Physics High School

A roller couster turns in a circular path that has a radius of 25 meters, what's the fastest Velocity the roller coaster can travel without exceeding a centripetal acceleration of 16m/s^2​

Answers

Answer 1

The fastest velocity that the roller coaster can travel without exceeding a centripetal acceleration of 16 m/s^2 is 20 m/s.

What is velocity ?

Velocity can be defined as the displacement of the object in unit time.

The centripetal acceleration (ac) of an object moving in a circular path with radius (r) and velocity (v) is given by the formula:

ac = v^2 / r

We want to find the maximum velocity (v) that the roller coaster can travel without exceeding a centripetal acceleration of 16 m/s^2, given that the radius of the circular path is 25 meters. We can rearrange the formula to solve for v:

v^2 = ac * r

v = sqrt(ac * r)

Substituting the given values, we get:

v = sqrt(16 m/s^2 * 25 m) = sqrt(400 m^2/s^2) = 20 m/s

Therefore, the fastest velocity that the roller coaster can travel without exceeding a centripetal acceleration of 16 m/s^2 is 20 m/s.

Learn more about velocity here :brainly.com/question/80295

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Related Questions

A car on a freeway ramp starts at a velocity of 12.0 m/s. If its average acceleration over 8 s is 3.20 m/s2, what is the velocity at the end of that interval?
A. 13.6 m/s
B. 99.2 m/s
C.25.6 m/s
D. 37.6 m/s

Answers

Answer:  D. 37.6 m/s

Explanation: its D

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