3. Simplify the expression (x3 - 5x2 + 7x - 12) = (x – 4) using long division. Show your work.
Answer:

Answer:

14.3

Step-by-step explanation:

2.75 * 5.2=14.3

Answer:

48

Step-by-step explanation:

6 + 14 ÷ 7

= 8

= 8 _ 2× 3

= 8_ 6

=8×6

=48

Step-by-step explanation:

Given equations :-

Substitute (2) in (1) :-

Answer:

the equation is not completed

Answer:

-20

Step-by-step explanation:

Multiply 4x5 which is 20 but since 5 is negative then it's -20

Answer:

320

Step-by-step explanation:

64 by 5 equals 320

Answer:

320

Step-by-step explanation:

Divide 64 by 0.2

Answer:

33.176

Step-by-step explanation:

Answer:  Parallelogram

Step-by-step explanation:

Yes , a parelogram will come out ; and it can be proved by the Pythagorean theorem by completing the parallelogram to a rectangle

Answer:

the answer is 1.6

Step-by-step explanation:

1. 5 x 4 = A. 20

2.

[tex] \frac{2}{5} \times 25 = 2 \times 5 = 10[/tex]

the answer is D. 25

3.

[tex] \frac{3}{5} \div 15 = \frac{3}{5} \times \frac{1}{15} = \frac{1}{5} \times \frac{1}{5} = \frac{1}{25} [/tex]

the answer is A. 1/25

4.

[tex]4 \div \frac{1}{2} = 4 \times \frac{2}{1} = 8[/tex]

the answer is C. 8

5.

[tex]9 \div \frac{1}{3} = 9 \times \frac{3}{1} = 27[/tex]

the answer is D. 27

6.

[tex]20 \div \frac{1}{4} = 20 \times \frac{4}{1} = 80[/tex]

the answer is D. 80

7.

[tex] \frac{9}{10} \div \frac{1}{2} = \frac{9}{10} \times \frac{2}{1} = \frac{18}{10} = \frac{9}{5} = 1 \frac{4}{5} [/tex]

the answer is C. 1 4/5

8.

[tex]9 \div \frac{3}{2} = 9 \times \frac{2}{3} = \frac{18}{ 3} = 6[/tex]

the answer is B. 6

9.

[tex] \frac{3}{4} \div \frac{3}{8} = \frac{3}{4} \times \frac{8}{3} = 2[/tex]

the answer is A. 2

Explanation:

If we replaced y with 3 in choice A, then we get

2y-3 = 6

2(3)-3 = 6

6-3 = 6

3 = 6

which is a false statement. So choice A's solution is not y = 3. We can cross choice A off the list. The same applies with choices B and D as well.

Choice C is the answer because,

11y+4 = 37

11(3)+4 = 37

33+4 = 37

37 = 37

which is true. This confirms choice C.

Answer:

your answer is 3/15

Step-by-step explanation:

if im wrong pls let me know

Answer:

4u³

Step-by-step explanation:

2/3u × 4/2u² = 4/3u³

4/3u³ × 3/1 = 4u³

Answer:

Step-by-step explanation:

Answer: The time is 20:15 on a military time clock.

Step-by-step explanation:

Answer:

How old are you

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

because it doesn't pass through the origin.

Step-by-step explanation:

I would say 5 x= 8.5; x = 42.5 ounces that's my guess

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Answer:

3/20

Step-by-step explanation:

This is a division question.

The equation is 3/4 ÷ 5 or, to simplify this, 3/4 ÷ 5/1.

When you divide fractions you have to flip the second number and multiply the two fractions.

So, you have to do 3/4 x 1/5 which is 3/20.

Thus, the answer is 3/20.

Good luck!

Answer:

I dont understand ur question

The equation of a line is written as t = ax + b where a is the slope and b is the y-intercept.

Using the slope and y intercept given the equation is:

Y = 3x + 2

Answer:

x = 6

Step-by-step explanation:

Answer:

maybe it's d.

Step-by-step explanation:

because 30*6=180 and 50*3=150

so total of 330 as I observed

Answer:

subtract the 3x from one side and put in the other

4y = -3x -2

then divide both sides by 4

y= -3/4x -1/2

so the slope is-3/4

Answer:

−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3

Step-by-step explanation:

(p2qr+pq2r+pqr2)((−p)(q)+qr+−pr)

(p2qr)((−p)(q))+(p2qr)(qr)+(p2qr)(−pr)+(pq2r)((−p)(q))+(pq2r)(qr)+(pq2r)(−pr)+(pqr2)((−p)(q))+(pqr2)(qr)+(pqr2)(−pr)

−p3q2r+p2q2r2−p3qr2−p2q3r+pq3r2−p2q2r2−p2q2r2+pq2r3−p2qr3

−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that:

[tex]\sf\longmapsto(p^2qr+pq^2r+pqr^2)(-pq+qr-pr)[/tex]

Opening the brackets,

[tex]\sf\longmapsto p^2qr(-pq+qr-pr) + pq^2r(-pq+qr-pr) + pqr^2(-pq+qr-pr)[/tex]

Opening the next brackets,

[tex]\sf\longmapsto p^2qr(-pq)+ p^2qr(qr)- p^2qr(pr) + pq^2r(-pq)+ pq^2r(qr)- pq^2r(pr) + pqr^2(-pq)+ pqr^2(qr)- pqr^2(pr)[/tex]

So,

[tex]\sf\longmapsto -p^3q^2r+ p^2q^2r^2- p^3qr^2 - p^2q^3r+ pq^3r^2- p^2q^2r^2-p^2q^2r^2+ pq^2r^3- p^2qr^3[/tex]

[tex]\sf\longmapsto -p^3q^2r- p^3qr^2 - p^2q^3r+ pq^3r^2+ pq^2r^3- p^2qr^3+ p^2q^2r^2-2p^2q^2r^2 [/tex]

[tex]\sf\longmapsto -p^3q^2r- p^3qr^2 - p^2q^3r+ pq^3r^2+ pq^2r^3- p^2qr^3- p^2q^2r^2 [/tex]

Hence, the product is,

[tex]\longmapsto\bf -p^3q^2r- p^3qr^2 - p^2q^3r- p^2qr^3+ pq^3r^2+ pq^2r^3 - p^2q^2r^2 [/tex]

Answer:

Step-by-step explanation:

x ≥ 1

Hope this helps!

close circle = ≥ or ≤

open circle = > or <

positive number = going to the right

negative number = going to the left

Derivatives can be calculated from graphed functions.

The values of the derivatives are:

The given parameter is:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Start by calculating the equations of f(x) and g(x)

Graph f(x)

The slopes of f(x) are: 3/2 and -3/2

So, the equations are:

[tex]\mathbf{f(x) = \frac{3}{2}x,\ 0 \le x \le 2}[/tex]

[tex]\mathbf{f(x) = -\frac{3}{2}x,\ x \ge 2}[/tex]

Graph g(x)

The slope of g(x) is: -1/2

So, the equation is:

[tex]\mathbf{g(x) = -\frac 12x}[/tex]

For x = 1 and x = 2, we have:

So, we have:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Where:

[tex]\mathbf{f(x) = \frac{3}{2}x\ 0 \le x \le 2}[/tex] and [tex]\mathbf{g(x) = -\frac 12x}[/tex]

[tex]\mathbf{h(x) = f(g(x))}[/tex] becomes

[tex]\mathbf{h(x) = \frac{3}{2}(-\frac{1}{2}x)}[/tex]

Open brackets

[tex]\mathbf{h(x) = -\frac{3}{4}x}[/tex]

Differentiate

[tex]\mathbf{h'(x) = -\frac{3}{4}}[/tex]

So:

[tex]\mathbf{h'(1) = -\frac{3}{4}}[/tex]

[tex]\mathbf{h'(2) = -\frac{3}{4}}[/tex]

For x = 3, we have:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Where:

[tex]\mathbf{f(x) = -\frac{3}{2}x\ x \ge 2}[/tex] and [tex]\mathbf{g(x) = -\frac 12x}[/tex]

[tex]\mathbf{h(x) = f(g(x))}[/tex] becomes

[tex]\mathbf{h(x) = -\frac{3}{2}(-\frac{1}{2}x)}[/tex]

[tex]\mathbf{h(x) = \frac{3}{4}x}[/tex]

Differentiate

[tex]\mathbf{h'(x) = \frac{3}{4}}[/tex]

Substitute 3 for x

[tex]\mathbf{h'(3) = \frac{3}{4}}[/tex]

Hence, the values of the derivatives are:

[tex]\mathbf{h'(1) = -\frac{3}{4}}[/tex], [tex]\mathbf{h'(2) = -\frac{3}{4}}[/tex] and [tex]\mathbf{h'(3) = \frac{3}{4}}[/tex]

Read more about graphed functions at:

https://brainly.com/question/11804653

Answer:

A. A reflection over the x-axis

Answer:

this is A, a reflection over the x axis