Answer:
The larger canister has 8 times the volume and 4 times the volume of the smaller one.
Step-by-step explanation:
The smaller canister has a diameter of 9 cm (radius = 4.5 cm) and height of 12 cm.
The larger canister has double the diameter and height of the smaller one. The diameter of the larger canister is 18 cm (radius = 9 cm) and height of 24 cm.
The canisters are in the shape of a cylinder.
The volume of a cylinder is given as:
[tex]V = \pi r^2h[/tex]
The surface area of a cylinder is given as:
A = 2πr(r + h)
SMALLER CANISTER
Volume = π * 4.5 * 4.5 * 12 = 763.41 cubic centimetres
Area = 2 * π * 4.5(4.5 + 12) = 2 * π * 4.5 * 16.5 = 466.53 square centimetres
LARGER CANISTER
Volume = π * 9 * 9 * 24 = 6107.26 cubic centimetres
Area = 2 * π * 9(9 + 24) = 2 * π * 9 * 33 = 1866.11 square centimetres
By reason of comparison, the larger canister has 8 times the volume and 4 times the volume of the smaller one despite having double the dimensions.
Answer:
Yeah, what they said above.
Step-by-step explanation:
graph itttt plssssss
━━━━━━━☆☆━━━━━━━
▹ Answer
You can use a graphing calculator. Attached is a picture of it graphed.
Hope this helps!
CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
HELP!! PLEASEE!
The graph f(x)=e^x-1+5 is shown below. g(x) is a transformation of f(x). How would you write the equation for the function g(x)?
Answer:
A
Step-by-step explanation:
The blue graph, g(x), is shifted down 8 units.
So the answer is f(x)-8 which is A
Answer: C. g(x) = eˣ⁻¹ - 3
Step-by-step explanation:
g(x) is a vertical shift 8 units down (-8) from f(x)
f(x) = eˣ⁻¹ + 5
g(x) = (eˣ⁻¹ + 5) - 8
= eˣ⁻¹ - 3
computer valued at $6500 in 2007 depreciates at the rate of 14.3% per year.
Answer:
Here,
initial price (p)=$6500
Time from 2007 to 2020 (t)= 13yrs.
rate (r)=14.3%
now,
[tex]present \: price \: (pt) = p(1 - \frac{r}{100} )[/tex]
or, pt = $6500(1-14.3/100)
by simplifying it we get,
The, present price is $5570.5.
now, if you are searching for depreciated amount only then,
depreciated amount =$6500-$5570.5
=$929.5.
Hope it helps...
12.
Find the values in the interval [-n/2, n] that satisfy the equation.
arctan (V3/3) = x
с
a. since tan (n/6) = 13/3, X = n/6
b. since sin (-1/4)= -V2/2, x = -1/4
c. since cos (3n/2) = -1/2, X = 3n/2
d. since cos 0 = 1, x = 0
e. since cos (1/4) = V2/2, X = n/4
13
Answer:
Step-by-step explanation:
[tex]tan^{-1} (\frac{\sqrt{3} }{3} )=x\\tan x=\frac{\sqrt{3} }{3} =tan (\frac{\pi}{6} )\\x=\frac{\pi}{6}[/tex]
Hurry please
What is the rule for the reflection?
Answer:
When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).
Step-by-step explanation:
Hope you understand
Answer this and I'll mark you the brainliest
if the polynomial x^4-3x^3-6x^2+kx-16 is exactly divisible by x^2+4x+3,find the value of k
Answer:
k = -18.
But See below.
Step-by-step explanation:
f(x) = x^4 - 3x^3 - 6x^2 + kx - 16
If x^2 + 3x + 2 is a factor then so is (x + 1) and (x + 2) as
x^2 + 3x + 2 = (x + 1)(x + 2)
So by the Factor Theorem f(-1) = 0:
f(-1) = (-1)^4 - 3(-1)^3 - 6(-1)^2 - 1k - 16 = 0
1 + 3 - 6 - k - 16 = 0
-18 - k = 0
k = -18.
Checking:
f(-2) = (-2)^4 - 3(-2)^3 - 6(-2)^2 - 18(-2) - 16
= 16 + 24 - 24 + 36 - 16 = 36 (NOT 0).
Answer:
k=11
explaination:
Please help ASAP. The graph of a quadratic function is shown. Which of the numbers below could be the discriminant of the corresponding quadratic equation? a) 10 b) -1 c) 0 d) none of the above
Answer:
a
Step-by-step explanation:
Since the graph intersects the x-axis at 2 points, it has 2 solutions which means that the discriminant is greater than 0. The only option that satisfies this is 10.
Answer:
10 option a)
Step-by-step explanation:
The discriminant has to be a number greater than zero, since we clearly see two solutions (crossings of the x axis) of the curve. So, the only option larger than zero among the possible answers is 10 (option a)
The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in randomly selected cities. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts (a) through (c) below
68.87 78.25 70.44 84.67 79.79 86.33 100.24 98.26
(a) Determine a point estimate for the population mean travel tax
A point estimate for the population mean travel tax is $ 83.36. (Round to two decimal places as needed.)
(b) Construct and interpret a 95% confidence interval for the mean tax paid for a three-day business trip.
Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.)
A. The lower bound is $ and the upper bound is $. One can be % confident that all cities have a travel tax between these values.
B. The lower bound is $ and the upper bound is $ The travel tax is between these values for % of all cities.
C. The lower bound is $ and the upper bound is $ There is a % probability that the mean travel tax for all cities is between these values.
D. The lower bound is $ and the upper bound is One can be [95]% confident that the mean travel tax for all cities is between these values.
(c) What would you recommend to a researcher who wants to increase the precision of the interval, but does not have access to additional data?
A. The researcher could decrease the level of confidence.
B. The researcher could decrease the sample standard deviation.
C. The researcher could increase the level of confidence
D. The researcher could increase the sample mean
Answer:
(a) The point estimate for the population mean travel tax is $ 83.36.
(b) The lower bound is $73.70 and the upper bound is $93.02 One can be [95]% confident that the mean travel tax for all cities is between these values.
(c) The researcher could decrease the level of confidence.
Step-by-step explanation:
We are given that a normal probability plot suggests the data could come from a population that is normally distributed.
X: 68.87, 78.25, 70.44, 84.67, 79.79, 86.33, 100.24, 98.26.
(a) A point estimate for the population mean travel tax is the sample mean of the data. i.e;
Point estimate, [tex]\bar X[/tex] = [tex]\frac{\sum X}{n}[/tex]
= [tex]\frac{68.87+ 78.25+ 70.44+ 84.67+ 79.79+ 86.33+ 100.24+ 98.26}{8}[/tex]
= [tex]\frac{666.85}{8}[/tex] = $83.36
So, the point estimate for the population mean travel tax is $ 83.36.
(b) Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean travel tax = $83.36
s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = $11.55
n = sample size = 8
[tex]\mu[/tex] = population mean travel tax
Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.
So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;
P(-2.365 < N(0,1) < 2.365) = 0.95 {As the critical value of t at 7 degrees of
freedom are -2.365 & 2.365 with P = 2.5%}
P(-2.365 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.365) = 0.95
P( [tex]-2.365 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.365 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95
P( [tex]\bar X-2.365 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.365 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95
95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.365 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.365 \times {\frac{s}{\sqrt{n} } }[/tex] ]
= [ [tex]\$83.36-2.365 \times {\frac{\$11.55}{\sqrt{8} } }[/tex] , [tex]\$83.36+2.365 \times {\frac{\$11.55}{\sqrt{8} } }[/tex] ]
= [$73.70, $93.02]
Therefore, a 95% confidence interval for the population average debt load of graduating students with a bachelor's degree is [$73.70, $93.02].
The lower bound is $73.70 and the upper bound is $93.02 One can be [95]% confident that the mean travel tax for all cities is between these values.
(c) The researcher could decrease the level of confidence who wants to increase the precision of the interval but does not have access to additional data.
Find f. f '''(x) = cos(x), f(0) = 8, f '(0) = 4, f ''(0) = 9 f(x) =
======================================================
Work Shown:
f ''' (x) = cos(x) .... third derivative
f '' (x) = sin(x)+C ... integrate both sides to get second derivative. Don't forget the +C at the end
We are given f '' (0) = 9, so we'll make use of this to find C
f '' (x) = sin(x)+C
f '' (0) = sin(0)+C
9 = sin(0) + C
9 = 0 + C
9 = C
C = 9
Therefore, f '' (x) = sin(x)+C turns into f '' (x) = sin(x)+9
------------
Integrate both sides of the second derivative to get the first derivative function
f '' (x) = sin(x)+9
f ' (x) = -cos(x)+9x+D ... D is some constant
Make use of f ' (0) = 4 to find D
f ' (x) = -cos(x)+9x+D
f ' (0) = -cos(0)+9(0)+D
4 = -1 + 0 + D
D = 5
So we have f ' (x) = -cos(x)+9x+D turn into f ' (x) = -cos(x)+9x+5
------------
Lastly, apply another round of integrals and substitutions to find the f(x) function. We'll use f(0) = 8.
f ' (x) = -cos(x)+9x+5
f(x) = -sin(x) + (9/2)x^2 + 5x + E .... E is some constant
f(0) = -sin(0) + (9/2)(0)^2 + 5(0) + E
8 = 0 + 0 + 0 = E
E = 8
------------
We have
f(x) = -sin(x) + (9/2)x^2 + 5x + E
turn into
f(x) = -sin(x) + (9/2)x^2 + 5x + 8
Besides the proportion of the sides, what else
must always be true for the polygons to be
similar?
Answer:
For two polygons to be similar, both of the following must be true: Corresponding angles are congruent. Corresponding sides are proportional.
Step-by-step explanation:
HOPE THIS HELPS AND PLSSS MARK AS BRAINLIEST]
THNXX :)
What must be true for two polygons to be similar?
Similar polygons: For two polygons to be similar, both of the following must be true: Corresponding angles are congruent. Corresponding sides are proportional.
Which statement is not true about the data shown by the box plot below? A. Three fourths of the data is less than 65. B. The median of the upper half of the data is 65. C. The interquartile range is 55. D. The median of the data is 55.
Answer:
C. The interquartile range is 55
Step-by-step explanation:
When you want to find the interquartile range you look at the box plot to see that it is everything from the upper interquartile range to the lower interquartile range is the interquartile range. So from 40 to 65. So there for the answer C. is incorrect.
Answer:
A.
Step-by-step explanation:
which is bigger 1.63m or 1.6m
Answer:
1.63
HOPE THIS WILL HELP..............!
The volume of a cone is 1540cm³. If its radius is 7cm, calculate the height of the cone. (Take pi = 22/7)
Answer:
[tex]h=30[/tex]
Step-by-step explanation:
Volume of a cone=1540[tex]cm^{3}[/tex], Radius=7cm.
The height of a cone=h
When we need to find the height of a cone, we can use the formula of the volume of a cone, which is [tex]\frac{1}{3} \pi r^{2} h[/tex] to find the height of a cone.
[tex]1540cm^{3} =\frac{1}{3}\pi r^{2} h[/tex]
Put the pi value=22/7 and the value of radius which is 7 cm into the formula.
[tex]1540cm^{3}=\frac{1}{3}*\frac{22}{7} 7^{2}h[/tex]
[tex]1540cm^{3} =\frac{154}{3}h[/tex]
Move [tex]\frac{154}{3}[/tex] to another side. 1540 divided by [tex]\frac{154}{3}[/tex] to calculate what is the value of h, h is the height of a cone. Like this.
[tex]\frac{1540cm^{3} }{\frac{154}{3} } =h[/tex]
[tex]30=h[/tex]
Rearrange the h.
[tex]h=30[/tex]
I hope you will understand my solution and explanation. If you still cannot get the point, you can ask me anytime! Thank you!
Answer:
The height of the cone is h = 30 cm.
Step-by-step explanation:
The formula for a cone is:
[tex] \\ V = \frac{1}{3}*\pi*r^2*h[/tex]
We have (without using units) and using pi = 22/7:
[tex] \\ 1540 = \frac{1}{3}*\frac{22}{7}*(7)^2*h[/tex]
Which is equals to:
[tex] \\ 1540 = \frac{1}{3}*\frac{22}{7}*(7)*h[/tex]
[tex] \\ 1540 = \frac{1}{3}*22*7*h[/tex]
Well, we have to solve the equation for h:
[tex] \\ \frac{1540*3}{22*7} = h[/tex]
[tex] \\ 30 = h[/tex]
Therefore, the height of the cone is 30 cm.
A newspaper article claimed: "The average cost of weekly groceries is $124.50." What
statistical measurement are they most likely claiming?
O A. median
B. mean
C. range
D. mode
The average cost of weekly groceries is $124.50." The statistical measurement are they most likely claiming is Mean
The correct option is (B)
what is Mean?The arithmetic mean of a given data is the sum of all observations divided by the number of observations.
For example, a cricketer's scores in five ODI matches are as follows: 12, 34, 45, 50, 24. To find his average score in a match, we calculate the arithmetic mean of data using the mean formula:
Mean = Sum of all observations/Number of observations
MedianThe value of the middlemost observation, obtained after arranging the data in ascending or descending order, is called the median of the data.
For example, consider the data: 4, 4, 6, 3, 2. Let's arrange this data in ascending order: 2, 3, 4, 4, 6. There are 5 observations. Thus, median = middle value i.e. 4.
ModeThe value which appears most often in the given data i.e. the observation with the highest frequency is called a mode of data.
As per the situation we have given average cost of groceries.
The mean is also the average sum of data divided by total number of data.
Hence, The statistical measurement is Mean.
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-1 1/6 ÷ (-4 2/3) Help pls
Answer:
1/4
Step-by-step explanation:
-1 1/6 ÷ (-4 2/3)
Change to improper fractions
- ( 6*1 +1)/6 ÷ -(3*4 +2)/3
-7/6÷ -14/3
Copy dot flip
-7/6 * -3/14
Rewriting
-7/14 * -3/6
-1/2 * -1/2
1/4
I need answers to this also a step by step explanation on how to do it would be great. :)
Answer:
48 degrees
Step-by-step explanation:
A straight line measures up to 180 degrees so take what we know which is 138 and subtract that from 180 to get your answer 48
Answer:
48
Step-by-step explanation:
Sum of angles On a straight line = 180
Given angle = 132
O, x is the remaining angle that must join 132 to form 180, which is
180-132 = 48 degrees.
Hope this helps
Good luck
In a class Vidya ranks 7th from the top. Divya
is 7 ranks ahead of Medha and 3 ranks
behind Vidya. Sushma who is 4th from the
bottom is 32 ranks behind Medha. How many
students are there in the class?
Answer:
52 students
Step-by-step explanation:
From the question above, we have the following information:
a) Vidya ranks 7th from the top.
Mathematically,
Vidya = 7th student
b) Divya 3 ranks behind Vidya.
Divya = Vidya + 3
Hence, Mathematically:
Divya = 7 + 3 = 10
Divya = 10th student
c) Also, Divya is 7 ranks ahead of Medha.
Mathematically,
Medha = 10 + 7= 17
Medha= 17th student
d)Sushma is 32 ranks behind Medha
Mathematically,
Sushma = Medha + 32
= 17 + 32 = 49
Sushma is the 49th student
Therefore, since, Sushma is 4th from the bottom, total number of students is:
49 + 3 = 52 students
Jeremy's father drives him to school in rush hour traffic in 20 minutes. One day there is no traffic, so his father can drive him 18 miles per hour faster and gets him to school in 12 minutes. How far (in miles) is it from Jeremy's home to school?
Answer:
Step-by-step explanation:
18/60-12/60= 4 miles
just my guess
Pls help me with this question
Answer:
[tex]\sqrt[5]{x^7}[/tex]
or (x ^ 1/5) ^7
or ([tex]\sqrt[5]{x}[/tex])^7
Step-by-step explanation:
x ^ 1.4
Rewriting the decimal as an improper fraction
x ^ 14/10
x ^ 7/5
The top is the power and the bottom is the root
[tex]\sqrt[5]{x^7}[/tex]
or (x ^ 1/5) ^7
or ([tex]\sqrt[5]{x}[/tex])^7
Below given are the details of transaction of a bank account of three brother Ram, Rahul and Rohit having AED 1000 in each account. a. Ram – Credits AED 500 on 12th May 2020 b. Rahul – Debits AED 700 on 12th May 2020 and Credits AED 500 on 15th May 2020. c. Rohit – Credits AED 700 on 12th May 2002 and Debits AED 500 on 15th May 2020. Who has more amount in his account at the end of the month Arrange the amounts in ascend
Answer:
Ram therefore has more amount in his account at the end of the month, and the balances in their bank accounts at the end of the month are arranged in ascending order, i.e. from the smallest to the largest, as follows:
Rahul – Debits AED 200; Rohit – Credits AED 200; and Ram – Credits AED 500.
Step-by-step explanation:
In banking and finance, a credit transaction on a bank account indicates that an additional amount of money has been added to the bank account and the balance has increased. This gives a positive balance in the account
On the other hand, a debit transaction on a bank account indicates that an amount of money has been deducted or withdrawn from the bank account and the balance has therefore reduced. This gives a negative balance in the account.
Based on the above, we have:
a. Ram – Credits AED 500 on 12th May 2020
Since there is no any other credit or debit transaction during the month, this implies that Ram still has Credits AED 500 in his account at the end of the month.
The Credits AED 500 indicates that Ram has a positive balance of AED 500 in his account at the end of the month.
b. Rahul – Debits AED 700 on 12th May 2020 and Credits AED 500 on 15th May 2020.
The balance in the account of Rahul gives Debits of AED 200 as follows:
Debits AED 700 - Credits AED 500 = Debits AED 200
The Debits AED 200 indicates that Rahul has a negative balance of AED 200 in his account at the end of the month.
c. Rohit – Credits AED 700 on 12th May 2002 and Debits AED 500 on 15th May 2020.
The balance in the account of Rohit gives Credits of AED 200 as follows:
Credits AED 700 - Dedits AED 500 = Credits AED 200
The Credits AED 200 indicates that Rohit has a positive balance of AED 200 in his account at the end of the month.
Conclusion
Arrangement of numbers or amounts of money in ascending order implies that they are arranged from the smallest to the largest number or amount.
Since Credits implies positive amount and Debits implies negative amount, Ram therefore has more amount in his account at the end of the month, and the balances in their bank accounts at the end of the month are arranged in ascending order, i.e. from the smallest to the largest, as follows:
Rahul – Debits AED 200; Rohit – Credits AED 200; and Ram – Credits AED 500.
Hi could somebody help me
Assuming both vertical lines are parallel and assuming I'm supposed to find all the unmarked angles...
Angle C:
Supplementary Angles.
x+36=180
180-36=x
x=144
Angle B:
Corresponding Angles.
Angle B ≅ Angle C
144
Angle A:
360 degrees in a quadrilateral
36+144+81+x=360
261+x=360
x = 99
Hope it helps <3
Type the correct answer in the box.
8.66 cm
10 cm
10 cm
10 cm
15 cm
15 cm
15 cm
15 cm
10 cm
10 cm
10 cm
8.66 cm
The surface area of the three-dimensional figure is
souare centimeters.
Hey there! I'm happy to help!
The surface area is just the area of this net. If you fold up the net it will give you a hollow 3-d shape.
On this net we have three congruent rectangles and two congruent triangles.
We see that each rectangle has a short side of 10 cm and a long side of 15 cm. The area of a rectangle is found by multiplying the long side by the short side.
15×10=150
So, each rectangle has an area of 150 cm².
Now, for the triangles. To find the area of a triangle you multiply the base by the height and then divide by two.
Each triangle has a base of 10 cm and a height 8 2/3 cm.
We multiply them.
10×8 2/3=86 2/3
And we divide by two.
86 2/3 ÷ 2 = 43 1/3
So, each triangle has an area of 43 1/3.
Now, we add together the areas of our three rectangles and two triangles.
150+150+150+43 1/3+43 1/3=536 2/3
Therefore, the surface area is 536 2/3 cm².
Have a wonderful day!
I don’t know how to answer this?
Answer:
SOLUTION SET ={a/a≥20}
Step-by-step explanation:
[tex]\frac{2a}{5}-2\geq\frac{a}{4}+1[/tex]
[tex]adding 2 on both sides[/tex]
[tex]\frac{2a}{5}-2+2\geq \frac{a}{4}+1+2[/tex]
[tex]now subtracting \frac{a}{4} on both sides[/tex]
[tex]\frac{2a}{5}-\frac{a}{4}\geq 3[/tex]
[tex]takig LCM as 20\\\frac{8a}{20}-\frac{5a}{20}\geq 3[/tex]
[tex]\frac{3a}{20}\geq 3[/tex]
[tex]by cross-multiplication[/tex]
3a≥3×20
3a≥60
dividing 3 on both sides
3a/3≥60/3
a≥20
SOLUTION SET ={a/a≥20} is the answer
i hope this will help you :)
At the shop near the beach, ice cream is offered in a cone or in a cylindrical cup as shown
below. The ice cream fills the entire cone and has a hemisphere on top. The ice cream
levelly fills the cylindrical cup.
radius of cone= 3 cm
radius of cylinder= 4.5 cm
height of cone = 10 cm
height of cylinder = 5 cm
Determine how much more ice cream the larger option has. Show your work. ( 19)
Answer:
B
Step-by-step explanation:
which answer is equivalent to √16/√49
Answer:
sqroot 16/49 A
Step-by-step explanation:
The expression [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] is equivalent to expression [tex]\sqrt{\frac{16}{49}}[/tex] because by property [tex]\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b} }[/tex].
The expression [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] can be simplified by taking the square root of 16 and the square root of 49 separately.
√16 equals 4 because the square root of 16 is the number that, when multiplied by itself, gives 16.
Similarly, √49 equals 7 because the square root of 49 is the number that, when multiplied by itself, gives 49.
So, the expression [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] simplifies to 4/7.
and we know that [tex]\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b} }[/tex]
[tex]\sqrt{\frac{16}{49}}[/tex] is equivalent to [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] , which simplifies to 4/7.
Therefore, [tex]\sqrt{\frac{16}{49}}[/tex] is equivalent to [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] .
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Which letter has a line of symmetry?
Answer:
D. all of the above
Step-by-step explanation:
All the letters from the options have a line of symmetry.
You need to find the volume of the plastic sphere that holds the gum in your gumball machine. If the diameter is 2 feet, what is the volume? Use 3.14 to approximate pi. Round your answer to the nearest hundredth.
Answer:
The volume is
4ft³Step-by-step explanation:
Volume of a sphere is given by
[tex]V = \frac{4}{3} \pi {r}^{ 3} [/tex]
where r is the radius
π = 3.14
From the question we were given the diameter and
radius = diameter/ 2
diameter = 2 feet
radius = 2/2 = 1 feet
So the volume of the sphere is
[tex]V = \frac{4}{3} (3.14)(1) ^{3} [/tex]
[tex] = \frac{4}{3} \times 3.14[/tex]
V = 4.186
We have the final answer as
V = 4 ft³ to the nearest hundredth
Hope this helps you
Help please! Thank you
Answer:
The rise is -6.
Step-by-step explanation:
For this problem, the direction of the vector gives the indication of a negative slope. We know that the equation to find slope = rise/run meaning y/x values. So for this, we can see the y-value of the blue triangle (the rise) to be 6, and the x-value of the blue triangle (the run) to be 3. And as stated before, this is a negative slope, in the y-direction. Hence, the rise is -6 for the blue triangle.
Please help me with this question
Answer:
a. 30 meters per second
b. -10 meters per second
Step-by-step explanation:
a. Average rate of change for the height from 0 to 6.6 secs can be calculated using the formula, [tex] m = \frac{H(b) - H(a)}{b - a} [/tex]
Thus,
Where,
[tex] a = 0, H(0) = 0 [/tex]
[tex] b = 6.6, H(6.6) = 198 [/tex]
Plug in the values into the formula:
[tex] m = \frac{198 - 0}{6.6 - 0} [/tex]
[tex] m = \frac{198}{6.6} [/tex]
[tex] m = 30 [/tex]
b. Average rate of change for the height from 8.8 to 13.2 secs = tex] m = \frac{H(b) - H(a)}{b - a} [/tex]
Where,
[tex] a = 8.8, H(8.8) = 44 [/tex]
[tex] b = 13.2, H(13.2) = 0 [/tex]
Plug in the values:
[tex] m = \frac{0 - 44}{13.2 - 8.8} [/tex]
[tex] m = \frac{-44}{4.4} [/tex]
[tex] m = -10 [/tex]
6x +6
7x-6
Equation ?
Solve for x
Answer:
Hey there!
6x+6=7x-6
6=x-6
12=x
x=12
Hope this helps :)