Calculate the magnitude and direction of the resultant of the following forces



Answer and I will give you brainiliest

Calculate The Magnitude And Direction Of The Resultant Of The Following Forces Answer And I Will Give

Answers

Answer 1

Answer:

250N same direction

Explanation:

100+150 = 250N

same direction


Related Questions

The most common stars in the universe are red dwarf stars. Red dwarf stars use their hydrogen fuel very slowly. Our universe also contains stars classified as blue supergiants. The table below lists the color and approximate surface temperatures of four stars. Based on the information from the table above, which of the following stars has the greatest absolute brightness?


The Sun


Vega


Bellatrix


Betelgeuse

Answers

Answer:

sun

Explanation:

if the forces on an object are balanced the resultant force is equal to zero true false

Answers

Answer:

If the forces are balanced, the resultant force is zero. If the forces on an object are unbalanced, this is what happens: a stationary object starts to move in the direction of the resultant force. a moving object changes speed and/or direction in the direction of the resultant force.

Explanation:

I need help please will mark brainliest

Answers

Answer:

200

Explanation:

20m/s*10sec=200

Which mode of kinetic energy contributes to temperature?

Answers

Answer:

Kinetic energy Temperature

Explanation:


3. A stone is thrown vertically upwards from the top of a building 50 m tall with an initial
velocity of 20.0 ms. If the stone just misses the edge of the roof on its return, determine
(a) The time is taken the stone to get to its maximum height.
(b) The maximum height reached by the stone
(c) The time at which the stone return to the point where it was thrown
(d) The velocity of the stone at this instance
(e) The velocity and position of the stone at t = 5 s.

Answers

Answer:

13.4436

Explanation:

A system with a mass of 10 kg, initially moving horizontally with a velocity of 20 m/s, experiences a constant horizontal force of 25 N opposing the direction of motion. As a result, the system comes to rest. Determine the amount of energy transfer by work, in kJ, for this process and the total distance, in m, that the system travels

Answers

Answer:

Explanation:

Kinetic energy of the mass of 10 kg

= 1/2 m v² , m is mass and v is velocity .

= .5 x 10 x 20²

= 2000 J

The opposing force stops it . so work done by opposing force will be equal to this energy and it will be negative .

So energy transfer will be  - 2000 J .

= 2 kJ .

If distance travelled by mass is d , force 25 N will have a displacement of d . so work done by force of 25 N

= 25 x d

25 d = 2000

d = 80 m .

Hence system travels a distance of 80 m .

I WILL MARK BRAINLIST!!!!
a person drops their phone. The phone's mass is 0.115 kilograms and the bridge is 15 meters tall. The instant the they dropped the phone, what was its mechanical energy?




1.725



16.9



200

Answers

Are you sure it’s mechanical energy? I haven’t taken a physics class in a while but mechanical energy doesn’t sound right.

what is the acceleration of a satellite moving in a circular orbit around the earth of radius 2r​

Answers

Explanation:

You do the radius times the circumference of the earth

Acceleration figures for cars usually are given as the number of seconds needed to go from 0.0 to 97 km/h. Convert 97 km/h into m/s.

Answers

Answer:

26.9444m/s

pls brainliest

A ball of mass m is thrown straight upward from ground level at speed v0. At the same instant, at a distance D above the ground, another ball of mass m is thrown straight downward toward the first ball, also at speed v0. Assume that gravity acts vertically downward on each mass m with a magnitude mg. v0 D b How far above the ground do the balls collide (in terms of only D, v0, and g)?

Answers

Answer:

Explanation:

Let the balls collide after time t .

distance covered by falling ball

s₁ = v₀ t + 1/2 g t²

distance covered by rising ball

s₂ = v₀ t - 1/2 g t²

Given ,

s₁ + s₂ = D

D = v₀ t + 1/2 g t² + v₀ t - 1/2 g t²

= 2v₀ t

t = D / 2v₀

s₂ = v₀ t - 1/2 g t²

= v₀ x D / 2v₀ - (1/2) x  g x D² / 4v₀²

= D / 2 - gD² / 8 v₀²

Ropes 3 m and 5 m in length are fastened to a holiday decoration that is suspended over a town square. The decoration has a mass of 3 kg. The ropes, fastened at different heights, make angles of 52° and 40° with the horizontal. Find the tension in each wire and the magnitude of each tension. (Use g = 9.8 m/s2 for the acceleration due to gravity. Round your answers to two decimal places.)

Answers

Answer:

Explanation:

Let the tension in ropes be T₁ and T₂ . Ropes are making angle of 52 and 40 degree with the horizontal . The vertical component of tension will add up together to balance the weight of the decoration

T₁ sin52 + T₂ sin40 = 3 x 9.8

.788 T₁ + .643 T₂ = 29.4

The horizontal component of tension will add up to zero because the decoration piece is at rest .

T₁ cos52 + T₂ cos40 = 0

.615 T₁ -  .766 T₂ = 0

T₁ =  1.24 T₂

Substituting this value of T₁ in earlier equation , we have

.788 x 1.24 T₂ + .643 T₂ = 29.4

1.62 T₂ = 29.4

T₂ = 18.15 N

T₁ = 1.24 x 18.15 = 22.51 N .

Suppose there is a 3Mbps uplink and 10Mbps downlink between a geostationary satellite and the base station on earth. If the propagation speed is the speed of light (3 * 10^8 m/sec), the packet size is 20Mb, and the distance from the satellite to earth is 36,000 km, what is the uplink propagation delay of the link in milliseconds

Answers

Answer:

[tex]120\ \text{ms}[/tex]

Explanation:

Distance between the satellite and Earth = [tex]36000\ \text{km}[/tex]

Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]

Propagation delay is given by distance by the speed of light

[tex]\dfrac{36000\times 10^3}{3\times 10^8}[/tex]

[tex]=0.12\ \text{s}\times 10^3[/tex]

[tex]=120\ \text{ms}[/tex]

The uplink propagation delay of the link is [tex]120\ \text{ms}[/tex].

First to answer gets brainliest

Answers

Answer:

has a charge

Explanation:

Answer:

gain electrons

Explanation:

I looked it up and that was what I found

side note: ions do have a charge

You've been hired to design the hardware for an ink jet printer. You know that these printers use a deflecting electrode to cause charged ink drops to form letters on a page. The basic mechanism is that uniform ink drops of about 30 microns radius are charged to varying amounts after being sprayed out towards the page at a speed of about 20 m/s. Along the way to the page, they pass into a region between two deflecting plates that are 1.6 cm long. The deflecting plates are 1.0 mm apart and charged to 1500 volts. You measure the distance from the edge of the plates to the paper and find that it is one-half inch. Assuming an uncharged droplet forms the bottom of the letter, how much charge is needed on the droplet to form the top of a letter 3 mm high (11 pt. type)

Answers

Answer:

the required charged is 7.06 × 10⁻¹³ C

Explanation:

Given that;

Radius = 30 microns = 30 × 10⁻⁶

Speed v = 20 m/s

length x = 1.6 cm = 0.016 m

spacing d = 1.0 mm = 0.001 m

Voltage V = 1500 V

from the question, the electric field between the plates is uniform and equal to Voltage divided by the distance between the plates.

Electric field E = V/d

E = 1500 V /  0.001 m

E = 1.5 × 10⁶ V/m

Mass of ink drop m = pv

m = 10³ kg/m³ × [tex]\frac{4}{3}[/tex]πr³

m = 1000 kg/m³ × [tex]\frac{4}{3}[/tex]π × (30 × 10⁻⁶)³

m = 1.131 × 10⁻¹⁰ Kg

Time taken to travel t =  x / sped

t = 0.016 m / 20 m/s

t = 0.0008 s

From the kinematic equation

to form the top of a letter 3 mm ( 0.003 m )high

y = [tex]\frac{1}{2}[/tex]at²

2y = at²

a = 2y/t²

we substitute

a = (2 × 0.003 m) / (0.0008 s)²

a =  9375 m/s²

Now Force F = Eq = ma

so

q = ma / E

we substitute

q = ( 1.131 × 10⁻¹⁰ Kg × 9375 m/s² ) / ( 1.5 × 10⁶ V/m )

q = 7.06 × 10⁻¹³ C

Therefore, the required charged is 7.06 × 10⁻¹³ C

An object with an initial horizontal velocity of 20 ft/s experiences a constant horizontal acceleration due to the action of a resultant force applied for 10 s. The work of the resultant force is 10 Btu. The mass of the object is 55 lb. Determine the constant horizontal acceleration, in ft/s2.

Answers

Answer:

a = 7.749 ft/s²

Explanation:

First to all, we need to convert all units, so we can work better in the calculations.

The horizontal acceleration is asked in ft/s² so the units of speed will be the same. The Work is in BTU and we need to convert it in ft.lbf in order to get the acceleration and final speed in ft/s:

W = 10 BTU * 778.15 Lbf.ft / BTU = 7781.5 lbf.ft

Now, to get the acceleration we need to get the final speed of the object first. This can be done, by using the following expression:

W = ΔKe  (1)

And Ke = 1/2mV²

So Work would be:

W = 1/2 mV₂² - 1/2mV₁²

W = 1/2m(V₂² - V₁²)    (2)

Finally, we need to convert the mass in lbf too, because Work is in lbf, so:

m = 55 lb * 1 lbf.s²/ft / 32.174 lb = 1.7095 lbf.s²/ft

Now, we can calculate the final speed by solving V₂ from (2):

7781.5 = (1/2) * (1.7095) * (V₂² - 20²)

7781.5 = 0.85475 * (V₂² - 441)

7781.5/0.85475 = (V₂² - 400)

9103.83 + 400 = V₂²

V₂ = √9503.83

V₂ = 97.49 ft/s

Now that we have the speed we can calculate the acceleration:

a = V₂ - V₁ / t

Replacing we have:

a = 97.49 - 20 / 10

a = 7.749 ft/s²

Hope this helps

A skier pushes off the top of a hill with an initial speed of 3.30 m/s. How fast will she be moving after dropping 5.00 meters in elevation if friction is negligible?

Answers

Answer:

eeeeeeeeeeeeeeeeeeeee

Heeeeelp please


Answer and I will give you brainiliest

Answers

Answer:

I think the answer is 63,

If the kinetic energy of the 40kg box is 784 J, what is the velocity before it strikes the ground?

Answers

Answer:

Explanation:

[tex]KE=\frac{1}{2}mv^2[/tex]

[tex]784=\frac{1}{2}(40)v^2[/tex]

[tex]784=20v^2[/tex]

[tex]39.2=v^2[/tex]

[tex]v=6.26m/s[/tex]

A loan of $8.000 accumulates simple interest at an annual interest rate of 5%. After how many years does the value the loan become $9.200?

Answers

8,000x.05=400 so 400x3=1,200
1,200 + 8,000=9,200
So 3 years

You throw a ball into the air as shown in the diagram. At what point does the ball have the most potential energy?

Answers

Answer:

Position X.

Explanation:

To know the correct answer to the question, it is important that we know the definition of potential energy.

Potential energy can be defined as the energy possessed by an object in relation to its position. Mathematically it can be expressed as:

PE = mgh

Where

PE => is the potential energy.

m => is the mass of the object.

g => is the acceleration due to gravity.

h => is the height to which the object is located.

Considering the formula for potential energy (i.e PE = mgh), we can see clearly that the potential energy (PE) is directly proportional to the height (h). This implies that the greater the height, the greater the potential energy and the smaller the height, the smaller the potential energy.

Considering the diagram given above, we can see that the greatest height attained by the ball is at position X. Thus, the ball will have the greatest potential energy at position X.

An athlete swims the length L of a pool in a time t1 and makes the return trip to the starting position in a time t2. If she is swimming initially in the positive x-direction, determine her average velocities symbolically in:

a. the first half of the swim
b. the second half of the swim
c. the round trip.

Answers

Answer:

B but I am not sure

Explanation:

A ball is thrown horizontally to the right, from the top of a vertical cliff of height h. A wind blows horizontally to the left, and assume (simplistically) that the effect of the wind is to provide a constant force to the left, equal in magnitude to the weight of the ball. How fast should the ball be thrown so that it lands at the foot of the cliff

Answers

Answer:

 v = [tex]\sqrt{\frac{y_o \ g}{2} }[/tex]

Explanation:

For this exercise we must use the projectile launch ratios, let's start by finding the time it takes to reach the bottom of the cliff, the initial vertical velocity is zero

          y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

         

at the bottom of the cliff y = 0 and as the body is thrown horizontally the initial vertical velocity is zero

          0 = y₀ + 0 - ½ g t²

          t = [tex]\sqrt{2y_o/g}[/tex]

this time is the same as the horizontal movement.

Let's use Newton's second law to find the acceleration on this x-axis due to the force of the air

           F = m aₓ

they tell us that force is equal to the weight of the body

           -mg = maₓ

           aₓ = -g

the sign indicates that the acceleration is to the left

we write the kinematics equation

          x = x₀ + v₀ₓ t + ½ aₓ t²

They indicate that the final position is the foot of the cliff (x = 0), when it leaves the top it is at x₀ = 0 and has a velocity v₀ₓ = v

we substitute

          0 = 0 + v t + ½ (-g) t²

          v = ½ g t

         

we use the drop time

          v = ½ g [tex]\sqrt{\frac{2yo}{g} }[/tex]

          v = [tex]\sqrt{\frac{y_o \ g}{2} }[/tex]

what is calculator program​

Answers

Answer:

software calculator is a calculator that has been implemented as a computer program, rather than as a physical hardware device. They are among the simpler interactive software tools, and, as such, they: Provide operations for the user to select one at a time.

Answer: The calculator is a compact portable device that performs mathematical calculations. Some calculators also allow easy text editing and programming. It's also a programming software that simulates a portable calculator. Calculator applications help you make basic math calculations without leaving your screen.

3. Describe how sound signals can be transmitted from a cell phone and received by another cell phone.
Create a labeled diagram that shows this process. (2 points)

Answers

Answer:

The sound energy travels through the air into the microphone and makes the diaphragm inside vibrate. The sound energy in your voice makes the air vibrate. Vibrating air carries the sound energy into the phone. The diaphragm in the mouthpiece microphone converts sound energy into electrical energy.

Explanation: Hope this helps! :)

Which statement about the sun's energy is correct?

It is entirely re-radiated back into space.
A part of it is destroyed by greenhouse gases.
A part of it is absorbed by atmospheric gases.
It makes Earth too hot for plants and animals to survive.

Answers

I believe it’s A. I know for sure it isn’t D.

Answer:

The answer is (A)

Explanation:

We know this because The suns energy is entirely re-radiated back into space.

We know also that the answer is not (D) It makes Earth too hot for plants and animals to survive.

Atmospheric gases are gases located in the Earth's atmosphere

The green house effect is a natural process that warms the Earth's surface

I also know the answer because I took the test... FLVS exam 3.09 right?

I took it and got this question right... So i know you will! GOOD LUCK!!

Mark me brainlyest please:)

An air-filled capacitor consists of two parallel plates, each with an area of A , separated by a distance d . A V potential difference is applied to these plates. What is the magnitude of the electric field between the plates

Answers

Answer:

  E = V / d

Explanation:

In a charged capacitor an electric field is established that goes from the positive to the negative plate, this field is constant,

the potential difference is

           D = E d

in this case they do not give the difference in potential V and the distance between the plates d

           E = V / d

The Short Answer:
Earth's tilted axis causes the seasons. Throughout the year, different
parts of Earth receive the Sun's most direct rays. So, when the North
Pole tilts toward the Sun, it's summer in the Northern Hemisphere. And
when the South Pole tilts toward the Sun, it's qvinter in the Northern
Hemisphere.
1. What direction is the Earth tilted in the summer here in
Buffalo?
a) towards the Sun
b) away from the Sun
23.5

Answers

Answer:

I cannot fully see the picture, but I'm going to have to tell you to go with towards the sun because it says summer.

In reaching her destination, a backpacker walks with an average velocity of 1.19 m/s, due west. This average velocity results because she hikes for 5.96 km with an average velocity of 3.10 m/s, due west, turns around, and hikes with an average velocity of 0.744 m/s, due east. How far east did she walk

Answers

Answer:

 x₂ = 4.455 m

Explanation:

The average speed is defined as the displacement traveled between the time interval

         v_average =  [tex]\frac{\Delta x}{\Delta t}[/tex]

in this case we have a first stop walking west at speed v = 3.10 m / s a ​​distance of x = 5.96 km = 5.96 10³ m

Let's find the time it takes on this tour

          v = x / t

          t = x / v

          t₁ = 5.96 10³ / 3.10

          t₁ = 1.9226 10³ s

in a second to walk east at a speed of v₂ = 0.744 m / s

           v₂ = x₂ / t₂

           t₂ = x₂ / v₂

for full movement

let's assume that the eastward movement is positive

         v =[tex]\frac{- x_1 + x_2}{t_1 +t_2}[/tex]

         v = [tex]\frac{-x_1 +x_2}{t_1 + \frac{x_2}{t_2} }[/tex]

the only unknown term is the distance to the east. We replace and resolve

         1.19 = [tex]\frac{-5.96 \ 10^3 + x_2}{1.92 \ 10^3 + \frac{x_2}{0.744} }[/tex]

         1.19 (1.92 10³ + [tex]\frac{x_2}{0.744}[/tex]) = x₂ 1.92 10³ - 5.96 10³

             

          2.2848 10³ + 1.599 x₂ = 1.92 10³ x₂ - 5.96 10³

          x₂ (1.92 10³ - 1.599) = 2.2848 10³ + 5.96 10³

          x₂ = 8.5448 10³ / 1.918 10³

          x₂ = 4.455 m

Two astronauts, each having a mass of 74.3 kg are connected by a 13.1 m rope of negligible mass. They are isolated in space, orbiting their center of mass at speeds of 5.65 m/s. a. Calculate the magnitude of the initial angular momentum of the system by treating the astronauts as particles.

Answers

Answer:

  L = 5076.5 kg m² / s

Explanation:

The angular momentum of a particle is given by

         L = r xp

         L = r m v sin θ

the bold are vectors, where the angle is between the position vector and the velocity, in this case it is 90º therefore the sine is 1

as we have two bodies

       L = 2 r m v

let's find the distance from the center of mass, let's place a reference frame on one of the masses

        [tex]x_{cm}[/tex] = [tex]\frac{1}{M} \sum x_{i} m_{i}[/tex]i

        x_{cm} = [tex]\frac{1}{m+m} ( 0 + l m)[/tex]

        x_{cm} = [tex]\frac{1}{2m} lm[/tex]

        x_{cm} = [tex]\frac{1}{2}[/tex]

        x_{cm} = 13.1 / 2 = 6.05 m

let's calculate

          L = 2  6.05  74.3  5.65

          L = 5076.5 kg m² / s

Answer:

5076.5

Explanation:

g Galileo's telescopes were not of high quality by modern standards. He was able to see the moons of Jupiter, but he never reported seeing features on Mars. Use the small-angle formula to find the angular diameter of Mars when it is closest to Earth. How does that compare with the maximum angular diameter of Jupiter

Answers

Answer:

θ₂/ θ₁= 2.58

Explanation:

In this exercise you are asked to compare the angular diameters of Mars and Jupiter. The angular diameter or angle in radians is

           θ = D / R

where D is the diameter of the body, the distance from Earth to the body of interest and θ is angle in radians

The different distances are tabulated with respect to the Sun

Sun -Earth     1,496 10¹¹ m

Sun- Mars     2.28 10¹¹ m

Sun - Jupiter 7.78 10 m

The Radii of the planets are

Mars     3.37 10⁶ m

Jupiter 6.99 10⁷ m

let's calculate the angles for each body

a) Mars

       θ₁ = 2r / R'

         

the distance from the ground is

      R ’= D_planet - D_earth

      R ’= 2.28 10¹¹ - 1.496 10¹¹

       R ’= 0.784 10¹¹ m

let's calculate

       θ₁ = [tex]\frac{2 \ 3.37 \ 10^6 }{0.784 \ 10^{11}}[/tex]

        θ₁ = 8.6 10⁻⁵ radians

b) Jupiter

       R ’= 7.78 10¹¹ - 1.496 10¹¹

      R ’= 6.284 10¹¹ m

let's calculate

       θ₂ = [tex]\frac{2 \ 6.99 \ 10^7}{6.284 \ 10^{11}}[/tex]

        θ₂ = 2.22 10⁻⁴ radians

the ratio of the angular diameters is

       θ₂/ θ₁ = [tex]\frac{2.22 \ 10^{-4}}{8.6 \ 10^{-5}}[/tex]

        θ₂/ θ₁= 2.58

Other Questions
WeMoveU charges an hourly rate for a moving team to load and unload a truck. The charges is a different hourly rate for a team pack and unpack boxes. Use the quotes below to determine the company's hourly rates. Weekday Move: 5hours of loading and unloading services. 4 hours of packing and unpacking service. $730 total cost. Weekend Move: 4 hours of loading and unloading services. 5 hours of packing and unpacking services. $710 total cost. what is the frequency of a wave having a period equal to 18 seconds I WILL MARK BRAINLIST, HELP PLEASE#1.At the beginning of the season, McDonald had to remove 5 orange trees from his farm. Each of the remaining trees produced 210 oranges for a total harvest of 41790 oranges. How can scientists use stoichiometry to ensure that commercial products contain the components that manufacturers claim they do? Combine Like Terms:2x + 3 - 5x + 8x + 3x2 + 2Help please The number sports training camp has a maximum capacity of 250 students if 85 have preregistered then how many students can still participate ?Write and solve an inequality 3 PARAGRAPHS: WHY IS THE MIDDLE EAST SO IMPORTANT How many Head of cattle was a cowboy typically responsible for moving in a long drive ? Read the excerpt from The Canterbury Tales.For Ill have money, wool, and cheese, and wheat,Though given by the poorest serving-lad,Or by the poorest widow in the place,Were all her children dying of famine,No, no! Ill drink the ichor of the vine,And have a pretty girl in every town.But hear me out now, gentlemen . . .Which statement best describes the satire in the excerpt?The Pardoners poverty suggests that the Church is too stingy.The Pardoners excessive drinking underscores the need for moderation.The Pardoners indulgent spending draws attention to the need for restraint.The Pardoners disregard for the poor reveals the Churchs hypocrisy. Give an example of a two variable function that is not continuous at (1,2) . Explain why your example works. Who moved the capital from Rome to Byzantium?DiocletianJulius CesarConstantineJustinian Wind travels from areas of HIGH pressure to LOW pressure.A. TrueB. False How do you think the Crusades affected Muslim attitudes toward the Christian West? 15. COLLEGE COSTS The table shows some college costs. How much more is tuition thanthe cost of fees and room and board?ItemCost ($)Tuition8x + 75Feesx + 50Room and Boardx + 3 6. In a jar of 650 marbles, 20% of the marbles are red.How many marbles are not red PLEASE HELP!! DUE TONIGHT!!! ill give points plz help me PlZ NEED HELP WITH THIS answer please and thank you 9/10What do you need in order to fill out your 1040?Your W-2Your employer benefits documentationYour credit card statementYour job offer