Arrange the following elements in order of decreasing first ionization energy: S, Ca, F, Rb, and Si.
Rank from largest to smallest. To rank items as equivalent, overlap them.

Answer:

b

Explanation:

The reaction that is not a displacement reaction from all the options is [tex]C_6H_6_{(l)} + Cl_{2(g)} --> C_6H_5Cl_{(l)} + HCl_{(g)}[/tex]

In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.

Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.

Correct option = b.

The reaction given in Option A is not a displacement reaction. In Displacement reaction functional group of one reactant is replaced by the functional group of the another reactant.

Displacement reaction:

In this reaction functional group of one reactant is replaced by the functional group of the another reactant.

[tex]\bold { Zn(s) + FeCl_2(aq) \rightarrow ZnCl_2(aq) + Fe(s).}[/tex]

In the above reaction Zinc does not any functional group to exchange with iron chloride.

Therefore, the reaction given in Option A is not a displacement reaction.

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Answer:

188

Explanation:

For every 2 molecules of methanol reacted, 4 molecules of water are formed.  Use this relationship to solve.

2/4 = 94/x

2x = 376

x = 188

188 molecules of water will be formed.

Answer:On these combined scales of pH and pH it can be shown that because for water when pH = pH = 7 that pH + pH = 14. This relationship is useful in the inter conversion of values. For example, the pH at a 0.01 M solution of sodium hydroxide is 2, the pH of the same solution must be 14-2 = 12.

Explanation:

The 0.10M HCI, pH = 1 solution has the highest pOH. Therefore, option (1) is correct.

pOH of a solution can be determined from the negative logarithm of the hydroxide ions concentration in the solution.

The mathematically pOH of the solution can be expressed as:

pOH = -log [OH⁻]                                                          ..............(1)

Where [OH⁻] represents the concentration of hydroxide ions in an aqueous solution.

Given, the pH = 1 of HCl

pH + pOH = 14

1 + pOH = 14

pOH = 14 - 1

pOH = 13

Given, the pH = 3 of HNO₃

pH + pOH = 14

3 + pOH = 14

pOH = 14 - 3

pOH = 11

Given, the pH = 12 of NaOH = 0.01 M

pH + pOH = 14

12 + pOH = 14

pOH = 14 - 12

pOH = 2

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Answer:

[OH⁻] = 1.60 × 10⁻⁶ M

Basic

Explanation:

Step 1: Given data

Concentration of H₃O⁺: 6.25 × 10⁻⁹ M

Step 2: Calculate the concentration of OH⁻

We will use the following expression.

Kw = [H₃O⁺] × [OH⁻] = 1.00 × 10⁻¹⁴

[OH⁻] = 1.00 × 10⁻¹⁴ / 6.25 × 10⁻⁹ = 1.60 × 10⁻⁶ M

Step 3: Calculate the pH

We will use the following expresion.

pH = -log [H₃O⁺] = -log (6.25 × 10⁻⁹) = 8.20

Since the pH > 7, the solution is basic.

Answer:

activation energy

Explanation:

Answer:

Activation Energy

Explanation:

Activation Energy is the energy required for a reaction to occur.

Answer::

Lower rate of reaction

Explanation:

Lower concentration of reactant in an experiment is indicative of fewer ions or atoms present, which means a slower rate of reaction. In a titration reaction for instance, the end point would take longer to be substantiated, thereby increasing volume of titres. This is further backed up by collision theory which states that more particles in a system improves combinations of molecules.

This however may not be the case if the iodine in question is  catalyst, in which case the change in concentration has no effect whatsoever on the reaction rte.

I hope this explanation fits the brief.

Answer:

Number of moles of gas is directly proportional to the volume of the gas

Number of moles of the gas is directly proportional to the temperature of the gas

Explanation:

According to Avogadro's law, changing the number of moles of a gas changing the volume of the gas also since the volume of a gas is directly proportional to the number of moles of the gas.

Hence from Avogadro's law; V= kn where k is a proportionality constant, V is the volume of the gas and n is the number of moles of the gas.

Changing the number of moles will also lead to a change in the temperature of the gas, since volume is directly proportional to the number of moles of the gas and volume is also directly proportional to temperature (Charles law), it the follows that number of moles of the gas is directly proportional to its temperature.

Answer:

[tex]Cu~+~PtCl_2->Pt~+~CuCl_2[/tex]

Explanation:

In this case, we can start with the formula of Platinum (II) Chloride. The cation is the atom at the left of the name (in this case [tex]Pt^+^2[/tex]) and the anion is the atom at the right of the name (in this case [tex]Cl^-[/tex]). With this in mind, the formula would be [tex]PtCl_2[/tex].

Now, if we used metallic copper we have to put in the reaction only the copper atom symbol [tex]Cu[/tex]. So, we have as reagents:

[tex]Cu~+~PtCl_2->[/tex]

The question now is: What would be the products? To answer this, we have to remember "single displacement reactions". With a general reaction:

[tex]A~+~BC->AB~+~C[/tex]

With this in mind, the reaction would be:

[tex]Cu~+~PtCl_2->Pt~+~CuCl_2[/tex]

I hope it helps!

Answer:

See figure 1

Explanation:

In this question, we have to start with the protonation of the double bond. In carvone we have two double bonds, so, we have to decide first which one would be protonated.

The problem states that the terminal alkene is the one that would is protonated. Therefore, we have to do the protonation in the double bond at the bottom to produce the carbocation number 1. Then, a hydride shift takes place to produce the carbocation number 2. A continuation, an elimination reaction takes place to produce the conjugated diene. Then the diene is protonated at the carbonyl group and with an elimination reaction of an hydrogen in the alpha carbon we can obtain carvacol.

Answer:

hi here goes your answer

Explanation:

iv. The lower the PH, the weaker the base

Answer:

A.∆s>0contribute to spontaneity.

Answer:

1120.62 kJ

Explanation:

In order to find how much heat is released for 7.70 mol, we have to compare it with the heat released from one mole.

So from the question, we have;

196.6 kJ = 1 mol

x = 5.70

x = 5.70 * 196.6 / 1

x = 1120.62 kJ

Answer:

solid dont know

Explanation:

so sorry ask another

Answer:

0.36 g of N2.

Explanation:

The following data were obtained from the question:

Temperature (T) = 25 °C

Volume (V) = 340 mL

Measured pressure = 730 torr

Vapour pressure = 23.76 torr

Mass of N2 =..?

First, we shall determine the true pressure of N2. This can be obtained as follow:

Measured pressure = 730 torr

Vapor pressure = 23.76 torr

True pressure =..?

True pressure = measured pressure – vapor pressure

True pressure = 730 – 23.76

True pressure = 706.24 torr.

Converting 706.24 torr to atm, we have:

760 torr = 1 atm

Therefore,

706.24 torr = 706.24 / 760 = 0.929 atm

Next, we shall convert 340 mL to L. This is illustrated below:

1000 mL = 1 L

Therefore,

340 mL = 340/1000 = 0.34 L

Next, we shall convert 25 °C to Kelvin temperature. This is illustrated below:

Temperature (K) = Temperature (°C) + 273

T(K) = T (°C) + 273

T (°C) = 25 °C

T(K) = 25 °C + 273

T (K) = 298 K

Next, we shall determine the number of mole of N2. This can be obtained as follow:

Pressure (P) = 0.929 atm

Volume (V) = 0.34 L

Temperature (T) = 298 K

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =...?

PV = nRT

0.929 x 0.34 = n x 0.0821 x 298

Divide both side by 0.0821 x 298

n = (0.929 x 0.34 ) /(0.0821 x 298)

n = 0.0129 mole

Finally, we shall determine the mass of N2 as shown below:

Mole of N2 = 0.0129 mole

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 =.?

Mole = mass /Molar mass

0.0129 = mass of N2/ 28

Cross multiply

Mass of N2 = 0.0129 x 28

Mass of N2 = 0.36 g

Therefore, 0.36 g of N2 was collected.

Answer:

1.3 mL

Explanation:

First, get the density of the olive oil, which is 0.917 kg/mL. Then divide the mass by the density:

1.2kg/0.917kg/mL= 1.3086150491 mL. The kg cancel out, leaving us with mL.

It should have 2 significant figures, because 1.2kg has 2 and we are dividing.

The volume of olive oil will be nearly 1300mL or 1.30 L as per the given data.

Volume is a measurement of three-dimensional space that is occupied. It is frequently numerically quantified using SI derived units or various imperial units. The definition of length is linked to the definition of volume.

Volume is, at its most basic, a measure of space. The units liters (L) and milliliters (mL) are used to measure the volume of a liquid, also known as capacity.

This measurement is done with graduated cylinders, beakers, and Erlenmeyer flasks.

Here, it is given that mass of olive oil is 1.2kg.

We know that,

Density of olive oil = 0.917kg/l.

Volume = mass/density

Volume = 1.2/0.917.

Volume = 1.30 lit.

Volume = 1300mL.

Thus, the volume of olive oil will be 1300 mL.

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Answer:

THE FRACTION OF THE SAMPLE REMAINING AFTER THREE HALF LIVES IS 0.125 OR 125/1000

Explanation:

A radioactive isotope of mercury decay to gold with a disintegration constant of 0.0108 h^-1

To calculate the fraction of sample remaining after three half life, we first calculate the half life of the decay.

Half life = ln 2 / Y

Y = disintegration constant

So therefore,

half life = ln 2 / 0.0108

half life = 0.693 / 0.0108

half life = 64.18 hours.

So a decay occurs after 64.18 hours.

To calculate the fraction remaining after 3 half life:

N(t) = N(o) e ^-Yt

where t = 3 half life

So, N / No = e^-Y ( 3 t1/2)

Since t 1/2 = ln 2 / Y, so we can re-write the formula as:

Nt / No = e^-Y ( 3 ln 2/ Y)

Nt / No = e^-3 ln2

Nt / No = e^-3 * 0.693

Nt / No = e^-2.079

Nt / No = 0.125

So the fraction of the sample remaining after 3 half lives is 125/ 1000 or 0.125

Answer:

Helium

Explanation:

The speed of the molecules in a gas is directly proportional to the temperature of the gas and inversely proportional to molar mass of the gas.

This implies that when the temperature of a sample of gas is increased, the speed of the gas molecules is increased accordingly.

At a given constant temperature, the molar mass of the gas is inversely proportional to its average molecular speed. This means that the greater the molecular mass of the gas the lesser the average speed of its molecules.

Oxygen has a greater molecular mass than helium hence it will have a lesser average molecular speed compared to helium.

The gas molecule which has the greater average speed is: Helium molecules because they are less massive.

Given the following data:

According to the kinetic-molecular theory, the average speed of gas molecules (particles) is highly dependent on temperature and the molar mass of a gas.

This ultimately implies that, the average speed of gas molecules (particles) is directly proportional to the absolute temperature of an ideal gas and inversely proportional to molar mass of the gas.

At a constant temperature, the higher the molar mass of a gas, the lower would be its average speed and vice-versa.

Hence, helium molecules would have the greater average speed at a constant temperature of 22°C because it is less massive and has a lower molar mass in comparison with oxygen gas.

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Answer:

The methane gas burns

Explanation:

The burning of methane gas is a combustion reaction. Combustion is an exothermic process. For all exothermic processes, ∆H is negative.

Combustion reaction involves the evolution of heat. The energy of reactants is greater than the energy of products hence the excess energy is given off in the form of heat leading to a negative value of the enthalpy of reaction, hence the answer.

Answer:

Rate constants are temperature dependent.

Explanation:

Reaction rate is used to quantify the rate of chemical reaction. There is a relationship between the reaction rate and the half-life of the reaction and the Gibbs free energy of activation, and the reaction rate is temperature dependent according to the equation.

For a reaction shown below

a A + b B ⇒ c C

The rate of reaction of the reaction is given by

[tex]r = k(T) [A]^{m}[B]^{n}[/tex]

where k(T) is the reaction constant, which is seen to be dependent on the temperature of the reaction.

Also, k(T) is numerically equal to

[tex]k(T) = Ae^{\frac{E_{a} }{RT} }[/tex]

where

r = reaction rate

A = pre exponential factor

[tex]E_{a}[/tex] = Activation energy

R = gas constant

T = temperature

and m and n are experimentally determined partial orders in [A] and [B]

Answer:

(a)  Cu²⁺ +2e⁻ ⇌ Cu

(c) 0.07 V  

Explanation:

(a) Cu half-reaction

Cu²⁺ + 2e⁻ ⇌ Cu

(c) Cell voltage

The standard reduction potentials for the half-reactions are+

                                              E°/V

Cu²⁺ + 2e⁻ ⇌ Cu;                  0.34  

Hg₂Cl₂ + 2e⁻ ⇌ 2Hg + 2Cl⁻; 0.241

The equation for the cell reaction is

                                                                            E°/V

Cu²⁺(0.1 mol·L⁻¹) + 2e⁻ ⇌ Cu;                               0.34  

2Hg + 2Cl⁻ ⇌ Hg₂Cl₂ + 2e⁻;                             -0.241

Cu²⁺(0.1 mol·L⁻¹) + 2Hg + 2Cl⁻ ⇌ Cu + Hg₂Cl₂;   0.10

The concentration is not 1 mol·L⁻¹, so we must use the Nernst equation

(ii) Calculations:  

T = 25 + 273.15 = 298.15 K

[tex]Q = \dfrac{\text{[Cl}^{-}]^{2}}{ \text{[Cu}^{2+}]} = \dfrac{1}{0.1} = 10\\\\E = 0.10 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln(10)\\\\=0.010 -0.01285 \times 2.3 = 0.10 - 0.03 = \textbf{0.07 V}\\\text{The cell potential is }\large\boxed{\textbf{0.07 V}}[/tex]

Answer:

B. four sp3

Hope that helps.

We have that for the Question "The blending of one s atomic orbital and three p atomic orbitals produces?"

Answer:

Explanation:

When 1 s orbital blends with 3 p orbitals, they form a tetrahedrical shaped figure with each being a [tex]SP^3[/tex] orbital.. A total of 4 orbitals

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Answer:

Mass = 26.53 g

Explanation:

Heat of combustion = −1380.0 kJ/mol

This means 1 mol of the compound releases 1380 kJ

Molar mass = 44.53 g/mol

This means 1 mol of the compound has a mass of 44.53 g

How many grams would release 822kJ..?

First, we have to obtain the number of moles

1 mol = 1380

x = 822

x = 0.5957 moles

Moles = Mass / Molar mass

Mass = Molar mass * moles

Mass = 44.53 * 0.5957

Mass = 26.53 g

Answer:

The compound is largely ionic with A as the cation.

Explanation:

A chemical bond is usually formed between two or more elements. A chemical bond may be ionic, covalent or polar covalent depending on the electro negativity difference between the atoms in the bond.

A large electro negativity difference usually implies an ionic bond. As a rule, when the electronegativity difference is greater than 2.0, the bond is considered ionic.

For the compound A2B, the electro negativity difference between the two atoms is about 2.2. This implies that A2B must be an ionic compound in which A is the cation and B is the anion.

Answer:

The three gases, in the three identical containers, will all have the same number of molecules

Explanation:

If these three gases (Helium He, Neon Ne, and Oxygen [tex]O_{2}[/tex]) are all contained in separate identical containers with the same volume. And they are all stored at the same temperature, and pressure. Then, they'll all contain the same number of molecules. This is in line with Avogadro's law which states that "Equal volume of all gases, at the same temperature and pressure, have the same number of molecules."

Answer:

Heat = 7375J

Final temperature of the mixture = 27.35°C

Explanation:

In the reaction:

2HCl(aq) + Ba(OH)₂(aq) → BaCl₂(aq) + 2H₂O(l) ΔH = –118 kJ

When 2 moles of HCl reacts with excess of Ba(OH)₂ there are released 118kJ.

In the reaction, moles of HCl and Ba(OH)₂ that reacts are:

Moles HCl = 0.250L ₓ (0.500 moles / L) = 0.125 moles HCl

Moles Ba(OH)₂ = 0.500L ₓ (0.500 moles / L) = 0.250 moles Ba(OH)₂

For a complete reaction of 0.125 moles of HCl you need:

0.125 mol HCl ₓ (1 mole Ba(OH)₂ / 2 moles HCl) = 0.0625 moles Ba(OH)₂

As you have 0.250 moles of Ba(OH)₂, this reactant is in excess

2 moles of HCl that react release 118kJ, 0.125 moles of HCl release:

0.125 moles HCl ₓ (118kJ / 2 moles) = 7.375kJ =

The heat released can be obtained with the formula:

Q = C×m×ΔT

Where Q is heat, C specific heat of the solution, m its mass and ΔT change in temperature.

Replacing:

Q = C×m×ΔT

7375J = 4.18J/g°C×750.0g×ΔT

2.35°C = ΔT

As ΔT = Final T - Initial T:

2.35°C = Final T - 25.0°C

Answer: The Clean Air Act was important because it emphasized cost-effective methods to protect the air; encouraged people to study the effects of dirty air on human health; and created a regulation that makes any activities that pollute the air illegal.

Explanation:

Answer:

Clean Air Act (CAA), U.S. federal law, passed in 1970 and later amended, to prevent air pollution and thereby protect the ozone layer and promote public health. The Clean Air Act (CAA) gave the federal Environmental Protection Agency (EPA) the power it needed to take effective action to fight environmental pollution.

Answer:

Explanation:

Mass of Erlenmeyer flask + KHP =  84.847 g

Mass of Erlenmeyer flask  = 84.347 g

Mass of KHP = .5 g

moles of KHP = .5 / 204.23

= 2.448 x 10⁻³ moles

moles of NaOH reacted = 2.448 x 10⁻³

Final buret reading =  12.25 mL

Initial buret reading = 0.50 mL

Volume of NaOH added=

Answer:

1.69 ×10^-10

Explanation:

Given that the equation for the dissolution of AgCl in water is;

AgCl(s) ⇄Ag^+(aq) + Cl^+(aq)

Also, silver ion and chloride ion are in equilibrium with the undissociated AgCl hence we can write;

Ksp= [Ag+][Cl-]/ [AgCl]

Since the activity of the pure sold is 1, we now have;Ksp= [Ag+][Cl-]

If we know the solubility of AgCl in pure water to be 1.3 x 10^-5 M, from standard tables, and [Ag+]=[Cl-]= 1.3 x 10^-5 M = x

Then;

Ksp= x^2

Ksp= (1.3 x 10^-5)^2

Ksp= 1.69 ×10^-10

When Ag⁺ and Cl⁻ are in equilibrium with AgCl, the expression for Ksp is

[tex]Ksp = [Ag^{+} ][Cl^{+} ][/tex]

And its value is 1.77 × 10⁻¹⁰.

Let's consider the equation for the solution of AgCl.

AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

The molar solubility of AgCl (S) at 25 °C is 1.33 × 10⁻⁵ M. We can use this information to calculate the solubility product (Ksp) through an ICE chart.

       AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

I                          0             0

C                       +S           +S

E                        S              S

The solubility product (Ksp) for AgCl is:

[tex]Ksp = [Ag^{+} ][Cl^{+} ] = S.S = S^{2} = (1.33 \times 10^{-5} )^{2} = 1.77 \times 10^{-10}[/tex]

When Ag⁺ and Cl⁻ are in equilibrium with AgCl, the expression for Ksp is

[tex]Ksp = [Ag^{+} ][Cl^{+} ][/tex]

And its value is 1.77 × 10⁻¹⁰.

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