As part of an ongoing service project, the students at Arlington High School recently spent an afternoon planting trees. They planted an average of 4 trees per participant. Soon they plan to do some more planting, averaging 2 trees per participant. If everything goes as planned, what will be the percent of decrease in the average number of trees planted?

The median from the vertex angle of an isosceles triangle divides the triangle into two congruent triangles.

The median of a triangle is a line segment joining a vertex to the midpoint of the opposite side. Each triangle has three medians, one from each vertex, and they are concurrent at a point called the centroid. The median from the vertex angle of an isosceles triangle divides the triangle into two congruent triangles.

Therefore, the median from the vertex angle of an isosceles triangle divides the triangle into two congruent triangles.

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Answer:

[tex]x \leqslant - 27[/tex]

Step-by-step explanation:

[tex]1. \: - \frac{x}{9} \geqslant 3 \\ 2. \: - x \geqslant 3 \times 9 \\ 3. \: - x \geqslant 27 \\ 4. \: x \leqslant - 27[/tex]

Subtracting the polynomial (1/6)c² + (1/9)c + 2 from (3/2)c² - (4/3)c + 9 will result to the polynomial (4/3)c² + (-13/9)c + 7.

To subtract the polynomials, we need to subtract the corresponding terms. That is, we subtract the coefficients of the c² terms, the coefficients of the c terms, and the constant terms. The result will be a new polynomial. Here is the solution:

((3)/(2)c² - (4)/(3)c + 9) - ((1)/(6)c² + (1)/(9)c + 2)
= (3/2)c² - (4/3)c + 9 - (1/6)c² - (1/9)c - 2
= (3/2 - 1/6)c² + (-4/3 - 1/9)c + (9 - 2)
= (8/6)c² + (-13/9)c + 7
= (4/3)c² + (-13/9)c + 7

So the answer is (4/3)c² + (-13/9)c + 7.

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The coordinate of the other endpoint of the line segment is (-1, 2).

In geometry, a line segment is a part of a line that has two endpoints. It is the shortest distance between two points on a line. A line segment can be straight or curved, and can be vertical, horizontal, or diagonal.

The length of a line segment can be measured using units such as centimeters, inches, or feet. The midpoint of a line segment is the point that is exactly halfway between its endpoints, and it is located at the average of the x-coordinates and the y-coordinates of the endpoints.

Let (x, y) be the coordinate of the other endpoint of the line segment. Then, we know that the midpoint of the line segment is given by the formula:

midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Substituting the given values, we have:

(1, -2) = ((3 + x)/2, (-6 + y)/2)

Multiplying both sides by 2, we get:

(2, -4) = (3 + x, -6 + y)

Separating the x and y terms, we have:

2 = 3 + x -> x = -1

-4 = -6 + y -> y = 2

Therefore, the coordinate of the other endpoint of the line segment is (-1, 2).

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As per the given distance, Martin was 79 kilometers from the hole when he started.

Let's call the initial distance between Martin and the hole "x". According to the problem statement, on Martin's first stroke, the golf ball traveled 4/5 of this distance. This means that the distance the ball traveled on the first stroke was:

distance traveled on first stroke = (4/5)x

After the first stroke, Martin was left with a distance of:

distance left after first stroke = x - (4/5)x = (1/5)x

On Martin's second stroke, the ball traveled 79 meters and went into the hole. This means that the total distance the ball traveled was:

total distance traveled = distance traveled on first stroke + distance left after first stroke + distance traveled on second stroke

total distance traveled = (4/5)x + (1/5)x + 79

total distance traveled = x + 79

Since the ball went into the hole after the second stroke, the total distance traveled is equal to the initial distance between Martin and the hole:

x + 79 = initial distance between Martin and the hole

Therefore, the initial distance between Martin and the hole was:

x = initial distance between Martin and the hole = (79 km)

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Answer:

5x^2+2x-7

Step-by-step explanation:

First find the common variable.

6x^2 + 10x -7 and -x^2 -8x

Add those together like any other problem.

[tex](6x^2 + 10x -7) + (-x^2 -8x)\\\\6x^2+10x-7 -x^2-8x\\\\(6x^2-x^2) + (10x-8x) - 7\\\\5x^2+2x-7[/tex]

Answer:10

Step-by-step explanation:

A^2 + B^2 = C^2

8^2 + 6^2 = 100^2

take the square root since c is squared

sqrt 100 = 10

Answer:

Step-by-step explanation:

10

Answer:

whats the equation

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

compare the coordinates of each point:

G: (1,2)    x4→   G': (4,8)

H: (3,0)   x4→   H': (12,0)

I:  (2,-2)   x4→    I':  (8,-8)

As you can see the scale factor is 4

Each x and each y coordinate of the small triangle GHI is multiplied by 4 to get the image triangle G'H'I'

The value of x is 23°

A line is a straight, one-dimensional figure that extends infinitely in both directions. It is often represented graphically as a straight line on a coordinate plane, with an equation that describes its position.

A line can be defined by any two points on it, and every point on the line can be expressed as a linear combination of those two points.

Line j and k are parallel and another line crossing it means transversal line, then the corresponding angles are equal which is,

(5x+9)° = (4x+32)°

5x-4x = 32-9

x = 23°

Therefore, the value of x is 23°

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If the discount net price is $7,800 and Net Price Factor, trade discount are to be calculated, then trade discount is equal to $1,170 and Net Price Factor is equal to 0.9216.

The formula used for Trade Discount is given as product of List Price and Trade Discount Rate. The value of list price is given as $7,800.00 and that of Trade Discount Rate is 0.15. Putting the given values in the formula, we get the following result:

Trade Discount = $7,800.00 x 0.15 = $1,170.00

Cash Discount 2 = 4% of (Net Price - Cash Discount 1)

∵ Net Price Factor = (100% - 4%) x (100% - 4%) / 100%

⇒ Net Price Factor = 0.9216

Single Equivalent Discount = (1 - Net Price Factor) x 100%

∴ Single Equivalent Discount = (1 - .9216) x 100%

Single Equivalent Discount = 7.84%.

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Refer to complete question below:

Complete the following table by finding the net price factor, single equivalent discount, trade discount (in dollars), and net price in dollars). Round the net price factor and single equivalent discount to five decimal places, and the trade discount and net price to the nearest cent, when necessary. List Price Trade Discount Rate Net Price Factor Single Equivalent Discount Trade Discount Net Price $7,800.00 15/4/4

The maximum of the sinusoidal function is 4

From the question, we have the following parameters that can be used in our computation:

The graph of the sinusoidal function

In the graph of the sinusoidal function, we can see that

The maximum is at y = 4

Also, we can see that

The minimum is at y = 1

Hence, the maximum is 4

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The perimeter, in miles, of the rectangle formed by connecting the points representing the cabana, beach, water slide, and roller coaster will be 22 miles.

The perimeter of a form is the space surrounding its edge. Find the perimeter of various forms by summing the lengths of their sides.

Given, a coordinate system where 1 unit = 1 mile

Lets,

First, calculate the linear distance between adjacent points as displayed in the graph.

Distance between car to cabana = 4 units = 4 miles

Distance between cabana to beach = 6 units = 6 miles

Distance between beach to water slide = 5 units = 5 miles

Distance between water slide to roller coaster = 6 units = 6 miles

Distance between roller coaster to cabana =5 units = 5 miles

Thus,

1) the perimeter, in miles, of the rectangle formed by connecting the points representing the cabana, beach, water slide, and roller coaster:

Perimeter = 6 + 5 + 6 + 5

Perimeter = 22 miles

2) the total distance in miles from the car to the cabana and then from the cabana to the beach:

Distance = 4 + 6

Distance = 10 miles

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The probability of being dealt 5 cards from a standard 52-card deck and getting a four of a kind is 0.00024.

To find the probability of being dealt 5 cards from a standard 52-card deck and getting a four of a kind, first find the total number of ways to get a four of a kind and then dividing that by the total number of possible 5-card hands.

Total number of 5-card hands:

52C5 = 52! / (5!)(47!) = 2,598,960

Total number of ways to get a four of a kind:

There are 13 different ranks in a standard deck, so there are 13 ways to choose the rank of the four of a kind. There are also 48 remaining cards in the deck after the four of a kind has been chosen, so there are 48 ways to choose the fifth card.

13(48) = 624

So the probability of getting a four of a kind is 624 / 2,598,960 = 0.00024.

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We have to, the solution to the inequality is x >= -2

How to solve the inequality?

To solve the inequality 10x >= -20, we need to isolate the variable x on one side of the inequality sign. We can do this by dividing both sides of the inequality by 10. This gives us:

10x/10 >= -20/10

Simplifying the fractions gives us:

x >= -2

Therefore, the solution to the inequality is x >= -2. This means that any value of x that is greater than or equal to -2 will satisfy the inequality.

Answer: x >= -2

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Answer:

nonlinear

Step-by-step explanation:

If that's a fraction with an x on the bottom, it is non-linear.

Linear (graph is a line) has y = mx + b format or similar, with x having only a power of 1 (just plain x)

You get curves and other graphs when x is squared or higher exponent, or x inside a squareroot is also not a line. And, like your problem if x is on the bottom of a fraction it is nonlinear.

The degree of the monomial -7q² + r³ + s⁶ is 11.

An algebraic expression is a combination of variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. It represents a mathematical phrase or sentence and can be simplified or evaluated by substituting numerical values for variables.

The degree of a monomial is the sum of the exponents of its variables.

In the given monomial, -7q² + r³ + s⁶, the variables are q, r, and s, and their exponents are 2, 3, and 6, respectively.

So, the degree of the monomial is the sum of these exponents:

degree = 2 + 3 + 6 = 11

Therefore, the degree of the monomial -7q² + r³ + s⁶ is 11.

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b=7

------------------

When we evaluate f(3) in the function f(x)=3x^2+9/x+1, we get the result 31.

The function f(x) = 3x^2 + 9/x + 1 is a quadratic function with a variable x. To find the value of f(3), we need to plug in the value of x = 3 into the function and simplify.
f(3) = 3(3)^2 + 9/3 + 1
f(3) = 3(9) + 3 + 1
f(3) = 27 + 3 + 1
f(3) = 31

Therefore, the value of f(3) is 31.

A quadratic term is any expression that has in its unknowns (in which letters are used) one that is squared (or two), these terms are part of a quadratic function.

For a term to be quadratic it must be multiplied by itself (twice), for example:

a² + a + 1

We can see that it is a quadratic function and that its literal term is a while the quadratic term is a², i.e. a*a.

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Answer:

27+X=42

X=15

Step-by-step explanation:

interior opposite angle are equal.

By answering the supplied question, we may infer that the response is slope As a result, the equation's y-intercept is equal to -8.

A line's slope determines how steep it is. The gradient is mathematically expressed as gradient overflow. By dividing the vertical change (run) between two spots by the height change (rise) between the same two locations, the slope is determined. The equation for a straight line, y = mx + b, is written as a curve form of an expression. When the slope is m, b is b, and the line's y-intercept is located (0, b). For instance, the y-intercept and slope of the equation y = 3x - 7 (0, 7). The location of the y-intercept is where the slope of the path is m, b is b, and (0, b).

The slope of the line is represented by the coefficient of x in the equation Y = -6x - 8.

As a result, the equation's slope is -6.

-8, the line's y-intercept, serves as the equation's constant term.

As a result, the equation's y-intercept is equal to -8.

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When x = 1331, the value of y is 55.72. So, the answer is y = 55.72.

According to the given information, y varies directly at the cube root of x. This means that we can write the equation as y = k * (x)^(1/3), where k is a constant. We can find the value of k by plugging in the given values of y and x. So,100 = k * (6859)^(1/3) => k = 100 / (6859)^(1/3)Now, we can plug in the value of x = 1331 and k into the equation to find the value of y.y = 100 / (6859)^(1/3) * (1331)^(1/3) => y = 100 * (1331/6859)^(1/3) => y = 55.72 when x = 1331, the value of y is 55.72. So, the answer is y = 55.72.

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123

Step-by-step explanation:

Answer: internal systolic blood pressure (100,110).

Step-by-step explanation:

Given the systolic blood pressure is normally distributed with a

mean G 105  and a standard leviation 5 .

to find : using empirical rule determines  the interval

dyslolie blood pressure that represent the middle 68% malen

solution 68% value  lie within 1 standard deviation the mean .

            { using empirical rule 2

we cab express this range as :

= (x -s , x +s)

= (105 -5, 105+5)

= (100 , 110)

So the probabilities of the given events are:

P(X = 5) = 1/9
P(2 ≤ X ≤ 6) = 5/12
P(X = 5 or X = 10) = 7/36

To find the probabilities of the given events, we need to consider all the possible outcomes of the two dice-throwing experiments and the number of favorable outcomes for each event.

There are 6 possible outcomes for each die, so the total number of possible outcomes for the two dice is 6 × 6 = 36.

For the event X = 5, the favorable outcomes are (1, 4), (2, 3), (3, 2), and (4, 1). So the probability of this event is P(X = 5) = 4/36 = 1/9.

For the event 2 ≤ X ≤ 6, the favorable outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (4, 1), (4, 2), and (5, 1). So the probability of this event is P(2 ≤ X ≤ 6) = 15/36 = 5/12.

For the event X = 5 or X = 10, the favorable outcomes are (1, 4), (2, 3), (3, 2), (4, 1), (4, 6), (5, 5), and (6, 4). So the probability of this event is P(X = 5 or X = 10) = 7/36.

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After 3 years and 9 months, the copier is worth $30,750. After 5 years, the salvage value of the copier is $35,000. The domain of the function is 0 <= t <= 5.

a. To find the value of the copier after 3 years and 9 months, we need to plug in the value of t into the function V(t). Since 3 years and 9 months is equivalent to 3.75 years, we plug in 3.75 for t:
V(3.75) = 3400(3.75) + 18000
V(3.75) = 12750 + 18000
V(3.75) = 30750
Therefore, the copier is worth $30,750 after 3 years and 9 months.

b. To find the salvage value of the copier after 5 years, we need to plug in 5 for t into the function V(t):
V(5) = 3400(5) + 18000
V(5) = 17000 + 18000
V(5) = 35000
Therefore, after 5 years, the salvage value of the copier is $35,000.

c. The domain of this function is the set of all possible values of t. Since the function is defined for the first 5 years of use, the domain is 0 <= t <= 5.

d. To sketch the graph of this function, we can plot a few points and connect them with a line. For example, we can plot the points (0, 18000), (1, 21400), (2, 24800), (3, 28200), (4, 31600), and (5, 35000). The graph will be a straight line with a positive slope, starting at (0, 18000) and ending at (5, 35000).

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1. 1920 Beetle Population

Beetle Type #Beetles #Beetle % Frequency

BB 22 22/86 ≈ 0.26

bb 14 14/86 ≈ 0.16

Bb 50 50/86 ≈ 0.58

2. 2020 Beetle Population

Beetle Type #Beetle % Frequency

BB 0 0/14 = 0

bb 14 14/14 = 1

Bb 0 0/14 = 0

3. Gene pool for the beetle population: The gene pool for the beetle population consists of the two alleles for the coloration gene, which are represented by "B" (dominant allele) and "b" (recessive allele).

4. Allele frequency for the 1920 Homozygote dominant Beetle population:

5. The allele frequency for the heterozygote population in 2020 is B = 0 and b = 1.

6. Yes, the beetle population experienced evolution because the allele frequencies changed from 1920 to 2020.

For question 1 and 2 above, The % frequency for each beetle type was calculated by dividing the number of beetles of that type by the total number of beetles in the population, and then multiplying the result by 100 to get a percentage.

For example, in the 1920 beetle population, the frequency of BB beetles was calculated as follows:

% Frequency of BB = (# of BB beetles / Total # of beetles) x 100

% Frequency of BB = (22 / 86) x 100

% Frequency of BB ≈ 25.58 or 26% (rounded to the nearest whole number)

Similarly, the % frequency for bb and Bb beetles in the 1920 population were calculated as:

% Frequency of bb = (14 / 86) x 100 ≈ 16%

% Frequency of Bb = (50 / 86) x 100 ≈ 58%

The same process was used to calculate the % frequency for the 2020 beetle population.

4. The frequency of the dominant allele (B) in the 1920 population is the sum of the number of copies of B (from BB and Bb beetles) divided by the total number of alleles (2x the total number of beetles).

Frequency of B = (22 + 50/2) / (86x2) ≈ 0.55

5. Allele frequency for the 2020 heterozygote beetle population:

Since only the frequency of the heterozygote (Bb) is given, the frequency of both alleles (B and b) can be calculated as follows:

Frequency of b = 1 - Frequency of B = 1 - 0 = 1

Frequency of B = frequency of Bb / 2 = 0 / 2 = 0

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The final answer is 2x^3 +x^2 +3x+5 = (2x^2 + 3x + 6)(x−1) + 11.

(2) To solve the inequality |2x − 5| ≤ 9, we need to split it into two separate inequalities and solve for x:
2x − 5 ≤ 9 and 2x − 5 ≥ −9
2x ≤ 14 and 2x ≥ 4
x ≤ 7 and x ≥ 2
The solution in interval notation is [2, 7].

(3) To find the inverse of the function f(x) = 5/(6x−1), we need to switch the x and y values and solve for y:
x = 5/(6y−1)
6y−1 = 5/x
6y = 5/x + 1
y = (5/x + 1)/6
The inverse function is f^(-1)(x) = (5/x + 1)/6.

(4) To find fg and fg, we need to plug in the functions for x and simplify:
fg(x) = f(g(x)) = √(x^2−11x+30−4) = √(x^2−11x+26)
fg(x) = g(f(x)) = (√x−4)^2−11(√x−4)+30 = x−8√x+16−11√x+44+30 = x−19√x+90
The domain of fg is all real numbers greater than or equal to 26, and the domain of fg is all real numbers greater than or equal to 0.

(5) To find the equation of the line perpendicular to y = 35 x − 4 and passing through the point (1, 2), we need to find the slope of the perpendicular line and use the point-slope form:
The slope of the original line is 35, so the slope of the perpendicular line is -1/35.
Using the point-slope form, y − y1 = m(x − x1), we get:
y − 2 = −1/35(x − 1)
y = −1/35x + 2 + 1/35
y = −1/35x + 71/35
The equation of the line in slope-intercept form is y = −1/35x + 71/35.

(6) To divide 2x^3 +x^2 +3x+5 by x−1 using long division, we need to divide each term of the dividend by the divisor and find the remainder:
2x^3 ÷ x = 2x^2
2x^2(x−1) = 2x^3−2x^2
(x^2 +3x+5) − (2x^3−2x^2) = 3x^2 +3x+5
3x^2 ÷ x = 3x
3x(x−1) = 3x^2−3x
(3x+5) − (3x^2−3x) = 6x+5
6x ÷ x = 6
6(x−1) = 6x−6
5 − (6x−6) = 11
The final answer is 2x^3 +x^2 +3x+5 = (2x^2 + 3x + 6)(x−1) + 11.

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The inverse of AB is B−1A−1

1. True. Every square matrix with ones down the main diagonal has an inverse, since the diagonal elements are all non-zero.
2. False. Generally, the determinant of B does not necessarily equal the determinant of A, even when B is a product of A and other matrices.
3. True. If a matrix A satisfies the equation A2=A, then its determinant is 0, since A=A2 implies detA=det(A2)=detA×detA=detA2=0.
4. True. If A and B are both invertible n×n matrices, then AB is also invertible, and the inverse of AB is B−1A−1.

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