Complete Question
Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 32.75 m/s at an angle θ = 32° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.
Randomized Variables
vo 32.75 m/s
theta 32 degrees
What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?
Answer:
The horizontal distance is [tex]R = 590.2 \ m [/tex]
Explanation:
From the question we are told that
The initial velocity is [tex]v_o = 32.75 \ m/s[/tex]
The angle is [tex]\theta = 26^o[/tex]
The gravitational acceleration of the moon is [tex]g_m = \frac{1}{6} * 9.8 = 1.633 m/s^2[/tex]
Generally the distance traveled is mathematically represented as
[tex]R = \frac{v_o^2 sin 2(\theta)}{g_m}[/tex]
=> [tex]R = \frac{32.75^2 sin 2(32)}{1.633}[/tex]
=> [tex]R = 590.2 \ m [/tex]
If two vector are perpendicular to each other, how should you add them
Answer:
Using pythagoras theorem
Answer:
use the pythagorean theorem
Explanation:
Three swimmers can swim equally fast relative to the water. They have a race to see who can swim across a flowing river in the least time. Swimmer A swims perpendicular to the current and lands on the opposite shore downstream, because the current has swept him in that direction. Swimmer B swims upstream at angle to the current, so that when she reaches the other side, she is straight across from where she started. Swimmer C swims downstream at an angle theta in an attempt to take advantage of the current. Who crosses the river in the least time?
Neutral hydrogen can be modeled as a positive point charge +1.6×10^−19C surrounded by a distribution of negative charge with volume density given by rhoE(r)=−Ae−2r/a0 where a0=0.53×10^−10m is called the Bohr radius, A is a constant such that the total amount of negative charge is −1.6×10^−19C, and e = 2.718 is the base of the natural log.
Required:
a. What is the net charge inside a sphere of radius a0?
b. What is the strength of the electric field at a distance a0 from the nucleus?
Answer:
a) 1.082 × 10⁻¹⁹C ( e = 1.6 × 10⁻¹⁹C)
b) 3.466 × 10¹¹ N/C
Explanation:
a)
p(r) = -A exp ( - 2r/a₀)
Q = ₀∫^∞ ₀∫^π ₀∫^2xπ p(r)dV = -A ₀∫^∞ ₀∫^π ₀∫^2π exp ( - 2r/a₀)r² sinθdrdθd∅
Q = -4πA ₀∫^∞ exp ( - 2r/a₀)r²dr = -e
now using integration by parts;
A = e / πa₀³
p(r) = - (e / πa₀³) exp (-2r/a₀)
Now Net charge inside a sphere of radius a₀ i.e Qnet is;
= e - (e / πa₀³) ₀∫^a₀ ₀∫^π ₀∫^2π r² exp (-2r/a₀)dr
= e - e + 5e exp (-2) = 1.082 × 10⁻¹⁹C ( e = 1.6 × 10⁻¹⁹C)
b)
Using Gauss's law,
E × 4πa₀ ² = Qnet / ∈₀
E = 4πa₀ ² × Qnet × 1/a₀²
E = 3.466 × 10¹¹ N/C
The NCAA Sportsmanship Award honors students who demonstrate the ideals of sportsmanship, including __________. A. fairness B. honesty C. respect D. all of the above
Answer:
the answer is D
Explanation:
Just took the test
The NCAA Sportsmanship Award honors students who demonstrate the ideals of sportsmanship, including fairness, honesty and respect.
What is NCAA?
NCAA stands for National Collegiate Athletic Association. The NCAA is a organization which will be useful for the well being and the success for life long to the college Athelet.
A person who got graduate from high school and completed a minimum of 16 core courses for Division I or II and to earn a minimum required grade-point average in normal core courses and also must earn a qualifying test score on either the ACT or SAT will be eligible to join NCAA.
The NCAA Sportsmanship Award honors a student-athlete who will takes actions in the competitive arena of intercollegiate athletics and who demonstrated one or more of the ideals of sportsmanship, including fairness, civility, honesty, unselfishness, respect and responsibility.
Hence, Option D is the correct answer.
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A bike of mass 125 g accelerates at 29 mis? What is the net horizontal force acting on the bike, in the units of Newton?
Answer:
Force = F = 3.63 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of all forces must be equal to the product of mass by acceleration.
where:
m = mass = 125 [g] = 0.125[kg]
a = 29 [m/s^2]
ΣF = m*a
F = (0.125*29)
F = 3.63 [N]
Convert 5 Liter in to cubic meter.convert 5 litre into cubic metre
Explanation:
To convert liters to cubic meters, multiply the liter value by 0.001 or divide by 1000
A cat chases a mouse across a 1.0 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the floor 2.3 m from the edge of the table. The acceleration of gravity is 9.81 m/s2. What was the cat's speed when it slid off the table? Answer in units of m/s.
Analysing the question:
We are given that the cat chases a rat on a 1m high table, this means that the height of the cat before falling is 1 m
The horizontal velocity of the cat after sliding off the table will not change in mid-air since there is no force to oppose it
We are given:
height of the cat before falling (h) = 1 m
Distance covered by cat after falling off the edge = 2.3 m
acceleration due to gravity (a) = 9.81 m/s²
initial vertical velocity of the cat (u) = 0 m/s
Since the cat will fall at a constant horizontal velocity, the time taken by the cat to reach the ground times the constant speed of the cat will be equal to the horizontal distance covered by the cat
[ since time taken to reach the ground = time for which the constant horizontal velocity will be applied]
The above can simply be written as:
time taken by the cat to reach the ground * horizontal velocity = horizontal distance covered
Time taken by the cat to reach the ground:
From the second equation of motion
s = ut + 1/2*at²
replacing the variables with vertical components
1 = (0)(t) + 1/2 * (9.8)(t²)
1 = 4.9t²
t² = 1 / 4.9
t = 1 / √4.9
t = 0.45 seconds
Cat's horizontal velocity when it slid off the table:
Speed of cat = distance travelled / time taken
here, the distance is the horizontal distance covered by the cat after falling off the table
replacing the variables
Speed of the cat = 2.3 / 0.45 = 5.11 m/s
3500 as a power of 10
Answer: 3.5 × 10^3
Explanation:
The system shown above consists of two identical blocks that are suspended using four cords, each of a different length. Which of the following claims are true about the magnitudes of the tensions in the cords? Select two answers.
Answer:
Option B and C are True
Note: The attachment below shows the force diagram
Explanation:
The weight of the two blocks acts downwards.
Let the weight of the two blocks be W. Solving for T₁ and T₂;
w = T₁/cos 60° -----(1)
w = T₂/cos 30° ----(2)
equating (1) and (2)
T₁/cos 60° = T₂/cos 30°
T₁ cos 30° = T₂ cos 60°
T₂/T₁ = cos 30°/cos 60°
T₂/T₁ =1.73
Therefore, option a is false since T₂ > T₁
Option B is true since T₁ cos 30° = T₂ cos 60°
Option C is true because the T₃ is due to the weight of the two blocks while T₄ is only due to one block.
Option D is wrong because T₁ + T₂ > T₃ by simple summation of the two forces, except by vector addition.
Average velocity of Mike Phelps swimming 100 m race in the 50 m long pool (2 laps) is approximately equal to
A. 0 m/s
B. 1 m/s
C. 2 m/s
D. 4 m/s
Answer:
I’m really not sur but I think it’s b
Explanation:
A box is initially sliding across a level floor at 10 m/s before being subjected to the forces shown below.
Refer to the above information and diagram. What is the sum of forces for this FBD?
Answer:
200m
Explanation:
PLEASE PROVIDE EXPLANATION
Answer:
(a) 9.52
(b) 3.81
Explanation:
Draw a free body diagram of block m. There are two forces:
Weight mg pulling down, and tension T₁ pulling up.
Draw a free body diagram of block M. There are two forces:
Weight Mg pulling down, and tension T₂ pulling up.
Draw a free body diagram of the double pulley. There are two torques:
Tension T₂ pulling counterclockwise at r, and tension T₁ pulling clockwise at R.
Let's assume that M moves down, m moves up, and the pulley rotates counterclockwise.
Sum of forces on block m in the +y direction:
∑F = ma
T₁ − mg = ma₁
T₁ = mg + ma₁
Sum of forces on block M in the -y direction:
∑F = ma
Mg − T₂ = Ma₂
T₂ = Mg − Ma₂
Sum of the torques about the pulley's center in the counterclockwise direction:
∑τ = Iα
T₂ r − T₁ R = (½ m₀ r² + ½ m₀ R²) α
T₂ r − T₁ R = ½ m₀ (r² + R²) α
Substitute:
(Mg − Ma₂) r − (mg + ma₁) R = ½ m₀ (r² + R²) α
The strings don't slip on the pulley, so a₁ = αR and a₂ = αr.
(Mg − Mαr) r − (mg + mαR) R = ½ m₀ (r² + R²) α
Mgr − Mαr² − mgR − mαR² = ½ m₀ (r² + R²) α
g (Mr − mR) − α (Mr² + mR²) = ½ m₀ (r² + R²) α
g (Mr − mR) = [½ m₀ (r² + R²) + Mr² + mR²] α
α = g (Mr − mR) / [½ m₀ (r² + R²) + Mr² + mR²]
α = (10) (9×0.2 − 1×0.5) / (½ (0.5) (0.2² + 0.5²) + 9(0.2)² + 1(0.5)²]
α = 19.0 rad/s²
Therefore:
a₁ = αR = (19.0 rad/s²) (0.5 m) = 9.52 m/s²
a₂ = αr = (19.0 rad/s²) (0.2 m) = 3.81 m/s²
What is the main role of the cell membrane?
Answer:
The plasma membrane, or the cell membrane, provides protection for a cell. It also provides a fixed environment inside the cell, and that membrane has several different functions. One is to transport nutrients into the cell and also to transport toxic substances out of the cell.
“Which of the following are scientific facts?”
E Many diseases are caused primarily by microorganisms too small to be seen with the naked eye.
All objects in the universe are attracted to one another through the force of gravity.
Species evolve through the process of natural selection.
The air we breath on Earth is mostly nitrogen
Tin expands as it is heated.
Water boils at 100°C.
1 nts
Answer:
Disease are caused by micro organisms
All objects in the universe are attracted to one another
species evolved through natural selection
The scientific facts from the given list are,
Microorganisms that are too tiny to be seen with the bare eye are the primary cause of many illnesses.
The force of gravity draws all objects in the cosmos toward one another.
Natural selection is the process through which species change.
What is science?Science is the methodical, empirically-based pursuit and application of knowledge and understanding of the natural and social worlds.
Microorganisms that are too tiny to be seen with the bare eye are the primary cause of many illnesses.
The force of gravity draws all objects in the cosmos toward one another.
Natural selection is the process through which species change.
Therefore options A, B, and C are scientific facts.
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Guys, please help, I need this answer urgently,
1. Ameylia conducted an experiment using a bar magnet and some paper clips. She divided the magnet into 5 parts, A, B, C, D and E. She put the magnet into a tray of paper clips. She noticed that thepaperclipsmoved towards the different parts of the magnet. She repeated the experiment thrice and recorded her observation in the table below.
Part A: 1st trial = 10 paper clips, 2nd trial=9 paper clips, 3rd trial =9 paper clips
Part B: 1st trial = 3 paper clips, 2nd trial=4 paper clips, 3rd trial =5 paper clips
Part C: 1st trial = 12 paper clips, 2nd trial=11 paper clips, 3rd trial =12 paper clips
Part D: 1st trial = 4 paper clips, 2nd trial=6 paper clips, 3rd trial =6 paper clips
Part E: 1st trial = 12 paper clips, 2nd trial=11 paper clips, 3rd trial =12 paper clips
a) Ameylia's teacher told her that there is a mistake in the results recorded for one part of the magnet. Identifyfor which part of the magnet, A,B,C,D or E is the results recorded wrongly. Give a reason for your answer.
Answer: Help me answer this question please????
Trently limited
Spiderman's cell phone falls from his pocket while he is surveying the city. His spider senses have
failed him. It takes the phone 3.6s to crash into the pavement below. How high up was Spiderman?
Answer:
h= 63.5 m
Explanation:
Assuming that air resistance is neglectable, and that the phone drops from Spiderman's pocket, we can use the following kinematic equation for the vertical displacement:[tex]\Delta h = \frac{1}2} * g* t^{2} = \frac{1}{2} *(-9.8 m/s2)*(3.6s)^{2} = -63.5 m[/tex]
[tex]\Delta h = y - y{o} = -63.5 m[/tex]Taking as zero level reference the ground level, we get:y₀ = h = 63.5 m
what is the objects final displacement
Answer:
Explanation:
The object starts at 0
It moves to - 2
It stops
It then moves to + 6
+6 - 2 = + 4
The new position is 4.
A student watches a soap bubble drift from inside a warm room, out an open window, and into the cold air outside. The student notices that the bubble gets smaller once it is outside. Assuming no air leaks out of the bubble, what conclusion could the student reasonably draw from this observation
Answer:
the air particles dont move as fast in the cold air as in warm, so it doesnt push as often and shrinks.
Explanation:
see above
could you vote me brainliest plz? thx :)
Since the air molecules in cold air travel more slowly than they do in warm air, the air pushes less frequently and contracts.
What is Refraction?Refraction is the process by which a wave changes direction while transitioning through one medium to another in physics. As an illustration, waves move much faster in the open ocean than in the shallow.
A tsunami will swing until it is moving perpendicular to the coastline if it is approaching a beach at an angle because the wave's outermost layer goes quicker than its inner portion. In warm air compared to cold, sound waves move more quickly. A lake's surface cools at night, and any sound waves that ascend are bent down by the warmer upper levels of the atmosphere. Because of their varying speeds, the electromagnetic waves which make up light are distorted when they move through a clear substance.
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How does your education contribute to comunity development
Which statement accurately describes an objects weight and mass?
Answer: A-p_Ex
Explanation: answer
Diesel electric power plant is best used as
Answer:
Diesel power plants are also popularly used as standby supply of different industries, commercial complexes, hospitals. During power cut, these diesel power generators are run to fulfill required demand.
Explanation:
A car has initial velocity of 72 km/hr. It is accelerated at 2m/s2
Calculate the final velocity and distance covered after 3 sec.
What is the distance covered by a car in 3rd second?
Answer:
Vf=78
d=
Explanation:
vf=vi+at
=72+(2)(3)
=78km/hr
d=vit+1/2at^2
=(72)(3)+1/2 (2)(3)^2
=216+9
=225m
1) 26m/s
2) 69 m
Explanation:Hi there !
1)
a = (v₂ - v₁)/t => at = v₂ - v₁ => v₂ = at + v₁
v₁ = 72km/h = 72000m/3600s = 20m/s
v₂ = 2m/s²ₓ3s + 20m/s
= 6m/s + 20m/s
= 26 m/s
2)
d = v₁t + at²/2
= 20m/sₓ3s + 2m/s²ₓ9s²/2
= 60m + 9m
= 69 m
Good luck !
What current will this array draw from a 35.0 V battery having negligible internal resistance if we connect it across ab.
Complete question is missing, so i have attached it.
Answer:
A) I = 3.5A
B) I = 4.5 A
C) I = 3.15A.
D)I = 3.25 A
Explanation:
a) When we connect across ab, the resistance from ac and bc is;
20ohms + 10ohms = 30 ohms.
This will now be parallel with the 15 ohms resistor.
Thus, equivalent resistance is;
R = (30 × 15)/(30 + 15)
R = 450/45
R = 10 ohms
Formula for Current is; I = (E/R)
Thus;
I = 35/10
I = 3.5A.
b) similarly, when we connect across bc, resistance from ac and ab is;
15 ohms + 20 ohms = 35 ohms.
This will now be parallel with the 10 ohms resistor.
Thus, equivalent resistance is;
R = (35 × 10)/(35 + 10)
R = 350/45
R = 7.778 ohms.
Current is;
I = 35/7.778
I = 4.5 A.
c) similarly, when we connect across ac, resistance from ab and bc is;
15 ohms + 10 ohms = 25 ohms.
This will now be parallel with the 20 ohms resistor.
Thus, equivalent resistance is;
R = (25 × 20)/(25 + 20)
R = 11.11 ohms.
Current is;
I = 35/11.11
I = 3.15A.
d) since connected across bc, the internal resistance will be added to the circuit resistance, which was seen to be 7.778 ohms in step b above
Thus, equivalent resistance = 7.778 + 3 ohms = 10.778
Current is;
I = 35/10.778
I = 3.25 A
(A) The current when connected across ab is 3.5A
(B) The current when connected across bc is 4.5 A
(C) The current when connected across ac is 3.15A
(D) The current when connected across bc with internal resistance is 3.25 A
Equivalent resistance and current:(a) When connected across ab, the resistance between ac and bc is;
20Ω + 10Ω = 30Ω
It is parallel with 15Ω resistor.
Thus, equivalent resistance is;
R = (30 × 15)/(30 + 15)
R = 450/45
R = 10Ω
Now current is given by
I = (V/R)
I = 35/10
I = 3.5A
(b) When connected across bc, the resistance between ab and ac is;
15Ω + 20Ω = 35Ω
It is in parallel combination with the 10Ω resistor
Thus, equivalent resistance is;
R = (35 × 10)/(35 + 10)
R = 350/45
R = 7.778Ω
Now the current is:
I = 35/7.778
I = 4.5 A
(c) When connected across ac, the resistance between ab and bc is;
15Ω + 10Ω = 25Ω
it is now parallel with the 20Ω resistor.
Thus, - is;
R = (25 × 20)/(25 + 20)
R = 11.11Ω
Current is;
I = 35/11.11
I = 3.15A
(d) when connected across bc, the internal resistance will be added to the circuit resistance across bc.
So, equivalent resistance = 7.778 + 3 = 10.778Ω
Current is;
I = 35/10.778
I = 3.25 A
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what is canadas offical winter sport
Answer:
Ice hockeyyyyyy
Explanation:
Which of the following is true about the strength of attraction or repulsion between particles with charge.
A. The larger the absolute value of the charges, the larger the force between them.
B. The larger the absolute value of the charges, the smaller the force between them.
C. The larger the distance between particles with charge, the larger the force between them.
D. The larger the distance between particles with charge, the weaker the force between them.
Explanation:
The force between charges is called electrostatic force. The force is given by the relation :
[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]
Where
k is the electrostatic constant
d is the distance between charges
It is clear from the above formula that the electrostatic force is directly proportional to the product of charges and inversely proportional to the square of distance between them.
It means the larger the absolute value of the charges, the larger the force between them. Also, the larger the distance between particles with charge, the weaker the force between them.
An athlete can exercise by making mechanical waves in ropes. What is the
medium of these waves?
A. Energy
B. The rope
C. The athlete
D. Air
Answer:
It would be B. The Rope
Explanation:
I say this because the rope is transferring energy from one location to another. Now, I could be totally wrong on this but I think this is right lol.
Answer:
The answer is B the rope.
Hope this helps <3 ;)
Frozen food will thaw more quickly when placed under running water than if it
is immersed in water. Why?
Answer:
google answers, i'm not 100% on how to type my own answer
Explanation:
Thaw food submerged under running water at a temperature of 70˚F (21˚C) or lower. The water flow must be strong enough to wash food particles into the overflow drain. In a microwave oven. You can safely thaw food in a microwave oven if the food will be cooked immediately.
The reason defrosting in water is preferable is because water conducts heat better than air. And the faster food is thawed, the better it tastes.
Answer:
The reason defrosting in water is preferable is because water conducts heat better than air. And the faster food is thawed, the better it tastes.
A liquid at rest in a fixed container exerts a force perpendicular to the wall of the container. Two students make claims about the microscopic cause of this force. Student A says that the force exerted by individual molecules as they bounce off the wall is always perpendicular to the wall. Student B says that the molecules may strike the wall at angles that are not perpendicular. Which student is correct and why?A. Student A . If the molecules hit at nonperpendicular angles, there would be a component of force parallel to the wall exerted on them. The net result would be macroscopic motion of the fluid.B. Student A . The molecules in a liquid are in random motion at the microscopic scale, so they move in every direction. Near the wall the molecules collide with each other in such a way that the components of their motion not parallel to the wall cancel.C. Student B . The molecules in a liquid are in random motion at the microscopic scale. For every atom that hits at an angle to one side of perpendicular, there is likely to be another atom hitting at the same speed at the same angle on the other side of perpendicular. On average the nonperpendicular components cancel.D. Student B . The walls of the container cannot move, so near the walls the parallel component of the motion of the molecules is cancelled by the net force the wall exerts on the liquid.
Answer:
C
Explanation:
Given that a liquid at rest in a fixed container exerts a force perpendicular to the wall of the container. Two students make claims about the microscopic cause of this force. Student A says that the force exerted by individual molecules as they bounce off the wall is always perpendicular to the wall. Student B says that the molecules may strike the wall at angles that are not perpendicular. Which student is correct and why?
The correct answer is option C
Student B . The molecules in a liquid are in random motion at the microscopic scale. For every atom that hits at an angle to one side of perpendicular, there is likely to be another atom hitting at the same speed at the same angle on the other side of perpendicular. On average the nonperpendicular components cancel
What does the diameter in meters need to be of a round parachute that the designer has determined needs to have an area of 500 square meters?
PLEASE HELP!!
A picnic basket falls out of a hot air balloon that is traveling horizontally at 14 m/s. The hot air balloon is
at an altitude of 250 m. Where does the picnic basket land relative to where it was dropped from?
Answer:
99.9999 m
Explanation:
[tex]a_{x} =0[/tex] [tex]v_{xo} =14[/tex] [tex]a_{y} =-g[/tex] [tex]v_{yo} =0[/tex]
X-direction | Y-direction
[tex]x=x_{o}v_{xo}t+\frac{1}{2} a_{x}t^2[/tex] | [tex]y=y_{o}v_{yo}t+\frac{1}{2} a_{y}t^2[/tex]
[tex]x=0+14(7.14285)[/tex] | [tex]0=250-\frac{1}{2} (-9.8)t^2[/tex]
x = 99.9999 m | [tex]-250=-4.9t^2[/tex]
| [tex]\sqrt{\frac{-250}{-4.9} } =\sqrt{t^2}[/tex]
| 7.14285s = t
Analysing the Question:
We are given:
height of the hot air balloon (h) = 250 m
horizontal velocity of hot air balloon (p) = 14 m/s
Since the balloon had no vertical velocity, the basket will drop vertically at a velocity of 0 m/s and gain its velocity due to acceleration
whereas the horizontal velocity of the balloon is 14 m/s, so the basket will have a horizontal velocity of 14 m/s when falling
there will be no change in the horizontal velocity of the basket since there is no force against the horizontal velocity of the falling basket
Time taken by the basket to reach the ground:
from the last section, we deduced that:
initial vertical velocity (u) = 0 m/s
time taken by the basket to reach the ground (t) = t seconds
acceleration of the basket due to gravity (a) = 10 m/s²
from the second equation of motion:
h = ut + 1/2*at²
replacing the variables
250 = (0)t + 1/2 * (10)(t)²
250 = 5t²
t² = 50
t = √50
t = 5√2 seconds OR 7 seconds
Horizontal distance travelled by the basket:
Distance travelled = horizontal speed * time taken to reach the ground
Distance travelled = 14 * 7
Distance travelled = 98 m