Assuming a Stop-and-Wait system, if the bandwidth-delay product of a channel is 500 Mbps and 1 bit takes 25 milliseconds to make the roundtrip, what is the bandwidth-delay product? If the data packets are 2500 bits in length, what is the utilization?

Answer:

This is the instance method inc_num_kids()

def inc_num_kids(self):

       self.num_kids += 1

Explanation:

The first line is the definition of function inc_num_kids() which has a parameter self. self is basically an instance of  class PersonInfo

self.num_kids += 1 this statement incremented the data member num_kids by 1. This means that the instance method inc_num_kids, using instance self, increments the value of num_kids data member by 1.

The complete program is as following:

class PersonInfo:  #class name PersonInfo

   def __init__(self):   #constructor of the class

       self.num_kids = 0  # data member num_kids

   def inc_num_kids(self):  # method inc_num_kids

       self.num_kids += 1  #increments num_kids by 1

person1 = PersonInfo()  #creates object person of class PersonInfo

print('Kids:', person1.num_kids)  # prints num_kids value before increment

person1.inc_num_kids()  #calls inc_num_kids method to increment num_kids

print('New baby, kids now:', person1.num_kids) #prints the value of num_kids after increment by inc_num_kids method

The person1 object first access the initial value of num_kids initialized by the constructor. So the first value of num_kids is 0. self.num_kids = 0  This statement assigns the value 0 to num_kids data member. Next the method inc_num_kids() using the object person1. Now when this method is called the value of data member num_kids is incremented to 1.

So previously the value was 0 which now increments by 1 and becomes 1. Last print statement displays this new value which is incremented by the inc_num_kids() method.

Hence the output is:

Kids: 0

New baby, kids now: 1

The program along with its output is attached.

In this exercise we have to use the knowledge of computational language in python to describe a code, like this:

The code can be found in the attached image.

To make it easier the code can be found below as:

class PersonInfo:  

  def __init__(self):  

      self.num_kids = 0  

  def inc_num_kids(self):  

      self.num_kids += 1  

person1 = PersonInfo()

print('Kids:', person1.num_kids)  

person1.inc_num_kids()

print('New baby, kids now:', person1.num_kids)

See more about python at brainly.com/question/26104476

Answer and Explanation:

public class petData

{

private int ageYears;

private String fullName;

private int IdNumber;

public void setName (String givenName)

{

fullName = givenName;

return;

}

public void setAge (int numYears)

{

ageYears = numYears;

return;

}

public void setID (int numID)

{

IdNumber = numID;

return;

}

public void printAll ()

{

System.out.print ("Name: " + fullName);

System.out.print (", Age: " + ageYears);

return;

}

}

From the above, we have defined a class petData, with methods setName, setAge, printAll. These methods all make use of the string variable fullName and integer variable ageYears. From the above, setName method sets fullName variable to name given to its string parameter givenName while setAge method does the same with the ageYears variable in initializing it. This is also done by the ID method. These variables are then used by printAll method in printing out the Name and age of the object which would be created with the petData class

E. g: petData dog= new petData();

Answer:

val = int(input("Enter a positive odd value "))

flag = True # let the number entered is alreay prime

if(val > 2 and val%2 == 1):  # prime numbers start from 2

   half = int(val/2);

   for div in range(2,half):  # dividing the number from 2 to half of its number

       if(val % div == 0): # if completely divisible

           print("Not prime")

           flag = False   # Changing the status of prime number as false

           break

   if(flag == True):

       print(val, "is a prime number")

else:

   print("Invalid input, Please Enter a valid positive odd number")

Explanation:

Steps:

1. Let us take input from the user using input() method.

2.  Initially, let the number is prime.

3. If the number is negative or even, the go to else part and ask the user for a valid input and terminate the program by giving a message to user.

(We actually check for values greater than 2 because 1 is not considered as  a prime number)

4. If the number is positive and odd, then we keep on dividing the number from 2 to half of its number.

(We actually check for values greater than 2 because 1 is not considered as  a prime number)

5. If the number is divisible, we change the status to False and break the loop.

6. If the flag is still True, we print that it is a Prime number else we print that it is not a prime number.

Please refer to the comments section as well and the attached image for proper indentation of the program.

Answer:

false

Explanation:

Answer:

Here is the C program :

#include<stdio.h>  // to use input output functions

   int main(){  //start of main() function body

   int n;  //to store the number of tests taken

   int test_scores[n], i;  //a variable length array test_score

   float sum=0,average;  //to store the sum and average of test scores

   int lowest;   //to store the lowest test score

   printf("Enter the number of tests taken :");//prompts user to enter number of test scores

   scanf("%d",&n); /  / reads the value of n from user

   printf("Enter test scores: ");  //prompts user to enter test scores

for(i=0; i<n; i++)  {  

 scanf("%d",&test_scores[i]);  //read the values of input test scores

 sum = sum + test_scores[i];   } //calculates the sum of the test scores by adding the values of test scores

        average=sum/n;  // compute the average by dividing sum of all test scores with the total number of test scores

               printf("Average is %.2f",average);  //displays the average

    printf("\nGrade is ");  // prints Grade is

    if (average >= 90) {  //if value of average is greater than or equal to 90

       printf("A");     }  //print the grade letter A

else if(average >= 80 && average < 90)  { //if value of average is greater than or equal to 80 and less than 90

 printf("B");  }   //print the grade letter B

else if(average>60 && average<80){ //if value of average is between 60 and 80

 printf("C");  }  //print the grade letter C

else if(average>40 && average<=60) {  //if value of average is greater than 40 and less than or equals to 60

 printf("D");  }  //print the grade letter D

else  {  //if the value of average is below 40

 printf("F");  }   //print the grade letter F

   lowest = test_scores[0];     //lowest points to the 1st element of test scores means the first input test score

   for (int j = 1; j < n;j++)     {  //loop iterates through the scores

       if (test_scores[j] < lowest)   {  // if the element at j-th index position of test_scores array is less than the element stored in the lowest variable

          lowest = test_scores[j];     }     } //then assign that element value of test_score to the lowest

     printf("\nLowest test score is:  %d.\n", lowest); } //displays the lowest test score

Explanation:

The program is well explained in the comments mentioned with each statement of the code.

The program prompts the user to enter the number of test scores as they are not already specified in the array because array test_scores is a variable length array which means its length is not fixed. The program then prompts the user to enter the test scores. The program then adds all the test scores and store the result in sum variable. Then it computes the average by dividing the value in sum variable to the number of test scores n. Then in order to determine the letter Grade the average value is used. The if else conditions are used to specify conditions in order to determine the Grade. Next the lowest score is determined by setting the value of lowest variable to the first element of the test_scores array. Then using for loop, the index variable j moves to each array element i.e. score and determines if the the value of element is less than that stored in the lowest variable. If the value positioned at j-th index of test_scores is less than that of lowest than this value is assigned to lowest. At last the lowest holds the minimum of the test scores.

Answer:

int ComputeFibonacci(int N) {

   if(N == 0)

       return 0;

   else if (N == 1)

       return 1;

   else

       return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);

}

Explanation:

Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.

For example,

If N = 4 as in the main part:

ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3

ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2

ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0  = 1

*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and  ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.

Answer:

It is a C++ program  :

#include <iostream>  // to use input output functions

using namespace std;  //to identify objects like cin cout

//following are the prototypes for the four functions placed above main

void displayMenu();  

void findSquareArea();  

void findCircleArea();

void findTriangleArea();

//definition for constant PI out of main

const float PI = 3.14159;  

int main(){  //start of main function

displayMenu(); //calls displayMenu() method

}

  void displayMenu(){  // to make user selection and calls relevant function to compute area according to the choice of user

int selection=0;  //to choose from 4 options

cout<<"Program to calculate areas of objects:\n" ;  //displays this message at start

do  {  //this loop asks user to enter a choice and this continues to execute and calculate depending on users choice until user enters 4 to exit

cout<<"\n1.Square \n2.Circle \n3.Right Triangle \n4.Quit";

cout<<"\nEnter your choice:";  //prompts user to enter choice

cin>>selection;  //reads the input choice

if(selection==1)  //if user enters 1

{  //computes area of square by calling findSquareArea

findSquareArea();  //function call to the findSquareArea function

}  

else if(selection==2)  //if user enters 2

{  //computes area of circle by calling findCircleArea

findCircleArea();  //function call to the findCircleArea function

}  

else if(selection==3)   //if user enters 3

{  //computes area of triangle by calling findTriangleArea

findTriangleArea();  //function call to the findTriangleArea function

}  

else if(selection==4)   //if user enters 4

{  

cout<<"\nTerminating!!.";  //exits after displaying this message

break;

}

else  // displays the following message if user enters anything other than the given choices

{

cout<<"\nInvalid selection";  //displays this message

}

}

while(1);  

}  

void findSquareArea(){  //function definition. this function has no parameters

float area=0.0;  //variable to store the area of square

float side=0;  //local variable of this method that stores value of side of square

cout<<"\nLength of side: ";  //prompts user to enter length of side

cin>>side;  //reads value of side from user

area=side*side;  //formula to compute area of square and result is assigned to area variable

cout<<"\nArea of Square: "<<area<<endl;   //displays are of the square

}  

void findCircleArea(){  //function definition. this function has no parameters

float area=0.0;  //variable to store the area of square

float radius=0.0;  //local variable of this method that stores value of radius of circle

cout<<"\nRadius of circle: ";  //prompts user to enter radius of circle

cin>>radius;  // reads input value of radius

area=PI*radius*radius;  //formula to compute area of circle

cout<<"\nArea of circle: "<<area<<endl;}  //displays are of the circle

void findTriangleArea(){  //function definition. this function has no parameters

   float area=0.0;  //variable to store the area of triangle

   float base=0.0;  //local variable of this method that stores value of base of triangle

   float height=0.0;  //holds value of height of triangle

cout<<"\nHeight of Triangle: ";  //prompts user to enter height

cin>>height;  //reads input value of height

cout<<"\nBase of Triangle: "; //prompts user to enter base

cin>>base;  //reads input value of base

area=0.5*height*base;  //computes area of triangle and assign the result to area variable

cout<<"\nArea of Triangle: "<<area<<endl;  //displays area of triangle

}

Explanation:

The program is modified as above. The prototypes for the four functions that are named as :

void displayMenu();  to display the Menu of choices and call relevant function to compute area

void findSquareArea();  To compute area of square

void findCircleArea(); To compute area of circle

void findTriangleArea();  To compute area of triangle

Note that these methods have no parameters and their return type is void. These 4 methods prototypes are placed above main() function.

Next the function definitions (consisting of a function header and initially empty body) for the four functions are written and placed below main() For example definition of findTriangleArea() is given below:

void findTriangleArea()

{

}

Next the code in the main is moved to the relevant methods. Then variables selection=0;  is moved to displayMenu method,  radius=0.0 to findCircleArea method , side=0; to findSquareArea float area=0.0;  to each method, float height=0.0;  and float base=0.0; to findTriangleArea method.

The relevant code moved to each method is shown in the above code.

The definition for the named constant PI is moved out of main and placed above the main function. const keyword before datatype of PI variable shows that PI is declared constant and its value is initialized once only to 3.14159.

Answer:

Here is the JAVA program:

Items.java

public class Item {  // Item class

private String name, ph_num;  // class data members name to hold the name and ph_num stores the telephone numbers

public Item(String fullName, String PhoneNo){  //constructor of Item class , so fields full name and ph_num can be initialized when the object is created

name = fullName;  // holds the name field

ph_num = PhoneNo;}  //holds the telephone number

public String getFullName(){  // accessor method to get access to the name field

return name;}  //returns the name from directory

public String getPhoneNo(){  //accessor method to get access to the ph_nujm field

return ph_num; } } //returns the telephone number

Explanation:

LookupTable.java

public class LookupTable{  //class name

private ArrayList<Item> data;  // dynamic array list named data of Item class. This array list stores the names and telephone numbers from file

public LookupTable(){  //default constructor

data = new ArrayList<Item>();}  // creates an array list of Item type which holds the names and phone numbers

public void read(Scanner in){  // Scanner class object is created and this class is used to read input and the method reads the names and phone numbers

while(in.hasNext()){  // the loop moves through each line of the file. scanner class method hasNext checks for the tokens in the input

String name = in.nextLine();  // scans for the name in the input

String ph_num = in.nextLine();  //scans for the phone numbers in the input

data.add(new Item(name, ph_num));}}  // adds the names and phone number in to the Array list

public String lookup(String k){  //method looks up for an item in the table.  param k is the key to find . returns the value with the given key, or null if no       such item was found

String result = null;  //result initialized to to null

for(Item item: data){  //creates Item object and traverses the array list for each item i.e. name or phone numbers

if(k.equals(item.getFullName())){  //access the getFullName method through object item and checks if that name matches the key to find.

result = item.getPhoneNo();}}  //gets the corresponding phone number and assigns it to result variable

return result;}  //returns the result containing the phone number

public String reverseLookup(String v){  //Looks up an item in the table. param v is the value to find . returns the key with the given value, or null if no  such item was found. This method performs the lookup through phone number

String result = null;  //result is set to null to start

for(Item item: data){  //Traversing list through the for each item in data  

if(v.equals(item.getPhoneNo())){  //if the value of v is equal to the phone number accessed by using accessor method and object item

result = item.getFullName();}}  //accesses the corresponding name of that phone number and assigns it to the result

return result;}}  //returns the result                                

The data from directory file which contains the number and names. The LookupTable class has a method lookup which handles the lookups by names and the method reverseLookup that handles the lookups by phone number.  

Answer:

age = int(input("Enter your age: "))

charge = 0

if age > 55:

   charge = 10

if 21 <= age <= 54:

   charge = 15

if 13 <= age <= 20:

   charge = 10

if 3 <= age <= 12:

   charge = 5

if 0 <= age < 3:

   charge = 0

print(charge)

Explanation:

*It is in Python.

Ask the user for the age

Check the each given range and set the charge accordingly using if statements

Print the charge

Answer:

Here is the next_number method:

def next_number(self): #method to return next number in the sequence

    temporary = self.back1 + self.back2 # adds previous number to next number and stores the result in a temporary variable

    self.back2 = self.back1 #Updates back2 with the former value of back1,

    self.back1 = temporary #update back1 with the new next item in the sequence.

    return temporary #

Explanation:

I will explain the working of the above method.

back1 = 1

back2 = 0

At first call to next_number()  method:

temporary = back1 + back2

                 = 1 + 0

temporary = 1

self.back2 = self.back1

self.back2 = 1

self.back1 = temporary

self.back1 = 1

return temporary

This return statement returns the value stored in temporary variable i.e. 1

Output: 1

back1 = 1

back2 = 1

At second call to next_number()  method:

temporary = back1 + back2

                 = 1 + 1

temporary = 2

self.back2 = self.back1

self.back2 = 1

self.back1 = temporary

self.back1 = 2

return temporary

This return statement returns the value stored in temporary variable i.e. 2

output: 2

back1 = 2

back2 = 1

At second call to next_number()  method:

temporary = back1 + back2

                 = 2 + 1

temporary = 3

self.back2 = self.back1

self.back2 = 2

self.back1 = temporary

self.back1 = 3

return temporary

This return statement returns the value stored in temporary variable i.e. 3

Output: 3

back1 = 3

back2 = 2

At second call to next_number()  method:

temporary = back1 + back2

                 = 3 + 2

temporary = 5

self.back2 = self.back1

self.back2 = 3

self.back1 = temporary

self.back1 = 5

return temporary

This return statement returns the value stored in temporary variable i.e. 5

Output: 5

back1 = 5

back2 = 3

At second call to next_number()  method:

temporary = back1 + back2

                 = 5 + 3

temporary = 8

self.back2 = self.back1

self.back2 = 5

self.back1 = temporary

self.back1 = 8

return temporary

This return statement returns the value stored in temporary variable i.e. 8

Output: 8

Calling next_number 5 times would print 1, 2, 3, 5, and 8.

The complete program along with its output is attached.

Answer:

The answer is "\root"

Explanation:

Answer:

15

Explanation:

for seamless playback each packet should be played before their predecessor so

4th packet will start at 12:01:03

3rd packet will start at 12:00:48

2nd packet will start at 12:00:33

1st packet will start at 12:00:18

as first packet arrives at 12:00:03 so wait time is 15 seconds for seamless playback

Answer:

Early in the history of technology, the development of tools and machines was based on technical know-how versus scientific knowledge as is done today.

Explanation:

In the era prior to technological development, men had a basic and at times rudimentary manufacturing development, based on artisan processes that developed their tools and machinery by hand, without any type of automation or mass production rules.

Thus, each part or tool was manufactured in a unique way, which required a broad mastery of the production process by the manufacturer. This is how the first professions began to emerge, such as blacksmiths for example, who mastered the technique of manufacturing different implements and carried them out without any scientific knowledge.

Answer:

SQRRR or SQ3R is a reading comprehension method named for its five steps: survey, question, read, recite, and review. The method was introduced by Francis P. Robinson, an American education philosopher in his 1946 book Effective Study. The method offers a more efficient and active approach to reading textbook material

Answer:

Following are the code to this question:

/*using the select statement, that selects column name from the table blog.posts */  

SELECT blog.posts.user_id, blog.posts.body, users.name/*column name user_id, body, name*/  

FROM blog.posts/* use table name blog.posts*/

RIGHT OUTER JOIN users ON blog.posts.user_id = users.id;/*use right join that connect table through user_id*/

Explanation:

In the structured query language, RIGHT JOIN  is used to recovers from both the right side of the table both numbers, although the left table has no sets. It also ensures that even if the 0 (null) documents are linked inside this left table, its entry will always return the outcome row, but still, the number of columns from its left table will be NULL.

In the above-given right join code, the select statements used that selects the column names "user_id, body, and the name" from the table "blog. posts" and use the right join syntax to connect the table through the id.    

Answer:

scope

Explanation:

An Open Authorization refers to a method  that helps to share data using third party services without giving your credentials and there is a mechanism in an Open Authorization that allows to limit the access that the third party app has to an account that is called scope. Because of that, the answer is that an Open Authorization (OAuth) access token would have a scope that tells what the third party app has access to because it is what limits the access the app has to an account and it shows the access given in a consent screen.

Answer:

The program written in python is as follows

def countchr(phrase, char):

     count = 0

     for i in range(len(phrase)):

           if phrase[i] == char:

                 count = count + 1

     return count

phrase = input("Enter a Phrase: ")

char = input("Enter a character: ")

print("Occurence: ",countchr(phrase,char))

Explanation:

To answer this question, I made use of function

This line defines function countchr

def countchr(phrase, char):

This line initializes count to 0

     count = 0

This line iterates through each character of input phrase

     for i in range(len(phrase)):

This line checks if current character equals input character

           if phrase[i] == char:

The count variable is incremented, if the above condition is true

                 count = count + 1

The total number of occurrence is returned using this line

     return count

The main method starts here; This line prompts user for phrase

phrase = input("Enter a Phrase: ")

This line prompts user for a character

char = input("Enter a character: ")

This line prints the number of occurrence of the input charcater in the input phrase

print("Occurence: ",countchr(phrase,char))

Answer:

Following are the answer to this question:

Explanation:

There will be several ways to provide it, although it is simpler to let another front side Will work out a three-way handshake or transfer packages to there with a Server chosen. Its application responds TCP packets with both the destination node of the front end.

The very first packet was sent to a computer as an option. Mention, even so, that perhaps the end of the queue end remains in the loop in this scenario. Rather than obtaining this information from the front end like in the primary healthcare services, you have the advantage of this capability: its selected server helps to generate TCP state.

Answer:

Decommission/Recycle

Explanation:

This specific scenario that is being described belongs to the final stage of the hardware lifecycle known as Decommission/Recycle. This is when the asset in question has completed its function for an extended period of time and is no longer functioning at maximum efficiency and/or newer hardware has hit the market. Once in this stage, the hardware in question is either repaired or scrapped for resources that can be used to create newer products.

Answer:

In C++ it can be written as:

if(cost>=50&&cost<=75)

   { cout<<"The cost is in the desired range";}

In Python:

if(cost <= 75 and cost>= 50):

   print("The cost is in the desired range")

Explanation:

cost>50&&cost<75 covers the requirement that cost should be between 50 and 75 dollars

But the whole statement cost>=50&&cost<=75 covers the requirement that cost should be between 50 and 75 dollars and message should also be displayed if the cost is exactly 50 dollars or exactly 75 dollars. For example if the value of cost=50 then this message The cost is in the desired range is displayed.

In the above program && in C++, and in Python is used which is a logical operator which means that both the conditions cost <= 75 and cost>= 50 should be true for the if condition to evaluate to true. For example if cost=35 then this message is not printed because both the conditions are false i.e. 35 is neither less than or equal to 75 nor greater than or equal to 50.

Answer:

Required code present in image attached

Explanation:

At first, the subquery (i.e., the inner query) will execute one time before executing the main query (i.e., outer query).  This sequence is important since the result from the subquery is being utilized for when the main query executes to produced the desired outcome. The final result will be obtained after the last line of code executes.

Answer:

Because if you don't do it BIOS doesn't support it. ... In troubleshooting a boot problem what would be the point of disabling the quick boot feature in BIOS setup

Explanation:

Answer:

I am writing a C++ program:

#include <iostream>  //to use input output functions

#include<iomanip>  // to format the output

using namespace std;   // to identify objects like cin cout

void calculateCharge(double weight, double distance);   // function prototype

int main(){  //start of main() function body

  double w = 0.0, t = 0.0;  // w variable is for weight and t is for total

   unsigned int d = 0;   // d variable is to hold the value of distance

   calculateCharge(w, d); }  //calls calculateCharge method by passing weight and distance values to this method

void calculateCharge(double weight, double distance){  //method that takes weight and distance as parameters and compute the shipping charge

   double charge = 0.0;  //to store the value of shipping charges

   do {  // do while loop to handle multiple packages until a weight of 0 is entered

       cout << "Enter weight: " << endl;  //prompts user to enter weight

       cin >> weight;  //reads the input weight value

       if (weight == 0){  // if the value of weight is equal to 0

           break; }  // the loop breaks if value of weight is 0

       cout << "Enter distance: " << endl;  // if value of weight is not zero then the program precedes by prompting user to enter the value of distance

       cin >> distance;  //reads the input distance value

       cout << fixed << setprecision(2) << endl;  //set the precision to 2 means the sets the number of digits of an output to 2 decimal places

       if(weight <= 2)  //if the value of weight is less than or equals to 2

charge = (distance/500) * 3.10;  //compute the charge by this formula

else if(weight > 2 && weight <= 6)  //if weight is over 2 kg but not more than 6 kg

charge = (distance/500) * 4.20;  //charge is computed by multiplying value of distance to that of weight and if distance is greater than 500 then it is divided by 500 first

else if(weight > 6 && weight <= 10)  // if weight is over 6 kg but not more than 10 kg

charge = (distance/500) * 5.30;  //compute shipping charges by this formula

else  //if weight is over 10 kg

charge = (distance/500) * 6.40;   // compute shipping charge by multiplying value of distance to that of 6.40 weight value and if distance is greater than 500 then distance is divided by 500 first

cout << "Shipping charges: $" << charge << "\n";   //display the computed shipping charge

   } while (weight != 0);  //the loop continues to execute until weight 0 is entered

}              

Explanation:

The program is explained in the comments mentioned above. The program has a main() function that declares variable for weight, distance and total and then calls calculateCharge() method passing weight and dsitance in order to compute and return the shipping charge.

In calculateCharge() the user is prompted to enter the values for weight and distance. Then the based on the value of weight , the shipping charge is computed. Shipping charge is computed by multiplying the weight with distance. The distance is assumed to be 500 but if the distance entered by user exceeds 500 then the distance value is divided by 500 and then multiplied by the specified weight (according to if or else if conditions) in order to compute shipping charge. The program has a do while loop that keeps taking input from user until the user enters 0 as the value of weight.

The screenshot of the program and its output is attached.

Answer:

Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?

Explanation:

Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?

Answer:

c. Create a lookup relationship between the Candidate and Interview objects.

d. Create a trigger on the Interview object that updates a field on the Candidate object.

Explanation:

Objects relationships is considered a form of field type that joins two or more objects together such that, after understanding objects and fields, it creates some form of bonding known as object relationships. This helps define security on interview records that is independent from the security on candidate records.

For an example, in a standard object like Account, where a sales representative opens an account, and has had interviews or chats with a few people at that account’s company, and as well made contacts with the likes of executives or IT managers and still stored those contacts’ information in salesforce.

Hence, what would a developer do to accomplish this task is to:

1. Create a lookup relationship between the Candidate and Interview objects.

2. Create a trigger on the Interview object that updates a field on the Candidate object.

Answer:

Total amount of O₂ occupy volume = 76.50 L

2 .30 gm O₂ occupy volume = 7.48 L

Explanation:

We konw that,

Molar mass of O₂ = 31.9988 gm / mol

1 mole of O₂ = 31.9988 gm

Sample of oxygen = 0.600 mole

Computation:

0.600 mole = 31.9988 × 0.600

0.600 mole = 19.199 gm

Total amount of O₂ = 4.30 + 19.199

Total amount of O₂ = 23.499 gm

Total amount of O₂ occupy volume = 14 × 23.499/4.30

Total amount of O₂ occupy volume = 76.50 L

Total gm of O₂ = 4.30 - 2.00= 4.30 gm

2 .30 gm O₂ occupy volume = 14 × 2.30/4.30

2 .30 gm O₂ occupy volume = 7.48 L

Answer:

10 minutes

Explanation:

Answer:

The program written in python is as follows;

import string

def easyCrypto(inputstring):

      for i in range(len(inputstring)):

             try:

                    ind = string.ascii_lowercase.index(inputstring[i])

                    pos = ind+1

                    if pos%2 == 0:

                           print(string.ascii_lowercase[ind-1],end="")

                    else:

                           print(string.ascii_lowercase[ind+1],end="")

             except:

                    ind = string.ascii_uppercase.index(inputstring[i])

                    pos = ind+1

                    if pos%2 == 0:

                           print(string.ascii_uppercase[ind-1],end="")

                    else:

                           print(string.ascii_uppercase[ind+1],end="")

anystring = input("Enter a string: ")

easyCrypto(anystring)

Explanation:

The first line imports the string module into the program

import string

The functipn easyCrypto() starts here

def easyCrypto(inputstring):

This line iterates through each character in the input string

      for i in range(len(inputstring)):

The try except handles the error in the program

             try:

This line gets the index of the current character (lower case)

                    ind = string.ascii_lowercase.index(inputstring[i])

This line adds 1 to the index

                    pos = ind+1

This line checks if the character is at even position

                    if pos%2 == 0:

If yes, it returns the alphabet before it

                           print(string.ascii_lowercase[ind-1],end="")

                    else:

It returns the alphabet after it, if otherwise

                           print(string.ascii_lowercase[ind+1],end="")

The except block does the same thing as the try block, but it handles uppercase letters

             except:

                    ind = string.ascii_uppercase.index(inputstring[i])

                    pos = ind+1

                    if pos%2 == 0:

                           print(string.ascii_uppercase[ind-1],end="")

                    else:

                           print(string.ascii_uppercase[ind+1],end="")

The main starts here

This line prompts user for input

anystring = input("Enter a string: ")

This line calls the easyCrypto() function

easyCrypto(anystring)