Answer:
2
Explanation:
1) the formula of the energy is:
E=cm*Δt, where E - the value of the energy (5480 J.), c - the specific heat capacity (4200 J/(kg*C)), Δt - the difference between initial temperature and the final one (it is unknown);
2) if to perform the substitution of the values 'E', 'm' and 'c' into the formula above, then
5480=4200*0.65*Δt;
3) to calculate Δt:
Δt=5480/4200/0.65≈2 (°C).
note: the initial temperature is higher than the final.
What’s the difference between nonrenewable and renewable energy sources? Is biomass a renewable energy source?
Answer:
Yes, biomass is a renewable energy source
Explanation:
Biomass—renewable energy from plants and animals
Nonrenewable energy resources, like coal, nuclear, oil, and natural gas, are available in limited supplies. Renewable resources are replenished naturally and over relatively short periods of time.
Answer:
Explanation:
Nonrenewable energy resources, like coal, nuclear, oil, and natural gas, are available in limited supplies while renewable resources are replenished naturally and over relatively short periods of time. Yes, Biomass is renewable organic material that comes from plants and animals.
assume that the density of all solutions are 1.000g/ml 1. Calculate the molarity of calcium in 1.9g of calcium chloride diluted in 100 ml of Di water. 2 Calculate the concentration of both calcium and chloride lons in problem 1 in units of mg/mL, ug/L, mg/L and ug/mL. 3. Calculate the concentration of both calcium and chloride ion in problem 1 in units of ppm and ppb. You may assume that the density of the solution is 1.0 g/ml 4. You have been provided 100 ml of a 1000 ug/ml barium standard. What volume of this standard must be diluted to a final volume of 50 ml using DI water to produce a 30 ug/mL standard
Answer:
1. 0.1712M
2. 6.86mg/mL Ca, 12.14mg/mL Cl, 6860000ug/L Ca, 12140000ug/L Cl, 6860mg/L Ca, 12140mg/L Cl, 6860ug/mL Ca, 12140ug/mL Cl.
3. 6860ppm Ca and 12140ppm of Cl.
4. 1.5mL of the 1000ug/mL barium standatd must be taken.
Explanation:
1. Molarity is defined as the amount of moles of solute (Calcium chloride) present in 1L of solution.
The moles of CaCl₂ are:
1.9g CaCl₂ * (1mol / 110.98g) = 0.01712 moles
In 100mL = 0.10L:
0.01712mol / 0.10L = 0.1712M
2. The masses of Calcium and Chloride ions are:
1.9g * (40.078g Ca / 110.98g) = 0.686g Ca
And:
1.9g - 0.686g Ca = 1.214g Cl
mg/mL:
686mg Ca / 100mL = 6.86mg/mL Ca
1214mg Cl / 100mL = 12.14mg/mL Cl
ug/L:
686000ug / 0.1L = 6860000ug/L Ca
1214000ug/ 0.1L = 12140000ug/L Cl
mg/L:
686mg Ca / 0.1L = 6860mg/L Ca
1214mg Cl / 0.1L = 12140mg/L Cl
ug/mL:
686000ug Ca / 100mL = 6860ug/mL Ca
1214000ug Cl / 100mL = 12140ug/mL Cl
3. ppm are defined as mg/L, the ppm of Ca are 6860ppm Ca and 12140ppm of Cl
4. The solution must be diluted from 1000ug/mL to 30ug/mL, that is a dilution of:
1000ug/mL / 30ug/mL:
33.33 times must be diluted the solution.
As final volume of the diluted solution must be 50mL, the volume of the standard needed is:
50mL / 33.33 times = 1.5mL of the 1000ug/mL barium standatd must be taken
What type of element would form an ionic bond with iodine?
1. metalloid
2. solid
3. metal
4. nonmetal
Earth systems can interact quickly or over long periods of time. Give an example of how Earth can change quickly and an example of how it changes slowly. Describe how Earth's systems interact in these changes.
Answer:
Earth is made of several subsystems or "spheres" that interact to form a complex and continuously changing whole called the Earth system. to thousands of kilometers, and on time scales that range from milliseconds to billions of years of the Earth; earthquake; Examples of long term - making coal; plate tectonics
Explanation:
Which type of decomposer can produce chemicals that are harmful to plants?
O aerobic microorganisms
O earthworms
O centipedes
O anaerobic microorganisms
Classify each chemical reaction:
reaction
1. CH3CH2OH(f) → 3O2g + 2CO2 + 3H2Og
a. combination
b. precipitation
c. single replacement
d. combustion
e. double replacement
f. acid-base decomposition
2. MgI2 (aq) + Pb(NO3)2(aq) → Mg(NO3)2(aq) + PbI2(s)
a. combination
b. precipitation
c. single replacement
d. combustion
e. double replacement
f. acid-base decomposition
3. 16Ks + S8s → 8K2 + Ss
a. combination
b. precipitation
c. single replacement
d. combustion
e. double replacement
f. acid-base decomposition
4. CH4g + 2O2g → CO2g + 2H2Og
a. combination
b. precipitation
c. single replacement
d. combustion
e. double replacement
f. acid-base decomposition
Answer:
1) combustion
2) double replacement
3) combination
4) combustion
Explanation:
The combustion of a compound refers to the reaction of that compound with oxygen to produce heat and light. In reactions (1) and (4) above, ethanol and methane reacted with oxygen to yield carbon dioxde and water. This is a combustion reaction.
Reaction(2) is a double replacement reaction because the both cations exchange their anion partners in the product.
Reaction (3) is a combination reaction. It involves the joining of two elements to form a new compound.
pls help I’ll give allot of points I need all the answers pls anybody help!!!
How many grams of carbon dioxide (CO2) are produced from the combustion of 13.00 g of CH4?
Answer:
35.68g CO2
Explanation:
we use the combustion equation with CH4:
CH4+ O2= CO2 + H2O
And then balance it:
CH4+ 2O2= CO2 + 2H2O
Using this equation we can use sociometry:
[tex]13g CH4*\frac{1molCH4}{16.032gCH4} *\frac{1mol CO2}{1molCH4} *\frac{44g CO2}{1mol CO2}=35.68g CO2[/tex]
We know that 16.032 is how many grams there are in one mole of CH4 by adding the weights of the atoms (12 +1.008+1.008+1.008+1.008). These weights can be found on the periodic table. The same goes for the amount of grams per CO2.
The important thing about sociometry is to make sure your units cancel out until you are only left with the unit you want. If grams of CH4 is in the numerator, the next fraction you multiply by should have grams of Ch4 in the denominator. If moles of CO2 are in the numerator, the next fraction should have moles of CO2 in the denominator.
Which part of the landscape shown in this image is the steepest?
Answer: A I believe
Explanation:
What is the percent enantiomeric excess (ee) of a mixture that has 86% of one enantiomer and 14% of the other
Answer:
86% - 14% = 72%
Explanation:
True or False: In a graph the independent variable will always go on the side.
A.True
B.False
Answer:
False, the independent variable goes on the bottom
The statement “In a graph, the independent variable will always go on the side.” is false. The correct option is B.
What is a graph?A graph is a simple way of representing data. It shows the relation between two or more data with lines, numbers, and charts. The mathematical graphs are of different types. Mainly, a graph has a line and an x-axis and y-axis.
The x-axis contains the independent variable, which is written n the bottom of the graph, horizontally. The y-axis contains the dependent variable, which is written on the left side of the graph vertically.
The independent variable change, but the dependent variable do not change. It is the input. The independent variable changes with the time or what is written on the dependent variables.
Thus, the correct option is B. False.
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What type(s) of orbital overlap is(are) used to form the indicated bond in the following structure.
H H
\ /
C --- C O --- H
// \\ |
H --- C C --- C --- H
\ / |
C == C H
/ ↑ \
H H
A. sp3-s
B. sp2-s
C. sp2-sp2 (I chose C but it is incorrect)
D. sp3-sp2
E. sp3-sp3
F. p=p orbitals
need help plz asap .......
Answer:
Purple flowers
Explanation:
Usually the dominant allele is a capital letter.
From the question, purple flowers are dominant to white flowers while white are recessive.
PP = Purple
pp = White
Answer:
Mostly purple flowers itself
Which atom is oxidized in the reaction of benzhydrol with bleach?
Answer:
Which atom is oxidized in the reaction of benzhydrol with bleach?
Explanation:
n this experiment, students will perform a simple oxidation reaction of a secondary
alcohol. Recall that Oxidation Is a Loss of electrons while Reduction Is a Gain of electrons (OIL
RIG). In order to apply this mnemonic, you must know the oxidation states of each atom within
the compound, with particular interest on carbon. Carbon can carry oxidation states ranging
from -4 to +4. A few examples are shown in Figure 1 below. It is also common for carbon to
carry an oxidation state of -3, -1, +1, and +3.
Figure 1. Examples of carbon’s oxidation levels.
You may have noticed that all of the compounds in Figure 1 are neutral and carbon has
zero formal charge in each example. The concept of oxidation state and formal charge are
similar with one important difference in the calculation. Both are calculated by taking the
difference between the valence electrons (from the periodic table) and the number of electrons
belonging to that atom within the molecule. For a given atom, the valence electrons will never
change but the electrons ‘belonging’ the atom in the molecule will vary depending on number of
lone pairs and attachments to more or less electronegative atoms. The important difference in
the calculation of oxidation states and formal charge is based on the following assignment of
bonding electrons (Figure 2). This is how the highlighted carbon in ethanol can have an
oxidation state of -1 but a formal charge of zero.
- Oxidation states assign bonding electrons to the more electronegative atom in a bond,
except when the two atoms are the same and the bonding electrons are split equally.
Answer:
so the reaction would probably would be a chemical reaction
"When benzophenone reduces to diphenylmethanol, leftover products include the CH2OH and NaBH3 species. The energetic CH2OH and NaBH3 quickly bond to give (CH2OH)H3B-Na+. This complex is the main second product of benzophenone reduction."
Reactant Ratios
"In life, four benzophenone molecules react with each BH4 complex. Since four benzophenone molecules each attract a hydrogen atom from the “BH4” hydrogen donor, four “CH2OH”s bond with each boron (B) atom. Realistically, the secondary product is (CH2OH)4B-Na+ and four diphenylmethanol molecules. Focusing on one benzophenone molecule at a time is helpful for explaining and understanding reaction steps."
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Which of the following statements is NOT true about practice?
1. Making coffee or tea requires hot water to remove soluble components from the grounds or leaves. This is a separation process called extraction, removing a soluble component from solid material. What other separation technique is used to prepare the coffee or tea to drink
Answer:
The other technique which used to separate the coffee or tea is Filtration.
Filtration is a physical, biological or chemical operation that separates solid matter and fluid from a mixture with a filter medium that has a complex structure through which only the fluid can pass.
Solid particles that cannot pass through the filter medium are described as oversize and the fluid that passes through is called the filtrate.
In a coffee cup calorimeter, 1.60 g of NH4NO3 is mixed with 75.0 g of water at an initial temperature of 25.008C. After dissolution of the salt, the final temperature of the calorimeter contents is 23.348C. Assuming the solution has a heat capacity of 4.18 J 8C21 g21 and assuming no heat loss to the calorimeter, calculate the enthalpy change for the dissolution of NH4NO3 in units of kJ/mol.
Answer: ΔH for the dissolution of [tex]NH_4NO_3[/tex] is +26.0205 kJ/mol
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times C\times \Delta T[/tex]
Q = Heat released by solution = ?
C = heat capacity = [tex]4.18J/g^0C[/tex]
Initial temperature of water = [tex]T_i[/tex] = [tex]25.008^0C[/tex]
Final temperature of water = [tex]T_f[/tex] = [tex]23.348^0C[/tex]
Change in temperature ,[tex]\Delta T=T_f-T_i=(23.348-25.008)^0C=-1.66^0C[/tex]
Putting in the values, we get:
[tex]Q=75.0g\times 4.18J/g^0C\times -1.66^0C=-520.41 J[/tex]
As heat released by water is equal to heat absorbed by dissolution of [tex]NH_4NO_3[/tex]
[tex]\text{Moles of}NH_4NO_3=\frac{\text{given mass}}{\text{Molar Mass}}=\frac{1.60g}{80g/mol}=0.02mol[/tex]
Enthalpy change for 0.02 moles of [tex]NH_4NO_3[/tex] = 520.41 J
Enthalpy change for 1 mole of [tex]NH_4NO_3[/tex] = [tex]\frac{520.41}{0.02}\times 1=+26020.5J=+26.0205kJ[/tex]
ΔH for the dissolution of [tex]NH_4NO_3[/tex] is +26.0205 kJ/mol
A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur. Solution A: 2.37 % (m/v) NaCl Solution B: 0.59 % (m/v) glucose Solution C: distilled H2O Solution D: 9.39 % (m/v) glucose Solution E: 5.0% (m/v) glucose and 0.9% (m/v) NaCl
Answer:
A: 2.37 % (m/v) NaCl Solution: crenation.
B: 0.59 % (m/v) glucose Solution: hemolysis.
C: distilled H2O Solution: hemolysis.
D: 9.39 % (m/v) glucose Solution: crenation.
E: 5.0% (m/v) glucose and 0.9% (m/v) NaCl: neither.
Explanation:
A red blood cell should be placed in an isotonic solution to avoid crenation or hemolysis. An isotonic solution has the same solute concentration as the one in the interior of the cell. As a result, the solvent does not have to move toward the place with a higher solute concentration to balance it.
When the red blood cell is in a solution that has a higher concentration of solutes than the one inside the cell, in other words, the cell is in a hypertonic solution. The solvent will flow from the cell to the solution causing a crenation of the cell.
When the red blood cell is in a solution with a lower solute concentration than the one inside the cell, also known as a hypotonic solution. The solvent will flow from the outside to the inside of the cell. As a result, the cell suffers hemolysis.
The isotonic solution for the cell should be 5.0% (m/v) glucose and 0.9% (m/v) NaCl, to avoid crenation or hemolysis.
During burning, elements in the coal are
converted to compounds called ?
During burning, elements in the coal are converted to compounds called oxides.
An oxide is a compound formed by combination of an element with oxygen. Usually, when an element is burnt in oxygen, it combines with oxygen in the presence of heat to form oxides.
Coal contains carbon, nitrogen and sulfur. When coal is burnt, these elements combine with oxygen to form oxides. The products of combustion of coal are oxides of sulfur, oxides of carbon and oxides of nitrogen.
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Stainless steel's ability to resist rust is a _____ property
Answer:
corrosion resistance.
Explanation:
In summary, stainless steel does not rust because it is sufficiently reactive to protect itself from further attack by forming a passive corrosion product layer. (Other important metals such as titanium and aluminum also rely on passive film formation for their corrosion resistance.)
Plz help me I Am timed plz
Which of the following is an example of a nonrenewable resource?
OA) water
OB) grass
C) soil
D) trees
Answer:
D) Trees
Explanation:
I'm sure its trees, because once you cut all trees you cant regenerate, or replenish them. hope im right, sorry of its wrong!!
What is the biggest difference between thermal energy and temperature?
Answer:
Heat deals more with thermal energy whereas temperature deals with molecular kinetic energy.
3. A helium filled balloon has a volume of 39.0mL at 17C and the current atmospheric pressure is reading 802mmHg on the barometer. What volume will the helium gas take up when the pressure reading on the barometer drops to 637mmHg and the temperature plummets to 7C?
Answer:
.0466 L
Explanation:
To start off, use dimensional analysis to convert everything to standard PV=nRT units.
[tex]\frac{39.0}{1}[/tex] x [tex]\frac{1}{1000}[/tex] = .039 L
[tex]\frac{802}{1}[/tex] x [tex]\frac{1}{760}[/tex] = 1.055 atm
17 +273 = 290
...and so on.
Solve for n for the starting pressure, volume and temp. You'll need it for the final equation.
n= PV/RT [tex]\frac{1.055 *.039}{.0821 * 290}[/tex]= .0017 number of moles
Solve for volume of the end point.
V= nRT/P [tex]\frac{.0017*.0821*280}{.838}[/tex] = .0466 L of helium, or 46.6ml Less pressure means it will take up more space.
Cell walls provide shape and structure in plant cells.
True or False?
Answer:
Plant cells are surrounded by a cell membrane and outside this is a fairly rigid cell wall. The cell wall gives the plant cell a more definite shape than an animal cell. Animal cells do not have a cell wall.
Explanation:
True because It is flexible, but provides strength to the cell which helps protect the cell against physical damage. It also gives the cell its shape and allows the organism to maintain a certain shape o
Writing Sample: At what pressure would 0.150 mole of nitrogen gas at -23.0 o C occupy 8.90 L?
Answer:
[tex]P=0.346atm[/tex]
Explanation:
Hello!
In this case, since the ideal gas equation is:
[tex]PV=nRT[/tex]
And we are asked to compute the pressure, we obtain:
[tex]P=\frac{nRT}{V}[/tex]
Thus, since the temperature must be expressed in Kelvins, we plug in to obtain:
[tex]P=\frac{0.150mol*0.08206\frac{atm*L}{mol*K}*250.15K}{8.90L}\\\\P=0.346atm[/tex]
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Photosynthesis is a cell process used by various organisms. Which of the following best
describes the process of photosynthesis? (SC.8.L.18.1)
A.Carbon dioxide and water are turned into sugar and oxygen.
B.Sugar and oxygen are turned into water and carbon dioxide.
C.Oxygen and carbon dioxide are turned into water and sugar.
D.Water and sugar are turned into oxygen and carbon dioxide.
Answer:
Carbon dioxide and water are turned into sugar and oxygen
What type of particle has no mass or charge?
A) Alpha
B) Beta
C) Gamma
D) Proton
Answer:
Your answer would be C.
Explanation:
Gamma radiation, unlike alpha or beta, does not consist of any particles, instead consisting of a photon of energy being emitted from an unstable nucleus. Having no mass or charge, gamma radiation can travel much farther through air than alpha or beta, losing (on average) half its energy for every 500 feet.
Gamma particles has no mass or charge.
What are gamma radiations?Gamma radiations is a kind of radiations, which are emitted during a nuclear reaction. Gamma radiations are emitted in the form of photons of energy, they did not carry any particles like alpha, beta and proton. So, because of not carrying any particle this radiations have no mass and as it is on the form of energy they also do not carry any charge.
Hence, the particles which has no mass or charge is gamma.
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7. Which substance is an element?
Owater
O Oxygen
O petroleum
O carbon dioxide
Oxygen
hope that helped.
If 0.200 moles of NO are produced, how many moles of copper (I) nitrate produced?
Indicate which techniques are appropriate for preparing a dilute solution from a solid.
ACTION ANSWER
When reading the meniscus of a volumetric flask, your eye should be level with the etched line.
The solid should be weighed into a clean, dry beaker. If too much solid is added, the spatula should be used to remove some solid. The removed solid should be considered waste.
If the volumetric flask is over-filled with solvent above the etched line, the solution should be discarded as it is now inaccurate.
Once the solid is dissolved, fill the volumetric flask with solvent until the top of the meniscus is touching the etched line. Preparation is now complete
The solid should be weighed in a beaker and poured into the volumetric flask using a paper funnel.
The solid remaining in the beaker should be rinsed into the waste.
Once solid is dissolved, fill the volumetric flask with solvent until the bottom of the meniscus is touching the etched line. Then mix the solution. Preparation of the solution is now complete.
The solid should be weighed into a clean, dry beaker. If too much solid is added, the spatula should be used to remove some solid and return it to the reagent jar.
Answer:
When reading the meniscus of a volumetric flask, your eye should be level with the etched line.
If the volumetric flask is over-filled with solvent above the etched line, the solution should be discarded as it is now inaccurate.
Once solid is dissolved, fill the volumetric flask with solvent until the bottom of the meniscus is touching the etched line. Then mix the solution. Preparation of the solution is now complete.
Explanation:
When preparing a solution of a solid, the solid must be accurately weighed. After the solid is weighed, it is now carefully transferred to the volumetric flask.
The person preparing the solution must ensure that his/her eyes is at the same level as the flask. In event of adding water above the etched line. The solution must be discarded because it has exceeded the required concentration.
Once the solid has been transferred to the flask, water is added until the bottom of the meniscus is touching the etched line. The solution is now mixed and preparation of the solution is now complete.