A walking path across a park is represented by the equation y=-3x - 3.A
new path will be built perpendicular to this path. The paths will intersect at
the point (-3,6). Identify the equation that represents the new path.

Answers

Answer 1

Answer:

[tex]y=\frac{1}{3} x+7[/tex]

Step-by-step explanation:

We need to find the equation of a line perpendicular to [tex]y=-3x-3[/tex], which passes through the point (-3, 6).

Recall that a line perpendicular to a line of the form: [tex]y=mx+b[/tex], must have a slope which is the opposite of the reciprocal of the slope of the original line. that is, a slope of the form;

[tex]slope=-\frac{1}{m}[/tex]

Then, in our case, since the original line has slope "-3", a perpendicular line to it should have a slope given by:

[tex]slope=-\frac{1}{-3} =\frac{1}{3}[/tex]

We now know the slope, and also a point for this new line, so we use the point-slope form of a line:

[tex]y-y_0=m_\perp\,(x-x_0)\\y-6=\frac{1}{3} (x-(-3))\\y-6=\frac{1}{3} x+\frac{3}{3} \\y-6=\frac{1}{3} x+1\\y=\frac{1}{3} x+7[/tex]


Related Questions

A cake mix calls for these ingredients. 2 cups of sugar 7 cups of flour 3 cups of milk 1 cup of oil Write the ratios of sugar to flour and milk to oil. Which correctly compares the ratios?

Answers

Answer:

Ratio of sugar and flour

2:7

Ratio of milk and oil

3:1

Step-by-step explanation:

Here in this question, we shall be writing ratios based on the given number of cups in the question.

We start with ratio of sugar to flour.

We have;2 cups of sugar and 7 cups of flour. Thus we have the ratio of sugar to flour as 2:7

Also we want the ratio of milk and oil

we have 3 cups of milk and 1 cup of oil

So the ratio of milk and oil is 3:1

Answer: TO be short for it its B! :D

A cake mix calls for these ingredients.

2 cups of sugar

7 cups of flour

3 cups of milk

1 cup of oil

Write the ratios of sugar to flour and milk to oil. Which correctly compares the ratios?

3/7 > 2/1

2/7<3/1

7/1<2/3

3/2>1/7

2

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2/7<3/1

with 2 cups of sugar to 7 cups of flour that is a small ratio/ fraction while as

3 cups of milk to 1 cup of oil is a larger ratio/fraction.

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Answer:  The correct option is (B).

The ratio of  sugar to flour is  and the ratio of milk to oil is

Step-by-step explanation:  Given that a cake mix calls for the following ingredients:

2 cups of sugar , 7 cups of flour , 3 cups of milk  and 1 cup of oil.

We are given to write the ratios of sugar to flour and milk to oil and select the correct comparison of the ratios.

The ratio of sugar to flour is given by

and the ratio of milk to oil is given by

Since

so have

Thus, the ratio of  sugar to flour is  and the ratio of milk to oil is  The correct comparison is

Option (B) is CORRECT.

Step-by-step explanation:

4. The difference between twice a number and
half the number is 30. What is the number?
Help me please

Answers

Answer:

20

Step-by-step explanation:

let the number be n then twice the number is 2n and half the number is [tex]\frac{1}{2}[/tex] n

Then the difference is

2n - [tex]\frac{1}{2}[/tex] n = 30 ( multiply through by 2 to clear the fraction )

4n - n = 60, that is

3n = 60 ( divide both sides by 3 )

n = 20

The television show Lett3rs has been successful for many years. That show recently had a share of 24, meaning that among the TV sets in use, 24% were tuned to Lett3rs. Assume that an advertiser wants to verify that 24% share value by conducting its own survey, and a pilot survey begins with 11 households have TV sets in use at the time of a Lett3rs broadcast.
Find the probability that none of the households are tuned to Lett3rs. P(none) =
Find the probability that at least one household is tuned to Lett3rs. P(at least one) =
Find the probability that at most one household is tuned to Lett3rs. P(at most one) =
If at most one household is tuned to Lett3rs, does it appear that the 24% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Lett3rs unusual?)

Answers

Answer:

(a) P(none) = 0.0488

(b) P(at least one) = 0.9512

(c) P(at most one) = 0.2186

(d) No, it doesn't appear that the 24% share value is wrong.

Step-by-step explanation:

We are given that among the TV sets in use, 24% were tuned to Lett3rs.

A pilot survey begins with 11 households have TV sets in use at the time of a Lett3rs broadcast.

Let X = Number of households that are tuned to Lett3rs

The above situation can be represented through binomial distribution;

[tex]P(X = r)=\binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......[/tex]

where, n = number of samples (trials) taken = 11 households

           r = number of success

           p = probability of success which in our question is % of  

                 households that were tuned to Lett3rs, i.e; 24%

So, X ~ Binom{n = 11, p = 0.24}

(a) The probability that none of the households are tuned to Lett3rs is given by = P(X = 0)

     P(X = 0) =  [tex]\binom{11}{0}\times 0.24^{0} \times (1-0.24)^{11-0}[/tex]

                   =  [tex]1\times 1 \times 0.76^{11}[/tex]

                   =  0.0488

(b) The probability that at least one households are tuned to Lett3rs is given by = P(X [tex]\geq[/tex] 1)

     P(X [tex]\geq[/tex] 1) = 1 - P(X = 0)

                   =  1 - 0.0488

                   =  0.9512

(b) The probability that at most one households are tuned to Lett3rs is given by = P(X [tex]\leq[/tex] 1)

     P(X [tex]\leq[/tex] 1) =  P(X = 0) + P(X = 1)

                   =  [tex]\binom{11}{0}\times 0.24^{0} \times (1-0.24)^{11-0}+\binom{11}{1}\times 0.24^{1} \times (1-0.24)^{11-1}[/tex]

                   =  [tex]1\times 1\times 0.76^{11}+11\times 0.24^{1} \times 0.76^{10}[/tex]

                   =  0.2186

No, it doesn't appear that the 24% share value is wrong because the probability that at most one household is tuned to Lett3rs is somewhere close to 24% and this probability is also not unusual as it is way more than the criteria of more than 5%.

Usando a fatoração com fator comum em evidência, fatore o seguinte polinômio: x3 + x2 + x

Answers

Answer:

x(x^2 + x + 1)

Step-by-step explanation:

x^3 + x^2 + x = x(x^2 + x + 1)

Please help Asap, will give brainiest only if answer correctly with a good explanation

Answers

Answer:

D, or the last option.

Step-by-step explanation:

See how the rotation does not say whether it is Clockwise or Counterclockwise?

Now, what that means, is that it will, default, be CCW. I don't know why, but math teachers are like that.

Now, 80* and 10* add up to 90* (because they are both unmarked and going to the same direction).

So, 90* rotation CCW. Simple! Thus, the last option should be correct.

Hope this helps!

P.S. Stay Safe!

Can someone help me with this problem?

Answers

━━━━━━━☆☆━━━━━━━

▹ Answer

Slope = 1

▹ Step-by-Step Explanation

y = mx + b

'm' represents the slope. since there is no number before the x, the coefficient will always be 1. therefore, the slope is 1.

Hope this helps!

CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Find HY if YL=9. nobody has shown me how to do this the last two weeks

Answers

Step-by-step explanation:

(a) Your computer may be programmed to allocate borderline cases to the

next group down, or the next group up; and it may or may not manage

to follow this rule consistently, depending on its handling of the numbers

involved. Following a rule which says 'move borderline cases to the next

group up', these are the five classifications.

(i) 1.0-1.2 1.2-1.4 1.4-1.6 1.6-1.8 1.8-2.0 2.0-2.2 2.2-2.4

6 6 4 8 4 3 4

2.4-2.6 2.6-2.8 2.8-3.0 3.0-3.2 3.2-3.4 3.4-3.6 3.6-3.8

6 3 2 2 0 1 1

(ii) 1.0-1.3 1.3-1.6 1.6-1.9 1.9-2.2 2.2-2.5

10 6 10 5 6

2.5-2.8 2.8-3.1 3.1-3.4 3.4-3.7

7 3 1 2

(iii) 0.8-1.1 1.1-1.4 1.4-1.7 1.7-2.0 2.0-2.3

2 10 6 10 7

2.3-2.6 2.6-2.9 2.9-3.2 3.2-3.5 3.5-3.8

6 4 3 1 1

(iv) 0.85-1.15 1.15-1.45 1.45-1.75 1.75-2.05 2.05-2.35

4 9 8 9 5

2.35-2.65 2.65-2.95 2.95-3.25 3.25-3.55 3.55-3.85

7 3 3 1 1

(V) 0.9-1.2 1.2-1.5 1.5-1.8 1.8-2.1 2.1-2.4

6 7 11 7 4

2.4-2.7 2.7-3.0 3.0-3.3 3.3-3.6 3.6-3.9

7 4 2 1 1

(b) Computer graphics: the diagrams are shown in Figures 1.9 to 1.11

George walks 1 mile to school. He leaves home at the same time each day, walks at a steady speed of 3 miles per hour, and arrives just as school begins. Today he was distracted by the pleasant weather and walked the first 1/2 mile at a speed of only 2 miles per hour. At how many miles per hour must George run the last 1/2 mile in order to arrive just as school begins today?

Answers

Answer:

George must run the last half mile at a speed of 6 miles per hour in order to arrive at school just as school begins today

Step-by-step explanation:

Here, we are interested in calculating the number of hours George must walk to arrive at school the normal time he arrives given that his speed is different from what it used to be.

Let’s first start at looking at how many hours he take per day on a normal day, all things being equal.

Mathematically;

time = distance/speed

He walks 1 mile at 3 miles per hour.

Thus, the total amount of time he spend each normal day would be;

time = 1/3 hour or 20 minutes

Now, let’s look at his split journey today. What we know is that by adding the times taken for each side of the journey, he would arrive at the school the normal time he arrives given that he left home at the time he used to.

Let the unknown speed be x miles/hour

Mathematically;

We shall be using the formula for time by dividing the distance by the speed

1/3 = 1/2/(2) + 1/2/x

1/3 = 1/4 + 1/2x

1/2x = 1/3 - 1/4

1/2x = (4-3)/12

1/2x = 1/12

2x = 12

x = 12/2

x = 6 miles per hour

how to solve for x?Knowledge and Understanding

Answers

Answer:

x = 25°

Step-by-step explanation:

The figure above is a quadrilateral

Angles in a quadrilateral add up to 360°

To find x add up all the angles and equate them to 360°

That's

6x + 4x + 3x + x + 10 = 360

14x = 350

Divide both sides by 14

x = 25°

Hope this helps you

The roots of \[x^2 + 5x + 3 = 0\]are $p$ and $q,$ and the roots of \[x^2 + bx + c = 0\]are $p^2$ and $q^2.$ Find $b + c.$[tex]The roots of\[x^2 + 5x + 3 = 0\]are $p$ and $q,$ and the roots of\[x^2 + bx + c = 0\]are $p^2$ and $q^2.$ Find $b + c.$[/tex]

Answers

By the factor theorem, we have

[tex]x^2+5x+3=(x-p)(x-q)\implies\begin{cases}3=pq\\-5=p+q\end{cases}[/tex]

[tex]x^2+bx+c=(x-p^2)(x-q^2)\implies\begin{cases}c=p^2q^2\\-b=p^2+q^2\end{cases}[/tex]

Then

[tex]c=p^2q^2=(pq)^2=3^2=9[/tex]

and

[tex]p+q=-5\implies(p+q)^2=p^2+2pq+q^2=25\implies b=-(p^2+q^2)=-19[/tex]

So we have b + c = -19 + 9 = -10.

The given roots of the equation x² + 5x + 3 = 0 as p and q, and x² + bx + c = 0 as p² and q², gives us the value of b + c = -10.

What are the sum and product of the roots of a quadratic equation?

If the quadratic equation ax² + bx + c = 0, has roots as α and β, then:

Sum of the roots, α + β = -b/aProduct of the roots, αβ = c/a

How to solve the given question?

In the question, we are informed that the roots of the expression x² + 5x + 3 = 0 are p and q, and the roots of the expression x² + bx + c = 0 are p² and q².

We are asked to find the value of b + c.

Since the roots of the equation x² + 5x + 3 = 0 are given as p and q.

So, we can say that:

Sum of the roots, p + q = -5Product of the roots, pq = 3

Now, we are informed that the roots of the equation x² + bx + c = 0 are p² and q². So, we can say that:

Sum of the roots, p² + q² = -b, or, (p + q)² - 2pq = -b, or, (-5)² - 2(3) = -b, or, 25 - 6 = -b, or, 19 = -b, or, b = -19.Product of the roots, p²q² = c, or, (pq)² = c, or, 3² = c, or, c = 9.

∴ b + c = -19 + 9 = -10.

∴ The given roots of the equation x² + 5x + 3 = 0 as p and q, and x² + bx + c = 0 as p² and q², gives us the value of b + c = -10.

Learn more about the sum and product of the roots of a quadratic equation at

https://brainly.com/question/10666510

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angle x and y are complementary angles . angle y measure 37 plzz help asap

Answers

Answer:

53 degrees

Step-by-step explanation:

Complementary angles add to 90 degrees

a+b = 90

a=37

37+b = 90

Subtract 37 from each side

37+b-37 = 90-37

b =53

Answer: 53 degrees

Step-by-step explanation: We can find the measure of <b by taking 90 minus the measure of <a which is 90 - 37 or 53 degrees.

simplify: m–(a–k–b) HElp!

Answers

Answer: m-a+k+b

Step-by-step explanation:

m-(a-k-b)= m+-1*(a-k-b). Then, simply use distributive property to simplify the equation into m-a+k+b

Hope it helps <3

Valerie had a jug that contained 128 fl oz of salsa to put into bowls at a restaurant. She filled each bowl with 6 fl oz of salsa until there was not enough salsa left in the jug to completely fill another bowl. How many fluid ounces of salsa were left in the jug?

Answers

Answer: 2 fl oz

Step-by-step explanation:

Division with remainders

128/6=21.33333..

[tex]21\cdot 6=126[/tex]

128-126=2

2 fl oz was left in the jug

StartLayout enlarged left-brace 1st row 4 x minus 5 y = 5 2nd row negative 0.08 x + 0.10 y = 0.10 EndLayout

Answers

Answer:

[tex]x = 1.25[/tex]

[tex]y = 0[/tex]

Step-by-step explanation:

Given

[tex]4x - 5y = 5[/tex]

[tex]0.08x + 0.10y = 0.10[/tex]

Required

Determine the solution

Make x the subject of formula in: [tex]4x - 5y = 5[/tex]

[tex]4x = 5 + 5y[/tex]

Divide both sides by 4

[tex]\frac{4x}{4} = \frac{5 + 5y}{4}[/tex]

[tex]x = \frac{5 + 5y}{4}[/tex]

Substitute [tex]x = \frac{5 + 5y}{4}[/tex] in [tex]0.08x + 0.10y = 0.10[/tex]

[tex]0.08(\frac{5 + 5y}{4}) + 0.10y = 0.10[/tex]

Solve the fraction

[tex]0.02(5 + 5y) + 0.10y = 0.10[/tex]

Open the bracket

[tex]0.1 + 0.1y + 0.10y = 0.10[/tex]

[tex]0.1 + 0.2y = 0.10[/tex]

Subtract 0.1 from both sides

[tex]0.1-0.1 + 0.2y = 0.10 - 0.1[/tex]

[tex]0.2y = 0[/tex]

Divide both sides by 0.2

[tex]y =0[/tex]

Substitute 0 for y in [tex]x = \frac{5 + 5y}{4}[/tex]

[tex]x = \frac{5 + 5*0}{4}[/tex]

[tex]x = \frac{5 + 0}{4}[/tex]

[tex]x = \frac{5 }{4}[/tex]

[tex]x = 1.25[/tex]

FI = 20 IH = 19. Calculate the length of GI

Answers

Answer:

7.55

Step-by-step explanation:

3/x = x/19

x² = 57

x = 7.54983....

What is 5/7 subtracted by 2/5

Answers

Answer:

11/35

Step-by-step explanation:

what is the value of X when f(x)=g(x) ?

Answers

Answer:

x=3

Step-by-step explanation:

We want to find the value of x where the two graphs intersect

The graphs intersect at ( 3,8)

The value of x is 3

X will be 3 I know for a fact

When using a calorimeter, the initial temperature of a metal is 70.4C. The initial temperature of the water is 23.6C. At the end of the experiment, the final equilibrium temperature of the water is 29.8C. What is the final temperature of the metal? C What is the temperature change of the water? C What is the temperature change of the metal? C

Answers

Answer:

29.8C6.2C-40.6C

Step-by-step explanation:

a) "Equilibrium" means the final temperatures of everything in the calorimeter are the same. The final temperature of the metal is the same as that of the water: 29.8C.

__

b) The temperature change of the water is ...

  final temp - initial temp = 29.8C -23.6C = 6.2C

__

c) The temperature change of the metal is ...

  final temp - initial temp = 29.8C -70.4C = -40.6C

Answer:

29.8C

6.2C

-40.6C

Step-by-step explanation:

Please answer this question now only answer if you know the answer

Answers

Answer:

v = 10.997

Step-by-step explanation:

For this, simply use the law of cosines.

v^2 = (16)^2 + (6)^2 - 2(16)(6)cos(27)

v^2 = 256 + 36 - 171.073

v^2 = 120.927

v = 10.997

Cheers.

Answer:

[tex]\boxed{11}[/tex] units

Step-by-step explanation:

To solve the length of UW, you can use the Law of Cosines for a SAS case:

[tex]\boxed{v^2=\sqrt{u^2+w^2-2(uw)cos(V)} }[/tex]

Substitute the values and solve with a calculator:

[tex]\boxed{\sqrt{16^2+6^2-2(16*6)cos(27)} = 10.99666983 \approxeq 11}[/tex]

The length of UW is 11 units.

HIIIIII 2 QUESTIONS IN THE 2 PICS HELP PLS

Answers

Answer:

(1)C- Trapezoid

(2)D-20 square feet

Step-by-step explanation:

Question 1

A cross-section of a rectangular pyramid cut perpendicular to the base but not passing through the top will have two parallel sides where one of the sides will be longer. Therefore, the shape which describes the cross-section will be a trapezoid.

Question 2

The base of the Triangle = 5 feet

Height of the Triangle = 8 feet

[tex]\text{Area of a triangle}=\dfrac12 \times $Base \times Height\\=\dfrac12 \times 5 \times 8\\=20 ft^2[/tex]

a football is fired upward with an initial speed of 800 feet per second. It is given that h=-12t^2+360t (h is the height of the football at any given time).what will you set h equal to in the equation to to find how many seconds it takes the football to hit the ground?

Answers

Answer:

30 s

Step-by-step explanation:

When the ball hits the ground h=0. To find the time t when this happens we must solve the equation h=0.

●h= 0

● -12t^2+360t =0

● t(-12t +360) = 0

● t = 0 or -12t +360 =0

● t=0 or -12t = -360

● t=0 or 12t =360

● t=0 or t=360/12

● t=0 or t= 30

The equation has two solutions.

The ball was fired with an initial speed of 800 feet per second so it cannot hit the ground at t=0.

So the ball hits the ground after 30 s.

c) Bhurashi can do 1/3 part of a work in 6 days.
(1) In how many days would she complete the whole work?
(ii) How much work does she do in 1 day?
m) How much work is left to do if she worked only for 9 days?​

Answers

Answer:

i. 18 daysii.[tex] \frac{1}{18} [/tex] part of workiii. [tex] \frac{1}{2} [/tex] part of work

Step-by-step explanation:

i.

[tex] \frac{1}{3} [/tex] part of work can be done in 6 days.

Days taken to complete the whole work:

= 6 * 3

= 18 days

ii. Whole work will be done in 18 days.

So, 1 day work = [tex] \frac{1}{18} [/tex]

iii. Work done in 9 days :

[tex] \frac{1}{18} \times 9 [/tex]

[tex] = \frac{1}{2} [/tex]

So, remaining work :

[tex]1 - \frac{1}{2} [/tex]

[tex] = \frac{1 \times 2 - 1}{2} [/tex]

[tex] = \frac{2 - 1}{2} [/tex]

[tex] = \frac{1}{2} [/tex] part of work

Hope this helps...

Good luck on your assignment..

2. A vertical stick 10 cm long casts a shadow 8 cm long. At the same time a tower casts a
shadow 30 m long. Determine the height of the tower.

Answers

Answer:

The height of the tower is:

24 meters

Step-by-step explanation:

1 meter = 100 centimeters

10 centimeters = 10/100 = 0.1 meters

8 centimeters = 8/100 = 0.08 meters

On a three rule:

0.1 meters is to 0.08 meters

30 meters is to A meters

A = 30*0.08/0.1

A = 24 meters

Related task:

https://brainly.lat/tarea/14821170

At a fun park, the cost of a rollercoaster ride and a ferris wheel ride is $10. The cost of a Gravitron ride and a Ferris wheel ride is $12. The cost of a rollercoaster ride and a Gravitron ride is $14. What is the cost of each ride?

Answers

Answer:

r = cost of rollercoaster = 6

f = cost of ferris wheel=4

g = cost of graviton=8

Step-by-step explanation:

r = cost of rollercoaster

f = cost of ferris wheel

g = cost of graviton

r+f = 10

g+f = 12

r+g = 14

Take the third equation and subtract the first equation

r+g =14

-r-f = -10

-------------------

g-f = 4

Take this and add it to the second equation

g-f = 4

g+f = 12

-------------------

2g = 16

Divide by 2

g = 8

Now find f

g+f = 12

8+f = 12

f = 12-8

f=4

Now find r

r+g =14

r+8 =14

r = 14-8

r = 6

What is the solution to the system of equations?
y= 2/3x+3
x = –2

Answers

Answer:

[tex]x = -2[/tex] and [tex]y = \frac{5}{3}[/tex]

Step-by-step explanation:

Given

[tex]y = \frac{2}{3}x + 3[/tex]

[tex]x = -2[/tex]

Required

Determine the solution to the equations

From the second equation, we have the value of x already;

The next step is to substitute -2 for x in the first equation

[tex]y = \frac{2}{3}x + 3[/tex] becomes

[tex]y = \frac{2}{3}(-2) + 3[/tex]

[tex]y = \frac{-4}{3} + 3[/tex]

[tex]y = -\frac{4}{3} + 3[/tex]

Take LCM

[tex]y = \frac{-4 + 9}{3}[/tex]

[tex]y = \frac{5}{3}[/tex]

Hence,

[tex]x = -2[/tex] and [tex]y = \frac{5}{3}[/tex]

Given each set of vertices, determine whether PQRS is a rhombus, a rectangle, or a square. List all that apply. Explain your reasoning, P(-2, -3). Q(2, - 6). R(6. - 3). S(2, 1)

Answers

Answer:

Rectangle

Step-by-step explanation:

Given the coordinates P(-2, -3). Q(2, - 6). R(6. - 3). S(2, 1), to determine the type of shape the quadrilateral is, we need to find the measure of the sides. To get the measure of each sides, we will take the distance between the adjacent coordinates using the formula to formula for calculating the distance between two points as shown;

D = √(x₂-x₁)²-(y₂-y₁)²

For the side PQ with the coordinate P(-2, -3). Q(2, - 6)

PQ = √(2-(-2))²-(-6-(-3))²

PQ = √(2+2)²-(-6+3)²

PQ = √4²-(-3)²

PQ = √16-9

PQ = √7

For the side QR with the coordinate Q(2, - 6) and R(6, -3)

QR = √(6-2))²-(-3-(-6))²

QR = √(4)²-(3)²

QR = √16-9

QR = √7

For the side RS with the coordinate R(6. - 3) and S(2, 1)

RS = √(2-6)²-(1-(-3))²

RS = √(-4)²-(1+3)²

RS = √16-(4)²

RS = √16-16

RS = 0

For the side PS with the coordinate P(-2, -3) and S(2, 1)

PS = √(2-(-2))²-(1-(-3))²

PS = √(4)²-(1+3)²

PS = √16-(4)²

PS = √16-16

PS = 0

For the quadrilateral to be a rectangle, then two of its sides must be equal and parallel to each other. A rectangle is a plane shape that has two of its adjacent sides equal and parallel to each other. Since two of he sides are equal i.e RS = PS and PQ = QR then the quadrilateral PQRS is a rectangle. Both rhombus and square has all of its sides equal thereby making them wrong.

Please answer this in two minutes

Answers

Answer:

366.6 mm²

Step-by-step explanation:

Step 1: find XY using the Law of sines.

Thus,

[tex] \frac{XY}{sin(W)} = \frac{WY}{sin(X)} [/tex]

m < W = 180 - (70+43) (sum of angles in a triangle)

W = 180 - 113 = 67°

WY = 24 mm

X = 43°

XY = ?

[tex] \frac{XY}{sin(67)} = \frac{24}{sin(43)} [/tex]

Cross multiply:

[tex] XY*sin(43) = 24*sin(67) [/tex]

[tex] XY*0.68 = 24*0.92 [/tex]

Divide both sides by 0.68 to solve for XY

[tex] \frac{XY*0.68}{0.68} = \frac{24*0.92}{0.68} [/tex]

[tex] XY = 32.47 [/tex]

XY ≈ 32.5 mm

Step 2: find the area using the formula, ½*XY*WY*sin(Y).

Area = ½*32.5*24*sin(70)

Area = ½*32.5*24*0.94

= 32.5*12*0.94

Area = 366.6 mm² (nearest tenth)

hey loves!!! PLz help me

Answers

Answer:

Hey there!

We must use what we are given, so even though it looks like there might be four isosceles triangles, we are only given CA=CE, so that only allows us to conclude mathematically that there is only 1 isosceles triangle.

Hope this helps :)

The function d(s) = 0.0056s squared + 0.14s models the stopping distance
of a car, d(s), in metres, and the speed, s, in kilometres per hour. What
is the speed when the stopping distance is 7 m? Use a graph to solve.​

Answers

Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be [tex]d(s) = 0.0056\cdot s^{2} + 0.14\cdot s[/tex], where [tex]d[/tex] is the stopping distance measured in metres and [tex]s[/tex] is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of [tex]d(s)[/tex].

2) Add the function [tex]d = 7\,m[/tex].

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Beth says that the graph of g(x)=x-5+1 is a
Translation of 5 units to the left and 1 unit up of
F(x)=x
She continues to explain that the point (0,0) on the square root function would be translated to the point (-5,1) on the graph of g(x) is Beths description of the transformation correct? Explain

Answers

Answer:

(-15,3)

Step-by-step explanation:

Answer:

No, Beth is not correct. The function g(x) has an h value of 5 and a k value of 1. This would be a horizontal translation of the square root function of 5 units to the right, rather than the left. Beth was correct about the vertical translation of the square root function of 1 unit up. The point (0, 0) from the square root function would be translated to the point (5, 1) on the graph of g(x).

Step-by-step explanation:

This came right from Edg

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