The total surface area of the tires making contact with the ground at any one time for the truck with 18 wheels, tire radius of 21 in, tire width of 12 in, and 20% contact area is approximately 5700.24 square inches.
The surface area of one tire making contact with the ground can be calculated as follows:
The diameter of the tire is 2 * radius = 2 * 21 in = 42 in
The length of the portion of the tire making contact with the ground is 20% of the circumference of the tire = 0.2 * π * 42 in ≈ 26.39 in
The width of the tire making contact with the ground is given as 12 in
Therefore, the surface area of one tire making contact with the ground is approximately 26.39 in * 12 in = 316.68 square inches
Since the truck has 18 wheels, the total surface area of all the tires making contact with the ground at any one time is 18 * 316.68 square inches = 5700.24 square inches.
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Grayson bought snacks for his team's practice. He bought a bag of popcorn for $3.50 and a 5-pack of juice bottles. The total cost before tax was $11.05. Write and solve an equation which can be used to determine
Answer:
7.55
Step-by-step explanation:
3.50 + x = 11.05, x = 11.05 - 3.50, x = 7.55
Answer:
Step-by-step explanation:
Let [tex]x[/tex] be the cost of a juice bottle. Then
[tex]3.50+5x=11.05[/tex]
Solve this:
[tex]5x=7.55[/tex] (subtracted 3.50 from both sides)
[tex]x=7.55/5=1.51[/tex] (divided both sides by 5)
So juice bottles cost $1.51
June spent a quarter hour practicing her piano. Then she spent a half
hour cleaning her room, and an eighth hour putting away her clean
laundry. What fraction of an hour did June spend doing these chores? (this is for a kid i’m forced to tutor.)
Answer: 0.875 h or for a fraction 8 3/4
Step-by-step explanation:
June spent 15 minutes practicing her piano, 30 minutes cleaning her room and 7.5 minutes putting away her dirty laundry so a total of 52.5 minutes
Answer:
8 3/4
Step-by-step explanation: IK IM SORRY im sooo confusing!! And it makes me frustrated too...
Ian placed 263 stamps on 9 pages of his collection book. He wanted to place the same number
of stamps on each page with as few as possible left over. How many stamps are on each page?
How many were left to put in an envelope?
Enter the correct value to complete each sentence.
Blank stamps were placed on each page.
Blank stamps were put in an envelope.
Answer: To find the number of stamps on each page, we can divide the total number of stamps by the number of pages:
263 stamps ÷ 9 pages = 29.22 stamps per page (rounded to two decimal places)
Since we want to place the same number of stamps on each page with as few left over as possible, we can round down to the nearest whole number:
29 stamps per page
To find out how many stamps were left to put in an envelope, we can multiply the number of pages by the number of stamps per page, and then subtract from the total number of stamps:
263 stamps - (29 stamps per page x 9 pages) = 8 stamps left over to put in an envelope
Therefore, the completed sentences are:
29 stamps were placed on each page.
8 stamps were put in an envelope.
Step-by-step explanation:
Exercise 2.4.28 LetAbe ann×nmatrix and letIbe then×nidentity matrix. a. IfA2=0, verify that(I−A)−1=I+A. b. IfA3=0, verify that(I−A)−1=I+A+A2.
a. For A2 = 0, it is proved that (I - A)-1 = I + A.
b. For A3 = 0, (I - A)-1 = I + A + A2.
a. If A2 = 0, then (I - A)-1 = I + A
Proof:
(I - A)-1 = (I + A)-1
(I + A)-1 = (I + A)(I - A)-1
(I + A)(I - A)-1 = I + A
Therefore, (I - A)-1 = I + A
b. If A3 = 0 then (I - A)-1 = I + A + A2
Proof:
(I - A)-1 = (I + A + A2)-1
(I + A + A2)-1 = (I + A + A2)(I - A)-1
(I + A + A2)(I - A)-1 = I + A + A2
Therefore, (I - A)-1 = I + A + A2
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Which equation would calculate the amount of wrapping paper, in square centimeters, needed to completely cover the cylinder shown?
a cylinder with the diameter labeled 2.8 centimeters and the height labeled 3.7 centimeters
A. SA = 2π(1.4)2 + 2.8π(3.7)
B. SA = 2π(1.4)2 + 1.4π(3.7)
C. SA = 2π(2.8)2 + 2.8π(3.7)
D. SA = 2π(2.8)2 + 1.4π(3.7)
The equation to calculate the amount of wrapping paper is 2π(1.4)² + 2.8π(3.7) cm²
The surface area of a cylinder:
Surface area is the total area that the surface of an object occupies. It is a measure of how much area is covered by the exterior of an object. The formula for the surface area of a cylinder is:
SA = 2πr² + 2πrhWhere r = radius of the base and h = height of the cylinder.
Here we have
Diameter of the cylinder = 2.8 cm
Radius of the cylinder = 2.8/2 = 1.4 cm
Height of the cylinder = 3.7 cm
Using the formula,
The surface area of a cylinder SA= 2πr² + 2πrh
The surface area of the cylinder
= 2π(1.4)² + 2π(1.4)(3.7)
= 2π(1.4)² + 2.8π(3.7)
Here, the total surface area of the cylinder will equal the amount of wrapping paper needed to completely cover the cylinder
Therefore,
The equation to calculate the amount of wrapping paper is 2π(1.4)² + 2.8π(3.7) cm²
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hi i think its A. SA = 2π(1.4)2 + 2.8π(3.7) hope this helped have a nice day! :)
4) If ABCD is a parallelogram, Find the value of Angle B. ∟AB=(6x-15)°
∟CD=(4x-11)°
5.) PQRS is a parallelogram, Find the value of angle R ∟QR=(8x - 12)° ∟PS=(3x + 5)º 7) Given the following quadrilateral is a rhombus, find the measure of x ∟AB=23°
∟BC=y°
∟CD=x°
x = 23°
4) To find the value of Angle B, we can use the alternate interior angles theorem, which states that if two parallel lines are cut by a transversal, the alternate interior angles are equal. In this case, we can say that ∟AB=∟CD, since ABCD is a parallelogram. Therefore, we can set 6x-15 = 4x-11 and solve for x to get x = 4. Plugging this back in, we can find that ∟AB = 6(4)-15 = 15°.
5) To find the value of Angle R, we can use the same method as above. We can set ∟QR=∟PS, since PQRS is a parallelogram. Therefore, we can set 8x-12 = 3x+5 and solve for x to get x = 7. Plugging this back in, we can find that ∟QR = 8(7)-12 = 56°.
7) To find the measure of x, we can use the fact that the quadrilateral is a rhombus. A rhombus is a quadrilateral with all four sides equal in length, so we can say that ∟AB = ∟CD. Therefore, we can set 23=x and solve for x to get x = 23°.
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given point A,P,Q construct D_a,k(R) if D_a,k(Q) = P
Points A and Q are connected by a line. To get the length of AR, measure the distance between A and Q and multiply that value by k. To find point R, mark off the length of AR along a ray that extends from point A in the direction of Q.
What serve ray lines?In mathematics, a ray is a segment of a line with a known starting point but no known endpoint. It can go on forever in that one direction. A beam cannot be measured since it lacks a terminal. fun facts A ray is similar to the sun's rays.
What is an example of a ray line?In geometry, a ray is a line that, starting from a single terminal, extends indefinitely in one direction (or point of origin). A ray is represented by a beam of sunlight travelling across space; while the sun is the ray's goal, it continues to travel forever.
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Complete question -
PLEASE HELP ASAP this math is kinda hard for me
The following are the correct convertion for the units of mass:
8000 mg converted to gram is 8 g
80 g converted to kilogram is 0.08 kg
0.8 kg converted to g is 800 g.
Units of mass measurementsGram (g) is the base unit of mass in the metric system. The milligrams (mg) and kilograms (kg) are derived units.
1 gram = 1000 milligrams (mg)
1000 grams = 1 kilogram (kg)
8000 mg = (8000/1000) g
8000 mg = 8 g
80 g = (80/1000) kg
80 g = 0.08 kg
0.8 kg = (0.8 × 1000) g
0.8 kg = 800 g.
In conclusion, 8000 mg converted to gram is 8 g, 80 g converted to kilogram is 0.08 kg, and 0.8 kg converted to g is 800 g.
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How does lowering interest rates by a government’s central bank affect the economy?
Lowering interest rate by a government's central bank can have a significant impact on the economy, as it affects the cost of borrowing money for businesses and individuals, as well as the return on savings and investments.
Lowering interest rate reduces the cost of borrowing money, making it easier for businesses and individuals to access credit. It can also encourage consumers to spend more money, as they may have more disposable income due to lower borrowing costs or higher investment returns.
It can also lead to increased inflation, as businesses and individuals have more money to spend and demand for goods and services increases and reduced returns on savings and investments, which can discourage people from saving and lead to more spending
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In the triangle ABC.
angle ABC is twice the size of angle BAC.
angle ACD is 31° more than angle ABC.
Work out the size of angle ACB.
The size of angle ACB is approximately 50.66°.
What is the angle sum property?The angle sum property of a triangle states that the sum of the interior angles of a triangle is 180 degrees.
We are given that;
Angle ABC= Angle ACD + 31°
Now,
Since angle ABC is twice angle BAC, we can write:
angle BAC = x
angle ABC = 2x
angle ACB = 180° - (angle BAC + angle ABC)
Substituting these values into the equation for angle ACD, we get:
angle ACD = angle ABC + 31° = 2x + 31°
Since angles ACB and ACD form a straight line, we can write:
angle ACB + angle ACD = 180°
Substituting the values we know, we get:
(angle BAC + angle ABC) + (angle ABC + 31°) = 180°
3x + 31° = 180°
3x = 149°
x = 49.67°
Therefore, the angle of triangles answer will be 50.66°.
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Complete the identity
The identity cos²θ/2 is (1 + cosθ)/2
What is Trigonometry?Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.
We can use the half-angle identity for the cosine function to solve this problem:
cos²θ/2 = (1 + cosθ)/2
Therefore, to find cos²θ/2 , we need to know the value of cosθ.
If the value of cosθ is known, we can substitute it into the half-angle identity to find cos²θ/2
Hence, the identity cos²θ/2 is (1 + cosθ)/2
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PLEASE HELP ME OUT THIS IS SO DIFFICULT
A cube of length 8cm is enlarged with a scale factor of 1 1/2
find the length of the enlargement
The length of the enlargement of the cube, given the scale factor and the length, would be 12 cm.
How to find the length of the enlargement ?When a shape is enlarged by a scale factor of k, all its dimensions are multiplied by k. In this case, the scale factor is 1 1/2, which can be written as 3/2 in fraction form. Therefore, the length of the enlargement is:
Length of enlargement = Scale factor x Original length
Length of enlargement = (3/2) x 8 cm
Length of enlargement = 12 cm
So, the length of the enlargement is 12 cm.
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ctIONS through a given point with a given slope ope -(2)/(3) passing through the point (3,4)
The equation of the line with slope -(2)/(3) passing through the point (3, 4) is y = -(2)/(3)x + 6. To find the equation of a line that passes through a given point with a given slope, we can use the point-slope formula. The point-slope formula is: y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point that the line passes through. In this case, the slope is -(2)/(3) and the point is (3, 4).
Plugging these values into the point-slope formula, we get:
y - 4 = -(2)/(3)(x - 3)
We can then rearrange the equation to get it into slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept:
y - 4 = -(2)/(3)x + 2
y = -(2)/(3)x + 6
So, the equation of the line with slope -(2)/(3) passing through the point (3, 4) is y = -(2)/(3)x + 6.
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Complete the rules for g (z) so that the graph represents it.
g(x) = -10, -15 ≤ x < -10
g(x) = , -10 ≤ x < -8
g(x) = 8, 10 ≤ x < 15
The rule for the function g(x) when completed is g(x) = -10, -15 ≤ x < -10; g(x) = -8, -10 ≤ x < -8; g(x) = -6, -8 ≤ x < -1; g(x) = 2, -1 ≤ x < 1; g(x) = 4, 1 ≤ x < 10; g(x) = 8, 10 ≤ x < 15
Completing the rule for the function g(x)Given
The graph of the function g(x) such that the function g(x) is a piecewise function and each sub-function is represented by horizontal lines
To complete the function definition, we write out the y value and the domain of the functions based on the current domain
Following the above statements, we have the following function definition for g(x)
g(x) = -10, -15 ≤ x < -10
g(x) = -8, -10 ≤ x < -8
g(x) = -6, -8 ≤ x < -1
g(x) = 2, -1 ≤ x < 1
g(x) = 4, 1 ≤ x < 10
g(x) = 8, 10 ≤ x < 15
The above is the definition of the function g(x)
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What is the measurement of the longest line segment in a right rectangular prism that is 12.6 centimeters long, 3.2 centimeters wide, and 7 centimeters tall
The right rectangular prism's longest line segment measures around 14.79 cm in length.
The right rectangular prism's longest line segment can be found in this way?We are aware that the rectangular prism's body diagonal makes up the longest line segment inside a right rectangular prism. The longest distance is that between points A and D. AD is the longest line segment as a result. To determine a line segment's length, use a scale. Straight line segments can be measured with it.
The Pythagorean theorem can be used to determine how long the space diagonal is:
a = length = 12.6 cm
b = width = 3.2 cm
c = height = 7 cm
You may determine the space diagonal (d) by using:
d = sqrt(a² + b² + c²)
Substituting the values, we get:
d = sqrt(12.6² + 3.2² + 7²) cm
d = sqrt(159.76 + 10.24 + 49) cm
d = sqrt(219) cm
d ≈ 14.79 cm
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Question:
What is the measurement of the longest line segment in a right rectangular prism that is 12.6 centimeters long, 3.2 centimeters wide, and 7 centimeters tall, and that connects two vertices that are not on the same face of the prism?
Using the formula for finding the simple interest, I = Prt, find the Interest earned in a savings account by depositing $9,800 for 15 months at 5% simple interest
let's recall that a year has 12 months, thus 15 months is really 15/12 of a year.
[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$9800\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{15}{12}\dotfill &\frac{5}{4} \end{cases} \\\\\\ I = (9800)(0.05)(\frac{5}{4}) \implies I = 612.5[/tex]
On a washington road map, Abigail measured a distance of 3.2 in from Snohomish to Seattle. The scale of this map is 1 inch = 10 miles what is the actual distance between Snohomish to Seattle?
Using the unitary method we found that the actual distance between Snohomish to Seattle is 32 miles.
What is meant by the unitary method?
The unitary approach is a strategy for problem-solving that involves first determining the value of a single unit, and then multiplying that value to determine the required value. We typically utilise this technique for maths computations. This method allows us to calculate both the value of many units from the value of one unit and the value of many units from the value of one unit.
Given,
The measured distance from Snohomish to Seattle on a road map = 3.2 inches
The scale of the map is given as:
1 inch = 10 miles
The ratio between a distance on a map and its actual distance on the ground is known as the map's scale. The use of scale is necessary for generating an accurate map and makes it simple to establish the real size of any area on the map.
The actual distance can be found using the unitary method.
So it is given 1 inch on the map = 10 miles on the road
Then 3.2 inches on the map = 10 * 3.2 = 32 miles on the road
Therefore using the unitary method we found that the actual distance between Snohomish to Seattle is 32 miles.
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59. Standard Normal areas Find the proportion of observations in a standard Normal distribution that satisfies each of the following statements.
(a) z > -1.66
(b) -1.66
(a) The proportion of observations in a standard normal distribution that satisfies z > -1.66 is 0.0475, or approximately 4.75%.
(b) The proportion of observations in a standard normal distribution that satisfies -1.66 < z < 1.66 is 0.9050, or approximately 90.50%.
What is z-score?A Z-score is a metric that quantifies how closely a value relates to the mean of a set of values.
Standard deviations from the mean are used to measure Z-score. A Z-score of zero means the data point's score is the same as the mean score.
To find the proportion of observations in a standard normal distribution that satisfies each of the statements, we need to use a standard normal distribution table or calculator.
(a) z > -1.66
We need to find the area to the right of z = -1.66 on a standard normal distribution table or calculator. This is equivalent to finding the area to the left of z = 1.66 since the standard normal distribution is symmetrical.
Using a standard normal distribution table or calculator, we find that the area to the left of z = 1.66 is 0.9525. Therefore, the area to the right of z = -1.66 is:
1 - 0.9525 = 0.0475
So, the proportion of observations in a standard normal distribution that satisfies z > -1.66 is 0.0475, or approximately 4.75%.
(b) -1.66 < z < 1.66
We need to find the area between z = -1.66 and z = 1.66 on a standard normal distribution table or calculator.
Using a standard normal distribution table or calculator, we find that the area to the left of z = 1.66 is 0.9525 and the area to the left of z = -1.66 is 0.0475 (as calculated in part (a)). Therefore, the area between z = -1.66 and z = 1.66 is:
0.9525 - 0.0475 = 0.9050
Therefore, the proportion of observations in a standard normal distribution that satisfies -1.66 < z < 1.66 is 0.9050, or approximately 90.50%.
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Leveled Practice In 8-11, complete each statement.
8. A die has 12 sides shown as follows: 6 triangles,
3 circles, and 3 squares.
The probability rolling a triangle is
Q
2
out of 12, or
or
%.
(s
The probability of rolling a triangle is 50%
How to determine the probability of rolling a triangleFrom the question, we have the following parameters that can be used in our computation:
Sides = 12
triangles = 6
Circles = 3
Squares = 3
The die has a total of 6 + 3 + 3 = 12 sides.
Since there are 6 triangles on the die, the probability of rolling a triangle is:
P(triangle) = number of favorable outcomes / total number of outcomes
Substitute the known values in the above equation, so, we have the following representation
P(triangle) = 6 / 12
Evaluate
P(triangle) = 50%
Hence, the probability of rolling a triangle on the die is 1/2 or 0.5.
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Use the formula for simple interest, I = Pxrxt, to find the missing quantity. P = $4000; r = 8%; t = 3 years 01 = $1160 01 = $9600 01 = $960 01 = $96,000 Use the formula for simple interest, I = Pxrxt
To find the missing quantity, we will plug in the given values into the formula for simple interest and solve for the unknown variable. The formula for simple interest is I = Pxrxt, where I is the interest, P is the principal, r is the interest rate, and t is the time in years.
Given:
P = $4000
r = 8% = 0.08
t = 3 years
Plugging in the given values into the formula, we get:
I = $4000 x 0.08 x 3
Simplifying the equation, we get:
I = $960
Therefore, the missing quantity is the interest, I, which is equal to $960.
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HELPP! NEED NOW!!! ASAP!!
The volume of a rectangular prism is 208 cm³. If the area of one end is 16 cm², what is the length of the prism? (FOUND ANSWER)
The length of the rectangular prism is 13 centimetres.
How to find the side of a rectangular prism?The volume of a rectangular prism is 208 cm³. The area of one end is 16 cm². The length of the rectangular prism can be found as follows:
Therefore,
volume of a rectangular prism = lwh
where
l = lengthw = widthh = heightHence, let's find the length
volume of a rectangular prism = lwh
208 = 16 × l
16l = 208
divide both sides by 16
l = 208 / 16
l = 13 cm
Therefore,
length of the prism = 13 cm
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Comment résoudre une équation ?
Ex: 3x + 4= 2x + 9
Given:-
[tex] \tt \: 3x + 4 = 2x + 9[/tex][tex] \: [/tex]
Solution:-
[tex] \tt \: 3x + 4 = 2x + 9[/tex][tex] \: [/tex]
[tex] \tt \: 3x - 2x = 9 - 4[/tex][tex] \: [/tex]
[tex] \tt \: 1x = 5[/tex][tex] \: [/tex]
[tex] \tt \: x = \cancel\frac{5}{1} [/tex][tex] \: [/tex]
[tex] \underline{ \underline{ \color{black}{ \tt \: x = 5}}}[/tex][tex] \: [/tex]
hope it helps!:)
Bonjour !
Il faut isoler x.
3x + 4 = 2x + 9
3x - 2x = 9 - 4
x = 5
need help you all with this question:(
Answer:
True both each.
Step-by-step explanation:
Your teacher would probably like you to remember the Trig Identities or allow you to have a cheat sheet for the Quiz or Test.
[tex]\frac{sin(\alpha )}{sin^{2}(\alpha) +cos2\alpha } \\\\\frac{sin(\alpha )}{sin^{2}(\alpha) +[cosx^{2} (\alpha)-sinx^{2} (\alpha )]} \\\\\frac{sin(\alpha )}{sin^{2}(\alpha) +cosx^{2} (\alpha)-sinx^{2} (\alpha )}\\\\\frac{sin(\alpha )}{[sin^{2}(\alpha) +cosx^{2} (\alpha)]-sinx^{2} (\alpha )}[/tex]
[tex]\frac{sin(\alpha )}{1-sinx^{2} (\alpha )}\\\\\frac{sin(\alpha )}{cos^{2} (\alpha )}\\\\\frac{sin(\alpha )}{cos^{2} (\alpha )}\\\\\frac{sin(\alpha )}{cos(\alpha )*cos(\alpha )}\\\\\frac{sin(\alpha )}{cos(\alpha )}*\frac{1}{cos(\alpha )} \\\\tan(\alpha )*sec(\alpha )\\\\\frac{1}{cot(\alpha )}*sec(\alpha )\\\\\frac{sec(\alpha )}{cot(\alpha )}[/tex]
Solve the following application question.
You must clearly show your variable designation(s), equation(s), and algebraic solution to the equation(s) to receive full credit.
Shiro bought some meat for a barbeque. The beef costs $6.00 per pound and the chicken costs $4.50 per pound. He bought a total of 18 pounds of meat and spent $96. How much of each type of meat did Shiro purchase?
Shiro purchased 11 pounds of beef and 4 pounds of chicken.
How to solveShiro purchased a total of 18 pounds of meat, spending $96.
We can designate the beef as x pounds, and the chicken as y pounds. To find the solution, we set up two equations:
6x + 4.5y = 96 x + y = 18
To solve this system of equations, we can subtract 6x from both sides of the first equation, giving us 4.5y = 96 - 6x.
We can substitute this expression into the second equation, giving us x + (96 - 6x) = 18.
We can then simplify this equation, giving us 7x = 78, and thus x = 11.
Now we can substitute x = 11 into the original equation, 6x + 4.5y = 96, to find y = 4.
Therefore, Shiro purchased 11 pounds of beef and 4 pounds of chicken.
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Dividing Polynon Use synthetic division to divide the polynomi. (3x^(2)+7x+2)+(x+2)
The result of this synthetic division is the quotient (1 2/3 5/3)
To divide two polynomials using synthetic division, we need to write the dividend as a binomial of the form (x-r) and the divisor in its linear form. In this case, the binomial is (x+2) and the linear form is 3x2+7x+2.
Quotient:
3/3=1
2/3=2/3
Coefficients of dividend: 3 7 2
Quotient: 1 2/3
Product of quotient and binomial: (x+2)
(3x2+7x+2) - (x+2): 3x+5 2
Quotient:
3/3=1
2/3=2/3
5/3=5/3
The result of this synthetic division is the quotient (1 2/3 5/3).
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What fraction of each 100 chart is shaded?
The fraction when a 100-square grid has 70 shaded squares will be 7/10.
How to calculate the FractionA fraction simply means a piece of a whole. In this situation, the number is represented as a quotient such that the numerator and denominator are split. In this situation, in a simple fraction, the numerator as well as the denominator are both integers.
In this case, a 100-square grid has 70 shaded squares.
The fraction will be:
= Number it shaded square / Total square
= 70 / 100
= 7 / 10
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A 100-square grid has 70 shaded squares. Explain how you could express this model as a fraction.
Answer:
The fraction when a 100-square grid has 70 shaded squares will be 7/10.
Solve the equation f(x) = 0
Factor the polynomial f(x) into linear factors.
State the multiplicity of each zero.
Use the table from your calculator to find any real zeros, then use synthetic division to find the remaining zeros. Show all steps.
f(x) = x ^ 4 + 2x ^ 3 + x ^ 2 + 8x - 12
The equation f(x) = 0 has four complex zeros: ±2i and 1 ± √2i, each with a multiplicity of 1.
To solve the equation f(x) = 0, we need to factor the polynomial f(x) into linear factors and then find the zeros of the equation.
Step 1: Factor the polynomial f(x) into linear factors.
f(x) = x ^ 4 + 2x ^ 3 + x ^ 2 + 8x - 12
= (x^2 + 4)(x^2 - 2x + 3)
Step 2: Find the zeros of the equation by setting each factor equal to zero and solving for x.
x^2 + 4 = 0
x^2 = -4
x = ±√(-4)
x = ±2i
x^2 - 2x + 3 = 0
Using the quadratic formula:
x = (-b ± √(b^2 - 4ac))/(2a)
x = (-(-2) ± √((-2)^2 - 4(1)(3)))/(2(1))
x = (2 ± √(-8))/2
x = (2 ± 2√2i)/2
x = 1 ± √2i
State the multiplicity of each zero.
The zeros of the equation are ±2i and 1 ± √2i. Each zero has a multiplicity of 1.
Use the table from your calculator to find any real zeros, then use synthetic division to find the remaining zeros.
There are no real zeros in this equation, as all of the zeros are complex numbers. Therefore, there is no need to use the table from the calculator or synthetic division to find the remaining zeros.
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given is a circle whose equation is x^2 + y^2 - 4x + 6y -12 = 0.
find the tangent distance from (8,6).
A. 11.31
B. 8.45
C. 9.59
D. 23.11
In a circle whose equation is [tex]x^2 + y^2 - 4x + 6y -12 = 0[/tex]. The correct answer is option C. 9.59.
Equation of the circle in standard form by completing the square for both x and y terms:
[tex](x^2 - 4x) + (y^2 + 6y) = 12(x - 2)^2 + (y + 3)^2 = 12 + 4 + 9(x - 2)^2 + (y + 3)^2 = 25[/tex]
then Center: (2, -3) and Radius: 5
Equation of the line passing through the point (8,6) and the center of the circle (2,-3): Slope =
[tex](6 - (-3))/(8 - 2) = 9/6 = 3/2y - 6 = (3/2)(x - 8)y = (3/2)x - 6[/tex]
Substitute the equation of the line into the equation of the circle and solve for x:
[tex](x - 2)^2 + ((3/2)x - 6 - 3)^2 = 25(x - 2)^2 + ((3/2)x - 9)^2 = 25 (5/4)x^2 - (19/2)x + 80 = 0[/tex]
Use the quadratic formula to find the x-intercepts of the line and circle:
[tex]x = (-(-19/2) ± √((-19/2)^2 - 4(5/4)(80)))/(2(5/4))x = (19/2 ± √(361/4 - 400))/(5/2)x = (19/2 ± √(-39/4))/(5/2)x = (19 ± √(-39))/(5)[/tex]
Use the distance formula to find the distance between the point (8,6) and the x-intercepts:
[tex]Distance = √((x - 8)^2 + (y - 6)^2)Distance = √(((19 ± √(-39))/5 - 8)^2 + ((3/2)(19 ± √(-39))/5 - 6)^2)Distance = √((-19/5)^2 + (-39/5)^2)Distance = √(961/25 + 1521/25)Distance = √(2482/25)Distance = 9.59[/tex]
Therefore, the tangent distance from the point (8,6) to the circle is 9.59. The correct answer is option C
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Given R(x) is a rational function with VA at x=-1,-2,2,3,
Holes at (10,1) and (1,1), and there is no HA. What x-values
can R(x) not be? Put commas between your values and values i
The x-values that R(x) cannot be are -1, -2, 2, 3, 10, and 1.
R(x) cannot be at x=-1, -2, 2, 3 because these are the values of the function at these points. Additionally, R(x) cannot be at x=10 and x=1 because these are the holes of the function. Therefore, the x-values that R(x) cannot be are -1, -2, 2, 3, 10, and 1.
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