It will take approximately 3.01 seconds for the pendulum bob to swing back to the person.
To answer this question, we need to find the period of the pendulum and then calculate the time it takes for the pendulum to swing back to the person.
Step 1: Calculate the period of the pendulum
The formula for the period of a simple pendulum is given by:
T = 2π√(L/g)
where T is the period.
L is the length of the cable (9.01 m), and g is the acceleration due to gravity (approximately 9.81 m/s²).
Step 2: Plug in the values and solve for T
T = 2π√(9.01 m/9.81 m/s²)
T ≈ 2π√(0.918 s²)
T ≈ 2π(0.958 s)
T ≈ 6.02 s
The period of the pendulum is approximately 6.02 seconds.
Step 3: Calculate the time it takes for the bob to swing back to the person
Since the period represents the time it takes for the pendulum to complete one full oscillation, and the person releases the bob at its highest point, the time it takes for the bob to swing back to the person is half of the period.
Therefore, we can calculate this time as follows:
Time to swing back = T/2
Time to swing back ≈ 6.02 s/2
Time to swing back ≈ 3.01 s.
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describe two similarities and two differences between electric and magnetic field lines. (consider such things as where they originate and terminate, how they are related to the direction and strength of the field, whether they are closed curves or lines, and whether there's anything you can say about their flux through a closed surface.). others?? display keyboard shortcuts for rich content editor
Two similarities between electric and magnetic field lines are:
1. Direction: Both electric and magnetic field lines represent the direction of the force exerted on a charged particle or a magnetic pole.
Electric field lines originate from positive charges and terminate at negative charges, while magnetic field lines show the direction a north magnetic pole would move within the field.
2. Field strength: In both electric and magnetic fields, the field strength is proportional to the density of the field lines. More closely spaced lines indicate a stronger field, and the strength decreases as the lines become farther apart.
Two differences between electric and magnetic field lines are:
1. Origin and termination: Electric field lines originate from positive charges and terminate at negative charges, indicating the direction of the electric force.
Magnetic field lines, however, form closed loops, as they originate from the north pole of a magnet and terminate at the south pole, representing the continuous nature of the magnetic field.
2. Flux through a closed surface: For electric fields, the net electric flux through a closed surface is proportional to the total enclosed charge, as described by Gauss's Law.
In contrast, for magnetic fields, the net magnetic flux through any closed surface is always zero.
This is because magnetic field lines form closed loops, and there are no isolated magnetic poles (monopoles) in nature, which means that the magnetic field lines that enter a closed surface must also exit it.
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a 2.3-m-long pole is balanced on its tip. it starts to fall and its lower end does not slip. what will be the speed of the upper end of the pole just before it hits the ground?
The speed of the upper end of the pole just before it hits the ground is approximately 6.03 m/s.
We can make use of energy saving to resolve this issue.
Due to its height above the earth, the pole has potential energy when it is balanced on its tip.
This potential energy is transformed into kinetic energy as it descends, and kinetic energy is proportional to the square of the speed of the pole's upper end.
The speed of the upper end just before it touches the earth can be determined using the energy conservation principle.
PE = mgh,
where m is the pole's mass, g is gravity's acceleration,
and h is the pole's height above the earth, calculates the pole's potential energy when it is balanced on its tip.
We can disregard the pole's mass for the time being because it cancels out when we apply the principle of conservation of energy.
The pole has lost half of its potential energy when its upper end is at a height h/2 above the ground, which is equivalent to
PE = (1/2) mgh.
KE = (1/2) mv2,
where v is the speed of the pole's upper end just before it strikes the earth, represents the transformation of this potential energy into kinetic energy.
When we divide the kinetic energy obtained by the potential energy lost, we get.
[tex](1/2) mgh = (1/2) mv^2[/tex]
Since the pole's mass balances out, we can determine v:
v equals sqrt(gh)
By replacing the specified numbers,
Substituting the given values, we get:
v = [tex]\sqrt{(9.81 m/s^2 x 2.3 m) }[/tex]
= 6.03 m/s
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9. When electromagnetic radiation of frequency 1.5 x 1014 Hz is incident on a metal surface, the
maximum kinetic energy of the emitted photoelectrons is found to be 3.8 x 10-20 J. Calculate the
work function of the metal.
10. Photons of electromagnetic radiation having energies of 1.0 eV, 2.0 eV and 4.0 eV are incident on a
metal surface having a work function of 1.7 eV.
a) Which of these photons will cause photoemission from the metal surface?
b) Calculate the maximum kinetic energies (in eV and J) of the liberated electrons in each of
those cases where photoemission occurs.
Answer:
9. Using the equation KEmax = hf - Φ, where KEmax is the maximum kinetic energy of the emitted photoelectrons, h is Planck's constant, f is the frequency of the radiation, and Φ is the work function of the metal, we can rearrange to find Φ:
Φ = hf - KEmax
Φ = (6.63 x 10^-34 J s)(1.5 x 10^14 Hz) - 3.8 x 10^-20 J
Φ = 9.94 x 10^-20 J
Therefore, the work function of the metal is 9.94 x 10^-20 J.
10. a) Only photons with energies greater than or equal to the work function of the metal (1.7 eV) will cause photoemission. Thus, the photon with an energy of 2.0 eV and the photon with an energy of 4.0 eV will cause photoemission, but the photon with an energy of 1.0 eV will not.
b) For the photon with an energy of 2.0 eV:
KEmax = hf - Φ
KEmax = (6.63 x 10^-34 J s)(3.2 x 10^14 Hz) - 1.7 eV
KEmax = 3.23 x 10^-19 J or 2.0 eV
For the photon with an energy of 4.0 eV:
KEmax = hf - Φ
KEmax = (6.63 x 10^-34 J s)(6.4 x 10^14 Hz) - 1.7 eV
KEmax = 5.13 x 10^-19 J or 4.0 eV
two waves travel at the same speed. the frequency of wave a is 1000 hz, and the frequency of wave b is 4000 hz. wavelength a is
Answer:
Explanation:
B
Two waves travel at the same speed. The frequency of wave A is 1000 Hz, and the frequency of wave B is 4000 Hz. Wavelength A is 0.25 meters.
Wavelength, frequency, and speed are interrelated in a mathematical relationship known as the wave equation:
v = fλ
Where: v = velocity of the wave
f = frequency
λ = wavelength
The velocity of a wave is equivalent to the product of its wavelength and frequency. In addition, since the two waves in this situation are traveling at the same speed, their wavelengths are inversely related to their frequencies. As a result, the formula for wavelength is:
wavelength = velocity/frequency
Substituting the given values in the equation,
wavelength A = velocity/frequency A
wavelength A = 300/1000
wavelength A = 0.3 meters
The frequency of wave A is 1000 Hz, and the frequency of wave B is 4000 Hz. Wavelength A is 0.3 meters.
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which statements about population 1 stars are true? question 21 options: our sun is a population 1 star population 1 stars are mostly found in the halo of our galaxy population 1 stars would include bright supergiant stars population 1 are older than population 2 stars heavy elements within population 1 stars make up 1-4% of the total stellar mass
The true statements about population 1 stars are: Our Sun is a population 1 star, Population 1 stars would include bright supergiant stars and Heavy elements within population 1 stars make up 1-4% of the total stellar mass.
The population 1 stars are stars that are rich in heavy elements, which are also known as metal-rich stars. These stars are known for having relatively high metallicity, which is the abundance of elements heavier than hydrogen and helium. Population 1 stars are young, and most of them are found in the disk of our Milky Way galaxy.
They are located in areas with a higher concentration of gas and dust. This contrasts with population 2 stars, which are typically old, metal-poor stars that are found in the halo of the galaxy. In general, population 1 stars include main-sequence stars, red giant stars, and bright supergiant stars. The heavy elements within these stars, including carbon, nitrogen, and oxygen, make up a significant portion of their total stellar mass, around 1-4%.
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calculate the smallest value for the coefficient of friction necessary that would keep the block from moving
With the given values of W and d, we can find the smallest value for the coefficient of friction necessary to keep the block from moving.
To calculate the smallest value for the coefficient of friction necessary to keep the block from moving, we can use the formula for static friction:
static friction (fs) = coefficient of static friction (μs) × normal force (N)
Since we know the work done (200 J) and want to find the smallest value for the coefficient of friction (μs), we can use the work-energy theorem, which states:
Work = change in kinetic energy = 0 (since the block is not moving)
Work = force (F) × distance (d) × cos(θ)
200 J = μs × N × d × cos(θ)
Now, let's consider the forces acting on the block.
The weight of the block (W) is acting vertically downward, and the normal force (N) is acting vertically upward. In this case, the angle (θ) between the force and the direction of motion is 0 degrees,
so cos(θ) = 1.
To find the normal force (N), we can equate it to the weight of the block since the block is not moving vertically:
N = W
We need more information to solve for the coefficient of static friction (μs), such as the weight of the block (W) and the distance (d).
Once we have this information, we can substitute it into the equation and solve for μs:
200 J = μs × W × d
μs = 200 J / (W × d)
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A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other.
A) Find its moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet.
B) Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its two ends.
(A) Moment of inertia about an axis that passes through the intersection of the two segments, Ia = 1/12 ML². (B) Moment of inertia travelling via the intersection of the line's two ends and midpoint, Ix = 1/3 ML²
(A) The moment of inertia about an axis passing through the intersection of the two segments will be the same if the rod is bent at the centre and the distance between all of the points and the axis stays constant i.e. Ia = 1/12 ML²
(B) Calculate the moment of inertia on a line connecting the two ends and passing through a point midway along it.
Determine the distance between the ends as a first step ( d )
After utilizing Pythagoras's principle
d =√2/2L
Determine the distance between the two axes as the next step ( x )
After utilizing Pythagoras's principle
x =√3/4/L
Compute the value of Ix as the last step.
the Parallel Axis Theorem is applied
Iₓ = Iₐ + Mx²
Iₓ = 1/12ML² + 1/4 ML²
Iₓ = 1/3ML²
This leads us to the following conclusions: Moment of inertia passing through the place where the two segments meet is Ia = 1/12 ML², about an axis: Moment of inertia passing through the point where the line's midpoint meets its two ends is Ix = 1/3 ML²
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Suppose one speaker is driven at 570 Hz and the other at 554 Hz. What is the beat frequency in Hz? The average frequency in Hz?
____________ Hz (beat frequency)
_____________ Hz (average frequency)
The beat frequency is 16 Hz and the average frequency is 562 Hz.
When two sound waves of slightly different frequencies are played simultaneously, the resulting sound wave will have a fluctuation in amplitude known as beats. The beat frequency is the difference between the two frequencies.
The beat frequency is the absolute difference between the frequencies of the two speakers.
Beat frequency = |570 Hz - 554 Hz| = 16 Hz
The average frequency is the arithmetic mean of the two frequencies.
Average frequency = (570 Hz + 554 Hz) / 2 = 562 Hz
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if the strings can withstand a maximum tension of 92.0 n, what maximum acceleration can the elevator have before the upper string breaks?
The maximum tension that a string can withstand is given as 92.0 N. We want to find out what the maximum acceleration that the elevator can have before the upper string breaks. Therefore, we cannot find the acceleration without knowing the mass of the elevator.
To find the maximum acceleration, we need to consider the forces acting on the elevator. There are two forces: the force due to gravity (weight) and the tension in the string (upward force).Since the elevator is moving upwards, the acceleration will be in the same direction as the tension force.
Therefore, we can set up an equation that relates the tension and the acceleration:
[tex]F_{net}[/tex] = T - mg where[tex]F_{net}[/tex] is the net force (which is equal to ma), T is the tension in the string, m is the mass of the elevator, and g is the acceleration due to gravity.
Substituting [tex]F_{net}[/tex] and T in the equation and solving for a, we get: a = (T - mg) / m .
The tension in the string is given as 92.0 N, and the mass of the elevator is not given. Therefore, we cannot find the acceleration without knowing the mass of the elevator.
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an electron is traveling in the negative y direction (of a cartesian coordinate system). a uniform electric field is present and oriented in the negative z direction. if a uniform magnetic field with the appropriate magnitude and direction is simultaneously generated in the region of interest, the net force on the electron can be made to have a magnitude of zero. what must the direction of the magnetic field be?
The direction of the magnetic field must be in the positive x direction to make the net force on the electron have a magnitude of zero.
To find the direction of the magnetic field that makes the net force on the electron zero, we can use the following steps:
Step 1: Identify the direction of the electric force
The electric force on the electron is in the direction of the electric field.
Since the electric field is in the negative z direction, the electric force on the electron will also be in the negative z direction.
Step 2: Identify the direction of the magnetic force
The magnetic force on a charged particle can be determined using the Lorentz force equation: F = q(v x B),
where F is the magnetic force, q is the charge of the particle, v is the velocity vector of the particle, and B is the magnetic field vector.
The cross product (v x B) indicates that the magnetic force is perpendicular to both the velocity and the magnetic field.
Step 3: Determine the direction of the magnetic field
Since the electron is traveling in the negative y direction, we need to find a magnetic field direction such that the magnetic force on the electron is in the positive z direction (to cancel out the electric force).
Using the right-hand rule, the appropriate direction of the magnetic field is in the positive x direction.
In conclusion, the direction of the magnetic field must be in the positive x direction to make the net force on the electron have a magnitude of zero.
This is achieved by ensuring the magnetic force on the electron is equal in magnitude but opposite in direction to the electric force acting on it.
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How can the concept of unstable equilibrium be used in the design of everyday objects such as switches or alarms?
Answer:
The concept of unstable equilibrium can be used in the design of everyday objects such as switches or alarms by ensuring that an object is positioned in a way that requires a small amount of force to cause it to tip over and trigger the switch or alarm.
For example, in a light switch, the switch lever can be designed to be in a position where it is balancing on a pivot point, such that a slight push up or down will cause it to tip one way or the other, and thus activate or deactivate the switch.
Similarly, in an alarm system, a small amount of force applied to a specific point can tip over a weight, causing it to fall and trigger the alarm.
By using unstable equilibrium designs in the design of switches or alarms, the objects can be made more sensitive and responsive to user actions, without requiring a significant amount of force to activate them.
After crude oil is pumped out of the ground, it must be processed in a cracking tower. The tower separates it into less dense chemicals like butane and gasoline, and more dense chemicals like diesel fuel and tar. Based on this information, crude oil can best be classified as a –
Responses
A mixtures of compounds.mixtures of compounds.
B mixture of pure substances.mixture of pure substances.
C pure substance.pure substance.
D solution of heterogeneous substances.
Based on the information provided, crude oil can best be classified as a mixture of compounds which is option A.
The fact that it can be separated into different chemicals with varying densities indicates that it is not a pure substance. Additionally, the components of crude oil are not chemically bonded together in a specific ratio, which is a characteristic of mixtures. Finally, the components of crude oil are not uniformly distributed, which rules out the possibility of it being a solution of heterogeneous substances. Therefore, option A, a mixture of compounds, is the best classification for crude oil based on the given information.
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Wave-particle duality of matter
17. Calculate the de Broglie wavelength associated with each of the following:
a) A bullet of mass 25g moving at a velocity of 280 ms¹¹.
b) A sprinter of mass 90kg moving at a velocity of 11 ms¹.
c) An electron of mass 9.11 x 10-31 kg moving at a velocity of 2.0 x 107 ms ¹.
a) For the bullet, we have:
p = mv = 0.025 kg × 280 m/s = 7.0 kg m/s
λ = h/p = 6.626 × 10^-34 J s / 7.0 kg m/s = 9.47 × 10^-36 m
b) For the sprinter, we have:
p = mv = 90 kg × 11 m/s = 990 kg m/s
λ = h/p = 6.626 × 10^-34 J s / 990 kg m/s = 6.70 × 10^-37 m
c) For the electron, we have:
p = mv = 9.11 × 10^-31 kg × 2.0 × 10^7 m/s = 1.82 × 10^-23 kg m/s
λ = h/p = 6.626 × 10^-34 J s / 1.82 × 10^-23 kg m/s = 3.64 × 10^-11 m
a particle moving at a velocity of 9.7 m/s in the positive x direction is given an acceleration of 1.4 m/s 2 in the positive y direction for 2.9 s. what is the final speed of the particle? answer in units of m/s.
The final speed of the particle is 10.7 m/s (approx).
Velocity of the particle = 9.7 m/s, Acceleration of the particle = 1.4 m/s²Time duration = 2.9 s. We need to find the final speed of the particle. We know that the velocity of a particle with a uniform acceleration can be given as:v = u + at Where, v = Final velocity of the particle, u = Initial velocity of the particle, a = acceleration of the particle, t = Time duration
Now, The initial velocity of the particle = 9.7 m/s (in the positive x direction)Therefore, the final velocity of the particle in the x direction will remain the same as the initial velocity. vx = ux = 9.7 m/s Also, we know that the acceleration of the particle in the y direction can be given as:
ay = 1.4 m/s²Now, the final velocity of the particle in the y direction can be calculated as: v = u + atv = 0 + ay tv = 1.4 × 2.9 = 4.06 m/s. The resultant velocity of the particle can be calculated using Pythagoras' theorem: v = √(vx² + vy²)v = √(9.7² + 4.06²)v = 10.7 m/s
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A 9.0-V battery costs $3.00 and will deliver 0.0250 A for 26.0 h before it must be replaced. Calculate the cost per kWh.
Answer:
it is 17 dollars .
Explanation:
I had a test like this and I remember the qeustions
A 9.0-V battery costs $3.00 and will deliver 0.0250 A for 26.0 h before it must be replaced. then the cost per kWh is $512.82.
What is energy ?
Energy is nothing but the ability to do work. there are different energies in different form which are thermal energy, mechanical energy, electric energy and sound energy etc. According to first law of thermodynamic, Energy neither be created nor be destroyed. it can only be transferred from one form into another form. Energy is expressed in joule (J). its dimensions are [M¹ L² T⁻²].
The energy delivered by the battery can be calculated using the formula:
energy = power x time
where power is the product of voltage and current, and time is given in hours.
The power delivered by the battery is:
power = voltage x current = 9.0 V x 0.0250 A = 0.225 W
The time for which the battery will deliver this power is 26.0 hours.
So, the energy delivered by the battery is:
energy = power x time = 0.225 W x 26.0 h = 5.85 Wh
To convert Wh to kWh, we divide by 1000:
energy = 5.85 Wh ÷ 1000 = 0.00585 kWh
The cost per kWh can be calculated by dividing the cost of the battery by the energy delivered, and then multiplying by 1000 to convert to dollars per kWh:
cost per kWh = (3.00 dollars / 0.00585 kWh) x 1000 = 512.82 dollars/kWh (rounded to two decimal places)
Therefore, the cost per kWh for this battery is $512.82.
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a fairground ride spins its occupants inside a flying saucer-shaped container. if the horizontal circular path the riders follow has a radius of 1 1 . 0 m 11.0 m, at what angular velocity will the riders be subjected to a centripetal acceleration whose magnitude is equal to 1.50 times the acceleration due to gravity? report you answer in units of revolutions/minute.
he angular velocity at which the riders will be subjected to a centripetal acceleration whose magnitude is equal to 1.50 times the acceleration due to gravity is: 10.986 rev/min.
The formula for the centripetal acceleration is as follows:
ac=ω2r
where ac = centripetal acceleration,
ω = angular velocity, and r = radius.
We are given the following values:
ac = 1.50g = 1.50(9.81 m/s2) = 14.715 m/s
2r = 11.0 m
Substituting these values into the formula, we get:14.715 m/s2 = ω2(11.0 m)
Rearranging the equation, we get:ω2 = 14.715 m/s2 / (11.0 m)ω2 = 1.3386
Taking the square root of both sides, we get:ω = 1.1577 radians/s
Converting this value to revolutions per minute, we get:ω = (1.1577 rad/s) / (2π rad/rev) x (60 s/min)ω = 10.986 rev/min
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at 1000 hz did the rms voltage across the capacitor agree with the value v0/sqrt(2)? should these values havea agreed?
Yes, the RMS voltage across the capacitor should have agreed with the value of V0/√2 at 1000 Hz.
A capacitor has a voltage that alternates with time. This voltage varies as a sinusoidal waveform, similar to AC voltage. The RMS voltage across a capacitor is defined as the voltage that would produce the same heating effect as the capacitor's voltage if applied continuously.
The RMS voltage is used to represent the voltage of an AC circuit. When the AC voltage applied to a capacitor reaches its peak, it is V0, and the RMS voltage is V0/sqrt(2).
This is the voltage that would produce the same heating effect as the capacitor's voltage if applied continuously.
Therefore, at 1000 Hz, the RMS voltage across the capacitor would agree with the value V0/sqrt(2). These values should have agreed.
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how can we determine the reflectivity of an asteroid?
A. by comparing its brightness in visible light to its brightness in infrared light
B. by taking a photograph of it
C. by measuring its mass and radius
D. by where it is located in the asteroid belt
The reflectivity of an asteroid can be determined by comparing its brightness in visible light to its brightness in infrared light. The correct answer is option A.
What is the reflectivity of an asteroid?The term "albedo" refers to the reflectivity of a celestial body, such as an asteroid. It refers to the amount of light that is reflected from an object's surface. Albedo is a term that astronomers and scientists use to describe the amount of light reflected by a celestial object. Scientists measure an asteroid's albedo by comparing its brightness in visible light to its brightness in infrared light.
Therefore, Option A is the correct answer to the question of how we can determine the reflectivity of an asteroid. By comparing its brightness in visible light to its brightness in infrared light.
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A child sleds down a frictionless hill with vertical drop h. At the bottom is a level stretch where the coefficient of friction is 0.16.If she slides 19 m across the level stretch, what's h? Express your answer with the appropriate units.
The vertical height of the hill is 36.75 m.
Given values the following values are given in the problem statement: Hill vertical drop h is unknown. The coefficient of friction is given as 0.16. The distance covered by the child while sliding across the level stretch is given as 19 m. Concept of energy conservation according to the concept of energy conservation, the potential energy at the top of the hill gets converted to kinetic energy at the bottom of the hill. Kinetic energy, in turn, gets converted to work done by friction, and hence the final kinetic energy is less than the initial kinetic energy. The net work done by all forces acting on the child will be equal to the change in kinetic energy. W = ΔKWe can calculate the change in kinetic energy as follows:ΔK = (1/2) mvf² - (1/2) mvi²where m is the mass of the child, vi is the initial velocity, and vf is the final velocity. The work done by friction force can be calculated as follows: Wf = f × where f is the frictional force acting on the child, and d is the distance covered by the child while sliding across the level stretch. The total work done by friction force will be equal to the change in kinetic energy, as given below: Wf = ΔKThe gravitational potential energy at the top of the hill can be calculated as follows: PE = where m is the mass of the child, g is the acceleration due to gravity, and h is the vertical height of the hill. The final velocity of the child can be calculated as follows: vf = √(2gh)The work done by friction force can be calculated as follows: Wf = f × d = μmgdwhere μ is the coefficient of friction, and Wf is the work done by the friction force on the child. Calculations The gravitational potential energy at the top of the hill can be calculated as follows: PE = mgt…………….. (1)The final velocity of the child can be calculated as follows:
vf = √(2gh) …………….. (2)
The change in kinetic energy can be calculated as follows:
ΔK = (1/2) mvf² - (1/2) mvi² …………….. (3)
The work done by friction force can be calculated as follows:
Wf = μmgd …………….. (4)
From the principle of conservation of energy, we have
Wf = ΔK = (1/2) mvf² - (1/2) mvi² …………….. (5)
Substituting the values in the above equations and solving them, we get h = 36.75
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which are true of reflection versus refraction? multiple select question. they are the same when discussing seismic waves and the properties of those waves as they cross boundaries between materials. refraction bends a portion of the wave energy as the wave either slows or speeds up as it crosses the encountered boundary. reflection sends a portion of the wave energy back away from the encountered boundary. either may happen to a seismic wave as it encounters a boundary between materials of different physical properties.
The statemens which are true about reflection versus refraction is 2 , 3 and 4.
It is not true that reflection and refraction are the same when discussing seismic waves and the properties of those waves as they cross boundaries between materials. Therefore, the correct options are the 2,3 and 4 statements.
Reflection occurs when a wave encounters a boundary between two materials and some of the wave energy is reflected back into the original material. The angle of incidence (the angle between the incoming wave and the normal to the boundary) is equal to the angle of reflection (the angle between the reflected wave and the normal to the boundary).
Refraction occurs when a wave encounters a boundary between two materials and some of the wave energy is transmitted into the second material at an angle different from the angle of incidence. .
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uniform circular motion: a disk-shaped space station 180 m in diameter spins uniformly about an axis perpendicular to the plane of the disk through its center. how many rpm (rev/min) must this disk make so that the acceleration of all points on its rim is 10 m/s2?
The uniform circular motion that a disk must make 11.47 rev/min so that the acceleration of all points on its rim is 10 m/s2.
We need to use the equation a = (ω2)*r,
where,
a is the acceleration
ω is the angular velocity in rad/s
r is the radius of the disk.
Since we know the acceleration (10 m/s2) and the radius of the disk (90 m), we can rearrange the equation to solve for ω.
10 m/s2 = (ω2)*90 m
ω2 = 10/90 = 0.1111111 rad/s2
ω = 0.333 rad/s
Finally, to convert from rad/s to rev/min, we can use the equation n = (ω*60)/2π, where n is the rev/min and ω is the angular velocity in rad/s.
n = (0.333*60)/2π = 11.47 rev/min
Therefore, the disk must make 11.47 rev/min so that the acceleration of all points on its rim is 10 m/s2.
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what is the definition of pressure? group of answer choices force per unit area the kinetic energy of a molecule a measure of average kinetic energy of a collection of particles the speed of a particle that has the average kinetic energy of the entire sample.
Pressure is defined as the force per unit area. It is the amount of force applied to a given area and is a measure of the average kinetic energy of a collection of particles. For example, the speed of a particle that has the average kinetic energy of the entire sample will affect the pressure.
What is kinetic energy?Kinetic energy is the energy associated with the motion of an object. It is a scalar quantity that is proportional to the square of an object's velocity. The kinetic energy of an object is directly proportional to the square of its velocity. The faster an object is moving, the more kinetic energy it has.
What is the speed of a particle that has the average kinetic energy of the entire sample?The speed of a particle with the average kinetic energy of the whole sample is determined by the temperature of the system. The temperature of a system is a measure of the average kinetic energy of its particles. The faster the particles are moving, the higher the temperature is, and the more kinetic energy they have.
Therefore, the answer to the question is that pressure is defined as the force per unit area.
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Sam (80 kg) takes off up a 50-m-high, 10∘∘ frictionless slope on his jet-powered skis. The skis have a thrust of 190 N. He keeps his skis tilted at 10∘∘ after becoming airborne. How far does Sam land from the base of the cliff? Express your answer to two significant figures and include the appropriate units.
Sam (80 kg) takes off up a 50-m-high, 10-frictionless slope on his jet-powered skis. The distance travelled by Sam (80 kg) is 50.02 m (with appropriate units).
As per the given question, Sam (80 kg) takes off up a 50-m-high, 10- frictionless slope on his jet-powered skis. The skis have a thrust of 190 N. He keeps his skis tilted at 10∘ after becoming airborne.
We need to determine how far Sam land from the base of the cliff. For this, we can use the formula given below.
Distance = Vx * T + 0.5 * ay * [tex]T^2[/tex].
We can calculate the velocity at the end of the slope as follows;
Vx = v * cos θVx = sqrt(2gh) * cos θ
Vx = sqrt(2*9.8*50) * cos(10)
Vx= 233.51 m/s.
Now, using the horizontal velocity, we can calculate the time required to reach the ground.
We know that;
distance = velocity * time + 0.5 * acceleration * time^2distance
= Vx * T
(as the acceleration in the horizontal direction is zero).
Solving for T;
T = distance / VxT = 50 m / 233.51 m/s
T = 0.214 s
Now, we can use the vertical equation to calculate the displacement (or distance travelled) in the vertical direction.
We know that; ay = g = 9.8 m/s^2Vyf = Vi + ay *t
We need to find the final velocity. Vyf at the end of the slope. Initially, we know that; Vi = 0So,
solving for Vyf;
Vyf = ay * tVyf = 9.8 m/s^2 * 0.214 sVyf = 2.10 m/s
Using this final velocity, we can calculate the displacement (distance travelled) as follows;
y = Vi * t + 0.5 * ay * t^2y = 0 + 0.5 * 9.8 m/s^2 * (0.214 s)^2y = 0.22 m.
Now, the horizontal displacement can be calculated as follows;
x = Vx * T (distance covered in the horizontal direction)
x = 233.51 m/s * 0.214 s
x = 50.02 m.
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Which is NOT a mechanism of air lift?Leeward liftingOrographic liftingConvective liftingConvergenceAll are correct
Leeward lifting is not a mechanism of air lift. So the correct answer is Option: 1.
The other three options, orographic lifting, convective lifting, and convergence, are all mechanisms that can cause air to lift and rise. Orographic lifting occurs when air is forced to rise over a mountain or other topographic barrier, while convective lifting occurs due to the heating of the Earth's surface, causing air to rise and form clouds. Convergence lifting occurs when two air masses with different characteristics collide and cause the air to rise. All of these mechanisms play important roles in weather patterns and can lead to the formation of clouds, precipitation, and other atmospheric phenomena. Option : 1 is correct.
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--The complete question is, Which is NOT a mechanism of air lift?
Leeward liftingOrographic liftingConvective liftingConvergenceAll are correct --A 75 kg man is riding an escalator in a shopping mall. The escalator moves the man at a constant velocity from ground level to the floor above, a vertical height of 4.6 m. What is the work done on the man by (a)the gravitational force and (b) the escalator?
3,247.95 J is the amount of work the gravitational force has done on the guy. Since the individual is travelling at a steady speed and the escalator is not exerting any force on him, the work done by the escalator on him is zero.
Is an escalator a type of acceleration if it moves at a constant speed?There is no acceleration in either axis after the platform has reached the maximum escalator angle since both the horizontal and vertical speeds are constant.
The following formula can be used to determine how much work the gravitational pull has done on the man:
W = mgh
where W is the amount of labor completed, m is the man's mass, g is the acceleration brought on by gravity, and h is the height in the air.
Substituting the given values, we get:
W = (75 kg)(9.81 m/s²)(4.6 m)
= 3,247.95 J
Therefore, the work done on the man by the gravitational force is 3,247.95 J.
(a) Because the guy is going at a constant speed and the escalator is not exerting any force on him, the work done on him by the escalator is zero.
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when a falling object reaches terminal velocity, the force of gravity __________ the force of air resistance.
When a falling object reaches terminal velocity, the force of gravity is equal to the force of air resistance.
What is terminal velocity?Terminal velocity is the maximum velocity that an object can achieve while falling through a fluid, such as air or water, due to the opposing forces of gravity and air resistance or drag.
When an object is first dropped, it will accelerate due to the force of gravity pulling it down. However, as the object's speed increases, the force of air resistance or drag also increases, until it reaches a point where it exactly balances out the force of gravity. At this point, the object will no longer accelerate and will fall at a constant speed, which is its terminal velocity.
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most devices designed to use dry-cell batteries can operate between 1.0 and 1.5 v. could this cell be used to make a battery that could replace a dry-cell battery? why or why not.
A cell that is designed to use dry-cell batteries and operates between 1.0 and 1.5 volts can be used to make a battery that could replace a dry-cell battery, as long as it meets the requirements of voltage output, capacity, compatibility, and stability.
Yes, a cell designed to operate between 1.0 and 1.5 volts can be used to make a battery that could replace a dry-cell battery. Here's a step-by-step explanation of why this is possible:
1. Dry-cell batteries are commonly used in devices because they provide a stable voltage output and have a wide operating range (1.0 to 1.5 volts), which is suitable for most electronic devices.
2. To replace a dry-cell battery, the new cell must also provide a similar voltage output and have a comparable operating range. If the new cell is designed to operate between 1.0 and 1.5 volts, it meets this requirement.
3. Another important factor in replacing a dry-cell battery is the capacity of the new cell. The capacity determines how long the battery can provide power to the device before it needs to be replaced or recharged. If the new cell has a similar or higher capacity than the dry-cell battery it is replacing, it will be a suitable replacement.
4. Additionally, the size and shape of the new cell must be compatible with the device it is intended to power. Many dry-cell batteries have standard sizes and shapes, so it's important to ensure that the new cell is compatible with the device's battery compartment.
5. Finally, the new cell must be able to provide a stable voltage output over its entire operating range. This ensures that the device will function properly and efficiently.
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You find a coin in your backyard
that has a volume of 0.8 cm3 and a
mass of 8.4g. What is the density of the coin?
Answer:
Density is defined as mass per unit volume. To calculate the density of the coin, you can divide its mass by its volume. Using the given values for mass and volume:
Density = Mass / Volume = 8.4 g / 0.8 cm3 = 10.5 g/cm3
The density of the coin is 10.5 grams per cubic centimeter (g/cm3).
Solve 4.667 x 104 g + 3.02 x 105 g. Give the correct numbers of significant figures in the answer.
The answer's 3.487 x 105 g is the one with the right number of significant figures.
How are three significant figures corrected?We also round a number to three significant numbers when rounding to three decimal places. Zeros are inserted into any void spaces to the right of the decimal point.
We must take into account the significant figures in the original numbers being added in order to establish the number of significant figures in the solution.
4.667 x 104 g has 4 significant figures, since all non-zero digits are significant.
3.02 x 105 g has 3 significant figures, since the trailing zero is not significant (it only serves to indicate the magnitude of the value).
When we add these values together, we get 3.487 x 105 g.
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Unlike most power stations, wind turbines do not produce steam while generating electricity.
Suggest the energy transfer that occurs during the generation of electricity by wind turbines.
Answer:The energy transfer that occurs during the generation of electricity by wind turbines is from kinetic energy to electrical energy. Wind turbines harness wind energy and convert it into rotational motion of the blades, which in turn rotates a generator that generates electricity. The kinetic energy of the wind is transformed into mechanical energy of the blades, which is then converted into electrical energy. Therefore, the energy transfer that occurs in wind turbines is from the wind's kinetic energy to electrical energy. This is a clean and renewable source of energy that does not involve the burning of fossil fuels, making it an environmentally friendly option for generating electricity.