Blank provide us with the actual rocks from inside Earth. They are considered blank evidence of

Answer: It detects any waves or any substance.

Explanation: Don't really know how to explain it but it detects specific stuff on every material, like a demand for Example, if it is real then it could scratch glass but glass couldn't scratch it.

A puck moves at 2.35 m/s in a -22° angle.It is pushed for 0.215 seconds by a hockey stick, changing its velocity to 6.42 m/s in a 50.0° direction. The negative sign indicates that the puck has fallen below its initial height.

How to solve the given problem with the help of trigonometry?

To solve the problem, we need to use the equations of motion and trigonometry.

First, let's find the initial velocity components:

[tex]\mathrm V_{i,x} = v_i cos(\theta_i) = 2.35 cos(-22^\circ) \approx 2.216\text{ m/s}[/tex]

[tex]\mathrm V_{i,y} = v_i sin(\theta_i) = 2.35 sin(-22^\circ) \approx -0.891\text{ m/s}[/tex]

where [tex]v_i[/tex] is the initial velocity and [tex]\theta_i[/tex] is the initial angle in degrees.

Next, we need to find the final velocity components:

[tex]\mathrm V_{f,x} = v_f cos(\theta_f) = 6.42 cos(50^\circ) \approx 4.121\text{ m/s}[/tex]

[tex]\mathrm V_{f,y} = v_f sin(\theta_f) = 6.42 sin(50^\circ) \approx 4.936\text{ m/s}[/tex]

where [tex]v_f[/tex] is the final velocity and [tex]\theta_f[/tex] is the final angle in degrees.

The change in velocity components are:

[tex]\Mathrm\Delta V_x = V_{f,x} - V_{i,x} \approx 1.905\text{ m/s}[/tex]

[tex]$\Delta V_y = V_{f,y} - V_{i,y} \approx 5.827\text{ m/s}[/tex]

The time of the push is t = 0.215 s.

Using the equation of motion, we can find the change in position in the y-direction:

[tex]$\Delta y = V_{i,y} t + \frac{1}{2} a_y t^2[/tex]

where a_y is the acceleration in the y-direction.

Since the puck is in flight, the only force acting on it is gravity, which causes an acceleration of [tex]-9.8 m/s^2[/tex] in the y-direction.

Plugging in the values, we get:

[tex]\Delta y = (-0.891\text{ m/s})(0.215\text{ s}) + \frac{1}{2} (-9.8\text{ m/s}^2)(0.215\text{ s})^2 \approx -0.139\text{ m}[/tex]

Note that the negative sign indicates that the puck has fallen below its initial height.

Therefore, the change in position in the y-direction is approximately 0.139 m.

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Answer:

0.434

Explanation:

The length and orientation of the road in a frame of reference that is moving with the given velocity  in a direction making an angle of 30 degrees with the road is calculated to be 2.641 meters and  16.83 degrees respectively.

Let's first calculate the velocity of the road in the frame of reference that is moving with a velocity of 0.6c. We can use the velocity addition formula to calculate this:

v' = (v - u) / (1 - uv/c²)

where

v = velocity of the road

u = velocity of the frame of reference = 0.6c

c = speed of light

Since the road is at rest in its own frame of reference, v = 0. Substituting the values, we get:

v' = (-0.6c) / (1 - 0.6c × 0 / c²)

v' = -0.8824c

The negative sign indicates that the road appears to be moving in the opposite direction in the moving frame of reference.

Now, let's calculate the length of the road in the moving frame of reference. We can use the length contraction formula to calculate this:

L' = L × √(1 - v'²/c²)

where

L = length of the road

v' = velocity of the road in the moving frame of reference

Substituting the values, we get:

L' = 5 × √(1 - (-0.8824c)²/c²)

L' = 2.641 meters

Therefore, the length of the road in the moving frame of reference is 2.641 meters.

Finally, let's calculate the orientation of the road in the moving frame of reference. We are given that the direction of the velocity of the frame of reference makes an angle of 30 degrees with the road. We can use the following formula to calculate the angle between the road and the velocity of the frame of reference in the moving frame of reference:

tan(e') = (tan(e) - u/c) / (1 - u×tan(e)/c)

where

e = angle between the road and the velocity of the frame of reference

u = velocity of the frame of reference = 0.6c

e' = angle between the road and the velocity of the frame of reference in the moving frame of reference

Substituting the values, we get:

tan(e') = (tan(30) - 0.6c/c) / (1 - 0.6c×tan(30)/c)

tan(e') = 0.294

Taking the inverse tangent, we get:

e' = 16.83 degrees

Therefore, the orientation of the road in the moving frame of reference is 16.83 degrees and the length of the road in the moving frame of reference is 2.641 meters.

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The complete question is :

Given a road of length 5 meters, calculate the length and orientation of the road in a frame of reference that is moving with a velocity of 0.6c in a direction making an angle of 30 degrees with the road.

According to the solving  the statement is correct. The work done on the car as it speeds up to 5.0 m/s is 22,500 J.

The work performed by a force is the sum of the movement and the component of something like the applied pressure of the object in the displacement direction. Work is accomplished when we push a block with a certain amount of force, "F," which causes the body to move with a certain amount of acceleration. Work completed is represented by the formula W = F.

KEf = (1/2)mv²

= (1/2)(1800 kg)(5.0 m/s)²

= 22,500 J

The work done on the car is equal to the change in kinetic energy:

W = KEf - KEi

= 22,500 J - 0 J

= 22,500 J

Therefore, the statement is correct. The work done on the car as it speeds up to 5.0 m/s is 22,500 J.

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I understand the the question you are looking for is:

If a 1800 kg car starts at rest and speeds up to 5. 0 m/s then the work done is?

The apparent weight of the pilot at the lowest point of the pullout 1040 N.

The centripetal force, F = mv²/r, where m is the mass of the pilot, v is her speed, and r is the radius of the circle. At the lowest point of the pullout, the radius of the circle is equal to the distance from the center of the circle to the point where the plane changes direction (i.e., the height above the ground).

Since the plane is diving vertically, the initial speed is, v₀ = √(2gh), where h is the initial height of the plane above the ground, and g is the acceleration due to gravity. At the lowest point of the pullout, all of the potential energy that the plane had at the start of the dive is converted into kinetic energy. Therefore, the speed, v = √(2gh).

Substituting the expressions for v and r into the expression for the centripetal force,

F = m * (2gh) / (2h) = mg

Therefore, the apparent weight of the pilot at the lowest point of the pullout is twice her actual weight,

2 * (53.0 kg * 9.81 m/s²) = 1040 N

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The engine is providing a forward force of 259,800 N to keep the train moving at a constant velocity.

What is forward force?

Forward force is the force applied in the direction of motion, which causes an object to move or maintain a constant velocity.

Constant velocity refers to the motion of an object moving in a straight line at a steady speed, without changing its direction. The velocity of the object is constant when its speed and direction remain unchanged over time, regardless of whether the object is moving or stationary.

Since the train is moving at a constant velocity, the net force acting on the train is zero. Therefore, the forward force provided by the engine must be equal in magnitude and opposite in direction to the force of air resistance and surface friction.

So, the magnitude of the forward force provided by the engine is:

Magnitude of forward force = Magnitude of force of air resistance and surface friction

Magnitude of forward force = 259,800 N

Therefore, the engine is providing a forward force of 259,800 N to keep the train moving at a constant velocity.

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Answer:

B. Disposition

Explanation:

In order for a delta to form, water must flow slowly so that the sediment can be deposited to create new landforms.

Answer: I think the answer is symbiotic tell me if I am right

Explanation:

Answer:

Symbiotic

Explanation:

Pathogenic relationships refer to things like microbes or viruses, think along the lines of how diseases spread throughout the body. One party is benefitted but the other is not.

'Microorganism' and 'macroorganism' refer to types of organisms rather than types of relationships.

Answer:

Current in first junction R1, R2 = 5 amps

Since current thru R2 = 3 amps the current thru R1 = 2 amps

V1 = V = I1 R1 = 15 volts

R1 = 15 volts / 2 amps = 7.5 ohms

Taking into account the definition of calorimetry, if 400 grams of water is to be heated from 24.0°C to 100.0°C to make a cup of tea, the heat added is 127254.4 J.

When heat absorbs or releases from a substance causes a temperature change in it without affecting its physical state (phase change), it is called sensible heat.

The expression that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the definition of sensible heat:

Q = 4.180 J/g∙C× 400 g× 76 C

Solving:

Q= 127254.4 J

Finally, the heat added is 127254.4 J.

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Both processes involve a change in the state of matter. In thermionic emissions, electrons are emitted from a solid metal surface to form a gas or plasma, while in liquid vaporization, a liquid is converted into a gas or vapor.

Liquid vaporisation, also known as evaporation, is the process by which a liquid transforms into its gaseous state at a temperature below its boiling point. This occurs due to the random motion of molecules in a liquid, where some of the molecules near the surface gain enough kinetic energy to overcome the intermolecular forces holding them together and escape into the air as a gas.

During the process of liquid vaporization, the liquid absorbs energy from its surroundings in the form of heat, which increases the average kinetic energy of the molecules and causes them to evaporate. The rate of evaporation depends on several factors such as temperature, humidity, and surface area of the liquid.

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Answer:

Different types of waves on the electromagnetic spectrum share the same speed, which is the speed of light in a vacuum, approximately 299,792,458 meters per second (or about 186,282 miles per second). All types of electromagnetic waves, including radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays, travel at the same speed in a vacuum. This is one of the fundamental properties of the electromagnetic spectrum.

The first two statements are false and the remaining three statements are true.

1. Magnetomotive force is the production of magnetic field by current in a conductor.

This statement is false. Magnetomotive force (MMF) is a measure of the strength of a magnetic field produced by a magnetic circuit, not by current in a conductor.

2. 25 mA is necessary for the coil with 4000 turns to produce 1000 A-T of MMF.

This statement is false. To produce 1000 A-T of MMF in a coil with 4000 turns, the current required would be:

MMF = N * I

1000 A-T = 4000 turns * I

I = 0.25 A or 250 mA

3. When unlike poles, that is, south and north poles, are placed close together, an attraction force is produced by the magnetic fields.

This statement is true. According to the laws of magnetism, opposite poles (north and south) attract each other, while like poles (north and north, or south and south) repel each other.

4. Magnetic lines of force never cross one another.

This statement is true. Magnetic lines of force (also known as magnetic field lines) are imaginary lines used to represent the direction and strength of a magnetic field. These lines are always continuous and form closed loops, never crossing one another.

5. When a magnetic field is moved past a stationary wire, there is relative motion.

This statement is true. According to Faraday's law of electromagnetic induction, a changing magnetic field induces an electromotive force (EMF) in a nearby conductor. This EMF causes current to flow in the conductor, creating a voltage.

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There is a requirement for 1,638,000 Joules of heat.

Q=I2Rt provides the Joule's heating formula. Joule's heating formula states that the amount of heat produced is proportional to the length of time that the electrical resistance and current are both constant.

The following equation must be used:

Q = m × Lfus + m × Cp × ΔT

Ethyl alcohol has a heat of fusion of 105 J/g and a specific heat capacity of 2.44 J/g°C.

The amount of ethyl alcohol is specified as 7.2 kg, or 7,200 g.

The ethyl alcohol must be melted at a temperature of:

Q1 = m × Lfus =

7,200 g × 105 J/g

= 756,000 J

In order to raise the temperature of the liquid ethyl alcohol from 0°C to 50°C, we must determine the amount of heat needed:

ΔT = 50°C - 0°C

= 50°C

The amount of heat required to raise the temperature of the liquid ethyl alcohol is:

Q2 = m × Cp × ΔT

= 7,200 g × 2.44 J/g°C × 50°C

= 882,000 J

As a result, the total amount of heat needed to transform 7.2 kg of solid ethyl alcohol from -211°C to 50.0°C into a liquid is:

Q = Q1 + Q2 = 756,000 J + 882,000 J

= 1,638,000 J

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The amount of work that Joe does to clear one path down his driveway is 1260 Nm.

The amount of work that Joe does to clear one path down his driveway is given by the product of the force he applies and the distance he moves the shovel:

Work = Force x Distance

In this case, the force is 10 N and the distance is the length of the driveway, which is 126 meters. Therefore:

Work = 10 N x 126 m = 1260 Nm

So Joe does 1260 Nm of work to clear one path down his driveway.

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The net work done during this process is -992 J. The negative sign indicates that work was done on the system, i.e. the gas lost energy to the surroundings.

W1 = (1 mol)(8.314 J/mol·K)(270 K) ln(3.5 L / 1 L) ≈ 5978 J

Next, the temperature is increased at constant volume, so no work is done:

W2 = 0

Then, the gas is compressed isothermally at 300 K to its initial volume, so we can use the same equation as before to calculate the work done:

W3 = (1 mol)(8.314 J/mol·K)(300 K) ln(1 L / 3.5 L) ≈ -6969 J

Finally, the gas is returned to its initial state, so the work done is:

W4 = 0

Therefore, the net work done is:

Wnet = W1 + W2 + W3 + W4 = 5978 J + 0 J - 6969 J + 0 J = -992 J

work done is defined as the product of force and displacement, where force is the amount of energy required to move an object and displacement is the distance over which the object is moved. Mathematically, work done is expressed as W = F x d, where W is the work done, F is the force applied and d is the displacement.

Work done can be positive, negative, or zero depending on the direction of force and displacement. When the force is in the same direction as displacement, work done is positive, when the force is in the opposite direction to displacement, work done is negative, and when the force and displacement are perpendicular, work done is zero.

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The Earth has four main interconnected systems: the atmosphere, the hydrosphere, the lithosphere, and the biosphere.

The model shows how all four systems interact with each other and influence each other. The atmosphere is responsible for controlling the climate and transferring energy through air currents and radiation. The hydrosphere includes all water on Earth, both frozen and liquid, and it is responsible for transporting water and energy. The lithosphere is made up of rocks, soil, and minerals, and it helps regulate and moderate the Earth's temperature. Finally, the biosphere is made up of all living things, and it influences and is influenced by all of the other systems.

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Answer:

1.076 m/s

Explanation:

Given a 3.0 kg fish is swimming at 1.5 m/s to the right. it swallows a 0.25 kg fish swimming to the left at 4.0 m/s. what is the speed and direction of the larger fish immediately after lunch?  

Mass of fish m1 = 3 kg

Velocity v1 = 1.5 m/s

Mass of small fish m2 = 0.25 kg

Velocity v2 = - 4 m/s (negative sign since the direction is opposite)

Therefore total mass of fish after swallowing will be M = 3 + 0.25 = 3.25 kg

Let the final velocity of fish be V

Now according to the law of conservation of momentum we have

     So m1v1 + m2v2 = M x V

           3 x 1.5 + 0.25 x – 4 = 3.25 x V

               4.5 – 1 = 3.25 V

                   3.25 V = 3.5

                     Or V = 1.076 m/s

So speed of the fish will be 1.076 m/s

Ionizing smoke detectors contain an isotope that undergoes alpha decay (such as americium-241) because alpha particles are more ionizing than beta or gamma particles.

What is Isotopes?

Isotopes are variants of an element that have the same number of protons in their atomic nuclei but differ in the number of neutrons. This means that isotopes of the same element have the same atomic number (which determines the element's chemical properties) but different atomic masses.

In an ionizing smoke detector, the alpha particles emitted by the radioactive source ionize the air in the detector's chamber, creating a current that is detected by a circuit. When smoke particles enter the chamber, they attach to the ions and reduce the current, triggering the detector's alarm.

Alpha particles are heavier and have a higher charge than beta or gamma particles, which means they interact more strongly with matter and create more ionization as they travel through air. This makes them more effective at ionizing the air in the detector's chamber, and therefore more sensitive to the presence of smoke particles.

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Answer:

4000 km

Explanation:

Answer: 1,6 KM

Explanation:

To determine the distance from the epicenter of an earthquake if P waves take 12 minutes to arrive, we need to use the formula:

distance = (time * 8) / 60

where "time" is the time it takes for the P waves to arrive in minutes, and "distance" is the distance from the epicenter in kilometers.

Substituting the given value of time, we get:

distance = (12 * 8) / 60

distance = 1.6 kilometers

Therefore, the distance from the epicenter of the earthquake is approximately 1.6 kilometers.

Answer:

a) We can use the following formula to calculate the acceleration of the object:

a = (v_f - v_i) / t

where a is the acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time interval. Substituting the given values, we get:

a = (90 m/s - 40 m/s) / (2 min * 60 s/min) = 0.83 m/s^2

The force applied causing it to speed up can be found using Newton's second law of motion:

F = m * a

where F is the net force, m is the mass of the object, and a is the acceleration. Substituting the given values, we get:

F = 0.05 kg * 0.83 m/s^2 = 0.042 N

Therefore, the force applied causing the object to speed up is 0.042 N.

b) The work done by this force can be calculated using the following formula:

W = F * d

where W is the work done, F is the net force, and d is the displacement of the object. The displacement of the object is given by:

d = 670 m

Substituting the given values, we get:

W = 0.042 N * 670 m = 28.14 J

Therefore, the work done by the force is 28.14 J.

c) The work done by friction can be calculated using the formula:

W_friction = F_friction * d

where W_friction is the work done by friction, F_friction is the force of friction, and d is the displacement of the object. The force of friction can be calculated using:

F_friction = μ * F_norm

where μ is the coefficient of friction and F_norm is the normal force. The normal force is equal to the weight of the object, which is given by:

F_weight = m * g

where m is the mass of the object and g is the acceleration due to gravity. Substituting the given values, we get:

F_weight = 0.05 kg * 9.81 m/s^2 = 0.49 N

The normal force is equal in magnitude to the weight of the object, so we have:

F_norm = F_weight = 0.49 N

Substituting the given coefficient of friction, we get:

F_friction = 0.34 * 0.49 N = 0.17 N

The work done by friction can now be calculated by substituting the values we have found:

W_friction = 0.17 N * 670 m = 113.9 J

Therefore, the work done by friction is 113.9 J.

d) The net work done can be calculated as the sum of the work done by the applied force and the work done by friction:

W_net = W_applied + W_friction

Substituting the values we have found, we get:

W_net = 28.14 J + 113.9 J = 142.0 J

Therefore, the net work done is 142.0 J.

The period of motion of the electron is 2.09 × 10^-6 seconds.

Period of motion can be defined as the time it takes for an object to complete one full cycle of its motion. In the context of circular motion, the period is the time it takes for an object to travel around a full circle and return to its starting position.

The period of motion, T, of an object moving in a circle can be calculated using the following formula:

T = 2πr/v

Where

In this case, the electron moves in a circular path with a radius of 0.20 m at a constant speed of 1.5 × 10^5 m/s. Plugging these values into the formula gives:

T = 2π(0.20 m) / (1.5 × 10^5 m/s)

T = 2.09 × 10^-6 s

Therefore, the period of motion of the electron is 2.09 × 10^-6 seconds.

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Answer:

The skateboarder has 2400 J of kinetic energy. We can use the formula for kinetic energy to find the speed:

KE = 1/2 mv^2

KE = 1/2 (68 kg) (v^2)

2400 J = 1/2 (68 kg) (v^2)

2400 J = 34 kg v^2

2400 J / 34 kg = v^2

70.59 m/s = v^2

If you jumped at an angle, it would depend on the angle you jumped at and the speed you jumped at. If you jumped at an angle that was greater than the escape velocity of 12 m/s, you would be able to escape.

An angle is a figure formed by two rays, or line segments, that extend from a common endpoint. It is a measure of the amount of turn between the two rays. The angle is measured in degrees, with a full circle being 360 degrees. Angles can be acute, obtuse, right, reflex, or straight. Acute angles measure less than 90 degrees, whereas obtuse angles measure more than 90 degrees. Right angles measure exactly 90 degrees, reflex angles are greater than 180 degrees, and straight angles measure exactly 180 degrees.

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The spring can not cross the hill.

Elastic potential energy is the potential energy stored in an object when it is deformed, or stretched or compressed, by a force. When an elastic object is stretched or compressed, it has the potential to return to its original shape and size, and the work done to stretch or compress it is stored as elastic potential energy.

We know that;

E = 1/2Ke^2

E = 0.5 * 3600 * (5 * 10^-2)^2

E = 4.5 J

Now the GPE of the hill is;

mgh = 50 * 10^-3 * 10 * 9.8

= 4.9 J

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This is because the higher the marble is released, the more potential energy it has.

Potential energy is the energy that is stored in an object due to its position, shape, or composition. This energy is released when the object is disturbed from its current state. Potential energy can be found in many different forms, such as gravitational, elastic, chemical, electrical, magnetic, and nuclear energy. Gravitational potential energy is the energy of an object due to its vertical position, and is calculated by multiplying its mass by the gravitational acceleration and its height. Elastic potential energy is the energy stored in a deformed material, such as a spring, that is released when the material returns to its original shape.

This potential energy is converted to kinetic energy as the marble rolls down the ramp, and this kinetic energy determines how far the marble will travel away from point A. The higher the initial potential energy, the further the marble will travel.

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Answer:

Originally Sonu and image is 8 m (4 m to mirror and 4 m to image)

If he moves 1 m towards the mirror the image distance will be reduced to  (c) 6 m

Explanation:

The angle of the plane is directly correlated to the shape of the elliptical shape cut out. When the plane is at a low angle, the resulting elliptical shape cut out is also much shorter in length. Conversely, when the plane is at a steep angle, the resulting elliptical shape cut out is much longer in length.

This is because the angle of the plane determines the amount of material that will be removed when the plane is used to cut the elliptical shape. When the plane is at a low angle, less material is removed, thus producing a shorter elliptical shape. When the plane is at a steep angle, more material is removed, thus producing a longer elliptical shape.

In addition, the angle of the plane also affects the depth of the elliptical shape cut out. When the plane is at a low angle, the resulting elliptical shape is shallow. Conversely, when the plane is at a steep angle, the resulting elliptical shape is deep.

The work required to bring the third charge from very far away to the point P is approximately 36 millijoules (to two significant figures). The units are joules (J).

To calculate the work required to bring the third charge q3 from very far away to the point P, we need to know the electric potential at point P due to the other two charges q1 and q2. The electric potential at point P is given by:

V = kq1/r1 + kq2/r2

U = q3 V

where q3 is the charge of the third charge.

r1 = 0.1 m

r2 = 0.2 m

q1 = -2 μC = -2 × 10^-6 C

q2 = 3 μC = 3 × 10^-6 C

Substituting these values into the electric potential formula, we get:

V = kq1/r1 + kq2/r2

V = (9 × 10^9 N m^2/C^2) × [(-2 × 10^-6 C)/0.1 m + (3 × 10^-6 C)/0.2 m]

V ≈ 9000 V

final = q3 V

final = (4 μC) × (9000 V)

final = 36000 μJ

final = 36 mJ

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