Answer:
F = I L X B = I L B sin theta
F = 5.2 * 1.2 * .87 sin 45 = 3.84 N in the direction of (L X B)
Note: L and B must be at right angles for F = I L B
A snowboarder on a slope starts from rest and reaches a speed of 3.4 m/s after 7.3 s.
The acceleration of the snowboarder is 0.466 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the acceleration of the snowboarder, we use the formula below.
Formula:
a = (v-u)/t........................ Equation 1Where:
a = Accelerationv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 3.4 m/su = 0 m/st = 7.3 sSusbtitute these values into equation 1
a = (3.4-0)/7.3a = 0.466 m/s²Hence, the acceleration is 0.466 m/s².
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Figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
1. List the values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s.
To solve this we must be knowing each and every concept related to interval. Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as below.
What is interval?An interval is any set of numbers that fall between two distinct integers. This range includes all real values that fall between those two. All real numbers that lie in any 2 of a set's numbers are collectively referred to as an interval within mathematics.
For instance, the set of integers x fulfilling 0 x 1 is the interval consisting of 0, 1, and all numbers in between. a snapshot graph of wave on a string moving toward one another at 1 m/s at time t = 0 s.
At time t = 0,Y₀= 0 cm
At At time t =1, Y₁= 0 cm
At time t = 2, Y₂= 0 cm
At time t =3, Y₃= 0 cm
At time t =4, Y₄= 0 cm
At time t = 5 ,Y₅=0 cm
At time t = 6, Y₆= 0 cm
Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as above.
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9. All of the following are adaptations of herbivores EXCEPT:
special digestive systems for digesting plant cellulose
Okeen eyesight for sporting prey
O coat colors that help them blend in with the land
fut teeth for chewing tough plant matter
PLZ HURRY PLZ IMM MARK BRAINLYEST
Answer:
B.KEEN EYESIGHT thats for predators !
Explanation:
Herbivores have multiple stomachs to process tough foods, coats to blend in so they don't get eaten, and tough teeth for chewing on the plants. THEY DO NOT HAVE PREY, THEY ARE THE PREY.
Which of the following light waves will have the highest frequency?
a. blue light
b. orange light
c. green light
d. red light
e. yellow light
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If could watch a rocket that's putting a satellite into orbit around the Earth, you'd see that it doesn't just go straight up. It eventually leans over and flies basically parallel to the Earth's surface when it gets up high. Why does it do this?
a. It needs to stay close to the Earth, so that the satellite doesn't get affected by the gravity of the Moon.
b. It needs to be moving horizontally at a high speed, in order for the satellite to stay in orbit once it's released from the rocket.
c. It has to release the satellite inside the Earth's atmosphere.
d. If it doesn't turn over horizontally, it'll release the satellite in a region where there's no gravity.
Answer:
the correct answers B
It needs to be moving horizontally at a high speed, in order for the satellite to stay in orbit once it's released from the rocket.
Explanation:
In this exercise, let's look for the solution to the problem before reviewing the statements to find out which one is correct.
When the satellite is in orbit it must comply with Newton's law
F = m a
the force of the universal attractive force and the acceleration is centripetal
a = v² / r
we substitute
- G m M /r² = -m v² / r
v² = G M / r
v = [tex]\sqrt{\frac{GM}{r} }[/tex]
When analyzing this expression, the satellite is in a stable orbit because its centripetal acceleration creates a change in the direction of the velocity in such a way that it remains in an orbit
when reviewing the correct answers B
Part A : A cylindrical water tank 10cm high and 520cm in diameter is filled with solution with a density of 0.75 g/cm^3
a) What is the water pressure on the bottom of the tank? (pressure in psi)
Show calculations
b) What is the average force on the bottom?
Answer: [tex]0.1066\ psi, 15.611\ kN[/tex]
Explanation:
Given
the height of the tank is [tex]h=10\ cm[/tex]
The diameter of the tank is [tex]d=520\ cm[/tex]
Density of solution [tex]\rho=0.75\ g/cm^3\ or\ 750\ kg/m^3[/tex]
[tex](a)[/tex] Water pressure at the bottom of the tank is
[tex]P=\rho gh\\P=750\times 9.8\times 0.1\\P=735\ Pa[/tex]
[tex]1\ Pa=0.000145038\ psi[/tex]
[tex]\Rightarrow P=735\ Pa\ or\ 0.1066\ psi[/tex]
[tex](b) \text{Average force on the bottom is the product of pressure and area of the base}[/tex]
[tex]F_{avg}=735\times \pi \cdot (\frac{520}{200})^2\\\\F_{avg}=735\times 3.142\times 6.76\\F_{avg}=15,611.34\ N\ or\ 15.611\ kN[/tex]
The rabbit flea Spilopsyllus has a mass of 0.45 mg. It can jump vertically to aheight of about 3.5 cm. Biologists have hypothesized that the energy for the jump is most likely derived from the elastic potential energy stored in the resilin pads ofthe two rear legs of the flea. Each pad is estimated to have a volume of about and its strain typically reaches a value of 100%. The elastic modulus of resilience is about . Is the hypothesis plausible
Answer:
Therefore The hypothesis is not plausible Because
[tex]P.E \geq P.E_e[/tex]
[tex]P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J[/tex]
Explanation:
From the question we are told that:
Mass [tex]M=0.45mg[/tex]
Jump height [tex]h=3.5cm \approx 0.03m[/tex]
Percentage strain [tex]\mu =100\%[/tex]
Generally the equation for potential energy is mathematically given by
[tex]P.E=mgh[/tex]
[tex]P.E=0.45*10^{-3}*9.8*0.03[/tex]
[tex]P.E=12.435*10^{-5}J[/tex]
Generally the equation for Elastic potential energy is mathematically given by
[tex]P.E_e=0.5*stress*strain *volume[/tex]
[tex]P.E_e=0.5*1*2*10^6*1*1.4*10^{-4*(10^-3)^3}[/tex]
[tex]P.E_e=1.4*10^{-7}J[/tex]
The hypothesis is only plausible at conditions where
[tex]P.E\leq P.E_e[/tex]
Therefore The hypothesis is not plausible Because
[tex]P.E \geq P.E_e[/tex]
[tex]P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J[/tex]
Draw and label where the molecules of the test mixture ended up after the fan was turned off
Answer:
ahhahsvdjdjkd
Explanation:
sbnwtauajababcahajanavgzuz
As an object falls freely, the potential energy of the object
What is the average time for the toy car to move 1.0 m on cement?
Answer:
24.4
Explanation:
you would add all the numbers , 25.5+24.4+24.2= 73.1/3=24.36 and you round up you get 24.4
A standard parallel plate capacitor is connected to a battery and is given enough time to charge fully. After it is fully charged, the capacitor is disconnected from the battery. After that, prankster Bob comes along and pulls the plates further apart from each other, doubling the distance d between the plates. How do the following quantities change? The choices are: quadruple, double, stay the same, halve, or quarter.
a) Capacitance
b) Charge on the capacitor
c) Voltage across the capacitor
d) Electric field within the capacitor
e) Energy stored in the capacitor
f) Does Bob have to do work in order to pull the plates apart? (Yes or no, and a brief explanation)
g) Are parts (e) and (f) consistent, given that the battery was disconnected?
Answer:
a) capacitance is doubled., b) Q = cte, c) oltage doubling the distance doubles, d) ΔE =0, e) U = Q² / 2C, f) W>0
Explanation:
he capacitance of a condensate is
C =[tex]\frac{ Q}{ \Delta V} =\epsilon_o \frac{A}{d}[/tex]
let's use this expression to answer the question
a) Capacitance.
Without distance, the capacitance is doubled.
Answer: Half
b) The charge.
As the battery is disconnected, no more electrons reach the capacitor, so the charge remains the same
Q = cte
c) the voltage
ΔV = E d = ([tex](\frac{Q}{\epsilon_o A}) \ d[/tex]
so the voltage doubling the distance doubles
d) The electric field between parallel plates is constant
E = Q / A eo
E =0
e) The stored energy is described by the expression
U = Q² / 2C
as capacitance decreases and discant increases, stored energy increases
f) The work to separate the positive charge, that the force must be in the same direction as the electric force
g) when the battery is disconnected the energy in the capacitor remains constant
Kam does 4000J of work in climbing a set of stairs. if he does work in 6 seconds, whi is his power output?
Answer:
666.7 W
Explanation:
Power = P = W/t = 4000 J/6 s = 666.7 W (watts)
All of the following are examples of physical properties except which one?
A. conductivity
B. malleability
C. flammability
D. solubility
Answer:
the answer is c
Explanation:
melting = become liquefied by heat
solubility = a new bond formation
conductivity = electric transmitter
flammability = burnable
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
Answer:
the f is 1.3 m
Explanation:
Given that
An object 2.0m is from the concave mirror
And, the image is 4.0m from the mirror
We need to find out the f
So,
u = -2 m
v = -4 m
1 ÷ f = 1 ÷ v + 1 ÷ u
= (-1 ÷ 4) + (-1 ÷ 2)
= -3 ÷4
f = -4 ÷ 3
= |1.3| m
Hence, the f is 1.3 m
which of the following changes will increase the period of an oscillating spring mass system?
a. an increase in the mass on the spring.
b. an increase in the initial displacement of the spring.
c. an increase in the spring constant.
d. more than one of the above.
e. none of the above.
explain your answer in your own words.
NO LINKS.
Answer:
. an increase in the mass on the spring
Explanation:
Period of oscillation is inversely proportional to amplitude. Since amplitude is displacement and displacement is, the answer of objective b is ignored
My answer is a
Differentiate between mass and weight
Answer:
The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.
Explanation:
what is the atmosphere pressure on earth will support a column of mercury about 760 mm high, since the atmosphere pressure on the surface of the planet venus is 9200 kpa (1330 pal) , about 91 times that of earth about how tall a mercury column could venus’s atmosphere support ?
The atmospheric pressure on earth is 1 atm. This pressure is equivalent to the mercuric pressure of 760 mmHg. The atmospheric pressure on the surface of Venus is 9200 kpa which is equivalent to 69017 mmHg.
What is atmospheric pressure?Pressure is the force acting per unit area. In the atmosphere, the gaseous particles and dust exerts a pressure in the atmosphere. The atmospheric pressure depends on the temperature.
There are various units for pressure. Normally the atmospheric pressure is expressed in atm unit. The mmHg pressure is based on the raise in mercuric level with respect to increase in pressure.
1 mmHg = 0.0013133 atm
hence, 760 mmHg = 1 atm
On the surface of Venus, the pressure is 9200 kilopascal.
1 mmHg = 0.133 KPa
then 9200 KPa = 9200/0.133 = 69017 mmHg pressure.
Therefore, height of mercuric column will be 69017 mm in Venus surface.
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Which describes the relationship between the frequency, wavelength, and speed of a wave as the wave travels through different media?
As speed changes, wavelength changes and frequency remains constant
As speed changes, frequency changes and wavelength remains constant As speed changes, wavelength and frequency change,
O As speed changes, wavelength and frequency remain constant
Answer: A) as speed changes, wavelength changes and frequency remains constant
Explanation: edg test
The ocean’s tides are not only affected by the shape of the coastlines, or slope of the ocean floor, but also by the gravitational tug of the Sun and the Moon. Write a 600 word report on the effect of the Moon, and Sun, on tidal reaction, and high tides and low tides. What orientation are the Sun and Moon in to create high tides? Low tides? There are two special types of tides. What are they called and what positions are the Sun and the Moon in during these times?
The shape of the coastlines and the slope of the ocean floor, as well as the gravitational pull of the Sun and Moon, all have an impact on the tides of the ocean.
What are tides?Tides are extremely long-period waves that travel across the water as a result of the moon's and the sun's gravitational pull. The rise and fall of the sea's surface on a regular basis is what tides, which originate in the ocean, appear as as they move toward the coastlines.
High tide is when the wave's highest portion, or crest, reaches a specific area; low tide is when the wave's lowest portion, or trough, reaches that location. The term "tidal range" refers to the height difference between high tide and low tide.
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Millikan used tiny oil droplets and adjusted the electric field until the electric force balanced the weight of the droplet, and one of the droplets hovered in air. However, the drops are all different sizes and weights, and the amount of charge on each droplet also varies. So, the tuning of the electric field is different for droplets of different sizes, which carry different charges. Let us assume that the density of the oil Millikan used in his experiment is 800 kg m3
A. Calculate the mass (in kg) of the hovering droplet if its radius is measured to be 65 um.
B. Calculate the electric field (in V/m) required to counter the weight of the above droplet if it carries a charge q = 2e.
C. In the second trial, the hovering droplet has a mass of 10-15 kg. It carries a charge of q = 11e. calculate the electric field (in V/m) required to counter the weight of this droplet.
Answer:
A. 9.203 × 10⁻¹⁰ kg
B. 2.82 × 10¹⁰ V/m
C. 5.56 × 10³ V/m
Explanation:
A. Calculate the mass (in kg) of the hovering droplet if its radius is measured to be 65 um.
We know density, ρ = mass of oil drop, m/volume of oil drop, v
m = ρv
ρ = 800 kg/m³ and v = 4πr³/3 (ince the oil drop is a sphere) where r = radius of oil drop = 65 μm = 65 × 10⁻⁶ m.
So, m = ρv = ρ4πr³/3
= 800 kg/m³ × 4π(65 × 10⁻⁶ m)³/3
= 800 kg/m³ × 4π274625 × 10⁻¹⁸ m³/3
= 878800000π × 10⁻¹⁸ kg/3
= 2760831623.97 × 10⁻¹⁸ kg/3
= 920277207.99 × 10⁻¹⁸ kg
= 9.203 × 10⁻¹⁰ kg
B. Calculate the electric field (in V/m) required to counter the weight of the above droplet if it carries a charge q = 2e.
Since the electric force F = qE where q = charge on oil drop = 2e where e = electron charge = 1.602 × 10⁻¹⁹ C and E = electric field equals the weight of the oil drop W = mg where m = mass of oil drop = 9.203 × 10⁻¹⁰ kg and g = acceleration due to gravity = 9.8 m/s².
So, F = W
qE = mg
E = mg/q
E = mg/2e
substituting the values of the variables into the equation, we have
E = 9.203 × 10⁻¹⁰ kg × 9.8 m/s²/(2 × 1.602 × 10⁻¹⁹ C)
E = 90.1894 × 10⁻¹⁰ kg-m/s²/3.204 × 10⁻¹⁹ C
E = 28.15 × 10⁹ V/m
E = 2.815 × 10¹⁰ V/m
E ≅ 2.82 × 10¹⁰ V/m
C. In the second trial, the hovering droplet has a mass of 10-15 kg. It carries a charge of q = 11e. calculate the electric field (in V/m) required to counter the weight of this droplet.
Since F = W
qE = mg
E = mg/q
E = mg/11e
E = 10⁻¹⁵ kg × 9.8 m/s²/(11 × 1.602 × 10⁻¹⁹ C)
E = 9.8 × 10⁻¹⁵ kg-m/s²/17.622 × 10⁻¹⁹ C
E = 0.556 × 10⁴ V/m
E = 5.56 × 10³ V/m
Usain Bolt requires five seconds to step after he runs the 100 meter dash . When he wins the race he's running at 10 meters per second . What is his declaration? Please answer as soon as possible!
Answer:
d= -2
Explanation:
t=5s
S=100 meters
V= 10 m/ s
d=?
deceleration = (final velocity - initial velocity) / time. d = (vf - vi)/t.
The formula for acceleration can be used, recognizing that the final result must have a negative signe.
d= (0-10)/5
d= -2
What is the difference between positive and negative punishment?
In psychology
Answer: Negative punishment includes taking away a certain reinforcing item after the undesired behavior happens in order to decrease future responses. Positive punishment involves adding an aversive consequence after an undesired behavior is emitted to decrease future responses.
HOPE THIS HELPS
SUKHMANJOT
Which of the following is not a safety tip for outdoor activities
The following which is not a safety tip for outdoor activities is to go alone for a sense of oneness with nature and is therefore denoted as option A.
What is Safety?This is referred to as the condition of being protected from harm or other danger and it involves the use of various methods and activities and an example is to ensure that a basic first aid kit is available so as to help in the incident of an injury.
However going alone for a sense of oneness with nature is not a safety tip as should in case any issue arises there will be no one to support and rescue such individual.
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The full question is:
Which of the following is not a safety tip for outdoor activities
a. go alone for a sense of oneness with nature
b. bring a basic first aid kit
c. bring a flashlight or headlamp
d. pack plenty of water and energy-dense food
Which letter of the following shows lateral inversion in a mirrior
i.A
ii.N
iii.M
iv.V
Answer:
ii. N
Explanation:
N is not laterally symmetrical. so it shows inversion in a mirror.
Answer:
ii) N
hope it is helpful to you
Three point charges are arranged at the corners of a square of side L as shown in Fig. What is the potential at the fourth corner (point A), taking V=0 at a great distance?
Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].
What is Electric field strength?Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.
We are given that:
Number of point charges = 3
Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so
E4 = E1 + E2 + E3
E4 = kQ/a² + kQ/√(2a²) + kQ/a²
E4 = kQ [1/a² + 1/√(2a²) + 1/a²]
E4 = kQ [2/a² + 1/a√2]Thus the electric field at the fourth corner is E4 = kQ [2/a² + 1/a√2].
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What makes water move through the water cycle? A the sun the rain C precipitation the ground
Answer: A. The Sun
Explanation: A. The Sun makes water move through the water cycle
5.33 A constant force F= (4.70-379, 2.09) N. acts on an object of mass 180 kg, causing a displacement of that object by F= (4.25, 3.69-245) m What is the total work done by this force
The total work done by this force is 28.9-1457.86 N m.
What is total work?Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.
The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.
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A thin rod has a length of 0.609m and rotates in a circle on a frictionless tabletop. The axis is perpendicular to the length of the rod at one of its ends. The rod has an angular velocity of 0.606rad/s and a moment of inertia of 1.05 x 10^-3 kg•m^2. A bug standing on the axis decides to crawl out to the other end of the rod. When the bug (whose mass is 5 x 10^-3 kg) gets where it’s going, what is the change in the angular velocity of the rod?
Answer:
-0.0069 rad/s
Explanation:
The change in angular velocity of the rod can be determined by using the conservation of angular momentum equation: Lf = Li.
The initial angular momentum of the rod is Li = Iwo and the final angular momentum of the rod is Lf = Iwf.
Plugging in the given values, we get:
(1.05 x 10^-3 kg•m^2)(0.606 rad/s) + (5 x 10^-3 kg)(0.609 m)^2(wf) = (1.05 x 10^-3 kg•m^2)(wo).
Solving for wf, we get wf = -0.0069 rad/s.
Therefore, the change in angular velocity of the rod is -0.0069 rad/s.
What is true about the direction of the force of friction? A. It always points straight down. B. It always opposes the direction of motion. C. It always points straight up. D. It never changes direction.
Answer: it always opposes the directions of motion is the right answer
Explanation:
A car is travelling at 27m/s and decelerates at a=5m/s2 for a distance of 10m. Calculate its final velocity. (Hint does deceleration imply that the acceleration is positive or negative?)
If deceleration = 5 m/s²
then acceleration = -5 m/s²
According to third law of motion,
= v² = 2as + u²
= v² = 2×-5×10 + 27²
= v² = -100 + 729
= v =√ 629
= 25.08 m/s