velocity once the skateboard is released Explain the reason of such behavior Part III. Friction 1. Click on "Friction" 2. Select the checkboxes: Forces, Sum of Forces, Values, Masses and Speed. Kee the knob that regulates the friction at the center of the scale. Forces Sum of Forces Values Masses
3. Start to push the box, increasing the force applied on the box slowly. There is a force that is opposite to the force you are applying. What is the name of the force opposing to the motion? 4. Once the box start moving, the magnitude of the resultant force increase instantaneously. How do you explain that? 5. Push the box and find the force needed to make the box to start moving. Add more mass (box, kid, man,refrigerator, basket as needed) and repeat the procedure such that you complete the table below. Hint: Weight = mass x gravity Magnitude of Normal Force = Magnitude of the Weight Mass (kg) Weight (N) Normal Force (N) Force of Static Friction (N) 50 90 130 150 180 x 0 N
Explanation:
The forces act on skateboard when we push it are , external force of 500N and friction force because of the surface.
What is the Newton's First law of motion?The stationary object will remain stationary or the subject in the motion will keep its motion until or unless the external force is not applied .
What will happen when we apply 500 N external force to the skateboard?We know the only force which is going to oppose the applied 500N force is the friction force due to surface.First as we will apply the external force the skateboard and the box will start gaining the velocity and the accelerationAfter some time because of the friction force the skateboard and the box will start losing its velocity because of the friction force and the combined mass they are having and at the end it will stop moving forward. it is also depends on their mass also.If we put different types of objects on the skateboard then the time period of lost of velocity will be different .If we put object having more mass then the combined system (skateboard + object ) will start losing its velocity quickly . and visa versa for the object having less mass.So, by the Newton's first law of motion we can understand this concept.
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what happens to kinetic energy as speed doubles and mass doubles
Answer:
If you double the mass of an object, you double the kinetic energy. If you double the speed of an object, the kinetic energy increases by four times. Kinetic energy can be passed from one object to another in the form of a collision....What happen to the kinetic energy of its velocity become double ? The energy possessed by a body because of its motion, equal to one half the mass of the body times the square of its speed is called its kinetic energy. Hence, when velocity is doubled, kinetic energy becomes 4 times.
Explanation:
Answer: It increases by four times
Explanation: If you double the mass of an object, you double the kinetic energy. If you double the speed of an object, the kinetic energy increases by four times. Kinetic energy can be passed from one object to another in the form of a collision.
physics
what are the two correct choices??
choice1
- insulating
- neutral
- large
- conductive
choice2
- potential energy
- potential difference
- charge
- electric potential
Answer:
3 and 2
May be
ok may be subscribeIsenberg Isenberg Ignatius
Which of the following is not a property of Newton’s Second Law?
a. The acceleration of the object is directly proportional to
the force acting on the object
b. The acceleration of the object is inversely proportional to
the mass of the object
c. The object moves in the same direction as the force acting
on the object.
d. There is no relationship between acceleration to force or
mass.
Answer:
La aceleración
del objeto
es directamente proporcional a la fuerza que actúa sobre el objeto
Explanation:
Which statement is true about vectors?
Answer:
Vectors are defined as quantities which are fully described by both their magnitude and direction. By definition, a vector has a direction associated with it.
Explanation:
is this what you want?
Which of the following best defines the definition of a Newton (N)? *
0/1
The amount of force that would give a mass of one kilogram an acceleration of one meter per second per second
Kg * m/s².
Both answers above are correct.
A cookie with a fig fruit filling
One Newton can be defined as the amount of force that would give a mass of one kilogram an acceleration of one meter per second per second.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
A spring balance can be used to calculate the Force. Newton is the SI unit of force.
From Newton's second law of motion: we know that:
Force = mass × acceleration
Now in SI system:
Unit of force is Newton.
Unit of mass is kg and unit of acceleration is meter per square second.
Hence, one Newton force can be defined as:
The required force to generate 1 meter per square second acceleration on an object of mass one kilogram.
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draw the well labelled diagram of thermo flask.
Answer:
Here the answer is attached
Explanation:
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A person pushes a 11.5KG lawn mower with an applied force of 70.0N along the 45.0-degree-handle. if the lawn mower moves at a constant velocity
Determine the net force on the mower:
Fnet=__N
Determine the horizontal component of applied force on the mower:
Fx=__N (round to 3 digits)
Determine the horizontal frictional force acting on the mower
Ff=__N (Round to 3 digits)
Calculate the applied force the person must exert on the mower for it to accelerate at a rate of 1.00m/s^2
F=__N (round to 3 digits)
Force is a vector quantity hence it can be resolved into a vertical and a horizontal components.
1) The horizontal component of the applied force is given by;
Fnet = F cos θ
Fnet = 70.0N × cos (45.0)
Fnet = 49.5 N
2) The horizontal component of the frictional force is;
F = -Ff + mgsinθ
F = applied force
Ff =mgsinθ - F
Ff = (11 × 10 × sin 45) - 49.5
Ff = 28.3 N
Horizontal component of Ff
28.3 N cos 45 = 19.9 N
3) The applied force is given by;
F = 11 Kg × 1.00m/s^2 = 11.0 N
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If the mass of an object is 176 and Net force is 50, what would be the Acceleration?
Answer:
0.28m/s²
Explanation:
Force = mass•acceleration
F = m•a
50 = 176•a Divide both sides by 176:
50/176 = a ≈ 0.28 m/s²
A large bottle contains a number of medicinal tablets is 0.5kg. Calculate the number of tablets in the bottle?
Answer:
the answer is 5k in the bottle have
a football quarterback throws a football. after it leaves his hand, what forces are acting on the football? choose all that apply.
golekeeper
Explanation:
because they use hand to save keeper
The horizontal surface on which the block of mass 2.2 kg slides is frictionless. The force of 27 N acts on the block in a horizontal direction and the force of 81 N acts on the block at an angle as shown below is the magnitude of the resulting ac celeration of the block? The acceleration of gravity is 9.8 m/s ^ 2
The magnitude of the resulting acceleration of the block is 6.14 m/s².
The given parameters;
mass of the block, m = 2.2 kghorizontal force on the block, F = 27 Nforce below the horizontal, 81 N at 60⁰The net horizontal force on the block is calculated as follows;
[tex]F_x = 27 \ - 81 \times cos (60)\\\\F_x = -13.5 \ N[/tex]
The acceleration of the block is calculated as follows;
[tex]a = \frac{-13.5}{2.2} \\\\a = - 6.14 \ m/s^2\\\\a = 6.14 \ m/s^2 \ to \ the \ left[/tex]
Thus, the magnitude of the resulting acceleration of the block is 6.14 m/s².
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