acceleration to move 650N with mass of 100 kg​

If heat is transferred between these objects via conduction, both arrows will point towards the cold.

Heat energy is transferred through the mechanism of conduction when nearby atoms or molecules collide. In solids and liquids, where particles are more closely spaced, conduction happens more easily than in gases, where particles are more widely spaced. Heat transfers through solid materials via conduction. The roof, walls, and windows of your house all carry heat on hot days.

The act of heating a skillet on a stovetop is a typical illustration of conduction. The surface of the pan receives heat directly from the burner. The amount of kinetic energy that the particles in a sample of matter have converted to heat is measured by temperature. Conduction mostly comes in two flavors. Steady-state conduction is what they are. temporary conduction.

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Answer:

Explanation:

Net force is determined by adding up all of the individual forces on an object. For example, to determine the net force on an airplane, you would add up the lift, weight, thrust, and drag. If forces are in opposite directions, like lift and weight, then you subtract them

The gravitational force that is acting on the masses is 1.73 * 10^-2 N.

We know that the force of gravity is that kind of force that is going to act on any two of the objects that we have on the earth. This force as we know it is attractive force. The implication of this is that any two masses that we find on the earth are the forces that would have to be attracted to each other.

Let us note that we would have the masses that we have of the asteroid and that of sally as m1 and m2 while we have the force as;

F = G m1m2/r^2

G = gravitational constant

F = magnitude of the force

m1 and m2 = masses

r = distance of separation.

We then have;

F = 6.6 * 10^-11 * 8.7 * 10^20 * 68/(15 * 10^6)^2

F = 3.9 * 10^12/2.25 * 10^14

F = 1.73 * 10^-2 N

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Answer:

vlarge = 4vsmall

Explanation:

Khan Academy

The mass of the car moving with a velocity of 17 m/s is 3115.4 kg.

Mass is the quantity of matter a body contains. The S.I unit of mass is kilogram

To calculate the mass of the car, we use the formula below

Formula:

Where:

From the question,

Given:

Substitite these values into equation 1

Hence, the mass of the car is 3115.4 kg.

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Answer:

a)The direction of the impulse that the glass imparts to the baseball Is opposite the direction of the balls motion

b)  [tex]I=0.6336Ns[/tex]

Explanation:

From the Question we are told that:

Mass [tex]m=0.144kg[/tex]

Initial Speed [tex]v_1=14.9m/s[/tex]

Final speed  [tex]v_2=10.5[/tex]

a)The direction of the impulse that the glass imparts to the baseball Is opposite the direction of the balls motion

b)

Generally the equation for impluse magnitude is mathematically given by

 [tex]I=m(v_1-v_2)[/tex]

Therefore

 [tex]I=0.144(14.9-10.5)[/tex]

 [tex]I=0.6336Ns[/tex]

Answer:

the surface temperature of Regulus A is 11724.13 K

Explanation:

Given the data in the question;

Sun's surface temperature T = 5800 K

total radiated power, relative to the sun is; P/P[tex]_{sun[/tex] = [tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex]

The star Regulus A is a bluish main-sequence star with mass 3.8M[tex]_{sun[/tex]  and radius 3.1R[tex]_{sun[/tex] .

First, we determine the value power emitted by the sun or sun as follows;

P = eσAT⁴

where P is the power, e is surface emissivity, σ is Stefan Boltzmann, A is area and T is temperature.

so, lets assume emissivity of star and sun is same;

let p be power related to star and p[tex]_{sun[/tex] be power related sun.

Ratio of power radiated by star and power radiated by sun;

P/P[tex]_{sun[/tex] = eσAT⁴ / eσA[tex]_{sun[/tex]T[tex]_{sun[/tex]⁴

we know that AREA A = πR²

we input the formula for area

P/P[tex]_{sun[/tex] = eσ(πR²)T⁴ / eσ(π(R[tex]_{sun[/tex])²)T[tex]_{sun[/tex]⁴

such that we now have;

P/P[tex]_{sun[/tex] = R²T⁴ / R[tex]_{sun[/tex]²T[tex]_{sun[/tex]⁴

given that P/P[tex]_{sun[/tex] = [tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex], we substitute

[tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex] = R²T⁴ / R[tex]_{sun[/tex]²T[tex]_{sun[/tex]⁴

we find temperature of the star T

T = 5800  × [tex][[/tex] 1.5[tex]([/tex]M/M[tex]_{sun[/tex][tex])^{3.5[/tex] (R[tex]_{sun[/tex]²/R²)[tex]]^{1/4[/tex]

Given that;  mass M is 3.8M[tex]_{sun[/tex] and radius R is 3.1R[tex]_{sun[/tex] .

we substitute

T = 5800  × [tex][[/tex] 1.5[tex]([/tex]3.8M[tex]_{sun[/tex]/M[tex]_{sun[/tex][tex])^{3.5[/tex] (R[tex]_{sun[/tex]²/( 3.1R[tex]_{sun[/tex] )²)[tex]]^{1/4[/tex]

T = 5800  × [tex][[/tex] 1.5[tex]([/tex]3.8[tex])^{3.5[/tex] ( 1/( 3.1)²)[tex]]^{1/4[/tex]

T = 5800  × [tex][[/tex] 1.5( 106.9652 ) ( 1/(9.61) [tex]]^{1/4[/tex]

T = 5800  × [tex][[/tex] 16.69592 [tex]]^{1/4[/tex]

T = 5800  ×  2.02140152

T = 11724.13 K

Therefore, the surface temperature of Regulus A is 11724.13 K

Explanation:

ac = v^2/r

= (7.0 m/s)^2/(0.75 m)

= 65 m/s^2

Answer:

Object 1

Explanation:

Newton's 2nd Law:  F = ma, therefore m = F/a

This shows that mass is inversely proportional to acceleration.  Because the resultant force (F) is held constant in this problem, the lower the acceleration, the greater the mass.  Therefore, the object that accelerates at 2 m/s² has the greater mass.  In other words, if the net force on both objects is the same, the object with the slower acceleration has the greater mass.  

Answer:

Did you forget to attach the image?

Explanation:

So far, we're not sure that you even HAVE a bulb or any switches.

If you had them, you probably would have included a diagram of the circuit you built with them. THEN we could look at the diagram and answer this question.

Right now, we can't.  We haven't seen such a diagram.

Answer:

Infinity. Yes, specific value of water during phase change is infinity. This is because, as long as water is present and it is changing phase (at boiling point or at any other constant temperature), the temperature of the water does not change no matter what amount of heat you are supplying to the water. Thus, its specific heat value is infinity.

Answer:

56.7m

Explanation:

horizontal velocity does not matter in this situation because it stays constant (no unbalanced force acting upon it)

a=9.81m/s^2              

t=3.4s

Vi=0m/s

d=Vi*t+1/2at^2

d=1/2at^2

d=1/2*9.81m/s^2*(3.4s)^2

d=4.905m/s^2*11.56s^2

d=56.7m

Beta decay is seen in the nuclear reaction: ⁹⁰₃₉Y → ⁹⁰₄₀Zr + ⁰₋₁e. Hence, option (A) is correct.

A proton can change into a neutron or vice versa inside the radioactive sample's nucleus through a process known as beta decay.

The radioactive sample's nucleus can approach the ideal neutron/proton ratio as closely as feasible through processes like beta decay and alpha decay. The nucleus releases a beta particle during this process, which can either be an electron or a positron.

As electron releases here, it is a Beta (β) decay.

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Answer:

the answer is a bowling ball

Answer:

24.132 m/s

Explanation:

Note

[tex]U[/tex] = Initial Velocity

[tex]U_x[/tex] = Initial Horizontal Velocity

[tex]U_y[/tex] = Initial Vertical Velocity

[tex]V[/tex] = Final Velocity

[tex]V_x[/tex] = Final Horizontal Velocity

[tex]V_y[/tex] = Final Vertical Velocity

[tex]B[/tex] = launch angle

[tex]g[/tex] = gravity

[tex]t[/tex] = time

[tex]U_x=U*cos(B)[/tex]

[tex]U_y=U*sin(B)[/tex]

The horizontal component of the velocity is constant throughout the flight. So [tex]U_x=V_x[/tex] It can be defined as

[tex]V_x=U*cos(B)[/tex]

We can use the kinematics equation

[tex]V=U+at[/tex]

Gravity is acting downwards; gravity would be negative

[tex]V_y=U_y-gt[/tex]

The magnitude of the velocity can be defined as

[tex]V=\sqrt{V_x^2+V_y^2}[/tex]

Inserting some of the other equations gives us an equation at a given time (t).

[tex]V=\sqrt{(U*cos(B))^2+(U*sin(B)-gt)^2}[/tex]

[tex]V=\sqrt{(UcosB)^2+(UsinB)^2+(gt)^2-2gtU*sinB[/tex]

[tex]V=\sqrt{U^2+g^2*t^2-2*t*g*U*sinB}[/tex]

[tex]V(t)=\sqrt{U^2+g^2t^2-2tgUsinB}[/tex]

We are given

[tex]U=34.6[/tex]

[tex]B=80.2[/tex]

[tex]t=1.09[/tex]

[tex]g=9.81[/tex]

[tex]V(1.09)=\sqrt{34.6^2+9.81^2*1.09^2-2*1.09*9.81*34.6*sin80.2}[/tex]

[tex]V(1.09)=\sqrt{34.6^2+114.338-2*1.09*9.81*34.6*sin80.2}[/tex]

[tex]V(1.09)=\sqrt{34.6^2+114.338-739.94868*sin80.2}[/tex]

[tex]V(1.09)=\sqrt{34.6^2+114.338-729.151}[/tex]

[tex]V(1.09)=\sqrt{1197.16+114.338-729.151}[/tex]

[tex]V(1.09)=\sqrt{582.347}[/tex]

[tex]V(1.09)=24.132[/tex]

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Let me know if you have any questions about my work

Answer:

drops

Explanation:

Ohm's Law states that V=I*R, where V is voltage, I is current and R is resistance. In a series circuit, the voltage drop across each resistor will be directly proportional to the size of the resistor. In a parallel circuit, the voltage drop across each resistor will be the same as the power source

Explanation:

a) ac = r(omega)^2

where omega = 2.5 rev/s

r = 0.75 m

We need to convert rev/s first into rad/s:

2.5 rev/s × (2pi rad/rev) = 5pi rad/s = omega

Therefore, the centripetal acceleration ac is

ac = (0.75 m)×(5pi rad/s)^2

= 185 m/s^2

b) Fc = mac

= (0.5 kg)(185 m/s^2)

= 92.5 N

Answer:

C. loses heat, temperature decreases

Explanation:

When gas condenses, energy decreases, therefore it would lose heat and the temperature would decrease.

Explanation:

it takes the earth 24 hours to spin on it's axis once

The maximum capillary rise of water to be expected  in the vertical glass tube is 15 mm.

The process of a liquid flowing in a small area without the aid of, or even in opposition to, any outside forces like gravity is known as capillary rise.

The effect can be observed in a biological cell, in a thin tube, in porous materials like paper and plaster, in some non-porous materials like sand, liquid carbon fiber, and some other porous materials.

The maximum capillary rise of water = 4σcosθ/ρgd

= ( 4 × 0.0733 × cos0°)/(10³ × 9.81 × 2 × 10⁻³) meter

= 0.015 meter

= 15 mm.

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Answer:

The magnitude of the gravitational force which the astronaut experience in satellite [tex]= 448[/tex] Newton

Explanation:

As we know

Gravitational force  F = [tex]\frac{GMm}{r^2}[/tex]

Where G is the gravitational constant [tex]6.67 * 10^{-11}[/tex]

M is the mass of earth [tex]= 6* 10^{24}[/tex]

m is not given

r is the radius of earth [tex]6 400*10^3[/tex]

Substituting the given values, we get -

[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3)^2}[/tex]

[tex]m = 71.6[/tex] Kg

Gravitational force in the satellite

[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3 + 1600 *10^3)^2}\\F = 448[/tex]N

Answer:

  x₁ = 0.62 m

Explanation:

In this exercise the force is electric, given by Coulomb's law

         F =[tex]k \frac{q_1q_2}{r^2}[/tex]

This force is a vector, since the three charges are in a line we can reduce the vector sum to a scalar sum.

For the sense of force let us use that charges of the same sign repel and charges of the opposite sign attract.

     ∑ F = F₁₂ - F₂₃

They ask us to find the point where the summaries of the force is zero.

      F₁₂ - F₂₃ = 0

      F₁₂ = F₂₃

let's fix a reference system located in the first charge (more to the left), the distance between the two charges is d = 1.5 m and x is the distance to the location of the second sphere

      k q₁q₂ / x² = k q₂q₃ / (d-x) ²

      q₁ (d-x) ² = q₃ x²

let's solve

       d² - 2 x d + x² = [tex]\frac{q_3}{q_1}[/tex]  x²

       x² (1 -  [tex]\frac{q_3}{q_1}[/tex]) - 2x d + d² = 0

we substitute the values

       x² (1- 4/2) - 2 1.5 x + 1.5² = 0

       x² (-1) - 3.0 x + 2.25 = 0

       x² + 3 x - 2.25 = 0

let's solve the quadratic equation

       x = [-3 ± [tex]\sqrt{ 3^2 + 4 \ 2.25}[/tex]] / 2

       x = [-3 ± 4.24] / 2

       x₁ = 0.62 m

       x₂ = 3.62 m

since it indicates that the charge q₂ e places between the spheres, the correct solution is

            x₁ = 0.62 m

Answer:

Joule ;)

Explanation:

In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.

Hope this helps!

Answer:

Explanation:

Joule

In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.

The magnitude of the constant acceleration of the ball is 9.7 m/s².

Acceleration is the rate of change of velocity.

To calculate the constant acceleration of the ball, we use the formula below.

Formula:

From the question,

Given:

From the question,

Given:

Substitute these values into equation 1

Hence, the acceleration is 9.7 m/s².

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1. Create a new question

2. Provide an image of your question/work so we don't have to download anything.

Answer:

electrons

Explanation:

Because electric current is flowed due to the presence of free electrons.

Answer:

The answer is "Option C"

Explanation:

Ohm's Rule we remember [tex]V = I\times R[/tex]

It looks like the sample is drawn y=mx while m is curve slope

The slope of the graph is its resistance if they draw a graph v vs I.

However, the internal battery presence resistance can be modified as the straight line equation

[tex]y = mx -c[/tex]

where c is y-intercept:

[tex]E = I(R+r) \\\\ E = IR+ Ir\\\\E = V + Ir\\\\V = E- Ir\\\\V = -Ir+E[/tex]

R is really the internal battery resistance to draw graph V vs I, the slope is internal resistance to the negative slope cure.

a,c,d, is your answer I think I hope it helps