The composition is three number of atoms in each sample.
How to determine the composition of atoms in a sample?The number of samples that was given include the following:
Water (H2O) : This sample is made up of three number of atoms but contains only two elements of oxygen and hydrogen in a ratio of 1:2 respectively.
Carbondioxide (CO2) : This sample is made up of three number of atoms but contains only two elements of carbon and oxygen in a ratio of 1:2.
Sugar (CHO) : This sample is made up of three number of atoms but contains three elements of carbon, oxygen and hydrogen in a ratio of 1:1:1.
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Three friends were talking about carbon dioxide and oxygen in the
ecosystem. They each had different ideas. This is what they said:
Flynn: I think animals take in oxygen and breathe out carbon dioxide.
Plants then take in the carbon dioxide and release oxygen, and the
cycle continues.
Jervis: I think both plants and animals take in oxygen and release carbon
dioxide; but only the plants take in the carbon dioxide and release
oxygen, and the cycle continues.
Melody: I think both plants and animals take in oxygen and release carbon
dioxide. The oxygen is used up and carbon dioxide is not cycled
again by living things.
Circle the name of the friend you agree with the most. Explain why you
agree. Describe your ideas about the cycling of matter.
The friend whose statement I agree with most about the cycling of carbon dioxide and oxygen in the ecosystem is Flynn.
Carbon dioxide and oxygen in the ecosystemI agree with Flynn's statement about the cycling of carbon dioxide and oxygen in the ecosystem.
Animals do indeed take in oxygen and release carbon dioxide during respiration, while plants take in carbon dioxide and release oxygen during photosynthesis. This process of exchanging gases between plants and animals is known as the carbon cycle, which is crucial for the survival of all living things.
The carbon cycle ensures that there is a balance between the amount of carbon dioxide in the atmosphere and the amount that is used up by living organisms. In addition, the cycling of other nutrients such as nitrogen and phosphorus is also important for the functioning of the ecosystem.
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A sample of N2 has 1.70 moles and occupies 3.80 L at 25°C. How many moles are in a sample that occupies 1.45 L? Answer should be numbers only, no units, to 2 decimal places
The concept Avogadro's law is used here to determine the moles of gas present in the sample. Avogadro's law is also known as the Avogadro's principle or Avogadro's hypothesis. It is closely related to the ideal gas equation.
According to Avogadro's law, equal volumes of all gases under similar conditions of temperature and pressure contain equal number of molecules. It follows that the volume of the gas is directly proportional to the number of molecules.
The equation is:
V₁n₁ = V₂n₂
n₂ = V₁n₁ / V₂
3.80 × 1.70 / 1.45 = 4.45
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Explain why a paper airplane thrown in a straight line from Chicago to Orlando would not reach its destination.
Answer: Gravity
Explanation:
A paper airplane in flight will experience an initial thrust forward which begins its flight and lift from air which will help push it upward. These forces are counteracted by drag that acts in the opposite direction as thrust and gravity which will constantly pull the plane toward the ground. Gravity will pull the paper airplane down before it travels to Orlando.
50 points, and I’ll mark as brainliest!!!
Problem 1. Sea water contains dissolved salts at a total ionic concentration of about 1.13 mol×L–1. What pressure must be applied to prevent osmotic flow of pure water into sea water through a membrane permeable only to water molecules (at 25oC)?
Problem 2. What is the osmotic pressure of a solution prepared by adding 6.65 g of glucose to enough water to make 350 mL of solution at 35°C?
Problem 3. What is the osmotic pressure of a solution prepared by adding 9.0 g of glucose to enough water to make 450 mL of solution at 35°C?
Problem 4. What is the osmotic pressure of a solution prepared by adding 11.0 g of propanol to enough water to make 850 mL of solution at 25°C?
Problem 5. What is the osmotic pressure of a solution prepared by adding 65 g of glucose to enough water to make 35000 mL of solution at 15°C?
Answer:
Problem 1:
The osmotic pressure, π, can be calculated using the formula:
π = iMRT
where i represents the van't Hoff factor (the number of particles into which a solute dissociates), M represents the molar concentration, R represents the gas constant (0.082 Latm/molK), and T is the temperature in Kelvin.
The osmotic pressure of pure water is 0. As a result, sea water's osmotic pressure must be equal to the pressure necessary to prevent osmosis.
Assuming that sea water is an ideal solution, the total dissolved ion concentration is 1.13 mol/L. Because each dissolved salt molecule dissociates into two ions, the effective particle concentration is 2.26 mol/L.
Filling in the blanks in the formula:
0.918 atm = (2)(2.26 mol/L)(0.082 Latm/molK)(298 K)
Therefore, a pressure of 0.918 atm must be applied to prevent osmotic flow of pure water into sea water.
Problem 2: Glucose has a molar mass of 180.16 g/mol. The solution contains the following number of moles of glucose:
n = 6.65 g / 180.16 g/mol = 0.0369 mol
The molarity of the solution is:
M = n / V = 0.0369 mol / 0.350 L = 0.105 M
Substituting the values into the formula:
π = iMRT = (1)(0.105 M)(0.082 L·atm/mol·K)(308 K) = 2.74 atm
As a result, the osmotic pressure of the solution is 2.74 atm.
Problem 3:
Following the same procedure as in Problem 2, the molarity of the solution is:
M = n / V = 0.02 mol / 0.450 L = 0.044 M
Substituting the values into the formula:
π = iMRT = (1)(0.044 M)(0.082 L·atm/mol·K)(308 K) = 1.14 atm
As a result, the osmotic pressure of the solution is 1.14 atm.
Problem 4:
The molar mass of propanol is 60.10 g/mol. The number of moles of propanol in the solution is:
n = 11.0 g / 60.10 g/mol = 0.183 mol
The molarity of the solution is:
M = n / V = 0.183 mol / 0.850 L = 0.215 M
Substituting the values into the formula:
π = iMRT = (1)(0.215 M)(0.082 L·atm/mol·K)(298 K) = 4.59 atm
Therefore, the osmotic pressure of the solution is 4.59 atm.
Problem 5:
Following the same procedure as in Problem 2, the molarity of the solution is:
M = n / V = 65 g / (180.16 g/mol × 35 L) = 0.104 M
Substituting the values into the formula:
π = iMRT = (1)(0.104 M)(0.082 L·atm/mol·K)(288 K) = 2.06 atm
Therefore, the osmotic pressure of the solution is 2.06 atm.
PLEASE ANSWER SOON AS POSSIBLE
What is the volume, in liters, of 1.20 mol of C3H8 gas at STP
26.8L is the volume, in liters, of 1.20 mol of C[tex]_3[/tex]H[tex]_8[/tex] gas at STP. A measurement of three-dimensional space is volume.
A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic metre or litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship.
The volume of an envelope is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the quantity of fluid (liquid or gas) that the container may hold.
Volume = 1.20×22.4
=26.8L
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In the electrolysis of water, how many coulombs of charge are needed to produce 1.50 L of oxygen at 25.0 °C and 1.00 atm pressure? (F = 96500 C/mol)
Answer in C
The electrolysis of water has the following balanced equation:
[tex]O_2(g) = 2H_2O(l) + 2H_2(g)[/tex]
According to the equation, it takes 2 moles of electrons to generate 1 mole O2.
The Faraday constant, F, which represents the charge carried by 1 mole of electrons, must be used to calculate the amount of charge needed to produce a specific amount of O2. The value of F is 96500 C/mol.
Using the Ideal Gas Law, we must first determine how many moles of O2 are formed from 1.50 L of O2 gas at 25.0 °C and 1.00 atm pressure:
PV = NRT
n = (PV)/(RT) = 1.00 atm/1.50 L/[(0.0821 lat/(molK)](298 K)]
= 0.0607 mol
Therefore, 0.0607 moles of O2 are formed.
We need 2 moles of electrons, or 2 x 0.0607, or 0.1214 moles, because 1 mole of oxygen requires 2 moles of electrons.
Finally, we can use the Faraday constant to determine the required charge:
Q = Nf = 0.1214 mol, 96500 C/mol, or 11700 C
Therefore, 11700 coulombs of charge are needed to produce 1.50 L of oxygen at 25.0 °C and 1.00 atm pressure.
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What is the pressure, in atm, in a 4.00 L tank with 5.15
moles of nitrogen at 69.6 °C?
The pressure in atm, in a 4.00 L tank with 5.15 moles of nitrogen gas at 69.6˚C is 36.18 atm.
According to the ideal gas law,
PV = nRT
Here,
Volume (V) = 4.00 L
Number of moles (n) = 5.15 mol
Temperature (T) = 69.6 ˚C = 69.6+273.15 = 342.75 K
Universal gas constant (R) = 0.082 L atm mol-1 K-1
Pressure (P) = ?
Therefore, mathematically
P × 4.00 = 5.15 × 0.082 × 342.75
P = [tex]\frac{(5.15)(0.082)(342.75)}{4.00}[/tex]
P = [tex]\frac{144.74}{4.00}[/tex]
P = 36.18 atm
The pressure in atm, in a 4.00 L tank with 5.15 moles of nitrogen gas at 69.6˚C is 36.18 atm.
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How many moles of KBr are dissolved in 60.2 mL of a 3.50 M solution?
There are 0.2107 moles of KBr are dissolved in 60.2 mL of a 3.50 M solution.
The molarity of a substance is defined as the number of moles of solute present in 1 litre of a solution.
According to the given data, the molarity of the solution tells us that there are 3.50 moles of KBr in 1000mL of solution. But we only have 60.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 60.2mL:
1000 ml - 3.50 moles
60.2 ml -x = 60.2 ml× 3.50 moles/1000 ml
x= 60.2 ml -0.2107 moles
So, there are 0.2107 moles of KBr.
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6. What happens to a substance at critical temperatures?
O A. The substance can't change its state, only its temperature.
O B. The substance changes its state if it continues gaining or losing thermal energy.
O C. The substance can't lose any more thermal energy.
O D. The substance changes its state only if it gains thermal energy.
At critical temperatures, B. The substance changes its state if it continues gaining or losing thermal energy.
What is the critical temperature of a given substance or material?The critical temperature of a given substance or material refers to the temperature above which vapor cannot be liquefied, which is also known as the critical point of the material.
Therefore, with this data, we can see that the critical temperature of a given substance or material is a given temperature above the critical point of such material and it is related to its vapor state.
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Pentane is a liquid and its formula is C3H₁2(1). When pentane reacts with
oxygen gas, it produces water and carbon dioxide gas. The enthalpy of this reaction is
-3,510 kJ. Write a correct thermochemical equation for this reaction, explain how you
came up with this equation, and explain what it tells you about the reaction. Make sure to
balance the chemical equation, include states of matter for each substance, and explain
why the enthalpy of the reaction is negative to earn full credit.
The balanced thermochemical equation for the reaction of pentane (C5H12) with oxygen gas (O2) to produce water (H2O) and carbon dioxide (CO2) is:
C5H12 (l) + 8 O2 (g) → 5 CO2 (g) + 6 H2O (l) ΔH = -3,510 kJ
The equation is balanced by making sure there are equal numbers of atoms of each element on both the reactant and product sides of the equation. The states of matter are included in the equation to show the physical state of each substance, with (l) indicating a liquid and (g) indicating a gas.
The negative value of enthalpy (ΔH) indicates that this reaction is exothermic, meaning that it releases heat to the surroundings. In other words, the products of the reaction have a lower enthalpy than the reactants. This can be explained by the fact that the bonds formed between carbon and oxygen in CO2 and between hydrogen and oxygen in H2O are stronger than the bonds broken between carbon and hydrogen in C5H12 and between oxygen atoms in O2. The excess energy is released in the form of heat, resulting in a negative value for ΔH.
Ammonia, which is used as a fertilizer, is made by combining nitrogen from the air with
hydrogen. The hydrogen is produced by reacting methane (CH4) with water. If you have 249
grams of methane, how much hydrogen will be produced and how much water will you
need to convert all of the methane to hydrogen?
The hydrogen is produced by reacting methane (CH4) with water. If you have 249 grams of methane, 45gram is the mass of hydrogen will be produced.
A body's mass is an inherent quality. Prior to the discoveries of the atom & particle physics, it was widely considered to be tied to the amount of matter within a physical body. It was discovered that, despite having a comparable amount of matter in theory, different atoms and elementary particles have varied masses.
There are various conceptions of mass in contemporary physics that are theoretically different but physically equivalent. The resistance of the body to deceleration (change of velocity) whenever a net force is applied can be measured experimentally as mass.
CH[tex]_2[/tex] + H[tex]_2[/tex]O →CO + 3H[tex]_2[/tex]
moles of methane = 249/16.043= 15.5moles
moles of hydrogen = 15.5×3 = 45moles
mass of hydrogen =45×1=45gram
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How many grams of Kr are in a 7.24 L cylinder at 14.7 and 7.77 atm? mass:
There are approximately 4.86 grams of Kr in the cylinder.
To calculate the number of grams of Kr in a cylinder, we need to use the ideal gas law:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.
First, we need to convert the volume from liters to cubic meters:
7.24 L = 0.00724 m³
Next, we can use the two pressures and volumes to calculate the number of moles of Kr:
n₁ = (14.7 atm × 0.00724 m³) ÷ (8.31 J/(molK) × 298 K)
n₁ = 0.038 mol
n₂ = (7.77 atm × 0.00724 m³) ÷ (8.31 J/(molK) × 298 K)
n₂ = 0.020 mol
The total number of moles of Kr in the cylinder is:
n = n₁ + n₂
n = 0.038 mol + 0.020 mol
n = 0.058 mol
Finally, we can use the molar mass of Kr (83.80 g/mol) to convert the number of moles to grams:
m = n × M
m = 0.058 mol × 83.80 g/mol
m = 4.86 g
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How many grams of KBr are dissolved in 72.7 mL of a 0.998 M solution?
8.63 grams of KBr are dissolved in 72.7 mL of a 0.998 M solution.
To answer first we need to calculate the molar mass of this molecule (KBr):
For this we go to the periodic table and check the molar weight of potassium and bromine:
K: 39.098 g/mol
Br: 79.904 g/mol
So the molar mass of KBr is
= 39.098 g/mol + 79.904 g/mol
=119 g/mol
Now, we know that the solution is 0.998 M, this means that in 1000 ml there are 0.998 moles of KBr. So we calculate the number of moles in 72.7ml:
number of moles of KBr
= 72.7 ml × 0.998 molL⁻¹/ 1000 mlL⁻¹
=0.0725 moles
Now we use the molar mass to calculate the mass in grams in the sample:
mass of KBr
= 0.0725 moles ₓ 119 g/mol
=8.6275 g
≈8.63 g
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Find the oxidation number P in Ca3(PO4)2 step by step
Answer: The oxidation number P in Ca3(PO4)2 is +1
Explanation:
To find the oxidation number of P in Ca3(PO4)2, we need to use the following rules:
The oxidation number of an atom in its elemental form is always 0.
The oxidation number of a monatomic ion is equal to its charge.
The sum of the oxidation numbers of all atoms in a neutral compound is 0.
The sum of the oxidation numbers of all atoms in a polyatomic ion is equal to the charge of the ion.
Let's start with Ca3(PO4)2:
The oxidation number of Ca is +2. This is because Ca is an alkaline earth metal and tends to lose 2 electrons to form a 2+ ion.
The oxidation number of O is -2. This is a common rule for oxygen in most compounds.
We don't know the oxidation number of P yet, so let's call it x.
Now we can use rule 3 to set up an equation:
3(2+) + 2x + 4(-2) = 0
Simplifying, we get:
6 + 2x - 8 = 0
2x - 2 = 0
2x = 2
x = +1
Therefore, the oxidation number of P in Ca3(PO4)2 is +1.
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What is the pH of a substance if it has a [H]=0.68?
Dwight made this model using a golfball, a baseball, and a basketball
How could Dwight improve his model?
Group of answer choices
Make the moon smaller than the earth
Place the sun between the Earth and the moon
Place Earth between the moon and the sun
Use a flat object, such as a coin, to represent the objects
He could improve the model if he place Earth between the moon and the sun.
What is the model?We know that the solar system is composed of the sun and the planets and we can have a model of the solar system when we get together the sun and the other parts of the solar system as has been done in the model that was put together by Dwight .
Since the model was intended to show the eclipse of the moon then the model can be improved if he place Earth between the moon and the sun in the image of the model
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A small amount of chemical splashes in Frank’s eye. What should Frank do immediately?
Answer:
A small amount of chemical splashes in Frank's eye. What should happen next? Frank should go to the eyewash station while his lab partner tells the teacher what happened.
Explanation:
Brainlist
Draw all structural and geometric isomers of butene and name them
Alkene is an unsaturated hydrocarbon which contain at least one carbon-carbon double bond. Here butene is an alkene with the chemical formula C₄H₈. The functional group present in alkenes is the double bond.
The structural isomers are those isomers in which the atoms are completely arranged in a different order but have the same molecular formulas. It is also called the constitutional isomers.
Geometric isomers are two or more compounds with the same number and types of atoms and bonds but have different geometries for the atoms.
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7. Calculate the percent yield for CasP₂ from the theoretical yield from question #6 if you were able
to produce 0.11 moles CasP₂ in the lab.
The efficiency of a chemical reaction is measured as a percentage yield, which shows what fraction of the theoretical yield was actually obtained in the laboratory. It is calculated by multiplying by 100% and dividing the theoretical yield (the largest amount of product that can be obtained under perfect conditions) by the actual yield (amount of product obtained in the experiment).
The theoretical yield of CasP₂ from question #6 was calculated to be 0.143 moles.
To calculate the percent yield, we use the formula:
Percent yield = (actual yield/theoretical yield) x 100%
Substituting the given values:
Percent yield = (0.11/0.143) x 100%
Percent yield = 76.92%
Therefore, the percent yield of CasP₂ is 76.92%.
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Which of the following statements best describes how the space program improved the culture in Florida?
The space program changed the education system, increased tourism, and created technology to help people.
The space program decreased the amount jobs available for people living in Florida, allowing families to spend more time together.
The space program developed rockets that can go into space and clean the air, helping living things breathe.
The space program led to the development of monuments and exhibits, which draws thousands of tourists every year.
The statement that best described how the space program improved the culture in Florida is that the space program changed the education system, increased tourism, and created technology to help people.
Florida's culture and economy were significantly impacted by the space program. The impact on education was one of the most significant ways. Many young people were motivated to pursue STEM (science, technology, engineering, and mathematics) careers by the space program. This prompted the development of institutions and educational programs devoted to these fields, aiding in Florida's development of a highly skilled labor force.
The space program also increased tourism in Florida because people from all over the world traveled to Florida to see space launches and to visit the Kennedy Space Center. This increased employment opportunities and state revenue.
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Calculate the molarity of a solution that contains 0.031 mol K2SO4 in 622 mL of solution
The molarity of the solution which contains 0.031 mol of K₂SO₄ in 622 mL of solution is approximately 0.0499 M.
Molarity is commonly used to describe the concentration of solutions in various chemical reactions, including reactions in the laboratory, industry, and everyday life. It is an important concept in chemistry for quantifying the amount of a substance present in a solution and for calculating the amount of reactants needed in chemical reactions.
To calculate the molarity of a solution, we use the formula:
Molarity (M) = moles of solute/volume of solution in liters
Given; moles of K₂SO₄ = 0.031 mol
volume of solution = 622 mL = 622/1000 L = 0.622 L
Plugging these values into the formula;
Molarity (M) = 0.031 mol / 0.622 L ≈ 0.0499 M
Therefore, the molarity of the solution is 0.0499 M
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Calculate the number of nitrogen atoms in a container of volume 0.50 dm³ at 0 °C. The pressure of the gas is 101 Pa.
The number of nitrogen atoms in a container of volume 0.50 dm³ at 0 °C. The pressure of the gas is 101 Pa. is approximately 1.47 x 10^19 nitrogen atoms in the given container.
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
0.50 dm³ = 0.50 x [tex]10^-^3[/tex] m³
0 °C = 273 K
n = PV/RT
n = (101 Pa)(0.50 x [tex]10^-^3[/tex] m³) / [(8.31 J/mol K)(273 K)]
n = 0.0000244 mol
n = (0.0000244 mol)(6.02 x [tex]10^2^3[/tex]atoms/mol)
n = 1.47 x [tex]10^1^9[/tex] nitrogen atoms
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Suppose the concentration of Al3+ is 1.90 M and the concentration of Sn2+ is 0.25 M in a galvanic cell that operates at 25°C with the same electrodes as the One above. Would the cell potential, Ecell, under these conditions be greater than, less than, or equal to the standard cell potential, E° cell from part b?
Justify your answer.
Under these conditions, the cell potential, Ecell, would be somewhat lower than the usual cell potential, E°cell.
How to determine cell potential?To determine whether the cell potential, Ecell, would be greater than, less than, or equal to the standard cell potential, E°cell, use the Nernst equation:
Ecell = E°cell - (RT/nF)ln(Q)
where:
Ecell = cell potential under the given conditions
E°cell = standard cell potential
R = gas constant (8.314 J/(mol·K))
T = temperature in Kelvin (25°C = 298 K)
n = number of electrons transferred in the overall cell reaction
F = Faraday constant (96,485 C/mol)
Q = reaction quotient
The balanced equation for the cell reaction is:
2Al(s) + 3Sn₂⁺(aq) → 2Al₃⁺(aq) + 3Sn(s)
The cell reaction involves the transfer of 3 electrons, so n = 3.
At standard conditions (1 M concentration for all species and 25°C), the cell potential, E°cell, can be calculated using the standard reduction potentials for the half-reactions:
Al₃⁺(aq) + 3e- → Al(s) E° = -1.66 V
Sn₂⁺(aq) + 2e- → Sn(s) E° = -0.14 V
E°cell = E°(cathode) - E°(anode) = (-0.14 V) - (-1.66 V) = 1.52 V
To calculate Q, use the given concentrations of Al3+ and Sn2+:
Q = ([Al₃⁺]²/[Sn⁺]³) = (1.90 M)² / (0.25 M)³ = 231.2
Now use the Nernst equation to calculate Ecell under the given conditions:
Ecell = E°cell - (RT/nF)ln(Q)
Ecell = 1.52 V - [(8.314 J/(mol·K))(298 K)/(3 mol)(96,485 C/mol)ln(231.2)]
Ecell = 1.52 V - (0.012 V) = 1.508 V
Therefore, the cell potential, Ecell, under these conditions would be slightly less than the standard cell potential, E°cell. This is because the concentration of Al₃⁺ is higher and the concentration of Sn₂⁺is lower than the standard conditions, which shifts the reaction towards the side with lower concentration of Al₃⁺ and higher concentration of Sn₂⁺. This means that the reaction is not occurring under standard conditions and the Nernst equation must be used to account for the non-standard conditions.
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How do you prepare a solution of sugar 342g/mol. 0.45 in 50ml
The following steps can be used to make a sugar 342g/mol. 0.45 solution in 50ml: 1. Determine the amount of sugar necessary. This may be accomplished by applying the formula mass = molarity x volume.
In this situation, the needed sugar mass is 0.45 x 50 = 22.5 g. 2. Dissolve 50 mL of water in the estimated quantity of sugar. To achieve this, add the sugar to the water in a beaker and swirl until it is completely dissolved.
3. Make sure the solution is exactly 50 ml in volume. This can be accomplished by adding extra water to the solution as needed. 4. The sugar 342g/mol 0.45 solution in 50 ml is now ready for use.
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Question 5 of 10
A scientist needs to study blood cells for medical research. Why might a
computer model benefit the scientist?
A. Using the model will give more accurate study results.
B. The model would enable the scientist to see what the flow of
blood cells would look like when slowed down.
C. The blood cell is too large to study, and the model is smaller.
D. The model can be adjusted until the scientist gets the desired
results.
A computer model will benefit a scientist while studying the blood cells for medical research because that would enable the scientist to see how the flow of the blood cells will look like when it is slowed down and the correct option is option B.
Our blood contains a number of blood cells which are suspended in a liquid which is known as plasma. Blood cells are the constituents of blood and are of different types like Red blood cells (RBCs), white blood cells (WBCs), Platelets etc. Plasma contains about 92% water and the most abundant solutes present in it are the plasma proteins and they include globulins, albumins etc.
Computer models help us to observe blood and its components and can provide us more insights and observation into the blood flow as we are able to slow it down as per our convenience.
Thus, the ideal selection is option B.
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Chemistry balancing equations - Can this be solved???
find k given [S0₂ 2] =1.50 M, [O₂] = 1.25 M [SO₃] = 3.50 M 2 SO₂ + 1 O₂ ← →2 SO₃
The value of K is 4.4 represents the equilibrium position of the reaction under the given conditions.
The equilibrium constant (K) for a reaction is a constant value that relates the concentrations of the reactants and products at equilibrium. For the given reaction, the equilibrium concentrations of SO₂, O₂, and SO₃ are given as [SO₂] = 1.50 M, [O₂] = 1.25 M, and [SO₃] = 3.50 M, respectively.
The equilibrium constant (K) for the reaction can be calculated using the equilibrium concentrations of the reactants and products.
K = [SO₃]²/([SO₂]²[O₂])
K = (3.50)²/[(1.50)²(1.25)]
K = 4.48
Therefore, the equilibrium constant (K) for the reaction is 4.48.
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Why are alternative fuels called "green energy"?
O A. Their wavelengths are in the green part of the EM spectrum.
B. They produce energy in a more environmentally friendly way than
fossil fuels do.
C. They are not yet developed as useful energy sources, so they are
young, or "green."
D. The energy they produce comes from green plants and trees.
Alternative fuels are called "green energy" as their wavelengths are in the green part of the EM spectrum. Therefore, the correct option is option A.
Natural resources like sunshine, wind, rain, waves, plants, algae, and geothermal heat are used to produce green energy. These energy sources can be renewed naturally because they are renewable. Fossil fuels, in contrast, take many thousands of years to form & will continue to deplete as they are used.
Furthermore, compared to fossil fuels, which as a byproduct release greenhouse gases that contribute to climate change, renewable energy sources have a significantly smaller negative environmental impact. Alternative fuels are called "green energy" as their wavelengths are in the green part of the EM spectrum.
Therefore, the correct option is option A.
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A steel bar and a copper bar have the same length of 1.500 m at -12.00 ∘C.
What is the difference in the lengths of the two bars at 41.0 ∘C ?
Express your answer in millimeters.
The difference in lengths between the steel and copper bars at 41.0°C is 8.729 mm.
The difference in the lengths of the two bars can be calculated using the linear expansion equation;
ΔL = α × L × ΔT
where; ΔL = Difference in length
α = Coefficient of linear expansion
L = Initial length
ΔT = Change in temperature
Given; Initial length (L) = 1.500 m
Change in temperature (ΔT) = 41.0°C - (-12.0°C) = 53.0°C
The coefficient of linear expansion for steel is typically around 11 x 10⁻⁶ /°C, and for copper, it's around 16 x 10⁻⁶ /°C.
For the steel bar;
α (steel) = 11 x 10⁻⁶ /°C
For the copper bar;
α (copper) = 16 x 10⁻⁶ /°C
Now we can calculate the difference in lengths for both bars.
For the steel bar;
ΔL (steel) = α (steel) × L × ΔT
ΔL (steel) = 11 x 10⁻⁶ /°C × 1.500 m × 53.0°C
For the copper bar;
ΔL (copper) = α (copper) × L × ΔT
ΔL (copper) = 16 x 10⁻⁶ /°C × 1.500 m × 53.0°C
Converting the length difference from meters to millimeters (1 m = 1000 mm):
ΔL (steel) = 11 x 10⁻⁶ /°C × 1.500 m × 53.0°C × 1000 mm/m = 8.729 mm (rounded to three decimal places)
ΔL (copper) = 16 x 10⁻⁶ /°C × 1.500 m × 53.0°C × 1000 mm/m = 12.168 mm (rounded to three decimal places)
Therefore, the difference in the lengths of the two bars will be 8.729 mm.
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Which one of the following would not be affected by boiling with aqueous sodium hydroxide?
A: ethyl ethanoate
B: glycerol
C: olive oil
D: propanoic acid
what is the answer and why? thanks!
Glycerol would not be affected by boiling with aqueous sodium hydroxide. The correct option is B
What is Glycerol ?Glycerol, usually referred to as glycerin, is a sticky liquid with a sweet taste that is frequently used in the manufacturing of food, medicines, and cosmetics. It is a triol, which is an alcohol since it has three hydroxyl (-OH) groups.
Therefore, Glycerol (option B) is a triol that lacks either a carboxylic acid group or an ester functional group. Since it doesn't react with aqueous sodium hydroxide, boiling it with it won't have any negative effects.
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5. If a beaker contains 15.6 moles of water, H2 O, how many molecules does this represent?
6. How many formula units of PbO are contained in 0.317 moles of lead (II) oxide?
7. 6.01 x 10 25 atoms of cesium, Cs, are equivalent to how many moles of cesium?
8. Determine the number of moles that are represented by 3.54 x 10 21 molecules of sulfur dioxide, SO2 .
If a beaker contains 15.6 moles of water, H[tex]_2[/tex]O, 9.3×10²⁴ are the number of molecules this represent.
The smallest recognisable unit into that a pure substance may be divided while retaining its composition & chemical properties is a molecule, which is a collection of more than one atom.
Until parts made up of individual molecules are reached, splitting of a sample of an item smaller progressively smaller parts does not result in a change regarding its composition as well as its chemical properties.
5.number of molecules= 15.6 × 6.022×10²³
=9.3×10²⁴
6. .number of molecules=0.317 × 6.022×10²³
=1.89×10²³
7. number of moles =6.01 x 10 25/ 6.022×10²³
= 100 moles
8. number of moles =3.54 x 10²¹/ 6.022×10²³
= 0.005moles
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