Calculate the magnitude and direction of the resultant of the following forces​

Answer:

The answer is below

Explanation:

The amplitude decreases by 2%  during each oscillation. Hence the decrease in amplitude can be represented by an exponential decay in the form:

y = abˣ; where x ad y are variables, a is the initial value and b is the factor.

Let y represent the amplitude after x oscillations. Since the initial amplitude is 10 cm, hence:

a = 10 cm, b = 2% = 0.02.

Therefore:

y = 10(0.02)ˣ

The amplitude after 25 oscillations is gotten by substituting x = 25 into the equation. Hence:

y = 10(0.02)²⁵

y= 3.355 * 10⁻⁴² cm

The amplitude after 25 oscillations is 3.355 * 10⁻⁴² cm

Answer:

Explanation:

Given the following

Ax = 9,

Ay = 12,

Bx = 15

By = 20

Get A and B

A = √9²+12²

A= √81+144

A = √225

A = 15

Get B;

B = √15²+20²

B = √225+400

B = √625

B = 25

get /A+B/

A+B = 15+25

/A+B/ = /40/

Hence the value of /A+B/ is 40

Answer:

ω = 0.571 rad/s

Explanation:

given data

radius = 30 m

solution

we take here g = 9.8 m/s²

and g is express as

g = r × ω²     ....................1

put here value and we get

9.8 = 30 × ω²

solve it we get

ω = 0.571 rad/s

Answer:

a) the new angular speed of the student is 0.9642 rad/s

b)

the kinetic energy of the student before the objects are pulled in is 1.9119 J

the kinetic energy of the student after the objects are pulled in is 2.4252 J

Explanation:

Given that;

mass of each object m = 1 kg

distance of objects from axis of rotation r = 0.9 m

Moment of inertia of each object initially [tex]I_{oi}[/tex]

[tex]I_{oi}[/tex] = mr² = 1kg ×(0.9m)² = 1 kg × 0.81 m²  = 0.81 kg.m²

moment of inertia of each object finally [tex]I_{of}[/tex]

[tex]I_{of}[/tex]  = mr² = 1kg × (0.33 m)² = 0.1089 kg.m²

Now

moment of inertia of student plus stool  [tex]I_{}[/tex] = 5 kg.m²

initial angular speed ω₀ = 0.76 rad/sec

final angular speed ω = ?

Now using conservation of angular momentum;

([tex]I_{}[/tex] + 2 [tex]I_{oi}[/tex] )ω₀ = ([tex]I_{}[/tex] + 2 [tex]I_{of}[/tex] )ω

so we substitute

(5 + 2 (0.81) )0.76 = (5 + 2 (0.1089) )ω

5.0312 = 5.2178 ω

ω =  5.0312 / 5.2178

ω  = 0.9642 rad/s

Therefore, the new angular speed of the student is 0.9642 rad/s

b)

K.E of student before = (0.5) ([tex]I_{}[/tex] + 2 [tex]I_{oi}[/tex] )ω₀²

= (0.5) (5 + 2 (0.81) )(0.76)²

= 0.5 × 6.62 × 0.5776

= 1.9119 J

Therefore, the kinetic energy of the student before the objects are pulled in is 1.9119 J

KE of student finally = (0.5) ([tex]I_{}[/tex] + 2 [tex]I_{of}[/tex] )ω²

= (0.5) (5 + 2 (0.1089) ) (0.9642)²

= 0.5 × 5.2178 × 0.9296

= 2.4252 J

Therefore, the kinetic energy of the student after the objects are pulled in is 2.4252 J

Answer:

the second one Test the rate of decay of specific elements in rock samples.

Answer:

a

Explanation:

i just took the test

Answer: I don't know my dude

Explanation:

Answer: Electrical energy is converted into other forms of energy, such as sound.

Explanation: Using the law of conservation of energy we know that energy can never be destryped it can be transferred or be transformed into from one form to another.

Electrical energy is converted into other forms of energy, such as sound.

The law of conservation of energy or matter, states that energy can neither be created nor destroyed but can be converted from one form to another.

When listening to music on radio, the electric energy supplied to the radio will be converted to mechanical energy of the moving parts of the radio which is then converted to sound energy.

Thus, we can conclude that electrical energy is converted into other forms of energy, such as sound.

Learn more here:https://brainly.com/question/2828402

Answer:

8.11 m/s

Explanation:

The bird has two velocity, one velocity is in the upward direction (+y direction) and the other velocity is in the x direction (that is along the radius of circle of the bird).

the vertical speed [tex]v_y=3\ m/s[/tex]

The horizontal speed ([tex]v_x[/tex]):

[tex]v_x=\frac{2\pi R}{T} =\frac{2\pi *6\ m}{5\ s} =7.54\ m/s[/tex]

The bird's speed relative to the ground (v) is given by:

v = [tex]\sqrt{v_x^2+v_y^2}[/tex]

[tex]v=\sqrt{7.54^2+3^2} \\\\v=8.11\ m/s[/tex]

Answer:

high and low tied maybe? not sure

That's a great question !

The answer is: It does !

A push on an object causes the object to accelerate in the direction of the force.  

The less mass the object has, the more the force accelerates it.

Now, when you jump, the forces on you and on the Earth are equal forces.

The up force on you causes you to accelerate up by some amount.

The down force on the Earth causes the Earth to accelerate down by some amount.

The Earth's mass is something like 5,972,000,000,000,000,000,000,000 kg, while your mass is something like 50 kg.

The Earth has something like 119,400,000,000,000,000,000,000 times as much mass as you have.

So your acceleration is something like 119,400,000,000,000,000,000,000 times as great as the Earth's acceleration.

==> The Earth's downward acceleration, caused by your jump, is there.  It's just too small to notice.

BUT . . . That's the reason why seismometers (instruments to detect and measure the vibrations from distant earthquakes) have to be located as far as possible from cities and busy roads.

In places that are too close to cities and roads, the Earth's surface is always vibrating, wiggling, jiggling, heaving and weaving, in reaction to the forces of people walking around, cars and trucks driving around, even rain falling down.  And kids jumping up and down !  

In such places, these people-motions are louder and stronger than the vibrations coming from distant earthquakes.  Seismometers wouldn't work there.    

Answer: Similarity

By.

Answer:

the magnitude of the charge on the drop is 5.163 × 10⁻¹⁸  C

Explanation:

Given that;

mass of the drop m = 8.0×10⁻¹⁵ kg

distance d = 16 cm = 0.16 m

potential difference between the plates V = 2.44 kV = 2440 v

acceleration of gravity g = 9.81 m/s²

the magnitude of the charge on the drop = ?

weight is balanced by the electrostatic force

weight = mg = 8.0×10⁻¹⁵ kg × 9.81 m/s² = 7.848 × 10⁻¹⁴

we know that; V = Ed

E = V/d =  2440 / 0.16 = 15200 v/m

Electrostatic force = qE

so weight = qE

q = weight / E

q = 7.848 × 10⁻¹⁴ / 15200

q = 5.163 × 10⁻¹⁸  C

Therefore, the magnitude of the charge on the drop is 5.163 × 10⁻¹⁸  C

Answer:

The answer is below

Explanation:

Let a be the initial velocity of motorcycle A and b be the initial velocity of motorcycle B.

After 5.68 seconds, both motorcycle had the same velocity (v), therefore for motorcycle A:

(a - v) / 5.68 = 3.87

a - v = 21.9816

v = a - 21.9816

For motorcycle B:

(b - v) / 5.68 = 18.2

b - v = 103.376

v = b - 103.376

Therefore:

a - 21.9816 = b - 103.376

b - a = -21.9816 + 103.376

b - a = 81.3944

a) The difference between their speeds at the beginning was 81.3944 m/s

b) Since b - a = 81.3944. This means that the initial velocity of motorcycle B is greater than that of motorcycle A by 81.3944 m/s.

Therefore motorcycle B was moving faster

Answer:

Explanation:

For resistance , the expression is as follows .

R = ρ L / S where ρ is specific resistance , L is length of wire and S is cross sectional area .

cross sectional area = π x ( .5 x 10⁻³ )²

S = .785 x 10⁻⁶ m²

Putting the values

R = 2.82 x 10⁻⁸ x .50 / .785 x 10⁻⁶

= 1.796 x 10⁻² ohm .

Answer:

Explanation:

mass of each part = 6 / 3 = 2 kg .

momentum of each of given part = 2 x 20 = 40 kg m/s

Two momentum of 40 kg m/s , acting at angle 60 degree .

Resultant momentum =  2 x 40 cos 30 = 69.28 kg m/s

The third mass will have equal and opposite momentum to this momentum , following law of conservation of momentum .

If its velocity be v .

2 x v = 69.28

v = 34.64 m /s

Third mass will have velocity of 34.64 m /s

Total kinetic energy of all three mass

KE = 1/2 x 2 ( 20² + 20² + 34.64² )

= 400 + 400 + 1199.92

= 1999.93 J .

Answer:

I think A

Explanation:

because I don't think a unknowned number can be a division problem

in the service producing sector

Answer:

Explanation:

The box is moving with constant velocity so acceleration of box is zero . That means net force on the box is zero .

The weight component acting on box parallel to incline plane

= mg sin 30⁰ = 20 x 9.8 x sin 30 = 98 N

This force is acting down the plane , hence to make the net force zero acting on box , force exerted by person will also be 98 N up the incline .

Force exerted by person = 98 N

distance travelled in 5 s

= velocity x time

= 2 x 5 = 10 m

Work done by person

= 98 x 10

= 980 J .

Im not sure this is correct but, i think thats because the wire connected at the negative side. The current go from positive to negative and thats why the bulb not light, also the bulb location is not at the center of the battery which explain why there's no current at the upper side.

Hope you understand. Sorry if my english sucks YEET

The light bulb isn't connected to the positive thing sticking out of the battery, both ends must connect back to the battery

Answer: 30 Years Old

Explanation: The constitution has around three qualifications for service in the U.S. Senate, Your age must be at least 30 years.

Answer:

5760 J

Explanation:

From the question given above, the following data were obtained:

Mass of block = 48 kg

Height (h) = 12 m

Gravitational field strength (g) = 10 N/Kg

Gravitational potential energy (PE) =?

The gravitational potential energy stored by the block can simply be obtained as follow:

PE = mgh

PE = 48 × 10 × 12

PE = 5760 J

Therefore, the gravitational potential energy stored by the block is 5760 J

Answer:

C the metal handle because it is a good conductor

Answer:

D.

Explanation:

Although the metal handle will last longer, if heated up enough it could burn her hand.

Answer:

4.8mph

Explanation:

Speed= Distance/time

Speed= 26.2/5.5

= 4.76mph

( To the nearest tenth ) = 4.8mph

Answer:

38.7 mph

Explanation:

I just add all the numbers together then divided them by 4, which is the amount of numbers you gave.

Answer:

The attraction is due to the induced charge.

Explanation:

When we approach a charged rod to a sheet, an induced load is produced in the sheet that is of the same magnitude as the rod of opposite sign, this is because the charges of different sign attract each other, this explains the initial attraction.

This induced load occurs if importing the plate load

The attraction is due to the induced charge.

Answer:

The answer to the given points can be defined as follows:

Explanation:

In point 1:

[tex]\bold{v_f^2= v_i^2+2as}\\\\\to v_f=0\\\\\to v_i=20 \frac{m}{s}\\\\\to s= 4.50\ m -3.60 \ m \\\\[/tex]

      [tex]=0.9 \ m \\[/tex]

put the value in the above formula:

[tex]\to 0= 20^2+2 \times a \times 0.9\\\\\to -1.8\ a=400\\\\\to -a= \frac{400}{1.8} \\\\ \to a= -222.22\ \ \frac{m}{s^2}[/tex]

 [tex]\bold{v_f=v_i+at}\\\\\to 0=20+ (-222.22)t\\\\\to 222.22t=20\\\\\to t=\frac{20}{222.22}\\\\\to t= 0.0900 \ s\\\\\to v_{avg}=\frac{s}{t}=\frac{0.9}{t}= 10\ \frac{m}{s}[/tex]

for point 2:

[tex]t= 0.0900 \ s -\text{found above}[/tex]

for point 3:

[tex]\to |a| = 222.22 \frac{m}{s^2} \text{found above}\\\\\to \bold{|F| = m \cdot |a|}\\\\[/tex]

         [tex]=1600 \ kg \times 222.22 \ \frac{m}{s^2} \\\\= 3.55\times 10^{5} \ N[/tex]

Answer:

63°

that's my answer

but then I am sorry if I'm wrong

Explanation:

90-27 = 63°