A woman invested $15,000 part in 7% stocks and the remainder in 9% bonds. If her yearly yield from both investments is $1,230.00, how much did she invest at each rate?

Answers

Answer 1

Using the simple interest relation, the amount invested in stocks and bond respectively is $15,000 and $2000

Simple interest

Principal × rate × time

Let her total principal = p

Stock :

Interest = 15000 × 0.07 × 1 = 1050

Bond :

Interest = (p - 15000) × 0.09 = 0.09p - 1350

Total interest earned :

1050 + 0.09p - 1350 = 1230

-300 + 0.09p = 1230

0.09p = 1230 + 300

0.09p = 1530

p = $17000

Hence,

Amount invested in stock at 7% = $15000

Amount invested in bond at 9% = $17000 - 15000 = $2000

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Related Questions

Maths Question - Topic Pythagoras

Please answer the question. Awarding 20 points

Answers

Answer:

h= 17.67 cm

Step-by-step explanation:

We have,

h=x

b=16 cm

p=7.5cm

Using Pythagoras Theorem,

h^2=p^2+b^2

h=√(7.5^2+16^2)

h=√(56.25+256)

h=√312.25

h=17.6705970471 cm

The State Education Department requires local school districts to keep these records on all students: age, race or ethnicity, days absent, current grade level, standardized test scores in reading and mathematics, and any disabilities or special educational needs the student may have.

Which of the following are categorical (or qualitative) variables in these records?
Current Grade Level
Mathematics Test Score
Disabilities or Special Needs
Reading Test Score
Days Absent
Age
Race or Ethnicity

Answers

Answer:

Disabilities or Special Needs, Race or Ethnicity

Step-by-step explanation:

these are categories, while the rest are numbers

According to the given data, the categorical (or qualitative) variables are Disabilities or Special Needs, Race or Ethnicity.

What is categorical (qualitative) variables?

A qualitative variable is a categorical variable which is not numerical, it is based on quality that describes the characteristic of an individual.

What is Disability or Special Need?

"In clinical diagnostic and functional development, special needs refers to individuals who require assistance for disabilities that may be medical, mental, or psychological."

What is Race?

"The belief that some races of people are better than others; unfair ways of treating people of different races"

What is Ethnicity?

"An ethnic group or an ethnicity is a grouping of people who identify with each other on the basis of shared attributes that distinguish them from other groups."

As we know each discussed variable Disability or Special Needs, Race, and Ethnicity describes the characteristics of an individual. Hence, Disabilities or Special Needs, Race or Ethnicity are the qualitative variables.

To learn more about qualitative variables here

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#SPJ3

Please help hurry ,,,.€.£\’smsmmsms

Answers

bemwmwlwkwnebeb what do u need help on my guy??!!

please help.... fast​

Answers

Answer:

Napakadali lang sagutin nyan pre basic mangiba naman dapat Ang sagot ay SAS hopefully all

Under his cell phone plan, Alonso pays a flat cost of $53.50 per month and $3 per gigabyte. He wants to keep his bill at $59.80 per month. Write and solve an equation which can be used to determine gg, the number of gigabytes of data Alonso can use while staying within his budget.

Answers

Answer:

Alonso can use 2.1 gigabytes while staying within his budget.

Step-by-step explanation:

53.50 + 3x = 59.80

3x = 59.80 - 53.50

3x = 6.3

x = 6.3 ÷ 3

x = 2.1

Alonso can use 2.1 gigabytes while staying within his budget.

Jenelle bought a home for $260,000, paying 10% as a down payment, and financing the rest at 5.4% interest for 30 years. Round your answers to the nearest cent. How much money did Jenelle pay as a down payment? $ What was the original amount financed? $ What is her monthly payment? $ If Jenelle makes these payments every month for thirty years, determine the total amount of money she will spend on this home. Include the down payment in your answer. $

Answers

Step-by-step explanation:

260000*0*54*30

$421200

rectangular equation for the curve whose parametric equations are x = 2cosθ, y = cos2θ.

Answers

The rectangular equation for the curve is [tex]y = \frac{x^{2}}{2} -1[/tex].

In this question, we have a set of parametric equation which must be reduced into a single rectangular equation both by algebraic and trigonometric means, that is to say:

[tex]x = f(\theta), y = g(\theta) \to y = h(x)[/tex]

If we know that [tex]x = 2\cdot \cos \theta[/tex] and [tex]y = \cos 2\theta[/tex], then the rectangular equation is:

[tex]y = \cos 2\theta[/tex]

[tex]y = \cos^{2}\theta - \sin^{2}\theta[/tex]

[tex]y = 2\cdot \cos^{2}\theta -1[/tex]

[tex]\cos \theta = \frac{x}{2}[/tex]

[tex]y = 2\cdot \left(\frac{x}{2} \right)^{2}-1[/tex]

[tex]y = \frac{x^{2}}{2} -1[/tex]

The rectangular equation for the curve is [tex]y = \frac{x^{2}}{2} -1[/tex].

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According to the new remuneration scheme, the starting pay of a lecturer a is RM3,087 per month and the annual increment is RM195. Ahmad, who is 25 years old, becomes a lecturer in a university. (a) What will his monthly salary be when he is 45 years old? (b) What will his age be when he gets a monthly payment of RM8,937?​

Answers

Step-by-step explanation:

arithmetic sequence : every new item of the sequence is created by adding a constant term to the previous item - in this case 195.

a1 = 3087 (that's our starting value)

a2 = a1 + 195

a3 = a2 + 195 = a1 + 2×195

an = a1 + (n-1)×195

a)

when he is 45 years old, that is 20 years (and 20 annual increments) plus to our starting value.

so, n = 1+20 = 21

a21 = a1 + 20×195 = 3087 + 20×195 = 6987

so, when he is 45 years old, his monthly salary will be RM6,987

b)

how many years (= how big is n) until he gets 8937 ?

8937 = a1 + (n-1)×195 = 3087 + (n-1)×195 =

= 3087 + n×195 - 195 = 2892 + n×195

6045 = n×195

n = 6045/195 = 31

so, a31 = 8937

and that means, he has to work 30 additional years (31 minus the starting level 1) to earn monthly RM8,937.

that means he will be 25+30 = 55 years old.

Find the area of the surface.
The part of the sphere
x2 + y2 + z2 = 81
that lies above the plane
z = 4.

Answers

Parameterize this surface by

r (u, v) = 9 cos(u) sin(v) i + 9 sin(u) sin(v) j + 9 cos(v) k

with 0 ≤ u ≤ 2π and 0 ≤ v ≤ arccos(4/9)

See the attached sketch to see how we arrive at the upper limit for v.

Take the normal vector to the surface to be

n = ∂r/∂u × ∂r/∂v

n =  -81 cos(u) sin²(v) i -  81 sin(u) sin²(v) j - 81 sin(v) cos(v) k

which has magnitude

||n|| = 81 sin(v)

Then the surface area is

[tex]\displaystyle \iint_S \|\mathbf n\| \,\mathrm du\,\mathrm dv = 81 \int_0^{2\pi} \int_0^{\arccos(4/9)} \sin(v)\,\mathrm dv\,\mathrm du \\\\ = 162\pi \int_0^{\arccos(4/9)} \sin(v)\,\mathrm dv \\\\ = -162\pi (\cos\left(\arccos\left(\frac49\right) - \cos(0)\right) \\\\ = 162\pi \left(1 - \dfrac49\right) \\\\ = \boxed{90\pi}[/tex]

If you're not familiar with surface integrals, you can instead use what's sometimes called the projection method. Let

z = f(x, y) = √(81 - x ² - y ²)

(where we take the positive square root because we're looking at a part of the top half of the sphere)

Projecting the surface down onto the (x, y)-plane, we see that it casts a "shadow" of a disk with radius √(9² - 4²) = √65. (Use the Pythagorean theorem to solve for the missing side of the triangle in the sketch.)

Then the surface S considered above is hovering over the set in the (x, y)-plane,

D = {(x, y) : x ² + y ² ≤ 65}

The area is then

[tex]\displaystyle \iint_D \sqrt{1 + \left(\dfrac{\partial f}{\partial x}\right)^2 + \left(\dfrac{\partial f}{\partial y}\right)^2} \,\mathrm dx\,\mathrm dy[/tex]

It's easier to compute this integral in polar coordinates, so we take

x = r cos(t )

y = r sin(t )

dx dy = r dr dt

and the region D is given by the set

{(r, t ) : 0 ≤ r ≤ √65 and 0 ≤ t ≤ 2π}

Then the integral would be

[tex]\displaystyle \iint_D \sqrt{1 + \left(\dfrac{\partial f}{\partial x}\right)^2 + \left(\dfrac{\partial f}{\partial y}\right)^2} \,\mathrm dx\,\mathrm dy = \iint_D \sqrt{1 + \frac{x^2+y^2}{81-x^2-y^2}}\,\mathrm dx\,\mathrm dy \\\\ = \iint_D \sqrt{\frac{81}{81-x^2-y^2}}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^{2\pi} \int_0^{\sqrt{65}} r \sqrt{\frac{81}{81-r^2}}\,\mathrm dr\,\mathrm dt[/tex]

Substitute s = 81 - r ² and ds = -2r dr :

[tex]\displaystyle \int_0^{2\pi} \int_0^{\sqrt{65}} r \sqrt{\frac{81}{81-r^2}}\,\mathrm dr\,\mathrm dt = 2\pi \int_0^{\sqrt{65}} r \sqrt{\frac{81}{81-r^2}}\,\mathrm dr \\\\ = -9\pi \int_{81}^{16} \frac{\mathrm ds}{\sqrt s} \\\\ = 9\pi \int_{16}^{81} s^{-1/2}\,\mathrm ds \\\\ = 18\pi \left(\sqrt{81} - \sqrt{16}\right) \\\\ = \boxed{90\pi}[/tex]

ACME insurance company estimates that the probability of the owners’ of a house worth between $120,000 to $170,000 making a claim for $5000 is 0.08, and that the probability of the house and contents being totally destroyed is 0.0041. Should that tragedy happen, the company will have to pay $150,000. The company charges $1300 for the insurance policy.

What is the expected value of this policy to the insurance company?

Round your answer to two decimal places.

Answers

The expected value of this policy to the insurance company is $285.00.

Using this formula

Policy expected value=Insurance policy charges-[(Probability × Claim)+(Probability × Claim)]

Let plug in the formula

Policy expected value=$1,300-{(.0041)($150,000)+(.08)($5,000)]

Policy expected value=$1,300-($615+$$400)

Policy expected value=$1,300-$1,015

Policy expected value=$285.00

Inconclusion the expected value of this policy to the insurance company is $285.00

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Solve equation for 3(2x - 5) - (2x - 5) = 6(4x + 5)​

Answers

Answer:

the answer is negative two / x= -2

>>Answer

_________

[tex] \: [/tex]

[tex] \rm3(2x - 5) - (2x - 5 ) = 6(4x + 5)[/tex]

[tex] \rm6x - 15 - 2x - 5 = 24x + 30[/tex]

[tex] \rm4x - 20 = 24x + 30[/tex]

[tex] \rm4x - 24x = 30 + 20[/tex]

[tex] \rm - 20x = 50[/tex]

[tex] \rm \: x = \frac{50}{ - 20} [/tex]

[tex] \rm \: x = \boxed{ - 2 \frac{1}{2} }[/tex]

The model below represents an equation. IN Which represent like terms in the model of the equation? and and T Save and Exit Next Mark this and return Ei O Type here to search NEWD HELP ASAP PLSSS ​

Answers

Answer:

x x x and 1 1 1

Step-by-step explanation:

3rd option is the correct answer.

can anyone help me pls asap​

Answers

polygon

quadrilateral

triangle

rectangle

hexagon

hexagon

octagon

square or parallelogram

trapezoid

square

heptagon

decagon

gon, gon, the gons mason, what do the gons mean.

need help with this algebra ii question

Answers

Vertex form: y = |x - h| + k

Vertex = (h, k)

G(x) was shifted 3 to the right and up 2.

G(x) = |x - 3| + 2

Hope this helps!! :)

I need help, please. ​

Answers

[tex]p = 2(l + w) = 2.(15 + 12) = 54 cm[/tex]

Solve for y 2 y = A 2Y + B + A B

Answers

Call me when you want, call me when you need

Call me in the morning, I'll be on the way

Call me when you want, call me when you need

Call me out by your name, I'll be on the way like


What is the distance from (-4, 0) to (2, 5)? Round your answer to the nearest hundredth.

Answers

Answer:

7.81

Step-by-step explanation:

Step-by-step explanation:

[tex]distance = \sqrt{(x2 - x1) ^{2} + (y2 - y1) ^{2} } [/tex]

Now, substitute the numbers into the equation,

[tex] \sqrt{(2 + 4) ^{2} +( 5 - 0)^{2} } [/tex]

distance = 7.81

brianlist me??

please please help me​

Answers

It’s 60°, because a triangle has 180° and it’s an equilateral triangle therefore 60

of all the trees planted last year by a landscaping firm, only 1 in 10 trees died within a month. suppose a new landscaping firm is hired to plant 15 new trees. Let X denote the number of trees planted out of the 15 that died.
What is the lowest value of X that is consistent with the belief that the tree died due to mishandling?

Answers

The number of trees that died is an illustration of proportions.

The lowest value of X that is consistent with the belief that the tree died due to mishandling is 1.5

From the question, we have: 1 out of 10 died

This means that, the mean number of trees that died are:

[tex]\mathbf{\bar x =\frac{1}{10}}[/tex]

In 15 trees, the number (n) of trees expected to die is:

[tex]\mathbf{n = \bar x \times 15}[/tex]

So, we have:

[tex]\mathbf{n = \frac{1}{10} \times 15}[/tex]

[tex]\mathbf{n = 1.5}[/tex]

Hence, the lowest value of X is 1.5

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A student bought 44 pencils for school. if he sharpened 8 of the pencils before school, what is his ratio of unsharpened pencils to sharpened pencils

Answers

Answer:

8:36

Step-by-step explanation:

if you sharpened 8 pencils out of 44 that means 8 pencils are sharpened and the other 36 aren't

36:8 this is it because after he sharpens them he will have 36 unsharpened to sharpened pencils

Two standard dice are thrown. Determine the theoretical probability that the sum is
a) 4 b) 7
c) an even number d) not a 6 e) not a perfect square

Answers

Step-by-step explanation:

there are 36 (6×6) possible results and number combinations for 2 dice.

a)

to create a sum of 4 we need one of the following combinations :

1 3

2 2

3 1

so, 3 out of the overall possible 36 possibilities.

and that means the probability is 3/36 = 1/12

b)

to create a sum of 7 we need one of the following combinations :

1 6

2 5

3 4

4 3

5 2

6 1

so, 6 out of the overall possible 36 possibilities.

and that means a probability of 6/36 = 1/6

c)

since the possible outcomes in that regard are only 2 (even and uneven), with equal balance the probability is 1/2.

make it more formal ?

to get an even sum, every possible number on one die can be combined with 3 possibilities on the other.

1 can be combined with 1, 3, 5

2 with 2, 4, 6

3 with 1, 3, 5

4 with 2, 4, 6

5 with 1, 3, 5

6 with 2, 4, 6

these are 6×3 = 18 combinations of of the possible 36.

so, the probability is 18/36 = 1/2

d)

not a 6 ?

so, what does that mean ?

we are looking only at 5 possible outcomes per die.

that is 5×5 = 25 combinations out of the possible 36.

that means that probabilty is 25/36.

e)

not a perfect square ?

we have in the range of the possible sums with 2 dice (2 .. 12) only two perfect squares : 4 and 9

so, the sum must NOT be 4 AND NOT be 9.

so, here it might be easier to count the unwanted cases and then deduct the probability from 1 to express the opposite.

the combinations to get 4 we have already under a)

3 combinations with 3/36=1/12 probability.

the combinations to get 9

1 none

2 none

3 6

4 5

5 4

6 3

so, 4 combinations with a probability of 4/36 = 1/9

therefore, we have (3+4) = 7 cases out of the possible 36 we actually want to avoid.

so, the probability to get any one of the other (desired) combinations is therefore (36-7)/36 = 29/36

The probabilities are:

a)  0.083b) 0.167c)   0.5d)  0.861e) 0.806.

How to get the probabilities?

The probability for a given outcome is given by the quotient between the number of combinations that give that outcome and the total number of combinations.

Here each dice has 6 possible outcomes, so the total number of combinations for the two dice is:

6*6 = 36 combinations.

a) Here we need to count how many combinations add to 4, the notation I will use is:

dice 1   dice 2

1              3

3               1

2               2

There are 3 combinations that add to 4, then the probability of getting a sum equal to 4 is:

P = 3/36 = 0.083

b) Same thing as before, this time we count the combinations that add to 7.

dice 1   dice 2

1               6

6               1

5               2

2               5

4                3

3                4

There are 6 combinations that add to 7, so the probability is:

P = 6/36 = 0.167

c) The possible even numbers are: {2, 4, 6, 8, 10, 12}

A way of doing this, is:

If the first dice is even/odd, then the second also must be even/odd.

Then the probability is just 1/2  = 0.5 (because there are the same number of odd and even numbers in a dice).

d) The sum must not be equal to 6, the combinations that add up to 6 are:

dice 1   dice 2

2            4

4             2

3             3

1              5

 5            1

So 5 combinations add up to 6, then there are 31 combinations that do not add up to 6, this means that the probability of not getting a sum equal to 6 is:

P = 31/36 = 0.861

e) The perfect squares are 4 and 9, we already know that 3 combinations add up to 4, now let's find the combinations that add up to 9.

dice 1   dice 2

6             3

3              6

5              4

4               5

So 4 combinations add up to 9, then there is a total of 7 combinations that give a perfect square, then there are 29 combinations that do not add to a perfect square.

The probability is:

P = 29/36 = 0.806

If you want to learn more about probability, you can read:

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can anyone heelp me pls

Answers

Answer: lotion- semisolid

capsule- solid

suspension- liquid

Step-by-step explanation:

UWUWUWUWIWUWUWUUWWUWUWUUWWUUWUWWUUWUWUWWUUWU2UWUWUWUWUWUWUWUWUWUUWUWUWU​

Answers

Answer:

UWUWUWUUWUWUWUWUUWUWUW

Step-by-step explanation:

UwU OwO

Michelle has money in two savings accounts. One rate is 6%

and the other is 14%
. If she has $900
$

900
more in the 14%

account and the total interest is $209

, how much is invested in each savings account?

Answers

Answer:

$415 at 6% and $1315 at 14%

Step-by-step explanation:

She has x amount at 6%.

She has y amount at 14%.

y = x + 900

0.06x + 0.14y = 209

Since the first equation is already solved for y, we use the substitution method. Substitute x + 900 for y in the second equation and solve for x.

0.06x + 0.14(x + 900) = 209

0.06x + 0.14x + 126 = 209

0.2x = 83

x = 415

y = x + 900

y = 415 + 900

y = 1315

Answer: $415 at 6% and $1315 at 14%

Please answer this question!!

Answers

I believe the answer is A A and A. pls mark me as brainliest!

What is the distance between the points (7, 8) and (-8, 0) on a coordinate grid?

Answers

Answer:

17 units

Step-by-step explanation:

Answer:

17

Step-by-step explanation:

What are the domain and range of the function below?

A. Domain: (-∞,-5)
Range: (5,∞)

B. Domain = (-∞,∞)
Range: (-10,5)

C. Domain: (-5,10)
Range: (-10,5)

D. Domain: (-∞,∞)
Range: (-∞,∞)

Answers

Answer:

D

Step-by-step explanation:

the graphic does not indicate any limitation in any form in any direction.

compared to a default y = x function this function is just shifted a bit. but that does not block x or y from "running" all the way from -infinity to +infinity.

NO LINKS!!! Hyperbola: y = 1/x

Shape:
Domain:
Range:
Locater point:
Asymptotes:

Answers

Hyperbola: y = 1/x

--------------------------------

Shape: open curve with two branches

Domain: Any non-zero real number x < 0, x > 0 or x∈ (-∞, 0) ∪ (0, +∞)

Range: Any non-zero real number y < 0, y > 0 or y∈ (-∞, 0) ∪ (0, +∞)

Locater point: Imaginary point of intersection of asymptotes (0, 0)

Asymptotes: x = 0 and y = 0

0.25555555 as a fraction

Answers

Answer:

23/90

Step-by-step explanation:Sorry if it's wrong!!!

If f ( x ) is a linear function, f ( − 1 ) = 2 , and f ( 5 ) = − 5 , find an equation for f ( x ) . f ( x ) =__
show your work!

Answers

Step-by-step explanation:

Let's first find the slope

(-5-2)/(5--1) = -7/6

the equation should be

[tex]y = \frac{ - 7}{6} x + c[/tex]

To find c, we replace X with -1 and Y with 2

c= 5/6

So the equation is

[tex]y = \frac{ - 7}{6} x + \frac{5}{6} [/tex]

And if you multiply everything by 6 you get

6y = -7x +5

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